WILL HIVE BRAINIEST A store buys 6 sweaters for $84 and sells them for $228. If p represents the total
profit in dollars and cents when the store buys any number of sweaters, s, write a
proportional equation for p in terms of s that matches the context.

We get the following sine model for the vertical displacement y of a point on the blade at time t: y = 7.5 sin(2π(3t - 1)) + 40. This model gives the height above the ground of a point on the blade at time t, measured in minutes.

Assuming that the blades move in a circular motion, the vertical displacement of a point on a blade can be modeled using a sine function.

Let's start by finding the period of the function, which is the time it takes for the blade to complete one full rotation. Since the blade completes 3 rotations every minute, the period is:

T = 1/3 minutes

Next, we need to find the amplitude of the function, which is half the distance between the highest and lowest points of the blade's path. Since the blade is 15 feet long, the amplitude is:

A = 15/2 = 7.5 feet

Finally, we need to find the vertical displacement of the blade at time t, measured in minutes. Let's assume that t=0 corresponds to a blade pointing directly upwards. As the blade rotates, it moves in a circle with radius 15 feet, centered at a height of 40 feet above the ground. The vertical displacement of the blade is the y-coordinate of the point on the circle at angle θ, where θ is given by:

θ = 2π(3t - 1) (in radians)

This formula gives the angle in radians that the blade has rotated through at time t, taking into account the fact that the blade starts at a random angle at t=0. (The "-1" term ensures that the blade starts at the top at t=0.)

Putting it all together, we get the following sine model for the vertical displacement y of a point on the blade at time t:

y = 7.5 sin(2π(3t - 1)) + 40

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Answer:

174 plums

Step-by-step explanation:

a=7b

a+58=3b

7b+58=3b

4b=58

b=14.5

29,203 earlier

87,261 now

261-87=174

In a two-player zero-sum game, player one and player two each have three strategies. Player one has a payoff matrix of (5, 2, 3), (2, 0, 4), and player two has a payoff matrix of (3, 3, 0). Find the optimal strategies for both players.1. Formulating the LP problem.

The linear programming formulation of a two-person zero-sum game is:Maximize the value of v given by: V = min (row maximums), where the minimum is taken over all rows of the matrix and the row maximums are the maximum element in each row of the matrix. Subject to the following constraints:Player 1 strategies: p11 + p12 + p13 = 1, where p11, p12, and p13 represent the probabilities of player 1 choosing strategies 1, 2, and 3, respectively.Player 2 strategies: p21 + p22 + p23 = 1, where p21, p22, and p23 represent the probabilities of player 2 choosing strategies 1, 2, and 3, respectively.Non-negativity constraints: p11, p12, p13, p21, p22, p23 ≥ 0.2. Finding the optimal strategies of the game between two playersThe given payoff matrix for the game is:5 2 32 0 43 3 0.

In this game, the row maximums are 5, 4, and 3.The linear programming formulation of the game can be represented as:Maximize V = min (row maximums)Subject to:p11 + p12 + p13 = 1p21 + p22 + p23 = 1p11, p12, p13, p21, p22, p23 ≥ 0The solution of this game is obtained by solving the following linear programming problem.Maximize V = min (5p11 + 2p12 + 3p13, 2p21 + 4p13, 3p21 + 3p22)Subject to:p11 + p12 + p13 = 1p21 + p22 + p23 = 1p11, p12, p13, p21, p22, p23 ≥ 0On solving the above problem, we get optimal strategies for the game between two players.Player 1 optimal strategy is:p11 = 0, p12 = 1/3, and p13 = 2/3.Player 2 optimal strategy is:p21 = 1/3, p22 = 0, and p23 = 2/3.Thus, player 1 should play strategy 3 with probability 2/3 and strategy 2 with probability 1/3. Player 2 should play strategy 3 with probability 2/3 and strategy 1 with probability 1/3.

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The p-value, which measures the strength of evidence against the null hypothesis, is extremely small. This indicates that the observed percentage of uninsured patients (35 out of 140) is significantly lower than the expected percentage of 32%.

Given that 32% of emergency room visitors are uninsured, we can calculate the expected number of uninsured patients in a sample of 140 patients:

Expected number of uninsured patients = (32% / 100%) * 140 = 0.32 * 140 = 44.8

Now, let's calculate the test statistic, which is the z-score, using the formula:

z = (observed value - expected value) / standard deviation

where p is the expected percentage of uninsured patients (32% or 0.32) and n is the sample size (140).

standard deviation = √((0.32 * (1 - 0.32)) / 140) = √(0.21824 / 140) = 0.03753

Now we can calculate the z-score:

z = (35 - 44.8) / 0.03753 = -9.8 / 0.03753 = -261.4

Since the z-score is very large (far into the tail of the distribution), the p-value will be extremely small, approaching zero. However, we can't directly find the exact p-value from the z-score table or calculator because it is beyond the limit of standard tables. We can approximate it as essentially zero.

Therefore, the p-value of the test statistic is approximately zero (0.0000) when rounded to four decimal places.

Therefore, based on this data, there is strong evidence to support the claim that the percentage of uninsured patients is below the expected percentage.

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Answer:

The first figure: Its the Triangle

The second figure: Its the rectangle

The third figure: Its the rectangle (for me this one would be a square)

Hope this helps!!

Answer:

\(x = 85 \: and \: y = 100 \\ \)

The correct answer is  you will get approximately £1.30 for one Australian dollar.

To find out how many British pounds you will get for one Australian dollar, we need to determine the exchange rate between the British pound and the Australian dollar.

Given that £1 = US$1.11316 and A$1 = US$0.8558, we can calculate the exchange rate between the British pound and the Australian dollar as follows:

£1 / (US$1.11316) = A$1 / (US$0.8558)

To find the value of £1 in Australian dollars, we can rearrange the equation:

£1 = (A$1 / (US$0.8558)) * (US$1.11316)

Calculating this expression, we get:

£1 ≈ (1 / 0.8558) * 1.11316 ≈ 1.2992

Therefore, you will get approximately £1.30 for one Australian dollar.

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Answer:

The numbers are 36 and 68.

Step-by-step explanation:

Let the smaller number be x.

"The larger number is four less than two times the smaller

number."

The larger number is

2x - 4

The sum of the numbers is x + 2x - 4, or 3x - 4.

"The sum of the numbers is 104."

3x - 4 = 104

3x = 108

x = 36

The smaller number is 36.

The larger number is 2x - 4, or

2x - 4 = 2(36) - 4 = 72 - 4 = 68

The larger number is 68.

Answer: The numbers are 36 and 68.

Answer: \(a_1=50,d=25\) and $475 deposited into the account on her birthdays by her 18th birthday.

Step-by-step explanation:

It is given that, on Gabriela’s first birthday, her parents gave her a $50 savings account.

Initial term : \(a_1=50\)

On every birthday after that her parents added to the account, increasing the amount they deposited by $25 each year.

Common difference : \(d=25\)

It forms an AP: 50,75,100,...

nth term of an AP is

\(a_n=a_1+(n-1)d\)

Substitute \(a_1=50\) and \(d=25\) in the above formula.

\(a_n=50+(n-1)25\)

It represents the amount deposited into the account after n birthdays.

We need to find the amount by her 18th birthday.

Put n=18 in the above equation.

\(a_{18}=50+(18-1)25\)

\(a_{18}=50+(17)25\)

\(a_{18}=50+425\)

\(a_{18}=475\)

Therefore, $475 deposited into the account on her birthdays by her 18th birthday.

We are to calculate total amount given to Gabriela on her 18th birthday

Total amount Gabriela’s parents will have deposited into the account on her birthdays by her 18th birthday is $475

Amount given to her on her first birthday = $50

Additional amount given to her each year = $25

number of years, n = 18

a1 = $50

d = $25

n = 18

Sum = a1 + (n - 1)d

= 50 + (18 - 1)25

= 50 + (17)25

= 50 + 425

= 475

sum = $475

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To find the instantaneous rate of change of the function f(x,y) = x^2 + ln(y) at (3,1) to (1,2), we can use the partial derivatives with respect to x and y:

fx(x,y) = 2x

fy(x,y) = 1/y

Then, we can use the gradient vector to find the direction of maximum increase:

∇f(x,y) = <fx(x,y), fy(x,y)> = <2x, 1/y>

At point (3,1), the gradient vector is:

∇f(3,1) = <6, 1>

At point (1,2), the gradient vector is:

∇f(1,2) = <2, 1/2>

To find the instantaneous rate of change from (3,1) to (1,2), we can use the formula for directional derivative:

Dv(f) = ∇f(x,y) · v

where v is the unit vector in the direction from (3,1) to (1,2). The direction vector v is given by:

v = <1, 2> - <3, 1> = <-2, 1>

To make v a unit vector, we need to normalize it by dividing it by its length:

|v| = sqrt((-2)^2 + 1^2) = sqrt(5)

u = v/|v| = <-2/sqrt(5), 1/sqrt(5)>

Then, the instantaneous rate of change from (3,1) to (1,2) is:

Dv(f) = ∇f(3,1) · u = <6, 1> · <-2/sqrt(5), 1/sqrt(5)> = (-12/sqrt(5)) + (1/sqrt(5)) = -11/sqrt(5)

Therefore, the instantaneous rate of change of the function f(x,y) = x^2 + ln(y) from (3,1) to (1,2) is -11/sqrt(5).

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Answer:

En matemáticas, las letras son utilizadas en las ecuaciones, para representar a través de ellas valores no conocidos que deben ser dilucidados por quien realiza la ecuación. Las letras más utilizadas con este propósito son las letras X e Y.

Así, por ejemplo, se da una suma con un valor numérico y un valor faltante denominado X, con un resultado también numérico, con lo cual el valor de X surgirá del resultado de la ecuación planteada. Por ejemplo:

8 + X = 10

X = 10 - 8

X = 2

8 + 2 = 10

To calculate the electric flux through each side of the box, we need to use Gauss's Law, which states that the electric flux through a closed surface is proportional to the total charge enclosed by that surface.

Given the magnitudes of the electric field on each side of the box, we can calculate the electric flux through each side using the formula:

Electric Flux = Electric Field * Area * Cos(θ)

where:

Electric Field is the magnitude of the electric field on a particular side of the box

Area is the area of that side of the box

θ is the angle between the electric field vector and the surface normal (which is 0 degrees for a perpendicular field)

Given the dimensions of the box, we can calculate the areas of each side:

Area of the right side = w * h

Area of the top and bottom sides = L * w

Area of the front and back sides = L * h

Area of the left side = w * h

Now, we can calculate the electric flux through each side:

Electric Flux through the right side = E₁ * Area of the right side * Cos(0°)

Electric Flux through the top side = E₂ * Area of the top side * Cos(0°)

Electric Flux through the bottom side = E₂ * Area of the bottom side * Cos(0°)

Electric Flux through the front side = E₂ * Area of the front side * Cos(0°)

Electric Flux through the back side = E₂ * Area of the back side * Cos(0°)

Electric Flux through the left side = E₃ * Area of the left side * Cos(0°)

To calculate the total charge enclosed by the Gaussian box, we use the formula:

Total Charge Enclosed = Electric Flux through the right side + Electric Flux through the left side

Now, let's calculate the values:

Area of the right side = w * h = 56.1 cm * 13.6 cm = 763.96 cm²

Electric Flux through the right side = 1156 N/C * 763.96 cm² * Cos(0°)

Area of the top and bottom sides = L * w = 89.5 cm * 56.1 cm = 5023.95 cm²

Electric Flux through the top side = 2842 N/C * 5023.95 cm² * Cos(0°)

Electric Flux through the bottom side = 2842 N/C * 5023.95 cm² * Cos(0°)

Area of the front and back sides = L * h = 89.5 cm * 13.6 cm = 1216.2 cm²

Electric Flux through the front side = 2842 N/C * 1216.2 cm² * Cos(0°)

Electric Flux through the back side = 2842 N/C * 1216.2 cm² * Cos(0°)

Area of the left side = w * h = 56.1 cm * 13.6 cm = 763.96 cm²

Electric Flux through the left side = 4484 N/C * 763.96 cm² * Cos(0°)

Total Charge Enclosed = Electric Flux through the right side + Electric Flux through the left side

Now, you can plug in the values and calculate the electric flux and total charge enclosed using the given magnitudes of the electric fields.

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Answer:

m=5/2

Step-by-step explanation:

just did

Answer:  2.78 Yards, 8.33 ft,

Step-by-step explanation:

Answer:

100 in. = 100 inches, 8 feet 4 inches, or 2.77777777778 yards.

Step-by-step explanation:

[2×3]^5 = ( 2^5 ) * (3^5) = 32 * 243 =7,776

we have used the rule

Answer:

in 7 mins she can hop 21 times

Step-by-step explanation:

24 divided by 8 = 3

24-3=21

Answer:

Natalie can hop 21 times in 7 minutes

Step-by-step explanation:

To figure out how many times she can hop in 7 minutes you need to find the average hop each minute.

First, you write 24/8. You simply that to 3/1.

So Natalie can jump 3 times in 1 minute.

If you want 7 minutes, you multiply 1 by 7, and 3 by 7, which gets you 21 hops for 7 minutes.

-I hope this helps!

Answer:

Part 1

|A| = -23

|Ax| = -46

|Ay| = 46

|Az| = -92

Part 2

X = 2

Y = -2

Z = 4

Step-by-step explanation:

The values of x, y and z from the given system of equations are 2, -2 and 4 respectively.

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

The given system of equations are

3x+4y-z =-6 ---------------(i)

5x+8y+2z=2 ----------(ii)

-x+y+z=0 ---------------(iii)

From equation (iii), z=x-y

Substitute z=x-y in equation (i), we get

3x+4y-(x-y)=-6

3x+4y-x+y=-6

2x+5y=-6 -----------(iv)

Substitute z=x-y in equation (ii), we get

5x+8y+2(x-y)=2

5x+8y+2x-2y=2

7x+6y=2 -----------(v)

From equation (iv) and (v), we have

7(2x+5y=-6)

-2(7x+6y=2)

14x+35y=-42

-14x-12y=-4

__________

       23y=-46

y=-2

Substitute y=-2 in equation (v), we get

7x+6(-2)=2

7x=14

x=2

Substitute x=2 and y=-2 in equation (iii), we get

-2-2+z=0

z=4

Hence, the values of x, y and z are 2, -2 and 4 respectively.

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Block diagram representation of R(di/dt) + L(d²i/dt²) + (1/C)i = dV/dt.

The given equation is R(di/dt)+L(d²i/dt²)+(1/C)i = dV/dt.

The block diagram is an essential tool in the analysis and design of dynamic systems. The blocks represent the interconnected subsystems of the system.

The interconnections and external inputs and outputs are shown by the connections between the blocks.The block diagram representation of the equation R(di/dt) + L(d²i/dt²) + (1/C)i = dV/dt is given below.

Therefore, the block diagram representation of the given equation is as follows:

Block diagram representation of R(di/dt) + L(d²i/dt²) + (1/C)i = dV/dt.

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Answer:

43 ft apart

Step-by-step explanation:

They are forty feet apart, because the bird is 40ft away from the ground, and then there is an extra 3 feet below the ground, so you add them up to get 43 ft

The CLI option on the MODEL statement of an MLR analysis in PROC GLM produces confidence intervals for the mean response at all predictor combinations in the dataset. b

The CLI option stands for "Confidence Level of Intervals," and it specifies the level of confidence for the confidence intervals produced.

By default, the CLI option is set to 0.95, which means that the confidence intervals produced will have a 95% level of confidence.

These confidence intervals provide a range of values within which the true mean response at a particular combination of predictor values is expected to fall with a specified level of confidence.

They can be useful for assessing the uncertainty associated with the estimated mean response at different combinations of predictor values and for making inferences about the relationships between predictors and the response variable.

The CLI option, which stands for "Confidence Level of Intervals," defines the degree of confidence in the confidence intervals that are generated.

The CLI option's default value of 0.95 designates a 95% degree of confidence for the confidence intervals that are generated.

With a given degree of confidence, these confidence intervals show the range of values within which the real mean response for a specific set of predictor values is anticipated to fall.

They can be helpful for determining the degree of uncertainty surrounding the predicted mean response for various combinations of predictor values and for drawing conclusions on the connections between predictors and the response variable.

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The particular solution to the differential equation \(4\frac{d^2y}{dt^2} + 5\frac{dy}{dt} +3y=e^{4it}\) is given by \(g(t) = \frac{1}{-61+20i} e^{4it}\).

An equation involving one or more functions and their derivatives is referred to as a differential equation. The rate of change of a function at a place is determined by the derivatives of the function. It is mostly employed in disciplines like physics, engineering, biology, and others. Studying equation-satisfying solutions and the solutions' characteristics is the main goal of differential equations.

The solution of a differential equation is a function that fulfils the specified differential equation. A generic solution is one that has as many arbitrary constants as the order of the differential equation. A specific solution is the one devoid of arbitrary constants. 

\(4\frac{d^2y}{dt^2} + 5\frac{dy}{dt} +3y=e^{4it}\)

(4D² + 5D + 3) y = \(e^{4it}\)

Using the particular solution,

\(g(t) = \frac{1}{f(D)} e^{at}\)

we have,

f(D) = (4D² + 5D + 3)

therefore,

\(g(t) = \frac{1}{4(4i)^2+5(4i)+3} e^{at}\\\\= \frac{1}{-64+20i+3} e^{at}\\\\g(t) = \frac{1}{-61+20i} e^{4it}\)

Therefore, the particular equation is : \(g(t) = \frac{1}{-61+20i} e^{4it}\).

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Complete question:

Find a particular solution Find a particular solution to the differential equation dạy  4d^2y/dt^2 +5 dy/dt + 3y = e^4it In the form y = Ae^4it, where A is a complex constant. Here i = -1 is the square root of -1. g(t) =

For the given matrices A = \(\left[\begin{array}{ccc}0&-2\\4&7\\\end{array}\right]\) and B = \(\left[\begin{array}{ccc}3&-2\\6&-9\\\end{array}\right]\) the value of

C = \(\left[\begin{array}{ccc}-8&-20\\24&-75\\\end{array}\right]\)

C₁₁ = -8 , C₁₂ = -20 , C₂₁ = 24 and C₂₂ = -75.

As given in the question,

Given matrices are

A = \(\left[\begin{array}{ccc}0&-2\\4&7\\\end{array}\right]\) and B = \(\left[\begin{array}{ccc}3&-2\\6&-9\\\end{array}\right]\)

C = BA

Both A and B  are of order 2 × 2 .

Multiplication of matrices BA is possible with order 2 × 2.

Substitute the value of matrix A and matrix in BA we get,

BA

=  \(\left[\begin{array}{ccc}3&-2\\6&-9\\\end{array}\right]\)  \(\left[\begin{array}{ccc}0&-2\\4&7\\\end{array}\right]\)

= \(\left[\begin{array}{ccc}0-8&-6-14\\0+24&-12-63\\\end{array}\right]\)

= \(\left[\begin{array}{ccc}-8&-20\\24&-75\\\end{array}\right]\)

C =  \(\left[\begin{array}{ccc}-8&-20\\24&-75\\\end{array}\right]\)

Value of C₁₁ = -8

Value of C₁₂ = -20 ,

Value of C₂₁ = 24

Value of C₂₂ = -75.

Therefore, for the given matrices A = \(\left[\begin{array}{ccc}0&-2\\4&7\\\end{array}\right]\) and B = \(\left[\begin{array}{ccc}3&-2\\6&-9\\\end{array}\right]\) the value of

C = \(\left[\begin{array}{ccc}-8&-20\\24&-75\\\end{array}\right]\)

C₁₁ = -8 , C₁₂ = -20 , C₂₁ = 24 and C₂₂ = -75.

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Answer: 2.95x+39.95(12)

Step-by-step explanation:

Hi, to answer this question we have t write an expression with the information given:

The yearly cost for x movie rentals is equal to : the product of the cost of each movie (2.95) and the number of movies (x) ;plus the product of the monthly fee (39.95) and the number of months in a year (12)

Mathematically speaking:

2.95x+39.95(12)

Answer:

D-295x+39.95(12)​

Step-by-step explanation:

EDG2021

Answer:

100

Step-by-step explanation:

(50-45)*20

=5*20

=100

PLEASE GIVE BRAINLIEST

Answer:

Renzi can type 100 more words than Samuel

Step-by-step explanation:

PLZ MARK BRAINLIEST!!!

Answer:

Wym lol

Step-by-step explanation:

Answer:

Wut...

Step-by-step explanation:

Ello m8 but what do you need?

Answer: 2\(\sqrt{2}\)

Step-by-step explanation: First plug in the value, which is \(\sqrt{8}\)

Then divided to 2\(\sqrt{2}\)

Answer:

Step-by-step explanation:

Area of rectangle= 250 sq.units

Width = (250-10)÷3

          = 240÷3

          = 80 units