Which of the following has the strongest gravitational field?
A. the sun
B. the earth
C. a football player
D. a tree

Answer:

See explanation

Explanation:

Total number of moles of gases in the mixture; 0.70 + 0.25 + 0.05 = 1 mole

Partial pressure= mole fraction of gas × total pressure

Mole fraction of hydrogen = 0.7/1 × 2.6 = 1.82 atm

Mole fraction of CO2 = 0.25/1 × 2.6 = 0.65 atm

Mole fraction of CO= 0.05/1 × 2.6 = 0.13 atm

We would need to 1.39 L of the stock solution and then make up to the 2.54 L mark.

The dilution formula is used to calculate the new concentration of a solution after it has been diluted with a solvent. The formula is:

C1V1 = C2V2

where:

C1 = the initial concentration of the solution

V1 = the initial volume of the solution

C2 = the final concentration of the solution

V2 = the final volume of the solution

By the use of the formula;

C1V1 = C2V2

V1 = C2V2/C1

V1 = 2.54 * 6/11

V1 = 1.39 L

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Answer:

The limiting reactant is: H₂O

265.3 g of K₂Sn(OH)₆ are formed in the reaction.

Explanation:

The reaction is:

Sn(s) + 2KOH (aq) + 4H₂O(l)  → K₂Sn(OH)₆ (s) + 2H₂ (g)

The first step to solve is to determine the moles of each reactant:

We controlled that reaction is ballanced.

122 g . 1mol / 118.71g = 1.03 moles of Sn

134g . 1mol /56.1g = 2.39 moles of KOH

63.9 g .1mol /18g = 3.55 mol of water

Stoichiometry is 1:2:4.

Sn is the lowest reactant and water, the highest, but I can see, that water is the limiting.

1 mol of Sn needs 4 moles of H₂O to react

Then, 1.03 moles of Sn may react to (1.03 . 4)/1 = 4.12 moles.

We only have 3.55 moles. It's ok.

2 moles of KOH need 4 moles of H₂O to react

Then, 2.39 moles of KOH may react to (2.39 . 4) /2 = 4.78 moles.

We only have 3.55, there's no enough water.

So 4 moles of water can produce 1 mol of potassium hydroxystannate

Then, 3.55 moles of H₂O may produce (3.55 . 1)/4 = 0.8875 moles.

We convert moles to mass: 0.08875 mol . 298.91g /1mol =265.3g

The Safety Data Sheet (SDS) for regular bleach can be obtained from the manufacturer or supplier of the specific brand or product. It contains important information regarding the hazardous properties, handling, storage, and emergency procedures related to the bleach.

An SDS typically includes details such as the product's chemical composition, physical and chemical properties, potential hazards to health and the environment, precautionary measures for safe handling and storage, first-aid procedures, and information about proper disposal. It also provides guidance on personal protective equipment (PPE) to be used when handling the product and steps to take in case of accidental release or exposure.

The SDS serves as a crucial resource for understanding the potential risks associated with the use of regular bleach and helps ensure that appropriate safety measures are implemented. It is important to review and follow the information provided in the SDS to minimize the risk of accidents, injuries, or adverse health effects associated with the use of the product.

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A wave is a recurring, periodic disturbance that moves from one place to another via a medium (like water).

A wave is a disturbance that moves or propagates away from its source. Although waves can move energy between locations, they do not always move mass. Common examples of waves are light, sound, and ocean waves.

Mobile phones and radar systems are two noteworthy examples of wave applications. Even though radio waves are usually thought to be safe and contribute to background radiation, it is still advised to keep your distance from radio wave sources.

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complete question;

Using your outline and the materials you’ve gathered, write a 250- to 500-word paper using word processing software. Be sure to proofread and revise your writing to catch any errors in grammar, spelling, logic, or organization. Add a works cited page at the end to give credit to your sources. Submit your completed paper and this activity to your teacher for evaluation. This is for Unit Activity: Waves in edmentum

The  number of molecules in one mole or 294.3 g of aspartame contains 6.02 × 10²³ molecules. Hence, 5 mg contains 1.022 × 10¹⁹ molecules of aspartame.

