You add 168.90 grams of NaCl to a container and then you add 616.00 grams of water to that same container What is the weight percent of NaCl in the containerI
Answer:
The weight percent of NaCl in the container is 21.5%
Explanation:
Given that,
Mass of NaCl = 168.90 gram
Mass of water = 616.00 grams
We need to calculate the weight percent of NaCl in the container
Using formula of percentage of weight
\(weight\ \%\ of\ component\ of\ the\ solution =\dfrac{weight\ of\ the\ component\ in\ the\ solution}{total\ weight\ of\ the\ solution}\times100\)
Put the value into the formula
\(weight\ \%\ of\ component\ of\ the\ solution =\dfrac{168.90}{168.90+616.00}\times100\)
\(weight\ \%\ of\ component\ of\ the\ solution=21.5\%\)
Hence, The weight percent of NaCl in the container is 21.5%
2NO(g) + O₂(g) = 2NO₂(g)
AH = -112 kJ K = 0.50
The equilibrium concentrations are
[NO] = 0.31 M, [02] = 1.10 M, and
[NO2] = [?]
What is the equilibrium concentration of
NO2 at this temperature?
The equilibrium concentration of NO₂ at this temperature is approximately 0.219 M.
To determine the equilibrium concentration of NO₂, we can use the equilibrium constant expression (Kc) and the given equilibrium concentrations of NO and O₂. The equilibrium constant expression for the given reaction is:
Kc = ([NO₂]²) / ([NO]²[O₂])
We are given the equilibrium concentrations of NO and O₂ as [NO] = 0.31 M and [O₂] = 1.10 M, respectively. We need to find the equilibrium concentration of NO₂, denoted as [NO₂].
Using the given equilibrium concentrations and the equilibrium constant expression, we can rearrange the equation and solve for [NO₂]:
Kc = ([NO₂]²) / ([NO]²[O₂])
0.50 = ([NO₂]²) / ((0.31 M)²(1.10 M))
0.50 = ([NO₂]²) / (0.0961 M³)
Multiplying both sides by 0.0961 M³, we have:
0.04805 M³ = [NO₂]²
Taking the square root of both sides, we find:
[NO₂] = √(0.04805 M³)
[NO₂] ≈ 0.219 M
Therefore, the equilibrium concentration of NO₂ at this temperature is approximately 0.219 M.
It's important to note that the units of concentration (M) were used throughout the calculations, and the answer is rounded to three significant figures based on the given data.
Additionally, the negative sign of the enthalpy change (AH) indicates an exothermic reaction, and the equilibrium constant (K) of 0.50 suggests that the reaction favors the products, as the concentration of NO₂ is greater at equilibrium.
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An expression for handerson Hestra of acid and base
An expression for Henderson's pH of acids and bases are given below-
pH = pKa + log\(\frac{conjugate base}{acid}\)
pOH = pKb + log\(\frac{conjugate acid}{base}\)
The Henderson-Hasselbalch equation provides a relationship between the pH of acids (in aqueous solutions) and their pKa (acid dissociation constant). The pH of a buffer solution can be estimated with the help of this equation when the concentration of the acid and its conjugate base, or the base and the corresponding conjugate acid, are known.
The Henderson-Hasselbalch equation fails to predict accurate values for the strong acids and strong bases because it assumes that the concentration of the acid and its conjugate base at chemical equilibrium will remain the same as the formal concentration (the binding of protons to the base is neglected).
Since the Henderson-Hasselbalch equation does not consider the self-dissociation undergone by water, it fails to offer accurate pH values for extremely dilute buffer solutions.
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What is the boiling point of a solution that contains 50.0 g of FeBr3 in 200.0 g of water?
12. In the modern periodic table, which of the following describes the elements with similar
properties?
