how is vapor pressure related to temperature? what happens to the vapor pressure of a substance when the temperature is increased? select all that apply.
Answers
Vapor pressure is indeed related to temperature. The relationship between vapor pressure and temperature can be described by the following statements:
Vapor pressure generally increases with an increase in temperature.Vapor pressure decreases with a decrease in temperature.There is a direct proportionality between vapor pressure and temperature.As temperature rises, more molecules of a substance have enough energy to escape from the liquid phase and enter the vapor phase, leading to an increase in vapor pressure.Increasing the temperature causes an increase in the average kinetic energy of the molecules, which results in a higher fraction of molecules having sufficient energy to escape from the liquid phase, leading to an increase in vapor pressure.
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Related Questions
Which of the following materials could be used to make an inactive electrode? (Select all that apply) a) a plastic rod b) a rubber policeman c) a carbon rod d) a glass stir rod e) a platinum wire
Answers
An inactive electrode can be made from a plastic rod, a rubber policeman, and a glass stir rod.
Inactive electrodes are used in electrochemical reactions to complete the electrical circuit with the active electrode. These electrodes do not participate in the reaction and are typically made of materials that do not react with the solution or produce any unwanted products. Platinum wire and carbon rod are examples of active electrodes that can participate in the reaction.
Plastic rods, rubber policemen, and glass stir rods are all non-conductive materials that can be used to make inactive electrodes. They do not conduct electricity and do not react with the solution, making them suitable for use as electrodes in electrochemical reactions. Plastic and rubber are particularly useful as they can be easily shaped into different forms to suit the requirements of the experiment.
In conclusion, a plastic rod, a rubber policeman, and a glass stir rod can be used to make inactive electrodes. These materials are non-conductive and do not react with the solution, making them suitable for use in electrochemical reactions. Platinum wire and carbon rods should be avoided as they are active electrodes that can participate in the reaction.
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natural energy sources, such as wind and moving water, have been used to mill grain.
Answers
Natural energy sources have been harnessed by humans for centuries, and one of the earliest uses of these energy sources was for milling grain.
Wind and moving water, specifically, have been used to power grain mills throughout history. Windmills were commonly used in areas with strong and consistent winds, such as the Netherlands and the American Midwest, to grind grains into flour. Watermills, on the other hand, used moving water, typically from a nearby river or stream, to power their machinery. This allowed for consistent and reliable power, which was essential for producing high-quality flour.
While modern technology has largely replaced traditional milling methods, there has been a resurgence of interest in using natural energy sources for grain milling. This is partly due to concerns about the environmental impact of fossil fuels and the desire for more sustainable energy sources. Today, small-scale wind and water turbines can be used to power grain mills in rural communities, helping to support local food systems and reduce reliance on non-renewable energy sources.
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The electric field 1.8 cm from a small object points toward the object with a strength of 180,000 n/c. what is the object's charge?
Answers
Charge,Q = 6.48 × \(10^-^9\) C
How is the object's charge calculated?It is given that,
Electric field strength, E = 180000 N/C
Distance from a small object, r = 1.8 cm = 0.018 m
Electric field at a point is given by :
\(E=\frac{KQ}{r^2}\)
Q is the charge on an object
\(Q=\frac{Er^2}{k}\)
Q = [180000 × \((0.018)^2\)] ÷ 9 × \(10^9\)
Q = 6.48 × \(10^-^9\) C
So, the charge on the object is Q = 6.48 × \(10^-^9\) C . Hence, this is the required solution.
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the head of a nail is 0.39 cm0.39 cm in diameter. you hit it with a hammer with a force of 27 n.27 n. what is the pressure pheadphead on the head of the nail?
Answers
The pressure is 22.59 x 10⁵ Pa.
We need to know about pressure to solve this problem. Pressure is unit that describe how much force applied on a surface area. It can be determined as
P = F / A
where P is pressure, F is force and A is area.
