Answers
The object requires the MOST power to lift a 2 kg box 2 m in 1 s. Hence, option (B) is correct.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power required for lifting a 2 kg box 1 m in 1 s = (2×9.8×1)/1 watt = 19.6 watt.
Power required for lifting a 2 kg box 2 m in 1 s = (2×9.8×2)/1 watt = 39.2 watt.
Power required for lifting a 2 kg box 1 m in 2 s = (2×9.8×1)/2watt =9.8 watt.
Power required for lifting a 2 kg box 2 m in 2 s = (2×9.8×2)/2watt =19.6 watt.
So, The most power required in lifting a 2 kg box 2 m in 1 s.
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Related Questions
Write a short essay describing the six key features of Mesopotamia. Be sure to include how it advanced human society as a whole.
Answers
Mesopotamia, with its key features of specialization, government, cities, religion, trade, and written records, advanced human society by fostering economic growth, establishing governance structures, creating urban centers, facilitating cultural exchange, promoting trade networks, and revolutionizing communication and knowledge preservation through writing.
Mesopotamia, often referred to as the "cradle of civilization," possessed several key features that contributed to its advancement and influenced human society as a whole. These features include specialization, government, cities, religion, trade, and written records. Let's explore each of these key features and their significance.
Specialization: Mesopotamian society developed specialization, where individuals began to focus on specific occupations and trades. This led to the emergence of skilled craftsmen, farmers, priests, scribes, and merchants. Specialization allowed for the production of surplus goods, leading to economic growth and the establishment of a more complex society.
Government: Mesopotamia witnessed the development of early forms of government. Initially, city-states were governed by religious leaders known as priest-kings. Over time, as society grew more complex, secular leaders, such as kings, emerged to rule the city-states. These early forms of governance laid the foundation for later systems of government and administration.
Cities: Mesopotamia was characterized by the rise of urban centers. These cities served as political, economic, and cultural hubs. They were densely populated, with advanced infrastructure, including defensive walls, temples, markets, and residential areas. The cities of Mesopotamia, such as Ur, Uruk, and Babylon, provided the framework for the organization and development of early urban societies.
Religion: Religion played a central role in Mesopotamian society. The people of Mesopotamia believed in a pantheon of gods and goddesses and practiced polytheism. Temples were constructed as sacred spaces to honor and worship deities. Priests held significant influence, serving as intermediaries between the people and the divine. Religious beliefs and rituals provided a sense of identity, social cohesion, and moral guidance to the Mesopotamian community.
Trade: Mesopotamia's strategic location between major rivers, the Tigris and Euphrates, facilitated extensive trade networks. The abundance of resources, such as fertile land for agriculture, allowed for surplus production. This surplus was exchanged with neighboring regions, fostering trade and the establishment of commercial relationships. The exchange of goods and ideas through trade networks promoted cultural diffusion and contributed to the overall prosperity and interconnectedness of Mesopotamia.
Written Records: Mesopotamia is credited with the invention of writing, making it one of the earliest literate civilizations. Scribes used wedge-shaped marks known as cuneiform to record important information on clay tablets. The development of writing enabled the recording of laws, contracts, administrative documents, literature, and historical accounts. Written records not only facilitated communication and administration but also served as a means of preserving knowledge and passing it down through generations.
Collectively, these key features of Mesopotamia played a pivotal role in advancing human society as a whole. Specialization allowed for the efficient allocation of resources and the growth of economies. The establishment of early forms of government provided organization and stability to communities. Urbanization transformed social structures and fostered cultural and intellectual exchange. Religion served as a unifying force and provided a moral framework. Trade networks expanded horizons and facilitated the exchange of goods and ideas. Finally, the invention of writing revolutionized communication, education, and the preservation of knowledge.
Therefore, Mesopotamia's legacy as a cradle of civilization lies in its ability to establish foundations for complex societies, laying the groundwork for subsequent advancements in various aspects of human life.
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Find the direction and magnitude of the vectors (a) A = (25m)x + (-12m)y(b) B = (2.0m)x + (15m)y and(c) A + B
Answers
ANSWER
\(\begin{gathered} a)\theta=-25.6\degree;|A|=27.73m \\ b)\theta=82.4\degree;|B|=15.13m \\ c)\theta=6.3\degree^{};|A+B|=27.17m \end{gathered}\)EXPLANATION
To find the direction of a two-dimensional vector, we apply the formula:
\(\theta=\tan ^{-1}(\frac{a_y}{a_x})\)To find the magnitude of a two-dimensional vector, we apply the formula:
\(|a|=\sqrt[]{(a^{}_y)^2+(a_x)^2}\)a) The direction of vector A is:
\(\begin{gathered} \theta=\tan ^{-1}(\frac{-12m}{25m}) \\ \theta=\tan ^{-1}(-0.48) \\ \theta=-25.6\degree \end{gathered}\)The magnitude of vector A is:
\(\begin{gathered} |A|=\sqrt[]{(25m)^2+(-12m)^2} \\ |A|=\sqrt[]{625m^2+144m^2}=\sqrt[]{769m^2} \\ |A|=27.73m \end{gathered}\)b) The direction of vector B is:
\(\begin{gathered} \theta=\tan ^{-1}(\frac{15m}{2m}) \\ \theta=\tan ^{-1}(7.5) \\ \theta=82.4\degree \end{gathered}\)The magnitude of vector B is:
\(\begin{gathered} |B|=\sqrt[]{(2.0m)^2+(15m)^2} \\ |B|=\sqrt[]{4m^2+225m^2}=\sqrt[]{229m^2} \\ |B|=15.13m \end{gathered}\)c) First, we have to find the sum of A and B:
\(\begin{gathered} A+B=(25m)x+(-12m)y+(2.0m)x+(15m)y \\ A+B=(25m+2.0m)x+(-12m+15m)y \\ A+B=(27m)x+(3m)y \end{gathered}\)The direction of the vector (A + B) is:
\(\begin{gathered} \theta=\tan ^{-1}(\frac{3m}{27m}) \\ \theta=\tan ^{-1}(0.1111) \\ \theta=6.3\degree^{} \end{gathered}\)The magnitude of the vector (A + B) is:
\(\begin{gathered} |A+B|=\sqrt[]{(27m)^2+(3m)^2} \\ |A+B|=\sqrt[]{729m^2+9m^2}=\sqrt[]{738m^2} \\ |A+B|=27.17m \end{gathered}\)Does an object travel farther on a smooth or slippery surface or on a rough surface? Why?
Answers
Answer:
There is much more friction on the rough surface than there is on the smooth surface.
Explanation:
write down the value of
920 kg in g
Answers
Answer:
920000
Explanation:
Each kg contains 1,000 grams
half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value after
Answers
Answer:
44 years
Explanation:
Use half life equation:
A = A₀ (½)^(t / T)
where A is the final amount,
A₀ is the initial amount,
t is time,
and T is the half life.
0.25 A₀ = A₀ (½)^(t / 22)
0.25 = (½)^(t / 22)
t / 22 = 2
t = 44
44 sec is half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value.
What is half-life?The period of time it takes for one-half of a radioactive isotope to decay is known as the half-life. A given radioactive isotope's half-life is constant; it is unaffected by external factors and independent of the isotope's starting concentration.
Use half life equation:
A = A₀ (½)^(t / T)
where A is the final amount,
A₀ is the initial amount,
t is time,
and T is the half life.
0.25 A₀ = A₀ (½)^(t / 22)
0.25 = (½)^(t / 22)
t / 22 = 2
t = 44 sec
44 sec is half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value.
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Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant speed for another
km. That part of her trip takes her 2 h. What is her average speed?
Answers
Answer:
Nicki's Average Speed is 6 km
Explanation:
If Nicki rides her bike at a constant speed for 1 hour, that means that Nicki will stay at a constant rate for another 2 hours.
Thus your answer: 6 km
what is the force of a body which have mass of 7 kg
Answers
Answer:
Force acting on a body of mass 7 kg which produces an accceleration of 10 m/s2 is 70 N
Answer:
10 m/s2 or 70 newtons.
Explanation:
............................
............