A. They have similar atomic masses.
B. They are located in the same group.
C. They are located in the same period.
D. They have the same number of protons.
1. Explain how you would determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following information. You do not need to calculate an answer. Respond to the prompt with a minimum response length of 50 words.
we can determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following steps:
write the balanced chemical equation for the reactionwe obtain the standard enthalpies of formation for each compoundwe apply Hess's law calculate the enthalpy of reactionwe then add up the changes to get the total enthalpy change for the reaction State Hess law?Hess's Law of Constant Heat Summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.
The law is Hess's Law of Constant Heat Summation is described as a manifestation that enthalpy is a state function.
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explain the early theories of the atomic structure
Hi
i hope this helps
Answer:
The Greek atom theory
Explanation:
The concept of the Greek atomos theory is an indivisible particle of matter, goes back to ancient Greece and a man named Democritus held that all matter could be subdivided only until some finite particle was reached.
Hi, can someone please help me out with finding the answers.
write the IUPAC name and the Molecular formula
The IUPAC name and molecular formula for the following are,
a) prop-1-yne, C3H4
b) non-4-yne, C9H16
c) hex-3-yne, C6H10
What is IUPAC name?
International Unit for Pure and Applied Chemistry (IUPAC) is the method of naming the organic compounds in chemistry. It creates a standardized naming for the chemical compounds. There are prefixes, suffixes and parent chain considered while naming a compound.
The IUPAC name can be written by counting the parent chain carbons and considering the functional group present which is a triple bond in the given compounds. The molecular formula can be written by counting the number of different atoms present in the compound.
Therefore, the IUPAC name and molecular formula of the given compounds can be written as,
a) prop-1-yne, C3H4
b) non-4-yne, C9H16
c) hex-3-yne, C6H10
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What is matter? a. A change of state b. Anything that has mass and takes up space c. Both a and b d. None of the above
Answer: B
Explanation: Anything that has mass and takes up space
Net ionic equation for potassium sulfide and magnesium iodide
The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.
To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.
Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):
K2S -> 2K+ + S2-
Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):
MgI2 -> Mg2+ + 2I-
Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):
K+ + I- -> KI
Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):
Mg2+ + S2- -> MgS
Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:
2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS
To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).
Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:
S2- + Mg2+ -> MgS
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2.50 g of As2O3 are titrated with 38.5 mL of KMnO4 to reach the end point.
5As2O3(s)+4MnO−4(aq)+9H2O(l)+12H+(aq)⟶10H3AsO4(aq)+4Mn2+(aq)
Calculate the concentration of the KMnO4 solution.
50 g of As\(_2\)O\(_3\) are titrated with 38.5 mL of KMnO\(_4\) to reach the end point. 0.26M is the concentration of the KMnO\(_4\) solution.
Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass in unit volume is typically used.
The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.
5As\(_2\)O\(_3\)(s)+4MnO\(_4\)⁻(aq)+9H\(_2\)O(l)+12H⁺(aq)⟶10H\(_3\)AsO\(_4\)(aq)+4Mn\(_2\)⁺(aq)
the stoichiometry ratio between As\(_2\)O\(_3\) and MnO\(_4\)⁻ is 5:4
0.0126 moles of As\(_2\)O\(_3\) will react with 4/5×0.0126 moles = 0.01008moles
0.01008moles of MnO\(_4\)⁻ is present in 38mL
concentration of KMnO\(_4\)= moles×volume
= 0.010/38×1000
=0.26M
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calculate the number of moles for the quanity 8.06 x 1021 atoms of Pt
The number of moles for the quanity 8.06 x\(10_{21\) atoms of Pt is approximately 2.61 grams.
To calculate the number of moles for a given quantity of atoms, we can use Avogadro's number and the molar mass of the element. Avogadro's number is 6.022 x 10²³ atoms/mol.
In this case, you have 8.06 x 10²¹ atoms of Pt. To find the number of moles, divide this quantity by Avogadro's number:
8.06 x 10²¹ atoms Pt / 6.022 x 10²³ atoms/mol = 0.0134 mol Pt
So, there are approximately 0.0134 moles of Pt in 8.06 x 10²¹ atoms of Pt.
The molar mass of Pt (platinum) is 195.08 g/mol. To convert the number of moles to grams, multiply the number of moles by the molar mass:
0.0134 mol Pt x 195.08 g/mol = 2.61 g Pt
Therefore, there are approximately 2.61 grams of Pt in 8.06 x10²¹ atoms of Pt.
In summary, the number of moles for the quantity 8.06 x 10²¹ atoms of Pt is approximately 0.0134 moles. This is equivalent to approximately 2.61 grams of Pt. Remember to use Avogadro's number and the molar mass to perform these calculations accurately.
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Which factor would slow down a chemical reaction? (Choose all that apply)
A)Adding an inhibitor
B)Decreasing temperature
C)Decreasing particle size
D)Increasing particle size
Answer:
(decreasing particle size) C
Explanation: That is one of the answers, if there are more I am sorry.
What is the zonecreated if force of separation occurs?
Calculate the mass (in grams) of chlorine (Cl2) gas sample which occupies a 2.50 L container at a pressure of 1.22 atm and temperature of 27.8°C?
Answer:Nothing
Explanation:
The answer is nothing the tempatature isnt matched with the degrees this is false
I need help I don’t understand this is hitting
Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.
Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.
In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.
In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.
Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.
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a sample of oxygen has its absolute temperature halved while the pressure of the has remained constant. if the initial volume is 400ml, what is the final volume?
Answer: 200mL
Explanation:
Calculate the pH of the following aqueous solution:
0.35 M NaF (pKa for HF = 3.14)
I'm pretty sure I know how to calculate the pH by itself, but I am confused on how to get the equation. I'm not sure what HF has to do with this, other than it's an acid. I'm probably overthinking it because it's worded differently. Thanks in advance!
The pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
How to calculate pH?The pH of a solution refers to the degree of acidity or alkalinity of the solution. It can be calculated using the Henderson-Hasselbalch Equation as follows:
pH = pka + log ([A-]/[HA])
Where;
A- = conjugate baseHA = weak acidpH = pKa + log([F-]/[HF])
pH = 3.14 + log(1/0.35)
pH = 3.14 + 0.4559 = 3.595
Therefore, the pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
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What volume (in mL) of 0.2950 M HCI is required to neutralize 75.00
mL of 0.6000 M LIOH?
203 mL of 0.2950 M HCI is required to neutralize 75.00 mL of 0.6000 mL NaOH.
Hcl + NaOH \(\rightarrow\) Nacl + H2O
Form dilution formula:
M1V1=M2V2.
So M1=0.6000M, V1=0.075L, M2=0.2950M HCl, V2=?
V2 = M1V1/M2
= (0.8)(0.075)/0.2950
=0.2033L=203 mL.
Explain Dilution ?Dilution is the process of "lowering the concentration of a solute in a solution simply by adding more solvent, such as water, to the solution." Diluting a solution requires adding a solvent without adding a solute.
A popular way to make a solution of a given concentration is to take a higher concentration and add water until the required concentration is reached. Dilution is the term for this procedure. Dilution can also be done by mixing a higher concentration solution with a lower concentration. Since stock solutions are often obtained and stored in very concentrated concentrations, dilution of the solutions is a mandatory procedure in the laboratory.
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How many moles of water contain each of the following number of molecules?
4.38 × 10^21 molecules
Report your answer using appropriate number of significant figures.
In 4.38 × 10^21 molecules of water, there are approximately 0.073 moles.
To calculate the number of moles, we can use Avogadro's number, which states that 1 mole of a substance contains 6.022 × 10^23 molecules. So, by dividing the given number of molecules (4.38 × 10^21) by Avogadro's number, we can find the number of moles.
Now, let's explain the process in detail. Avogadro's number is a constant that represents the number of particles (atoms, molecules, etc.) in one mole of a substance. It is approximately 6.022 × 10^23. Therefore, if we divide the given number of molecules by Avogadro's number, we can determine the number of moles.
In this case, we divide 4.38 × 10^21 molecules by 6.022 × 10^23 molecules/mole, resulting in approximately 0.073 moles.
Significant figures play an important role in reporting the answer. The given number of molecules has three significant figures (4, 3, and 8), so our answer should be reported with three significant figures as well. Therefore, the number of moles is approximately 0.073.
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Lightning struck a tree, causing it to break and crash to the ground. The tree broke off 12 feet above the ground and the broken part was 20 feet long. The broken tree formed a right triangle. Determine how far the tip of the tree is from the base of the tree.
Distance =_______ ft.
Distance 11.143 ft or thereabouts is Distance roughly how far the tree extends from its tip to its base.
How Far Is It?Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting and ending position.
We obtain a quadratic equation by simplifying and expanding the left side:
2y^2 - 288y + 144 = 0
The quadratic formula is used to solve for y, and the result is: y = [288 (2882 - 4(2)(144)]
/(2(2))
y = [288 ± √58368]
y = 0.857 ft or /4 y = 84 foot
The only viable answer is: y 0.857 ft since y cannot be higher than 12 ft (the whole height of the tree).
The result of changing this number for y in the equation x + y = 12 ft is: x + 0.857 ft = 12 ft x 11.143 ft
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54.1miles/gallons how many liters of gas will be consumed traveling 132 km
Answer:
5.75 L.
Explanation:
From the question given above, the following data were obtained:
Rate = 54.1 miles/gallons
Distance = 132 km
Volume (in L) consumed =?
Next, we shall convert 132 km to mile. This can be obtained as follow:
1 km = 0.621 mile
Therefore,
132 km = 132 km × 0.621 mile / 1 km
132 km = 81.972 mile
Next, we shall determine the volume (in gallons) of the gas needed. This can be obtained as follow:
Rate = 54.1 miles/gallons
Distance = 81.972 mile
Volume (in gallon) =?
Rate = Distance / volume
54.1 = 81.972 / volume
Cross multiply
54.1 × volume = 81.972
Divide both side by 54.1
Volume = 81.972 / 54.1
Volume = 1.52 gallon.
Finally, we shall convert 1.52 gallon to litre (L). This can be obtained as follow:
1 gallon = 3.785 L
Therefore,
1.52 gallon = 1.52 gallon × 3.785 L / 1 gallon
1.52 gallon = 5.75 L
Therefore, 5.75 L of the gas will be consumed.
Determine the molar mass of a 0.643-g sample of gas occupies 125 mL at 60. cm of Hg and 25°C
Explanation:
To determine the molar mass of the gas, we need to use the ideal gas law equation:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. We can rearrange this equation to solve for the number of moles:
n = (PV) / (RT)
We are given the mass of the gas (0.643 g), the volume (125 mL), the pressure (60. cm Hg), and the temperature (25°C). To use these values in the ideal gas law equation, we need to convert the volume to liters and the pressure to atmospheres (atm) and the temperature to Kelvin (K):
V = 125 mL = 0.125 L
P = 60. cm Hg = 0.789 atm (using the conversion factor 1 atm = 760 mm Hg and 1 cm Hg = 1.33322 mm Hg)
T = 25°C + 273.15 = 298.15 K
Substituting these values into the ideal gas law equation and solving for n gives:
n = (PV) / (RT) = (0.789 atm x 0.125 L) / (0.0821 L·atm/mol·K x 298.15 K) = 0.00314 mol
To find the molar mass, we can use the formula:
molar mass = mass of sample / number of moles
molar mass = 0.643 g / 0.00314 mol = 204.46 g/mol
Therefore, the molar mass of the gas is approximately 204.46 g/mol.
