In a laboratory, nakisha mixes a sodium hydroxide solution with an indicator called phenolphthalein. when combined, they create a pink solution. nakisha wonders if mixing other solutions with phenolphthalein will also create this pink color. how could nakisha use the scientific inquiry process to determine whether mixing other solutions with phenolphthalein will also create a pink color? check all that apply.

Answer:

The answer is 0.33 H!

Explanation:

Comparing the vapor pressures, we find that Parcel a has a higher vapor pressure (13.2 hPa) compared to Parcel b (9.9 hPa). Therefore, Parcel a has a greater water vapor content.

To determine which parcel of air has a greater water vapor content, we need to compare the actual vapor pressure (water vapor present in the air) at each temperature and relative humidity.

Using the information provided, we can calculate the vapor pressure for each parcel of air using the following formula:

Vapor Pressure = Relative Humidity × Saturation Vapor Pressure

For Parcel a:

Temperature = 36°C

Relative Humidity = 33%

For Parcel b:

Temperature = 18°C

Relative Humidity = 66%

We need to compare the vapor pressures of each parcel to determine which one has a higher water vapor content.

Calculating the vapor pressure for Parcel a:

Vapor Pressure a = 0.33 × Saturation Vapor Pressure at 36°C

Calculating the vapor pressure for Parcel b:

Vapor Pressure b = 0.66 × Saturation Vapor Pressure at 18°C

Since the saturation vapor pressure changes with temperature, we need to refer to a reference table or use an equation to obtain the specific saturation vapor pressures at 36°C and 18°C.

Let's assume the saturation vapor pressure at 36°C is 40 hPa and the saturation vapor pressure at 18°C is 15 hPa.

Calculating the vapor pressure for Parcel a:

Vapor Pressure a = 0.33 × 40 hPa = 13.2 hPa

Calculating the vapor pressure for Parcel b:

Vapor Pressure b = 0.66 × 15 hPa = 9.9 hPa

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Answer:

w = 1,662 rad / s,    v = 33.25 m / s

Explanation:

This this exercise indicates that the acceleration felt by the astronauts is

         a = 5.64 g

in a circular motion the centripetal acceleration is

        a_c = v²/ r

angular and linear variables are related

         v = w r

we substitute

        a_c = w² r

we finally have

         5.64 g = w² r

         w² = 5.64 g / r

let's calculate

         w = \(\sqrt{ \frac{5.64 \ 9.8}{20.0} }\)

         w = 1,662 rad / s

linear velocity is

        v = w r

        v = 1,662 20

         v = 33.25 m / s

The speed with which the string of the kite is let out when the kite is at 100 ft away from the girl would be  14.71 ft/s.

Given that,The height of the kite above the ground is 600 ft.The rate at which the wind carries the kite is 25 ft/sec.Let v be the speed with which the string of the kite is let out when the kite is at 100 ft away from the girl.The kite flies at a constant height and horizontally away from the girl.Thus the horizontal distance x traveled by the kite after t seconds is given by x = 25t.Let y be the height of the kite at time t.

Thus, the length of the string let out is given by s = √(x² + y²).

Differentiating both sides with respect to t we get,ds/dt = (x/√(x² + y²)) (dx/dt) + (y/√(x² + y²)) (dy/dt)Hence ds/dt = (25/√(25² + 600²)) (25) + (y/√(25² + 600²)) (v)

Also, when the kite is 100ft away from the girl, y = 400 ft and we are to find v.

Therefore,ds/dt = (25/√(25² + 600²)) (25) + (400/√(25² + 600²)) (v)ds/dt = 25(25/625) + (400/√(625 + 360000)) (v)ds/dt = 1 + (400v/√360625)

Here, we have to find v when s = 100.We know that, x = 25tThus t = x/25 = 100/25 = 4.

Hence, when the kite is 100ft away from the girl, we have ds/dt = 1 + (400v/√360625)And t = 4.

Therefore, substituting this value in x, we have, x = 25t = 25 × 4 = 100.

Substituting these values in the expression for s, we get,100 = √(100² + 600²) + 400v/√360625100 = 10√37 + 400v/605

Hence, solving for v, we getv = (605/400) (100 - 10√37)v ≈ 14.71 ft/s

Answer: The speed with which the string of the kite is let out when the kite is at 100 ft away from the girl is ≈ 14.71 ft/s.

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Answer:

\(\boxed{V_{i} = 5\ m/s}\)

Explanation:

Given:

Acceleration = a = 0.75 m/s²

Time = t = ?

Final Velocity = \(V_{f}\) = 72 km/hr = 20 m/s

Required:

Initial Velocity = \(V_{i}\) = ?

Formula:

a = \(\frac{V_{f}-V_{i}}{t}\)

Solution:

For  \(V_{i}\)  the formula becomes:

\(V_{i} = V_{f}-at\)

\(V_{i}\)  = 20 - (0.75)(20)

\(V_{i}\)  = 20 - 15

\(V_{i}\)  = 5 m/s

In Case: If you want it in km/hr:

\(V_{i}\)  = 5 * 3.6

\(V_{i}\)  = 18 km/hr

Answer:

5 m/s

Explanation:

acceleration = 0.75 m/s²

time = 20 s

final velocity = 72 km/h = 20 m/s

initial velocity = ?

Apply formula for initial velocity.

\(u=-at+v\)

\(\sf a=acceleration\\t=time\\v=final \: velocity\\u=initial \: velocity\)

Solve for u.

\(u=-(0.75)(20)+ 20\)

\(u=-15+20\)

\(u= 5\)

Question:-

A man standing on a road has to hold his umbrella in 30° with the vertical to keep the rain away.He throws the umbrella and starts running at 10km/h.He finds that raindrops are hitting his head vertically .Find the speed of rain w.r.t road.

Answer:-

Look at the attachment

\(\\ \sf\longmapsto tan\Theta=\dfrac{Perpendicular}{Base}\)

\(\\ \sf\longmapsto tan30=\dfrac{V_{RAIN}}{10}\)

\(\\ \sf\longmapsto \sqrt{3}=\dfrac{V_{RAIN}}{10}\)

\(\\ \sf\longmapsto V_{RAIN}=10\sqrt{3}km/s\)

option C

Answer:

• From trigonometric ratios:

\({ \boxed{ \rm{ \tan( \theta) = \frac{opposite}{adjacent} }}} \\ \)

• theta is 30°

• opposite speed is Vp

• adjacent speed is 10 km/h

\({ \tt{ \tan(30 \degree) = \frac{v _{p} }{10} }} \\ \\ { \tt{v _{p} = 10 \tan(30 \degree) = 10 \times \sqrt{3} }} \\ \\ { \underline{ \underline{ \tt{ \: \: v _{p} = 10 \sqrt{ 3} \: km }}}}\)

Answer:

a. All the laboratory equipment given are very basic equipment used in all the laboratories. Name of each equipment is as follows:

b. Use of each laboratory equipment identified is:

Answer:

Choice A

Explanation:

The lower the point the higher the kinetic energy because Mechanical energy is conserved and the Gravitational Potential Energy gets lower when the height is lower

I'm sorry but I don't know

Answer:

The voltage drop across each resistance is the same as the applied one. Hence most of the supplied voltage (the electrical energy) reaches the bulb. Hence it glows brighter. Now in the case of series combination of resistors, the effective resistance of the circuit increases.

Explanation: Discuss your theory on why the light bulbs in the combination circuit have

different brightness.

Answer: Unequal heating rates of land and water

Explanation: During the day the land heats up faster, the warm air over the land rises up and the cold air from the sea blows towards the land causing a sea breeze.

After a gamma ray is produced in the core of the sun, it will typically travel outward through the layers of the sun's interior. As it moves through these layers, it will likely interact with other particles and lose energy. Eventually, it will reach the sun's surface and be emitted into space as part of the sun's overall radiation output.

A gamma ray is produced in the core of the sun. After that, the gamma ray goes through several processes, including:

1. Photon Scattering: The gamma ray, being a high-energy photon, interacts with charged particles like protons and electrons in the solar core, changing direction and losing energy through scattering.

2. Conversion to Lower-Energy Photons: As the gamma ray scatters and loses energy, it is converted into lower-energy photons, such as X-rays, ultraviolet, visible light, and infrared radiation.

3. Radiative Transfer: Lower-energy photons gradually make their way to the outer layers of the sun through a process called radiative transfer, which involves multiple scattering events and absorption/re-emission processes.

4. Reaching the Photosphere: The photons eventually reach the photosphere, which is the visible surface of the sun. This process takes thousands of years due to the numerous interactions the photons go through during their journey.

5. Emission into Space: Once the photons reach the photosphere, they are emitted as sunlight and travel through space, eventually reaching Earth and other celestial bodies.

