Answer:
a. On the 13th day
b. 2,451 players we’re sold on that day
Step-by-step explanation:
a. The day in which the company sold the same number of players can be calculated by equating the values of y that we have ;
y = 191x-32 and y = -x^2 + 200x + 20
Equating both, we have;
191x-32 = -x^2 + 200x + 20
x^2 -200x + 191x-20-32 = 0
x^2-9x-52 = 0
x^2-13x + 4x -52 = 0
x(x-13)+4(x-13) = 0
(x-13)(x+4) = 0
x = 13 or -4
as days cannot be negative we choose only x = 13
This means the company sold equal numbers of players on the 13th day
b. To get the number of players sold on that day, we choose any of the y equation and substitute x = 13
Thus, we have for y = 191x -32; 191(13) - 32 = 2,451 players
If the taking turns procedure takes place on this distribution of goods, who would walk away with each pile? Person A chooses first.
Pile 1
Pile 2
Pile 3
Pile 4
Pile 5
Pile 1 will go to(No answer given)
Pile 2 will go to(No answer given)
Pile 3 will go to (No answer given)
Pile 4 will go to (No answer given) + Person A views,21% 13% 22% 18% 26%
Person B views 24% 17% 14% 22% 23%
In this situation, did each person get their fair share? (No answer given)
a) Note that the distribution of piles would be:
Person A gets Pile 5
Person B gets Pile 1
Person A gets Pile 3
Person B gets Pile 4
Person A gets Pile 2.
b) No, in this situation each person did not get their fair share.
If the taking turns procedure is such that Person A chooses first and then they alternate turns, then the following would be the distribution of piles:
Person A chooses first and would likely choose Pile 5, as it has the highest percentage viewed by them.Person B chooses next and would likely choose Pile 1, as it has the highest percentage viewed by them among the remaining piles.Person A chooses next and would likely choose Pile 3, as it has the highest percentage viewed by them among the remaining piles.Person B chooses next and would likely choose Pile 4, as it has the highest percentage viewed by them among the remaining piles.Finally, Person A would choose Pile 2, as it is the only remaining pile.So the distribution of piles would be:
Person A gets Pile 5Person B gets Pile 1Person A gets Pile 3Person B gets Pile 4Person A gets Pile 2.b) No, in this situation each person did not get their fair share if the criterion for fairness is defined as each person receiving an equal share of the piles.
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Full Question:
Although part of your question is missing, you might be referring to this full question: See attached image.
Christy earned $41.25 for selling 3 birdhouses at a craft market. The equation y=13.75x can be used to represent this situation. What is the constant of proportionality? Express your answer in decimal form.
A kite is flying 86 ft off the ground, and its string is pulled taut. The angle of elevation of the kite is 56 degrees . Find the length of the string. Round your answer to the nearest tenth.
what is the nth term rule of the linear sequence below 15, 7, -1, -9, -17
Answer:
8n+7
Step-by-step explanation:
The diagram shows the cross-section ABCD of a sculpture in the shape of
a prism
with perpendicular height 9 cm.
AB = 14 cm, CD = 8cm, AD = 12cm and BC = 10cm
The height of the prism is also 9 cm.
What is the volume of the sculpture in cm3?
Answer:
891 cm³
Step-by-step explanation:
The volume (V) of the prism is calculated as
V = Ah ( A is the area of cross- section and h is the height (
The cross- section is a trapezium with area (A) calculated as
A = \(\frac{1}{2}\) h ( a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 9, a = AB = 14 and b = CD = 8 , thus
A = \(\frac{1}{2}\) × 9 × (14 + 8) = 4.5 × 22 = 99 cm² , thus
V = 99 × 9 = 891 cm³
1. What are the 3 conditions for a function to be continuous at xa? 2. the below. Discuss the continuity of function defined by graph 3. Does the functionf(x) = { ***
The three conditions for a function to be continuous at a point x=a are:
a) The function is defined at x=a.
b) The limit of the function as x approaches a exists.
c) The limit of the function as x approaches a is equal to the value of the function at x=a.
The continuity of a function can be analyzed by observing its graph. However, as the graph is not provided, a specific discussion about its continuity cannot be made without further information. It is necessary to examine the behavior of the function around the point in question and determine if the three conditions for continuity are satisfied.
The function f(x) = { *** is not defined in the question. In order to discuss its continuity, the function needs to be provided or described. Without the specific form of the function, it is impossible to analyze its continuity. Different functions can exhibit different behaviors with respect to continuity, so additional information is required to determine whether or not the function is continuous at a particular point or interval.
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How many incas did the spanish kill on november 16 1532 o 100 o 600 o 1000 6000?
Spanish killed nearly 6000 Incas.
The Spanish conquistador and explorer Francisco Pizarro springs a trap on Atahualpa, the monarch of the Incas, in the year 1532. Atahualpa allowed roughly 6,000 unarmed men to attend the feast despite having almost 80,000 soldiers with him in the mountains. It took the Spanish a long time and much violence to conquer the Inca Empire. Pizarro's soldiers massacred the 6,000 Incans in approximately one hour.
The lone Spanish wounded were received by Pizarro himself, who injured his hand while saving Atahualpa's life. Pizarro retained Atahualpa in captivity while he prepared plans to conquer his empire because he understood that the emperor was worthy alive than dead. Atahualpa responded by appealing to his hostages' avarice and supplying them with money and silver in exchange for their release.
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Drake and Evan are teammates on a high school swim team drake swim 312. 63 m during practice evan swim exactly 1/3 times farther than drake exactly how far did Evan swim?
Answer:
416.84 m
Step-by-step explanation:
First Step:
Multiple 312.63 by 1/3
312.63*1/3=104.21
Second Step:
Add 312.63 to 104.21
312.63+104.21=416.84
\(✤ \: \underline{ \underline{ \frak{Understanding~the~question : - }}} \\ \\ \)
In this question, we have been provided that Evan swims 1/3 times farther than Drake, thus, the total distance covered by Evan will be equal to the sum of 312.63 m and the 1/3rd of 312.63 m. Thus, at first we will calculate the one third of the distance and then add them up to get our final answer.
⠀
\(✤ \: \underline{ \underline{ \frak{Given:-}}} \\ \\ \)
There are two teammates in a high school teamDrake swims 312.63 m Evan swims 1/3 times farther than Drake⠀
\(✤ \: \underline{ \underline{ \frak{To~Find :-}}} \\ \\ \)
The distance travelled ( swim ) by Evan⠀
\(✤ \: \underline{ \underline{ \frak{Solution :-}}} \\ \\ \)
Calculating the one - third,
\( \sf \longrightarrow \dfrac{1}{3} \: of \: 312.63 \: m \\ \\ \\ \sf \longrightarrow \dfrac{1}{3} \times 312.63 \: m \\ \\ \\ \sf \longrightarrow \dfrac{1}{ \cancel3} \times \cancel{312.63} \: m \: \\ \\ \\ \sf \longrightarrow 1 \times 104.21 \: m \: \: \\ \\ \\ \sf \longrightarrow 104.21 \: m \: \: \: \: \: \: \: \: \: \: \\ \\ \)
Thus,
⠀
\( \sf \longrightarrow Distance~covered~by~Evan =312.63 \: m + 104.21 \: m \\ \\ \\ \sf \longrightarrow Distance~covered~by~Evan =416.84 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \)
Thus, the distance covered by Evan is 416.84 m.
⠀
\(\underline{\rule{227pt}{2pt}} \\ \\ \)
Studies show that people who live in very cold climates have a 30% chance of getting influenza and a 15% chance of getting appendicitis during the winter. What is the probability a person has both diagnoses, rounded to the nearest percent?
Answer: The probability a person has both diagnoses = 4.5%
Step-by-step explanation:
Given: Chances of getting influenza = 30% = 0.30
Chances of getting appendicitis = 15% = 0.15
Since both the events are independent , so the probability a person has both diagnoses will be
P(influenza and appendicitis) =P(influenza) x P(appendicitis)
\(=0.30\times0.15\\\\=0.045\\\\=4.5\%\)
Hence, the probability a person has both diagnoses = 4.5%
the mayor of a town has proposed a plan for the construction of an adjoining community. a political study took a sample of 1600 voters in the town and found that 34% of the residents favored construction. using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is over 31%. find the value of the test statistic. round your answer to two decimal places.
The value of the test statistic is 2.59.
What is Test Statistics?A number derived from a statistical test of a hypothesis is the test statistic. It displays how closely your actual data fit the distribution predicted by the statistical test's null hypothesis.
Here, the percentage of residents favored construction is 34%.
\(p\leq 0.31\\p > 0.31\)
The test statistics is given by,
\(Z=P-\frac{p}{\sqrt{p(1-p)n} }\)
Here n=1600, P=0.34 and p=0.31,
Putting the values,
\(Z=0.34-\frac{0.31}{\sqrt{0.31(1-0.31)1600} }\\=2.59\)
Test Statistics = 2.59
Therefore, the value of test statistics is 2.59.
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-3.2 < -3 Is this true or false?
Answer:true
Step-by-step explanation: because -3.2 is smaller than -3 because negatives get smaller the bigger the negative
i need help with the image below
Answer:
A. k ≥ 8.14
Step-by-step explanation:
Hope this helps! :))
Is this correct
16-2t=5t+9
Answer: yes it is t={1}
PREMISES
16–2t=5t+9
CALCULATIONS
16–2t=5t+9
(16–9)-(2t-2t)=5t+2t+(9–9)
7–0=7t+0
7t=7
7t/7=7/7
t=1/1
t=
1
PROOF
If t=1, then the equations
16–2t=5t+9
16–2(1)=5(1)+9
16–2=5+9 and
14=14 prove the root (zero) t=1 of the statement 16–2t=5t+9
Step-by-step explanation:
Suppose that X is a random variable with mean 20 and standard deviation 4. Also suppose that Y is a random variable with mean 40 and standard deviation 7. Find the mean and the variance of the random variable Z for each of the following cases. Be sure to show your work.
(a) Z = 40 - 5X
(b) Z = 15X - 20
(c) Z = X + Y
(d) Z = X - Y
(e) Z = -2X + 3Y
(a) The mean of Z in case (a) is -60 and the variance is 400.
(b) The mean of Z in case (b) is 280 and the variance is 3600.
(c) The mean of Z in case (c) is 60 and the variance is 65.
(d) The mean of Z in case (d) is -20 and the variance is 65.
(e) The mean of Z in case (e) is 80 and the variance is 505.
To find the mean and variance of the random variable Z for each case, we can use the properties of means and variances.
(a) Z = 40 - 5X
Mean of Z:
E(Z) = E(40 - 5X) = 40 - 5E(X) = 40 - 5 * 20 = 40 - 100 = -60
Variance of Z:
Var(Z) = Var(40 - 5X) = Var(-5X) = (-5)² * Var(X) = 25 * Var(X) = 25 * (4)² = 25 * 16 = 400
Therefore, the mean of Z in case (a) is -60 and the variance is 400.
(b) Z = 15X - 20
Mean of Z:
E(Z) = E(15X - 20) = 15E(X) - 20 = 15 * 20 - 20 = 300 - 20 = 280
Variance of Z:
Var(Z) = Var(15X - 20) = Var(15X) = (15)² * Var(X) = 225 * Var(X) = 225 * (4)² = 225 * 16 = 3600
Therefore, the mean of Z in case (b) is 280 and the variance is 3600.
(c) Z = X + Y
Mean of Z:
E(Z) = E(X + Y) = E(X) + E(Y) = 20 + 40 = 60
Variance of Z:
Var(Z) = Var(X + Y) = Var(X) + Var(Y) = (4)² + (7)² = 16 + 49 = 65
Therefore, the mean of Z in case (c) is 60 and the variance is 65.
(d) Z = X - Y
Mean of Z:
E(Z) = E(X - Y) = E(X) - E(Y) = 20 - 40 = -20
Variance of Z:
Var(Z) = Var(X - Y) = Var(X) + Var(Y) = (4)² + (7)² = 16 + 49 = 65
Therefore, the mean of Z in case (d) is -20 and the variance is 65.
(e) Z = -2X + 3Y
Mean of Z:
E(Z) = E(-2X + 3Y) = -2E(X) + 3E(Y) = -2 * 20 + 3 * 40 = -40 + 120 = 80
Variance of Z:
Var(Z) = Var(-2X + 3Y) = (-2)² * Var(X) + (3)² * Var(Y) = 4 * 16 + 9 * 49 = 64 + 441 = 505
Therefore, the mean of Z in case (e) is 80 and the variance is 505.
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Find m∠G.
In the following image shown below
Applying the exterior angle of a triangle theorem, m∠G = 40°.
How to Apply the Exterior Angle Theorem of a Triangle?According to the exterior angle theorem of a triangle, we have the following equation that is derived:
11x - 4 + 55 = 23x + 3
11x + 51 = 23x + 3
11x - 23x = -51 + 3
-12x = -48
-12x/-12 = -48/-12
x = 4
m∠G = 11x - 4 = 11(4) - 4
m∠G = 40°
Thus, applying the exterior angle of a triangle theorem, m∠G = 40°.
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pls help me with this some one
Answer:
5,5 is the answer
Step-by-step explanation:
because I calculated and I want brainliest
Answer:
(5.5,5)
Step-by-step explanation:
(8+3)/2=x variable
=5.5
(2+8)/2=y variables
=5
finding the averages
(5.5,5)
In a game, players roll a number cube. the faces of the cube are numbered from 1 to 6. for the player to win a prize, the number cube must land with the top face showing the number 3. what is the probability of the complement of this event occurring?
