Total distance travelled is 35m and displacement is 25m.
Distance: Distance is a scalar that expresses the total distance traveled by an object. It's a measure of physical distance that's covered and always good. The distance has nothing to do with the direction, only the magnitude of the change is determined.
Displacement: Displacement is the vector of change in the position of an object. It takes into account the magnitude and direction of change in position from the starting point to the ending point. Perception can be positive, negative or zero depending on the direction of movement.
Total distance = 15m + 20m
Total distance = 35m
Displacement = \(\sqrt{15^{2} +20^{2} \\}\) (as both are perpendicular to each other)
Displacement = 25m
Therefore, Total distance is 35m and displacement is 25m.
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In the Roman soldier model for refraction, what happens to the first soldier who hits the muddy stream?
A. They slow down and keep going straight
B. They slow down and turn slightly
C. They speed up and keep going straight
D. They speed up and turn slightly
In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.
The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.
When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.
The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.
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How do people get energy from the food they eat
a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction
The temperature gradient in the flow of direction is 294525 W.
What is Temperature gradient?A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.
Q= T/( L/ KA)
Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)
= 294525 W
Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.
Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.
Therefore, The temperature gradient in the flow of direction is 294525 W.
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Which is an example of convection currents?
An example of convection currents is the movement of air in a room when a heater is turned on. When the heater warms the air in the room, the warm air becomes less dense and rises, creating a convection current. As the warm air rises, cooler air from other parts of the room moves in to replace it, creating a continuous circulation of air. This process is known as natural convection.
Convection currents occur when there is a transfer of heat through the movement of a fluid, either liquid or gas. Here is a step-by-step explanation of convection currents:
Heating: In the example of a room with a heater, the heating element of the heater warms the air in the vicinity.
Expansion: As the air near the heater gets heated, it expands and becomes less dense. This decrease in density makes the warm air rise.
Rising: The warm air rises upward due to its buoyancy. This upward movement creates an area of low pressure near the heater.
Replacement: As the warm air rises, cooler air from other parts of the room moves in to fill the space left by the rising warm air. This cooler air is denser and moves downward.
Circulation: The cycle continues as the warm air rises, cools down, and then descends to be heated again by the heater. This creates a continuous circulation of air, forming convection currents.
Other examples of convection currents include the movement of boiling water in a pot, the circulation of air in the atmosphere resulting in wind patterns, and the movement of magma in the Earth's mantle leading to plate tectonics. Convection currents play a significant role in distributing heat energy and maintaining fluid movements in various natural and artificial systems.
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A moving walkway has a speed of 0.5 m/s to the east. A stationary observer
sees a man walking on the walkway with a velocity of 0.8 m/s to the east.
What is the man's velocity relative to the moving walkway?
Answer: 0.3 m/sec
Explanation:
Vrel = (Vs-Vm) = (0.8-0.5) = 0.3 m/sec
Answer:
0.3 m/s east
Explanation:
Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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A particle leaves the origin with a speed of 3 106 m/s at 38 degrees to the positive x axis. It moves in a uniform electric field directed along positive y axis. Find Ey such that the particle will cross the x axis at x
Answer:
If the particle is an electron \(E_y = 3.311 * 10^3 N/C\)
If the particle is a proton, \(E_y = 6.08 * 10^6 N/C\)
Explanation:
Initial speed at the origin, \(u = 3 * 10^6 m/s\)
\(\theta = 38^0\) to +ve x-axis
The particle crosses the x-axis at , x = 1.5 cm = 0.015 m
The particle can either be an electron or a proton:
Mass of an electron, \(m_e = 9.1 * 10^{-31} kg\)
Mass of a proton, \(m_p = 1.67 * 10^{-27} kg\)
The electric field intensity along the positive y axis \(E_y\), can be given by the formula:
\(E_y = \frac{2 m u^2 sin \theta cos \theta}{qx} \\\)
If the particle is an electron:
\(E_y = \frac{2 m_e u^2 sin \theta cos \theta}{qx} \\\)
\(E_y = \frac{2 * 9.1 * 10^{-31} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\\)
\(E_y = 3311.13 N/C\\E_y = 3.311 * 10^3 N/C\)
If the particle is a proton:
\(E_y = \frac{2 m_p u^2 sin \theta cos \theta}{qx} \\\)
\(E_y = \frac{2 * 1.67 * 10^{-27} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\\)
\(E_y = 6.08 * 10^6 N/C\)
what is the angle between 3i-2j-3k and the negative x axis
Answer:
Um its the vbuck card on the 3 thrid level
Explanation:
Bc its a vbuck card you know sihdg;aig
Peter rides his bike 5 blocks north and then 10 blocks east. What is his displacement? What is his total distance traveled?
Answer:
5 blocks east. His total distance is 15 feet.
Explanation:
I hope that this helps! Have a good day!
