Because your brain cant handle all of the information.
A whale swims at a constant speed of 8 m/s for 17 s. What distance did the whale travel in km?
Answer:
0.136 kmExplanation:
whale speed = 8 m/s for 17 sec.
find distance traveled in km
distance = velocity x time
= 8 m/sec. x 17 sec.
= 136 meters x 1 km
1000 meters
= 0.136 km
Prove me wrong:
So you know how you can't really breathe in smoke or it'll make u sick right? and let's use wood for example, when you burn wood, it kinda shrinks, right? so when it burns, it's kinda like it's evaporating, and when something evaporates, it has to go somewhere, right? so, in conclusion, the reason you cant breathe in the smoke from wood is that if you do, a piece of wood will form in your lungs and kill you.
If a truck weighs 195,000N what is the mass of the truck
Answer:
19500kg
Explanation:
If you divide 195000N by 10
A tap supplies water at 26°c while another supplies at 82°c. If a man wishes to bath with water at 40°c, what is the ratio of the mass of hot water to that of cold water
Where a tap supplies water at 26°c while another supply at 82°c. If a man wishes to bath with water at 40°c, then the ratio of the mass of hot water to that of cold water is: 1/3.
What is the rationale for the above response?The ratio of the mass of hot water to that of Cold water is determined as follows:
M₁C (82 40) = M₂C (40-26)
Where M₁C is the Mass of Tap 1; and
M₂C is the Mass of Tap 2.
Thus,
M₁C (82 40) = M₂C (40-26)
M₁/M₂ = 14/42
= 1/3
Thus, it is right to state that the ratio of the mass of hot water to that of cold water is: 1/3.
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If you have 5 protrons and 6 neutrons how many electrons would you need to make a neutral atom
If a machine exerts 12,000 J of work with 800 N of force, what distance did it cover?
Show Work!!!
Hi! Let's see.
TOPIC: Mechanical Work.Explanation:
Data:
Work(W) = 12000 JoulesForce(F) = 800 NewtonsDistance(d) = ?==================================================================
We apply the distance formula:
\(\boxed{\boxed{\bold{d=\frac{W}{F}}}}\)We replace by the data:
\(\boxed{d=\frac{12000J}{800N}}\)It divides:
\(\boxed{\bold{d=15m}}}\)Answer: The distance is 15 meters.
Cordially Alejanndraax. Greetings!
The distance covered by the machine is 15 m.
What is meant by work done ?Work done on an object is defined as the dot product of the force applied on the object and the displacement of the object.
Here,
Amount of work done by the machine, W = 12000 J
Force exerted on the machine, F = 800 N
The equation for work done,
W = F.s
Therefore, displacement,
s = W/F
s = 12000/800
s = 15 m
Hence,
The distance covered by the machine is 15 m.
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Question 2 A generator is connected through a transformer to a synchronous motor. Reduced to the same base, the per-unit subtransient reactances of the generator and motor are 0.15 and 0.35, respectively, and the leakage reactance of the transformer is 0.10 per unit. A three-phase fault occurs at the terminals of the motor when the terminal voltage of the generator is 0.9 per unit and the output current of the generator is 1.0 per unit at 0.8 power factor leading. Find the subtransient current in per unit in the fault, in the generator, and in the motor. Use the terminal voltage of the generator as the reference phasor and obtain the solution (a) by computing the voltages behind subtransient reactance in the generator and motor and (b) by using Thévenin's theorem.
(a) The sub transient current in per unit at the fault is approximately 0.6428, in the generator is approximately 2.523, and in the motor is approximately 0.9190.
(b) Using Thévenin's theorem, the subtransient current in per unit at the fault is approximately 0.6428.
(a) Computing the voltages behind subtransient reactance:
To find the subtransient current in per unit at the fault, in the generator, and in the motor, we need to compute the voltages behind subtransient reactance in both the generator and motor.