Any substance containing 6.02 × 10²³ molecules is called one mole of that substance. This number is called Avogadro number. Thus one mole of every compound contains Avogadro number of molecules.

The mass containing Avogadro number of molecules is called the molar mass of the compound.

molar mass of aspartame = 294.30 g

5 mg = 0.005 g

then , number of moles = 0.005 / 294.3  = 1.69 × 10⁻⁵

Then, number of molecules = 1.69 × 10⁻⁵  × 6.02 × 10²³ =  1.022 × 10¹⁹

Therefore, the number of molecules in 5 mg of aspartame is  1.022 × 10¹⁹

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Answer:

The correct Answer is Number 3 the 74 g per mole ...

The gram-formula mass of Ca(OH)₂ is 74 g/mol. Therefore, option D is correct.

The quantity of a compound that has the same mass in grammes as the formula mass in an atomic mass unit is said to have the compound's gramme formula mass.

Each atom of each element has a distinctive mass, and each molecule of a compound has a distinctive mass determined by the complex's formula.

The mass of the solute divided by the solute's formula mass is known as the gramme formula mass. The atomic weights of all the atoms in the empirical formula are added to determine formula mass.

The gram formula mass of Ca(OH)₂ is 74.093 grams. This is the composed molar mass if each of the atoms in the molecule are one calcium atom, two oxygen atoms, and two hydrogen atoms.

Thus, option D is correct.

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Answer:

Earthquakes and Volcanos?

Explanation:

I'm a little unsure about my answer, however, I do have some insight backing my answer. Earthquakes happen when the plate tectonics shift into each other, causing them to collide. Then for volcanos, the plate tectonics shift from convection current and molten rock from the mantle come to the surface.

Answer:

Constant temperature variations

Explanation:

With temperature constantly heating many molecules within many forms of matter tend to move around. Take air for instance and density. When air is hot the molecules are moving very quickly because they are being what is known as energized (I don't know the scientific word I apologize.) However, when air is cold it tends to get harder to breath and that is because the air is more dense, since the molecules are atoms are much more compacted.

To further detail the process of cooling and heating up matter, water when it is cooled it tends to become ice; a solid based structure. Therefore, making it more dense or more compacted together. However, once heated the molecules begin to spread apart, in which the density lessens and the molecules become a liquid state or a gas state (depending on the amount of heat applied in terms of kelvin.)

Answer:

:)

Explanation:

The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction.

The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

1. acid produced by plants growing on rocks

plz give me BRAINLIEST answer

We are going to start with an example:

A reactant; B Product

If we consider just: A ==> B, we have a direct rate. This tells us that A is consumed in the reaction and B is formed as a product.

As we have a reversible reaction, we can have another situation: B ==> A, then we have an indirect rate.

At a certain time and we can say infinite time, there will be no change in the amount of products and reactants. The rates of reaction for the forward (direct) and backward (indirect) reactions are the same which means that the reaction has reached an equilibrium.

----------------------------------------------------

Always remember this: in equilibrium, the amounts of reactants or products no longer change and chemical equilibrium is a dynamic process.

From a single location on the circular chromosome, DNA is copied in both directions.

The correct option is E.

Binary fission is the process of asexual reproduction in which one organism is divided into two separate ones. An organism's genetic material, or deoxyribonucleic acid (DNA), doubles when it splits into two halves (cytokinesis) through binary fission, with each new species inheriting one copy of the latter.

Bacterial binary fission is the method by which bacteria split their cells. Find out how binary fission functions, including how to make a new cell wall and a copy of a bacterial chromosome. Mitosis and binary fission, two types of asexual reproduction, both entail the division of a parent cell into two identical daughter cells.