The power P radiated by a loudspeaker at a rock concert is 50 W at a frequency of 1000 Hz.
a) Assuming that the speaker sends the sound waves uniformly in all direction, what is the
intensity I at a distance of 20 meters from the speaker.
b) At what distance will the sound intensity be at the threshold of pain of 1.00 W/m2?
The intensity of waves is 9.96 × 10⁻³W/m².
Power radiated, P = 50 W
Frequency of the sound, f = 1000 Hz
a) Distance, r = 20 m
The intensity of waves,
I = P/4πr²
I = 50/(4π × 20²)
I = 9.96 × 10⁻³W/m²
b) We know that, the intensity of waves,
I ∝ 1/r²
So, I/I' = (r'/r)²
Therefore,
r' = r(√I/I')
r' = 20(√9.96 × 10⁻³/1)
r' = 0.19 m
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A ball of mass 4 kg strikes a floor with a velocity of 10 m/s at an angle of 37° with the normal to the floor. The ball bounces off of the floor with the exact same speed along a path with the same angle. What is the impulse applied to the ball by the floor?
Given:
The mass of the ball is,
\(m=4\text{ kg}\)The initial velocity of the ball is,
\(v_i=10\text{ m/s}\)The angle with the floor is,
\(\theta=37^{\circ}\)The change in momentum is the impulse by the floor, so the impulse is,
\(\begin{gathered} P=m(v_f-v_i) \\ =4\lbrack10-(-10\rbrack \\ =80\text{ kg m/s} \end{gathered}\)The impulse is 80 kgm/s along with the final velocity.
One out of every 92 tax returns that a tax auditor examines requires an audit. If 50
returns are selected at random, what is the probability that less than 2 will need an audit?
O 0.0109
O 0.8971
O 0.9828
O 0.9999
Answer:
I think it's 0.8971-??correct me if I'm wrong because thats what my note said
Vector A points along the + y axis and a magnitude of 100.0 units. Vector B points at an angle of 60.0 degrees above the +x axis and has a magnitude of 200.0 units. Vector C points along the +x axis and has a magnitude of 150.0 units. Which vector has (a ) the largest x component and (b) the largest y component ?
Answer:
vector quantities are resolved into their component form (along the x and y-axis) before adding them. Let us assume that two vectors are
→
a
=
x
1
^
i
+
y
1
^
j
and
→
b
=
x
2
^
i
+
y
2
^
j
, we can find the sum of two vectors as follows.
→
a
+
→
b
=
x
1
^
i
+
y
1
^
j
+
x
2
^
i
+
y
2
^
j
=
(
x
1
+
x
2
)
^
i
+
(
y
1
+
y
2
)
^
j
The direction of the sum of the vectors (with positive x-axis) is,
θ
=
tan
−
1
(
y
1
+
y
2
x
1
+
x
2
)
Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j
What is vector ?Vectors are objects which have both, magnitude and direction. Magnitude defines the size of the vector. It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.
Vector A = direction is in y direction = 100j
Since , this vector is only in y direction and have no component in x direction , so its x component will be = 0i
Vector B = direction is at angle of 60.0 degrees above the +x axis
Resolving into x and y components
x component = Vector B*cos(60) = Vector B * (1/2) = Vector B /2 = 200 /2
= 100i
y component = Vector B * sin(60) = Vector B * \(\sqrt{3}\)/2 = 173j
Vector C = direction is along the +x axis
hence , it will not have any y component
x component = 150i
y component = 0j
Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j
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Help please ! Ill give brainliest !! ☁️✨
How do ocean currents affect ocean surface temperature?
Answer:
Ocean currents act as conveyor belts of warm and cold water, sending heat toward the polar regions and helping tropical areas cool off. Land areas also absorb some sunlight, and the atmosphere helps to retain heat that would otherwise quickly radiate into space after sunset.
A sample of vegetable oil with density 913 kg/m3 is found to have a mass of 0.0365 kg. Find the volume of this sample
The volume of the vegetable oil is 0.00003998 m³.
The density of vegetable oil,
ρ = 913 kg/m³
The mass of vegetable oil,
m = 0.0365 kg
To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.
The formula for density is:
ρ = m/V
where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:
V = m/ρSubstituting the given values of mass and density in the above formula,
We get:
V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)
Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.
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Two bowling balls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8 cm apart. What gravitational force do they exert on each other?
Answer:
6.49 x 10^-8 N
Explanation:
formula is
F= G * ((m1 * m2)/r^2)
F = 6.67x10^-11 * ((6.8*6.8/.218)
F = 6.49 x 10^-8 Newtons
F= G * ((m1 * m2)/r^2)
F = 6.67x10^-11 * ((6.8*6.8/.218)
F = 6.49 x 10^-8 Newtons
What is gravitational force?Gravitational force is the force of attraction on a body by earth. Example - Leaves and fruits fall from a tree downwards towards the ground due to the gravitational pull.
