A 12 volt battery will increase the potential energy of 4 coulombs of charge by _____ Joules.

Question 8 options:

16 J


3 J


.33J


48 J

                  least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.

Answer:

Explanation:

Chlamydia is a bacterial infection that affects the reproductive system in a myriad of nasty and invasive ways, including pain during micturition, genital discharge, and spreading to the rectum and eyes. Other than safe sex practices and abstinence, ways to prevent and treat Chlamydia are antibiotics for both partners (if they're both infected) and surgical intervention in severe cases.

Trichomoniasis is a parasitic sexually transmitted disease that infects women but can affect men during intercourse, women who are infected are more likely to suffer from pain in the vaginal area during moments including micturition and intercourse as foul-smelling discharge. The more concerning aspect of this disease is how women afflicted are more likely to give premature birth and spread the infection to the baby upon birth. Much like Chlamydia, Trichomoniasis can be prevented via safe-sex practices and abstinence, but it can also be treated by antibiotics for both sexual partners to prevent spreading it between them.

The relationship between the temperature of an object and the frequency of electromagnetic waves generated by the object is described by the concept of blackbody radiation.

A blackbody is an idealized object that perfectly absorbs all electromagnetic radiation that falls on it and emits radiation in a continuous spectrum over a range of frequencies.

According to Planck's law, the spectral distribution of blackbody radiation depends on the temperature of the object. As the temperature of the object increases, the peak of the spectral distribution shifts towards higher frequencies.

This relationship is known as Wien's displacement law, which states that the wavelength at which the spectral radiance of a blackbody is maximum is inversely proportional to the temperature of the object.

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Explanation:

Object is under the effect of the acceleration of gravity

v = 1/2 a t^2       a = 9.81 m/s^2   t = 2.3

v = 25.9 m/s^2 = ~ 26 m/s   ( two significant digits)

The surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K, based on the peak wavelength of 40 μm.

To find the surface temperature of the asteroid, we can use Wien's displacement law, which states that the peak wavelength of radiation emitted by a blackbody is inversely proportional to its temperature. Given that the power per unit wavelength peaks at 40 μm, we can calculate the surface temperature of the asteroid.

1. According to Wien's displacement law, the peak wavelength (λ) is related to the temperature (T) by the equation: λ_max = (b / T), where b is Wien's displacement constant equal to 2898 μm·K.

2. We are given that the peak wavelength is 40 μm. Substituting this value into the equation, we have: 40 μm = (2898 μm·K / T).

3. Rearranging the equation, we find: T = (2898 μm·K) / (40 μm).

4. Calculating the values, we get: T = 72.45 K.

Therefore, the surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K.

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In A. part, the magnetic field at (0, 50) is in west direction. In B. part, the strength of the field at (0,50) is 2.06 G.

A. The current is flowing up for west as shown by the front view figure at the bottom of the gadget. Your fingers will curve to the west if you wrap your right hand around the wire with your thumb up. Put a compass at (0,50) to check the direction as well. It indicates west.

B. By using the Pythagorean Theorem to determine the strength of the combined field, the strength of the field at (0,50) is 2.06 G.

The earth's magnetic field strength= 0.50 G

The induced current magnetic field strength= 2.0

B is given by=

\(\sqrt{0.50^{2} - 2.00^{2} }\\ =\sqrt{0.25-4.00}\\ =2.06\)

Hence, we can also check by putting the probe on (0,50) and the probe reads 2.06 G.

Therefore, the strength of the field at (0,50) is 2.06 G.

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Answer:

To determine the minimum blade length, add 1" to the workpiece thickness. One type of material, and some materials can be cut by more than one type of blade. No matter the material, there's likely a jigsaw blade designed specifically for. Armed with the right blade, follow these pointers to make your work go (and cut) .

Explanation:

The gravitational force between the spheres is

\(F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N\)

where G = 6.674 x 10⁻¹¹ N m²/kg².

The weight of the lighter sphere is

\(F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N\)

where g = 9.80 m/s².

The ratio between the two forces is then

\(\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}\)

The two molecules that best complete the reactants' side of the equation\(CO_2\) + 2\(H_2O\) are \(O_2\) and CO.

The correct answer would be \(O_2\) and CO.

Based on the partial chemical equation provided, \(CO_2\) + 2\(H_2O\), we need to select two molecules that complete the reactants' side of the equation while also considering the conservation of mass. Let's evaluate the given options:

1. \(NaCl_3\): This compound, sodium trichloride, does not contain carbon (C) or oxygen (O) atoms, which are required to balance the equation. Therefore, \(NaCl_3\) is not a suitable choice.

2. \(HS_4\): This compound, hydrogen tetrasulfide, also does not contain carbon (C) or oxygen (O) atoms necessary to balance the equation. Hence, \(HS_4\) is not the correct choice.

3. \(CH_4\): This molecule, methane, consists of one carbon atom (C) and four hydrogen atoms (H). It contains carbon but lacks oxygen atoms required for balancing the equation. Thus, \(CH_4\) does not complete the reactants' side.

4. \(O_2\): Oxygen gas (diatomic oxygen) is represented by\(O_2\). It contains two oxygen atoms, which helps balance the equation since there are two oxygen atoms on the product side (2\(H_2O\)). \(O_2\) is a valid choice for completing the reactants' side.

Considering the conservation of mass, we still need a molecule that contains carbon. Among the given options, CO is the only molecule that consists of one carbon atom (C) and one oxygen atom (O). By adding CO to the reactants' side, we balance both carbon and oxygen atoms in the equation.

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Answer:

0.44 EST + 0.33 NTH

Explanation:

if this is incorrect and brainly removes the comments to try and sabotage you guys please report this for the sake of learning

Answer:  1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.

2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.

3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.

4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.

5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.

Explanation:

I hope this helps!

The ions are;

S^2- Gained 2 electrons

Li^+ - Lost one electron

Al^3+ - Lost 3 electrons

Cl^- gained one electron

Sr^2+ Lost two electrons

P^3- gained 3 electrons

As an atom or molecule acquires or loses one or more electrons, ions are created. Protons and neutrons make up the positively charged nucleus of an atom, which is encircled by negatively charged electrons. An atom typically has a neutral charge because the amount of electrons and protons in it equals one.

The balance between the negatively charged electrons and positively charged protons is upset when an atom receives or loses an electron, creating an ion with a positive or negative charge.

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Answer:

what are the choices

Explanation:

Answer:

Landforms are a result of a combination of constructive and destructive forces. Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.

Explanation:

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.

The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.

The amount of kinetic energy converted to internal energy can be calculated as follows:

m1*v1 = (m1 + m2)*vf

vf = (m1*v1)/(m1 + m2)

KE = (1/2)*m2*v2²

KE converted = KE initial - KE final

KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²

KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²

KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)

KE converted = 28.8 - 22.15

KE converted = 6.65 J

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.

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Answer:

r₁/r₂ = 1/2 = 0.5

Explanation:

The resistance of a wire is given by the following formula:

R = ρL/A

where,

R = Resistance of wire

ρ = resistivity of the material of wire

L = Length of wire

A = Cross-sectional area of wire = πr²

r = radius of wire

Therefore,

R = ρL/πr²

FOR WIRE A:

R₁ = ρ₁L₁/πr₁²   -------- equation 1

FOR WIRE B:

R₂ = ρ₂L₂/πr₂²   -------- equation 2

It is given that resistance of wire A is four times greater than the resistance of wire B.

R₁ = 4 R₂

using values from equation 1 and equation 2:

ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²

since, the material and length of both wires are same.

ρ₁ = ρ₂ = ρ

L₁ = L₂ = L

Therefore,

ρL/πr₁² = 4ρL/πr₂²

1/r₁² = 4/r₂²

r₁²/r₂² = 1/4

taking square root on both sides:

r₁/r₂ = 1/2 = 0.5

a) the magnitude of the force per unit length that one wire exerts on the other: 1.084 × 10⁻⁵ T

b) Force is repulsive in nature.

The surface magnetic field and Earth's magnetic field are roughly magnetic dipoles, with the magnetic field's S pole located close to the planet's geographic north pole  and the magnetic field's N pole located close to the planet's geographic south pole. The magnetic field, which is created by the movement of molten iron in the Earth's core, shields the globe from cosmic radiation and solar radiation as well as from charged particles. Furthermore, it offers the framework for compass navigation.

a)

Given that,

Two long parallel wires separated by 2.40 cm

The current in one wire 1.30 A

current in the other is 3.10 A

So, magnetic field due to I₁:  B₁ = {μ₀ I₁} / 2π(r/2)

B₁ = {12.57× 10⁻⁷ H/m (1.30 A)} / 2π(2.40 × 10⁻² m/2)

B₁ = 1.084 × 10⁻⁵ T

So, magnetic field due to I₁:  B₂ = {μ₀ I₂} / 2π(r/2)

B₂ = {12.57× 10⁻⁷ H/m (3.10 A)} / 2π(2.40 × 10⁻² m/2)

B₂ = 2.168 × 10⁻⁵ T

Thus, the net magnitude of magnetic field (B) = B₂ - B₁

or, B = 1.084 × 10⁻⁵ T

b)

Force is repulsive as currents are opposite in direction

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Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

Answer:

I cannot fully see the picture, but I'm going to have to tell you to go with towards the sun because it says summer.

Answer:

  A. separation is increasing at about 9.90 m/s

  B. about 9.90 m/s

  C. see attached

Explanation:

A. Both stones are accelerated at the same rate, so the difference in their velocities is the velocity stone A had when stone B was dropped. The distance between the stones increases linearly at that velocity, about 9.90 m/s.

__

B. The speed when accelerated from rest over some distance d can be found as ...

  v = √(2dg) = √(2(5 m)(9.8 m/s²)) = 7√2 m/s

The speed of stone B at 5 meters is about 7√2 ≈ 9.90 m/s.

__

C. See the attachment for a velocity vs. time graph. Stone B has traveled 10 m when its velocity is -14 m/s

Answer:

0.125

Explanation:

Density =mass/volume

Density =2.5/20

Density =0.125

Answer:

D=m/v

=2.5kg/(20/1000000)m^3

2.5kg÷0.000002m^3

1250000kgm^-3

Explanation:

20 is divided by 1000000 because m^3 is its si unit

False, Paleomagnetism, is the study of glamorous fields recorded in jewels, deposition, or archeological accoutrements . Geophysicists who specialize in paleomagnetism are called paleomagnetists.

Certain glamorous minerals in jewels can record the direction and intensity of Earth's glamorous field at the time they formed. This record provides information on the once geste of the geomagnetic field and the once position of monumental plates. The record of geomagnetic reversals saved in stormy and sedimentary gemstone sequences provides a time- scale that's used as a geochronologic tool.

substantiation from paleomagnetism led to the reanimation of the international drift thesis and its metamorphosis into the ultramodern proposition of plate tectonics. Apparent polar wander paths handed the first clear geophysical substantiation for international drift, while marine glamorous anomalies did the same for seafloor spreading. Paleomagnetic data continues to extend the history of plate tectonics back in time, constraining the ancient position and movement of mainland and international fractions( topographies).

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Biomolecules are fundamental for life. They required both energy supply and building structures.

Biomolecules are organic molecules that fundamental for life and must be ingested from the regular diet.

Biomolecules include proteins (e.g., meal proteins), lipids (fats) and also carbohydrates (e.g., glucose).

Biomolecules required both energy supply (e.g., glucose) and building structures (e.g., amino acids in proteins).

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Answer:

Sy = S sin θ = 17.8 sin 63 = 15.9 m          north of east from the start

The new efficiency of the ideal engine rated at 50% is : 59%

Given data :

Inital exhaust temperature = 20ºC

Final exhaust temperature = - 30 ºC

The efficiency of an ideal engine can be calculated with the formula below

η = 1 - Texhaust / Tinput

Therefore :

Tinput = Texhaust / 1 - η ---- ( 2 )

where : Texhaust = 293 k ,   η = 0.50 ,

insert values into equation ( 2 )

Tinput = 293 / 1 - 0.50

           = 586 k

The new efficiency of the ideal engine ;

η = 1 - T'exhaust / Tinput

  = 1 - 243 / 586

  = 1 - 0.41 = 59%

Hence we can conclude that the new efficieny is 59%

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Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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As vₙ<v, no photoelectron is emitted, thus no extraction work is required.

The minimum frequency of incident radiation below which photoelectric emission or electron emission is not feasible is referred to as the threshold frequency.

The frequency of light at which an electron will be forced to leave a metal surface is referred to as the threshold frequency.

The wavelength of incident radiation is λ = 180nm = 1800A = 1800 * 10⁻¹⁰ m.

Therefore, the frequency of incident radiation is

v = c / λ

v = 3 * 10⁸ / 1800 * 10⁻¹⁰

v = 0.166 * 10¹⁶ Hz

Therefore, threshold frequency is

v₀ = c/λₙ

vₙ = 3 * 10⁸ / 275 * 10⁻¹⁰

vₙ = = 1.09 * 10¹⁶ Hz

As vₙ<v, no photoelectron is emitted.

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Answer:  45 A

Explanation:

Primary only protection 3-phase

I =  3 phase kVA / ( 1.723 * V)

I = 30000 / ( 1.732 * 480 ) = 36.085 A

Table 450.3(B)

Currents of 9A or more column

primary only protection  = 125%

Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A

 Table 450.3(B) Note 1   does not apply, use next smaller Table 240.6(A)

Next smaller = 45 A

Answer:

 x_total = 4.29m

Explanation:

To solve this exercise we must work in parts. Let's use the law of refraction to find the angle of the refracted ray and trigonometry to find the distances.

Let's start by looking for the angles that the laser refracts

        n₁ sin θ₁ = n₂ sin θ₂

where n₁ is the air refraction compensation n₁ = 1, n₂ the water refractive index n₂ = 1,333

        θ₂ = sin⁻¹ (n₁  sin θ₁/n₂)

        θ₂ = sin⁻¹ (1 sin 27 / 1,333)

        θ₂ = sin⁻¹ 0.34057

        θ₂ = 19.9º

now let's find the distance from the edge of the pool to the point where the ₂lightning strikes the water

               tan θ₁ = y₁ / x₁

               x₁ = y₁ / tan θ₁

               x₁ = 1.49 / tan 27

               x₁ = 2,924 m

Now let's look for the waterfall in the water as far as Robin

             tan θ₂₂ = y₂ / x₂

             x₂ = y₂ / tan θ₂

             x₂ = 3.77 / tan 19.9

             x₂ = 1,364

the distance from the edge of the pool to Robin is

              x_total = x₁ + x₂

              x_total = 2,924 + 1,364

              x_total = 4.29m

The ratio of atoms in a compound is shown by the subscripts: option A.

When writing the chemical formula of a compound, the ratio of atoms in the compound is shown by the subscripts attached to the element in the compound.

For example, the chemical formula of the compound water is H₂O

From the formula, the ratio of hydrogen to oxygen is shown by the subscript:

The ratio of hydrogen to oxygen is H : O = 2 : 1

Therefore, the ratio of atoms in a compound is shown by the subscripts: option A.

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The ratio of atoms in a compound is shown by the chemical formula.

Chemical formula refers to a representation of a compound using the symbols of the elements that make up the compound. The ratio of atoms in the compound can easily be observed by looking at the subscripts in the chemical formula.

Hence, the ratio of atoms in a compound is shown by the chemical formula. The chemical formula of a compound serves as the identity of the compound.

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Answer:

If two bumper cars collide with a certain force, then they will move away from each other in opposite directions with the same force. This demonstrates Newton's third law, which states that for every action, there is an equal and opposite reaction.

Explanation: