A. For z = 0.50 = 66; B. For z = -0.25 = 57 and the probability of randomly selecting a score less than z = -0.25, you can use a standard normal (z-score) table or calculator. For z = -0.25, the probability is approximately 0.4013, meaning there's a 40.13% chance of randomly selecting a score less than z = -0.25.
To find the X value for each z-score, we use the formula:
X = u + (z * a)
where u is the mean, a is the standard deviation, and z is the z-score.
A. For z = 0.50:
X = 60 + (0.50 * 12)
X = 66
Therefore, the X value for z = 0.50 is 66.
B. For z = -0.25:
X = 60 + (-0.25 * 12)
X = 57
Therefore, the X value for z = -0.25 is 57.
To find the probability of randomly selecting a score that is less than z = -0.25, we use a z-table or a calculator that can calculate normal distribution probabilities. The probability of a score being less than z = -0.25 is the same as the area under the curve to the left of z = -0.25.
Using a z-table, we find that the probability of a score being less than z = -0.25 is 0.4013.
Therefore, the probability of randomly selecting a score that is less than z = -0.25 is 0.4013 or approximately 40.13%.
A. For z = 0.50:
To find the X value, use the formula X = μ + (z * σ), where μ is the mean and σ is the standard deviation.
X = 60 + (0.50 * 12) = 60 + 6 = 66
B. For z = -0.25:
X = 60 + (-0.25 * 12) = 60 - 3 = 57
To find the probability of randomly selecting a score less than z = -0.25, you can use a standard normal (z-score) table or calculator. For z = -0.25, the probability is approximately 0.4013, meaning there's a 40.13% chance of randomly selecting a score less than z = -0.25.
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Graph the line y=-3x+b if its graph goes through the given point.
B(5,2)
The equation of the line y = -3x + 17 would have a graph that is shown in the diagram attached below.
How to Graph the Equation of a Line?Given that the line y = -3x + b goes through the point B(5, 2), it means that the slope (m) of the line would be -3, while the line would intercept the y-axis at b.
To find the value of b, substitute (x, y) = (5, 2) into y = -3x + b:
2 = -3(5) + b
2 = -15 + b
2 + 15 = b
17 = b
b = 17
Thus, the equation of the line y = -3x + 17 would have a graph that is shown in the diagram attached below.
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how many yards are in 8.2 Miles?
Answer:
14432 yards I hop this helps
What is the sum of the interior angles of a polygon that has 9 sides?
Answer:
1260 degrees
Step-by-step explanation:
All methods used for visualizing distributions are based on which of the following? Choose the correct answer below.
A. Make a mark that indicates how many times each value occurred in the data set.
B. Make a histogram of the data.
C. Pick a graph and summarize the data using that graph.
D. Make a dotplot of the data.
B. Make a histogram of the data.It can also be used to detect outliers and to compare distributions of different data sets.
A histogram is a type of graph used to visualize the distribution of a given set of data. It is created by plotting the frequency of occurrence of each data point on a graph, with the x-axis representing the data points and the y-axis representing the frequency of occurrence. The height of the bar above each data point indicates how often the value appears in the data set. The shape of the histogram gives an indication of the underlying distribution of the data. By plotting the frequency of occurrence of each data point, a histogram can provide insights into the mean, median, mode, and other characteristics of the data set. It can also be used to detect outliers and to compare distributions of different data sets.
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new similarity measures of intuitionistic fuzzy sets based on the {jaccard} index with its application to clustering
Develop similarity measures by applying the Jaccard index formula to the membership degrees of the fuzzy sets and use these measures for clustering objects based on their fuzzy characteristics.
The question is asking about new similarity measures of intuitionistic fuzzy sets based on the Jaccard index and their application to clustering.
To answer the question, first, let's understand what fuzzy sets and clustering are. Fuzzy sets are a generalization of classical sets where an element can have a degree of membership ranging between 0 and 1. Clustering, on the other hand, is a technique used to group similar objects together based on their characteristics.
Now, the question specifically mentions the Jaccard index as a basis for similarity measures. The Jaccard index is a measure of similarity between two sets, which is calculated as the ratio of the intersection of the sets to the union of the sets.
To develop new similarity measures for intuitionistic fuzzy sets based on the Jaccard index, you can apply the Jaccard index formula to compare the membership degrees of the elements in the fuzzy sets. The resulting similarity measure will provide a quantitative value indicating the degree of similarity between the sets.
These new similarity measures can then be applied to clustering. In clustering, the similarity measures between objects are used to determine the groupings. By utilizing the Jaccard index-based similarity measures for intuitionistic fuzzy sets, you can cluster objects based on their fuzzy characteristics and similarities.
In summary, the question asks about new similarity measures of intuitionistic fuzzy sets based on the Jaccard index and their application to clustering. To answer this, you can develop similarity measures by applying the Jaccard index formula to the membership degrees of the fuzzy sets and use these measures for clustering objects based on their fuzzy characteristics.
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You buy a computer for $3000. It depreciates at the rate of 20% per year. Find the value of the computer after 5 years
The value of the computer after 5 years is $960
Given that the computer was bought at $3000 and it depreciates at the rate of 20% per year
We can calculate the value of the computer using the formula below;P = A(1 - r)^nwhere; P is the final value of the computer, A is the initial amount, r is the depreciation rate and n is the number of years
Hence, substituting the given values into the formula above,P = $3000(1 - 0.20)^5P = $3000(0.80)^5P = $3000(0.32768)P = $983.04
SummaryThe value of the computer after 5 years is $960.
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If the vertex of a parabola is (4,-6), what is the axis of symmetry?
Answer:
x = 4
Step-by-step explanation:
Tekan-Tekan Sdn. Bhd. has order for 200 Model AS-120 calculator for delivery on day 200. The calculator consists of three parts. Components 2 and 3 form subassembly 1 . Sub-assembly 1 and component 4 form the final assembly. Following are the work centers and times of each operation. Table Q3(a) shows routine file of the operation. Assuming: - Only one machine is assigned to each operation - The factory works on 8-hour shift, 5 days a week - All parts move in one lot of 200. (a) Illustrate the backward schedule based on the information given above. (12 marks) (b) Identify when component 3 must be started to meet the delivery date. (2 marks)
Component 3 must be started on day 197 to meet the delivery date of day 200.
To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.
(a) Backward schedule:
Operation | Work Center | Time (hours) | Start Day
--------------------------------------------------------
Final Assembly | Work Center 1 | 1 | 200
Sub-assembly 1 | Work Center 2 | 2 | 199
Component 4 | Work Center 3 | 3 | 197
Component 2 | Work Center 4 | 4 | 196
Component 3 | Work Center 5 | 3 | ????
(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.
From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.
Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.
Hence, component 3 must be started on day 197 to meet the delivery date of day 200.
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consider the equation n=2/5m-30 for what value of m is n equal to 50?
Answer:
m = 200
Step-by-step explanation:
Substitute n = 50 in the equation
n = 2/5m - 30
50 = 2/5m - 30
50 + 30 = 2/5m
80 = 2/5m
m = 80 ÷ 2/5
m = 200
3. You purchase a car using a $30,000 loan with a 6% simple interest rate.
(a) Suppose you pay the loan off after 6 years. How much interest do you pay on your loan? Show your work.
(b) Suppose you pay the loan off after 3 years. How much interest do you save by paying the loan off sooner? Show your work.
Answer:
(1) if the loan is paid off after 6 years, the interest paid on the loan is $10,800. (2) $5,400 in interest will be conserved if the debt is repaid in 3 years as opposed to 6 years.
What, using an illustration, is simple interest?Simple Interest (S.I.) is a technique for figuring out how much interest will accrue on a specific initial sum of money at a certain rate of interest. For instance, if someone borrows Rs. 5000 at a cost of ten p.a. for 2 years, they will pay S.I. on the loaned money for those two years.
