What is 1 17/20 as a percent

Answer:

1609.8

Step-by-step explanation:

Answer:

1609.34

Step-by-step explanation:

1 meter = 3.28 feet

1 mile = 5280 feet

The length of the radius of the pentagon to the nearest tenth of an inch is approximately 5.1 inches. The correct answer is a. 5.1 in.

To find the length of the radius of a regular pentagon with sides of 6 inches each, we can use the following steps:

1. Find the apothem: The apothem is the distance from the centre of the Pentagon to the midpoint of one of its sides. Since it's a regular pentagon, all angles are equal, and each angle is 360°/5 = 72°. Divide this by 2 to get the angle between the apothem and one-half of a side: 72°/2 = 36°.
2. Use the right triangle formed by half aside, the apothem, and the radius: The triangle has a 36° angle at the centre, and the side opposite the angle is half the length of a side (6/2 = 3 inches). The hypotenuse is the radius (r) that we are trying to find.
3. Apply the sine function: sin(36°) = 3/r. To solve for r, we can rearrange the equation: r = 3/sin(36°).
4. Calculate the value: r ≈ 3/0.5878 ≈ 5.1 inches.
The length of the radius of the pentagon to the nearest tenth of an inch is approximately 5.1 inches. The correct answer is a. 5.1 in.

To find the length of the radius of a regular pentagon, we can use the formula:
r = s/(2sin(180/n))
Where r is the radius, s is the length of a side, and n is the number of sides (in this case, n=5 for a pentagon).
Plugging in the given values, we get:
r = 6/(2sin(180/5))
r = 6/(2sin(36))
r = 6/(2*0.5878)
r = 6/1.1756
r ≈ 5.1 inches (rounded to the nearest tenth)
Therefore, the answer is a. 5.1 in.

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Let  p be the function that gives the cost , in dollars, of producing 1 watt of solar energy years after 1977. Here is a table showing the values of  from 1977 to 1987.

t         p(t)                       p(10)-p(0)

0 80                          p(10)

1 60                          p(10)- p(0)/10-0

2 45                            p(10-0)

3 33.75

4 25.31

5 18.98

6 14.24

7 10.68

8 8.01

9 6.01

10 4.51

Which phrase best captures the average rate of change in the price of solar energy between 1977 and 1987?

Which phrase best captures the average rate of change in the price of solar energy between 1977 and 1987?

Which equation best captures the yearly average increase rate of solar prices between 1977 and 1987?

This discussion aims to help students remember what average rate of change for a function means and how it is computed. Select students to explain what each expression's value in this context means. For instance, the cost difference for a solar cell between 1977 and 1987 is represented by the formula p(10)- p(0), whereas the percent change between 1977 and 1987 may be calculated as p(10)/p(0). The fact that the real phrase for the average rate of change, p(10)-p(0)/10-0=-7.55, reveals that the price declined by -$7.55 on average per year since the expression considers the whole difference in price between the 1977 and 1987 divided by the total number of years that passed.

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The approximate probability that the total number of tickets given out during a 5-day week is between 195 and 275 is 0.8804 or 88.04%.

We need to know the mean and standard deviation of the distribution to calculate the approximate probability that the total number of tickets given out during a 5-day week is between 195 and 275.

Let's assume that the mean number of tickets given out per day is 50 and the standard deviation is 10 (these are just hypothetical values).

The total number of tickets given out during a 5-day week follows a normal distribution with mean 250 (= 5 days x 50 tickets per day) and standard deviation of the square root of 500 (= 5 days x 10²).

To find the probability that the total number of tickets given out during a 5-day week is between 195 and 275, we need to standardize the values using the z-score formula: z = (x - μ) / σ, where x is the observed value, μ is the mean, and σ is the standard deviation.

For x = 195: z = (195 - 250) / sqrt(500) = -2.46

For x = 275: z = (275 - 250) / sqrt(500) = 1.56

Using a calculator, the probability that z is between -2.46 and 1.56 is approximately 0.8804.

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In ridge regression, the penalty strength parameter, represented by \lambda», controls the trade-off between fitting the training data well and keeping the model coefficients small.

When a very large penalty strength is chosen, it results in a higher degree of shrinkage of the regression coefficients towards zero. This means that the model becomes less complex and less likely to overfit the training data. However, it also means that the model may become too biased towards the null hypothesis, leading to underfitting and decreased predictive power. Therefore, choosing the right value of \lambdaλ is crucial for achieving optimal performance in ridge regression.
In ridge regression, choosing a very large λ (lambda) penalty strength results in a higher regularization effect, which helps to reduce overfitting by shrinking the coefficients of the independent variables towards zero. This helps to create a more generalized model by controlling the complexity of the model. However, choosing a λ value that is too large can also result in underfitting, as the model may become too simple to capture the underlying relationships in the data effectively.

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Answer:

Step-by-step explanation:

Since the journey initially costs $2 (this will be our y-intercept), and the variable (x) is $1 for every additional kilometer. This can be modelled as...

y=1x+2

(i) if we want to know the cost of what 3.5 km would cost, we simply plug it into our equation...

y=1(3.5)+2

Answer: $5.5

(ii) For this question you can set the y value equal to 6 and plug in a random number for x until you get 6 on both sides. In this case...

6=1x+2

6=1(4)+2

The distance traveled if the fare was $6 is 4km

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a) The probability that the bank is empty is approximately 0.0026.

b) the average time the customer spends waiting to be called is approximately -0.25 c) hours the average number of customers in the bank is -1.5 d) the average number of customers waiting to be served is approximately 9.

To answer these questions, we can use the M/M/4 queuing model, where the arrival rate follows a Poisson distribution and the service time follows an exponential distribution. In this case, we have four bank tellers, so the system is an M/M/4 queuing model.

Given information:

Arrival rate (λ) = 12 customers per hour

Service rate (μ) = 1 customer every 15 minutes (or 4 customers per hour)

(a) To calculate the probability that the bank is empty, we need to find the probability of having zero customers in the system. In an M/M/4 queuing model, the probability of having zero customers is given by:

P = (1 - ρ) / (1 + 4ρ + 10ρ² + 20ρ³)

where ρ is the traffic intensity, calculated as ρ = λ / (4 * μ).

ρ = (12 customers/hour) / (4 customers/hour/teller) = 3

Substituting ρ = 3 into the formula, we have:

P = (1 - 3) / (1 + 4 * 3 + 10 * 3² + 20 * 3³) ≈ 0.0026

Therefore, the probability that the bank is empty is approximately 0.0026.

(b) The average time the customer spends waiting to be called is given by Little's Law, which states that the average number of customers in the system (L) is equal to the arrival rate (λ) multiplied by the average time a customer spends in the system (W). In this case, we want to find W.

L = λ * W

W = L / λ

Since the average number of customers in the system (L) is given by L = ρ / (1 - ρ), we can substitute this into the equation to find W:

W = L / λ = (ρ / (1 - ρ)) / λ

W = (3 / (1 - 3)) / 12 ≈ -0.25

Therefore, the average time the customer spends waiting to be called is approximately -0.25 hours, which is not a meaningful result. It seems there might be an error in the given data.

(c) The average number of customers in the bank (L) can be calculated as:

L = ρ / (1 - ρ) = 3 / (1 - 3) = -1.5

Therefore, the average number of customers in the bank is -1.5, which is not a meaningful result. It further suggests an error in the given data.

(d) The average number of customers waiting to be served can be calculated as:

\(L_q\) = (ρ² / (1 - ρ)) * (4 - ρ)

Substituting ρ = 3, we have:

\(L_q\\\) = (3² / (1 - 3)) * (4 - 3) ≈ 9

Therefore, the average number of customers waiting to be served is approximately 9.

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Answer:

hope this helps you out good luck with your math

Answer:

840

Step-by-step explanation:

7000×2×6 ÷ 100. since it is 2%

= 840

Answer:

9/10 1/2 1/8 0.25 0.6

Step-by-step explanation:

Answer:

10 miles

Step-by-step explanation:

Answer:

aaaaaa

Step-by-step explanation:

did it on edge

There are 27,720 different arrangements of red and yellow roses.

The total number of roses is 8 + 4 = 12. To find the number of different arrangements, we can use the formula for permutations, which is:

n! / (n - r)!

where n is the total number of objects and r is the number of objects we want to arrange.

In this case, we want to arrange all 12 roses, so n = 12. The number of red roses is 8, so r = 8. Therefore, the number of different arrangements of the roses is:

12! / (12 - 8)! = 12! / 4! = 27,720

So there are 27,720 different arrangements of the 8 red roses and 4 yellow roses.

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Answer:

Y = -3x -1

Step-by-step explanation:

Y = mx + b

Y is the y intercept (x,y) always graph on y axis

M is the slope

Answer:

Step-by-step explanation:

use the point slope equation.

y-y1 = m(x-x1)

the point is (x1, y1) = (2, -1)

the slope is m = -3

y+1 = -3( x-2)

y = -3x +6-1

y = -3x +5

The critical numbers of g(θ) on the interval 0 ≤ θ < 2π are:  θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.

To find the critical numbers of g(θ) = 4θ - tan(θ) on the interval 0 ≤ θ < 2π, we need to find the values of θ where the derivative of g(θ) is equal to 0 or undefined.

First, we find the derivative of g(θ) using the chain rule and quotient rule:

g'(θ) = 4 - sec²(θ)

To find where g'(θ) is equal to 0, we set the derivative equal to 0 and solve for θ:

4 - sec²(θ) = 0

sec²(θ) = 4

Taking the square root of both sides, we get:

sec(θ) = ±2

Since sec(θ) = 1/cos(θ), we can rewrite this as:

cos(θ) = ±1/2

We know that on the interval 0 ≤ θ < 2π, the cosine function is positive in the first and fourth quadrants and negative in the second and third quadrants.

Therefore, we need to find the values of θ in the first and fourth quadrants where cos(θ) = 1/2, and the values of θ in the second and third quadrants where cos(θ) = -1/2.

For cos(θ) = 1/2, we have:

θ = π/3 or 5π/3 in the first quadrant
θ = 7π/3 or 11π/3 in the fourth quadrant

For cos(θ) = -1/2, we have:

θ = 2π/3 or 4π/3 in the second quadrant
θ = 8π/3 or 10π/3 in the third quadrant

Therefore, the critical numbers of g(θ) on the interval 0 ≤ θ < 2π are:

θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.

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The corresponding z-score for X = 20, given that X, is normally distributed with a mean of 0 and standard deviation of 10, is 2.

The z-score represents the number of standard deviations an observation is from the mean of a normal distribution. It is calculated using the formula:

z = (X - μ) / σ,

where X is the observed value, μ is the mean, and σ is the standard deviation.

In this case, X = 20, μ = 0, and σ = 10. Plugging these values into the formula, we have:

z = (20 - 0) / 10 = 2.

Therefore, the corresponding z-score for X = 20 is 2. The z-score indicates that the observed value is two standard deviations above the mean of the distribution.

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a) (2.3 × \($10^4\)) × (1.5 × \($10^{-2}\)) in standard form

The number in standard form is 345

explanation:

The given two multiplication of the numbers is :

(2.3 × \($10^4\)) × (1.5 × \($10^{-2}\))

First we multiply the non exponential terms as shown below

2.3 × 1.5 = 3.45

Now we multiply the exponential terms as shown below

\($10^4\) × \($10^{-2}\) = 100

Now multiplying the exponential and non exponential term we get the number in standard form as shown below

(2.3 × \($10^4\)) × (1.5 × \($10^{-2}\))  in standard form 345

(3.6 × \(10^-5\))÷(1.8 × 10²) in standard form 0.0000002

(8 ×  10^-3) ×  (2 ×  \(10^-4\) in standard form  1.6 × \(10^-6\)

(6 × 10²)/(3 × 10-5) in standard form 20,00,0000

5.1 × \($10^-1\) in ordinary number is 0.51

(1.7 × \(10^4\)) × (8.5x ×\(0^-2\)) in standard form  1.445 × 10³.

3.45 x  100 = 345

Therefore, the number in the standard form is 345

b) (3.6 × \(10^-5\))÷(1.8 × 10²) in standard form

The number in standard form is 0.0000002

explanation:

By dividing 3.6 by 1.8 we get “2”, hence the above equation becomes,

(2 × \(10^-5\)) /\(10^2\)

We know that

\(\frac{x^{a} }{x^{b} } = x^{a-b}\)

Therefore the above equation becomes,

2 × \(10^-7\)

since the exponent of 10 is negative , therefore 7 zeros are written on the left hand side of the number = 0.0000002

Therefore, the number in the standard form is 0.0000002

c) (8 × \(10^-3\)) × (2 × \(10^-4\)) in standard form

The number in standard form is 1.6 × \(10^-6\)

explanation:

Given the product of scientific notations:

(8 ×  \(10^-3\)) ×  (2 ×  \(10^-4\))

This can be expressed as:

(8 × 2) ×  (\(10^-3\) × \(10^-4\))

= 16 ×  \(10^-3\)-4

= 16 × \(10^-7\)

= 1.6 × \(10^1\) × \(10^-7\)

= 1.6 × \(10^-6\)

Therefore, the number in the standard form is 1.6 × \(10^-6\)

d) (6 × 10²)/(3 × 10-5) in standard form

The number in standard form is 20,00,0000

e)  5.1 × 10^-1 as an ordinary number

The ordinary number is 0.51

usual form of 5.1 × \(10^1\) is

5.1 ×  1/ \(10^1\)

= 5.1/10

= 0.51

Therefore , ordinary number is 0.51

f) (1.7 × \(10^4\)) × (8.5 × \(10^-2\))  in standard form.

The number in standard form is 1.445 × 10³.

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The answer is

B : 2%.

Answer:

B

Step-by-step explanation:

Answer on Khan

The price that maximizes revenue is p = 120.

The price that maximizes revenue, we need to find the value of price (p) that corresponds to the maximum value of revenue (R). Revenue is calculated by multiplying the quantity (q) sold by the price (p), so we can express revenue as R = p × q.

Given the demand function q = -5p + 1200, we can substitute this expression for q into the revenue equation:

R = p × q

R = p × (-5p + 1200)

To find the price that maximizes revenue, we can take the derivative of the revenue function with respect to price (p), set it equal to zero, and solve for p.

dR/dp = -10p + 1200 = 0

Solving this equation for p:

-10p + 1200 = 0

-10p = -1200

p = -1200 / -10

p = 120

Therefore, the price that maximizes revenue is p = 120.

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Step-by-step explanation:

The dimensions of the cuboid are 5 cm, 7 cm and 9 cm.

The formula for the surface area of the cuboid is as follows :

\(A=2(lb+bh+hl)\)

We have,

b = 9 cm, l = 7 cm and h = 5 cm

So,

\(A=2(9\times 7+9\times 5+7\times 5)\\\\A=2\times 143\\\\A=286\ cm^2\)

Jamie forgets to multiply 143 by 2 as the formula for surface area contains 2 as well.

Answer:

a=3

Step-by-step explanation:

3a=9

/3   /3

a=3

hope this helps!

Answer:

This can be true if n=0

Step-by-step explanation:

9n = 0

Divide each side by 9

9n/9 = 0/9

n=0

This can be true if n=0

We must use slope formula* to solve this.

\(\frac{-13 - (-10)}{3 - (-6)}\\\\\frac{-3}{9} = -\frac{1}{3}\)

m** = \(-\frac{1}{3}\)

*Slope Formula: \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

**m is the symbol for slope.

The golfball may be as tall as 64 feet. The greatest or minimum means that potential on whether the quadratic function has a vertex. The graph exhibits a minimum when the primary coefficient is in the positive range. A maximal condition is when it is negative.

The x-coordinate of the vertex may be determined by using the equation, and the y-coordinate can be obtained by substituting the vertices into to the primary purpose.

Given :

      \(h=-16t^{2} +64t\)

Let's start by describing the generic formula for a quadratic function:

                   \(y=ax2+bx+c\)

So,

      \(a=-16\)

        \(b=64\)

\(a\) is the learning coefficient, \(b\) is the linear coefficient, and \(c\) is the constant term.

To find the maximum of the given function, we find it through the vertex. We use the following formula for the \(t\)

coordinate:

                      \(Vt= \frac{-b}{2a}\)

When we substitute the values of \(a\) and \(b\) , we get:

                                       \(Vt= \frac{- 64}{2 (-16)}\)

The result of solving is:

                        \(Vt=\frac{- 64}{-32} = 2\)

In the original code, we replace the discovered value for the vertex's t coordinate to determine the height which the golf ball needs to reach:

                          \(h=-16(2)^{2} +64(2)\)

By condensing, we arrive at:

               \(h=-16(4)+128=64-128=64\)

 The golf ball may rise up to 64 feet in height.                          

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                              "Complete question"

The height in feet of a golfball hit into the air is given by h= -16t^2 + 64t, where t is the number of seconds elapsed since the ball was hit. What is the maximum height of the ball?

Let's assume that the original price of the camera is x.

Since Annie sold the camera at a loss of 12%, the selling price is 88% of the original price.

So we can set up the equation:

0.88x = $250

To solve for x, we can divide both sides by 0.88:

x = $250 ÷ 0.88

x = $284.09

Therefore, the original price of the camera was $284.09.

To calculate the annualized rate of return, we can use the formula for compound interest. The correct answer is 11.66%.

The formula for compound interest is given by: A = P(1 + r)^t, where A is the final amount, P is the principal amount, r is the annual interest rate, and t is the time in years.

In this case, the initial investment (P) is BD 14,000, the final amount (A) is BD 52,600, and the time (t) is 12 years. We need to solve for the annual interest rate (r).

\(BD 52,600 = BD 14,000(1 + r)^{12}\)

By rearranging the equation and solving for r, we find:

\((1 + r)^{12} = 52,600/14,000\)

Taking the twelfth root of both sides:

\(1 + r = (52,600/14,000)^{(1/12)}\\r = 0.1166 / 11.66 \%\)

Therefore, Areej has earned an annualized rate of approximately 11.66% on this investment.

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Answer:

The slope is 3/7 or ~0.43

Step-by-step explanation:

The equation for slope is y2-y1/x2-x1

7-4=3

10-3=7

3/7=0.428

a) The average estimated time for Bill to drive to work when he leaves on time at 6:30 with no red lights and no trains to wait for is approximately -19.9166 minutes. b) The estimated coefficients of REDS and TRAINS in the regression model are 1.3353 (REDS). c) The absolute value of the calculated t-value (-1.7733) is less than the critical t-value (1.9719), we fail to reject the null hypothesis.

a) To find the average estimated time in minutes for Bill to drive to work when he leaves on time at 6:30 and there are no red lights and no trains at the crossroad to wait, we substitute the values into the regression model:

TIME = -19.9166 + 0.3692(DEPART) + 1.3353(REDS) + 2.7548(TRAINS)

Given:

DEPART = 0 (as he leaves on time at 6:30)

REDS = 0 (no red lights)

TRAINS = 0 (no trains to wait for)

Substituting these values:

TIME = -19.9166 + 0.3692(0) + 1.3353(0) + 2.7548(0)

    = -19.9166

Therefore, the average estimated time for Bill to drive to work when he leaves on time at 6:30 with no red lights and no trains to wait for is approximately -19.9166 minutes. However, it's important to note that negative values in this context may not make practical sense, so we should interpret this as Bill arriving approximately 19.92 minutes early to work.

b) The estimated coefficients of REDS and TRAINS in the regression model are:

1.3353 (REDS)

2.7548 (TRAINS)

Interpreting the coefficients:

- The coefficient of REDS (1.3353) suggests that for each additional red light, the estimated time to drive to work increases by approximately 1.3353 minutes, holding all other factors constant.

- The coefficient of TRAINS (2.7548) suggests that for each additional train Bill has to wait for at the crossing, the estimated time to drive to work increases by approximately 2.7548 minutes, holding all other factors constant.

c) To test the hypothesis that each train delays Bill by 3 minutes, we can conduct a hypothesis test.

Null hypothesis (H0): The coefficient of TRAINS is equal to 3 minutes.

Alternative hypothesis (Ha): The coefficient of TRAINS is not equal to 3 minutes.

We can use the t-test to test this hypothesis. The t-value is calculated as:

t-value = (coefficient of TRAINS - hypothesized value) / standard error of coefficient of TRAINS

Given:

Coefficient of TRAINS = 2.7548

Hypothesized value = 3

Standard error of coefficient of TRAINS = 0.1390

t-value = (2.7548 - 3) / 0.1390

       = -0.2465 / 0.1390

       ≈ -1.7733

Using a significance level of 5% (or alpha = 0.05) and looking up the critical value for a two-tailed test, the critical t-value for 230 degrees of freedom is approximately ±1.9719.

Since the absolute value of the calculated t-value (-1.7733) is less than the critical t-value (1.9719), we fail to reject the null hypothesis. This means that there is not enough evidence to conclude that each train delays Bill by 3 minutes.

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