Answer:
inertia:
a tendency to do nothing or to remain unchanged.
balanced force:
When two forces acting on an object are equal in size but act in opposite directions.
unbalanced force:
When two forces acting on an object are not equal in size.
N2 + 3H2 + 2NH3
What type of reaction is this
Answer:It is a combination reaction; nitrogen and hydrogen combine to form ammonia
Explanation:
This is the reaction that is used to make ammonia from hydrogen and nitrogen. In this reaction, only one product is formed. Therefore, this reaction is known as a combination reaction.
An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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How many valence electrons do most stable atoms have?
A) one
B) two
C) four
D) eight
Answer:
D) 8
Explanation:
Due to the octet rule the most stable atoms will have 8 valence electrons.
Identify the energy levels from which the 410.2 nm emission line of the Balmer series of the
hydrogen atom originates, i.e., state the values of ninitial and nfinal. What is the frequency of the
radiation involved in the transition between these levels?
The energy level from which is emitted is n = 6
The frequency is\(7.3 * 10^14\) Hz
What is the energy level?The Rydberg equation is a mathematical formula that relates the wavelengths of light emitted by an atom to the energy levels of its electrons.
Using the Rydberg equation;
1/λ= RH (1/\(n_{2}^2\) - 1/\(n_{1} ^2\))
1/\(410.2 * 10^-9\) = \(1.097 * 10^7\)(1/\(2^2\) - 1/ /\(n_{1} ^2\))
1/\(4.102 * 10^-7\) = \(1.097 * 10^7\)(1/4 - 1/\(n_{1} ^2\))
1/\(4.102 * 10^-7\) * 1/ \(1.097 * 10^7\) = (1/4 - 1/\(n_{1} ^2\))
0.22 = 0.25 - 1/\(n_{1} ^2\)
0.22 - 0.25 = - 1/\(n_{1} ^2\)
-0.03 = - 1//\(n_{1} ^2\)
\(n_{1}\) = 6
Using;
f = c/λ
\(3 * 10^8/4.102 * 10^-7 \\f = 7.3 * 10^14 Hz\)
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A solid weighs 237.5 g in air and 12.5 g in a liquid in which it is wholly submerged. The density of the liquid is 900 kg/m³.
Calculate (1) the density of the solid (il) the density of another liquid in which the same solid would float with one-fifth of its volume exposed above the liquid surface.
(i) The density of the solid is 950 kg/m³
(ii) the density of another liquid in which the same solid would float is 200 kg/m³
The given parameters;
mass of the solid in air, Ma = 237.5 g
mass of the solid in liquid, Ms = 12.5 g
density of the liquid, \(\rho_l = 900 \ kg/m^3\)
(i) The density of the solid is calculated as follows;
Weight in air - Weight in liquid = upthrust
\(\frac{\rho_o}{\rho_l} = \frac{Ma}{M_a - Ms} \\\\\frac{\rho_o}{900} = \frac{237.5}{237.5 - 12.5}\\\\\frac{\rho_o}{900} =1.0556\\\\\rho_o = 1.0556 \times 900\\\\\rho_o = 950 \ kg/m^3\)
(ii) the density of another liquid in which the same solid would float with one-fifth of its volume exposed above the liquid surface.
This is a low density liquid, because one-fifth of the solid is above the liquid surface while four-fifth is below the liquid surface.
the specific gravity of the liquid = ¹/₅ = 0.2
density of water , \(\rho_w = 1000 \ kg/m^3\)
\(S.G = \frac{\rho_l}{\rho_w} \\\\0.2 = \frac{\rho_l}{1000} \\\\\rho_l = 0.2 \times 1000\\\\\rho_l = 200 \ kg/m^3\)
Thus, the density of another liquid in which the same solid would float is 200 kg/m³
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How does a trampoline work? Make sure to include which law explains this
Determine the magnitude of current in the 6 Ω resistor shown in Figure 3 if emf 1 has
an internal resistance of 1 Ω and emf 2 has an internal resistance of 0.2 Ω.
The magnitude of current in the 6Ω resistor is 0.72A.
EMF stands for electromotive force, which is the energy supplied by a source (such as a battery or generator) per unit of charge that passes through it, measured in volts. It represents the potential difference between the two terminals of the source when it is not connected to any circuit.
From the circuit diagram, we can see that the current flowing through the 6Ω resistor can be found by using Ohm's Law:
V = IR
where V is the voltage across the 6Ω resistor, I is the current flowing through it, and R is the resistance of the resistor.
To find V, we need to use Kirchhoff's Voltage Law (KVL) to determine the total voltage drop across the circuit. Starting from the top left corner and moving clockwise, we have:
V1 (emf) = IR1 + V2 (emf)
V2 (emf) - IR2 - IR1 = 0
Substituting V2 = -IR2 - 0.2I (since emf 2 has an internal resistance of 0.2Ω) into the first equation, we get:
V1 = I(R1 + R2 + 1) + 0.2I
Simplifying, we get:
V1 = I(7Ω) + 0.2I
Now we can solve for I:
I = V1 / (7Ω + 0.2Ω)
I = V1 / 7.2Ω
To find V1, we can use KVL again, starting from the bottom left corner and moving clockwise:
V1 - IR1 - V2 = 0
V1 - IR1 - (IR2 + 0.2I) = 0
Substituting V2 = -IR2 - 0.2I, we get:
V1 = I(R1 + R2 + 0.2) = I(7.2Ω)
Now we can substitute this expression for V1 into the equation for I:
I = (I(7.2Ω)) / (7Ω + 0.2Ω)
Simplifying, we get:
I = 0.72A
Therefore, the magnitude of current in the 6Ω resistor is 0.72A.
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Which of your drawings approximates the orbit of Halley's comet about the sun?
Answer:
What???
Explanation:
Answer:
It is a elipse and it comes super close to the sun only to be launched back past pluto and then return back
Explanation:
Due to the conservation of angular momentum, what will happen to the rotation speed of a large, Red Giant star when it undergoes a Type II Supernova explosion and collapses into a compact Neutron Star? Note: Consider only what happens to the star during its collapse, not what may happen to it later.
During a Type II supernova explosion, a Red Giant star collapses in on itself and the core of the star undergoes a rapid implosion, causing it to form a compact neutron star.
Rotation speed of Neutron StarsDuring a Type II supernova explosion, a Red Giant star collapses in on itself and the core of the star undergoes a rapid implosion, causing it to form a compact neutron star. This process involves a large amount of angular momentum being conserved, meaning that the rotation speed of the star will increase significantly.
This is due to the conservation of angular momentum, which states that the total angular momentum of a system remains constant unless acted upon by an external torque. The Red Giant star has a large moment of inertia due to its size and rotation, and when it collapses into a much smaller neutron star, the moment of inertia decreases significantly.
In order to conserve angular momentum, the rotational speed of the neutron star must increase significantly to compensate for the decreased moment of inertia. This increase in rotational speed can be quite dramatic, with some neutron stars rotating hundreds of times per second.
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Calculate the average speed between 0 s and 20 s
Answer:
2 m/s
Explanation:
The following data were obtained from the question:
Distance (D) = 40 m
Time (t) = 20 s.
Average speed =?
Average speed is the total distance travelled divided by the total time taken. Mathematically, it is expressed as:
Average speed = Total distance /Total time
Thus, we can obtain the average speed as follow:
Total Distance (D) = 40 m
Time time (t) = 20 s.
Average speed =?
Average speed = Total distance /Total time
Average spee= 40/20
Average speed = 2 m/s
Therefore, the average speed between 0 and 20 seconds is 2 m/s.
A 10-KG mass is lifted upward, by a light cable . what is the tension in the cable if the acceleration is (A) zero, (B) 6m/s2 upward , and (C) 6m/s2 downward
Answer:
(a) 98 N
(b) 158 N
(c) 38 N
Explanation:
Part (a)When the acceleration is 0 m/s², the net force on the mass is 0 N. Therefore, the tension force is equal to the weight force due to Newton's Second Law:
∑F_y = T - w = ma_y ∑F_y = T - w = m(0 m/s²)∑F_y = T - w = 0 ∑F_y = T = wSince the tension in the cable and the weight of the mass are equal to each other, we can solve for the weight force of the mass by using:
w = mg w = (10 kg)(9.8 m/s²)w = 98 NSince T = w, we can say that T = 98 N.