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Answer: D.

Explanation:

Asexual reproduction requires only one parent, making it more efficient and take a shorter amount of time than sexual reproduction.

Answer:

a. -5218.7 kJ/mol

Explanation:

Hello,

In this case, the combustion of liquid n-octane is represented by:

\(C_8H_{18}(l)+\frac{25}{2} O_2(g)\rightarrow 8CO_2(g)+9H_2O(g)\)

Thus, the molar free energy of combustion (reaction) is:

\(\Delta _CH=8*\Delta _fH_{CO_2}+9*\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{18}}\)

Hence, with the given data we obtain:

\(\Delta _CH=8*(-394.4kJ/mol)+9*\Delta _fH_{-228.57kJ/mol}-6.4kJ/mol\\\\\Delta _CH=-5218.73kJ/mol\)

Therefore, answer is a. -52 kJ/mol18.7.

Regards.

The heat of combustion is  -5218.7 kJ/mol.

The molar free energy of the reaction can be obtained as the sum of the free energy of the products minus the sum of the free energy of the reactants.

Now the reaction is;

C8H18(g) + 25/2O2(g) ----> 8CO2(g) + 9H2O(l)

Hence;

ΔGreaction = [8( -394.4) + 9(-228.57)] - [ 6.4  + 0]

=[(-3155.2) + (-2057.13)] - 6.4

=  -5218.7 kJ/mol

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Answer:

name four agricultural inputs are subsidized by the government

0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Given,

mass = 10g

c = 0.901J/g⁰C

Initial temperature (T₁) = 22⁰C

Final Temperature (T₂) = 55⁰C

Q = mcΔT

= 10 × 0.901 × (55 -22)

= 297.33 J = 0.297 kJ

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Answer:

\(\%_{Rb-85}=33.9\%\)

\(\%_{Rb-87}=66.1\%\)

Explanation:

Hello,

In this case, for the natural occurring isotopes we equal the average atomic mass via:

\(86.231=84.911*\%_{Rb-85}+86.909*\%_{Rb-87}\)

Thus, since both percentages of abundance must turn out 100%, we can write:

\(\%_{Rb-85}+\%_{Rb-87}=100\%\\\\\%_{Rb-85}=100\%-\%_{Rb-87}\)

So we can write:

\(86.231=84.911*(100\%-\%_{Rb-87})+86.909*\%_{Rb-87}\)

Solving for the percentage of abundance of Rb-87:

\(86.231=84911.00\%-84.911\%_{Rb-87}+86.909*\%_{Rb-87}\\\\\%_{Rb-87}=\frac{86.231-84.911}{-84.911+86.909}\\ \\\%_{Rb-87}=66.1\%\)

Therefore, the percentage of abundance of Rb-85 turns out:

\(\%_{Rb-85}=100\%-66.1\%\\\\\%_{Rb-85}=33.9\%\)

Best regards.

Considering the definition of atomic mass, isotopes and atomic mass of an element, the percentages of the isotopes in this sample are:

First of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.

On the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

In this case, a certain sample of rubidium has just two isotopes, 85Rb (mass = 84.911amu) and 87Rb (mass = 86.909amu).  Then, the average mass of lithium can be calculated as:

84.911× percent of Rb-85 + 86.909× percent of Rb-87= 86.231

Since both abundance percentages must be 100%, you can write:

percent of Rb-85 + percent of Rb-87= 100

Then:

percent of Rb-85 = 100% - percent of Rb-87

So, replacing this expression in the first equation:

84.911× (100% - percent of Rb-87) + 86.909× percent of Rb-87= 86.231

Solving:

84.911×100% - 84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231

8491.1% -84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231

-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 8491.1%

-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 84.911

1.998× percent of Rb-87= 86.231 - 84.911

1.998× percent of Rb-87= 1.32

percent of Rb-87= 1.32÷ 1.998

percent of Rb-87= 0.6607

percent of Rb-87= 66.07%

Therefore, the percentage of abundance of Rb-85 is:

percent of Rb-85 = 100% - percent of Rb-87

percent of Rb-85 = 100% - 66.07%

percent of Rb-85 = 33.93%

Finally, the percentages of the isotopes in this sample are:

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Answer:

Discoloration of leaves.

Food Digestion.

Common salt.

Icefloating on water.

Tears while chopping onions.

Sunscreen.

Medicines.

Hygiene.

i gave you 8 answers. :)

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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we can do soo by noticing any colour change, or by the formation of an insoluble precipitate or by the evolution of a gas.

The volume of carbon dioxide produced is approximately (d) 11.9 liters.

To determine the amount of carbon dioxide (C\(O_2\)) produced when 37.8 grams of carbon disulfide (C\(S_2\)) reacts with excess oxygen gas (\(O_2\)), we need to use stoichiometry and the given balanced chemical equation:

C\(S_2\)(l) + 3\(O_2\)(g) → C\(O_2\)(g) + 2S\(O_2\)(g)

First, we calculate the number of moles of C\(S_2\) using its molar mass:

Molar mass of (C\(S_2\)) = 12.01 g/mol (C) + 32.07 g/mol (S) × 2 = 76.14 g/mol

Number of moles of (C\(S_2\)) = mass / molar mass = 37.8 g / 76.14 g/mol ≈ 0.496 mol

From the balanced equation, we can see that the stoichiometric ratio between (C\(S_2\)) and C\(O_2\) is 1:1. Therefore, the number of moles of C\(O_2\) produced will also be 0.496 mol.

Now we can use the ideal gas law to calculate the volume of C\(O_2\) at the given temperature and pressure. The ideal gas law equation is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

Converting the temperature from Celsius to Kelvin:

T(K) = 28.85°C + 273.15 = 302 K

Using the ideal gas law:

V = nRT / P = (0.496 mol) × (0.0821 L·atm/mol·K) × (302 K) / (1.02 atm) ≈ 11.9 L

The correct answer is 11.9 liters.

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Answer:

The answer is "how closely the model's behavior matches the real world "

Explanation:

Your options were glitched out, so it only showed A and C, and B and D were blank so lol

The total mass of the balloon and its content is 1521.17 g, the number of moles of CO₂ in the balloon is 34.15 mol, and the number of CO₂ molecules in the balloon is 2.06 x 10²⁵ molecules.

a) The molar mass of CO₂ is 44.01 g/mol. To find the total mass of the balloon and its content, we need to add the mass of the balloon (20g) to the mass of the CO₂ inside the balloon.

Mass of CO₂ = number of moles of CO₂ x molar mass of CO₂

Since the balloon is at STP (standard temperature and pressure), we can use the molar volume of a gas at STP (22.4 L/mol) to find the number of moles of CO₂ in the balloon:

Volume of CO₂ = Volume of balloon = 765 L (at STP)

Number of moles of CO₂ = volume of CO₂ / molar volume of a gas at STP

                                          = 765 L / 22.4 L/mol

                                          = 34.15 mol

Mass of CO₂ = 34.15 mol x 44.01 g/mol

                       = 1501.17 g

Total mass of balloon and its content = 20 g + 1501.17 g

                                                               = 1521.17 g

b) Number of moles of CO₂ in the balloon is 34.15 mol

c) To find the number of CO₂ molecules in the balloon, we need to use Avogadro's number (6.02 x 10²³ molecules/mol).

Number of CO₂ molecules = number of moles of CO₂ x Avogadro's number

                                           = 34.15 mol x 6.02 x 10²³ molecules/mol

                                           = 2.06 x 10²⁵ molecules

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Light energy travels in the form of waves.

