two forces act concurrently on an object on a horizontal frictionless surface. their resultatn force has the largest magnitude when the angle between the forces is

Explanation:

Newton's second law of motion gives the relation between mass, force and acceleration.

We know that,

Force, F = mass (m) × acceleration (a)

or

\(m=\dfrac{F}{a}\)

or

\(a=\dfrac{F}{m}\)

Hence, this is the required solution.

Since the electric field between the plates is constant, If the two plates are brought closer together, the potential difference between the two plates decreases

The relation between potential difference and the electric field is given by

ΔV = E.d

Since the electric field is maintained constant, the potential difference is directly inversely proportional to the distance between the plates.

The potential difference between the plates will therefore likewise decrease if the distance between the plates is reduced, we will state in this case.

The energy required to move a unit charge, or one coulomb, from one point to the other in a circuit is measured as the potential difference between the two points. Potential difference is measured in volts or joules per coulomb.

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By way of Ohm's Law, the voltage drop is proportional to the cutting-edge flowing thru a resistor. (So in numerous collection resistors with the same resistance, the drop across each one is identical, because the present day throughout each one is equal).

The connection between the current, voltage, and resistance is expressed through Ohm's regulation. This states that the modern-day flowing in a circuit is at once proportional to the implemented voltage and inversely proportional to the resistance of the circuit, provided the temperature stays steady.

Resistors in the collection deliver identical cutting-edge, however, the voltage drop throughout them isn't the same as their man or woman resistance values will create one-of-a-kind voltage drops across every resistor as decided by way of Ohm's regulation ( V = I*R ).

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A coiled spring would be useful in illustrating a d. compressional wave. A compressional wave, also known as a longitudinal wave, is a type of wave where the disturbance or oscillation occurs parallel to the direction of wave propagation.

A coiled spring can be used to demonstrate this type of wave by compressing and expanding the coils of the spring. As the coils are compressed, they represent the regions of compression in the compressional wave. When the coils expand, they illustrate the regions of rarefaction. The coiled spring visually represents the alternating pattern of compression and rarefaction characteristic of compressional waves. A compressional wave, also known as a longitudinal wave, is a type of wave where the disturbance or oscillation occurs parallel to the direction of wave propagation. In a compressional wave, particles within the medium oscillate back and forth in the same direction as the wave is traveling.

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Answer:

The answer is

proton- mass-1,charge+

Neutron-mass-1,charge-no charge

electron-mass-1/1840,charge-

Answer:

Dogs are able to hear much higher frequencies than humans are capable of detecting. For this reason, dog whistles that are inaudible to the human ear can be heard easily by a dog. If a dog whistle has a frequency of 30,000 Hz, what is the wavelength of the sound emitted?

A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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According to the Newtons third law of motion, the collision between the bumper car and the rider will affect both of them as both the systems have mass and are moving with certain velocities.

Collision is a case where one moving object or person violently collides with another.

The law of interaction or the Newton's third law of motion, says that if one body exerts a force on a second body, the second body exerts a force equal in magnitude and opposite in direction on the first body.

As we know momentum is P = m*v i.e. momentum (P) is directly proportional to the mass and velocity.

Heavier bodies have more mass, therefore have more momentum.

here, the bumper car is the heavy system and hence, it will exerts more impact on the rider.

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The angular momentum of the satellite remains constant at the labeled locations (A, B, C, D).

How do quantities change in orbit?

Let's analyze the quantities that remain constant at the labeled locations (A, B, C, D):

A. The tidal force on the satellite: This force depends on the gravitational gradient and the satellite's position relative to the primary. Since the position changes along the elliptical orbit, the tidal force is not constant. Therefore, it does not remain constant at any labeled location.

B. The kinetic energy of the satellite: The kinetic energy of the satellite changes as it moves along its elliptical orbit. It is highest at the perigee (closest point to the primary) and lowest at the apogee (farthest point from the primary). Therefore, it does not remain constant at any labeled location.

C. The mechanical energy of the satellite: The mechanical energy of the satellite is the sum of its kinetic energy and gravitational potential energy. Since both of these quantities change along the elliptical orbit, the mechanical energy is not constant at any labeled location.

D. The work done by the force of gravitational attraction on the satellite: The work done by the force of gravitational attraction is given by the change in gravitational potential energy. As the satellite moves along its elliptical orbit, the distance from the primary changes, causing the gravitational potential energy to vary.

Therefore, the work done by the force of gravitational attraction is not constant at any labeled location.

E. The angular momentum of the satellite: The angular momentum of the satellite remains constant throughout its motion if no external torques act upon it. This is known as the conservation of angular momentum. Therefore, the angular momentum remains constant at all labeled locations (A, B, C, D).

F. The gravitational potential energy of the satellite: The gravitational potential energy of the satellite changes as it moves along its elliptical orbit. It is highest at the apogee and lowest at the perigee. Therefore, it does not remain constant at any labeled location.

In summary, the quantities that remain constant at the labeled locations (A, B, C, D) are:

The angular momentum of the satellite.

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Hot spot volcanism is responsible for the formation of volcanic island chains in the oceans and is denoted as option D.

This is a rupture in the earth crust thereby giving rise to the release of hot lava, gases etc from below the surface.

The pushing of the lava through the cracks partially melts the plate at a subduction zone thereby forming the volcanic island chains.

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The position in the graph between 4 - 6 seconds is the region of constant velocity.

The term constant velocity refers to the period in the graph when the velocity is not changing with time. As such, the graph is shown to be a flat portion at such a point.

Hence, it follows that the position in the graph between 4 - 6 seconds is the region of constant velocity.

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Answer:  water vapor

Explanstion

When water is heated it evaporates, which means it turns into water vapor and expands. At 100℃ it boils, thus rapidly evaporating. And at boiling point, the invisible gas of steam is created. ... Those drops of water are called condensation

The steam coming off the pot of boiling water is an example of Water vapor.

Water throughout a gaseous condition, particularly in the atmosphere and at temperatures lower than the boiling point. This same basic ingredient for cloud as well as rain production is water vapor throughout the environment.

It also serves to maintain the Earth's temperature by reflecting and dispersing solar energy as well as absorbing infrared heat from this same Planet.

Thus the response above is correct.

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Answer:

Bowling ball

Explanation:

The bowling ball's mass will make it roll down the incline faster than the lighter volleyball.

Have an amazing day!!

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Answer:

part a: 4.25s

part b: 180.625m

Explanation:

part a:

what we know: vi=42.5m/s

                          t=?

                          vf=0

                          g= -10m/s^2

----------------------------------------------------------

equation: vf-vi/g=t

plug in: -42.5m/s/ - 10m/s^2 = 4.25s

-----------------------------------------------------------

part b: 42.5m/s x(times) 4.25s = 180.625m

Answer:

a. T₂ = 60 N

b. W = 25.98 N

Explanation:

a.

Taking right side as positive x direction, the equation for sum of forces in x-direction can be written as follows:

\(T_{2}Sin\ 30^o - T_{1} = 0\\T_{2}Sin\ 30^o = T_{1}\\T_{1} = (T_{2})(Sin\ 30^o)\\where,\\T_{2} = 30\ N\\Therefore,\\T_{1} = (30\ N)(Sin\ 30^o)\\\)

T₁ = 15 N

b.

Taking upward direction as positive y direction, the equation for sum of forces in y-direction can be written as follows:

\(T_{2}Cos\ 30^o - W = 0\\T_{2}Cos\ 30^o = W\\W = (30\ N)Cos\ 30^o\\\)

W = 25.98 N

Answer:

C

Explanation:

When the planet in motion should have the same speed so until it should be acted by an outer force. This statement explained the movement of the planets.

The information regarding the first law of motion is as follows:

Therefore, the third option is correct.

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To determine the position of the minute hand at 8:15 a.m., we can use the following approach:

Convert the time to radians: At 8:15 a.m., the minute hand is 75% of the way from the 8:00 a.m. mark to the 9:00 a.m. mark. Since the minute hand travels 360 degrees in 60 minutes, it travels 6 degrees per minute. Therefore, at 8:15 a.m., it has traveled 90 degrees from the 8:00 a.m. mark. This is equivalent to (90/360) x 2π radians = π/2 radians. Use trigonometry to determine the position: Since the minute hand is 3.00 cm long and pointing in the direction of the positive x-axis at 8:15 a.m., its position can be described by the coordinates (3.00 cos(π/2), 3.00 sin(π/2)) = (0, 3.00). Therefore, the minute hand is pointing straight up at 8:15 a.m. Note that the x-axis points in the same direction as the minute hand at 8:15 a.m., while the y-axis points in the same direction as the minute hand at 8:00 a.m. This means that the x-axis is perpendicular to the minute hand at 8:00 a.m., and the y-axis is perpendicular to the minute hand at 8:15 a.m.

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The problem is asking to find the minimum value of the coefficient of static friction between the box and the ramp so that it remains stationary (no motion). Since the box is stationary, it is in equilibrium and the sum of forces acting on it is zero. We can consider the forces acting on the box in the direction of the incline plane and perpendicular to the incline plane.

The forces acting on the box are:Weight of the box (mg)Normal force (N)Frictional force (F)Since the box is in equilibrium, the forces acting on it in the direction of the incline plane will be balanced by the frictional force acting in the opposite direction. The minimum value of the coefficient of static friction is the one that balances the weight component acting down the incline plane. It can be calculated as follows:mg sin θ = Fmaxstatic friction = F/NF = mg cos θμs = F/N = mg cos θ/mg= cos θTherefore, the minimum value of the coefficient of static friction between the box and the ramp is μs = cos 7°.μs = cos 7° = 0.9986 (rounded to four decimal places)Answer: 0.9986.

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Answer:

Endothermic

Explanation:

Ap3x

This is the type of Neutralization reaction. So, the correct option is (B).

Neutralization is defined as a chemical reaction in which an acid and a base react quantitatively with each other. Neutrality results from the absence of an excess of hydrogen or hydroxide ions present in the solution.

In this, acid and base react quantitatively to form salt and water as products. In a neutralization reaction, H+ ions and OH- ions combine to form water.

For example,

HCl + NaOH → NaCl + H₂O

Thus, this is the type of Neutralization reaction. So, the correct option is (B).

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Your question is incomplete, most probably the complete question is :

Which statement is true about the reaction shown by this chemical equation HCl + NaOH ------> NaCl + H2O

1. Decomposition Reaction

2. Neutralization reaction

3. Combustion reaction

4. Synthesis reaction

Answer:

Professional education as a science has been defined as a field of educational science that studies the growth of a person into a profession and the related problems. It refers to organized education aimed at the knowledge and skills needed in the profession and working life, as well as growing into active citizenship and membership of society. Professional education as a discipline studies vocational training, skills and learning related to the profession and working life.  

It enables young people and adults to pursue goal-oriented learning with the aim of acquiring and developing the necessary skills in the profession and creating the conditions for independent professional activity and continuous development in the profession.

Answer:

If a star is moving towards the earth, its light is shifted to higher frequencies on the color spectrum (towards the green/blue/violet/ultraviolet/x-ray/gamma-ray end of the spectrum). A higher frequency shift is called a "blue shift".

Explanation:

It just means that the entire spectrum is shifted up in frequency.

Answer:

Explanation:

Let us calculate the time of flight first using the formula;

Velocity = Displacement/Time

Time = Displacement/speed

Time = 10.0/3

Time = 3.33secs

Next is to calculate how far out from the edge of the cliff it will hit the water. To get that, we will use the equation of motion;

S= ut+1/2gt²

u is the initial velocity = 0m/s

g is the acceleration due to gravity = 9.81m/s

S = 0 + 1/2(9.81)(3.33)²

S = 4.905*3.33*3.33

S = 54.39m

Hence it will hit the water at 54.39m from the edge of the cliff

Answer:

Explanation:

Applying kinematic relations along vertical direction

\(y = V_0t + \frac{1}{2}a_yt^2\)

where,

\(a_y = g\)

therefore,

\(y = 0 + \frac{1}{2}gt^2\)

The time taken

\(t = \sqrt{\frac{2y}{g}}\\\\t = \sqrt{\frac{2*10}{9.8}}\\\\t = 1.428s\)

The horizontal distance

\(x = V_yt\\\\x = 3*1.428\\\\x = 4.28m\\\\\)

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If the bullet achieves a speed of 220 m/s as a result of this impluse given to it in the barrel of a gun, so the equation of mass is m = (FΔt) / v.

