Two radio antennas A and B radiate in phase. Antenna B is a distance of 140 m to the right of antenna A. Consider point Q along the extension of the line connecting the antennas, a horizontal distance of 40.0 m to the right of antenna B. The frequency, and hence the wavelength, of the emitted waves can be varied.
a) What is the longest wavelength for which there will be destructive interference at point ?
b) What is the longest wavelength for which there will be constructive interference at point ?
Answers
Explanation:
a) 120m
b) since Q is the first order constructive interference, the distance between mid point of antennas and Q is 0.5 wavelengths (appear in A-Level question). so the wavelength should be (2)(30) =60m
60m
Related Questions
You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30 A , even for an instant.
What is the largest root-mean-square current you can run through this bulb?
Answers
Answer:
about 0.919 amp
Explanation:
\(I_r_m_s=\frac{I_m_a_x} {\sqrt{2}}\\ I_r_m_s=\frac{1.3}{\sqrt{2}}\\I_r_m_s\approx 0.919 amp\)
Tom applied 10 000J of heat energy to four (4) metals A, B, C and D. All the metals were of the same mass and were initially at the same temperature. After heating the metals the temperature change was noted as shown in the table below. Metal 9 A.25 B.35 C.10 D.15 Which of these four (4) metals has the highest heat capacity?
Answers
The metal with the highest heat capacity between metals A.25 B.35 C.10 and D.15 is metal A.
How to determine heat capacity?Heat capacity is the amount of heat required to raise the temperature of a substance by one degree Celsius. Metal A has a heat capacity of 400 J/kg°C, which means that it takes 400 joules of heat to raise the temperature of one kilogram of metal A by one degree Celsius.
Metal B has a heat capacity of 285.7 J/kg°C, metal C has a heat capacity of 1000 J/kg°C, and metal D has a heat capacity of 666.7 J/kg°C. Therefore, metal A has the highest heat capacity of the four metals.
Metal A's high heat capacity means that it can absorb a lot of heat without its temperature changing very much. This makes metal A a good material for things like heat sinks and thermal insulation.
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Which of the following statements is true? Thunderstorms are not dangerous The eye of a hurricane is the most danger Tornadoes form when wind change all of the above
honestly they all seem wrong to me but it's not giving me another option hurry if possible
Answers
Answer:
False
Explanation:
includess lighting and powerful winds over 50Mph,creates hail and causes flash flooding and also tornadoes
prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?
Answers
Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.
Why should cars be maintained and / or serviced ?First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.
The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.
This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.
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A car goes 20 mph to 10 mph in five seconds find its acceleration
Answers
Explanation;
Acceleration = change in velocity / time
Acceleration = (final velocity - initial velocity )/time
Acceleration = (v - u)/t
Given: u = 20 miles per hour, v = 10 miles per hour
t = 5 seconds
Acceleration = (10 - 20)/5
Acceleration = -10/5
Acceleration = -2 miles per hour per second
3 Study the circuits in Figure 36.8. The switch S is open (there
is a break in the circuit at this point). In which circuit would
lamps Q and R light but not lamp P?
Answers
The circuit in which lamps Q and R light but not lamp P when switch S is open is circuit B.
What is an electric circuit?An electric circuit is a path for transmitting electric current.
Given the circuits below, when switch S is open, we want to determine the circuit in which lamps Q and R light but not lamp P.
To determine the circuit, we proceed as follows.
To determine the circuit in which lamps Q and R light but not lamp P, it must satisfy this condition
The switch must be before lamp P and The circuit for lamp P must be different from that of lamps Q and RLamps Q and R must be in the same circuitLooking at all the circuits, the circuit which satisfy these condition is circuit B
So, the circuit in which lamps Q and R light but not lamp P is circuit B.
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How long is a day in Neptune
Answers
Answer: the long day in neptune would be .18383562 years!