To find out if the diet lemonade contains any sugar, Liam should follow these steps (using Benedict's solution):

1. Take a sample of the diet lemonade and pour it into a test tube.

2. Add a few drops of Benedict's solution to the test tube with the diet lemonade sample.

3. Mix it to make it homogeneous.

4. Take the test tube to a water bath.

5. Heat the test tube in the water bath.

6. If the solution (sample of diet lemonade + drops of Benedict's solution) turns orange-red, the diet lemonade contains sugar.

a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. The volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. According to the balanced chemical equation, for every 2 moles of water (H2O) electrolyzed, 1 mole of oxygen gas (O2) is obtained. Since 1 mole of any gas occupies 22.4 L at standard temperature and pressure (STP), we can use the stoichiometry of the reaction to determine the volume of oxygen gas produced.

Given that 50 cm³ of gas is obtained at the anode, we need to convert this volume to liters:

50 cm³ = 50/1000 L = 0.05 L

Using the stoichiometric ratio of the balanced equation, we find that 2 moles of water produce 1 mole of oxygen gas. Therefore, 0.05 L of oxygen gas is equivalent to:

0.05 L × (1 mole/22.4 L) = 0.002232 moles

Thus, the volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

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The number of moles for the quanity 8.06 x\(10_{21\) atoms of Pt​ is approximately 2.61 grams.

To calculate the number of moles for a given quantity of atoms, we can use Avogadro's number and the molar mass of the element. Avogadro's number is 6.022 x 10²³ atoms/mol.

In this case, you have 8.06 x 10²¹ atoms of Pt. To find the number of moles, divide this quantity by Avogadro's number:

8.06 x 10²¹  atoms Pt / 6.022 x 10²³  atoms/mol = 0.0134 mol Pt

So, there are approximately 0.0134 moles of Pt in 8.06 x 10²¹  atoms of Pt.

The molar mass of Pt (platinum) is 195.08 g/mol. To convert the number of moles to grams, multiply the number of moles by the molar mass:

0.0134 mol Pt x 195.08 g/mol = 2.61 g Pt

Therefore, there are approximately 2.61 grams of Pt in 8.06 x10²¹  atoms of Pt.

In summary, the number of moles for the quantity 8.06 x 10²¹ atoms of Pt is approximately 0.0134 moles. This is equivalent to approximately 2.61 grams of Pt. Remember to use Avogadro's number and the molar mass to perform these calculations accurately.

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8.986 g and 85%

Explanation:

Theoretical Yield:

\(6.00 \: g \: Ca(OH₂) \times \frac{1 \: mol \: Ca(OH₂)}{74.10g \: Ca(OH₂)} \times \frac{1 \: mol \: CaCl₂}{1 \: mol \: Ca(OH₂)} \times \frac{111.0 \: g \: CaCl₂}{1 \: mol \:CaCl₂ } = 8.986 \: g \: CaCl₂\)

Percent Yield:

\( \frac{7.64 \: g}{8.986 \: g} \times 100 = 85.0\%\)

J.J. Thomson discovered electrons and their negative charge through the cathode ray experiment, leading to the development of the plum pudding model of the atom.

J.J. Thomson, a British physicist, was the first to discover electrons in 1897.

He conducted the cathode ray experiment to identify the negatively charged particles.

The cathode ray tube is a vacuum-sealed glass tube with two electrodes at each end: a cathode and an anode.

When a high voltage electrical current is applied to the electrodes, the tube glows, indicating that the cathode rays are being emitted from the cathode and traveling through the tube towards the anode.

The cathode rays were found to have a negative charge, according to Thomson.

These rays were identified as particles by the presence of a magnet, which caused the particles to bend in the direction opposite to the magnet's polarity.

This discovery indicated that the particles had a charge on them because they were deflected by the magnetic field, which is only possible if the particles have an electric charge.

Thomson further concluded that these particles were about 1,000 times smaller than hydrogen atoms because of the degree of deflection they experienced in the magnetic field.

Furthermore, Thomson created the plum pudding model of an atom, in which electrons are dispersed throughout a positively charged matrix, based on his findings.

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