Let's practice this process of using the position function to
determine the position at a certain time. If an object is
moving with a constant velocity of 970 cm/s and starts at
an initial position of 40 cm at t=0, what will be the
position at t= 0.2 s?
Answers
1.94 m will be the distance (position) at t= 0.2 s.
Velocity=970 cm/s
distance=?
time=0.2
distance=Velocity×time
distance=970 cm/s × 0.2
distance=194 cm= 1.94 m
Distance is the length between two locations or things, independent of direction. Since distance is a scalar property, it only takes into consideration the total magnitude and ignores the start and finish positions. Since distance is a scalar attribute, it can only have a positive or zero value; it cannot have a negative value. The most common unit of measurement for distance is the meter (m), while larger distances can also be stated in kilometers (km), while smaller distances can be expressed in centimeters (cm) or millimeters (mm). When calculating distance, the letter D is the conventional way to represent the distance traveled.
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If it takes Jeff 3 hours and 33 minutes to drive 500 miles, what is his average velocity over this time?
Answers
Answer:
141 mphExplanation:
aver. velocity = distance over time
= 500 miles
3 hours + (33 min. x 1 hr. )
60 min.
= 500 miles
3.55 hours
= 140.845 ≈ 141 miles / hour
why might someone buy a more expensive CFL intead of an incandescent light bulb ?
Answers
Answer:
Even though CFL are more expensive, they tend to last longer. Research proves that CFL uses 1/4 to 1/3 the same amount of energy to produce the same lighting as an incandescent light bulb (source: enhso.com)
A Carnot engine working between two heat baths of temperatures 264 oC and 0 oC completes each cycle in 6 s. In each cycle, the engine absorbs 12.3 kJ of heat. Find the power of the engine in W
Answers
The power of the Carnot engine is 1.025 W.
Temperature of the hot reservoir, T₁ = 264°C = 537 K
Temperature of the cold reservoir, T₀ = 0°C = 273 K
Heat absorbed by the Carnot engine, Q₁ = 12.3 kJ
Efficiency of the Carnot engine,
η = 1 - (T₀/T₁)
η = 1 - 273/537
η = 0.5
We know that efficiency of Carnot engine,
η = 1 - Q₀/Q₁
Therefore, exhausted heat,
Q₀ = Q₁(1 - η)
Q₀ = 12.3(1 - 0.5)
Q₀ = 6.16 kJ
So, work done by the engine,
W = Q₁ - Q₀ = 12.3 - 6.15
W = 6.15 kJ
Therefore, power of the engine,
P = W/t = 6.15/6
P = 1.025 W
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What is the net force net
on an airplane window of area 1800 cm2
if the pressure inside the cabin is 0.95 atm
and the pressure outside is 0.76 atm
?
Answers
The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .
Given:
Pressure inside the cabin: 0.95 atm
Pressure outside the cabin: 0.76 atm
Area of the airplane window: 1800 cm²
Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.
Pressure Difference = Pressure inside - Pressure outside
Pressure Difference = 0.95 atm - 0.76 atm
Pressure Difference = 0.19 atm
The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:
Area in m² = (Area in cm²) / 10,000
Area in m² = 1800 cm² / 10,000
Area in m² = 0.18 m²
As we know,
Net Force = Pressure Difference * Area
Net Force = 0.19 atm * 0.18 m²
Net Force = 0.0342 atm·m²
To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get
Net Force = 3469.47 Pa·m²
Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).
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A student has tested several types of wood for density. The best way of presenting this information graphically would be to use which item?
Scatterplot
Pie Chart
Line Graph
Bar Graph
Previous
Search
Answers
The best way of presenting the information on density graphically would be to use a D, bar graph.
What is a bar graph?A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.
A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.
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The straightest road in the USA is the Simi Highway, Route 28, in Michigan. A driver, seated in a car, is viewing a deer crossing the road. The eyes of the driver are about 3 ft above the ground, and the deer is about 3 ft in height. If the radius of the Earth is 6400 km.
Required:
a. How far away can the driver see the very top of the deer as it emerges from below the horizon?
b. If the deer is 5 feet long, what angle does the deer subtend from the driver (i.e. what is the angular size of the 5’ long deer at this distance)?
