Answers
Answer:
137.8 N
Explanation:
First we need to find the acceleration of the sprinter. To do so, we can use the Torricelli's equation:
V^2 = Vo^2 + 2*a*S
9^2 = 2^2 + 2*a*25
81 = 4 + 50a
50a = 77
a = 77/50 = 1.54 m/s2
Now, to find the resulting force in the sprinter, we can use the following equation:
Force = mass * acceleration
Force = 70 * 1.54 = 107.8 N
If we have a 30 N force against the sprinter, the total force applied is:
Resulting force = Applied force - Wind force
107.8 = Applied force - 30
Applied force = 137.8 N
Related Questions
A 39.4 kg beam is attached to a wall with a link and its far end is supported by a cable such that the angle between the beam and the cable is 90 degrees. If the beam is inclined at an angle of theta = 33.1 degrees with respect to horizontal, what is the magnitude of the horizontal component of the force exerted by the link on the beam?
Answers
Answer:
192.6N
Explanation:
Let's consider the forces acting on the beam:
Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.
Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.
Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.
Let's break down the forces acting on the beam:
Vertical forces:
W (weight of the beam) - T (vertical component of tension) = 0
T = W
Horizontal forces:
F_link (horizontal component of the force exerted by the link) = ?
To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.
Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:
F_link = W * sin(θ)
Let's substitute the given values:
W = 39.4 kg * 9.8 m/s^2
θ = 33.1 degrees
F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)
Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.
deduce an expression, in terms of m, c, and V, for the contribution of P to the pressure exerted on W. Refer to appropriate Newton’s laws of motion.
Answers
The expression for the contribution of P to the pressure exerted on W is P = mV/(c^2t), derived using Newton's laws of motion and the definition of pressure.
In order to deduce an expression, in terms of m, c, and V, for the contribution of P to the pressure exerted on W, we can use the appropriate Newton’s laws of motion. Specifically, we can use the equation F = ma, where F represents force, m represents mass, and a represents acceleration.We know that pressure (P) is defined as force per unit area, or P = F/A. Rearranging this equation, we can solve for force: F = PA.Substituting this into the equation F = ma, we get PA = ma. Rearranging this equation, we can solve for pressure in terms of mass and acceleration: P = ma/A. Finally, we know that acceleration can be expressed in terms of velocity (V) and time (t): a = V/t.Substituting this into our equation for pressure, we get P = mV/(At). Since c represents the speed of sound, we can express A as \(A = c^2\). Therefore, our final expression for the contribution of P to the pressure exerted on W is:\(P = mV/(c^{2t})\)In summary, we used the equation F = ma, the definition of pressure (P = F/A), and the relationship between acceleration (a), velocity (V), time (t), and the speed of sound (c) to deduce an expression for the contribution of P to the pressure exerted on W in terms of m, c, and V.For more questions on pressure
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Which of the following describes the role of C6H12O6 in the Calvin cycle?
Answers
Answer:
C6H12O6 is the final product of Calvin cycle light independent reactions
Explanation:
* steps in Calvin cycle
: carbon fixation
: reduction
: regeneration
for C6H12O6 it requires 2 molecules of PGAL or G3P
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A person takes a trip, driving with a constant speed of 98.5 km/h, except for a 20.0-min rest stop. The person's average speed is 68.8 km/h. (a) How much time is spent on the trip? h (b) How far does the person travel? km
Answers
Answer:
Total time taken(T) = 1.1 hour
Distance = 75.68 km
Explanation:
Given:
Average speed = 68.8 km/h
Constant speed = 98.5 km/h
Rest time = 20 min = 20 / 60 = 0.3333 hour
Find:
Total time taken(T)
Total distance (D)
Computation:
Distance = speed × time
D = 68.8 × t.........Eq1
and
D = 98.5 × [t-0.33]
D = 98.5 t - 32.8333.........Eq2
From Eq1 and Eq2
68.8 t = 98.5 t - 32.83333
29.7 t = 32.83333
t = 1.1
Total time taken(T) = 1.1 hour
Distance = speed × time
Distance = 68.8 × 1.1
Distance = 75.68 km
vector A has a magnitude of 8unit Victor has a magnitude of 80 units and makes angle of 45° with the Positive x-axis Vector B has the same magnitude of 8 unit anddirected a long the negative x-axis alon find the magnitude and direction of A+B.
Answers
Part: a
First let's represent each vector on a grid.
When we combine vectors visually, we connect the tip (arrow side) of one vector to the tail (non-arrow side) of the other. The vector is then drawn from the beginning point to the final position.The graphical representation of the sum of vectors \($\vec{A}$\)and \($\vec{B}$\) is:[See attachment]
Part: b
The graphical representation \($\vec{A}-\vec{B}$\) is: [See attachment]
What is Vectors?
Vectors are things that have a magnitude as well as a direction. They may be represented numerically by a number expressing the magnitude and an angle representing the magnitude. They can also be represented visually, with addition and subtraction.A vector is a number that defines not only the size of an object but also its movement or location with respect to another point or object. It is sometimes referred to as a Euclidean vector, a geometric vector, or a spatial vector.The length of the segment of the directed line is known as the magnitude of a vector in mathematics, and the angle at which the vector is slanted displays the vector's direction.Learn more about vector https://brainly.com/question/13322477
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How to solve the question, pls ignore my answer ? I don't know how to finsih
Answers
The final velocity of the puck, v, is determined as 3 m/s.
What is the impulse received by the puck?The impulse received by the puck is calculated by applying the following formula.
impulse received = change in momentum of the puck = area under the curve
Area under the curve = area of triangle
Area of triangle = ¹/₂ x b x h
where;
b is the base = ( 5 ms - 2 ms) = 3 ms = 0.003 sh is the height = 160 NArea = ¹/₂ x 0.003 s x 160 N
Area = 0.24 Ns
Therefore, impulse (J) = change in momentum (ΔP) = 0.24 Ns
The final velocity of the puck is calculated as follows;
m(vf - vi) = ΔP
where;
vf is the final velocity of the puckvi is the initial velocity of the puckm is the mass of the puckLet vf be in positive direction,
then vi will in negative direction
0.03 kg(vf - (-5 m/s)) = 0.24 Ns
vf + 5 = 0.24/0.03
vf + 5 = 8
vf = 8 - 5
vf = 3 m/s
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The earth rotates on its axis with a period of 24 hours. What is the frequency in Hertz?
Answers
Answer:
The answer is 0.042 Hz (rounded)
or 0.0417 Hz
Explanation:
Hope it helps
Answer:
The answer is 0.041Hz
Explanation:
The answer is 0.041Hz
I guess
a rectangle has a length of (2.8+-0.2) m and a width of (1.2+-0.2) m. calculate the area and perimeter of the rectangle, and give the uncertainty in each value
Answers
Answer:
AREA = 3.6
PERIMETER = 7.2
UNCERTAINTY of Area = 3.0m
UNCERTAINTY of Perimeter = 7.0m
Explanation:
Formula for Area = length • width
(2.8 + -0.2)m • (1.2 + -0.2)m
= 2.6m^2
Formula for Perimeter:
2 • (length + width)
= 7.2m
UNCERTAINTY: round numbers to their correct significant figures.
A charged Adam or particle is called a
Answers
Answer:
A charged atom or particle is called an ion :)
A cellphone emits a radio signal with a frequency of 1910 MHz. Determine its wavelength
Answers
The wavelength of the radio signal, λ = 1.57 m.
Equation :To find the wavelength we use the formula,
fλ = c
where,
f is frequency of radio signal
c is speed of light
λ is wavelength
So,
The known values are :
frequency = 1910 MHz
speed of light = 3 x 10⁸ m/s
λ = ?
By rearranging the formula we get,
λ = c / f
Putting values,
λ = 3 x 10⁸ m/s / 1910 MHz
λ = 3 x 10⁸ m/s / 1.91 x 10⁸ Hz
λ = 1.57 m
What is wavelength and frequency?The wavelength, which will also apply to troughs, is the separation between two wave crests. The frequency is measured in cycles per second (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz). In this article, the relationship between wavelength and frequency is covered.
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A 1500-kg car moving at 20 m/s strikes a truck waiting at a traffic light, hooking bumpers. The two continue to move together at 5 m/s. What was the mass of the truck
Answers
Answer:
The mass of the truck is 6000kg
What is the SI unit that is equal to 0.01 meters?
Answers
Answer:one centimeter is equal to one hundredth of a meter (1 cm = 0.01 m).
Explanation:
The brick wall (of thermal conductivity 0.77 W/m ·◦ C) of a building has dimensions of 4.3 m by 5 m and is 19 cm thick.How much heat flows through the wall in a 7.7 h period when the average inside and outside temperatures are, respectively, 29◦C and 4◦C?Answer in units of MJ.
Answers
Given:
The thermal conductivity of the wall, k=0.77 W/(m·°C)
The dimensions of the wall, 4.3 m by 5 m
Thus the area of the wall, A=4.3×5=21.5 m²
The thickness of the wall, d=19 cm=0.19 m
The time period, t=7.7 h=7.7×3600=27720 s
The temperature inside the building, T₁=29 °C
The temperature outside the building, T₂=4 °C
To find:
The amount of the heat that flows through the wall in 7.7 h
Explanation:
The amount of the heat lost through the wall is given by,
\(Q=\frac{ktA(T_1-T_2)}{d}\)On substituting the known values,
\(\begin{gathered} Q=\frac{0.77\times27720\operatorname{\times}21.5\operatorname{\times}(29-4)}{0.19} \\ =60.38\times10^6 \\ =60.38\text{ MJ} \end{gathered}\)Final answer:
The heat that flows through the wall in the given time period is 60.38 MJ
A. 65-year old emmetrope wearing +2.50D readers has a near point of accommodation of 25cm.what is his near point of accommodation without glasses? B. The patient above wishes to have glasses for reading material at 50cm. what should the appropriate power of the reading spectacles be?