Part (b)Let's set the upwards direction to be positive and the downwards direction to be negative. We can use Newton's Second Law to solve for the tension in the cable if the acceleration is 6 m/s² upward:
∑F_y = T - w = ma_y∑F_y = T - mg = m(6 m/s²)∑F_y = T - mg = 6mPlug the known values into the equation and solve for T.
T - mg = 6mT - (10 kg)(9.8 m/s²) = 6(10 kg) T - 98 = 60 T = 158 NThe tension in the cable if the acceleration is +6 m/s² is 158 N.
Part (c)The process is the same, but this time acceleration is -6 m/s².
∑F_y = T - w = ma_y∑F_y = T - mg = m(-6 m/s²)∑F_y = T - mg = -6mPlug known values into the equation and solve for T.
T - mg = -6mT - (10 kg)(9.8 m/s²) = -6(10 kg) T - 98 = -60 T = 38 NThe tension in the cable if the acceleration is -6 m/s² is 38 N.
In music, the note G above middle C has a frequency of about 392 hertz. If the speed of sound in the air is 340 m/s, what is the approximate wavelength of this note?(1 point)
0.87 meters
0.0026 meters
1.2 meters
8.7 meters
(cmmt if you wanna be added to a physics B ig gc)
Answer:
1.2 meter because the equa
Answer:
1.) 2 seconds
2.) 4.5 hertz
3.) it will become one third its original value
4.) 5.9 seconds
5.) 0.87 meters
Explanation:
just took the connexus quick check
A student is making a model of the famous Giza pyramid,
which has four triangular sides and a square base. The
scale of the model is 1:1,000.
How many sides should the model pyramid have?
Answer:
The Great Pyramid of Giza (also known as the Pyramid of Khufu or the Pyramid of Cheops) is the oldest and largest of the pyramids in the Giza pyramid complex bordering present-day Giza in Greater Cairo, Egypt.It is the oldest of the Seven Wonders of the Ancient World, and the only one to remain largely intact.
Explanation:
Six identical cells with an EDS of 3 V connected in a battery. Resistors R₁ and R₂=16Ω are connected to the battery, the total resistance of the external circuit is R=6Ω and the current flowing in it is 1 A. Determine the resistance of the first resistor and the EDS and internal resistance of the battery.
- The resistance of the first resistor (R₁) is 12 Ω.
- The electromotive force (EMF) of the battery is 18 V.
- The internal resistance of the battery is 12 Ω.
To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.
Let's start by calculating the resistance of the first resistor (R₁):
1. Apply Ohm's law to find the voltage drop across the external circuit:
V = I * R
V = 1 A * 6 Ω
V = 6 V
2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:
V = E - Ir
6 V = E - (1 A * r) (where r is the internal resistance of the battery)
3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:
E = 6 cells * 3 V/cell
E = 18 V
4. Substitute the value of E in the equation from step 2:
6 V = 18 V - r
r = 12 Ω
Therefore, the resistance of the first resistor (R₁) is 12 Ω.
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A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
a. How much work does he do on the wall? ____________
b. How much energy is used?__________
c. How much power is exerted?____________
Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.
What is force?In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.
Here,
a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.
b. Since no work is done, no energy is used or transferred.
c. The power exerted by the man can be calculated using the formula:
Power = Work / Time
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in the figure a plane mirror MN of height h is mounted in an adjustable vertical position on vertical wall E is an observers eye which is 1 m from the wall and 1.5 above the ground PQ is a vertical post of height 3 m and is 4 m behind the observer. looking into the mirror the observer can see the whole image of the post what’s the minimum value of h
The minimum value of h is 3.75 meters.
To determine the minimum value of h, we need to consider the geometry of the situation.
From the given information, we know that the observer's eye is 1 m from the wall and 1.5 m above the ground. The vertical post-PQ is 3 m tall and located 4 m behind the observer. The observer can see the whole image of the post in the mirror.
