Answer:
cell
Explanation:
here are all the symbols-
hope this helps, take care and stay safe
A parallel-plate capacitor has circular plates of 10 cm radius and a separation of 120 mm.
assume €0= 8,85 x 10^-12 F/m, 1m = 100cm and 1m = 1000mm
A parallel-plate capacitor with circular plates of 10 cm radius and a separation of 120 mm has a capacitance of 9.27 pF.
The capacitance of a parallel-plate capacitor is directly proportional to the area of the plates and inversely proportional to the separation between the plates. This is because the larger the area of the plates, the more charge can be stored on them.
The smaller the separation between the plates, the stronger the electric field between them, and the more charge can be stored. In this case, the capacitance is relatively small because the separation between the plates is relatively large. If the plates were brought closer together, the capacitance would increase.
This can be calculated using the following formula:
C = (epsilon_0 * A) / d
where:
* C is the capacitance in Farads
* epsilon_0 is the permittivity of free space (8.85 x 10^-12 F/m)
* A is the area of the plates in square meters
* d is the separation between the plates in meters
In this case, the area of the plates is pi * (10 cm)^2 = 78.54 square centimeters, and the separation between the plates is 0.12 m. Substituting these values into the formula, we get:
C = (8.85 x 10^-12 F/m * 78.54 square centimeters) / 0.12 m = 9.27 pF
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the gravitational potential energy of a ball is 20 J when the ball is dropped. If mechanical energy is conserved, which energies are possible for the ball as it falls
Taking into account the definition of kinetic, potencial and mechanical energy, the potential and kinetic energy are possible for the ball as it falls.
Kinetic energyKinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and at rest, until it reaches a given speed.
Potential energyOn the other hand, potential energy is the energy that measures the ability of a system to perform work based on its position. In other words, this is the energy that a body has at a certain height above the ground.
Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the force of gravity.
Mechanical energyFinally, mechanical energy is that which a body or a system obtains as a result of the speed of its movement or its specific position, and which is capable of producing mechanical work. Then:
Potential energy + kinetic energy = total mechanical energy
Principle of conservation of mechanical energyThe principle of conservation of mechanical energy indicates that the mechanical energy of a body remains constant when all the forces acting on it are conservative (a force is conservative when the work it does on a body depends only on the initial and final points and not the path taken to get from one to the other.)
Therefore, if the potential energy decreases, the kinetic energy will increase. In the same way, if the kinetics decreases, the potential energy will increase.
This caseThe gravitational potential energy of a ball is 20 J when the ball is dropped.
If principle of conservation of mechanical energy can be applied and the mechanical energy is conserved, the potential and kinetic energy are possible for the ball as it falls.
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What words experiences in Niels Bohrs life That led to his interest in science and the study of the atom
The words experiences in Niels Bohr's life that led to his interest in science and the study of the atom is he disliked writing essays and talented in mathematics.
What is atom?Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.
Neil Bohr loved talking, he had a disliking of writing essays. He was talented in mathematics. He then attracted to the sciences. Physics interested Neil and when he was a teenager, he started correcting the mistakes in his school's textbooks.
The contributions are present in the modern atomic model. They are: All matter consists of atoms. Atoms of the same element are the same in size and atoms of different elements are different. Atoms combine in whole-number ratios to form compounds.
Thus, Physics interested him to further study for atom.
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Across the northern part of our continent, many bodies of water are covered by a thick layer of ice for many months of the year. Which properties of water make it possible for life to continue to exist in those lakes? Water has a high specific heat in comparison to other substances. Water has a high solvent capacity for a variety of substances. Old water is denser than ice, so the ice floats to the top. a I only b I and II only c I and III only d I, II, and III
Answer:
Bbbbbbbbbbbbbb. bbbbbbbbbbbbbbb
The properties of water that makes it possible for life to continue to exist in lakes covered by a thick layer of ice for many months of the year are:
Water has a high specific heat in comparison to other substancesCold water is denser than ice, so the ice floats to the top.The correct option is C.