Answers
If he does not use the lenses, his near point will be 66.7 cm. For him to read a material at 50 cm, he has to use a lens of 2.0D.
What is the near point?The near point is the nearest area which a person can see or have distinct vision. The focal length of the lens is f = 100/2.5 = 40cm
Then;
1/40 = -1/v + 1/25
1/v = 1/25 - 1/40
v = 66.7 cm
Also, for the purpose of reading at 50 cm
1/f = -1/50 + 1/25
1/f = 1/25 - 1/50
f = 50cm
The power of this lens is;
100/50 cm = 2 D
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Which of the following represents an example of thermal energy?
O a
Saxophone
Ob
Oven
с
Powerlines
Od
Windmill
Answers
Answer:
The answer of this question is windmill
Why are S-H bonds longer than O-H bonds?
Answers
Answer: S-H bonds are typically longer than O-H bonds because sulfur is larger than oxygen. The size difference between the two atoms means that the electrons in the bond are farther apart in an S-H bond, resulting in a longer bond length. Additionally, sulfur is less electronegative than oxygen, which means that the electrons in the bond are less strongly attracted to the sulfur atom and are therefore more likely to be found in the region between the two atoms, further increasing the bond length.
Explanation:
Answer:
Describe the differences between the O-H and S-H bond lengths. Due to its stronger shielding, which lessens the nuclear pull for the bonding electrons and causes a longer bond length, sulfur is a bigger atom than oxygen.
Explanation:
A dog accelerates at 1.50 m/s2 to reach a velocity of 13.5 m/s while covering a distance of 49.3 m. What was his initial velocity?
Answers
Let v be the dog's initial velocity. Then
(13.5 m/s)^2 - v ^2 = 2 (1.50 m/s^2) (49.3 m)
==> v ^2 = (13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m)
==> v = √((13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m))
==> v ≈ 5.86 m/s
2. A 7 kg. Mass is moved across the table at 25 m/sec. What force caused the acceleration?
Answers
A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.
To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
Given:
Mass (m) = 7 kg
Acceleration (a) = 25 \(m/s^2\)
We can substitute these values into the equation:
Force (F) = mass (m) * acceleration (a)
F = 7 kg * 25 \(m/s^2\)
F = 175 kg·\(m/s^2\)
Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).
To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).
By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)
In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.
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3 A rocket of mass 1200 kg is travelling at 2000 m/s. It fires its engine for 1 minute. The forward thrust provided by the rocket engines is 10 kN (10 000 N).
(i) Use increase in momentum = F x t to calculate the increase in momentum of the rocket.
(ii) Use your answer to a to calculate the increase in velocity of the rocket and its new velocity after firing the engines.
Answers
The impulse shared by the object equals the difference in momentum of the object. In equation form,
F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.
How to calculate thrust provided by the rocket engines is 10 kN (10 000 N).?
a)There is this impulse-momentum change equation.
\(where m$ is the mass of a body, $F$ is a force acting to the body, $t$ is time and $D E L A T A N\}=V_{2}-V_{1}$ is the change of velocity.We consider everything is happen along a straight line, and gravitation does not participate.So, the increase of momentum is $\mathrm{F}^{*} \mathrm{t}=10000 \mathrm{~N} * 60$ seconds $=600000 \mathrm{~N}^{*} \mathrm{~s}=600000\left(\mathrm{~kg}^{*} \mathrm{~m}\right)^{*} \mathrm{~s} / \mathrm{s}^{\wedge} 2=600000 \mathrm{~kg}{ }^{*} \mathrm{~m} / \mathrm{s}$.\)
We consider everything exits happen along a straight line, and gravitation does not participate.
So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.
\($$\Delta(\mathrm{V})=\frac{\mathrm{F.t}}{\mathrm{m}}=\frac{600000}{1200}=500 \mathrm{~m} / \mathrm{s} .$$\)
New velocity after engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.
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After initially picking the stone up off the ground, a man exerts a 148 N force upwards on a 10 kg stone. What is the acceleration of the stone?
Answers
Answer:
5m/s²
Explanation:
The force exerted on an object is calculated using the formula ;
F = ma
Note that the upward force (F) is 148N
Where;
F = force (N)
m = mass (kg)
a = acceleration (m/s²)
The downward force towards gravity is F' = mg
F' = 10 × 9.8m/s²
F' = 98N
Net force (F - F') = m × a
148 - 98 = 10 × a
50 = 10a
a = 50/10
a = 5m/s²
solve the quadratic equation: 5x²-2x-25=0
Answers
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
Answers
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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What color is a mirror, Is mirror a color?