Explanation:also for every day is 16 hours
2000kg of mass is equal to
Answers
w= mg
w = 2000×9.8
w= 19,600 kg
Can someone check my answers? If they’re incorrect can you correct me? Image below. Thank you.
Answers
Kinetic energy is the energy that an entity has as a result of its movement. If we want to accelerate an object, we must impart power to it. Using power needs us to put in effort.
What is kinetic energy called?In physics, an object's kinetic energy is the type of energy it has as a result of its velocity. It is described as the amount of effort required to propel an entity of a given mass from rest to a given velocity. The body retains its kinetic energy after gaining it during acceleration unless its pace alters. The body does the same amount of effort when slowing down from its present speed to rest.
A kinetic energy is any term in a system's Lagrangian that contains a time component, as well as the second term in a Taylor expansion of a particle's relativistic energy.
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a. The energy diagrams when the ball is just thrown into the air and when it reaches maximum height is attached below.
b. The initial kinetic energy of the ball is 19.96 J.
c. The total energy of the ball at any time during its flight is the sum of its kinetic and potential energy.
d. The potential energy of the ball at the maximum height is 23.67 J.
e. The acceleration due to gravity on this planet is approximately 6.49 m/s²
Give a brief account on law of conservation of energy.Law of conservation of energy is the physical principle that the energy of interacting bodies or particles in a closed system remains constant. The kinetic energy that an object loses as it moves upward against gravity is converted into potential or stored energy, which is converted into kinetic energy as the object accelerates as it returns to Earth.
a. Here are two energy diagrams:
Initial state: The ball is thrown with a speed of 23 m/s from ground level. At this point, it has only kinetic energy.
Maximum height: The ball reaches a maximum height of 32 m, where it has zero kinetic energy and maximum potential energy.
b. The initial kinetic energy of the ball can be calculated using the formula:
KE = 0.5 × m × v²
Where m is the mass of the ball (0.0755 kg) and v is initial velocity (23 m/s). Plugging in the values, we get:
KE = 0.5 × 0.0755 kg × (23 m/s)²
KE = 19.96 J
c. The total energy of the ball at any time during its flight is the sum of its kinetic and potential energy.
Total Energy = Kinetic Energy + Potential Energy
d. At the maximum height, the ball has zero kinetic energy and maximum potential energy. The potential energy of the ball can be calculated using the formula:
PE = m × g × h
where m is the mass of the ball, g is the acceleration due to gravity on the planet, and h is the height of the ball. We are given that the ball reaches a maximum height of 32 m, so we can plug in the values to get:
PE = 0.0755 kg × 9.8 m/s² × 32 m
PE = 23.67 J
e. To determine how strong gravity is on this planet, we can use the formula for the maximum height of a projectile:
h = (v² × sin²θ) / (2 × g)
where v is the initial velocity, theta is the angle of projection (which we don't know), h is the maximum height, and g is the acceleration due to gravity on the planet (which we want to find).
Since we don't know the angle of projection, we can assume that the ball was thrown at a 45-degree angle, which will give us the maximum height for a given initial velocity. Plugging in the values, we get:
32 m = (23 m/s)² × sin²(45) / (2 × g)
Simplifying, we get:
g = (23 m/s)² × sin²(45) / (2 × 32 m)
g = 6.49 m/s²
So the acceleration due to gravity on this planet is approximately 6.49 m/s²
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The bottom of a rectangular swimming pool is 16 m × 20 m. If the atmospheric pressure above the swimming pool changes from 737 to 761 mm of mercury, determine the amount by which the force on the bottom of the pool increases? (Assume the density of mercury is 13.6 ✕ 103 kg/m3.)
Answers
First, let's calculate the increase in the pressure:
\(761-737=24\text{ mmHg}\)Now, let's convert this difference to Pascal:
\(24\text{ mmHg}=24\cdot133.322\text{ Pa}=3199.73\text{ Pa}\)Then, let's find the area of the bottom of the pool:
\(A=16\cdot20=320\text{ m^^b2}\)Having the difference of pressure and the area, we can find the difference of force:
\(\begin{gathered} P=\frac{F}{A}\\ \\ F=P\cdot A\\ \\ F=3199.73\cdot320\\ \\ F=1023913.6\text{ N} \end{gathered}\)How the government can ensure basic human dignity is maintained in relation to safe and healthy living
Answers
To ensure basic human dignity in relation to safe and healthy living, governments can implement various measures such as accessible healthcare, adequate housing, and sanitation and clean water.
How government can ensure basic human dignity is maintainedGovernments should place a high priority on ensuring that everyone has access to healthcare services, enabling them to receive the essential medical care without suffering financial difficulty. This entails providing access to necessary pharmaceuticals, cheap healthcare, and a strong healthcare system.
All citizens should have access to affordable and good housing, according to governments. Policies may include restrictions on rental costs, programs to expand the supply of affordable housing, and efforts to combat homelessness. Basic hygienic and safety criteria should be met by housing.
Governments must make sure that everyone has access to clean, safe drinking water and adequate sanitary facilities. The spread of diseases and the maintenance of sanitary living circumstances can be aided by investments in sewage systems, water treatment facilities, and public hygiene education.
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what kind of surface is suitable for infared radiation
Answers
Answer:
Different surfaces
You can see that dull surfaces are good absorbers and emitters of infrared radiation. Shiny surfaces are poor absorbers and emitters (but they are good reflectors of infrared radiationA flywheel with a radius of 0.200m starts from rest and accelerates with a constant angular acceleration of 0.900rad/s2.
Compute the magnitude of the radial acceleration of a point on its rim after it has turned through 120.0.
Answers
Answer:
The magnitude of the radial acceleration is 0.754 rad/s²
Explanation:
Given;
radius of the flywheel, r = 0.2 m
initial angular velocity of the flywheel, \(\omega_i = 0\)
angular acceleration of the flywheel, a = 0.900 rad/s².
angular distance, θ = 120⁰
the angular distance in radian = \(\frac{120}{180} \pi = \frac{2 \pi}{3} \ rad\)
Apply the following kinematic equation to determine the final angular velocity;
\(\omega _f^2 = \omega _i ^2 + 2\alpha \theta\\\\\omega _f^2 = 0 + 2(0.9)(\frac{2\pi}{3} )\\\\\omega _f^2 = 3.7699\\\\\omega _f = \sqrt{ 3.7699} \\\\ \omega _f = 1.942 \ rad/s\)
The magnitude of the radial acceleration is calculated as;
\(\alpha _r = \omega ^2r\\\\\alpha _r = (1.942)^2 (0.2)\\\\\alpha _r =0.754 \ rad/s^2\)
Therefore, the magnitude of the radial acceleration is 0.754 rad/s²
From the 1780s to the late 1800s, people thought the amount of land and resources in the West was limited
Answers
Answer:true
Explanation:
2 parts that increase the reaction rate
Answers
Two parts that increase the reaction rate of a chemical reaction are concentration of reactants and increase in temperature.
What are two parts that increase the reaction rate?There are several factors that can increase the rate of a chemical reaction, but two common parts are:
Increase in concentration of reactants: An increase in the concentration of reactants leads to more frequent collisions between the reactant molecules, which in turn increases the likelihood of successful collisions and the rate of the reaction. This is because with a higher concentration, there are more molecules in a given space, and therefore more chances of them reacting.Increase in temperature: Increasing the temperature of the reactants increases the average kinetic energy of the molecules, which makes them move faster and collide more frequently. This also increases the likelihood of successful collisions and the rate of the reaction. According to the Arrhenius equation, for every 10°C increase in temperature, the rate of a reaction doubles.Learn more about reactions in: https://brainly.com/question/28984750
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QUESTION 3 (Start on a new page.)
A small disc, C, is thrown vertically upwards at a speed of 15 m-s¹ from the edge of
the roof of a building of height 30 m. AFTER 0,5 s, a small ball B is shot vertically
upwards from the foot of the building at a speed of 40 m-s in order to hit disc C.
Ignore the effects of air resistance.
3.1
3.2
3.3
15 m-s¹
30 m
Explain the term projectile.
Calculate the:
40 m-s¹
B
3.2.1
Time taken by disc C to reach its maximum height
3.2.2
Maximum height above the ground reached by disc C
Calculate the time from the moment that disc C was thrown upwards until
the time ball B hits the disc..
(2)
(3)
(4)
(6)
Answers
A projectile is an object thrown into the air and subject only to gravity and, if applicable, air resistance. The time taken by disc C to reach its maximum height is approximately 1.53 seconds, and its maximum height above the ground is around 11.48 meters. The time from when disc C was thrown upwards until ball B hits the disc is roughly 1.29 seconds.
3.1 Explanation of the term projectile:
A projectile refers to an object that is launched or thrown into the air and is subject only to the forces of gravity and air resistance (if applicable). The motion of a projectile can be analyzed independently of its mass, shape, or any other physical property. The key characteristic of a projectile is that it follows a curved path known as a trajectory.
When a projectile is launched, it moves along a parabolic trajectory due to the combination of its initial velocity and the force of gravity acting vertically downward. The horizontal motion of a projectile remains constant and unaffected by gravity, while the vertical motion is influenced by the acceleration due to gravity.
The path of a projectile can be described mathematically by considering its initial velocity, angle of projection, and the acceleration due to gravity. Projectile motion finds applications in various fields, such as sports, engineering, and physics, where objects are launched or thrown.
3.2.1 Time taken by disc C to reach its maximum height:
To determine the time taken by disc C to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:
vf = vi + at
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
t = time
Since the disc is thrown vertically upwards, its initial velocity is 15 m/s. We want to find the time it takes for the disc to reach its maximum height, so we'll use the equation and solve for time (t):
0 = 15 + (-9.8)t
Rearranging the equation, we get:
9.8t = 15
t = 15 / 9.8
Calculating this, we find:
t ≈ 1.53 seconds
Therefore, it takes approximately 1.53 seconds for disc C to reach its maximum height.
3.2.2 Maximum height above the ground reached by disc C:
To determine the maximum height reached by disc C, we can use another kinematic equation for vertical motion:
vf² = vi² + 2ad
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
d = displacement (maximum height)
Since we know the initial velocity (vi) and acceleration (a), we can solve for the displacement (d), which represents the maximum height:
0² = 15² + 2(-9.8)d
Rearranging the equation, we get:
0 = 225 - 19.6d
19.6d = 225
d = 225 / 19.6
Calculating this, we find:
d ≈ 11.48 meters
Therefore, the disc C reaches a maximum height of approximately 11.48 meters above the ground.
Calculating the time from the moment that disc C was thrown upwards until the time ball B hits the disc:
To find the time it takes for ball B to hit disc C, we need to calculate the time it takes for both objects to reach the same height.
Since disc C was thrown upwards from the edge of the roof and ball B was shot vertically upwards from the foot of the building, we need to consider the additional height of the building (30 meters).
The time it takes for disc C to reach the ground is the same as the time it takes for ball B to reach a height of 30 meters above the ground.
Using the kinematic equation for vertical motion, we can calculate the time for ball B:
d = vit + 0.5at²
Where:
d = displacement (30 meters)
vi = initial velocity (40 m/s)
a = acceleration (acceleration due to gravity, -9.8 m/s²)
t = time
30 = 40t + 0.5(-9.8)t²
Rearranging the equation, we get:
4.9t² + 40t - 30 = 0
Solving this quadratic equation, we find:
t ≈ 1.29 seconds or t ≈ -5.82 seconds
Since time cannot be negative in this context, we discard the negative solution.
Therefore, it takes approximately 1.29 seconds from the moment that disc C was thrown upwards until ball B hits the disc.
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Two rocks, each of mass 72 kg, are positioned 95 m away from each other in deep space. What is the magnitude of the gravitational attraction between them? G=6.674 x 10^-11 N*m^2/kg^2.
3.8 x 10-12N
9.8 x 10-11N
3.0 x 10-10N
3.8 x 10-11N
Answers
Answer:
3.8 x 10^-11N
Explanation:
Given
M=72 kg
R=95 m
G=6.67x10^-11
Equation
Fg= 6.67x10^-11((72kg*72)/(95)^2)
Plug into calculator and get
3.8127756 x 10^-11
A single coil of wire, with a radius of 0.13 m is rotated in a uniform magnetic field such that the angle between the field vector and the area vector obeys θ=ωt. If the strength of the field is 3.746 T, and the angular frequency is 524.7 rad/s, what is the induced emf in the loop at t=1.16 s?
Answers
The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.
The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.
emf = N(dФ/dt)
where;
N is number of turns of the wireФ is magnetic fluxФ = BA
where;
B is magnetic field strengthA is the area of the loopemf = NBA/t
A = πr²
A = π x (0.13)²
A = 0.053 m²
emf = NBA/t
emf = (1 x 3.746 x 0.053)/(1.16)
emf = 0.171 V
Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.
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A 1.70 m tall woman stands 5.00 m in front of a camera with a 50.00 cm focal
length lens. Calculate the size of the image formed on flim
Answers
Answer:
18.89cm
Explanation:
As we know that the person is standing 5m in front of the camera
\(d_0=5m=500cm\)
The focal length of the lens =50cm
f=50 cm
By Lens formula we have:
\(\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}\\\dfrac{1}{50} = \dfrac{1}{d_i} + \dfrac{1}{500}\\\dfrac{1}{d_i} =\dfrac{1}{50}-\dfrac{1}{500}\\\dfrac{1}{d_i}=0.018\\d_i=55.56cm\)
By the formula of magnification
\(\dfrac{h_i}{h_o} = \dfrac{55.56}{500}\\\\h_i = \dfrac{55.56}{500} \times h_o\\\\ h_o=1.70m=170cm\\\\Therefore: h_i=\dfrac{55.56}{500} \times$ 170 cm\\\\h_i =18.89 cm\)
The height of the image formed is 18.89cm.
Pls help will give brainlist
Answers
potential energy is the stored energy an object has, the bike is not moving and it just sitting on the hill, with the stored energy
establish the relation among energy, density, strain and stress
Answers
Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation.
All the outer planets of our solar system-the "gas giants"-orbit the sun much more quickly than the inner planets. True or False?
Answers
When a planet is far away from the Sun (that is, outer planets), their trajectory around the sun is bigger, therefore they will need more time to orbit around the Sun.
So outer planets take a longer time, and inner planets are quicker.
Therefore the correct answer is FALSE.
You throw a ball upwards at 22 m/s. How high will it go?
Answers
Answer:
24.69 meters
Explanation:
sorry if it's not right.
answer:
\(h=24.69m\)
step-by-step explanation:
\(eg=mgh \\ek=\frac{1}{2} mv^2\)
eg= gravitational energy
ek= kinetic energy
now, since no mass is given of the ball, both equations on their own do nothing for us, except leave us scratching our heads wondering how to figure out the problem. but, since the question states, “and no air resistance,” we now know, according to the law of conservation of energy, that the energy of the two equations will equal each other because none of the energy has dissipated or left the system.
the amount of energy present during the initial phase of the woman about to throw the ball will be present in the final phase, which will be at its highest point (according to this problem).
so now \(eg=ek\)
knowing this, we can now set the equations equal
\(eg=ek\\mgh=\frac{1}{2} mv^2\)
the two m’s cancel out, making the mass of the ball insignificant and not influential; next, substitute the values we are given in the problem
\((22m/s),(9.8m/s^2)\\m(9.8m/s^2)h=\frac{1}{2} m(22m/s)^2\\(9.8 m/s^2)h=\frac{1}{2} (22m/s)^2\\(9.8m/s^2)h=1/2 (484m^2/s^2)\\(9.8m/s^2)h=1/2 (242m^2/s^2)\\\\h= (242m^2/s^2)/(9.8m/s^2)\)
as you can see, all units that need to be canceled out are indeed canceled, leaving us with just m, meters, which is what height is measured in
therefore, \(h=24.69m\)
19) Study the chart above. Which statement is TRUE regarding natural and synthetic (manufactured) fibers?
A) Glass is a natural material.
B) Staple fibers do not come from animals.
C) Organic manufactured materials are either synthetic or natural plastics.
D) Synthetic polymers including polyester and nylon, make up a large category of synthetic material.
Answers
Answer: The answer is D: Synthetic polymers including polyester and nylon, make up a large category of synthetic material.
Explanation:
study 60cm ady the water the diagram Pressure at A, B and C. C B 30cm A ram and calculate the liquid pressure
Answers
To calculate the liquid pressure at points A, B, and C in the given diagram, we need to consider the height and density of the liquid.
Let's assume that the liquid in the container is water, which has a density of approximately 1000 kg/m³.
Given:
- Height of column AB = 60 cm = 0.6 m
- Height of column BC = 30 cm = 0.3 m
To calculate the pressure at each point, we can use the formula:
Pressure = density * gravity * height
where:
- Density = 1000 kg/m³ (density of water)
- Gravity = 9.8 m/s² (acceleration due to gravity)
Calculating the pressures:
At point A:
Pressure_A = density * gravity * height_AB
= 1000 kg/m³ * 9.8 m/s² * 0.6 m
= 5880 Pascal (Pa)
At point B:
Pressure_B = density * gravity * (height_AB + height_BC)
= 1000 kg/m³ * 9.8 m/s² * (0.6 m + 0.3 m)
= 8820 Pascal (Pa)
At point C:
Pressure_C = density * gravity * height_BC
= 1000 kg/m³ * 9.8 m/s² * 0.3 m
= 2940 Pascal (Pa)
Therefore, the liquid pressures at points A, B, and C are as follows:
- Pressure at point A = 5880 Pa
- Pressure at point B = 8820 Pa
- Pressure at point C = 2940 Pa
Find the force necessary to stop a 900. kg jetta traveling at +25 m/s in a time of 5.0 seconds. (2sigfigs)(include units)
Answers
Given data:
* The mass of the object is m = 900 kg.
* The initial velocity of the object is u = 25 m/s.
* The final velocity of the object is v = 0 m/s.
* The time taken by the object is t = 5 seconds.
Solution:
The force required to stop the object is,
\(F=\frac{m(v-u)}{t}\)Substituting the known values,
\(\begin{gathered} F=\frac{900\times(0-25)}{5} \\ F=-\frac{900\times25}{5} \\ F=-4500\text{ N} \\ F=-4.5\times10^3\text{ N} \\ F=-4.5\text{ kN} \end{gathered}\)Here, the negative sign indicates the force is applied in the opposite direction to the direction of motion of an object.
Thus, the force applied to the object is - 4.5 kN.
Which type of electromagnetic wave has the least energy?
O A. Ultraviolet
O B. Infrared
O C. Microwaves
O D. Radio
Help!
Answers
Answer:
The answer is radio waves
A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
Answers
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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A concave lens cannot produce a real image.
A. True
B. False
Answers
Answer:
B. False
A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point.
~Hoped this helped~
~Brainiliest?~
Explain how a balloon can become positively charged when rubbed with a cloth
Answers
For more static electricity information and experiments, see the list of Web Resources and Further Reading sections.