(a) Using the straightforward interest calculation, we can determine the amount of interest paid on the debt if it is repaid after six years:
I = Prt
where P represents the loan's capital, r represents the interest rate, and t represents the quantity of time (in years).
P is $30 000, r is 6%, and t is 6 years in this example. With these numbers entered into the algorithm, we obtain:
I = 30,000 * 0.06 * 6 = $10,800
Therefore, if the loan is paid off after 6 years, the interest paid on the loan is $10,800.
(b) To calculate the interest saved by paying off the loan after 3 years instead of 6 years, we can calculate the interest paid in both scenarios and then subtract the interest paid at 3 years from the interest paid at 6 years.
If the loan is paid off after 3 years, the total interest paid can be calculated using the same formula as before:
I = 30,000 * 0.06 * 3 = $5,400
By deducting the interest costs at 3 years from of the interest charged at 6 years, we can determine the amount of interest that would have been paid had the debt been repaid after 3 years:
Interest saved = Interest paid at 6 years - Interest paid at 3 years
= 10,800 - 5,400
= $5,400
Therefore, $5,400 in interest will be conserved if the debt is repaid in 3 years as opposed to 6 years.
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I need help with my homework
What is the area of the following circle?
Answer:
49pi
Step-by-step explanation:
Area of a circle is diameter * 1/2 squared times pi. Then, ((14 * 1/2)^2)pi equals 49pi.
P.S: don't cheat in khan my man, that's dishonored
express 8cm as fraction of 2metres.
Answer:
4/200 is the answer
The steps to derive the quadratic formula are shown below: Step 1 ax2 + bx + c = 0 Step 2 ax2 + bx = − c Step 3 x2 + b over a times x equals negative c over a Step 4 x2 + b over a times x plus b squared over 4 times a squared equals negative c over a plus b squared over 4 times a squared Step 5 x2 + b over a times x plus b squared over 4 times a squared equals negative 4 multiplied by a multiplied by c, all over 4 multiplied by a squared plus b squared over 4 times a squared Step 6 Provide the next step to derive the quadratic formula. x plus b over 2 times a equals plus or minus b squared minus 4 times a times c all over the square root of 4 times a squared x plus b over 2 times a equals plus or minus b minus 2 times a times c all over square root of 2 times a x plus b over 2 times a equals plus or minus the square root of the quantity b squared minus 4 times a times c all over the square root of 4 times a squared x plus b over 2 times a equals plus or minus the square root of the quantity b squared minus 4 times a times c all over the square root of 2 times a
Answer:
\(x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}\)
Step-by-step explanation:
Step 1:
\(ax^2+bx+c = 0\)
Step 2:
\(ax^2+bx = -c\)
Step 3:
\(\frac{ax^2+bx}{a} = \frac{-c}{a}\)
Step 4:
Adding \(\frac{b^2}{4a^2}\) to both sides to complete the square
\(x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-c}{a} + \frac{b^2}{4a^2}\)
Step 5:
\(x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-4ac+b^2}{4a^2}\)
Step 6:
Taking square root on both sides
\(x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}\)
Answer:
A. Rewrite the perfect square trinomial as a binomial squared on the left side of the equation
Step-by-step explanation:
Consider the function.
f(x) = x2 + 3
Which answer pairs a possible domain restriction that if placed upon f(x) would impact f–1(x) as shown?
Answer:
b
Step-by-step explanation:
edge 2021
The solution is:
B. f(x) domain: x ≥ 1
f–1(x) range: y ≥ 1
What is function?Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable.
Here, we have,
Because the two functions are inverse to each other, so we all know that the domain of f(x) will be the range of f^-1(x) and the range of f(x) will be the domain of f^-1(x)
As can be seen from the attached photo,
f(x) extends to the right of x=1, so its domain is x ≥ 1.
<=> f^-1(x) range is y≥ 1.
Therefore, we choose answer B
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complete question:
Which answer pairs a possible domain restriction for f(x) and its corresponding impact on f-1(x)
Write 230,000,000,000 in scientific notation.
Answer:
4?
Step-by-step explanation:
on a certain standardized test, the mean is 180 and the standard deviation is 35. which of the following is within 2 standard deviations of the mean?
Any value between 110 and 250 is within 2 standard deviations of the mean. In other words, any data point between 110 and 250 is considered within this range.
Within 2 standard deviations of the mean refers to the range that includes data points within two units of standard deviation from the mean. In this case, the mean is 180 and the standard deviation is 35.
To find the range within 2 standard deviations of the mean, we need to calculate the upper and lower bounds.
The upper bound can be found by adding 2 standard deviations (2 * 35 = 70) to the mean: 180 + 70 = 250.
The lower bound can be found by subtracting 2 standard deviations (2 * 35 = 70) from the mean: 180 - 70 = 110.
Therefore, any value between 110 and 250 is within 2 standard deviations of the mean. In other words, any data point between 110 and 250 is considered within this range.
It's important to note that this answer is specific to the given mean and standard deviation. If the mean and standard deviation were different, the range within 2 standard deviations would also be different.
Always calculate the upper and lower bounds based on the provided mean and standard deviation to determine the range within 2 standard deviations accurately.
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find the distance between the spheres x^2+y^2+z^2=4 and x^2+y^2+z^2=4x+4y+4z-11
The distance between the sphere x² + y² + z² = 4; x² + y² + z² - 4x - 4y - 4z + 11 is sqrt(12) - 5.
We can solve the above problem in the following steps:Step 1: Write the equation of both spheres in the general form .
Step 2: Find the center of both spheres by completing the square.
Step 3: Calculate the distance between the centers of both spheres
Step 4: Subtract the radius of both spheres from the above distance to get the required distance.
Step 1: Equation of the spheresx² + y² + z² = 4.............(1)x² + y² + z² - 4x - 4y - 4z + 11 = 0... (2)
Step 2: Find the center of both spheres
Completing the square in equation (1):x² + y² + z² = 4Add +1 on both sides to complete the square:x² + y² + z² + 0x - 0y - 0z = 4 + 1
Completing the square, we get:(x - 0)² + (y - 0)² + (z - 0)² = √5²Completing the square in equation (2):x² + y² + z² - 4x - 4y - 4z + 11 = 0
Move the constant term to RHS:x² - 4x + y² - 4y + z² - 4z = -11Add +4 and +4 on LHS to complete the square:x² - 4x + 4 + y² - 4y + 4 + z² - 4z + 4 = -11 + 4 + 4
Completing the square, we get:(x - 2)² + (y - 2)² + (z - 2)² = 9
Step 3: Calculate the distance between the centers of both spheres. Center of sphere (1) = (0, 0, 0)Center of sphere (2) = (2, 2, 2)Distance between the centers of both spheres = sqrt((2 - 0)² + (2 - 0)² + (2 - 0)²) = sqrt(12)
Step 4: Subtract the radius of both spheres from the above distance to get the required distance.
Radius of sphere (1) = sqrt(4) = 2Radius of sphere (2) = sqrt(9) = 3Required distance = sqrt(12) - 2 - 3 = sqrt(12) - 5Thus, the distance between the given spheres is sqrt(12) - 5.
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Scenario 2 Magnifi Co. produces a high-end amplifier for musical aficionados. Historically, only 85% of the 200 amplifiers produced per month on average have met the company's demanding standards for
Scenario 2 Magnifi Co. produces a high-end amplifier for musical aficionados. Historically, only 85% of the 200 amplifiers produced per month on average have met the company's demanding standards for quality control. Suppose a random sample of 50 amplifiers is taken from a month's production..
What is the probability that less than 40 of the amplifiers will meet the company's quality standards? b) What is the probability that between 40 and 45 inclusive of the amplifiers will meet the company's quality standards? c) What is the probability that more than 45 of the amplifiers will meet the company's quality standards? a) In order to solve for the probability that less than 40 amplifiers will meet the company's quality standards, we can use the binomial distribution formula: P(X < 40) = Σi=0^39 C(50, i) (0.85)i(1-0.85)50-i
This can be solved using a computer, calculator, or by using a binomial probability table. Using a binomial table, we can find that P(X < 40) = 0.024. Therefore, there is a 0.024 probability that less than 40 amplifiers will meet the company's quality standards. b) To solve for the probability that between 40 and 45 amplifiers inclusive will meet the company's quality standards, we can use the binomial distribution formula again. We need to solve for P(40 ≤ X ≤ 45): P(40 ≤ X ≤ 45) = Σi=40^45 C(50, i) (0.85)i(1-0.85)50-i This can also be solved using a computer, calculator, or binomial table. Using a binomial table, we can find that P(40 ≤ X ≤ 45) = 0.435. Therefore, there is a 0.435 probability that between 40 and 45 amplifiers inclusive will meet the company's quality standards. c) To solve for the probability that more than 45 amplifiers will meet the company's quality standards, we can use the binomial distribution formula one more time. We need to solve for P(X > 45): P(X > 45) = Σi=46^50 C(50, i) (0.85)i(1-0.85)50-i Once again, this can be solved using a computer, calculator, or binomial table. Using a binomial table, we can find that P(X > 45) = 0.056. Therefore, there is a 0.056 probability that more than 45 amplifiers will meet the company's quality standards.Overall, it can be concluded that the probability that less than 40 amplifiers will meet the company's quality standards is low, the probability that between 40 and 45 amplifiers inclusive will meet the company's quality standards is relatively high, and the probability that more than 45 amplifiers will meet the company's quality standards is relatively low.
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Please help me
Solve the following system of equations and show all work.
Please show all work
Answer:
-1/2 and -1
Step-by-step explanation:
Our system of equations is:
y = 2x²
y = -3x - 1
We can set the y's equal to each other:
y = 2x² = -3x - 1
Now, we have:
2x² = -3x - 1
Move all the terms to one side by adding both sides by 3x and 1:
2x² + 3x + 1 = 0
We must factor this quadratic. Note that the factoring is:
(2x + 1)(x + 1) = 0
Our solutions are now:
2x + 1 = 0 OR x + 1 = 0
x = -1/2 x = -1
.
Thus, our solutions are -1/2 and -1.
) let x be an exponential random variable. then, its mean and its standard deviation are equal. true or false?
False. The mean and the standard deviation of an exponential random variable are not equal.
An exponential random variable has a probability density function given by:
\($f(x) = \lambda e^{-\lambda x}$ for $x > 0$\)
where\($\lambda > 0$ i\)s the rate parameter.
Mean for exponential random variable:
\($\frac{1}{\lambda}$\)
Standard deviation for exponential random variable:
\($\frac{1}{\lambda}$\)
Thus, the mean and the standard deviation of an exponential random variable are not equal, and they have different values depending on the value of \($\lambda$\)
It is important to note that exponential random variables have a memoryless property, which means that the future behavior of an exponential random variable is independent of its past values. This property makes exponential random variables useful for modeling various real-world phenomena such as the time between failures in reliability engineering or the time between events in a Poisson process.
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7x-7=2x-2 what is the answer
Answer:
x = 1
Step-by-step explanation:
7x-7=2x-2
5x = 5
x = 1
Please help it’s graded and I just don’t want to fail
Answer:
630/49
Step-by-step explanation:
a balloon is being fileld with helium at the rate of 4 ft^3/min. the rate, in square fee per minute, at which the surface area in increaisng when the volume 32pi/3 ft^3 is
The volume of the balloon is 32π/3 ft³, and the rate at which the surface area is increasing is 16π square feet per minute.
The volume V of a balloon is given as V = (4/3)πr³, where r is the radius of the balloon.
Differentiating both sides of the equation concerning time t, we get
dV/dt = 4πr²(dr/dt).
Here, dV/dt represents the rate at which the volume is changing, which is 4 ft³/min as given in the problem.
the volume is 32π/3 ft³, we can substitute these values into the equation
4 = 4πr²(dr/dt)
To simplifying, we have
r²(dr/dt) = 1/π
The surface area A of a balloon, we can use the formula
A = 4πr².
Differentiating both sides of the equation concerning time t, we get dA/dt = 8πr(dr/dt).
We need to find dA/dt when V = 32π/3 ft³.
From the volume formula, we know that V = (4/3)πr³. Setting V = 32π/3, we can solve for r
(4/3)πr³ = 32π/3
r³ = 8
r = 2
Now, substitute r = 2 into the equation for dA/dt
dA/dt = 8π(2)(dr/dt)
Substituting the value of dr/dt from earlier
dA/dt = 8π(2)(1/π)
dA/dt = 16π
Therefore, when the volume of the balloon is 32π/3 ft³, the rate at which the surface area is increasing is 16π square feet per minute.
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Does the problem involve permutations or combinations? Do not solve. From 8 names on a ballot, a committee of 5 will be elected to attend a political national convention. How many different committees are possible?
Answer: Combination
There are 56 committees possible
============================================
Explanation:
The reason why we know we'll use a combination (instead of a permutation) is because order does not matter. There are no ranking positions on a committee. No one person has a special job compared to the other. The ordering of a committee doesn't matter. All that matters is the entire group itself. For instance, if we had people A,B,C then the committee ABC is the same as CBA and BAC. We would have to introduce a different person, say person D, to get a new committee group.
We have n = 8 people overall to choose from and r = 5 slots to fill. Use the combination formula to get
\(_n C _r = \frac{n!}{r!*(n-r)!}\\\\_8 C _5 = \frac{8!}{5!*(8-5)!}\\\\_8 C _5 = \frac{8!}{5!*3!}\\\\_8 C _5 = \frac{8*7*6*5!}{5!*3!}\\\\_8 C _5 = \frac{8*7*6}{3!}\\\\_8 C _5 = \frac{8*7*6}{3*2*1}\\\\_8 C _5 = \frac{56*6}{6}\\\\_8 C _5 = 56\\\\\)
We can conclude there are 56 different committees possible.
30 in
16 in
21 in
19 in
The area is
in²
The area of the shape (Trapezium) is 392 in².
What is area?Area is the region bounded by a plane shape.
To calculate the area of the shape (Trapezium), we use the formula below
Formula:
A = (a+b)h/2..................... Equation 1Where:
A = Area of the shapea, b = Pair of the parallel sidesh = Height of the trapeziumFrom the question,
Given:
a = 30 inb = 19 inh = 16 inSubstitute these values into equation 1
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What is a value in math
Help meeeee lleaseeeee :))
Answer:
a
Step-by-step explanation:
Worth 60 points for a rapid reply- find the area of each regular polygon. Answers are rounded to the nearest whole number.
The area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.
How to calculate for the area of the polygonArea of regular polygon = 1/2 × apothem × perimeter
perimeter = (s)side length of octagon × (n)number of side.
apothem = s/[2tan(180/n)].
11 = s/[2tan(180/12)]
s = 11 × 2tan15
s = 5.8949
perimeter = 5.8949 × 12 = 70.7388
Area of dodecagon = 1/2 × 11 × 70.7388
Area of dodecagon = 389.0634 in²
Area of pentagon = 1/2 × 5.23 × 7.6
Area of pentagon = 19.874 in²
Therefore, the area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.
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How many partial tables will be produced if a researcher controlled for gender? a. One. b. Four. c. Two. d. Three
The answer is c. Two.
When a researcher controls for gender, it means that the data is analyzed separately for each gender category. This approach allows the researcher to examine the relationship between variables while accounting for the potential differences between genders. By creating two separate groups based on gender (male and female), the researcher can analyze and compare the data within each group.
Therefore, controlling for gender will result in two partial tables, one for each gender category. Each partial table will contain the data specific to that gender, allowing for gender-specific analysis and comparisons. This approach enables the researcher to understand any variations or patterns that may exist within each gender group.
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