Given: Y is the midpoint of XZ
Prove: XY = 1/2 XZ
Statements
Reasons

Answer:

ok I don't know need help to

Ross's profit percentage is 17%.

How to calculate the percentages?

To calculate a percentage, you need to divide the part by the whole and then multiply the result by 100. The formula is:

Percentage = (part/whole) x 100

Let's work through the problem step by step:

Ross bought the chair for 1000.

1. He marked it up by 30%, which means he added 30% of 1000 to the original price:

\(1000 + 0.3 * 1000 = 1300\)

2. He gave a discount of 10%, which means he subtracted 10% of the marked-up price:

\(1300 - 0.1 * 1300 = 1170\)

3. The customer paid 1228.50 inclusive of a 5% tax, which means the original price before tax was:

1228.50 / 1.05 = 1170

4. Ross's profit was the difference between the price he sold the chair for and the price he bought it for:

1170 - 1000 = 170

5. To find the profit percentage, we divide the profit by the cost and multiply by 100:

\((170 / 1000) * 100 = 17%\)

Hence, Ross's profit percentage is 17%.

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The Heaviside step function, often denoted as u(t), is a mathematical function that represents a unit step at t = 0. It is defined as follows:

u(t) = 0, for t < 0

u(t) = 1, for t ≥ 0

It is a piecewise-defined function that jumps from 0 to 1 at t = 0. It is widely used in engineering, physics, and mathematics to model sudden changes or switches in a system.

Examples of the Heaviside step function:

Shifted Heaviside step function:

u(t - a) represents a step function that occurs at t = a instead of t = 0. It has the same properties but is shifted along the time axis.

Scaled Heaviside step function:

b * u(t) represents a step function that is scaled by a factor of b. It jumps from 0 to b at t = 0.

Summed Heaviside step function:

u(t - a) + u(t - b) represents a combination of two shifted step functions occurring at different times a and b. It can be used to model systems with multiple switches or events.

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Answer: Systematic sampling is a type of probability sampling method where sample members from a larger population are selected based on a random starting point but with a fixed, periodic gap.

Step-by-step explanation:

Answer:

the answer is b

Step-by-step explanation:

hoped that helped

Answer:

Step-by-step explanation:

I got x=2.779 sorry if it's not right

A(n) IQ test evaluates a child's performance in relation to other kids in terms of how well they can perform specific activities at a specific time.

Each individual IQ exam is made up of a number of smaller questions, and no reading nor writing are required. Some verbal subtests consist of spoken questions with no set time restriction. Other subtests are frequently timed and typically have a visual or spatial focus. It takes one to two hours to give the exam.

115 to 129: Superior or intelligent. 130 through 144: Fairly talented. From 145 through 159: Very talented. Exceptionally talented from 160 to 179.

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the closest measurement to the volume of the prism in cubic inches is

J. \(12 inches^3.\)

What is volume?

The area that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.

Many forms have various volumes. We have studied the several solids and forms that are specified in three dimensions, such as cubes, cuboids, cylinders, cones, etc., in 3D geometry. We will discover how to find the volume for each of these shapes.

from the question:

We must multiply the rectangular prism's length, width, and height to determine its volume. We can observe from the photograph that the rectangle's dimensions are roughly 5.5 inches long and 4 inches wide. Hence, the rectangular prism's volume is:

Volume = Length x Width x Height

= 5.5 inches x 4 inches x 218 inches

= 4 x 5.5 x 218 \(inches^3\)

= 4 x 1199 \(inches^3\)

= 4796\(inches^3\)

4796 cubic inches is the result when we round this response to the nearest whole number. J. 12 inches3 is the measurement that most closely approximates the prism's volume in cubic inches.

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Answer:

1568 in^3

Step-by-step explanation:

Answer:

Volume = 1,568

Step-by-step explanation:

V = Bh

B = 17.5 x 14 = 245

h = 6.4

245 x 6.4 = 1,568

The easier way:

17.5 x 14 x 6.4 = 1,568

Let me know if this helps!

Answer:

15

Step-by-step explanation:

its 90 degrees so the other side will be the same

Answer:

b=20

Step-by-step explanation:

a^2 + b^2 = c^2

15^2 + b^2 = 25^2

225 + b^2 = 625

b^2 = 625-225

b^2 = 400

b = 20

Answer:

x° = 35°

Step-by-step explanation:

at 125° to get the opposite angle

180° - 125° = 55°

then,

x° + 90° + 55° = 180°

x° = 180° - 145°

x° = 35°

The equation of the relation between the time and the total number of cassavas is 0.429T

Rate of change:

Rate of change is defined as the rate at which one quantity is changing with respect to another quantity.

It can be calculated by, the amount of change in one item is divided by the corresponding amount of change in another.

So, the formula is,

Rate of change = (Change in quantity 1) / (Change in quantity 2)

Given:

Carlos gives  35 minutes to harvest a total of 15 cassavas.

First, we have to find the total number of cassavas.

We know that, Carlos harvests cassava at constant rate is 35 minutes per 15 cassavas

So,

=> 15/35

=>0.429

To write the equation,

Let us consider, A formula for the quantity of cassava (C) that Carlos harvests each time (T).

So, based on this, we know that, after 35 minutes, 15 cassavas have been harvested, after 70 minutes, 30 cassavas, and so on.

Based on this fact we have write the equation as

=> 0.429T

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Step-by-step explanation:

just look at the graph ! what answer options can be possible, when you look at the first and the last point ?

the position km are 40 and 15.

the first answer option is the right one.

The value of the total area of the shaded region are,

⇒ 42 units²

We have to given that;

Sides of rectangle are,

AB = 9

BC = 6

Hence, The area of rectangle is,

⇒ 9 x 6

⇒ 54 units²

And, Area of triangle is,

A = 1/2 × 4 × 6

A = 12 units²

Thus, The value of the total area of the shaded region are,

⇒ 54 - 12

⇒ 42 units²

So, The value of the total area of the shaded region are,

⇒ 42 units²

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Answer:

ABDC

Step-by-step explanation:

Company A B C D

Sales 110(0.70)x 140(1.07)x 430(1.90)x 310(1.14)x

the order from least to greatest is

110,140,310,430 or

ABDC

The solution for the given quadratic equation would be x = √8 and x = -√8.

What are quadratic equations?

A quadratic equation is an equation that can be written in the form\(ax^2 + bx + c = 0\) where x is the variable, and a, b, and c are coefficients. The variable x is the unknown value in the equation and the goal is to find the value(s) of x that make the equation true. The graph of a quadratic equation is a parabola. The general form of a quadratic equation is:

\(ax^2 + bx + c = 0\)

Where x is the variable and a, b, and c are constants.

The given equation is x^2 = 8, which is a quadratic equation.

The solutions to the equation x^2 = 8 are x = √8 and x = -√8.

Hence, the solution for the given quadratic equation would be x = √8 and x = -√8.

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Main Answer: The below code will generate a plot showing the CDF of X for p = 1/2 (black line) and p = 3/4 (red line) up to 10 toss.

Supporting Question and Answer:

What is the purpose of defining the scope of a project?

Defining the scope of a project helps establish the boundaries and objectives of the project, determining what is included and what is not. It sets clear expectations, outlines deliverables, and helps manage resources effectively. By defining the scope, project stakeholders can align their understanding of project goals and ensure that the project stays focused and on track.

Body of the Solution:To find the cumulative distribution function (CDF) of the random variable X, we need to calculate the probability that X takes on a specific value or less. In this case, X represents the number of tosses required until the first head is obtained.

For p = 1/2:

The probability of obtaining a head on the first toss is p = 1/2.

The probability of obtaining a head on the second toss is (1 - p) * p

= (1/2) * (1/2)

= 1/4.

The probability of obtaining a head on the third toss is (1 - p)^2 * p

= (1/2)^2 * (1/2) = 1/8. And so on.

The CDF of X can be calculated as follows:

CDF(X = 1) = p = 1/2

CDF(X = 2) = p + (1 - p) * p

= 1/2 + (1/2) * (1/2)

= 3/4

CDF(X = 3) = p + (1 - p) * p + (1 - p)^2 * p

= 1/2 + (1/2) * (1/2) + (1/2)^2 * (1/2)

= 7/8 And so on.

For p = 3/4:

The probability of obtaining a head on the first toss is p = 3/4.

The probability of obtaining a head on the second toss is (1 - p) * p

= (1/4) * (3/4) = 3/16.

The probability of obtaining a head on the third toss is (1 - p)^2 * p = (1/4)^2 * (3/4)

= 9/64. And so on.

The CDF of X can be calculated similarly as before:

CDF(X = 1) = p = 3/4

CDF(X = 2) = p + (1 - p) * p = 3/4 + (1/4) * (3/4)

= 15/16

CDF(X = 3) = p + (1 - p) * p + (1 - p)^2 * p

= 3/4 + (1/4) * (3/4) + (1/4)^2 * (3/4)

= 57/64 And so on.

To plot the CDF of X for p = 1/2 and p = 3/4 using R, you can use the following code:

To plot the CDF of X for p = 1/2 and p = 3/4 using R, you can use the following code:

# Define the probability p

p1 <- 1/2

p2 <- 3/4

# Calculate the CDF for X

x <- 1:10 cdf1 <- cumsum(p1 * (1-p1)^(x-1))

cdf2 <- cumsum(p2 * (1-p2)^(x-1))

# Plot the CDF plot(x, cdf1, type="s", ylim=c(0, 1), xlab="X", ylab="CDF", main="CDF of X for p=1/2 and p=3/4")

lines(x, cdf2, type="s", col="red")

legend("topleft", legend=c("p=1/2", "p=3/4"), col=c("black", "red"), lty=1)

This code will generate a plot showing the CDF of X for p = 1/2 (black line) and p = 3/4 (red line) up to 10 toss.

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The below code will generate a plot showing the CDF of X for p = 1/2 (black line) and p = 3/4 (red line) up to 10 toss.

Defining the scope of a project helps establish the boundaries and objectives of the project, determining what is included and what is not. It sets clear expectations, outlines deliverables, and helps manage resources effectively. By defining the scope, project stakeholders can align their understanding of project goals and ensure that the project stays focused and on track.

To find the cumulative distribution function (CDF) of the random variable X, we need to calculate the probability that X takes on a specific value or less. In this case, X represents the number of tosses required until the first head is obtained.

For p = 1/2:

The probability of obtaining a head on the first toss is p = 1/2.

The probability of obtaining a head on the second toss is (1 - p) * p

= (1/2) * (1/2)

= 1/4.

The probability of obtaining a head on the third toss is (1 - p)^2 * p

= (1/2)^2 * (1/2) = 1/8. And so on.

The CDF of X can be calculated as follows:

CDF(X = 1) = p = 1/2

CDF(X = 2) = p + (1 - p) * p

= 1/2 + (1/2) * (1/2)

= 3/4

CDF(X = 3) = p + (1 - p) * p + (1 - p)^2 * p

= 1/2 + (1/2) * (1/2) + (1/2)^2 * (1/2)

= 7/8 And so on.

For p = 3/4:

The probability of obtaining a head on the first toss is p = 3/4.

The probability of obtaining a head on the second toss is (1 - p) * p

= (1/4) * (3/4) = 3/16.

The probability of obtaining a head on the third toss is (1 - p)^2 * p = (1/4)^2 * (3/4)

= 9/64. And so on.

The CDF of X can be calculated similarly as before:

CDF(X = 1) = p = 3/4

CDF(X = 2) = p + (1 - p) * p = 3/4 + (1/4) * (3/4)

= 15/16

CDF(X = 3) = p + (1 - p) * p + (1 - p)^2 * p

= 3/4 + (1/4) * (3/4) + (1/4)^2 * (3/4)

= 57/64 And so on.

To plot the CDF of X for p = 1/2 and p = 3/4 using R, you can use the following code:

To plot the CDF of X for p = 1/2 and p = 3/4 using R, you can use the following code:

# Define the probability p

p1 <- 1/2

p2 <- 3/4

# Calculate the CDF for X

x <- 1:10 cdf1 <- cumsum(p1 * (1-p1)^(x-1))

cdf2 <- cumsum(p2 * (1-p2)^(x-1))

# Plot the CDF plot(x, cdf1, type="s", ylim=c(0, 1), xlab="X", ylab="CDF", main="CDF of X for p=1/2 and p=3/4")

lines(x, cdf2, type="s", col="red")

legend("topleft", legend=c("p=1/2", "p=3/4"), col=c("black", "red"), lty=1)

This code will generate a plot showing the CDF of X for p = 1/2 (black line) and p = 3/4 (red line) up to 10 toss

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True, a pie chart should be considered when you have just one data series to plot. A pie chart is a circular chart that is divided into slices to represent numerical proportions.

Each slice of the pie chart represents a category or percentage of a whole. Pie charts are useful when you want to display relative proportions or percentages of a single data series. They are easy to understand and provide a quick visual representation of data. However, pie charts are not recommended for complex data sets or when comparing multiple data series. In such cases, a bar chart or a line graph may be a better option. It is important to choose the right type of chart based on the nature of the data and the purpose of the visualization.

True, a pie chart should be considered when you have just one data series to plot. A pie chart is a circular graphical representation of data that displays the size of items in one data series as a proportion of the total sum of the items. The individual data points are shown as slices or segments of the pie, with each segment's size representing the proportion of the whole.

Pie charts are particularly useful for visualizing percentages and proportions of a whole, and they work best when there are a limited number of categories in the data series. They are simple and easy to understand, making them a popular choice for presenting information to a broad audience.

However, pie charts may not be the best choice for every situation. If there are too many categories, the segments may become too small to easily distinguish between them. Additionally, if you need to compare multiple data series or trends over time, other chart types, such as bar or line charts, might be more appropriate.

In summary, pie charts are an effective choice for visualizing a single data series with a limited number of categories, especially when the goal is to show proportions or percentages. If these conditions are met, a pie chart can be a useful and easily understood way to display your data.

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= ∂V∂t + (V⋅∇)V

In mathematics, the complete derivative of a function f at a point is the best linear approximation near that point of the function with respect to its arguments. Unlike partial derivatives, the total derivative approximates a function with respect to all of its arguments, not just one. Pressure is defined as force/area, and the derivatives of pressure physically correspond to the rate of change of this quantity. If the derivatives are with time, the derivatives will tell you how fast the pressure is changing with time, just like any function.a = dVdt = ∂V∂t + u∂V∂x+v∂V∂y+w∂V∂z = ∂V∂t + (V⋅∇)V

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Answer:

2 ft

Step-by-step explanation:

Given that Dimensions of rectangular plot are: 26 feet by 30 feet

Length is 26 ft

Width is 30 ft

Area of rectangle = Length \(\times\) Width

So, area of given rectangular field is = 26 \(\times\) 30 = 780 sq ft

Let the width of the walk = \(x\) ft

Kindly refer to the attached image for the given scenario.

Dimensions of the plot with walk = (26+2\(x\)) ft by (30+2\(x\)) ft

So, area of plot without walk = 780 sq ft

Area of walk = Area with walk - Area of plot

Now, we are given that area of walk = 240 sq ft

So, we get:

240 = (26+2\(x\)) \(\times\) (30+2\(x\)) - 840

\(\Rightarrow (26+2x)(30+2x)=780+240\\\Rightarrow 780+4x^2+112x=780+240\\\Rightarrow 4x^2+112x-240=0\\\Rightarrow x^2+28x-60=0\\\Rightarrow x^2+30x-2x-60=0\\\Rightarrow x(x+30)-2(x+30)=0\\\Rightarrow x = 2, -30\ ft\)

\(x\) can not be negative, so \(x = 2\ ft\)

So, the width of the walk = 2 ft

Answer:

747+9+83=839

Step-by-step explanation:

We can use 9x83=747 as a extra help to get the answer. Say you need the answer above (which I gave you) so you get 9x83 as an example to help figure out 749+9+83=839.

Answer:

35

Step-by-step explanation:

Answer:

35

Step-by-step explanation:

Answer:

1.) The Remainder Theorem states that if a polynomial is divided by (x – a), the remainder is the value of the function at a. So, if (x – a) is a factor of P(x), then P(a) = 0. Determine whether the given binomial is a factor of the polynomial P(x).

2.) if there is a remainder then it is not a factor

3.) x-2 divided by x^3+5x^2-2x+9        

 across you have

×

2           1 5 -2 9

+              2  14 24

__________________

          1   7   12    33

your remainder is 33 so x-2 is not a factor of x^3+5x^2-2x+9

I hope this is good enough:

The acceleration of the particle at \(t = 2\) seconds is \(4\) cm/s².

To find the acceleration of the particle at \(t = 2\) seconds, we need to differentiate the position function twice with respect to time. First, let's differentiate the position function \(s(t)\) once to find the velocity function \(v(t)\). Using the chain rule, we have:

\(\(v(t) = \frac{d}{dt}[(4t+1)^{3/2}]\)\)

To simplify the differentiation, we can rewrite the function as\(\(v(t) = (4t+1)^{3/2}\)\) . Applying the power rule, the derivative becomes:

\(\(v(t) = \frac{3}{2}(4t+1)^{1/2} \cdot 4\)\)

Simplifying further, we have:

\(\(v(t) = 6(4t+1)^{1/2}\)\)

Next, we differentiate the velocity function \(v(t)\) to find the acceleration function \(a(t)\):

\(\(a(t) = \frac{d}{dt}[6(4t+1)^{1/2}]\)\)

Using the power rule again, we get:

\(\(a(t) = 6 \cdot \frac{1}{2}(4t+1)^{-1/2} \cdot 4\)\)

Simplifying further, we have:

\(\(a(t) = 12(4t+1)^{-1/2}\)\)

Now we can find the acceleration at \(t = 2\) seconds by substituting \(t = 2\) into the acceleration function:

\(\(a(2) = 12(4 \cdot 2 + 1)^{-1/2}\)\)

\(\(a(2) = 12(9)^{-1/2}\)\)

Simplifying the expression, we have:

\(\(a(2) = \frac{12}{3} = 4\) cm/s²\)

Therefore, the acceleration of the particle at \(t = 2\) seconds is \(4\) cm/s².

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To translate figure ABCD into A'B'C'D' rotate 90° about D and then reflect across AB.

When a figure is relocated from one place to another without changing its size, shape, or orientation, a transition known as translation takes place.

If we know which way the figure is moving and how much, we can draw the translation in the coordinate plane.

Every point of the object must be translated by the same amount and in the same direction.

To translate figure ABCD into A'B'C'D' rotate 90° about D and then reflect across AB.

option (d)

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