A toy car accelerates uniformly from rest at a constant rate. The car travels 1.0 meters in 1.0 seconds. The acceleration of the car is ________ meters per second squared.

Answer:

What are the best flowers? (My opinion)

Explanation:

You're welcome.

Answer:

Tulips,

Lilies,

Lotuses on my opinion...

Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

Answer:

The answer is 0.042 Hz (rounded)

or 0.0417 Hz

Explanation:

Hope it helps

Answer:

The answer is 0.041Hz

Explanation:

The answer is 0.041Hz

I guess

Answer:

Explanation:

Given the height reached by a balloon after t sec modeled by the equation

h=1/2t²+1/2t

a) To calculate the height of the balloon after 40 secs we will substitute t = 40 into the modeled equation and calculate the value of t

If h(t)=1/2t²+1/2t

h(40) = 1/2(40)²+1/2 (40)

h(40) = 1600/2 + 40/2

h(40) = 800 + 20

h(40) = 820 feet

The height of the balloon after 40 secs is 820 feet

b) Velocity is the change of displacement of a body with respect to time.

v = dh/dt

v(t) = 2(1/2)t²⁻¹ + 1/2

v(t) = t + 1/2

when v = 0sec

v(0) = 0 + 1/2

v(0) = 1/2 ft/sec

at v = 30secs

v(30) = 30 + 1/2

v(30) = 30 1/2 ft/sec

average velocity = v(30) - v(0)

average velocity = 30 1/2 - 1/2

average velocity of the balloon between t = 0 and t = 30 = 30 ft/sec

c) Velocity is the change of displacement of a body with respect to time.

v = dh/dt

v(t) = 2(1/2)t²⁻¹ + 1/2

v(t) = t + 1/2

The velocity of the balloon after 30secs will be;

v(30) = 30+1/2

v(30) = 30.5ft/sec

The velocity of the balloon after 30 secs is 30.5 feet/sec

A)  The height of the balloon at the end of 40 sec is 820 feet.

B) The average velocity of the balloon is 30 ft/sec.

C) The velocity of the balloon at the end of 30 sec is

Given :

Part A)

The height of the balloon after 40 secs is :

h(t)=1/2t²+1/2t

h(40) = 1/2(40)²+1/2 (40)

h(40) = 1600/2 + 40/2

h(40) = 800 + 20

h(40) = 820 feet

The height of the balloon after 40 secs is 820 feet

Part B)

The average velocity of the balloon is  :

v = dh/dt

v(t) = 2(1/2)t²⁻¹ + 1/2

v(t) = t + 1/2

when v = 0 sec

v(0) = 0 + 1/2

v(0) = 1/2 ft/sec

When at v = 30secs

v(30) = 30 + 1/2

v(30) = 30 1/2 ft/sec

average velocity = v(30) - v(0)

average velocity = 30 1/2 - 1/2

average velocity of the balloon = 30 ft/sec

The average velocity of the balloon  is  30 ft/sec.

Part C)

The velocity of the balloon at the end of 30 sec is :

v = dh/dt

v(t) = 2(1/2)t²⁻¹ + 1/2

v(t) = t + 1/2

The velocity of the balloon after 30secs will be;

v(30) = 30+1/2

v(30) = 30.5ft/sec

The velocity of the balloon after 30 secs is 30.5 feet/sec.

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Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Answer:

0.028 M.

Explanation:

NOTE: This question is a chemistry question. However, the answer to the question can be obtained as shown below:

We'll begin by calculating the number of mole in 2.52 g of oxalic acid, C₂H₂O₄. This can be obtained as follow:

Mass of C₂H₂O₄ = 2.52 g

Molar mass of C₂H₂O₄ = (2×12) + (2×1) + (4×16)

= 24 + 2 + 64

= 90 g/mol

Mole of C₂H₂O₄ =?

Mole = mass / molar mass

Mole of C₂H₂O₄ = 2.52 / 90

Mole of C₂H₂O₄ = 0.028 mole

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of C₂H₂O₄ = 0.028 mole

Volume = 1 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.028 / 1

Molarity = 0.028 M

Therefore, the molarity of the solution is 0.028 M.

Answer:

B. Constant motion

Explanation:

There is acceleration or deceleration when the speed changes in an interval of time. In this case, the speed of the object is 20 m/s in the 4 minutes, so we can say that the speed was constant and then it is a constant motion.

Then, the answer is

B. Constant motion

Answer:

The tears would stick to said face,never moving

from below the eyes

Explanation:

A object remains in its moment of motion or rest until or unless any external force is applied.

Hence tears will remain sticked to face .

Answer:

3.0 mph

Explanation:

The rate would be Change in distance/Change in time = 1.2-0.7/12-2

When you simplify that, it gives you 0.5/10 = 0.05

To convert 0.05 minutes into hours, you multiply by 60.

0.05 x 60 = 3.0 mph

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Based on the mass of the liquid and the mass of the cylinder, the reading shown on the balance is 1.593 kg.

To calculate the reading shown on the digital balance, we need to first find the mass of the liquid in the cylinder, and then add it to the weight of the empty cylinder.

The volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where;

r is the radius of the cylinder, and h is the depth of the liquid.

Substituting the given values, we get:

V = π x (3.5 cm)² x 12.0 cm

= 1486.96 cm³

We need to convert the volume from cubic centimeters to cubic meters to use the density of the liquid in kilograms per cubic meter:

V = 1.48696 x 10⁻³ m^3

The mass of the liquid can be found using the formula:

mass = density x volume

Substituting the given values, we get:

mass = 900 kg/m³ x 1.48696 x 10⁻³ m³

= 1.33826 kg

Therefore, the reading shown on the digital balance is:

mass of empty cylinder + mass of liquid

mass of empty cylinder = 2.5/9.81

mass of empty cylinder = 0.2548 kg

reading shown on the digital balance =  0.2548 kg + 1.33826 kg

reading shown on the digital balance = 1.593 kg

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Answer:

it would look like what I did in the picture

Explanation:

Option D. continental shelf

Continental shelf is a part of a continent that is submerged under an area of ​​relatively shallow water known as a shelf sea.

It is given in the question, that the shelf of undersea land reaches 200 meters and it also extends out from the shoreline. This condition is only possible when a structure is submerged, and such submerged region can only be called as continental shelf.

On the other hand guyots is a underwater volcanic mountain and deep-sea trenches are the the long narrow lowerings in the ocean floor with the depth upto 6000 meters. And abyssal plains are the underwater ocean floors which cannot be found at the depth of 200 meters.

Therefore continental shelf is used to described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline.

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The average speed of the baseball is  option  a. 40 m/s .

To calculate the average speed of the baseball, we use the formula:

Average Speed = Distance / Time

Given:

Distance = 18.4 m

Time = 0.46 s

Plugging in the values, we have:

Average Speed = 18.4 m / 0.46 s = 40 m/s

Therefore, the average speed of the baseball is 40 m/s.

Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.

Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.

In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.

It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.

Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.

Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.

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Which air pocket would you expect to cool down more at night? 

Answer: The ocean air.

Why?

Because ocean water seems to cool faster at night which may cause the ocean air to cool down more at night.

Ocean water seems to cool faster at night which may cause the ocean air to cool down more at night.

"Air pocket" is merely another term for ordinary turbulence. You might feel as if you're falling from the sky, but rest assured, if you flying commercially, you rarely gain or lose more than about twenty feet, especially if the plane is on autopilot.

The term "air pocket" comes from early aviation, a time when pilots flying open-cockpit biplanes took adventurous locals on a rides in their “flying machines.”

When the plane entered air that, instead of simply sitting there, was flowing slightly upward or slightly downward, the plane's path was altered slightly upward or slightly downward.  

Therefore, Ocean water seems to cool faster at night which may cause the ocean air to cool down more at night.

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Answer:

The lithosphere is the Earth's stable outer layer. The lithosphere is made from the brittle top mantle and the crust, which are the Earth's outermost layers. The atmosphere above it and the asthenosphere (another issue of the top mantle) underneath it define its limitations. even though the rocks of the lithosphere are nevertheless taken into consideration elastic, they may be not viscous. The asthenosphere is viscous, and the lithosphere-asthenosphere boundary (LAB) is the component in which geologists and rheologists—scientists who study the drift of depend—mark the difference in ductility among the 2 layers of the top mantle. Ductility measures a strong cloth’s ability to deform or stretch under strain. The lithosphere is a long way less ductile than the asthenosphere.

Explanation:

Plagarism checked, 100% unique [I think, if not sorryyyyeeeeee]

Hope this helps!

Byeeee have a nice day

Answer:

Tipping over dominos

Explanation:

Because when tipping the dominos it carrys energy from one place to the other and it is a good repersenteive of a wave

We can compare tipping over dominos to wave because both involves the transfer of energy.

A wave is a disturbance that transfers energy from one point to another without any permanent displacement of the particles of the medium.

Tipping over dominos is delivery service that involves movement of energy from one place to another just like wave.

Thus, we can compare tipping over dominos to wave because both involves the transfer of energy.

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Answer:

35000

Explanation:

The ratio of their rotational kinetic energies is 4/5 or 0.8.

Let's denote the mass and radius of the cylinder and sphere as "m" and "r", respectively. At the top of the incline, both objects have only potential energy, which is then converted to kinetic energy. At the bottom of the incline, both objects have both translational and rotational kinetic energy.

For a uniform solid cylinder, the rotational inertia is\(1/2 * m * r^2\). For a uniform sphere, the rotational inertia is\(2/5 * m * r^2\). Therefore, the ratio of their rotational kinetic energies is:

(rotational kinetic energy of sphere) / (rotational kinetic energy of cylinder)

\(= (2/5 * m * r^2 * (v/r)^2) / (1/2 * m * r^2 * (v/r)^2)\)

= (4/5)

Therefore,  rotational kinetic energy of  sphere is 80% of  rotational kinetic energy of the cylinder at  bottom of the incline.

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--The complete Question is, A uniform solid cylinder and a uniform sphere with the same mass and radius are released from rest at the top of an incline. They both roll without slipping down the incline and reach the bottom with the same translational speed. What is the ratio of their rotational kinetic energies at the bottom of the incline?--

Answer:

e:10 m   b: -5 m/s b.The object decreases its velocity.

Explanation:

Answer:

Explanation:

Impulse = change in momentum

Initial momentum = mass x initial velocity = 100 x 5 = 500 kg m/s

final momentum = mass x final velocity = 100 x - 4 = -400 ( - ve sign due to reversal of direction )

change in momentum = final momentum - initial momentum

= - 400 - 500 = - 900 kg m/s .

As it is - ve , it acts upwards .

So magnitude of  impulse on Perter = 900 kg m/s

Answer:

C

Explanation:

trust me

D. Fixed position ,mean position , Equilibrium position.

Wave motion is the transfer of energy and momentum from one point of the medium to another point of the medium without actual transport of matter between two points.

The particles of the medium vibrate about their equilibrium position in a direction parallel to the direction of propagation of the wave is called a longitudinal waves.

Characteristics of Wave Motion

In wave motion, the disturbance travels through the medium due to repeated periodic oscillations of the particles of the medium about their mean position (or) Equilibrium position.

Energy and momentum are transferred from one point to another without any actual transfer of the particles of the medium.

There is a regular phase difference between the particles of the medium because each particle receives disturbance little later than its preceding particle.

Therefore,

In a wave, each particle of the medium vibrates, or oscillates, around a fixed position.

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Answer:

It is independent of the path of the body and depends only on the starting and ending points.

Explanation:

In Physics we define a conservative force as a force that is independent of the path of the body and depends only on the starting and ending points.

For conservative forces we can write;

KEi + PEi = KEf +PEf

where;

KEi= initial kinetic energy

PEi= initial potential energy

KEf= final kinetic energy

PEf= final potential energy

This equation is known as the principle conservation of mechanical energy . It applies only to conservative forces where friction is negligible. The term KE + PE  is also known as the total mechanical energy of the system.

Answer:

The rescue workers can get energy to the batteries in their equipment during rescue missions by using a generator to convert the kinetic energy to potential energy. Potential energy is then stored in the battery.

Explanation:

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kPa or 1 atm and serves as a reference point for scientific measurements and comparisons related to atmospheric pressure.

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kilopascals (kPa) or 1 atmosphere (atm). This pressure is used as a reference point for various scientific measurements and is crucial in fields such as meteorology, physics, and engineering.

Atmospheric pressure is caused by the weight of the air above a given point on the Earth's surface. The air is composed of molecules, mainly nitrogen (approximately 78%) and oxygen (approximately 21%), along with other trace gases. These molecules are in constant motion and exert a force on the surfaces they come into contact with, including the Earth's surface.

The standard atmospheric pressure of 101.325 kPa is equivalent to the pressure exerted by a column of mercury 760 millimeters (mm) in height in a barometer at sea level. This measurement was established as a reference point for atmospheric pressure, providing a consistent value for scientific calculations and comparisons.

It is important to note that atmospheric pressure can vary with altitude and weather conditions. As altitude increases, the atmospheric pressure decreases because the column of air above becomes thinner. In areas of high or low pressure systems associated with weather patterns, the atmospheric pressure deviates from the standard value.

The standard atmospheric pressure is a valuable reference in many applications. For instance, it is used as a standard for measuring gas pressure in laboratories and industrial processes. It is also used in meteorology to calculate and compare pressure systems and to study atmospheric phenomena such as wind patterns and weather changes.

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Final Answer:

If there is lower air pressure being "pushed" onto the surface of the water, then the water molecules do not need as much energy to overcome the force of atmospheric pressure pushing on the surface, and they can more easily escape and become a vapor. When the vapor pressure of the liquid is equal to the air pressure surrounding the liquid, it will boil. If you lower the air pressure, you will lower the temperature that water will boil at.

Explanation:

The boiling point of a liquid depends on the balance between the vapor pressure of the liquid and the external pressure, which is typically atmospheric pressure. When the external pressure is reduced, such as at higher altitudes or in a vacuum, the liquid molecules require less energy to escape the surface and become vapor. This is because there is less force pushing down on the liquid's surface, allowing for easier vaporization.

At lower air pressure, the water molecules can overcome the diminished force of atmospheric pressure more readily, requiring less heat energy to transition from liquid to vapor. When the vapor pressure of the liquid equals the surrounding air pressure, the liquid will start to boil.

Boiling point and vapor pressure are fundamental concepts in thermodynamics and phase transitions. Understanding how pressure affects the boiling point of liquids is crucial in various scientific and engineering applications, such as cooking, chemical processes, and high-altitude cooking.

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Answer:

Explanation:

1. x-axis: Temperature (in degrees Celsius)

2. y-axis: Heat (in Joules)

3. Title: Heating Curve for Water

4. All 3 phases of matter: solid (ice), liquid (water), gas (steam)

5. Show where KE is increasing: The line segment from A to B represents the increase in kinetic energy as the water is heated from solid to liquid state, and the line segment from C to D represents the increase in kinetic energy as the water is heated from liquid to gas state.

6. Show where PE is increasing: The line segment from A to B represents the increase in potential energy as the ice is melting into water, and the line segment from C to D represents the increase in potential energy as the liquid water is vaporizing into steam.

7. Identify the phase changes: The segment from A to B represents the melting of ice (solid to liquid), and the segment from C to D represents the vaporization of water (liquid to gas). The flat portions between B and C represent the heating of water in liquid state and the absorption of heat without any change in temperature (latent heat of fusion and latent heat of vaporization).

Vehicle driving round a curve