How does the water in frozen lakes support life?The water in frozen lakes supports life because of the following properties f water;
Water has a high specific heat in comparison to other substancesCold water is denser than ice, so the ice floats to the top.As soon as the water turns to ice, the ice loses a lot of its water-like density and continues to float on the lake's surface. Water loses density when it grows colder below 4° Celsius, forcing water that is about to freeze to float to the top.
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A car can go from 0 m/s to 38 m/s in 4.5 seconds. If a net force of 6570 N acted on
the car, what is its mass
The Mass of the car = 782.1 Kg
What is the mass of the car?The mass of the car is calculated as follows:
Mass = Force/ accelerationThe force on the car = 6570 N
The acceleration of the car, a = 38 - 0/4.5
acceleration = 8.44 m/s²
Mass of the car = 6570/8.44
Mass of the car = 782.1 Kg
In conclusion, the mass of the car is obtained from the acceleration and force on the car.
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Give me right solution with clear calculations
. Tourists arrive at the Manila Zoo at a rate of 250 vehicles per hour. But before entering the zoo, the vehicles must get a brochure and pay the entrance fee at the single entrance booth. If the vehicles can be serviced at a rate of 400 vehicles per hour, determine the percentage of time that the operator of the single entrance booth will be free.
Note: Round off your answers to the nearest thousandths. Only include the numeric value of vour answer without the unit (i.e. 0.123).
The percentage of time the operator of the single entrance booth will be free is approximately 38.462%.
To determine the percentage of time that the operator of the single entrance booth will be free, we need to calculate the service rate and the arrival rate. The service rate is given as 400 vehicles per hour, and the arrival rate is 250 vehicles per hour. The percentage of time the operator will be free can be calculated using the formula:
Free time percentage = (Service rate - Arrival rate) / Service rate * 100
Substituting the given values into the formula:
Free time percentage = (400 - 250) / 400 * 100
= 150 / 400 * 100
= 0.375 * 100
= 37.5%
Rounding off the answer to the nearest thousandths, the percentage of time the operator of the single entrance booth will be free is approximately 38.462%.
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Sn^4+ (1.5m) + Zn gives Sn^2+ (0.5m) + Zn^2+ (2m) Ecell = 0.80v , Calculate Ecell. Will the cell path increase or decrease if the concentration of Sn^4+ increases
Cell potential (Ecell) for the \(Sn^4^+ (1.5m) + Zn\) gives \(Sn^2^+ (0.5m) + Zn^2^+ (2m) Ecell = 0.80v\) is 0.80554 V. If the concentration of \(Sn^4^+\) increases, the cell potential Ecell will increase.
To calculate the cell potential (Ecell) for the given reaction involving \(Sn^4^+, Sn^2^+, Zn^2^+\), and Zn ions, we can use the Nernst equation:Ecell = E°cell - (0.0592 V/n) * log(Q),where E°cell is the standard cell potential, n is the number of electrons transferred in the reaction, and Q is the reaction quotient.Given the reaction:\(Sn^4^+ (1.5 M) + Zn \rightarrow Sn^2^+ (0.5 M) + Zn^2^+ (2 M),\)we can write the reaction equation as:\(Sn^4^+ + Zn \rightarrow Sn^2^+ + Zn^2^+.\)The coefficients in the balanced equation indicate the stoichiometry of the reaction, so we can determine the number of electrons transferred:n = 2.The reaction quotient Q can be calculated using the concentrations of the species involved:\(Q = [Sn^2^+][Zn^2^+]/[Sn^4^+][Zn].\)Plugging in the given concentrations, we have:Q = (0.5 M * 2 M)/(1.5 M * 1 M) = 0.67.Now, let's assume that E°cell is given as 0.80 V. Plugging the values into the Nernst equation:Ecell = 0.80 V - (0.0592 V/2) * log(0.67).Calculating the logarithm:log(0.67) ≈ -0.176Ecell ≈ 0.80 V - (0.0592 V/2) * (-0.176).Simplifying:Ecell ≈ 0.80 V + 0.00554 V.Ecell ≈ 0.80554 V.Therefore, the calculated cell potential (Ecell) for the given reaction is approximately 0.80554 V.Now, we need to determine whether the cell potential will increase or decrease if the concentration of \(Sn^4^+\) increases. Since \(Sn^4^+\) is on the anode side of the reaction, an increase in its concentration would cause a decrease in Q. According to the Nernst equation, a decrease in Q leads to an increase in Ecell. Therefore, if the concentration of \(Sn^4^+\) increases, the cell potential Ecell will increase.For more such questions on Cell potential:
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1. A 20 ohms resistor is connected in parallel with resistor " R " and the combination is then connected in series with 10 ohms resistor. Find the value of " R " if the equivalent total resistance between them is also equal to " R " ?
2.Two equal resistors R1 and R2 are connected in parallel. If the total voltage is equal to the total current, find R1 and R2 .
3. The resistance of a given electric device is 46 ohms at 25 0C. If the temperature coefficient of resistance of the material is 0.00454 at 20 0C determine the temperature of the device when its resistance is 92 ohms.
4. A electric motor operates 20 hours a day, 20 days a month, at an average output of 20 Hp. Calculate the cost of supplying this energy if the billing rate is constant at 1.5 cents per kwhr?
5.A coil of copper wire ( = 10.37 ) has a length of 600 feet. What is the length of an aluminum conductor ( = 17 ) if its cross-sectional area and resistance are the same ?
6.. Three resistors with values 1, 2 and 3 ohms respectively are connected in parallel. The combination is in series with 6 ohms resistor across a supply battery. The resistor that carries minimum current is
7. A electric motor operates 20 hours a day, 20 days a month, at an average output of 20 Hp. Calculate the cost of supplying this energy if the billing rate is constant at 1.5 cents per kw-hr.?
8.. A variable resistor R is connected in parallel with a 30 ohms resistor and the combination is connected in series with a 6 ohms across a 120 volts source. What are the values of R so that the power in it is equal to that of a 6 ohms resistor?
9. 8 ohms, 12 ohms and a variable resistor are connected in parallel. To what value in kilohm should resistor R be adjusted so that the power in 12 ohms resistor shall be 441 watts, if the total current is 20 amperes?
Explanation of electrical circuit and resistance-related questions.
Physics questions related to electrical circuits and resistors.The given set of questions focuses on different aspects of electrical circuits and resistance.
These questions require applying principles and formulas related to resistors in parallel and series, temperature coefficient of resistance, power calculations, and variable resistors.
By solving these questions, one can deepen their understanding of electrical circuit concepts and practice the application of relevant formulas.
Answering these questions helps to reinforce knowledge of circuit analysis, resistance calculations, and power considerations, which are fundamental in the study of electrical engineering and physics.
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an object that is accelerating may be
It must be either speeding up, or slowing down, or turning. There are no other possibilities.
How are solar flares different from solar prominences.
Answer:
What is the difference between a prominence and a solar flare? A prominence is a loop of cool incandescent gas that extends above the photosphere. A solar flare is an explosive release of energy that comes from the sun and causes magnetic ditrubances.
Explanation:
If one soccer ball is rolling to the right at 3 m/s and another soccer ball is rolling left with a speed of 5 m/s, how much momentum is there in this system before they collide with each other? Both have a mass of 1 KG
Answer:
Final momentum after a head on collision is -2kgm/
Explanation:
One ball moves to the right and the other moves opposite and momentum is a vector quantity so that considering the direction
Initial momenta are P₁=2x3=6kgm/s P₂=4x(-2)=-8kgm/s
Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s
Find the intervals where ℎ(x) = x^4 − 20x^3 − 144x^2 is concave up and concave down.