Per-unit subtransient reactance of the generator (X''g) = 0.15
Per-unit subtransient reactance of the motor (X''m) = 0.35
Leakage reactance of the transformer (Xl) = 0.10
Terminal voltage of the generator (Vg) = 0.9 per unit
Output current of the generator (Ig) = 1.0 per unit
Power factor of the generator (pf) = 0.8 leading
The subtransient voltage in the generator (V''g) can be calculated using the formula:
V''g = Vg - (X''g * Ig)
V''g = 0.9 - (0.15 * 1.0)
V''g = 0.75 per unit
The subtransient voltage in the motor (V''m) can be calculated using the formula:
V''m = V''g * (X''g / X''m)
V''m = 0.75 * (0.15 / 0.35)
V''m ≈ 0.3214 per unit
Now, let's calculate the subtransient current at the fault (If):
If = V''m / (X''m + Xl)
If = 0.3214 / (0.35 + 0.10)
If ≈ 0.6428 per unit
The subtransient current in the generator (I''g) can be calculated using the formula:
I''g = (V''g - V''m) / X''g
I''g = (0.75 - 0.3214) / 0.15
I''g ≈ 2.523 per unit
The subtransient current in the motor (I''m) can be calculated using the formula:
I''m = (V''m - 0) / X''m
I''m = 0.3214 / 0.35
I''m ≈ 0.9190 per unit
Therefore, the subtransient current in per unit at the fault is approximately 0.6428, in the generator is approximately 2.523, and in the motor is approximately 0.9190.
(b) Using Thévenin's theorem:
By using Thévenin's theorem, we can calculate the subtransient current at the fault (If) directly.
The equivalent impedance looking back into the generator and motor combined can be calculated as:
Zeq = (X''g * X''m) / (X''g + X''m + Xl)
Zeq = (0.15 * 0.35) / (0.15 + 0.35 + 0.10)
Zeq ≈ 0.0567 per unit
The equivalent subtransient voltage behind the impedance (Veq) can be calculated as:
Veq = Vg - (Zeq * Ig)
Veq = 0.9 - (0.0567 * 1.0)
Veq ≈ 0.8433 per unit
Finally, the sub-transient current at the fault (If) is given by:
If = Veq / (Zeq + X''m)
If = 0.8433 / (0.0567 + 0.35)
If ≈ 0.6428 per unit
Therefore, using Thévenin's theorem, the sub-transient current in per unit at the fault is approximately 0.6428.
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A vector starts at the point (0, 0) and ends at (3, 1). What is the magnitude and direction of the displacement?
Answer:
tbh vector does not have any direction at all the answer is 0
What is the momentum, in kg m/s, of a tyre of mass 6 kg rolling along at a velocity of 3m/s?
Answer:
p = 18 kg-m/s
Explanation:
Given that,
The mass of tyre, m = 6 kg
The velocity of the tyre, v = 3 m/s
We need to find the momentum of the tyre. We know that, the momentum of an object is equal to the product of mass and velocity. SO,
p = mv
\(p=6\ kg\times 3\ m/s\\\\=18\ kg-m/s\)
So, the momentum of the tyre is equal to 18 kg-m/s.
Question at position 3
The table shows mass and weight data of some common items.
Based on the data, which conclusion is valid regarding the relationship between the force of gravity, mass, and weight?
The table shows mass and weight data of some common items.
Based on the data, which conclusion is valid regarding the relationship between the force of gravity, mass, and weight?
The weight of an object depends on the force of gravity of the planet, but the mass does not.
Neither the mass nor the weight of an object depends on the force of gravity.
The mass of an object depends on the force of gravity of the planet, but the weight does not.
Both the mass and the weight of an object depend on the force of gravity.
An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. It depends on the object's mass and acceleration due to gravity.
Mass is an intrinsic unchanging property. Weight is a force and it depends on gravitational force. This force is directly proportional to mass the more mass the object has the stronger the force of gravity will be. Because of this, it turns out that gravity does not matter when we compare the distance traveled by objects with different masses. The important part of the force is air resistance also called drag.
The slope of the graph is the relationship between weight and mass. The slope tells how many newtons of weight pull down on each kilogram of mass. Mass is the measure of the amount of matter in an object. This is an immutable property inherent in the body. Mass cannot be destroyed or created. Weight is the production of mass and acceleration due to gravity.
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The work done in accelerating an object along a frictionless horizontal surface is equal to the change in the object's
(A) momentum
(B) velocity
(C) potential energy
(D) kinetic energy
"The work done in accelerating an object along a frictionless horizontal surface is equal to the change in the object's kinetic energy."
The amount of internal and mechanical energy that objects possess fluctuates as a result of work. When work is done on a system or an object, energy is contributed to it. When a system or item accomplishes work, some of its energy is transferred to something else.
Work involves the transfer of energy from the agent to the object, which modifies the object's motion.
The energy of motion is known as kinetic energy, and it can be observed in the motion of objects or subatomic particles. Kinetic energy can be found in all particles and moving objects. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.
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Two solutions are added together and the new solution becomes hot. This tells you that
A.
the solutions are not soluble.
B.
a gas is being produced.
C.
a chemical change is taking place.
D.
the physical properties are the same.
Answer:
C
Explanation:
the reason the new solution becomes hot is because an exothermic reaction is taking place. This is a kind of chemical change.
a playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.350 rev/s. what is its angular velocity (in rev/s) after a 15.0 kg child gets onto it by grabbing its outer edge? the child is initially at rest.
Angular velocity (in rev/s) after a 15.0 kg child gets onto it by grabbing its outer edge is 1.575 rad/s.
The angular velocity of the merry-go-round after a child gets on it is equal to the angular velocity of the child plus the angular velocity of the merry-go-round.
The angular velocity of a rotating object can be calculated using a formula:
ω = ω + (m/r)
where ω is the original angular velocity, m is the mass of an object that's been added to it, r is its radius, and (m/r) is the change in mass divided by its radius. When we plug in our values for this problem, we get:
ω = 0.350 rad/s + ((15 kg)/(1.8 m)) rad/s
= 0.350 rad/s + 1.25 rad/s
= 1.575 rad/s
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please help me to solve the problem
?cm=1m
A diffuse sound field is desired within a theater. The following room treatment would best
contribute to this acoustic characteristic:
(a) the back wall of the stage (behind the performers) is concave in shape
(b) a series of convex panels are suspended from the entire ceiling
(c) velvet curtains are hung on the side walls of the theater
(d) the back wall of the theater is finished with an acoustically reflective material
To create a diffuse sound field within a theater, the goal is to distribute sound energy evenly throughout the space, reducing the presence of distinct echoes and reflections.
Among the given options, the treatment that would best contribute to this acoustic characteristic is:
(c) Velvet curtains hung on the side walls of the theater.
Velvet curtains have a soft and textured surface that can absorb and scatter sound waves, preventing them from reflecting directly back into the audience or creating focused sound reflections. This helps to reduce the presence of strong reflections and echoes, promoting a more diffuse sound field within the theater.
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An environmental scientist performs research to discover what is in the solid
garbage of the average American family. She calculates these amounts in
kilograms per year. The categories are paper, yard waste, metals, glass, plastics,
food scraps, and "other." Which kind of graph should she use to present her
finding, and how should the graph be labeled?
A. She should use a line graph. The x-axis should be labeled "Kind
of garbage." The y-axis should be labeled "kilograms per year."
B. She should use a circle graph. Each segment of the graph should
be labeled "number of kilograms per year."
C. She should use a bar graph. The bottom of each bar should be
labeled "kilograms per year." The vertical side should be labeled
"type of garbage."
D. She should use a bar graph. The bottom of each bar should be
labeled with the category of garbage. The vertical side should
have a scale and be labeled "kilograms per year."
Answer:
D i took the test
Explanation:
Answer:
The answer is D.
Explanation:
The other ones just don't make sense. AT ALLLLLL!!!!!!!!!!!!!!!!!!!!!!!
a pilot has just started on the glide path for landing at an airport where the length of the runway is 9000 feet. the angles of depression from the plane to the ends of the runway are 17.5 degrees and 18.8 degrees. find the air distance the plane must travel until touching down on the near end of the runway.
The air distance the plane must travel until touching down on the near end of the runway is approximately 59,612 feet.
To find the air distance the aeroplane must travel until touching down on the near end of the runway, we can use the trigonometric relationship between the angles of depression and the distance between the aeroplaneand the ends of the runway.
Let's assume that the aeroplane is at point P, and the two ends of the runway are at points A and B, with A being the near end of the runway. also, we can draw a right triangle with hypotenuse Dad and angles of depression of17.5 and18.8 degrees at points A and B, independently. Using trigonometry, we can express the length of the runway AB in terms of the distance Dad and the angles of depression
tan(17.5) = AB/ Dad
tan(18.8) = AB/( PA 9000)
working these two equations contemporaneously for PA, we get
Dad = AB/ tan(17.5)
Dad = AB/( tan(18.8)- tan(17.5))
Setting these two expressions for PA equal to each other and working for AB, we get
AB = 9000/( tan(18.8)- tan(17.5)) = 59612 bases( approx.)
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bulbs A, B, and C in figure Q32.11 are identical, and all are glowing.
a) Rank in order, from most to least, the brightness of the three bulbs. Explain
b) Suppose a wire is connected between points 1 and 2. What happens to each bulb? does it get brighter, stay the same, get dimmer, or go out? Explain.
a) The resistors in series have the same current.
b. The current through the resistor determines how much power passes through it
Ranking in order the brightnesses of the bulbs?a) A succession of resistors will share the same electricity. Therefore, the current going through light A is the same as the sum of the currents going through bulbs B and C. The brightness of light A is greater than that of bulbs C and B because the current is higher.
(b) When a wire is connected between 1 and 2, then the bulbs B and C are short circuited and no current pass through them. Then more current passes through the bulb A.
Bulb A: glows brighter ( due to more current )
Bulb B: go out ( due to no current )
Bulb C: go out ( due to no current )
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What is a destructive insect resembling a grasshopper?.
These grasshopper-related insects generate massive swarms that travel across areas. Since the Pharaohs ruled ancient Egypt, plagues of locusts have destroyed societies and continue to cause devastation now.
What exactly is regarded as an insect?Invertebrates (animals without a backbone) have a hard exterior covering called an exoskeleton. The head, thorax, and abdomen make up an insect's three-part body. The majority of mature insects also have wings, and they all have six legs. Insects come in more than a million different varieties.
What kind of bug is most prevalent?Ants are the most common bug in the world, which should not be surprising. There are around 10,000 species of these colonial hymenopterans, with an estimated population size of 10–100 trillion individuals worldwide.
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Drag each label to the correct location on the table. Sort the units based on the measurement system they're used in. kilometer milligram inch kelvin Fahrenheit Ounce yard SI System US Customary System
Answer:
The correction is the state of mind being for the Fahrenheit that is calculator from anarchy
Explanation:
Answer:
Si system is :kilo miligram kelvin
us system is: Fahrenheit Ounce yard inch
Explanation:
a man traveled 2.2 in to the store in 5.0 minutes and then stayed at the store for 10.0 minutes. he than traveled 6.1 kn to the bank in 12 minutes and stayed in the bank for 5.0 minutes. he than travelled 4.7 km to his home in 7.0 minutes. what was his average speed in units of km/min
The speed of the man is obtained as 0.54 Km/min.
What is the average speed?One of the first things that must come to our minds is that fact that speed is a scalar quantity and as such we do not look at the direction of the movement of the object but just the algebraic sum.
We then have that;
Total distance = 2.2 + 6.1 + 4.7 = 13 Km
Total time = 5 + 12 + 7 = 24 min
Note that we do not count the times that were spent in the store without moving
The speed is now; = 13 Km/24 min
= 0.54 Km/min
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the scissor lift is comprised of a 6-m-wide lift platform, a single double-actinghydraulic cylinder, and four support struts. the struts are 4-m-long and are pinnedtogether at p halfway along their length. the lift platform is pin connected to the struts atc and is supported by rollers in a slot at d. the pins at c are located 1.2 m from the rightedge of the lift platform. the scissor lift is supported by pins at a and rollers at b. thelift platform weighs 1000 n and its center of gravity is at the geometric center of theplatform (ignore the slot). the weight of the struts of the lift can be safely neglected(their weight is small relative to the weight of the platform and boxes).
The scissor lift consists of a 6-m-wide lift platform, a hydraulic cylinder, and four support struts.
The lift platform is 6 meters wide.
The hydraulic cylinder is a double-acting cylinder, meaning it can extend and retract.
The four support struts are each 4 meters long and pinned together at point P, which is located halfway along their length.
The lift platform is pin connected to the struts at point C and is supported by rollers in a slot at point D.
The pins at point C are located 1.2 meters from the right edge of the lift platform.
The scissor lift is supported by pins at point A and rollers at point B.
The lift platform weighs 1000 Newtons, and its center of gravity is at the geometric center of the platform.
The scissor lift is a mechanical device used for lifting and positioning heavy objects. It consists of a wide lift platform, a hydraulic cylinder, and support struts. The specific dimensions and arrangements of the lift components provide stability and allow for vertical movement of the platform. The weight of the struts is neglected as it is small compared to the weight of the platform and the loads being lifted.
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So I know this is a weird question but if you were to send a piece of paper from the Milky Way to the andromeda galaxy how long would it take (please don’t answer with I don’t know people keep doing that)
Answer:
Roughly 4.5 billion years
1. battery, light bulb, switch, all connected in seriesDirections: Create a circuit diagram for each item.
ANSWER and EXPLANATION
When the components of a circuit are connected in series, they are connected along a single electrical path with each component having the same current flowing through it.
To draw the circuit diagram, use the appropriate symbol for each object. Let us draw it now:
That is the circuit diagram.
A car is decelerating at the rate of 3 km/s 2. if its initial speed is 66 km/s, how long will it take the car to come to a complete stop?
The car with an initial speed of 66 km/s will come to a complete stop at 22 s
The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:
t = (vf - vi) /a
Where:
vf = final velocityvi = initial velocityt = timea = accelerationInformation about the problem:
vi= 66 km/svf = 0 m/sa= - 3 km/s2t = ?Applying the time formula, we have:
t = (vf - vi) /a
t = (0 m/s - 66 km/s) / - 3 km/s2
t = (- 66 km/s) / - 3 km/s2
t = 22 s
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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The north pole of one bar magnet is near the south pole of another bar
magnet. What happens to the magnets?
O A. They repel each other.
B. They attract each other.
C. They twist away from each other.
O D. They neither attract nor repel each other.
Answer: they attract each other .
Explanation: jus took it.
Two carts, moving at opposite directions, collide and recoil. Which question would help determine if the system of two carts is open or closed? A) Do the carts have the same mass? B) Do the carts have different initial velocities? ) Is energy transferred from one cart to the other? D) Is the total momentum constant before and after the collision?
Answer:D
Explanation:
i’m not sure if that’s right but that’s what i think
A string is used to pull a wooden block across the floor without accelerating the block. The string makes an angle to the horizontal as shown below
Does the force applied via the string do work on the block?
Answer: Yes
Explanation: The block moves a distance d under the influence of the force, so work is done by the force. Note that since the object is not accelerating, there is another force present, most likely friction.
b.
A train is moving to the right. The force of air resistance and the surface friction from the tracks totals 259,800 N . In order for the train to keep moving at a constant velocity, how much forward force is the engine providing?
The engine is providing a forward force of 259,800 N to keep the train moving at a constant velocity.
What is forward force?
Forward force is the force applied in the direction of motion, which causes an object to move or maintain a constant velocity.
Constant velocity refers to the motion of an object moving in a straight line at a steady speed, without changing its direction. The velocity of the object is constant when its speed and direction remain unchanged over time, regardless of whether the object is moving or stationary.
Since the train is moving at a constant velocity, the net force acting on the train is zero. Therefore, the forward force provided by the engine must be equal in magnitude and opposite in direction to the force of air resistance and surface friction.
So, the magnitude of the forward force provided by the engine is:
Magnitude of forward force = Magnitude of force of air resistance and surface friction
Magnitude of forward force = 259,800 N
Therefore, the engine is providing a forward force of 259,800 N to keep the train moving at a constant velocity.
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Need help please as soon as possible
1. speed=distance/time
but D=400m
T=32s
there fore
speed=400/32=12.5mls
back ward force=forward force