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One of the best ways to protect yourself from excessive exposure to radiation is to avoid unnecessary exposure. If possible, avoid getting X-rays or other types of radiation when they are not medically necessary. However, if you do need to get an X-ray, make sure it is done by a licensed professional who will take the necessary precautions to limit your exposure.

Radiation can be harmful to the human body, and exposure to excessive radiation can lead to serious health problems such as cancer and radiation sickness. Therefore, it is essential to protect yourself from excessive exposure to radiation.

Finally, increasing your distance from the source of radiation can also help protect you from excessive exposure. The further away you are from the source of radiation, the less exposure you will receive. Therefore, if you work in an environment where you are exposed to radiation, try to keep as much distance between yourself and the source as possible.

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(a) The time of 13 A current flow for 32.5 C charge is 2.5 s.

(b) The time of 13 A current flow for 62.4 C charge is 4.8 s

(c) The time of 13 A current flow for 312 C charge is 24 s.

(d) The time of 13 A current flow for 780 C charge is 60 s.

(e) The time of 13 A current flow for 1612 C charge is 124 s.

(f) The time of 13 A current flow for 812.5 C charge is 62.5 s.

(g) The time of 13 A current flow for 468 kC charge is 36,000 s.

(h) The time of 13 A current flow for 187.2 kC charge is 14,400 s.

(i) The time of 13 A current flow for 163.8 kC charge is 12,600 s.

Electric current is the flow of charges or electron in a given time period.

The relationship between charges, current and time is given as;

Q = It

t = Q / I

where;

The time of 13 A current flow for 32.5 C charge is calculated as;

t = (32.5 C ) / 13 A

t = 2.5 s

The time of 13 A current flow for 62.4 C charge is calculated as;

t = (62.4 C ) / 13 A

t = 4.8 s

The time of 13 A current flow for 312 C charge is calculated as;

t = (312 C ) / 13 A

t = 24 s

The time of 13 A current flow for 780C charge is calculated as;

t = (780 C ) / 13 A

t = 60 s

The time of 13 A current flow for 1612 C charge is calculated as;

t = (1612 C ) / 13 A

t = 124 s

The time of 13 A current flow for 812.5 C charge is calculated as;

t = (812.5 C ) / 13 A

t = 62.5 s

The time of 13 A current flow for 468 kC charge is calculated as;

t = (468,000 C ) / 13 A

t = 36,000 s

The time of 13 A current flow for 187.2 kC charge is calculated as;

t = (187,200 C ) / 13 A

t = 14,400 s

The time of 13 A current flow for 163.8 kC charge is calculated as;

t = (32.5 C ) / 13 A

t = 12,600 s

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When two charged particles are released from rest simultaneously, they repel one another and move apart. After a long time, when they are far apart, nearly all the initial electric potential energy has been converted into kinetic energy, some taken away by particle 1 and the rest by particle .

If we want to know the percentage of initial energy carried away by particle 2, we need to determine the fraction of initial energy carried away by particle 1. The sum of the fractions for both particles will be equal to one. According to the law of conservation of energy, total energy remains constant and cannot be destroyed.

We can see that the fraction of initial energy carried away by particle 1 depends on the ratio of the masses of the particles as well as their charges and final separation distance. However, we do not have enough information to calculate this fraction. Therefore, we cannot determine the percentage of the initial energy carried away by particle 2.

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Answer: 41.9 below the negative x-axis.

Explanation: To find the direction of the resultant vector, we need to use some trigonometry and vector addition. Here are the steps:

Draw a diagram of the particle’s motion and label the vectors. The particle starts at the origin and moves 7.22 cm in the negative y-direction, which we can call vector A. Then it moves 8.05 cm in the positive x-direction, which we can call vector B. The resultant vector R is the vector that goes from the origin to the final position of the particle.

