Which action can be explained by physics?

Answers

Answer 1

Answer:

Actions that underlie mathematical rules, patterns or probability distributions.

For example how fast something falls at any given point or time.

More complex actions, such as human decision making in single individuals would be way too complicated to describe in physical terms.

But note that there can be physical models of such things as traffic when we can assume statistical knowledge of behavior.

Also physical models are used to plan such things as emergency exits in big stadiums, because many thousands of people can be described as particles flowing under a given pressure.

Every time we can gain good statistical knowledge and can therefore see patterns and rules in action, we can build theoretical models to make predictions and simulations (and games btw)

Since it's fair to say that mathematics is the science of patterns, it is plausible that physical descriptions often come in mathematical formulations, so that it can be understand as an efficient language of physics.

Neighboring disciplines like chemistry relay on physical theories to build on them,and then add shortcuts to fit their needs and interests, generating an own language for their field of study. But physicists may refer to them as anadd-on to physics.

Physics can basically explain all actions wich you can express in numbers.

But note that on a fundamental level physics describes 'how' things work, not necessarily 'why' they do it this way. The source of the basic and most fundamental physical constants and rules remains a mystery till this day.But of course there are theories on that as well, wich mostly can neither be proved or falsified.

The text is my own work and based of my general knowledge and quintessence of lectures on physics and other fields I attended.

(I would really appreciate the brainliest)


Related Questions

at an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. people sit in seats facing the axis, their backs against the outer wall. at one instant the outer wall moves at a speed of 3.13 m/s, and an 83.6 kg person feels a 578 n force pressing against his back. what is the radius of a chamber

Answers

The radius of the cylindrical chamber in the amusement park ride can be calculated using  formula for centripetal force and the given values for velocity and force. In this case, the radius is approximately 14.3 meters.

The person is seated facing the axis, with their back against outer wall. At a given instant, the outer wall moves at a speed of 3.13 m/s, and the person feels a 578 N force pressing against their back.

To determine the radius of the chamber, we can use formula for centripetal force, \(Fc = (mv^2) / r\).

Rearranging the formula to solve for r, we get r = (mv^2) / Fc. Substituting the given values, we get\(r = (83.6 kg * (3.13 m/s)^2) / 578 N,\) which simplifies to  \(r = 14.3 m\). Therefore, the radius of the cylindrical chamber is approximately \(14.3 meters\).

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The first Tacoma Narrows Bridge in Washington crossed over a strait in Puget Sound. At the time the suspension bridge was built, construction workers noticed that it moved up and down in the wind. Measures to stop the bridge's movement were ineffective, but the bridge was opened to the public on July 1, 1940. The bridge collapsed on November 7, 1940. Luckily, no people were seriously injured. Determine which technological design criteria the Tacoma Narrows Bridge did and did not meet. Explain your answer.

Answers

Answer:

Follows are the solution to this question:

Explanation:

When the Tacoma Narrows Bridge was built, it may not have met the technical design requirements and when it didn't solve the problem for long so, the bridge will be unsustainable and fell. or we can say that Due to an aeroelastic flutter caused by high winds, the bridge collapsed. The bridge oscillated rapidly and ultimately dropped. Its collapse of the bridge has lasting impacts on science and technology.

Answer:

When the Tacoma Narrows Bridge was built, it may not have met the technical design requirements and when it didn't solve the problem for long so, the bridge will be unsustainable and fell. or we can say that Due to an aeroelastic flutter caused by high winds, the bridge collapsed. The bridge oscillated rapidly and ultimately dropped. Its collapse of the bridge has lasting impacts on science and technology.

For a total of 8 hours, Erica rode her motorcycle down a freeway at 80 kilometers per hour.
There was a car behind her for one-quarter of that time. How far did Erica ride while the car
was behind her?

Answers

80 kilometers 1/4 of that is 20 kilometers so the car followed her for 20 kilometers or 2 hrs

1. according to the hertzsprung-russell diagram, what type of star is the sun? a) spectral type o b) red giant c) main sequence d) white dwarf

Answers

The kind of star that belongs to the main sequence is the sun, according to the Hertzsprung-Russell diagram.

What were the monsters in Spectral?

In Pac-Man World 3, opponents are called Spectral Monsters. They are fiery Spectral Realm beings who are enraged by Erwin's interference with their world. They appear to be much less intellectual than ghosts, yet because of their special skills, they are more dangerous. Pac-Man can consume Spectral creatures in the same manner as ghosts.

What happens when spectral is over?

When Clyne turns off the device, the human parts of these apparitions are promptly killed along with their spirit counterparts. The final rebels in the town are swept up by American and Moldovan forces as the fight comes to an end.

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look at attached photo pls. physics, momentum, acceleration. 30 points:)

look at attached photo pls. physics, momentum, acceleration. 30 points:)

Answers

1. The deceleration of the aeroplane in the 35s is -1.6m/s²

2. The force acting on the aeroplane is 4.0× 10⁵N

3. The momentum of the aeroplane when its speed is 6.0m/s is 15 ×10⁶kgm/s

What are the equation of motion?

The equation of motion are used in solving problems related to motion. The equations of motion are

1. v = u+ at

2 S = ut + 1/2at²

3. v² = u²+2as

where v is the final velocity

u is the initial velocity

S is the distance

t is time

a is the acceleration

The deceleration of the plane after 35s can be calculated as;

v = u+at

v= 6m/s, u= 62m/s , t = 35s

6 = 62+35a

35a = 6-62

35a =- 56

a = - 56/35

a = -1.6m/s²

the negative sign shows that the plane decelerates.

The force acting on the plane is calculated as;

F = ma

F = 2.5×10⁵× 1.6

F = 4× 10⁵N

The momentum of the plane at 6m/s is ;

p = mv

p = 2.5×10⁵ × 6

p = 1.5× 10⁶ kgm/s

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When the current in a coil flows in anti-clockwise direction, what pole does it create?​

Answers

Answer:

The North Pole.

Explanation:

According to the Lenz's law of electromagnetic induction, an induced elemagnetic force tends to give rise to the current. In reaction, this current's magnetic field try to oppose any replacement in the magnetic flux.

So,  as per the law of Lenz's electromagnetic induction, when the current passes in a coil in anti-clockwise direction, this will produce the opposite end of the coil in the north pole.

So, the correct answer is north pole.

What is the number of the strength of gravity on Earth?

Answers

Answer:

i don't know this answer

Given: Rocket motor equation: " Ve + (Pe – Pa) AC Rocket weight (no propellant): 300 kg Propellant weight: 800 kg Acceleration at burnout: 10 18 G ur. First things first – the contribution of the pressure differential, (Pe - Pa)Ae is typically very small. Its contribution will be ignored for this problem. Compute the Isp required to develop a rocket with a burnout velocity of 1000 m/s. Compute the exit velocity (Ve or Vj) required for this rocket. Plot the rocket acceleration (in terms of G) and rocket weight as a function of time. What is the burn time of the rocket? Finally, plot the speed of the rocket, assuming a flight path angle of 45 degrees assuming no gravity. Plot the speed of the rocket considering gravity.

Answers

To develop a rocket with a burnout velocity of 1000 m/s, the specific impulse (Isp) required needs to be calculated. The exit velocity (Ve or Vj) required for the rocket can be determined using the rocket motor equation. The burn time of the rocket can be found by considering the rocket's weight and acceleration over time.

Additionally, the speed of the rocket, assuming a flight path angle of 45 degrees and considering gravity, can be plotted.

1. Calculating Required Isp:

To calculate the required Isp, we use the rocket motor equation: Ve + (Pe - Pa)AC = (m0 / mf) * g0 * Isp, where Ve is the exit velocity, Pe is the pressure at the exit, Pa is the ambient pressure, AC is the throat cross-sectional area, m0 is the initial total mass (rocket weight + propellant weight), mf is the final total mass (rocket weight), g0 is the acceleration due to gravity, and Isp is the specific impulse.

Since the contribution of the pressure differential is ignored, the equation simplifies to Ve = (m0 / mf) * g0 * Isp.

Given the burnout velocity of 1000 m/s, we can substitute the values and solve for Isp.

2. Determining Exit Velocity:

Using the rocket motor equation and the burnout velocity, we can solve for the exit velocity (Ve). This value represents the speed at which exhaust gases leave the rocket nozzle.

3. Plotting Rocket Acceleration and Weight:

To plot the rocket acceleration as a function of time, we need to consider the mass of the rocket over time. Initially, the rocket weight is the sum of the rocket weight (300 kg) and propellant weight (800 kg). As the propellant burns, the rocket weight decreases, resulting in a changing acceleration.

4. Calculating Burn Time:

The burn time of the rocket can be determined by dividing the propellant weight (800 kg) by the propellant consumption rate, which is the mass flow rate of the propellant.

5. Plotting Rocket Speed:

Assuming a flight path angle of 45 degrees and neglecting gravity, the rocket's speed can be plotted over time. This plot represents the rocket's horizontal velocity.

6. Considering Gravity:

To plot the rocket's speed while considering gravity, we need to account for the vertical acceleration due to gravity. By considering the rocket's horizontal and vertical velocities, we can determine the overall speed of the rocket.

By following these steps, the required Isp, exit velocity, burn time, and velocity plots can be determined for the given rocket scenario.

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The average kinetic energy of the molecules of an ideal gas at 10∘C has the value K10. At what temperature T1 (in degrees Celsius) will the average kinetic energy of the same gas be twice this value, 2K10? Express the temperature to the nearest integer. View Available Hint(s) T1 T 1 T_1 = nothing ∘C Part B The molecules in an ideal gas at 10∘C have a root-mean-square (rms) speed vrms. At what temperature T2 (in degrees Celsius) will the molecules have twice the rms speed, 2vrms? Express the temperature to the nearest integer. View Available Hint(s) T2 T 2 T_2 = nothing ∘C

Answers

Answer:

A) T1 = 566 k = 293°C

B) T2 = 1132 k = 859°C

Explanation:

A)

The average kinetic energy of the molecules of an ideal gas is givwn by the formula:

K.E = (3/2)KT

where,

K.E = Average Kinetic Energy

K = Boltzman Constant

T = Absolute Temperature

At 10°C:

K.E = K10

T = 10°C + 273 = 283 K

Therefore,

K10 = (3/2)(K)(283)

FOR TWICE VALUE OF K10:

T = T1

Therefore,

2 K10 = (3/2)(K)(T1)

using the value of K10:

2(3/2)(K)(283) = (3/2)(K)(T1)

T1 = 566 k = 293°C

B)

The average kinetic energy of the molecules of an ideal gas is given by the formula:

K.E = (3/2)KT

but K.E is also given by:

K.E = (1/2)(m)(vrms)²

Therefore,

(3/2)KT = (1/2)(m)(vrms)²

vrms = √(3KT/m)

where,

vrms = Root Mean Square Velocity of Molecule

K = Boltzman Constant

T = Absolute Temperature

m = mass

At

T = 10°C + 273 = 283 K

vrms = √[3K(283)/m]

FOR TWICE VALUE OF vrms:

T = T2

Therefore,

2 vrms = √(3KT2/m)

using the value of vrms:

2√[3K(283)/m] = √(3KT2/m)

2√283 = √T2

Squaring on both sides:

(4)(283) = T2

T2 = 1132 k = 859°C

A) The temperature at which the average kinetic energy will have a value of 2K10 is; T1 = 293 °C

B) The temperature at which the molecules have twice the rms speed, 2vrms is; T2 = 859 °C

A) We are given;

Initial temperature; T = 10°C = 283 K

Initial kinetic energy; KE = K10

Final kinetic energy; KE1 = 2K10

Now,formula for average kinetic energy of the molecules of an ideal gas is given as;

KE = (3/2)kT

Where;

k is Boltzmann constant

T is temperature

We are told that in the second case, KE = 2K10. Thus;

2K10 = (3/2)kT1

K10 = ¾kT1 - - - (eq 2)

In the first instance, we have;

K10 = (3/2)kT - - - (eq 1)

Put (3/2)kT for K10 in eq 2 to get;

(3/2)kT = ¾kT1

k will cancel out to get;

(3/2)T = ¾T1

Make T1 the subject to get;

T1 = 2T

Thus;

T1 = 2 × 283

T1 = 566 K

Converting to °C gives;

T1 = 293 °C

B) We want to find the temperature T2 (in degrees Celsius) at which the molecules will have twice the rms speed, 2v_rms.

Formula for kinetic energy is also;

KE = ½mv²

Thus;

½m(v_rms)² = (3/2)kT

v_rms = √(3kT/m) - - - (eq 1)

When rms speed is 2v_rms, we have;

½m(2v_rms)² = (3/2)kT2

v_rms = √(¾kT2/m) - - - (eq 2)

Thus;

√(3kT/m) = √(¾kT2/m)

Square both sides to get;

(3kT/m) = (¾kT2/m)

4T = T2

T2 = 283 × 4

T2 = 1132 K

Converting to °C gives;

T2 = 859 °C

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A net force of 126 N [S] is applied to a 70 kg sprinter. Determine the acceleration of
the sprinter. [ans: 1.8 m/s? [S]]

Answers

ACCELERATION

\( \color{darkblue} \mathbb{ANSWER:}\)Yes, the acceleration of the sprinter is 1.8 but it should be measured in meters per second squared.

\( \color{darkblue} \mathbb{EXPLANATION:}\)

— The formula for acceleration is given by:

\( \underline{ \boxed{ \tt a = \frac{F}{m} }}\)

where,

a is the acceleration measured in meters per second squared (m/s²)F is the net Force (Newtons/N)m is the mass (kilograms/kg)

---------

— To get the acceleration, divide the given net force by the given mass. Its quotient is the acceleration that should be measured in meters per second squared (m/s²).

Using our formula/equation, we get:

\( \tt a = \frac{F}{m} \\ \: \: \: \: \: \: \: \tt \: a = \frac{126 \:N }{70 \: kg} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt \: a = \underline{ \boxed{ \purple{ \tt \: 1.8 \: m/s²}}}\)

\( \color{darkblue} \mathbb{FINAL \: \: ANSWER:}\)

\(\bold{1.8 \: m/s²} \\ \)

_______________◇_______________

We have an Atwood device, two blocks connect by a string strung over a pulley, but the twist this time is that both blocks are on perfectly smooth inclines. The upper block is on an incline 15 degrees to the horizontal and has a mass of 7kg. The lower block is on an incline of 65 degrees to the horizontal and has a mass of 11kg. Find the acceleration of the system?

Answers

The Acceleration of the system is 6.41 m/s².

Given,

α= 15°, m₁ = 7kg

β= 65°, m₂ = 11 kg

Let, a be the acceleration and T is the tensions at the end it's the cord.

Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,

Resultant force, m₂a=m₂g sin β -T

11a=((11) ×g sin 65°) -T  ...(i)

Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.

Resultant force m₁a = m₁g sin α+T

7a =7g sin 15°+T  ...(ii)

Solving both the equations by adding them,

18a=11gsin 65°+7g sin 15°-T+T

18a=11gsin 65°+7g sin 15°=115.45

a=115.45/18=6.41 m/s²

Hence, the Acceleration of the system is 6.41 m/s².

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A 6kg object is lifted to a height of 10m. How much PE does it have?

Answers

Answer:

588 J

Explanation:

P.E = mgh

      = 6 * 9.8 * 10

     = 588 J

if g value is rounded and taken as 10 then answer is 600 J.

Two people walking on a sidewalk have the following

equations of motion:

xi = 8. 2 m + (-1. 1 m/s)t

x2 = 5. 9 m + (1. 7 m/s)t

(a) Which person is moving faster? (b) Which

person

will be at x = 0 at some time in the future?

Answers

Person 1 will be at x = 0 at some time in the future, specifically after approximately 7.45 seconds.

To determine which person is moving faster, we can compare their velocities. The velocity of each person can be obtained by taking the derivative of their respective equations of motion with respect to time (t).

For Person 1:

v1 = d(xi)/dt = -1.1 m/s

For Person 2:

v2 = d(x2)/dt = 1.7 m/s

Comparing the velocities, we find that Person 2 (v2 = 1.7 m/s) is moving faster than Person 1 (v1 = -1.1 m/s).

To determine which person will be at x = 0 at some time in the future, we can set their respective position equations equal to zero and solve for t.

For Person 1:

xi = 8.2 m + (-1.1 m/s)t = 0

-1.1t = -8.2

t = 7.45 seconds

For Person 2:

x2 = 5.9 m + (1.7 m/s)t = 0

1.7t = -5.9

t = -3.47 seconds

Since time cannot be negative in this context, we disregard the negative value for Person 2. Therefore, Person 1 will be at x = 0 at some time in the future, specifically after approximately 7.45 seconds.

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which is 20 light years planet from earth​

Answers

A light-year is a unit of distance, specifically the distance that light travels in one year.

Light travels at a speed of approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum. Therefore, to determine which planet is 20 light-years away from Earth, we need to identify a planet located at a distance of approximately 20 times this speed of light.

As of my knowledge cutoff in September 2021, no known exoplanets have been directly observed and confirmed to be located exactly 20 light-years away from Earth. However, there are numerous exoplanets that have been discovered within a range of distances from Earth.

Some notable exoplanets discovered within approximately 20 light-years of Earth include:

Proxima Centauri b: This exoplanet is located in the habitable zone of the closest star system to our Solar System, Proxima Centauri. It is estimated to be around 4.24 light-years away.

Ross 128 b: This exoplanet orbits a red dwarf star known as Ross 128, located approximately 11 light-years away from Earth.

TRAPPIST-1 system: This system hosts seven Earth-sized planets orbiting the ultra-cool dwarf star TRAPPIST-1. The TRAPPIST-1 system is located around 39 light-years away from Earth.

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What conditions must be satisfied for momentum to be conserved in a system?

Answers

The conditions that must be satisfied for momentum to be conserved in a system are; The total external force acting on a system must be zero. In other words, the net force on the system must be zero.

If there is no net force on the system, the momentum of the system will remain constant with time.The mass of the system must remain constant with time. If the mass of the system is changing with time, the momentum of the system will also change with time. Therefore, it is essential to keep the mass of the system constant.

The collision must be elastic. In an elastic collision, the total kinetic energy of the system is conserved, and the momentum of the system is conserved. In other words, the system behaves as if there were no external forces acting on it. If the collision is not elastic, the total kinetic energy of the system will not be conserved. Instead, some of the kinetic energy will be converted into other forms of energy, such as thermal energy or sound energy.If the above three conditions are satisfied, the momentum of the system will be conserved.

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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.

Answers

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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You have a 6-m-long copper wire. You want to make an N-turn current loop that generates a 4.085 mT magnetic field at the center when the current is 1.513 A. You must use the entire wire. What will be the diameter, in cm, of your coil?

Answers

ANSWER:

2.98 cm

STEP-BY-STEP EXPLANATION:

Given:

Length wire (L) = 6 m

Current (i) = 1.513 A

magnetic field (β) = 4.085 mT = 4.085 x 10^-3 T

Magnetic field at the center of circular coil is given for the following formula:

\(\beta=\frac{\mu_0\cdot N\cdot i}{2R}=\frac{\mu_0\cdot N\cdot\imaginaryI}{d}\)

The total length of wire in the coil is given by:

\(\begin{gathered} L=\pi\cdot d\cdot N \\ \\ N=\frac{L}{\pi d} \end{gathered}\)

We replacing:

\(\begin{gathered} \beta=\frac{\mu_0\cdot\frac{L}{\pi d}\cdot\imaginaryI}{d} \\ \\ \beta=\frac{\mu_0\cdot L\cdot\imaginaryI}{\pi\cdot d^2} \\ \\ d^2=\frac{\mu_0\cdot L\cdot\imaginaryI}{\pi\beta} \\ \\ d=\sqrt{\frac{\mu_0L\imaginaryI}{\pi\beta}} \\ \\ \text{ Therefore:} \\ \\ d=\sqrt{\frac{4\pi\cdot10^{-7}\cdot6\cdot1.513}{\pi\cdot4.085\cdot10^{-3}}} \\ \\ d=0.0298\text{ m}=2.98\text{ cm} \end{gathered}\)

Therefore, the diameter in centimeters is equal to 2.98 cm

anderson video - solenoids 4 of 5 review | constants first, launch the video solenoids. after watching the video, answer the follow-up question below. select to launch video part a a solenoid with 200 loops is 60 cm long. it has a current of 4.2 a. what is the magnetic field in this solenoid?

Answers

The magnetic field in this solenoid is  0.3438 X 10⁻³ mT.

Number of loops = n = 200

Length of the solenoid = l = 60 cm = 0.6m

Thus, turns per m = 200/0.6 = 333.33

Current through the solenoid = i = 4.2

The magnetic field through the solenoid is = B =

= B = μ X n X I

= B = ( 4 X π X 10⁻⁷ X 200 X 4.2 ) / 0.60

= B = 10500.4 X 10⁻⁷ / 0.60

= B = 34383.66 X 10⁻⁷ T

= B = 0.3438 X 10⁻³ mT

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Madison applied a force of 150 N in a horizontal direction to a sleigh. Meanwhile the sleigh slid 30.0 m across a level surface of snow. The work done on the sleigh by Madison is _________ J.

Answers

Answer:

4500 joules

Explanation:

since work(joules) = force(newtons) x distance(meters),

150N x 30M = 4500 Joules

Answer:

4500 joules

Explanation:

150 N x 30 M = 4500 joules

Four forces are acting on a block as shown in the figure. What is the net force on the block?

Four forces are acting on a block as shown in the figure. What is the net force on the block?

Answers

Answer:

8 N  upwards

Explanation:

What net force would be necessary to cause a block of wood with a mass of 2.5 kg to accelerate at a rate of 3.0 m/s2

Answers

Answer:

7.5 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 2.5 kg

acceleration = 3.0 m/s²

We have

force = 2.5 × 3.0 = 7.5

We have the final answer as

7.5 N

Hope this helps you

A solenoid 1.85 m long and 2.20 cm in diameter carries a current of 21.0 A. The magnetic field inside the solenoid is 25.0 mT. Find the length of the wire forming the solenoid.

Answers

Answer:

A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences a 2.16-N force on the 4.00 cm of wire in the field. What is the average field strength?

Explanation:

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Calculate the temperature increase ΔT in a 1.40 kg sample of water that results from the conversion of 19% of the gravitational potential energy directly to heat energy in the world's tallest waterfall, the 807-m ‑tall Salto Angel in Canaima National Park, Venezuela.

Answers

The temperature increase is 0.24°C.

Solution:

Gravitational potential energy = mgh

= 1.4*9.8*807 = 11072.04 J

19% of PE = heat energy

0.19*11072 = mcΔ

1439.3652 = 1.4*4186*Δ

Δ = 0.24° C

so the temperature increase is 0.24°C.

Gravitational potential energy is converted to thermal energy at the fire point. When an object high above the ground heats a surface or other object, it produces thermal energy through friction and vibration. When an object falls from a great height, gravitational potential energy is converted into kinetic energy.

When you hit something and stop falling, all the kinetic energy is converted into heat. When the light is turned on, potential energy travels through the wires and is converted into light and heat, which are forms of kinetic energy. The gravitational potential energy at large distances is directly proportional to mass and inversely proportional to the distance between them. The gravitational potential energy increases with the increase.

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Please help me!!!!

Make a hypothesis on this question. Can you use density to identify eight cubes made of different materials?

Answers

The ratio of an object's mass to volume is known as its density. Density is defined as the product of mass and volume, or D = m/v. Because of the size, mass, and arrangement of each substance's atoms or molecules, each substance has a unique characteristic density.

Can density be used to identify a material?One of an object's most significant and practicable physical characteristics is density. Densities are frequently used to identify pure substances, classify mixtures, and estimate their composition.The ratio of an object's mass to volume is known as its density. Density is defined as the product of mass and volume, or D = m/v. Because of the size, mass, and arrangement of each substance's atoms or molecules, each substance has a unique characteristic density.The densities of pure materials cannot be the same. The densities of mixtures, compounds, or distinct phases can be the same (assuming they are not isotopes of one another).

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How does time affect change in momentum?

Answers

Time plays a crucial role in determining the change in momentum of an object, and longer durations of force application can produce the same change in momentum as shorter durations with larger forces.

As per the question given,  

Time is an important factor that affects the change in momentum of an object. Momentum is defined as the product of an object's mass and velocity. When an object experiences a force for a certain amount of time, its momentum changes. The change in momentum is directly proportional to the force applied and the duration of the force.

A smaller force acting for a longer time can produce the same change in momentum as a larger force acting for a shorter time. This is known as the principle of conservation of momentum. The total momentum of a system is conserved in the absence of external forces.

In collisions, the duration of the impact is an important factor that determines the change in momentum of the colliding objects. A longer collision time results in a smaller force and a smaller change in momentum, while a shorter collision time results in a larger force and a larger change in momentum.

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can the transfer of heat by convection occur in solids ?why?​

Answers

Answer:

cannot

Explanation:

because convection occurs to difference in densities between particles and there is a movement of particles during convection ( gases and liquids ) , in solids , atoms are very tightly packed and cannot move

what can be done to increase speed of rotation of a DC motor​

Answers

Answer: There are multiple options:

By varying the supply voltage.

By varying the flux, and by varying the current through the field winding.

By varying the armature voltage, and by varying the armature resistance.

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a clown 1.88 m tall looks at himself in a full-length mirror (floor-to-ceiling). at what point on the mirror must he look to see his feet (distance measured up from the floor)?

Answers

This is the same height as the clown, so if he looks up at the mirror from the floor he should be able to see his feet reflected in the mirror.

What is mirror?

Mirror is a reflective surface, typically of glass, which displays images of objects placed in front of it. Mirrors are used in a variety of different applications, including personal grooming, decoration, interior design, viewing art, scientific uses, and more. A mirror is composed of a flat, smooth surface that reflects light in a specific direction. This reflection is what produces the image we see in the mirror. The reflective surface is usually made of glass, although other materials such as metal, plastic, and wood can also be used. Mirrors can be manufactured in a variety of shapes and sizes, from small hand-held makeup mirrors to large wall-mounted mirrors. Some mirrors are also designed with special coatings or treatments to enhance their reflective properties.

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What does it mean when the
compressions of a longitudinal
wave are far apart?
A. the amplitude is higher
B. the wavelength is longer
C. the wavelength is shorter
D. the amplitude is shorter

Answers

Answer:

it will option B,hope it helps

C. The wavelength is longer.

What is longitudinal wave?

A sound wave is called a longitudinal wave because compressions and rarefactions in the air produce it.

The air particles vibrate parallel to the direction of propagation.

A longitudinal wave consists of a repeating pattern of compressions and rarefactions.

Thus, the wavelength is commonly measured as the distance from one compression to the next adjacent compression or the distance from one rarefaction to the next adjacent rarefaction.

Longitudinal waves move through a medium from the point of the disturbance in the form of compressions (where particles of the medium are bunched together) followed by rarefactions (where particles of the medium are farther apart).

In longitudinal waves, the distance from one compression to the next is the wavelength.

Therefore,

In longitudinal wave the wavelength is longer.

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when a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm. let 2.0 cm be the rest position for the mass-spring system. the mass is then pulled down an additional distance of 1.5 cm and released.calculate the period of resulting oscillation in si units.

Answers

When a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm, with an additional distance of 1.5cm,

Mass m= 0.30 kg

Distance x = 2.0 + 1.5 cm = 0.035 m

Since spring constant k = \({\frac{mg}{x}\) , (g=9.81)

k = \({\frac{0.3*9.81}{0.035}\) = 84.085 N/m

ω = \(\sqrt{\frac{k}{m} }\) = \(\sqrt{\frac{84.085}{0.3} }\) = 16.74 rad/sec

T = \(\frac{2\pi }{w}\) = \(\frac{2*3.14}{16.74}\) = 0.375 sec

The spring constant is the force required to stretch or compress the spring divided by the distance the spring is lengthened or shortened. It is used to determine the stability or instability of a spring and thus the system for which it is intended.

Therefore the time period of resulting oscillation is 0.375 sec.

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