Since the observer can see the entire image of the post, we can conclude that the line of sight from the top of the post to the observer's eye must be parallel to the line of sight from the bottom of the post to the observer's eye. This is because the mirror reflects light rays at equal angles of incidence and reflection.
Let's denote the height of the observer's eye from the ground as x. We can set up a proportion to find the height of the image of the post in the mirror:
(Height of post-PQ) / (Distance from observer to post) = (Height of the image in the mirror) / (Distance from mirror to image)
Using the given values, we have:
3 m / 4 m = h / (4 m + 1 m)
Simplifying the equation:
3/4 = h/5
Cross-multiplying:
4h = 15
h = 15/4 = 3.75 m
Therefore, the minimum value of h is 3.75 meters.
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How do you find the number of electrons, protons and neutrons that are in
the atom of an element with the aid of an example
If the atomic number is given then the number of electrons and protons is the same as the atomic number, but the number of neutrons can be calculated by subtracting the atomic number from the atomic mass number of the element.
What is the Atomic mass number?We know that inside the nucleus protons and neutrons are present, the sum of the protons and newtons is called the atomic mass number. and the electron revolves around the nucleus for the stability of an element the number of positive charges (protons ) should be the number of negative charges (electrons).
For example, take Fluorine(F)
Fluorine has a mass number(M)= 19
Atomic number(Z) =9
Now no. of protons in fluorine is = 9
no. of electrons in fluorine is= 9
no of newton in fluorine= M-Z=19-9=10
Hence the number of protons and electrons are same as the atomic number and the number of neutrons is the difference between the atomic mass number and the no f protons or the atomic number.
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how to get the main scale and vernier scale once you have already the total reading?
Answer:
Explanation:
How to find main scale and vernier scale reading?
Follow these steps to read the vernier scale:
Read the main scale. Look for the last whole increment visible before the 0 (zero) mark.
Read the secondary scale (Vernier) measurement. This is the division tick mark that lines up best with a mark on the main scale.
Add the two measurements together.
How do you find the main scale reading?
The main scale on a Vernier caliper typically tells you the whole number plus the first decimal. Read this just as you would a ruler, measuring to the zero mark on the sliding (Vernier) scale. For example, if the 0 on the sliding scale lines up with the 2 inch mark, your measurement is 2 inches
A pinball machine launches a .045 kg ball at a speed of 9.2 m/s. Determine the potential energy of the spring just before it launched the pinball
Given :
A pinball machine launches a .045 kg ball at a speed of 9.2 m/s.
To Find :
The potential energy of the spring just before it launched the pinball.
Solution :
We know, their is no external force applied on system.
It means that kinetic energy will remains constant.
Initial Energy = Final Energy
\(K.E_i + P.E_i = K.E_f + P.E_f\\\\0 + P.E_i= \dfrac{mv^2}{2}+ 0\\\\P.E_i = \dfrac{0.045 \times 9.2^2}{2}\ J\\\\P.E_i = 1.9044\ J\)
Therefore, the potential energy of the spring just before it launched the pinball os 1.9044 J.
Can someone please help me with this one
Answer:
im pretty sure the answer is A. up but im not 100% sure
The product of an object's mass and velocity is it's
A) acceleration
B) inertia
C) momentum
D) weight
Answer:
C) Momentum
Explanation:
Refers to an objects mass in motion.
A gas expands from I to F in the figure. The energy added to the gas by heat is 465 J when the gas goes from I to F along the diagonal path. What is the change in internal energy of the gas?
The gas's internal energy that expands from I to F changes by 1015 J.
How to determine internal energy?Since the gas is expanding and energy is added to it by heat, the change in internal energy of the gas can be calculated using the first law of thermodynamics, which states that:
ΔU = Q - W
where ΔU = change in internal energy,
Q = heat added to the system, 465 J and
W = work done by the system.
Assuming that the process is quasi-static use approximation known as the "staircase approximation."
By adding up the work done in each step, find that the total work done by the gas is approximately -550 J. The negative sign indicates that work is done on the gas.
Therefore, using the first law of thermodynamics, we can calculate the change in internal energy of the gas as:
ΔU = Q - W
ΔU = 465 J - (-550 J)
ΔU = 1015 J
Therefore, the change in internal energy of the gas is 1015 J.
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An object has temperature of 2310° C. Calculate the wavelength this object emits the most. Give the answer in micrometers with two
significant figures.
The wavelength at which the object emits the most radiation is 1.12 micrometers.
How do we perform the calculation?We use Wien's displacement law in order to find the wavelength at which the object emits the maximum radiation.
The temperature of the item has an inverse relationship with the peak wavelength of the radiation it emits according to Wien's displacement law,
The formula of Wien's displacement law, is given as
λ_max = b/T
where λ_max =e peak wavelength of emitted radiation,
T = temperature of the object in Kelvin, and
b = Wien's displacement constant 2.898 × 10^-3 mK.
T = 2310°C + 273.15 = 2583.15 K
λ_max = (2.898 × 10^-3 mK) / 2583.15 K
λ_max = 1.12 × 10^-6 m = 1.12 μm
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What conditions are needed for germination?
Air, water, and warmth
Cold air, water, and soil
Water, warmth, and a good location
Warmth, water, and wind
Answer:
I think it would be A
Explanation:
Air, water, and warmth
Excuse my mistake if I get it wrong.
Answer:
I think it would be A
Explanation:
Air, water, and warmth
hopes this helps
A particle is moving with a constant velocity in the +x
+
x
-direction. When the particle reaches the origin, a constant force is exerted on it in the +y
+
y
-direction. Which of the following graphs best shows the path the particle will follow?
Answer:
The options are not shown, so i will answer in a general way:
We can separate the problem in two cases.
The movement in the x-axis, that is unperturbed, so the particle will keep moving in the +x direction with the same speed.
The movement in the y-axis, as a constant force is applied, by the second Newton's law:
F = m*a
a = F/m = constant
v = a*t + v0
p = (a/2)*t^2 + v0*t + p0
Where v0 = initial velocity in the y-axis, p0 = initial position (in this case the origin) and t is the time. (In this case, these values really do not matter, i only want to show the general equations of movement in the y-axis)
We will also have a constant acceleration, which means that the velocity in this axis will be linear, and the position quadratic, then after the particle reaches the origin, it will start moving up and to the right, and the upward movement will increase in magnitude as time passes, a graph in the x-y plane would be something like:
eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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Steve is given extra chores each time he hits his little brother. After a few times of having extra chores given to him, Steve's misbehavior toward his little brother decreases. This is an example of __________
Steve's misbehavior toward his little brother decreases. This is an example of Positive punishment
What is positive punishment?
Positive punishment is a variation is a conditioning theory. Its major goal is to minimize future behavior frequency by delivering an unpleasant stimulation after the action has occurred.
Steve is given extra chores each time he hits his little brother. After a few times of having extra chores given to him.
Steve's misbehavior toward his little brother decreases. This is an example of Positive punishment.
Hence positive punishment is the right answer.
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A cheetah runs at a constant velocity of 7 m/s. What is it’s acceleration in m/s/s
PLEASE HELP
Answer:
0 m/s²
Explanation:
Acceleration is the change in velocity over change in time. If the velocity is constant, then the acceleration is 0.
How far an object moves from a reference point is known as
type your answer...
Answer:
distance
hope it helps
Explanation:
-
what happens to the weight and mass of an object transported from earth to the moon
When an object transported from earth to the moon, its mass remains same but weight becomes 1/6th that on earth..
What is mass?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter.
It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The change caused by an applied force is smaller the more mass a body has.
What is weight?The amount of a body's weight indicates how much gravity is pulling on it. Weight is calculated using the method w = mg. Since weight is a force, it has the same SI unit as a force, which is the Newton (N).
So, mass of an object is intrinsic property of the object - it remains same in earth and in moon. But weight is the amount of gravitational attraction force. Moon has nearly 1/6th gravitational attraction field. So, the weight of the object on moon will be 1/6th that on earth.
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