Answer:
To determine the molar mass of the gas, we need to use the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can rearrange this equation to solve for n:
n = PV/RT
First, we need to convert the pressure to atmospheres (atm) and the volume to liters (L):
cm Hg = 0.788 atm (using the conversion factor 1 atm = 760 mm Hg)
125 mL = 0.125 L
Next, we can substitute the given values into the equation and solve for n:
n = (0.788 atm)(0.125 L)/(0.0821 L·atm/mol·K)(298 K) = 0.00472 mol
Finally, we can calculate the molar mass by dividing the mass of the sample by the number of moles:
molar mass = 0.643 g/0.00472 mol = 136 g/mol (rounded to three significant figures)
Therefore, the molar mass of the gas is approximately 136 g/mol.
need help whoever answers will be awarded branliest answer
Answer:
1.used to seperate solids from liquids, and is a act of pouring a mixture onto a membrane this allows the passage of liquid and results in the collection of a solid
2. the solution would passed through without losing and solids
3 would allow them to dry or on further hearing decompose
Explanation:
Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction.
S2O3 2- (aq) --> S4O6 2- (aq)
We must take into consideration the balance of atoms and charges in order to balance the half-reaction for the conversion of S2O3 2- to S4O6 2- in acidic solution.
Write the imbalanced half-reaction as the first step.
S2O3 S4O6 2- (aq)
Step 2: Align the atoms, with the exception of hydrogen and oxygen.
2S4O6 2-(aq) = S2O3 2-(aq)
Step 3: Add water (H2O) to balance the oxygen atoms.
2S4O6 2- (aq) + H2O = S2O3 2- (aq)
Step 4: Add hydrogen ions (H+) to balance the hydrogen atoms.
2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq)
Step 5: Add more electrons (e-) to balance the charge.
2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq) + 2e-
The balanced half-reaction in acidic solution is:
S2O3 2- (aq) + 4H+ (aq) + 2e- → 2S4O6 2- (aq) + H2O
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When a solution of sodium hydroxide is mixed with iron (II) chloride, a green precipitate is formed. What is the balanced equation for that reaction?
The balanced chemical equation for the reaction is:
2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)
What is a chemical equation?Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.
The reactants are located on the left side while the products are located on the right side.
Reactants —> Products
The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
How to write the balanced equationSodium hydroxide => NaOH
Iron (II) chloride => FeCl₂
2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)
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871g of sodium chloride is how many moles
Answer:
14.9 mol
Explanation:
To find the number of moles in a given mass of a sample of sodium chloride (NaCl), we can multiply the number of grams in the sample by the molar mass of sodium chloride, which is 58.44 g/mol.
871 g × (1 mol / 58.44 g)
= 871/58.44 mol
≈ 14.9 mol
Note that we rounded to 3 significant figures in the final answer because that is how many significant figures were given in the mass measurement of the sodium chloride sample.
How can the third digit of the VSPER number be determined if only 1st two VSEPR number are known
The VSEPR (Valence Shell Electron Pair Repulsion) theory describes the arrangement of electron pairs around a central atom in a molecule, and the VSEPR number represents the total number of electron pairs around the central atom, including both bonding pairs and lone pairs.The VSEPR number can be determined from the Lewis structure of the molecule, which shows the arrangement of atoms and lone pairs around the central atom. The first two digits of the VSEPR number correspond to the number of bonding pairs and lone pairs, respectively, around the central atom.To determine the third digit of the VSEPR number, you need to consider the shape of the molecule. The shape is determined by the repulsion between electron pairs, which is strongest between lone pairs and decreases in the order lone pair-lone pair > lone pair-bonding pair > bonding pair-bonding pair.The third digit of the VSEPR number indicates the shape of the molecule according to the following scheme:1: linear shape2: trigonal planar shape3: tetrahedral shape4: trigonal bipyramidal shape5: octahedral shapeThus, to determine the third digit of the VSEPR number, you need to determine the shape of the molecule based on the number of electron pairs and their relative positions. This can be done by applying the VSEPR theory and considering the repulsion between electron pairs. Alternatively, you can consult a table or chart that lists the shapes associated with different VSEPR numbers.
How many different E2 products are expected in the reaction of 3-bromo-1,1-dimethylcyclohexane with NaOCH2CH3?
A) only 1
B) 2
C) 3
D) 4
The electron configuration 1s2 is correct for an element that has 2 electrons, both in the first principle energy level
Answer:
The answer is True
Explanation:
I got it right on my quiz, hope this helps!