Find the components of vector A and vector B. Vector A has a magnitude of 7.22cm and a direction of 270 degrees (or -90 degrees) from the positive x-axis. Vector B has a magnitude of 8.05 cm and a direction of 0 degrees (or 360 degrees) from the positive x-axis. Using trigonometry, we can find the x and y components of each vector as follows:

A_x = A cos(270) = 7.22 cos(270) = 0

A_y = A sin(270) = 7.22 sin(270) = -7.22

B_x = B cos(0) = 8.05 cos(0) = 8.05

B_y = B sin(0) = 8.05 sin(0) = 0

Add the components of vector A and vector B to get the components of vector R. Using vector addition, we can find the x and y components of the resultant vector as follows:

R_x = A_x + B_x = 0 + 8.05 = 8.05

R_y = A_y + B_y = -7.22 + 0 = -7.22

Find the magnitude and direction of vector R using Pythagoras’ theorem and inverse tangent function. The magnitude of vector R is given by the square root of the sum of the squares of its components, and the direction of vector R is given by the inverse tangent of its y component divided by its x component, as follows:

R = sqrt(R_x^2 + R_y^2) = sqrt(8.05^2 + (-7.22)^2) = sqrt(114.81) = 10.71 cm

theta = tan^-1(R_y / R_x) = tan^-1(-7.22 / 8.05) = -41.9 degrees

Adjust the direction of vector R according to its quadrant. Since vector R is in the fourth quadrant, where both x and y are positive, we need to add 360 degrees to its direction to get a positive angle measured counterclockwise from the positive x-axis, as follows:

theta = -41.9 + 360 = 318.1 degrees

Alternatively, we can express the direction of vector R as an angle measured clockwise from the negative x-axis, which is equivalent to subtracting its direction from 360 degrees, as follows:

theta = 360 - (-41.9) = 401.9 degrees

However, since angles are periodic with a period of 360 degrees, we can subtract multiples of 360 degrees from this angle to get an equivalent angle between 0 and 360 degrees, as follows:

theta = 401.9 - 360 = 41.9 degrees

Therefore, the direction of vector R is either 318.1 degrees counterclockwise from the positive x-axis or 41.9 degrees clockwise from the negative x-axis.

Hope this helps, and have a great day! =)

The average velocity of the athlete over the time interval from t = 4 to t = 6 is  -8589668868.5 meters per second.

Compute the average velocity of the athlete over the time interval t = 4 to t = 6, we need to find the displacement of the athlete during that time interval and divide it by the duration.

The displacement of the athlete can be found by subtracting the position at t = 4 from the position at t = 6:

Displacement = h(6) - h(4)

Calculate h(6), substitute t = 6 into the given equation:

h(6) = \(6^{34\) + 3(6)

To calculate h(4), substitute t = 4 into the equation:

h(4) = \(4^{34\) + 3(4)

Once you have both values, compute the displacement:

Displacement = h(6) - h(4)

Next, calculate the duration of the time interval:

Duration = t(6) - t(4) = 6 - 4

Finally, compute the average velocity by dividing the displacement by the duration:

Average Velocity = Displacement / Duration

calculate the displacement of the athlete during the time interval from t = 4 to t = 6.

h(6) = \(6^{34\) + 3(6)

= 531441 + 18

= 531459

h(4) = \(4^{34\) + 3(4)

= 17179869184 + 12

= 17179869196

The displacement is given by:

Displacement = h(6) - h(4)

= 531459 - 17179869196

= -17179337737

Calculate the duration of the time interval:

Duration = t(6) - t(4)

= 6 - 4

= 2

We can compute the average velocity:

Average Velocity = Displacement / Duration

= (-17179337737) / 2

= -8589668868.5

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From the calculations, we have the coefficient of friction as  0.026.

We know that friction has to do with the force that tends to oppose the motion of an object. As such, the point where the force of friction acts is actually the surface that lies between two bodies.

Now, we can see that It takes 6 people pulling with a force of 500 N each to begin moving the opposing team which was pulling with a combined force of 2500 N. This implies that the total force of the people that are pulling from this other side is 6 (500N) = 3000 N

Now we have the net force that is acting on the the rope as; 3000 N - 2500 N = 500 N

Then;

Coefficient of friction = Net force/ Normal reaction

= 500 N/(2000 * 9.8) N

= 0.026

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Answer:

Correct Answer: Option B

Explanation:

Explanation

P1/T1 = P2/T2

80/(273+47) = P1/(273+27) = 75Nm-2

Answer: 75.0 Nm^-2

Explanation:

P1/T1 = P2/T2 80/(273+47) = P1/(273+27) = 75Nm-2

To simplify the expression, we need to combine the fractions into a single fraction. To do this, we'll first find a common denominator for the two fractions.

The denominators are (b^2 - 2b - 15) and (b^2 + b - 30). To find the common denominator, we factorize both denominators:

The common denominator is (b - 5)(b + 3)(b + 6).

Now, let's rewrite the fractions with the common denominator:

Next, we can combine the fractions:

Expanding the numerator and simplifying further:

Combining like terms in the numerator:

Finally, we have simplified the expression to:

Restrictions on the variables:

To find any restrictions on the variables, we need to consider the values that would make the denominator zero. In this case, the denominator is (b - 5)(b + 3)(b + 6). Therefore, the restrictions on the variables are:

b ≠ 5, -3, -6

These values are excluded because they would result in a zero denominator, which would make the expression undefined.

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Explanation:

The surface tension of a liquid results from an imbalance of intermolecular attractive forces, the cohesive forces between molecules: A molecule in the bulk liquid experiences cohesive forces with other molecules in all directions. A molecule at the surface of a liquid experiences only net inward cohesive forces.

Answer: 71.6 degree farheniet

Explanation:

°F = °C × (9/5) + 32.

Given C = 22.

F = 22 × (9/5) + 32

F = 39.6 + 32

F = 71.6

Answer:

hope it helps you...........

The change in the momentum of the bus is 10600 kg-m/s, if bus of 1600 kg crashes with a SUV of 600 kg.

The mass of the bus, m₁ = 1600 kg

The mass of the SUV, m₂ = 600 kg

Initial velocity of the bus, v₁ = 10 m/s

initial velocity of the SUV, v₂ = 0 (at rest)

Velocity of the bus after collision, v₃ = 3 m/s

Velocity of the SUV after collision, v₄ = 1 m/s

The change in momentum(Δp) is given by,

Δp = (m₁v₁ + m₂v₂) - (m₁v₃ + m₂v₄)

Δp = (1600 × 10 + 600 × 0) - (1600 × 3 + 600 × 1)

Δp = 16000 - 5400

Δp = 10600 kg-m/s

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Answer:

A

Explanation:

where the hole is because it's a rigid object with uniform density.

In a perfectly inelastic collision, the final velocity of the higher-momentum object is equal to the final velocity of the lower-momentum object.

This occurs because in a perfectly inelastic collision, the two objects stick together and move as one combined object after the collision.

To understand why their final velocities are equal, let's consider the conservation of momentum in a perfectly inelastic collision.

The law of conservation of momentum states that the total momentum of a system remains constant before and after a collision, assuming no external forces act on the system. Mathematically, this can be expressed as:

(m1 + m2) * v_final = m1 * v1_initial + m2 * v2_initial

where m1 and m2 are the masses of the objects, v1_initial and v2_initial are their initial velocities, and v_final is their final velocity after the collision.

In a perfectly inelastic collision, the objects stick together, so they move with the same final velocity v_final. Therefore, the equation can be written as:

(m1 + m2) * v_final =m1 * v1_initial + m2 * v2_initial

Since the objects stick together and move as one, their masses add up (m1 + m2). Rearranging the equation, we get:

v_final = (m1 * v1_initial + m2 * v2_initial) / (m1 + m2)

As you can see, the final velocity v_final is determined by the initial velocities and the masses of the objects involved in the collision.

However, notice that both the initial velocities and masses appear in the numerator of the equation. Therefore, regardless of the initial velocities or masses, the final velocity will be the same for both objects in a perfectly inelastic collision.

In a perfectly inelastic collision, the final velocity of the higher-momentum object is equal to the final velocity of the lower-momentum object.

This is due to the conservation of momentum, where the total momentum before and after the collision remains constant. The objects stick together and move as one combined object, resulting in the same final velocity for both objects.

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The calculated value is 5:2.

The reciprocal of the focal length is used to calculate a lens's power. In diopter's, lens power is expressed (D). Positive focal lengths and positive power values are characteristics of convergent (convex) lenses. Negative focal lengths and negative power values are characteristics of diverging (concave) lenses.

Given that a N l =1.25 and a Ng =1.5

The focal length of a glass (g) lens in a medium (m) may be calculated using the formula

f1= (mNg 1) [1/R1/ 1/R2].

fa1 = (aNg1) [1/R1/ 1/R 2] while the lens is in the air.

When the lens is submerged in liquid, f l1 = (aNg 1) [1/R 1/1/R2] =1.5/1.25, which divides equation 1 by equation 2, and

fi/fa = (1.5/1.251)/ (1.51)

=5/2 or

Pa / Pi = 5/2 (since f=1/P).

Therefore, Pa:Pi= 5:2.

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Answer: true

Explanation:

Answer:

True

Explanation: