Answer:
gamma is shortest, radio waves are longest
if you can't test an explanation through experiment,
A) the phenomena let's not have occurred in the physical world
B) people will disagree on whether the explanation is correct
C) your observation must not have really occurred
D) a group of scientists will vote on their favorite explanation
Answer:
B
Explanation:
A jet is flying from atlanta to gulfport and is cruising at Mach .79 or 844 km/hr. During the last 89 km it reduces its speed for landing at a rate of -2780 km/hr^2. How long will it take for the jet to reach landing speed? What was the landing speed of the jet?
Answer:
The time it takes for the jet to reach landing speed is approximately 0.136 hours which is approximately 489 seconds
The landing speed is approximately 466.365 km/hr
Explanation:
The given parameters are;
The initial cruising speed of the jet = Mach 0.79 = 844 km/hr
The rate of speed reduction in the last 89 km = -2780 km/hr²
The distance it takes the jet to reduce its speed for landing = 89 km
Given the above information, we make use of the following equation of motion;
s = u·t - 1/2·a·t²
v² = u² - 2·a·s
Where;
s = The distance over which the acceleration (deceleration) is applied = 89 km
u = The initial velocity = 844 km/hr
t = The time taken for the accelerating/decelerating motion
v = The final velocity (landing speed)
Substituting the values gives;
v² = 844² - 2·(2780)·89 = 217496
v = √217496 = 466.365 km/hr
v ≈ 466.365 km/hr
Therefore, the landing speed, v ≈ 466.365 km/hr
The time it takes is given by the equation, v = u - a·t
Therefore;
t = (u - v)/a = (844 - 466.365)/2780 ≈ 0.136 hours
The time it takes for the jet to reach landing speed ≈ 0.136 hours
From, s = u·t - 1/2·a·t², we have
89 = 844·t - 1/2 × 2780 × t²
89 = 844·t - 1390 × t²
1390 × t² - 844·t + 89 = 0
Solving with an online application gives;
t = 211/695 + (√(27187/2))/695 = 0.4715 hours or t = 211/695 - (√(27187/2))/695 = 0.136 hours
We note that the second time is for the time it will take the jet to get back to 89 km after reaching a speed of 0
Therefore, the correct time is t = 0.136 hours
The time it takes for the jet to reach landing speed ≈ 0.136 hours
Which of the following is true about the mass of an object?
O It is equal to its weight.
O It is proportional to its weight.
O it is always more than its weight.
Olt changes at different locations
Two charged particles near each other are released. As they move, the force on each particle increases. Therefore, the particles haveA) the same sign.B) the opposite sign.C) not enough information
ANSWER
B) the opposite sign
EXPLANATION
The force between charged particles is inversely proportional to the square of the distance between particles, from Coulomb's law:
\(F=k_e\cdot\frac{q_1\cdot q_2}{r^2}\)If the force increases it can mean two things: either one or both particles are gaining charge - which is not the case of this problem, or the distance between them is decreasing. In this case, the distance must be decreasing for the force to increase. This means that the particles are moving towards each other, they are being attracted by each other. Since only particles with opposite signs attract, the answer is option B, they have opposite sign.
Thirty-five coulombs of charge flow through a wire in 2 minutes. determine the current in the wire.
Thirty-five coulombs of charge flow through a wire in 2 minutes accounts for around 0.29167 amperes in the current wire.
Given:
Electric charge= 30 coulomb
Time for which charge flows through a wire = 2 minutes = 120 seconds
To find:
Electric current flowing in a wire=?
To calculate electric current understand the concept:
An electric current is the flow of charged particles through the conducting material.
The Standard International unit of electric current is Ampere or amp or A.
One ampere is defined as the flow of one-coulomb electric charge in one second.
It can be calculated as follows:
Electric current (Ampere) = Electric charge(Coulomb) ÷ time(seconds)
Electric current (A) = 35 C ÷ 120 s
Electric current = 0.29167 amperes
Hence, the electric current is flowing at the rate of 0.29167C/s or 0.29167 Ampere through a wire.
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Your friend's car is stuck in the snow. You push very hard and become very 1 tired but the car won't move. Did you do work?
Yes, work was done
No, work wasn't done
Answer:
Yes you worked
Explanation:
You may have not seen a good outcome but you did put effort in.
When a force is applied on the car and it doesn't move then it simply means
work wasn't done.
The formula for work is given below:
Work = Force ₓ Displacement
For work to have been done , the applied force must cause the object to
change its position(displacement).
In situations where the force applied doesn't cause a change in position then work can't be calculated. This means no work was done on the car despite the applied force causing him to be tired.
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Given the following MATLAB code, which defines the transfer function H(s) of a system and
calculates the impulse response h(t), Ha-gym(' (8+2)/ (8 2+7:8+12)!) hemilaplace (Ha) Adding the line
pzmap(Hs) to the above code gives the system pole-zero plot. True False
The given MATLAB code defines the transfer function H(s) of a system and calculates the impulse response h(t). Adding the line "pzmap(Hs)" to the code will generate the pole-zero plot of the system.
The given MATLAB code defines the transfer function H(s) of a system and calculates the impulse response h(t). However, the line "Ha-gym(' (8+2)/ (8 2+7:8+12)!) hemilaplace (Ha)" seems to be incomplete and unclear. It is not clear what the purpose of this line is or how it relates to the rest of the code.
Adding the line "pzmap(Hs)" to the code would plot the system's pole-zero plot. The function "pzmap()" takes the transfer function H(s) as an input and generates a plot showing the locations of the poles and zeros of the system.
Therefore, the statement "Adding the line pzmap(Hs) to the above code gives the system pole-zero plot" is true.
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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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a red ball has a mass of 290 g. a constant force pushes the red ball horizontally and launches it at a speed of 20 m/s. the same force pushes a green ball through the same distance, launching it at 25 m/s. what is the mass of the green ball?
Using the theories of kinetic energy, we got that the 185.6g is the mass of the green ball if force pushes the red ball horizontally and launches it at a speed of 20 m/s, and the same force pushes a green ball through the same distance, launching it at 25 m/s.
Since force acting on both of the balls is constant, therefore work done by friction on both of the balls remains same, therefore we can conserve energy.
Since both of balls have velocity, therefore kinetic energy of both balls remains same
Using formula of kinetic energy, we got
=>[(1/2)×mass of red ball×(velocity of red ball)²]=[(1/2)×mass of green ball×(velocity of green ball)²]
=> [ (1/2)×290×(20)²]=[1/2×m×(25)²]
=>m=290×(20)²/(25)²
=>m=(290×400)/625
=>m=185.6g
Hence, if a red ball has a mass of 290 g. a constant force pushes the red ball horizontally and launches it at a speed of 20 m/s. the same force pushes a green ball through the same distance, launching it at 25 m/s, the mass of the green ball is 185.6g
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A student wants to test if a bean plant will grow taller under green light than under sunlight. Select from the drop-down menu the correct step of the scientific method that each statement describes.
Two identical bean plants are grown next to each other. They receive the same amount of water and sunlight. One plant is covered with a green, light-filtering plastic cover, and the other with a clear plastic cover. Measurements of the bean plants’ heights are recorded every day for two weeks.
Answer:
Experiment
Record Results
Predict
Hypothesis
Analyze and Conclude
Observation and Questioning
Note: The question is incomplete. The complete question is given below:
A student wants to test if a bean plant will grow taller under green light than under sunlight. Select from the drop-down menu the correct step of the scientific method that each statement describes. Two identical bean plants are grown next to each other. They receive the same amount of water and sunlight. One plant is covered with a green, light-filtering plastic cover, and the other with a clear plastic cover. Measurements of the bean plants’ heights are recorded every day for two weeks. The student writes a lab report detailing the experimental procedure and results. The bean plant grown under the green filter will grow taller than the bean plant grown under unfiltered sunlight. Green light makes plants grow taller. The measurements show that the plant grown in natural sunlight grew taller than the green-filtered plant. So green light does not make plants grow taller. Plants are colored green, so maybe they grow more in green light.
Explanation:
1. An experiment is a procedure carried to test a hypothesis in order to support, reject or confirm the hypothesis. The steps below are for an experiment to whether bean plants grow taller under green light or sunlight.
Two identical bean plants are grown next to each other. They receive the same amount of water and sunlight. One plant is covered with a green, light-filtering plastic cover, and the other with a clear plastic cover. Measurements of the bean plants’ heights are recorded every day for two weeks.
2. Results of the experiment are recorded. The statement below indicates that results were recorded.
The student writes a lab report detailing the experimental procedure and results.
3. Predictions are expected results based on an initial hypothesis. The statement below is a prediction.
The bean plant grown under the green filter will grow taller than the bean plant grown under unfiltered sunlight.
4. A hypothesis is a statement that seeks to explain an observed phenomena. The statement below is a hypothesis:
Green light makes plants grow taller.
5. Analysis and conclusion: the results of the experiment are analysed and conclusions are then drawn. The statement below shows analysis and conclusion based on results of the experiment:
The measurements show that the plant grown in natural sunlight grew taller than the green-filtered plant. So green light does not make plants grow taller.
6. Observations and Questions are necessary parts of the scientific method. Observing phenomena around and asking questions about our observations helps in the process of making a hypothesis. The statement below is illustrates observation and questioning:
Plants are colored green, so maybe they grow more in green light.
Answer: D,F,C,B,E,A
Explanation:
i took the test
What part of the microscope do you adjust to change the amount of light?
The microscope has two sets of lenses, one in the eyepiece and one in the objective lens. The amount of light is changed by adjusting the diaphragm of the microscope. The diaphragm controls the amount of light that passes through the stage and is focused on the object being viewed.
There are two types of diaphragms in a microscope: the iris diaphragm and the disk diaphragm. The iris diaphragm is adjustable, while the disk diaphragm is preset. The iris diaphragm is located near the base of the microscope and can be adjusted to control the amount of light that enters the microscope. It works like a camera aperture, opening or closing to let in more or less light. When the iris diaphragm is closed, less light enters the microscope, and the image appears darker.
When the iris diaphragm is open, more light enters the microscope, and the image appears brighter. By adjusting the iris diaphragm, you can get the best possible image of the object being viewed. To summarize, the diaphragm is the part of the microscope that you adjust to change the amount of light. The iris diaphragm is adjustable, while the disk diaphragm is preset. By adjusting the diaphragm, you can get the best possible image of the object being viewed.
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Which of the following best defines energy?
the ability to do work
the resistance to motion
how fast an object moves
amount of force in a given time
Answer:
The Ability to do work
Explanation:
energy is needed to do work because without energy no work can be done due to the fact that there is no energy
Two spherical objects have masses of 1.5 x 10^5 kg and 8.5 x 10^2 kg. Their centers are separated by a distance of 2500 m. Find the gravitational attraction between them.
Answer:
1.36 x 10^(-9) N
Explanation:
The gravitational attraction between two objects can be calculated as
\(F=G\frac{m_1m_2}{r^2}\)Where G is a constant equal to 6.67 x 10^(-11) m³/kg·s², m1 and m2 are the masses of the objects and r is the distance between them. So, replacing the values, we get:
\(\begin{gathered} F=(6.67\times10^{-11})\frac{(1.5\times10^5)(8.5\times10^2)}{2500^2} \\ F=1.36\times10^{-9}N \end{gathered}\)Therefore, the gravitational attraction between them is 1.36 x 10^(-9) N
A
heat engine is measured to have 30% efficiency. Is the theoretical
efficiency going to be greater or less than that? Why?
The theoretical efficiency is greater than that of the actual efficiency of the engine. This is because heat engine always produces some waste heat.
The Second Law of Thermodynamics states that a heat engine cannot be 100% efficient. In practice, a heat engine is only 100% efficient when it is operating at about 30-50% efficiency.
If we were to multiply this by 100, we would get the efficiency as a percent: 49%. This is the theoretical maximum efficiency. If we were to actually build an engine, it would be less efficient than the theoretical engine. The theoretical engine that can achieve this theoretical maximum efficiency is called the Carnot Engine.
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force of 4 Newtons in 20 power output? 40 Nm/sec 2 Nm 2 Nm/sec 1
Answer:
P = 0.2 W
Explanation:
Given that,
Force, F = 4 N
Displacement, d = 1 m (say)
Time, t = 20 s
We need to find the power output. Power is the rate of doing work. So,
P = W/t
\(P=\dfrac{Fd}{t}\\\\P=\dfrac{4\times 1}{20}\\\\P=0.2\ W\)
So, the required power is 0.2 W.
what is mach number?
Mach number is "the ratio of the speed of a body to the speed of sound in the surrounding medium" (Oxford Languages). Put simply, it's a ratio comparing the local flow velocity to the speed of sound in the medium.
It is represented with the following formula. M is the mach number, u is the local flow velocity, and c is the speed of the sound in the medium.
\(\boxed{\displaystyle M=\frac{u}{c} }\)
a car accelerates uniformly from rest to 25 m/s over a distance of 30 meters. what is the acceleration of the car?
Answer:
a=25/24 m/s^2
Explanation:
I’m going to assume you mean the final velocity is 25m/s.
v^2=u^2+2as
625=0+2a300
a=25/24 m/s^2 or 1.0416^_ (period 1) ^m
The length of a soild of a metallic cube at 20°C is 5•0cm. Given that the linear expansivity of the metal is 4×^-5k^-1. Find the volume of the cube at 120°C. Find the volume of the cube at 120°C
Answer:
Explanation:
Length of one side of cube = 5 x 10⁻² m .
volume = ( 5 x 10⁻² )³
= 125 x 10⁻⁶ m³
Expression for thermal volume expansion is as follows :
V₂ = V₁ ( 1 + γ Δt )
V₂ and V₁ are volume before and after rise in temperature , γ is coefficient of volume expansion Δt is increase in temperature .
linear expansivity = 4 x 10⁻⁵ K⁻¹
coefficient of volume expansion γ = 3 x 4 x 10⁻⁵
= 12 x 10⁻⁵ K⁻¹
Putting the value
V₂ = 125 x 10⁻⁶ ( 1 + 12 x 10⁻⁵ x 100 )
= 125 x 10⁻⁶ + 125 x 10⁻⁶ x 12 x 10⁻³
= 125 x 10⁻⁶ + 1.5 x 10⁻⁶
= 126.5 x 10⁻⁶
= 126.5 cm³
3. An earthquake measures 3 on Richterscale:
(i)Would it be recorded by a seismograph ?
(ii)ls it likely to cause much damage ?
Answer:
Yes, it would be recorded by a seismograph. The earthquake with magnitude of 3 on Richter Scale is not likely to cause much damageIn mammals, the weight of the heart is approximately 0.5% of the total body weight. Write a linear model that gives the heart weight in terms of the total body weight. d)the weight of the heart of a whale whose weight is 2.402 × 105 lbs. Answer in units of lbs.
Answer:
1201 lbs
Explanation:
Given that in mammals, the weight of the heart is approximately 0.5% of the total body weight.
Let the weight of the heart of a mammal be H
And the weight of the total body be B
The linear model that can gives the heart weight in terms of the total body weight will be:
H = 0.005B
B.) To find the weight of the heart of a whale whose weight is 2.402 × 105 lbs, substitute the whole weight in the formula.
H = 0.005 × 2.402 × 10^5
H = 1201 lbs
Therefore, the weight of the heart of the whale is 1201 lbs
A converging mirror with a focal length of 7cm is held 4cm from your face. Determine the image location?
The image is approximately 9.33 cm away from the mirror, on the object's side.
To determine the image location formed by a converging mirror, we can use the mirror equation:
1/f = 1/d_o + 1/d_i
where:
f is the focal length of the mirror,
d_o is the object distance (distance of the object from the mirror), and
d_i is the image distance (distance of the image from the mirror).
In this case, the focal length (f) is given as 7 cm, and the object distance (d_o) is 4 cm.
Plugging in the values into the mirror equation:
1/7 = 1/4 + 1/d_i
To find the image distance (d_i), we can solve for it:
1/d_i = 1/7 - 1/4
1/d_i = (4 - 7) / (4 * 7)
1/d_i = -3 / 28
Taking the reciprocal of both sides:
d_i = 28 / -3
d_i ≈ -9.33 cm
The negative sign indicates that the image formed by the converging mirror is virtual and located on the same side as the object.
Therefore, the image is approximately 9.33 cm away from the mirror, on the object's side.
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Thermal expansion means ____as the temperature
a. More strength, increases
b. More atomic movement, decreases
c. Atomic attraction, increases
d. More atomic movement, increases
Answer: Thermal expansion is the tendency of matter to change its shape, area, volume, and density in response to a change in temperature, usually not including phase transitions.
Explanation:
Answer:
I believe the answer is c I believe not a 100% sure on this one.
Explanation:
Thermal expansion, the general increase in the volume of a material as its temperature is increased. ...
If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?
m/s2
Answer:
2ms-2
Explanation:
F = ma
a = F/m
= 0.5 / 0.25
= 2ms-2
Answer 2m/s^2
Explanation:
mass=0.25kg
Force =0.5N
Acceleration=force/ mass
Acceleration=0.5/0.25
Acceleration=2
Acceleration =2m/s^2
what is the relation between liquid pressure and density of liquid
plzz fast
Explanation:
Pressure due to the weight of a liquid of constant density is given by p=ρgh p = ρ g h , where p is the pressure, h is the depth of the liquid, ρ is the density of the liquid, and g is the acceleration due to gravity
Answer:Pressure due to the weight of a liquid of constant density is given by p=ρgh p = ρ g h , where p is the pressure, h is the depth of the liquid, ρ is the density of the liquid, and g is the acceleration due to gravity.
Explanation:
Among the reasons for the frequent use of composite measures is(are) that:
a. the researcher is seldom able to develop in advance single indicators of complex concepts.
b. a single data item might not have enough categories to provide a range of variation.
c. composite measures give a more comprehensive and accurate indication of a given variable.
d. they are efficient data reduction devices.
e. all of these choices.
Among the reasons for the frequent use of composite measures is that they give a more comprehensive and accurate indication of a given variable. Besides, the researcher is seldom able to develop in advance single indicators of complex concepts. A single data item might not have enough categories to provide a range of variation. And lastly, they are efficient data reduction devices.
So, the correct answer is option (e) all of these choices.
What are composite measures?Composite measures are used to combine several variables or scores into a single measurement or index. In other words, they are multidimensional measurement tools. It is useful to make this kind of index because it is possible to calculate the reliability and validity of composite measures, which are statistical measures that indicate whether or not the measurements were conducted accurately or are otherwise legitimate.
For example, if a researcher wants to assess the economic development of a country, he/she could create a composite measure by combining data on GDP per capita, literacy rates, and poverty rates. In this case, each of the three variables reflects a different aspect of economic development.
So, the correct answer is E.
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Ozzie estimates the weight of his cat to be 10 pounds. The actual weight of the cat is 7 pounds. Find
the percent error in his estimation.
Answer:
The percent error in his estimation is 30%
Explanation:
Percentage error = |UA- UE| \ UE × 100
UA= Actual value = 7 pounds
UE = Expected value = 10 pounds
Percent error of his estimate = ∣7-10∣ / 10 ×100
= ∣-3∣ / 10 × 100
= 30%
A hockey player skates across a rink of length 75m in 8.9 seconds. What is the average speed of the hockey player? The hockey player is moving at a speed of 9.5 m/s. If it takes him 2 seconds to come to a stop under constant acceleration, how far does he travel while stopping?
The average velocity is given by
\(v=\frac{d}{t}\)Where d is the distance covered and t is the time taken.
For the given case, we have
d = 75 m
t = 8.9 s
\(v=\frac{d}{t}=\frac{75}{8.9}=8.43\; \frac{m}{s}\)Therefore, the average speed of the hockey player is 8.43 m/s
The hockey player is moving at a speed of 9.5 m/s.
a 102-m wide river flows with a uniform speed of 3.2 m/s toward the east. it takes 14 minutes for a boat to cross the river to a point directly north of its departure point on the south bank. what is the speed of the boat relative to the water?
The speed of the boat relative to the water is 9.08 m/s, when the boat takes 14 minutes to cross the river.
We can decompose the velocity of the boat into two components: one parallel to the river, and one perpendicular to it. Let's call the parallel component \(v_p_a_r\) and the perpendicular component \(v_p_e_r_p\):-
\(v_p_a_r = v_b_o_a_t cos\theta\)
\(v_p_e_r_p = v_b_o_a_t sin\theta\)
The boat will travel a distance of 102 m across the river, which will take 14 minutes or 840 seconds. Therefore, the distance traveled parallel to the river will be:
\(d_p_a_r = v_p_a_r * t = v_b_o_a_t cos\theta * 840 s\)
The distance traveled perpendicular to the river will be:
\(d_p_e_r_p = v_p_e_r_p * t = v_b_o_a_t sin\theta * 840 s\)
The boat will end up at a point directly north of its departure point on the south bank, which means that \(d_p_e_r_p = 102 m\). Therefore, we can solve for \(v_b_o_a_t\) as follows:
\(v_b_o_a_t sin\theta * 840 s = 102 m\)
\(v_b_o_a_t sin\theta = 102 m / 840 s\)
\(v_b_o_a_t sin\theta = 0.1214 m/s\)
To solve for \(v_b_o_a_t\):-
\(tan\theta = d_p_a_r / d_p_e_r_p\)
\(tan\theta = (v_p_a_r * t) / (v_p_e_r_p * t)\)
\(tan\theta = v_p_a_r / v_p_e_r_p\\tan\theta = v_b_o_a_t cos\theta / (v_b_o_a_t sin(\theta))\\\)
Reserving the value of \(d_p_e_r_p\) and solving for \(\theta\):-
\(\theta = arctan(v_p_a_r / (102 m / 840 s))\\\theta = arctan(v_b_o_a_t cos(\theta) / 0.1214 m/s)\)
\(v_p_a_r^2 + v_p_e_r_p^2 = v_b_o_a_t^2\\(v_b_o_a_t cos(\theta))^2 + (v_b_o_a_t sin(\theta))^2 = v_b_o_a_t^2\)
\(v_b_o_a_t^2 (cos^2(\theta) + sin^2(\theta)) = v_b_o_a_t^2\\v_b_o_a_t^2 = 102^2 / (cos^2(\theta) + sin^2(\theta))\\v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]}\)
Reserving the value of \(\theta\):-
\(v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]} \\v_b_o_a_t = 9.08 m/s\)
Therefore, the speed of the boat relative to the water is 9.08 m/s.
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Which device transforms electrical energy to mechanical energy?
A. a fan
B. an iron
C. iPod
A power line carrying a current of 120 amps toward the east hangs 7.14 meters above a black squirrel on the ground directly below it. Calculate the magnitude of the magnetic field B, in tesla, at the squirrel's location. Express your answer in micro Tesla.
The magnitude of the magnetic field (B) at the squirrel's location is approximately 0.0574 μT (microtesla).
The magnetic field around a long, straight current-carrying wire can be calculated using Ampere's Law. The formula to calculate the magnetic field at a distance "r" from the wire is:
B = (μ0 * I) / (2π * r)
where:
B is the magnetic field
μ0 is the permeability of free space (4π × 10^(-7) T·m/A)
I is the current in the wire
r is the distance from the wire
Given:
Current (I) = 120 A
Distance from the wire (r) = 7.14 m
Substituting the values into the formula, we have:
B = (4π × 10^(-7) T·m/A * 120 A) / (2π * 7.14 m)
Simplifying the equation, we find:
B = (4π × 10^(-7) * 120) / (2 * 7.14)
B ≈ 0.0574 × 10^(-6) T
Converting to microtesla (μT), we get:
B ≈ 0.0574 μT
The magnitude of the magnetic field (B) at the location of the squirrel is approximately 0.0574 μT (microtesla).
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