The function \(h(x) = x^4 - 20x^3 - 144x^2\) is concave up on the intervals (-∞, -4) and (5, ∞), and concave down on the interval (-4, 5).
To determine the intervals where ℎ(x) is concave up or concave down, we need to find the second derivative of the function. Let's start by finding the first derivative, ℎ'(x), which represents the slope of the function at any given point.
Taking the derivative of \(h(x) = x^4 - 20x^3 -144x^2\) with respect to x, we get \(h'(x) = 4x^3 - 60x^2 - 288x\).
Next, we find the second derivative, ℎ''(x), by taking the derivative of ℎ'(x). Differentiating \(h(x) = 4x^3 - 60x^2 - 288x\), we obtain \(h''(x) = 12x^2 - 120x - 288.\)
To determine the concavity of ℎ(x), we need to find the intervals where ℎ''(x) > 0 (concave up) and ℎ''(x) < 0 (concave down). Setting ℎ''(x) = 0 and solving for x, we get the critical points x = -4 and x = 5.
Now, let's analyze the intervals:
For x < -4, ℎ''(x) > 0, indicating concave up.
For -4 < x < 5, ℎ''(x) < 0, indicating concave down.
For x > 5, ℎ''(x) > 0, indicating concave up.
Therefore, the function \(h(x) = x^4 -20x^3 -144x^2\) is concave up on the intervals (-∞, -4) and (5, ∞), and concave down on the interval (-4, 5).
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how much force does an 87.0 kg astronaut exert on his chair while sitting at rest on the launch pad?
The amount of force exerted by an 87.0 kg astronaut on his chair while sitting at rest on the launch pad is 0 N.
When an object is at rest, it is not moving, and therefore, the net force acting on it is zero. This is known as the first law of motion, also known as the law of inertia.
The law of inertia states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity unless acted upon by an unbalanced force. Since the astronaut is sitting at rest, there is no net force acting on him, and therefore, the amount of force he exerts on his chair is zero.
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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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what is defination of uniform speed?
If an object of mass 70kg falls from a height of 500 m, what is the maximum velocity of the object?
Answer:
H = 1/2 * g * t^2 since initial velocity is zero
v = g * t where v is the final velocity
t = v / g
H = 1/2 g * v^2 / g^2 = 1/2 v^2 / g
v = (2 * H * g)^1.2
v = (2 * 500 * 9.8)^1/2 = 99 m/s
Check: t = v / g = 99 / 9.8 = 10.1 sec
H = 1/2 * 9.8 * 10.1^2 = 500 m
Mutations and New Traits. Before watching the video, list one or two questions you may have about mutations. Alternatively, you can list a few things you already know about mutations.
Answer:
No, there are multiple ways in which different mutations in the same gene can cause the same phenotype
Explanation:
Several different mechanisms of mutation can lead to the same phenotype. For example, lets say our phenotype is that flies have white eyes, and we know that this occurs in one particular gene that normally makes the eye colour red. (the red gene)
These mutations likely rendered the red gene ineffective (as the eyes are not red). However, this could happen in a variety of ways.
There could be a single base deletion in the first exon of the mRNA, changing the reading frame of the protein and messing up the entire sequence (a frame shift mutations)
The entire gene could be deleted
A single base could be substituted in an important site of the gene, for example, one which translates into a catalytic residue or binding site in the protein
There could be an inversion at the promoter region of the gene, such that a transcription factor can no longer bind to transcribe the gene.
There are countless other ways in which a mutation could have been caused. Therefore, just because we know the same gene is affected does not mean that we can assume the mutations are identical.
1. The temperature of the water in each of two beakers measures 50°C. One beaker contains 100 g of water, and the other beaker contains 250 g of water.
a. How does the amount of thermal energy in the two beakers compare? Explain your answer.
b. How does the average kinetic energy of the water molecules in the two beakers compare? How do you know?
1.Beaker A has less thermal energy than Beaker B
2.The water molecules in both beakers A and B have the same average kinetic energy
The temperature of the water in each of two beakers is same (50°C).
Beaker One contains (\(m_{1}\)) 100 g of water
Beaker Two contains (\(m_{2}\)) 250 g of water
Heat gained and lose by the object is depends on mass, change in temperature and specific heat.
Both beakers are made with same materials so their Specific heats and temperature are same .
Beaker B has more mass then Beaker A so Beaker A has less thermal energy than Beaker B.
2.The water molecules in both beakers A and B have the same average kinetic energy.
The temperature of an object is a measure of its internal energy. Thermal Energy is a form of Kinetic Energy because it is related to the Molecular Velocity.
When Temperature increases the velocity of the molecules ( increases or decreases) and the Kinetic Energy (increases or decreases) as Temperature decreases the velocity of the molecules ( increases or decreases) and the Kinetic Energy (increases or decreases).
so Kinetic Energy Depends on Velocity and Velocity depends on the Temperature in this problem Temperature are same so The water molecules in both beakers A and B have the same average kinetic energy.
what do you mean by Heat capacity of water?
It takes a lot of heat to increase the temperature of liquid water because some of the heat must be used to break hydrogen bonds between the molecules.
In other words, water has a high specific heat capacity, which is defined as the amount of heat needed to raise the temperature of one gram of a substance by one degree Celsius. The amount of heat needed to raise the temperature of 1 g water by 1 °C is has its own name, the calorie.
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How many electrons does a gallium-(2+) ion have?
2nd question
How many electronics does a Titanium-(2-) ion have?
Answer:
gallium ion has 31 electrons
titanium ion has 20 electrons
6. The tailgate of a moving van is 3.5 feet above the ground. A loading ramp is attached to the rear of the van at an incline of 10°. Find the length of the ramp to the nearest tenth of a foot. Draw
The length of the ramp to the nearest tenth of a foot is 20.7 feet.
Given that the tailgate of a moving van is 3.5 feet above the ground and a loading ramp is attached to the rear of the van at an incline of 10°.We are to find the length of the ramp to the nearest tenth of a foot. Here, the given angle of elevation is 10°.From the diagram, the length of the ramp is the hypotenuse of the right triangle, and the height of the ramp is the opposite side of the right triangle. The ground distance is the adjacent side of the right triangle. Using the trigonometric function of tan, we can find the length of the ramp. We know that tan 10° = opposite/adjacent. Hence, the opposite side = adjacent * tan 10°.Hence, length of the ramp = 3.5 / tan 10°≈20.7 ft. Therefore, the length of the ramp to the nearest tenth of a foot is 20.7 feet.
Length is an estimation, which distinguishes the distance between two focuses. It additionally gauges how long an article is, its level and its width. In math classes, children will learn about length to help them solve problems in real life and as part of the learning process.
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A rocket is launched from the surface of the earth with a speed of 9.0x103 m/s. What is the maximum altitude reached by the rocket? (MEarth=5.98x1024 kg, REarth=6.37x106 m)
From the Law of conservation of energy, we know that the sum of the kinetic and potential energy of the rocket is the same at the surface of the Earth and at the maximum altitude. Nevertheless, the kinetic energy of the rocket when it is at the maximum altitude is 0:
\(\begin{gathered} K_1+U_1=K_2+U_2 \\ K_2=0 \\ \Rightarrow K_1+U_1=U_2 \end{gathered}\)The kinetic energy is given by:
\(K=\frac{1}{2}mv^2\)On the other hand, the gravitational potential energy for big changes in altitude (comparable to the radius of the Earth) is given by the expression:
\(U=-\frac{GMm}{r}\)Where M is the mass of the Earth, m is the mass of the rocket, r is the distance from the center of the Earth to the rocket and G is the gravitational constant:
\(G=6.67\times10^{-11}N\cdot\frac{m^2}{\operatorname{kg}}\)At the beggining of the movement, the value of r corresponds to the radius of the Earth:
\(U_1=-\frac{GMm}{R_E}\)At the end of the movement, the value of r corresponds to the radius of the Earth plus the maximum altitude h:
\(U_2=-\frac{GMm}{R_E+h_{}}\)Substitute the expressions for U_1, K_1 and U_2 and simplify the equation by eliminating the factor m:
\(\begin{gathered} \frac{1}{2}mv^2-\frac{GMm}{R_E}=-\frac{GMm}{R_E+h} \\ \Rightarrow\frac{1}{2}v^2-\frac{GM}{R_E}=-\frac{GM}{R_E+h} \end{gathered}\)Isolate the term GM/(R_E+h):
\(\Rightarrow\frac{GM}{R_E+h}=\frac{GM}{R_E_{}}-\frac{1}{2}v^2\)Divide both sides by the factor GM:
\(\Rightarrow\frac{1}{R_E+h}=\frac{1}{R_E}-\frac{v^2}{2GM}\)Take the reciprocal to both sides of the equation:
\(\Rightarrow R_E+h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}\)Isolate h:
\(h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}-R_E\)Substitute the values of each variable: R_E=6.37x10^6m, M=5.98x10^24kg, G=6.67x10^-11 N*m^2/kg^2, and v=9.0x10^-3 m/s:
\(\begin{gathered} h=\frac{1}{\frac{1}{6.37\times10^6m}-\frac{(9.0\times10^3\cdot\frac{m}{s})^2}{2(6.67\times10^{-11}N\cdot\frac{m^2}{kg^2})(5.98\times10^{24}kg)}}-6.37\times10^6m \\ =18.03\times10^6m-6.37\times10^6m \\ =11.7\times10^6m \end{gathered}\)Therefore, the maximum altitude reached by a rocket with an initial speed of 9.0x10^3m is:
\(11.7\times10^6m\)A 350kg motorcycle is moving at 20m/s. It then speeds up to 30m/s. How much work did the engine do to accelerate?
Answer:
momentum= mass× velocity
=350kg (30-20) m/s
=3500kgm/s
A sled of mass 100. kg decelerates at 0.40 m/s² while coasting over the ice. Draw the free body diagram.
What is the "slowing" force of friction due to ice?
The slowing force of friction due to ice on the given sled on the ice is determined as 40 N.
Slowing force of friction due to ice
The slowing force of friction due to ice can be determined by using Newton's second law of motion as follows;
F = ma
where;
m is mass a is accelerationF = 100 x 0.4
F = 40 N
Thus, the slowing force of friction due to ice on the given sled on the ice is determined as 40 N.
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f the planet were orbiting a star twice as massive as our sun but still taking 3.862 years to orbit, how far would it be from its host star?
Distance-Related Data the distance between us and Proxima Centauri, the star closest to us, is still 40,208,000,000,000 km. Or around 268,770 AU.
Explain about the planet were orbiting a star?Exoplanets are planets that revolve around other stars. In our solar system, every planet revolves around the Sun. Exoplanets are extremely difficult to directly observe using telescopes.
One particular planetary system a star with planets surrounding it—is our solar system. Although there are more than 3,200 other stars in our galaxy with planets around them, our solar system is the only one that is formally referred to as a "solar system."
Surprisingly, our simulations reveal that a planet does not rapidly disintegrate inside of a red giant star or even modify its orbit—in certain situations, a planet continues to circle below a red giant star's photosphere for thousands or even millions of years.
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Strength training is beneficial because it decreases your risk of injury. Which statement BEST describes why this is true? A. Muscular fitness training can prevent or improve diabetes and sarcopenia. B. Muscular fitness training increases muscle mass, which increases your metabolism. C. Muscular fitness training strengthens tendons, ligaments, and cartilage. D. Muscular fitness training improves self-image and athletic performance. Please select the best answer from the choices provided. A B C D
Answer: B. Muscular fitness training increases muscle mass, which increases your metabolism
Determine the Relative Humidity, Dew Point, and Lifting Condensation Level: 1. The temperature is 30∘F and it contains 3.5 g/kg of water vapor. 2. The temperature is 50∘F and it contains 5.70 g/kg of water vapor. 3. The temperature is 70∘F and it contains 3.5 g/kg of water vapor. 4. The temperature is 80∘F and it contains 5.60 g/kg of water vapor. 5. The temperature is 80∘F and it contains 11.56 g/kg of water vapor. 6. The temperature is 30∘F and the mixing ratio is 3.5. 7. The temperature is 70∘F and the mixing ratio is 8.32. 8. The temperature is 70∘F and the mixing ratio is 3.66. 9. The temperature is 80∘F and the mixing ratio is 17.59. 10. The temperature is 50∘F and the mixing ratio is 6.54.
To determine the relative humidity, dew point, and lifting condensation level (LCL) for the given conditions, we can use the provided temperature and water vapor values.
Here are the calculations for each scenario:
1. Temperature: 30°F, Water Vapor: 3.5 g/kg - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
2. Temperature: 50°F, Water Vapor: 5.70 g/kg
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
3. Temperature: 70°F, Water Vapor: 3.5 g/kg - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
4. Temperature: 80°F, Water Vapor: 5.60 g/kg
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
5. Temperature: 80°F, Water Vapor: 11.56 g/kg - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
6. Temperature: 30°F, Mixing Ratio: 3.5
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
7. Temperature: 70°F, Mixing Ratio: 8.32 - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
8. Temperature: 70°F, Mixing Ratio: 3.66
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
9. Temperature: 80°F, Mixing Ratio: 17.59 - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)
- Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure) - LCL: N/A (Need the temperature and dew point)
10. Temperature: 50°F, Mixing Ratio: 6.54
- Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure) - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)
- LCL: N/A (Need the temperature and dew point)
To calculate the relative humidity, dew point, and LCL, we require
Learn more about relative humidity, here:
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What is the net force on this box?
100 N
80N
90 N
110
100 N
Answer:
where is the box? how can we answer if your question is lack given? how do we know what box is it your talking about
If an electron (with a charge of 1.6 x10−19c) Experiences a force of 500 N at a certain point in an electric field, then find the strength of the electric field in that location
Answer:
3.125×10²¹ N/C
Explanation:
Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C
Applying,
E = F/q.................. Equation 1
Where E = Electric Field, F = Force experienced, q = Charge of an electron.
From the question,
Given: F = 500 N, q = 1.6×10⁻¹⁹ C
Substitute these values into equation 1
E = 500/(1.6×10⁻¹⁹)
E = 312.5×10¹⁹
E = 3.125×10²¹ N/C
Explain how the shape of a river's stream bed can affect the river's speed and its power to cause erosion.
Answer:
Possiable answer by edge:
The shape of a river’s stream bed affects the speed and eroding power of a river by influencing the amount of friction between the water flowing through the river and the stream bed below. Friction is the force that opposes the motion of one surface as it moves across another surface. In a river, there is friction between the flowing water and the stream bed beneath it. Where a river is deep, less water comes into contact with the stream bed, so there is less friction. The reduced friction means there is less opposition to the water’s motion, so the river flows at a greater speed and has more kinetic energy for erosion. On the other hand, where a river is shallow, more water comes into contact with the stream bed, so there is more friction. The increased friction means there is more opposition to the water’s motion, so the river flows at a lesser speed and has less kinetic energy for erosion. Also, the roughness of a stream bed covered with boulders and other obstacles causes the water to flow through the river in a turbulent fashion. This could cause the river to move slower in some cases or erode more in other cases.
Explanation:
summary of answer:
influencing the amount of friction between the water flowing through the river and the stream bed below.
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Answer:
A
Explanation: