PLEASE HELP ME ANSWER THE PHYSICS QUESTIONS ON MY PROFILE!!!

i will give brainliest to the first to answer!!! this one and the other ones

Two freight cars, each with a mass of 291,001 kg, collide and stick together. One was initially moving at 2.4 m/s and the other was at rest. What is their final speed?

For a spacecraft is traveling with a velocity of Vox-5690 m/s:

To solve this problem, use the equations of motion to calculate the final velocity and the vertical component of the velocity. Assume that the initial velocity in the y-direction is zero.

Given:

Initial velocity in the x-direction (V₀ₓ) = -5690 m/s

Time of engine firing (t) = 865 s

Acceleration in the x-direction (ax) = 1.45 m/s²

Acceleration in the y-direction (ay) = -8.66 m/s²

(a) To calculate the final velocity (v), use the equation:

v = V₀ₓ + ax × t

Substituting the values:

v = -5690 m/s + 1.45 m/s² × 865 s

v = -5690 m/s + 1254.25 m/s

v ≈ 685.25 m/s

Therefore, the final velocity (v) is approximately 685.25 m/s.

(b) To calculate the vertical component of the velocity (vy), use the equation:

vy = ay × t

Substituting the values:

vy = -8.66 m/s² * 865 s

vy = -7484.9 m/s

Therefore, the vertical component of the velocity (vy) is -7484.9 m/s.

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So the acceleration of the student-bicycle system is \(a=5m/s^{2}\).

The gravitational force that acts on the bicycle system is

\(F_{g}=500N\)

Now the force, that is the gravitational force is related to mass of the system and the acceleration due to gravity of the system, 'm' and 'g' respectively.

Therefore, we can write

\(F_{g}=mg\)

500  = m x 10    (since , g = 10 m/s-s)

∴ m = 50 kg

Now the net vertical force acting on the student bicycle system is 0. And the vertical acceleration of system is also 0. The total horizontal force acts to the right of the system. So by Newton's 2nd law of motion, we can write

\(F_{f}=ma\)

\(a=\frac{F_{f}}{m}\)

\(=\frac{250}{50}\)

Therefore \(a=5m/s^{2}\)

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The complete question is

A student rides a bicycle in a circle at a constant speed and constant radius. A force diagram for the student-bicycle system is shown in the figure above. The value for each force is shown in the figure. What is the acceleration of the student-bicycle system?

Without knowing the forces exerted by Kari and Sandra, as well as the specific details about the stairs, we cannot determine who did more work. Option D

The amount of work done depends not only on the distance traveled but also on the force applied and the direction of the force. Without information about the force applied by both Kari and Sandra, we cannot determine who did more work.

Work is defined as the product of force and displacement in the direction of the force. In this case, the force exerted by Kari and Sandra while climbing the stairs is unknown.

If Kari and Sandra exerted the same amount of force while moving up the stairs, then the work done would be the same. However, if Sandra exerted a greater force compared to Kari, then Sandra would have done more work.

Additionally, the presence of stairs implies a vertical displacement. If Kari and Sandra were climbing stairs at the same height, the work done would be the same. However, if the stairs had different heights or slopes, the vertical displacement would differ, and that could affect the work done. Option D

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The value of the charge on each particle is \(1.05 x 10^-8 C\).

Coulomb's law is a fundamental principle of electrostatics that describes the interaction between electric charges. It states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. We can use Coulomb's law to solve this problem. Mathematically,

\(F = k(q1q2)/r^2\)

where F is the force of attraction or repulsion between the two charged particles,\(q1\) and \(q2\) are the magnitudes of the charges on the two particles, r is the distance between them, and k is Coulomb's constant, which has a value of \(9.0 x 10^9 Nm^2/C^2.\)

In this problem, we know that the charges are equal and the distance between them is 10.0 cm. We also know that the force between them is 0.5 N. Therefore,

\(0.5 N = k(q^2)/(0.1 m)^2\)

Solving for q, we get:

\(q = \sqrt{[(0.5 N)(0.1 m)^2/k]}\)

\(q = \sqrt{(0.5 N)(0.01 m)/(9.0 x 10^9 Nm^2/C^2)}\)

\(q = 1.05 x 10^-8 C\)

Therefore, the value of the charge on each particle is \(1.05 x 10^-8 C.\)

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The spontaneous drying of leaves occurs due to the loss of moisture through evaporation, primarily facilitated by transpiration and environmental factors such as temperature, humidity, and airflow. Aging and senescence also contribute to the process.

The spontaneous process of drying leaves, also known as desiccation, is a natural occurrence that takes place as a result of various factors. Primarily, it involves the loss of moisture from the leaf tissues through evaporation. Leaves have specialized structures called stomata, small openings on their surfaces, which facilitate the exchange of gases, including water vapor.

When environmental conditions such as high temperature, low humidity, and increased airflow prevail, water molecules escape through the stomata into the surrounding air. This process, called transpiration, plays a significant role in leaf drying. Additionally, sunlight accelerates the rate of evaporation by providing energy to convert water into vapor.

As moisture content decreases, the cell walls of the leaf tissues contract, causing the leaf to become dehydrated and eventually dry. The process is also influenced by the plant's natural aging and senescence, where the leaf undergoes programmed cell death.

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The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J

First, we shall obtain the initial kinetic energy. Details below:

KE₁ = ½mu²

= ½ × 1500 × 55²

= 41250 J

Next, we shall final kinetic energy. Details below:

KE₂ = ½mv²

= ½ × 1500 × 65²

= 3168750 J

Finally, we shall determine the net work done. Details below:

W = KE₂ - KE₁

= 3168750 - 41250

= 3127500 J

Thus, the net work done is 3127500 J

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Answer:

Answer: The correct statement is : all the inner planets are dense.

Explanation:

The out planets are more gaseous because they are farther from the sun and the inner planets are more dense because they are closer to the sun.

The new angular velocity becomes  0.286 rev/s.

Given parameters:

Mass of the marry go round: M = 120 kg.

Radius of the marry go round: r = 1.80 m.

Mass of the boy: m = 27 kg.

Initial angular velocity of the marry go round: ω₁ = 0.350 rev/s.

Final angular velocity of the marry go round: ω₂ = ?

From the principle of conservation of angular momentum;

Initial angular momentum = final angular momentum

⇒ 1/2 Mr²ω₁ = 1/2( M+m)r²ω₂

⇒ ω₂ = Mω₁/(m+M)

= 120×0.35/(120+27) rev/s

= 0.286 rev/s.

So, final angular velocity of the marry go round: ω₂ = 0.286 rev/s.

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Answer:

The first choice, one block per minute.

Explanation:

When you exercise the muscles in your body must contract, in order to do that they need oxygen, glucose, a molecule called ATP, and amino acids. As your muscles use these compounds and contract themselves, they will create waste products like carbon dioxide, and lactic acid that must be carried away from the muscles. When exercising many muscles will all require nutrients and elimination of waste products constantly at the same time. To meet this demand the heart must rapidly increase the rate at which it beats and pushes blood through the body. This is why the heart beats significantly faster during exercise.

The seasons in the Northern Hemisphere are the opposite of those in the Southern Hemisphere. Seasons occur because Earth is tilted on its axis relative to the orbital plane, the invisible, flat disc where most objects in the solar system orbit the sun.

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

T=3.12 Sec

Distance d= 9.703m

The distance can refer to a physical length in physics or to an estimate based on other factors in ordinary language (e.g. "two counties over"). It is sometimes used to indicate the distance between two points: display style |AB||AB|. The terms "distance from A to B" and "distance from B to A" are frequently used interchangeably.

It is a generalization of the idea of physical distance. Distance is a non-numerical measurement in psychology and the social sciences; psychological distance refers to how an object feels.

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Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 95 × 25

We have the final answer as

Hope this helps you

Answer:

Horizontal component of pull = (cos 55 x 33.9) = 19.4N.

Net horizontal force = (19.4 - 14.2) = 5.2N.

Work = (fd) = (5.2 x 13.5) = 70.2 Joules.

Rounded to 1 decimal place throughout.

Explanation:

The total work done on the vacuum is 70.2 J.

What is work done?

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0° angle, against a 14.2 N friction force.

Horizontal component of pull = (cos 55 x 33.9) = 19.4N.

Net horizontal force = (19.4 - 14.2) = 5.2N.

Work done by vacuum will be

Work =5.2 x 13.5

Work =70.2 J

Thus, the total work done on the vacuum is 70.2 J.

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Answer:

Approximately \(5.9\; {\rm m\cdot s^{-1}}\) (assuming that the partner is holding the other end of the coil stationary.)

Explanation:

In a standing wave, an antinode is a point that moves with maximal amplitude, while a node is a point that does not move at all. There is an antinode between every two adjacent nodes. Likewise, there is a node between every two adjacent antinodes.

The side of the spring that is being shaken moving with maximal amplitude. Hence, that point on this spring would also be an antinode. In contrast, the side of the spring that is held still (does not move at all) would be a node.

There would be a node between:

Overall, the nodes and antinodes on this spring would be:

The distance between two adjacent nodes is equal to one-half (that is, \((1/2)\)) the wavelength of the wave. The distance between a node and an adjacent antinode is one-quarter (that is, \((1/4)\)) of the wavelength of the wave.

Thus, if the wavelength of the wave in this question is \(\lambda\), the length of this spring would be:

\(\displaystyle \frac{1}{2}\, \lambda + \frac{1}{4}\, \lambda = \frac{3}{4}\, \lambda\).

The question states that the length of this coiled spring is \(7.2\; {\rm m}\). In other words, \((3/4) \, \lambda = 7.2\; {\rm m}\). The wavelength of this wave would be \((7.2\; {\rm m}) / (3/4) = 9.6\; {\rm m}\).

The frequency \(f\) of this wave is the number of cycles in unit time:

\(\begin{aligned} f &= \frac{10}{16.3\; {\rm s}} \approx 0.613\; {\rm s^{-1}}\end{aligned}\).

Hence, the speed \(v\) of this wave would be:

\(\begin{aligned} v &= \lambda\, f \\ &=9.6\; {\rm m} \times 0.613\; {\rm s^{-1}} \\ &\approx 5.9\; {\rm m \cdot s^{-1}}\end{aligned}\).

Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

The maximum velocity of the pendulum is determined as 3.03 m/s.

The maximum velocity of the pendulum is calculated from the principle of conservation of energy as shown below;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 0.468)

v = 3.03 m/s

Thus, the maximum velocity of the pendulum is determined as 3.03 m/s.

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The minimum coefficient of static friction required for this claim to be made possible is 0.7

In an inclined plane system, the coefficient of static friction is the angle at which an object slide over another.  

The gravitational force component exceeds the static friction force when the angle rises. Hence, the object begins to slide.

According to Newton second law;

\(\sum F_x = \sum F_y = 0\)

\(\mathbf{mg sin \theta -f_s= N-mgcos \theta = 0 }\)

\(\mathbf{mg sin \theta =f_s}\)

\(\mathbf{mg sin \theta =\mu_s N}\)

N = mg cos θ

Equating both force components on the L.H.S and R.H.S, we have the following

\(\mathbf{mg sin \theta =\mu_s \ mg \ cos \theta}\)

\(\mathbf{sin \theta =\mu_s \ \ cos \theta}\)

\(\mathbf{\mu_s = \dfrac{sin \theta }{ cos \theta}}\)

According to the trigonometry rule:

\(\mathbf{tan \theta= \dfrac{sin \theta }{ cos \theta}}\)

∴

\(\mathbf{\mu_s =\tan \theta}}\)

\(\mathbf{\mu_s =\tan 35^0}}\)

\(\mathbf{\mu_s = 0.700}}\)

Therefore, we can conclude that the minimum coefficient of static friction needed for this claim to be possible is 0.7

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Answer:

a. Contains a resistor and a capacitor

Ans: RC circuit

b. One coulomb per volt

Ans: Farad

c. The constant of proportionality between charge and voltage

Ans: Capacitance

d. The characteristic time for a capacitor

Ans: Time constant

e. The insulator between two capacitor plates

Ans: Dielectric

f. The measure of the difficulty required to push charges through a device

Ans: Resistance

The force of friction acting on the crate is 950 N.

Force of friction is defined as the force that opposes the motion of an object when two surfaces are in contact.

The frictional force on the object is determined by applying Newton's second law of motion as shown below.

F - Ff = ma

where;

1200   -  Ff = 500(0.5)

1200 - Ff = 250

Ff = 1200 - 250

Ff = 950 N

Thus, the force of friction acting on the crate preventing the motion of the crate is determined by applying Newton's second law of motion.

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The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)

The magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.

So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.

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The answer to this question is the Sun.

As im writing this, 12,826 people vote the Sun.

animals such as snakes and frogs, which do not make their own body heat. They usually get their heat from the sun. Hence option B is correct.

A body temperature that is only slightly higher than the ambient temperature. This condition differentiates cold-blooded, or homoiothermic, animals from fishes, amphibians, reptiles, and invertebrates (birds and mammals). Due of their reliance on external warmth for metabolic activity, terrestrial cold-blooded species are restricted to locations with temperatures ranging from 5-10° to 35-40° C (41-50° to 95-104° F).

Cold-blooded creatures cannot create their own body heat, but they may control it by modifying their surroundings. Alligators and other reptiles frequently lay in the sun to warm up. They, on the other hand, cool off by swimming, going into a burrow in the earth, or moving inside the sade of a rock.

Hence option B is correct.

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The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.

The velocity of the 25.8 g marble after the collision is calculated as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

The final velocity of the 25.8 g marble after the collision is calculated as;

( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )

712.92 = 296.36 + 25.8v

25.8v = 416.56

v = 416.56 / 25.8

v = 16.15 cm/s

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Just before the collision, the ball has a velocity of 9.3 m/s, downward. After the collision, the ball has a velocity of 6.2 m/s, upward.

To solve this problem, we can analyze the motion of the ball and block before and after the collision using the principles of conservation of energy and momentum. Since the collision is elastic, the total kinetic energy of the system is conserved. The ball has gravitational potential energy before the collision, which is converted to kinetic energy as it falls.

The block has no kinetic energy before the collision, but gains some after the collision due to the transfer of momentum from the ball. By equating the total kinetic energy before and after the collision and using the principle of conservation of momentum, we can solve for the velocities of the ball and block.

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The resistance of the wire bent through 180 degrees at its mid point and the two halves are twisted together 0.25R.

The resistance of a wire directly proportional to the length of the wire and inversely proportional to the area of the wires.

R = ρL/A

where;

When the piece of wire is bent through 180 degrees at its mid point and the two halves are twisted together. So, the length is halved (l/2) and the area of cross section is doubled (2A).

\(R =\rho \frac{\frac{1}{2} l}{2A} \\\\R = \frac{1}{4} (\frac{\rho L}{A} )\\\\R_{new} = \frac{R}{4}\)

Thus, the resistance of the wire bent through 180 degrees at its mid point and the two halves are twisted together 0.25R.

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The specific heat capacity of silver is 0.235 J/g°C.

The theory used in this question is the specific heat capacity equation, which states that the amount of energy required to raise the temperature of an object is proportional to the mass, specific heat capacity, and change in temperature.

The equation is Q = mcΔT, where Q is the amount of energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Explanations given below

Calculate the specific heat capacity of silver by dividing the energy absorbed (197.9 J) by the mass of the silver (55.0 g) and the temperature rise (15°C).

Divide 197.9 J by 825 g°C (55.0 g * 15°C).

             (197.9 J) / (55.0 g * 15°C) = 0.235 J/g°C

The result is 0.235 J/g°C, which is the specific heat capacity of silver.

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Given data

*The given equation is x = 5 + 3 × (5 - 2)^2

Solve the given equation as