From the question above, we know that
d = 0.39 cm = 0.0039 m
F = 27 N
Calculate the surface area of the nail
A = π . r²
A = π . (1/2 . d)²
A = π . (1/2 . 0.0039)²
A = 1.195 x 10¯⁵ m²
Determine the pressure
P = F / A
P = 27 / (1.195 x 10¯⁵ )
P = 22.59 x 10⁵ Pa
Hence, the pressure is 22.59 x 10⁵ Pa.
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A statue of a great baseball player weighs 2400 N and has a base that is 4 m x 2 m. What is the pressure the statue exerts on the floor?
Answers
Answer:
300N/m²
Explanation:
Pressure is calculated using the formula;
Pressure = Force/Area
Given
Force = 2400N
Area = 4m×2m = 8m²
Substitute the given parameters into the formula as shown;
Pressure = 2400/8
Pressure = 300N/m²
Hence the pressure the statue exerts on the floor is 300N/m²
1. A 250g bullet is fired with a speed of 300m/s. if it stopped after hitting a target 150m away, (a) what is its initial kinetic energy? (b) What is the magnitude of the force that stopped it? 2. Determine the GPE of a 0.5kg object when it is raised (a.) 0.75m from the floor. (b) What happens to its GPE if we double the height? 3. How high could a 40kg mass be lifted if an energy of 2x10^6 J is used in lifting it?
Answers
Answer:
See below
Explanation:
KE = 1/2 m v ^2
= 1/2 (250/1000) 300^2 j the bullet is 250/1000 kg ( assuming g is grams and not GRAINS - in which bullet weight is usually measured)
force to stop it is the same number
PE = mgh = .5 *9.81 * .75 =
doubling height will double PE
2 x 10^6 = 40 * 9.81 * h sove for 'h' in meters
Initial kinetic energy is 11250 J and magnitude of force to stop bullet is 75 N.
The GPE for 0.75m height floor is 3.75J.
The GPE for double of 0.75m height is 7.5J.
The high on which 40 kg mass is lifted is 5000m.
What is kinetic energy?The kinetic energy of an object is the energy that it possesses due to its motion.
\(KE = 1/2 m v ^2\)
\(=1/2 (250/1000) 300^2 J\\= 11250 J\)
Work done,
\(W= fs\\\\f=\frac{W}{s}\\\\f=\frac{11250}{150}\)
\(f=75 N\)
What is GPE?Gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity.
PE = mgh
= .5 *9.81 * .75
= 3.75 J
Potential energy when height doubles = 7.5J
What is height to which object lift?The potential energy is given by
\(PE = mgh\\\\h = PE/ mg\\\\h = 2*10^6 J /40*9.8\\\\h = 5000 m\)
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PLEASE HELP WILL GIVE BRAINLIEST (I NEED TWO PICKED) PLZzZZZZ AND THxS
Answers
Answer:
A and B
Explanation:
They contain Chlorophyll
They are relatively tall
Two children are bouncing small rubber Ball. One child simply drops ball. At the same time, the second child throws a ball downward so that it has an initial speed of 10m/s what is the acceleration of each ball while in motion
Answers
The acceleration of each ball while in motion is the acceleration due to gravity, that is 9.81 m/s²
How to illustrate the information?Here one child simply drops a ball. The second child simultaneously launches a ball downward at a 10-meter-per-second initial speed.
In first case acceleration on the ball is the acceleration due to gravity, it should be noted that in the second case also acceleration on the ball is the acceleration due to gravity,
Therefore, only gravitational force is acting on both cases so their acceleration is the acceleration due to gravity. Therefore, the acceleration of each ball while in motion is the acceleration due to gravity, that is 9.81 m/s².
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On his fishing trip Justin takes the boat 12 km south. The fish aren't biting so he goes 4 km North. He follows a school of fish 1 km further north.
What distance did he cover? What was his displacement?
I give Brainliest!
Answers
Answer:
Distance: 17 km
Displacement: 7 km
Explanation:
The distance is the total measure of how much he moved.
The displacement is the straight line between the star point and the end point
Water flowing through an 8-cm-diameter pipe enters a porous section, as in fig. p3.10, which allows a uniform radial velocity vw through the wall surfaces for a distance of 1.2 m. if the entrance average velocity v1 is 12 m/s, find the exit velocity v2 if (a) vw
Answers
The exit velocity of water flowing through an 8 centimetres in idiameter pipe s Vw= 0.05 m/s = 5 cm/s out
(a) For a
suction velocity
of V{w} = 0.15m / s , and a
cylindrical suction
surface area, 2 A{W} = 2pi RL=2π(0.04)(1.2) = 0.3016 m²
From
continuity equation
, Q1=Qw +Q₂
VIA=VwAw+V2A2
(12)(π )(0.08 )²/4 = (0.15)(0.3016) + V2 (π )(0.08 )²/4 V2=3 m/s
(b) For a
smaller wall velocity
, Vw = 0.10 m/s,
(12)(π )(0.08 )²/4 = (0.10)(0.3016) + V2 (π )(0.08 )²/4 V2= 6 m/s
(c) Setting the outflow V2 to 9 m/s, the
wall suction velocity
is,
(12)(π )(0.08 )²/4 = (Vw)(0.3016) + (9)(π )(0.08 )²/4
Vw= 0.05 m/s = 5 cm/s out
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what would happen if you used very large amplitudes? check your hypothesis by trial. what amplitude did you use? what is the result?
Answers
The amplitude of a wave is proportional to the amount of energy it carries. When the amplitude of a wave is increased, the energy carried by the wave also increases. This can result in several potential outcomes, depending on the specific wave system being considered.
In mechanical wave systems, such as a vibrating string or a loudspeaker, using very large amplitude can cause the system to become nonlinear, meaning that the wave behavior deviates from the expected linear relationship between the wave amplitude and energy. Nonlinearities can cause the wave to generate harmonics, which are higher frequency components in the wave spectrum. They can also cause the wave to become distorted, producing a sound that is different from the original waveform. In extreme cases, the system can become mechanically unstable and break or stop functioning altogether.
In electromagnetic wave systems, such as radio waves or light waves, very large amplitudes can cause similar nonlinear distortions. They can also cause unwanted interference with other signals in the system, as well as increase the risk of damage to the transmitting or receiving equipment.
It is important to use appropriate amplitudes for the specific wave system being considered, as excessive amplitudes can result in unwanted side effects and potentially cause damage to the system.
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the main cause of melting along subduction zones is the:
a. rise and decompression melting of mantle lithosphere
b. rise and decompression melting of mantle lithosphere
c. melting of the subducting plate
d. release of water from the subducting plate
Answers
The main cause of melting along subduction zones is the d. release of water from the subducting plate.
Subduction zones are areas where one tectonic plate moves beneath another, causing the denser plate to sink into the mantle. This process generates a significant amount of heat, which contributes to the melting of rocks in the mantle lithosphere.
As the subducting plate moves deeper into the mantle, it experiences increasing pressure and temperature. The minerals within the subducting plate contain water, which is released as the plate is subjected to these extreme conditions. This released water reduces the melting point of the surrounding mantle rocks, causing them to partially melt.
This partial melting creates magma, which can rise through the mantle lithosphere and eventually reach the Earth's surface, resulting in volcanic activity. The release of water from the subducting plate, therefore, plays a crucial role in generating the magma that leads to volcanic eruptions along subduction zones.
In summary, the main cause of melting along subduction zones is the d. release of water from the subducting plate, which lowers the melting point of surrounding mantle rocks and generates magma. This magma can rise through the mantle lithosphere, causing volcanic activity in these regions.
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The main cause of melting in subduction zones is the release of water from the subducting plate, which lowers the melting temperature of the surrounding rocks and causes them to melt.
Explanation:The main cause of melting along subduction zones is primarily the release of water from the subducting plate (option d). When the oceanic lithosphere subducts, it carries with it water that has been trapped in the minerals of the crust and upper mantle. This water lowers the melting temperature of the surrounding rocks, causing them to melt and form magma. This is termed 'flux melting'. For example, the subduction of the Pacific Plate beneath the North American Plate in the Cascadia subduction zone causes intense volcanic activity in the Pacific Northwest.
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What is an inertial frame of reference? does a perfect inertial frame of reference exist, and if it does, give me an example?
Answers
Answer:
Within the realm of Newtonian mechanics, an internal frame of reference or internal reference frame, is one in which newton's law of motions is valid
Make a table Using the musical scale in figure 9, make a table that shows how many wavelengths will pass you in one minute for each musical note. What it the relationship between frequency and the number of wavelengths that pass you in one minute?
Answers
Assuming the speed of the wave is taken as the speed of sound wave in air that is 340 m/s. The wavenumber for 262 Hz is 0.77 m⁻¹ and that for 294 Hz is 0.86 m⁻¹ .
What is wavenumber ?The wave number of a wave is the number of wavelengths passing through unit length. It is the inverse of wavelength.
Wave number is directly proportional to the frequency.
The relation between frequency and wave number is written as:
wave number = ν/v
where v is the speed of the wave and ν is the frequency.
The wave number of the wave with the frequency of 330 Hz is then,
330 Hz/ 340 m/s = 0.97 m⁻¹
and for the remaining frequencies:
349 Hz /340 m/s = 1.052 m⁻¹
for 392 Hz,
392 Hz/340 m/s = 1.15 m⁻¹
For 440 Hz,
440 Hz/340 m/s = 1.29 m⁻¹.
for 494 Hz,
494 Hz/340 m/s = 1.45 m⁻¹
and for 523 Hz,
523 Hz/340 m/s = 1.53 m⁻¹
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any gfci breaker or receptacle that _____ should be written up as in need of immediate replacement.
Answers
Any GFCI breaker or receptacle that fails to trip when tested should be written up as in need of immediate replacement.
GFCI (Ground Fault Circuit Interrupter) breakers and receptacles play a crucial role in electrical safety by quickly shutting off power in the event of a ground fault or electrical leakage. They are designed to protect against electrical shocks and reduce the risk of electrical fires.
If a GFCI breaker or receptacle fails to trip when tested, it indicates a potential malfunction or loss of functionality. This means that the device may no longer provide the necessary protection in case of a ground fault. Without the proper tripping mechanism, individuals and property are exposed to increased electrical hazards.
When a GFCI breaker or receptacle fails to trip during testing, it should be documented and flagged for immediate replacement. This ensures that the faulty device is taken out of service and a new one is installed promptly to restore the safety features of the electrical system.
Prompt replacement of a malfunctioning GFCI device is essential to maintain electrical safety standards and prevent potential accidents or injuries. Regular testing and maintenance of GFCI devices are recommended to ensure their proper functioning and continued protection.
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Desde lo alto de un acantilado de 140 m, se lanza verticalmente un objeto hacia abajo con velocidad de 3m/s. Entonces la magnitud del desplazamiento que ejecuta en t = 3s es: (use g = 10 m/s2)
Answers
Answer:
54
Explanation:
d = vo*t + ½*g*t²
d = 3*3 + ½*10*3²
d = 9 + 45
d = 54 m
entonces el objeto tiene 54 m de desplazamiento
A car goes forward along a level road with a certain acceleration, a. The additional force needed to bring the car into equilibrium is.
Answers
The additional force needed to bring the car into equilibrium is equal to the mass of the car times the acceleration of the car, or F = ma.
What is equilibrium?Equilibrium is a state of balance and stability between opposing forces or actions. In economics, it refers to the point where the supply and demand for a given product or service are equal, and the market price of the product or service is stable. In physics and chemistry, equilibrium is a state in which different competing forces are balanced, so that no net change is observed. In biology, it is the ability of an organism to maintain a stable internal environment despite changes in external conditions. Ultimately, equilibrium is a state of balance, stability, and homeostasis.
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Which best describes a radio wave?
A. an electromagnetic wave at very long wavelength (low
frequency)
B. a pressure wave at very long wavelength (low frequency)
C. a pressure wave at very short wavele
Answers
Option A. An electromagnetic wave at very long wavelength (low frequency) best describes a radio wave.
A radio wave is best described as an electromagnetic wave at a very long wavelength or low frequency. It is not a pressure wave. Radio waves are a type of electromagnetic radiation, which also includes other forms such as visible light, infrared, and X-rays. The term "wavelength" refers to the distance between two consecutive points in a wave, such as from one crest to the next. In the case of radio waves, the wavelength is quite long, ranging from several millimeters to hundreds of meters. This long wavelength allows radio waves to travel long distances and pass through obstacles such as buildings and trees. Radio waves are used for various purposes, including communication, broadcasting, and radar systems. For example, when you listen to the radio, the sound is encoded onto a carrier wave, which is a specific radio wave frequency. The receiver then extracts the sound from the carrier wave, allowing you to hear it. Similarly, radar systems use radio waves to detect and track objects like airplanes or weather patterns. To summarize, a radio wave is an electromagnetic wave at a very long wavelength or low frequency. It is not a pressure wave. Radio waves are used for communication, broadcasting, and radar systems due to their ability to travel long distances and pass through obstacles. They play a crucial role in everyday life, allowing us to enjoy wireless communication and entertainment.
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how can the movement of energy can be tracked by observing the changes the energy causes to matter
Answers
HELPP ILL GIVE 20 BRAINLIST!!!
__________ powers are powers in which authority is shared by both the federal and state governments.
A.
Reserved
B.
Federalist
C.
Delegated
D.
Concurrent
Please select the best answer from the choices provided
A
B
C
D
Answers
Answer:
C. Delegated
Explanation:
Answer:
its letter C
Explanation:
just trust
Assuming we receive a signal from a civilization on the other side of our galaxy, a two-way conversation with them is ________.
Answers
a 0.590 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 50.0 pc charge on its surface. what is the potential (in v) near its surface
Answers
The potential (in v) near the surface of a 0.590 cm diameter plastic sphere is 3.04 x \(10^{10}\) V.
The potential near the surface of a 0.590 cm diameter plastic sphere, which has a uniformly distributed 50.0 pc charge on its surface, can be calculated using Coulomb's Law.
Coulomb's Law states that the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Using this law, we can calculate the potential near the surface of the sphere.
The potential, V, is equal to the sum of all of the charges, q, on the sphere multiplied by the Coulomb's constant, k, and divided by the distance, r, from the center of the sphere. The equation can be expressed as V = (qk)/r.
Since the sphere is uniform, q = 50.0 pc, and k is a constant, \(8.99 * 10^9 Nm^2/C^2\)
Thus, the distance, r, is the radius of the sphere, 0.295 cm.
Thus, the potential near the surface of the sphere is \(V = (50.0 * 8.99 * 10^9) / 0.295 = 3.04 * 10^10 V.\)
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Suppose that the mirror is moved so that the tree is between the focus point F and the mirror. What happens to the image of the tree?
1. the image moves behind the curved mirror.
2.The image stays the same.
3.The image appears taller and on the same side of the mirror.
4. The image appears shorter and on the same side of the mirror.
Answers
When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.
As a result, a virtual image is formed behind the mirror. This virtual image is similar in size and shape to the object being reflected.The characteristics of the image produced by a mirror depends on the location of the object relative to the mirror. There are two types of mirrors that we use to reflect light: Concave and Convex. In the case of a concave mirror, the image produced can either be real or virtual. When an object is placed between the focus point and the mirror, a virtual and erect image is produced. This image is smaller than the actual object and appears behind the mirror. The image is virtual because the light rays do not converge at the location of the image. In the case of a convex mirror, the image produced is always virtual, erect, and smaller than the actual object. As the object moves closer to the mirror, the image gets smaller. If the object is moved to a position where it is between the focus point and the mirror, the image produced will appear shorter and on the same side of the mirror.For such more question on Concave
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What is a good question to ponder/Think about ?
Answers
Explanation:
how to alweays win amoung us_
A warm cup of coffee has 20 000 J of energy.
After being heated in a microwave, the cup of
coffee has 70 000 J of energy. How much work
was done by the microwave to heat the coffee?
(a) 20 000 J
(b) 50 000 J
(c) 70 000 J
(d) 90 000 J
Answers
Answer:
(b) 50,000 J
Explanation:
it starts with 20,000 and ends with 70,000 so the difference is 50,000
hope this helps:)
The ozone layer is an important component of earth’s atmosphere because it helps to block uv radiation from reaching earth. the ozone layer absorbs most of the harmful uv radiation from the sun and stores it as heat within the stratosphere. if the ozone layer were completely removed, what effect would that change have on temperature?
Answers
If ozone layer is completely removed then many severe effects can be seen in the temperature of the earth.
The ice in the Antarctica starts getting melt which increases the level of water in ocean and proved to be harmful for the coastal areas. The rise in temperature also lead to long summers and high temperatures ranges from 50° C to 65° C .Explanation:
The removal of ozone layer will not only effect the temperature but also had a great impact on human and animals such as
The harmful rays will directly fall on earth in the absence of ozone cause cancer in animals, plants and humans. These harmful rays weaken the immune system. Lead to disturbance of food chain in following ways : -It will led to increase in herbivores as a result, the number of plants will decrease and the amount of oxygen will also decrease in the atmosphere. The carnivores keep the population of other carnivores and herbivores in check. This will disturb the balance of ecosystem. The concentration of harmful chemicals is maximum at the last trophic level . Because these chemicals are not degradable, these get accumulated progressively at each trophic level.Answer:
2 & 5 (picture is attached)
Explanation:
hope this helps!
How can red giants be so bright when they are so cool
Answers
Answer:
The star's luminosity rises above its previous level. Because it is so cool, the surface will be red, and it will be much farther away from the center than it was during the earlier stages of star evolution. Despite its lower surface temperature, the red giant has a large surface area, which makes it very luminous.
Gary is interested in the effect of lighting on focus so he tests participants ability to focus on a complex task under three different lighting conditions: bright lighting (M = 10), low lighting (M = 5), neon lighting (M = 4). His results were significant, F(2, 90) = 5.6, p < .05. What can Gary conclude? O a. Bright lights make it easier to focus than low lights or neon lights. O b. Type of lighting has no effect on focus. O c. Bright lights make it more difficult to focus than low lights or neon lights. O d. Type of lighting has some effect on focus.
Answers
Based on the given information, Gary conducted an experiment to test the effect of lighting on participants' ability to focus. He compared three different lighting conditions: bright lighting, low lighting, and neon lighting. The results showed a significant effect, with an F-value of 5.6 and p-value less than 0.05. Now we need to determine what Gary can conclude from these results.
The F-value and p-value are indicators of statistical significance in an analysis of variance (ANOVA) test. In this case, the F(2, 90) value suggests that there is a significant difference in participants' ability to focus across the three lighting conditions.
Since the p-value is less than 0.05, Gary can reject the null hypothesis, which states that there is no difference in focus ability between the different lighting conditions. Therefore, he can conclude that the type of lighting does have some effect on focus.
However, the specific nature of the effect cannot be determined solely based on the information provided. The mean values indicate that participants performed best under bright lighting (M = 10), followed by low lighting (M = 5), and neon lighting (M = 4). This suggests that bright lights may make it easier to focus compared to low lights or neon lights, but further analysis or post-hoc tests would be required to provide a more definitive conclusion.
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The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is
Answers
The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.
The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.
Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:
E/B = (NC^(-1))/(NA^(-1) m^(-1))
To simplify this expression, we can cancel out the common units in the numerator and denominator:
E/B = (N/C)/(N/(A m))
Now, let's simplify further by dividing the numerator and denominator:
E/B = (N/C) * (A m/N)
Canceling out the common units:
E/B = (A m)/(C)
Therefore, the unit of E/B is A m/C (ampere meter per coulomb).
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Describe how an adult can teach a child to become a racist or bigot using positive reinforcement and negative punishment. Make sure you define the terms and apply the term to a real world example.
Answers
Answer:
by raising them in an environment in wich it is common and giving false information about other races to install bad stereo types and distrust in the child who will grow up to not know any better do to the dumb ignorant parent raised the same way
Explanation:
?????? thats all i got im not a politician BLM