Impulse is a vector quantity defined as the product of force and the time interval over which the force acts on an object. It represents the change in momentum of an object and is given by the equation:

Impulse = Force * Time

Impulse can also be expressed as the integral of force with respect to time:

Impulse = ∫ F dt

The unit of impulse is newton-second (Ns) or kilogram-meter per second (kg·m/s). Impulse is directly related to the change in momentum experienced by an object. According to the principle of impulse-momentum, the impulse applied to an object is equal to the change in its momentum.

The formula for impulse is given as:

I = FΔt

where

I is impulse

F is the force

Δt is the change in time

According to Newton's second law, the force acting on an object is equal to the mass of the object multiplied by its acceleration.

F = ma

Where F is force,

m is mass,

and a is acceleration.

Rearranging the formula:

F/m = a

Now, we can substitute a = Δv/Δt,

where a is acceleration, Δv is change in velocity and Δt is change in time.

F/m = Δv/Δt

Rearranging this formula gives:FΔt = mΔvOrΔp = mΔvwhere Δp is the momentum.

Impulse (I) is the change in momentum (Δp).

Thus:

I = Δp

We can rewrite this as:

FΔt = mΔv

Given data:

Speed (v) = 220 m/s

Impulse (I) = Δp

Δp = mv - 0 = mv

Where m is the mass of the bullet.

We know that,

I = Δp

I = mv

220 m/s is the speed achieved by the bullet and we need to find the mass m.

Therefore,

m = I / v

Now, we can find impulse by using the formula for impulse:

Δp = mv - 0 = mv

I = Δp = mv

I = m * v

Substitute the given values in the formula to get the mass of the bullet.

I = m * v

m = I / v

m = (FΔt) / v

From the given data, we don't know either force or change in time. Thus, the mass of the bullet cannot be calculated. Therefore, the mass of the bullet cannot be determined using the given data.

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The net change in a free energy reaction is that energy released in the conversion of reactants to products under standard favourable conditions.

As long as a reaction's ΔS is positive, the reaction is always thermodynamically favored.

An element is a substance which cannot be split into simpler forms by an ordinary chemical process. This simply goes to say that elements are substances which cannot be decomposed into simpler substances by ordinary chemical reactions.

An atom is the smallest unit or part of an element which can take part in a chemical reaction.

On a general note, elements are classified as thus:

So therefore, the net change in a free energy reaction is that energy released in the conversion of reactants to products under standard favourable conditions.

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The buoyant force on a Styrofoam sphere that is 10% submerged in water is smaller that the buoyant force on a metal sphere that is 100% submerged in water, if the two volumes of the sphere are equal. Because water is incompressible, its density, stickiness, and other properties stay pretty much the same as you go deeper… and so the buoyant force stays the same as well.

A fluid's buoyancy, also known as upthrust, opposes the weight of an item that is partially or completely submerged by exerting an upward push. The weight of the fluid on top causes pressure in a fluid column to rise with depth. As a result, the pressure at the bottom of a fluid column is higher than at the top. Similar to this, an object submerged in a fluid experiences greater pressure at its bottom than it does at its top. A net upward force is exerted on the item as a result of the pressure differential. The size of the force equals the weight of the fluid that would otherwise fill the submerged volume of the item, direction, and its magnitude is proportional to the pressure difference.

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     Power is, summarized, how fast something is done using energy. More specifically, power is the amount of energy transferred or converted per unit time.

     To determine power, you use the following formula:

                              \(P=\frac{W}{Δt}\)

(formatting is messed up, the denominator is Δt)

         P - power

         W - work

         Δt - elapsed time

     Hope this helps, have a wonderful day :D

Answer:

sorry

Explanation:

Answer:

Explanation:

initial velocity u = 54 km/h = 15 m/s

final velocity v = 18 km/h = 5 m/s

distance s = 10 m

1. v^2 = u^2 + 2as

5^2 = 15^2 + 2a × 10

25 = 225 + 20a

25 - 225 = 20a

20 a = -200

a = -200/2

a = -100m/s^2

∴Deacceleration = -100m/s^2

2. v = u + at

5 = 15 -100t

5-15 = -100t

-10 = -100t

t = 100 / 10

∴t = 10 sec

Total distance covered by the car 10 m

To me, the hardest part of this whole thing is keeping the units straight.  We're starting out with information given to us in kilometers, hours, and meters, and we have to come up with answers in m/s² , seconds, and meters.

When I worked this problem, I jumped right in without thinking, and I immediately got bogged down when I had to go off to the side and convert some units.

Now I know better.  THIS time, before we get all tangled up trying to solve anything, let's get clever and change everything to m/s right now !

(54 km/hour) · (1,000m/km) · (1 hour/3600 sec)  =  15 meters/second

(18 km/hour) · (1,000 m/km) · (1 hour/3600 sec) = 5 meters/second

NOW I'll betcha it's gonna be about 70% faster and easier !

i). Acceleration = (change in speed / time for the change)

We know the distance, but not the time.  I know there's a formula for it, but I've learned so many formulas during my lifetime that I can't remember ALL of them.  So I just memorize some of them, and I work things out from the formulas that I know.  Here's how I do time:)

Average speed during the given slow-down = (1/2)·(15+5) = 10 m/s

Distance covered during the given slow-down = 10 m.

Time = (distance) / (average speed) = (10m) / (10 m/s) = 1 second

Acceleration = (change in speed) / (time for the change)

Acceleration = (5 m/s - 15 m/s) / (1 second)

Acceleration = (-10 m/s) / (1 second)

Acceleration = -10 m/s²   (or 'Deceleration' = 10 m/s² )

_____________________________________________

For parts ii). and iii)., there's a big shift in the question.

It only gave you the slow-down from 54 to 18 km/hr for the purpose of calculating the deceleration.  NOW, for the rest of the answers, it's talking about a complete stop ... 0 m/s .

____________________________________________

ii). Time required to stop = (initial speed) / (deceleration)

Time to stop from 54 km/hr = (15 m/s) / (10 m/s²)

Time to stop = 1.5 seconds

iii).  Distance covered = (average speed) · (time to stop)

Distance covered = (7.5 m/s) · (1.5 sec)

Distance covered = 11.25 meters

OR ... use the official formula:

Distance = (1/2) · (acceleration) · (time² )

Distance = (1/2) · (10 m/s²) · (1.5 sec)²

Distance = 11.25 meters           yay !

The prism's index of refraction is approximately 1.50.


1. Since the prism is an equilateral triangle, all angles are equal to 60 degrees.
2. When the light inside the prism travels parallel to the base, the angle of refraction (alpha) inside the prism is 90 degrees.
3. Use the formula for the angle of deviation (D) in an isosceles prism: D = 2(beta - alpha)
4. Calculate the angle of deviation for the given angle of incidence (beta = 52.2 degrees): D = 2(52.2 - 60) = -15.6 degrees.
5. The angle of deviation in an equilateral prism is given by: D = 60 - A, where A is the angle between the refracted ray and the base.
6. Calculate the angle A: A = 60 - (-15.6) = 75.6 degrees.
7. Use Snell's Law at the first surface (air-to-prism): n1 * sin(beta) = n2 * sin(alpha), where n1 is the index of refraction of air (approximately 1), and n2 is the index of refraction of the prism.
8. Substitute the known values into the equation: 1 * sin(52.2) = n2 * sin(75.6)
9. Solve for n2: n2 = sin(52.2) / sin(75.6) ≈ 1.50

The index of refraction of the prism is approximately 1.50.

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