Answers
Mirror isn't a color, it's a reflection of you.
Answer:
It is not a color but a reflection
Explanation:
force is measured by: a) ammeter b) spring balance c) two pan balance d) ruler
Answers
Answer:
force can also be considered as weight so
Spring balance is used for measuring Force.
Explanation:
What does density show? Explain.
Answers
Answer:
What is Density? The density of material shows the denseness of that material in a specific given area. A material's density is defined as its mass per unit volume. Density is essentially a measurement of how tightly matter is packed together.
Explanation:
Answer:
The density of material shows the denseness of that material in a specific given area. A material's density is defined as its mass per unit volume. Density is essentially a measurement of how tightly matter is packed together.
An airplane flies east with a velocity of 150 km/h. It encounters a tail wind of 30 km/h. How fast is the airplane traveling? (convert answer in m/s)
Answers
Answer:
50 m/s
Explanation:
Hi.
just for little clarification, I'd explain what a tail wind is, if you don't mind.
A tail wind is a wind that moves in the direction of the aircraft. If an aircraft is moving in a direction northwards, then a tail wind is also a wind moving northwards.
Now to the question, the airplane is flying at, 150 km/h with a tail wind of 30 km/h.
The airplane's speed is then,
150 + 30 = 180 km/h
And to convert to m/s, we have
180 km/h = 180 * 1000/3600 m/s
180 km/h = 50 m/s
A student pushes a 6.0-kg box to the right with a
constant force FSB. The box moves at a constant velocity. The box experiences a
friction force f from the floor.
a. What type of friction does the box experience? Explain your reasoning.
b. Identify the four forces acting on the box.
Answers
b. The four forces acting on the box are:
1. Force of gravity (weight), which acts downwards towards the center of the earth, and has a magnitude of mg, where m is the mass of the box and g is the acceleration due to gravity.
2. Normal force, which is the force exerted by the floor on the box, perpendicular to the surface of contact, and has a magnitude of mg when the box is at rest or moving at a constant velocity.
3. Force applied by the student, denoted as FSB, which is directed to the right and has a magnitude that is equal to or greater than the force of friction.
4. Force of friction, denoted as f, which opposes the motion of the box and is directed to the left, opposite to the direction of the applied force. The magnitude of the frictional force is equal to the magnitude of the force applied by the student, as long as the box is moving at a constant velocity.
Which situation does NOT show kinetic energy? *
PLS ANSWER ASAPPPP
Answer options:
A. a hockey puck sliding on the ice
B. a baseball in a catcher's glove
C. a lady walking slowly across the street
D. a man running around a track
Answers
"Kinetic" energy is the energy of motion.
The ball in the glove is not moving. It's just laying there. (B)
So it has no kinetic energy.
All the other choices describe something moving, so they all have some.
A radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm. (a) Find the angular speed of the blade in rad/min. Incorrect: Your answer is incorrect. webMathematica generated answer key rad/min (b) Find the linear speed of the sawteeth in ft/s. Incorrect: Your answer is incorrect. webMathematica generated answer key ft/
Answers
Answer:
The angular speed of the blade is of 166.67 rad/min
If a radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm then the angular speed of the blade would be 104.72 rad/seconds.
What is speed?
The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
speed = total distance /Total time
As given in the problem If a radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm then we have to find the angular speed of the blade,
the angular speed of the blade (ω) = 2πN/60
=2×π×1000/60
= 104.72 rad/seconds
Thus, the angular speed of the radial saw would be 104.72 rad/seconds
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A scientist observes rock masses that have moved past each other in opposite horizontal directions. Which feature
does the scientist observe?
A. plateau
B. syncline
C. strike-slip fault
D. fault-block mountain
Answers
Answer:
C. strike-slip fault
Explanation:
The scientist must have observed a strike- slip fault.
A fault is an evidence of brittle deformation of the crust in the presence of applied stress on earth materials. Here, the earth material is the rock subjected to tension.
Where a fault occurs, there must have been movement between two blocks of rocks. The direction of movement helps us to delineate the fault type.
When two blocks moves past each other horizontally, it is a strike-slip fault like rubbing your palms together. When a block moves in the direction of the dip, it forms a dip-slip fault which results in a fault-block mountain characterized by graben and horst systems.Option A, Plateau is a table landform usually a mountain with flat peak.
Option B is a bowl shaped stratigraphic pattern in which the youngest sequence is at the core of the strata or a fold.
So, the most fitting option is C, a strike-slip fault.
Answer:
Explanation:
c