Answers
Answer:
a) d = 3.6 km
b) 0.024°
Explanation:
To see the top of a 1 m tall deer over the surface of a 6400 km radius perfect sphere, the angle subtended is
cosθ = 6 400 000 / (6 400 001)
θ = 0.0320293...°
d = Rtanθ = 6 400 000tan0.0320293
d = 3,577.708... m
5 ft = 1.524 m
tanθ = 1.524 / 3577.7
θ = 0.0244063...°
What is the formula for Angular velocity?
Answers
Answer:
The formulas are down below
Explanation:
\(w = \frac{o}{t} \)
From V=rw
\(w = \frac{v}{r} \)
A(n)_____ planet is composed of rocky material, has no rings, and is closer to the sun.
Answers
Answer:
A terrestrial planet.
Explanation:
Terrestrial planets (Inner planets) are closer to the sun then outer planets. No inner planet has rings and they are all composed of rocky material.
A terrestrial planet planet is composed of rocky material, has no rings, and is closer to the sun.
What is terrestrial planet?Terrestrial planets are Earth-like planets having a hard surface consisting of rocks or metals. A molten heavy-metal core, few moons, and topographical features like valleys, volcanoes, and craters are also characteristics of terrestrial planets.
Mercury, Venus, Earth, and Mars are the four terrestrial planets in our solar system, and they also happen to be the four nearest to the sun.
There may have been more terrestrial planetoids during the solar system's formation, but they either combined or were obliterated.
The planets are not entirely terrestrial. Gas giants, also referred to as Jovian planets, include Jupiter, Saturn, Uranus, and Neptune in our solar system.
Hence, a terrestrial planet planet is composed of rocky material, has no rings, and is closer to the sun.
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Which substance shown has the greatest kinetic energy at room temperature (~25°C)?
A.methane
B.helium
C.mercury
D.silicon
Answers
helium will have the greatest kinetic energy at room temperature.
According to Kinetic theory of gases, an increase in temperature of the gases will increase the average kinetic energy of the gas molecules, while a decrease in the temperature of the gases will cause a decrease in the average kinetic energy of the gases.
The average kinetic energy of the gas molecules increases with increase in temperature. Temperature is simply the measure of average kinetic energy of gas molecules.
At room temperature gases have the highest kinetic energy, followed by liquid, and the least is solid.
A among the gases, methane is more dense than helium and consequently it will have low kinetic energy.
Thus, helium will have the greatest kinetic energy at room temperature.
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A man yells across a canyon to his friend who hears the yell 3.25 seconds later. How far away is the man's friend? (speed of sound in air = 343 m/s)
Answers
The man's friend is at a distance 552.5 m away.
Speed of sound in air, v = 340 m/s
Time after which the echo is heard, t = 3.25 s
The expression for the total distance covered by the sound in the given time,
d = v x t
d = 340 x 3.25
d = 1105 m
Therefore, the distance where the friend is staying would be half of the total distance covered by the sound during the given time.
So, the distance of the friend from the man,
d' = d/2
d' = 1105/2
d' = 552.5 m
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What is the cost per month to operate an A.C. 10hours per day whose power is 3kW and 1KWH cost 79francs
Answers
The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.
What is Power?Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.
Cost of operation for 10 hours a day;
Daily consumption = 3kW x 10 hours
Daily Consumption = 30kW
Since 1kWH = 79 francs;
Daily consumption amount = 30 x 79 francs
Daily consumption amount = 2,370 francs
Therefore, the monthly consumption (using 30days) will be;
2,370 francs x 30 = 71,100 francs
In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.
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Select the correct answer
A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?
A
velocity and wavelength
B
velocity and frequency
C
frequency and wavelength
D.
Frequency and Phase
E.
Wavelength and phase
Answers
Answer:
velocity and wavelength
Explanation:
When a ray of light moves from one medium to another, the ray of light changes the direction when it enters the second medium, refraction of light occurs.
When it changes the direction, the frequency will remain the same because it depends only on the source not on the medium.
As the refractive index of two medium is not same, it means the wavelength will change.
Also, speed = frequency × wavelength
So, wavelength and velocity changes. Hence, the correct option is (a).
Answer:
velocity and wavelength
Explanation:
On a hot summer day, the temperature of air in Arizona reaches 108°F. What is the speed of sound in air at this temperature? (The speed of sound at 0°C is 331 m/s. Use the conversion 0°C = 273 K as necessary.)
______m/s
Answers
355.7 meter/ sec is the speed of sound in air at 108°F temperature because with the increase in temperature the speed of sound increases.
What is the relationship between speed of sound and temperature?The speed of sound is directly proportional to the temperature. We know that directly proportional means when the temperature increases, the speed of sound also increases while on the other hand, when the temperature decreases, the speed of sound also decreases which shows direct relationship. That's why the speed of sound is 355.7 meter/ sec in air at 108°F temperature.
So we can conclude that 355.7 meter/ sec is the speed of sound in air at 108°F temperature because with the increase in temperature the speed of sound increase.
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Can someone please check my review answers before I take my exam (sorry I’m advance for poor quality)
Answers
Answer:
Explanation: #1 is A #2 is C #3 is correct #4 is correct #5 is correct
An electron in a hydrogen atom is in a p state. Which of the following statements is true?
a.
The electron’s wavefunction has at least one node (i.e., at least one place in space where it goes to zero).
b.
The electron has an energy of -13.6 eV.
c.
The electron has a total angular momentum of ħ.
d.
The electron has a z-component of angular momentum equal to sqrt(2)* ħ.
Answers
Answer:
The electron’s wavefunction has at least one node (i.e., at least one place in space where it goes to zero).
Explanation:
We know that the p-orbitals have nodes. A node is a region where the probability of finding an electron goes down to zero.
P orbitals are oriented along the x,y,z Cartesian axes and are known to have angular nodes along the axes.
Hence, if an electron in a hydrogen atom is in a p state, the electron’s wavefunction has at least one node
An object accelerates from rest. After accelerating for 12 s, it has traveled 240 m. What is its velocity at that time?
Answers
The velocity of the object that accelerates from rest in 12 seconds and traveled 240m is 20m/s.
How to calculate velocity?The velocity of a body is a vector quantity that denotes the rate of change of position with respect to time i.e. combining speed with a directional component.
Displacement is a vector quantity which denotes distance with a directional component.
The velocity of a body can be calculated by dividing the displacement by the time taken as follows:
∆v = ∆x ÷ ∆t
Where;
∆V = change in velocity (m/s)∆x = displacement (m)∆t = time (s)∆V = 240m ÷ 12s
∆v = 20m/s
Therefore, the velocity of the object that accelerates from rest in 12 seconds and traveled 240m is 20m/s.
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An apple with mass M is hanging at rest from the lower end of a light vertical rope. A dart of mass M/4 is shot vertically upward, strikes the bottom of the apple, and remains embedded in it.
Answers
The apple moves a height of h = \(\frac{v^{2} }{50 g}\) because of its collision with the dart.
How do we calculate height?we can calculate the height of an object using the distance and angle.
In order to calculate the height of an apple with mass M is hanging at rest from the lower end of a light vertical rope. A dart of mass M/4 is shot vertically upward, strikes the bottom of the apple, and remains embedded in it.
We first calculate the velocity that the final mass gets once the collision takes place, in order to do this, we use momentum conservation.
pi = Pf = (5/4)Mv
We get the value for the velocity of the final mass, v , once the collision has been produced.
Once we have pi, with this final velocity, we can calculate the final height that the mass will get, to do this we use energy conservation.
An instant after the collision, the mass has kinetic energy, and we say that that is our altitude zero, but when the mass gets to its higher altitude, the kinetic energy is zero and the potential energy is different than zero, and we will write as follows:
Ei = Ef = (1/2) (5/4 M (V/5)² =(5/4 M)g*h
Equating and solving for height, we will get as the apple moves a height of h = \(\frac{v^{2} }{50 g}\) because of its collision with the dart.