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A girl is moving in a straight line at a velocity of 3 m/s and starts to slow down at a constant rate. If she stops 6 seconds later, what is her acceleration?
The acceleration of the girl moving in a straight line at a velocity of 3 m/s is - 0.5 m / s²
a = v - u / t
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
v = 0
u = 3 m / s
t = 6 s
a = ( 0 - 3 ) / 6
a = - 0.5 m / s²
The negative symbol signifies that she is decelerating.
Deceleration is the acceleration in opposite direction. As a result, the body will lose velocity at a constant pace. Hence, if the acceleration has a negative value it is called as Deceleration.
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How many Joules are absorbed by a pot of water with a mass of 600 g in order to raise the temperature from 30° C to 40° C? (The specific heat of water is 4.184 J/g°C) *
Answer:
25104 J
Explanation:
We are given;
Mass; m = 600 g
Change in temperature;Δt = (40 - 30) = 10°C
Specific heat of water; c = 4.184 J/g°C
Now, to find how many joules, we simply use the formula for quantity of heat.
Thus;
Q = mcΔt
Plugging in the relevant values to give;
Q = 600 × 4.184 × 10
Q = 25104 J
Quantity of heat = 25104 J
Franny drew a diagram to compare images produced by concave and convex lenses.
2 overlapping circles, the left circle labeled Concave lenses and the right circle labeled Convex lenses. An X in the overlap.
Which belongs in the area marked X?
Answer:
Virtual
Explanation:
Answer:
B. Virtual
Good Luck!
Identify one way oceans can influence climate change. (1 point)
Oceans moderate warming by absorbing carbon dioxide.
Ocean salinity affects water volume.
Ocean currents affect tidal movement.
Ocean acidity affect marine organisms.
One way oceans can influence climate change is Oceans moderate warming by absorbing carbon dioxide. The correct option is A.
What is ocean acidification?Ocean acidification is the continuous, long-term absorption of carbon dioxide that results in a drop in the pH of ocean water.
The ocean can take in CO2 in a variety of ways, including through the process of photosynthesis by phytoplankton and green algae. CO2 can also be taken in by the ocean through the diffusion of gases.
Effects of ocean acidification:-
Has an impact on marine life and is the main cause of the coral reefs' decline as well as the decline of the marine ecosystem that depends on and surrounds corals.The development and reproduction of calcifying marine organisms are disrupted and put in danger.Numerous marine organisms and aquatic plants' life cycles will be impacted by the rise in acidity.Because some marine plankton and algae thrive in acidic conditions, the increased population of these organisms will speed up the absorption of CO2 and contribute to the acidification of the ocean.To know more about ocean acidification follow
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Answer: A) Oceans moderate warming by absorbing carbon dioxide.
Explanation: What does oceans absorbing carbon dioxide have to do with warming? Since carbon dioxide or CO2, is a greenhouse gas, it can absorb heat. As oceans are melted into water by the Earth getting warmer it absorbs more and more CO2, that's part of the reason why we have had such hot years. As the oceans absorb the CO2, more glaciers melt, therefore there's more ice and the Earth just keeps getting warmer.
Hope this helps ^_^
Compare the number of electrons with the number of protons in a charged object.
Friction produces heat because it causes molecules to move faster and
have more energy.
True or false.
Answer:
True
Explanation:
Friction occurs because no surface is perfectly smooth. Even surfaces that look smooth to the unaided eye make look rough or bumpy when viewed under a microscope. You know that friction produces heat. That’s why rubbing your hands together makes them warmer. But do you know why? Friction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer. Heat from friction can be useful. It not only warms your hands.
Drag each label to the correct location on the chart.
Based on Newton's law of universal gravitation, complete the following table.
tum. All rights reserved.
distance increases
mass increases
Gravity Increases When:
distance decreases mass decreases
Reset
Gravity Decreases When:
Next
When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.
Which Newtonian principle is universal?Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.
Is there a universal rule governing gravity?What exactly does the Law of Gravitation apply to According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.
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When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.
Which Newtonian principle is universal?Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.
Is there a universal rule governing gravity?What exactly does the Law of Gravitation apply to According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.
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Determine the tangential and centripetal components of the net force exerted on the car (by the ground) in Example when its speed is 15 . The car's mass is
The tangential component of the net force exerted on the car is ≈3.0 × 10³ N & the centripetal component of the net force exerted on the car is ≈4.3 × 10² N
The centripetal acceleration's magnitude is expressed as:
a = v²/r
The tangential acceleration's magnitude is stated as:
a= ∆v/∆t
The following is the net force's tangential component:
F =ma
Replace each value in the equation above.
F = (950 kg) (3.2 m/s²) (1N/(1kg ×m∕s² ))
= 3040N
≈3.0 × 10³ N
Consequently, the net force applied to the automobile has a tangential component that is ≈3.0 × 10³ N
The following is the centripetal component of the net force:
F = mv²/r
Replace each value in the equation above.
FR =((950 kg) (15 m∕s²) )/(500 m) (1N/(1kg ×m∕s² ))
= 427.5 N
≈4.3 × 10² N
Consequently, the net force applied to the automobile has a centripetal component that is ≈4.3 × 10² N
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A guitar string is 90 cm long and has a mass of 3.5g . The distance from the bridge to the support post is L=62cm, and the string is under a tension of 540N . What are the frequencies of the fundamental and first two overtones? Express your answers using two significant figures. Enter your answers in ascending order separated by commas.
Answer:
\(v_1 = 301 Hz\)
\(v_2 = 601 \ \ Hz\)
\(v_3 = 901 \ Hz\)
Explanation:
From the question we are told that
The length of the string is \(l = 90 \ cm = 0.9 \ m\)
The mass of the string is \(m_s = 3.5 \ g =0.0035 \ kg\)
The distance from the bridge to the support post \(L = 62 \ c m = 0.62 \ m\)
The tension is \(T = 540 \ N\)
Generally the frequency is mathematically represented as
\(v = \frac{n}{2 * L } [\sqrt{ \frac{T}{\mu} } ]\)
Where n is and integer that defines that overtones
i.e n = 1 is for fundamental frequency
n = 2 first overtone
n =3 second overtone
Also \(\mu\) is the linear density of the string which is mathematically represented as
\(\mu = \frac{m_s}{l}\)
=> \(\mu = \frac{0.0035 }{ 0.9 }\)
=> \(\mu = 0.003889 \ kg/m\)
So for n = 1
\(v_1 = \frac{1}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]\)
\(v_1 = 301 \ Hz\)
So for n = 2
\(v_2 = \frac{2}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]\)
\(v_2 = 601 \ Hz\)
So for n = 3
\(v_3 = \frac{3}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]\)
\(v =901 \ Hz\)
A banana is placed on a spring scale to measure its weight. It wins the award for
the Biggest Banana EVER because it's 17 kg. If banana causes the spring in the
scale to compress 0.8 m, what is the spring constant?
Answer:
do 17 +8.0 and see what you get
Explanation:
The calculated value of spring constant of the spring is 208.25 N/m.
What is spring constant?The ratio of the force acting on the spring to the displacement it causes is known as the spring constant, which is a property of springs. Si unit of spring constant is Newton per meter.
Given parameters:
Mass of the banana: M = 17 kg.
Compression of the scale: x = 0.8 m.
We know that: acceleration due to gravity: g = 9.8 m/s².
So, weight of the banana: W = Mg = 17 kg × 9.8 m/s². = 166.6 Newton.
For applying 166.6 Newton weight on the spring, the spring in the
scale to compress 0.8 m.
Then, spring constant: k = F/x = 166.6 N /0.8 m = 208.25 N/m.
Hence, the spring constant is 208.25 N/m.
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5. The mechanical advantage of a jaw when it is used as a second-class lever is 1.4.
a. If the input force is 100 newtons, what is the output force?
b. How does the input lever arm compare to the output lever arm when the jaw is used as a
second-class lever? Draw a diagram to illustrate your answer.
Answer: a. It would be 140 N
I don’t know, I just got it right
A force directed 51.8° below the positive x-axis has an x component of 4.93 lb. Find its y component.
y= 6.26 lb.
Explanation:1. Draw the vector of the force to better visualize and understand the problem.Check attached image 1.
2. Find an expression for the force in the y axis.Using the trigonometric functions, we need to find a function that relates the angle, opposite side and adjacent side of the drawn triangle. The function that does this is the tangent.
Let theta (θ) be the angle given by the problem.
Let "y" be the missing y component.
Tangent (θ) = Opposite side (y) / Adjacent side (x)
\(Tan(tetha)=\frac{y}{x}\)
3. Solve the equation for y by multiplying both sides by x.\(Tan(tetha)*x=y\)
4. Substitute the information given by the problem and calculate y.\(Tan(51.8)*(4.93)=y\\ \\y=6.26\)
5. Express the result.
y= 6.26 lb.
On the moon, what would be the force of gravity acting on an object that has a mass of 7kg?
Answer:
Force of gravity, F = 70 N
Explanation:
It is required to find the force of gravity acting on an object that has a mass of 7 kg. Force of gravity always acts in downward direction.
The force of gravity is equal to the weight of an object. It is given by :
\(F=mg\)
g = acceleration due to gravity, for Earth, g = 10 m/s²
So,
\(F=7\times 10\\\\F=70\ N\)
So, 70 N of force of acting on an object.