What is the mass of 8.83x10^23 formula units of iron oxide

Answer: 1.079 kg/m3

Explanation:

The formula for the density is as follows as; Here, D is the density, m is the mass and V is the volume. Density is inversely proportional to the volume and it is directly proportional to the mass. It is given in the problem that density of an object is 700 kg having volume .

Answer:

orange

Explanation:

Answer:

1,325

Explanation:

The little power above 10 tells us how many spaces the decimal point should be moved.

If the number is positive, we move it to the right; if negative - we move it to the left.

Since the number is 0, we don't move the decimal point anywhere.

Therefore, 1, 325 x 10⁰ is just 1,325

Approximately 352.51 grams of zinc are required to produce 10.8 grams of hydrogen gas through this reaction.

To determine the amount of zinc required to produce 10.8 g of hydrogen gas, we need to consider the stoichiometry of the reaction.

The balanced chemical equation for the reaction is:

Zn + 2HCl -> ZnCl2 + H2

From the equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

First, we need to calculate the number of moles of hydrogen gas:

Molar mass of hydrogen (H2) = 2 g/mol

Number of moles of hydrogen = mass / molar mass = 10.8 g / 2 g/mol = 5.4 mol

Since the ratio of zinc to hydrogen is 1:1, the number of moles of zinc required will also be 5.4 mol.

Next, we calculate the molar mass of zinc:

Molar mass of zinc (Zn) = 65.38 g/mol

Finally, we can calculate the mass of zinc needed:

Mass of zinc = number of moles of zinc × molar mass of zinc = 5.4 mol × 65.38 g/mol ≈ 352.51 g

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Answer:

2 Na^1+ +CO3^2-

Explanation:

Na2CO3-----------> 2 Na^1+ +CO3^2-

The reaction has not yet started, and the time required for 16.8% of the reactant to remain cannot be calculated using the given rate constant.

Given,The rate constant for this first-order reaction is 0.0830 s−1 at 400 ∘C.A⟶products After how many seconds will 16.8% of the reactant remain-The time taken for a first-order reaction to reach a particular percentage of completion can be calculated using the following formula:t = (ln(A/A₀))/kwhere A₀ is the initial concentration of the reactant, A is the concentration of the reactant at a given time, k is the rate constant, and t is the time elapsed since the reaction began.In this question, we are given the rate constant, k = 0.0830 s−1 at 400 ∘C, and we want to find out the time required for 16.8% of the reactant to remain.Let's assume that the initial concentration of the reactant is 100 units (we can assume any value as it does not affect the percentage of completion).Therefore, the concentration of the reactant remaining after 16.8% of completion would be: A = 16.8 units.Substituting these values in the above formula, we get:t = (ln(16.8/100))/0.0830t = (−1.7918)/0.0830t = −21.58 sThis time value is negative, which means that the reaction has not even started yet. Therefore, we need to check the given percentage of completion.

If it is less than 50%, we can assume that the reaction has not yet started. In this case, the percentage of completion is 16.8%, which is less than 50%.

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Answer:

Explanation: In the previous section we listed four characteristics of radioactivity and nuclear decay that form the basis for the use of radioisotopes in the health and biological sciences. A fifth characteristic of nuclear reactions is that they release enormous amounts of energy. The first nuclear reactor to achieve controlled nuclear disintegration was built in the early 1940s by Enrico Fermi and his colleagues at the University of Chicago. Since that time, a great deal of effort and expense has gone into developing nuclear reactors as a source of energy. The nuclear reactions presently used or studied by the nuclear power industry fall into two categories: fission reactions and fusion reactions

Answer:

Molecularity is the number of ions or molecules that take part in the rate determining step

Order of reaction is the number of molecules of reactant whose concentration changes during the chemical change

Answer:

To dissolve an ionic compound

Explanation:

the water molecules must be able to stabilize the ions that result from breaking the ionic bond. They do this by hydrating the ions. Water is a polar molecule. ... When you place an ionic substance in water, the water molecules attract the positive and negative ions from the crystal.

Answer:

They are positively charged ions.

Explanation:

Though, I am not exactly sure about what do you actually mean by your question, but cations are positively charged ions.

Answer:

Explanation:

Answer:

1.0 moles

Explanation:

we are given the number of atoms of the ionic compound, carbon dioxide (\(\rm CO_2\)) which is 6.02x10²³ and we want to find the number of moles in \(\rm CO_2\).

recall that, there are approximately 6.02x10²³ atoms in a mole of any substance (which is actually Avogardro's number, \(\rm N_a=6.02214x10^{23} \: mol^{-1}\) )The answer therefore can be found by dividing given the number of atoms of \(\rm CO_2\) by the Avogadro's number.so, dividing the given number of atoms of \(\rm CO_2\) by the Avogadro's number yields approximately 1.0

Hence,There are approximately 1.0 moles in 6.02x10²³ atoms of \(\rm CO_2.\)

Answer:

3785.4g

Explanation:

210.3 mol of water are

210.3 mol × (18.0g/mol) = 3785.4g

Answer:

1 × 10^10 years

Explanation:

The current distance of the Moon from the Earth = 400,000 km

Every year, the Moon moves: 40 millimeters away from the Earth

From the question:

1 millimeter = 1 x 10^-6 kilometers

40 millimeters =

= 40 ×1 × 10^-6km

= 4 × 10^-5km

= 0.00004km

In approximately how many years will the moon be twice as far from the Earth as it is now, assuming that nothing else changes?

Twice as far = 400,000km × 2

= 800,000km

0.00004km = 1 year

400000km =

= 400,000km/0.00004km

= 10000000000years

= 1 × 10^10 years

Answer:

Explanation:

To find the number of grams in 3.20 moles of a substance, you need to use the formula weight of the substance, which is the number of grams per mole.

In the case of O (oxygen), the formula weight is 15.999 g/mol. To find the number of grams in 3.20 moles of oxygen, you can multiply 3.20 moles by 15.999 g/mol:

3.20 moles * 15.999 g/mol = 51.198 grams

So, 3.20 moles of O (oxygen) is equivalent to 51.198 grams.

Answer:1) There are 0.0128 moles of BBr3 present in 3.20 grams of this compound

2) There are 909.35 grams of BBr3 present in 3.63 moles of this compound

Explanation:

Step 1: Given data

Boron tribromide = BBr3

Molar mass of Boron = 10.81 g/mole

Molar mass of Bromide = 79.9 g/mole

Molar mass of Boron tribromide = 10.81 + 3*79.9 = 250.51 g/mole

Step 2: Calculating number of moles

Number of moles = mass / molar mass

Number of moles of BBr3 = 3.20 grams / 250.51 g/mole

Number of moles of BBr3 = 0.0128 moles

Step 3: Calculating mass

If we have 3.63 moles of boron tribromide (= BBr3)

Mass of BBr3 = number of moles of BBr3 * Molar mass of BBr3

Mass of BBr3 = 3.63 moles * 250.51 g/mole

Mass of BBr3 = 909.35 grams

purines (adenine and guanine) have a larger double-ring structure, while pyrimidines (cytosine, thymine, and uracil) have a smaller single-ring structure. Adenine pairs with thymine (DNA) or uracil (RNA), while guanine pairs with cytosine in both DNA and RNA. These base pairing interactions are essential for the complementary base pairing rules in DNA and RNA molecules.

Purines:

Purines have a double-ring structure composed of a pyrimidine ring fused with an imidazole ring.

The two purine bases found in DNA and RNA are adenine (A) and guanine (G).

Adenine (A) can form two hydrogen bonds with thymine (T) in DNA or uracil (U) in RNA.

Guanine (G) can form three hydrogen bonds with cytosine (C) in both DNA and RNA.

Pyrimidines:

Pyrimidines have a single-ring structure consisting of only a pyrimidine ring.

The three pyrimidine bases found in DNA and RNA are cytosine (C), thymine (T), and uracil (U).

Cytosine (C) forms three hydrogen bonds with guanine (G) in both DNA and RNA.

Thymine (T) pairs with adenine (A) through two hydrogen bonds in DNA only.

Uracil (U) pairs with adenine (A) through two hydrogen bonds in RNA only.

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To calculate the root mean square velocity and kinetic energy of F2, Cl2, and Br2 at 298K, we need to use the kinetic theory of gases.

The root mean square velocity of a gas can be calculated using the formula:

v_rms = √(3kT/m)

where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the gas.

The kinetic energy of a gas can be calculated using the formula:

E_k = (1/2)mv_rms^2

At 298K, the root mean square velocity and kinetic energy of F2, Cl2, and Br2 can be calculated as follows:

F2:

molar mass = 2 * 18.998 g/mol = 37.996 g/mol

v_rms = √(3 * 8.314 J/mol*K * 298K / 37.996 g/mol) = √(0.0244) m/s

E_k = (1/2) * 37.996 g/mol * (0.0244 m/s)^2 = 0.0167 J/mol

Cl2:

molar mass = 2 * 35.453 g/mol = 70.906 g/mol

v_rms = √(3 * 8.314 J/mol*K * 298K / 70.906 g/mol) = √(0.0132) m/s

E_k = (1/2) * 70.906 g/mol * (0.0132 m/s)^2 = 0.0051 J/mol

Br2:

molar mass = 2 * 78.918 g/mol = 157.836 g/mol

v_rms = √(3 * 8.314 J/mol*K * 298K / 157.836 g/mol) = √(0.0064) m/s

E_k = (1/2) * 157.836 g/mol * (0.0064 m/s)^2 = 0.0016 J/mol

To rank the halogens with respect to their rate of effusion, we need to consider the root mean square velocity of each gas. The rate of effusion of a gas is directly proportional to the root mean square velocity of the gas, which is the velocity of the gas particles. Therefore, the gas with the higher root mean square velocity will effuse faster than the gas with the lower root mean square velocity.

From the above calculation, we can see that the root mean square velocity of F2 is the highest, followed by Cl2, and then Br2. Therefore, the halogens can be ranked in terms of their rate of effusion as follows:

F2

Cl2

Br2

So Fluorine(F2) will effuse faster than Chlorine(Cl2) and Bromine(Br2)

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The temperature difference between inner and outer surfaces of the glass is 21°C.

What is  coefficient of thermal conductivity?

The thermal conductivity coefficient k is a material parameter depending on temperature, physical properties of the material, water content, and the pressure on the material. The coefficient k is measured in watts per meter Kelvin (or degree) (W/mK).

According to the given question:

Heat generated by bulb in one second, H = 95 W

Radius = 3 cm = 0.03 m, Area = 3.14 x 0.03 x 0.03 = 2.826 x 10^-3 m^2

Thickness, d = 0.5 mm = 0.5 x 10^-3 m

Coefficient of thermal conductivity of glass, K = 0.8 W/mK

Let ΔT be the temperature difference between inner and outer surface.

H = K A ΔT / d

95 = 0.8 x 2.826 x 10^-3 x ΔT / (0.5 x 10^-3)

ΔT = 21 °C

Thus, the temperature difference between the inner and outer surface of the bulb is 21 °C.

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Answer:

This question is incomplete, it should read 3x² - 10x + 8. The answer is (3x-4) (x-2).

Please find the solved explanation to this question attached

Explanation:

To factorize means to write an expression as a product of its factors using brackets. It is the opposite of expanding an algebraic expression i.e. it involves contracting it using factors common to the variables.

In this question, 3x² - 10x + 8 is given

For the sum, which is -10x, and product, which is 24x², -6x and -4x are the two variables whose sum will give rise to -10x and also whose product will give rise to 24x².

We have;

3x² - 10x + 8

3x² - 6x - 4x + 8

Next, we look for factors of each pair of expression.

3x (x - 2) - 4 (x - 2)

(3x - 4) (x - 2)

Based on the given information, we reject the null hypothesis H₀ at α=0.01.

In hypothesis testing, the null hypothesis (H₀) represents the assumption or claim to be tested, while the alternate hypothesis (H₁) is the alternative claim. In this case, the null hypothesis is H₀: p=0.3, and the alternate hypothesis is H₁: p<0.3.

To perform the hypothesis test, we need to compute the test statistic (z) and the p-value. The test statistic is calculated by subtracting the null value from the sample proportion (p), dividing it by the standard error of the proportion hypothesis. The formula for the test statistic is:

z = (p - p₀) /  hypothesis

However, the given question does not provide the values of p or SEp, so it is not possible to calculate the test statistic (z) accurately.

The p-value represents the probability of observing a test statistic as extreme or more extreme than the one obtained, assuming the null hypothesis is true. By comparing the p-value to a significance level (α), we can determine whether to reject the null hypothesis. Unfortunately, the question does not provide the p-value, making it impossible to make a conclusive decision regarding the rejection or acceptance of the null hypothesis.

In summary, without the necessary values to compute the test statistic and the p-value, it is not possible to provide a precise answer to the question.

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The safe house of lean might influence a product owner to provide better customer service.

The safe house of lean is designed to provide ultimate value to the customer one the shortest possible time.

Employing the safe house of lean might influence the product owner in the following two ways:

Therefore, the safe house of lean might influence a product owner to provide better customer service.

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Answer:

The kinetic energy is transferred from the ball to the bumper. The bumper gives the same energy back and the ball eventually stopped due to friction of the ground.

Explanation:

Hope this y'all <3

When the ball hits/bounces off  the bumper kinetic energy is transferred between the bumper and the ball, while the slowing down is caused by surface friction ( applied force )

In the scenerio explained in the question there is an applied force between the surface and the pool ball, and an energy transfer occurring between the pool ball and the bumper.

hence the applied force that cause the ball to come to a halt is friction while the energy transferred is Kinetic energy ( between the ball and bumper )

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The amount of water produced from the given reactants is 5.71 grams. The correct answer is c) 5.71 g.

The amount of water produced from the given reactants, we need to find the limiting reactant first. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed.

Let's calculate the moles of carbon dioxide (CO2) and ammonia (NH3) using their respective molar masses:

Molar mass of CO2 = 12.01 g/mol (carbon) + 2 * 16.00 g/mol (oxygen) = 44.01 g/mol

Moles of CO2 = 20.1 g / 44.01 g/mol = 0.456 mol

Molar mass of NH3 = 14.01 g/mol (nitrogen) + 3 * 1.01 g/mol (hydrogen) = 17.04 g/mol

Moles of NH3 = 10.8 g / 17.04 g/mol = 0.634 mol

From the balanced equation, we can see that the ratio between CO2 and H2O is 1:1. Therefore, the moles of CO2 and H2O are the same.

Since the balanced equation shows that the ratio between NH3 and H2O is 2:1, we need twice as many moles of NH3 compared to H2O. Thus, the maximum number of moles of H2O that can be produced is 0.634 mol / 2 = 0.317 mol.

Finally, we can calculate the mass of water produced using its molar mass:

Molar mass of H2O = 2 * 1.01 g/mol (hydrogen) + 16.00 g/mol (oxygen) = 18.02 g/mol

Mass of H2O = 0.317 mol * 18.02 g/mol = 5.71 g

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The balanced chemical reaction for the given chemical equation is given by; 3Ba3N2 + 6H2O → 6Ba(OH)2 + 2NH3. Therefore, the balanced values for w, x, y and z are 3, 6, 6, and 2, respectively.

The balanced chemical reaction for the given chemical equation can be obtained by following the below steps;

Count the number of atoms of each element on both sides of the chemical equation

Find the coefficients to balance the number of atoms on both sides of the chemical equation

Check the balance of the chemical equation

Write down the balanced chemical equation by putting coefficients to the molecules. The balanced chemical reaction is; 3Ba3N2 + 6H2O → 6Ba(OH)2 + 2NH3. Therefore, the balanced values for w, x, y and z are 3, 6, 6, and 2, respectively.

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The height of the sheet pile above the ground surface will be 6 + 5.125 = 11.125 m.Therefore, the correct answer is C, 4.872 m.

The right answer is option C, 4.872 m.Explanation:Given,Depth of weir (h)

= 6 m Soil strata depth

= 16 mBase length of weir (B)

= 20 m Foundation depth (df)

= 2 mHead of water retained (H)

= 8 m Permeability coefficient (k)

= 4.6 × 10⁻⁴ m/s Specific gravity (G)

= 2.65Void ratio (e)

= 0.72

To calculate: The height of sheet pile above the weir crest, h1 Assuming the flow is in the horizontal direction from left to right, the weir will act as a vertical wall. Let h1 be the height of the sheet pile above the weir crest.As the water level will be retained to a height of 8 m, the total head on the soil below the sheet pile will be H + h1. Applying the Darcy's law, we can obtain the seepage velocity as:v

= ki.e., v

= 4.6 × 10⁻⁴ × (8 + h1)

So,The seepage velocity at the weir base will be:v

= 4.6 × 10⁻⁴ × (8 + h1)

= (kh/B) × i.e., 4.6 × 10⁻⁴ × (8 + h1)

= (4.6 × 10⁻⁴ × 16) / 20

Hence,

8 + h1

= 2.875

Solving this equation, we get,h1

= 2.875 − 8

= −5.125 m.

Thus, the height of the sheet pile above the weir crest is -5.125 m which means that the sheet pile will extend 5.125 m below the ground surface. The height of the sheet pile above the ground surface will be

6 + 5.125

= 11.125 m.

Therefore, the correct answer is C, 4.872 m.

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Answer:

183 K

General Formulas and Concepts:

Chemistry - Gas Laws

Combined Gas Law: PV = nRT

Explanation:

Step 1: Define

10.0 L

3.00 mol H₂

4.50 atm

Step 2: Find Temperature

Step 3: Check

Round to the nearest whole number.

182.704 K ≈ 183 K

The mass of an object is a measure of the total amount of matter present in it. Mass is usually measured in grams (g) or kilograms (kg).The mass of the object with a volume of 49 cm³ and density of 63 g/cm³ is 3087 g or 3.087 kg.

The given data is;

volume = 49 cm³,
density = 63 g/cm³.

Now, we have to calculate the mass of the object.

Density = mass / volume
Mass = density × volume

Substitute the given values in the above equation.

Mass = 63 × 49

Mass = 3087 g or 3.087 kg

The mass of the object is 3087 g or 3.087 kg.

The mass of the object with a volume of 49 cm³ and density of 63 g/cm³ is 3087 g or 3.087 kg. It means the mass of the object is 3087 times its volume.

The mass of the object with a volume of 49 cm³ and density of 63 g/cm³ is 3087 g or 3.087 kg.

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the atomic radius is 0.144 nm.

Given:

FCC structure. Lattice constant = a = 0.40788 nm.

Atomic radius = r.

According to the definition of the FCC structure, there are 4 atoms per unit cell.

So, the length of the face diagonal can be found as follows:

a√2 = 0.40788 nm√2a = 0.40788 nm/√2a = 0.288 nm

From this, the radius can be calculated:

r = a/2r = 0.288 nm/2r = 0.144 nm

Therefore, the atomic radius is 0.144 nm.

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Answer:

It tells about the data for each line graph is plotted.

Explanation:

Answer:

It can describe what the line graph is measuring and how it is measuring it

According to the periodic trends of the periodic table, the  increasing first ionization energy order is  Br < Cl < F .

Ionization energy is defined as the minimum amount of energy required to remove an electron which is loosely held in the outermost shell to form an isolated gaseous atom,ion or molecule.

In the periodic table,ionization energy increases across period as more energy is required to remove electron from an atom as it is closely held along a period while it is decreasing down the group as on going the group the inter-nuclear distance increases and as a result less energy is required to remove an electron.

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