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The parallel plates in a capacitor, with a plate area of 9.30 cm2 and an air-filled separation of 4.50 mm, are charged by a 7.80 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 9.60 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
Answers
Answer:
a) ΔV ’= 1.66 10¹ V= 16.6 V, b) U = 55.64 10⁻¹² J, c) U_f = 1.18 10⁻¹⁰ J
d) W = 6.236 10⁻¹¹ J
Explanation:
Capacitance can be found for a parallel plate capacitor
C = ε₀ \(\frac{A}{d}\)
Let's reduce the magnitudes to the SI system
A = 9.30 cm² (1 m / 10² cm) 2 = 9.30 10⁻⁴ m²
c = 4.50 mm (1 m / 1000 mm) = 4.50 10⁻³ m
Co = 8.85 10⁻¹² 9.30 10⁻⁴ /4.50 10⁻³
Co = 1.829 10⁻¹² F
when the plates separate at d = 9.60 10⁻³ m, the capcitance changes to
C = ε₀ \frac{A}{d_1}
C = 8.85 10⁻¹² 9.30 10⁻⁴/9.60 10⁻³
C = 8.57 10⁻¹³ F
a) the potential difference
C =
since the capacitor is not discharged, let's look for the initial charge
Co = \frac{Q}{ \Delta V}
Q = C₀ ΔV
Q = 1.829 10⁻¹² 7.80
Q = 14.2662 10⁻¹² C
when the condensate plates are separated
C = \frac{Q}{ \Delta V' }
ΔV ’= Q / C
ΔV ’= 14.266 10⁻¹² / 8.57 10⁻¹³
ΔV ’= 1.66 10¹ V= 16.6 V
b) the stored energy is
U = ½ C ΔV²
for initial separation
U = ½ C₀ ΔV²
U = ½ 1.829 10⁻¹² 7.80²
U = 55.64 10⁻¹² J
c) The energy for end separation;
U_f = ½ C DV’2
U_f = ½ 8.57 10⁻¹³ 16,6²2
U_f = 1.18 10⁻¹⁰ J
d) The work
as there are no losses, the work is equal to the variation of the energy
W = ΔU = U_f -U₀
W = 1.18 10⁻¹⁰ - 55.64 10-12
W = 6.236 10⁻¹¹ J
A body of mass 1.0 kg initially at rest slides down an incline plane that is 1.0 m high and 10.0 m long. If the body experiences a constant resistive force of 0.5 N over the slope, what is the KE of the body at the base of the plane?
Answers
Answer:
answer is
Explanation:
because
A ball of mass m is dropped. What is the formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time τ later? Ignore air resistance.
Answers
The formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.
Impulse exerted on the ballThe impulse exerted on the ball at any given instant is calculated as follows;
J = ΔP
J = Pf - Pi
where;
J is impulse exerted on the ballpf is final momentumpi is the initial momentumThus, the formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.
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A 2,766 kHz AM radio station broadcasts with a power of 35 kW. How many photons does the transmitting antenna emit each second?
Answers
Given:
The frequency of the wave is f = 2766 kHz
The power is P = 35 kW
Required: Number of photons emit each second by the transmitting antenna.
Explanation:
Power and energy are related as
\(P=\frac{E}{t}\)For each second the time will be t = 1 s
Also, the energy can be calculated by the formula
\(E=nhf\)Here, Planck's constant is
\(h\text{ = 6.6}\times10^{-34}\text{ J s}\)On substituting the values, the number of photons each second will be
\(\begin{gathered} P=\text{ nhf} \\ n=\frac{P}{hf} \\ =\frac{35\times10^3W}{6.6\times10^{-34}\text{ J.s }\times2766\times10^3\text{ Hz}} \\ =1.92\times10^{31}\text{ photons each second} \end{gathered}\)Final Answer: There are 1.92 x 10^(31) photons each second.
The position-time equation for a certain train is
2.9m + (8.8m/s)t + (2.4m/s2)+2
What is it’s acceleration?
Answers
Answer:
\(a=4.8m/s^2\)
Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:
\(a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)\)
The purpose here is derive x(t) twice as follows:
\(a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2\)
Thus, the acceleration turns out 4.8 meters per squared seconds.
Best regards.