The probability of the complement of this event occurring is 5/6.
What is probability?
Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.
The likelihood that a population parameter will be less than a given value when the null hypothesis is true is expressed as the p-value, also known as a probability value or a measure of significance, for a particular statistical model.
Sample space: {1,2,3,4,5,6}
Total number of outcomes=6
Complement of an Event: All outcomes that are NOT the event
In this case:
So, possible outcomes in the complement event:{1,2,4,5,6}
Number of possible outcomes=5
Formula:
Probability = (Number of possible outcomes)/(Total number of outcomes)
= 5/6
So, the probability of the complement of this event occurring is 5/6.
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How many cans of paint are needed to cover an area of 2000?
The number of cans required to paint an area of 2000 square units is equal to 5 cans.
As given in the question,
Total area to be painted is equal to 2000 square units.
Area covered by one can of paint is equal to 400 square units
400 square units = 1 can of paint
⇒ 1 square units = ( 1 / 400 ) cans of paint
⇒ 2000 square units = ( 2000 / 400 ) cans of paint
⇒ 2000 square units = 5 cans of paint
Therefore, the number of cans required to paint an area of 2000 square units using given can is equal to 5 cans.
The above question is incomplete, the complete question is:
How many cans of paint are needed to cover an area of 2000 square units if one can of paint covers in area 400 square units?
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Jay makes a base salary of $2000 per month. Once he reaches $50000 in total sales, he earns an additional 5% commission (salary) on the amount of sales over $50000. Let s be the amount of his total sales for the month and j(s) be the amount of his salary for the month.
Answer:
\(j(s) = 0.05s -500\)
Step-by-step explanation:
Given
\(Base\ Salary = 2000\)
\(Commission = 5\%\) on Sales over 50000
Required
Determine the function j(s) for sales over 50000
Represent the total sales in a month with s.
Sales over 50000 in that month will be: s - 50000
So, the function j(s) is:
j(s) = Base Amount + Commission * Sales over 50000
\(j(s) = 2000 + 5\% * (s - 50000)\)
Convert % to decimal
\(j(s) = 2000 + 0.05 * (s - 50000)\)
Open bracket
\(j(s) = 2000 + 0.05 * s - 0.05 * 50000\)
\(j(s) = 2000 + 0.05s - 2500\)
Collect Like Terms
\(j(s) = 0.05s - 2500 + 2000\)
\(j(s) = 0.05s -500\)
The LCD for adding the fractions 1/5 + 1/10 is 10.
True
False
Answer:
true
Step-by-step explanation:
Answer: false
Step-by-step explanation:
Ms. Kumar has a checking account at the bank. If the account balance ever falls below zero, the bank charges her a fee of $5.95 per day. Today, the balance in Ms. Kumar's account is -$2.67. If she does not make any deposits or withdrawals, what will be the balance in her account after 2 days?
Answer:
-14.57
Step-by-step explanation:
5.95×2=11.90 (for the fee in 2 days) 11.90+2.67=14.57 and sense she owes money it would be -14.57
the average number of pounds of red meat a person consumes each year is 196 with a standard deviation of 22 pounds. if a sample of 50 individuals is randomly selected, find the probability that the mean of the sample will be less than 200 pounds.
The probability that the sample mean will be less than 200 pounds is approximately 0.9015 or 90.15%.
Step-by-step explanation:
To solve this problem, we can use the central limit theorem, which states that the sampling distribution of the mean of a large sample (n >= 30) will be approximately normal, regardless of the distribution of the population.
We are given that the population mean is 196 pounds and the standard deviation is 22 pounds. The sample size is 50, which is large enough to apply the central limit theorem.
To find the probability that the mean of the sample will be less than 200 pounds, we need to standardize the sample mean using the formula:
z = (x - mu) / (sigma / sqrt(n))
where x is the sample mean, mu is the population mean, sigma is the population standard deviation, and n is the sample size.
Plugging in the values we get:
z = (200 - 196) / (22 / sqrt(50)) = 1.59
Now we need to find the probability that a standard normal variable is less than 1.59. We can use a standard normal table or calculator to find this probability, which is approximately 0.944.
Therefore, the probability that the mean of the sample will be less than 200 pounds is 0.944 or 94.4% (rounded to one decimal place).
So, we can say that there is a 94.4% chance that the mean weight of 50 randomly selected individuals will be less than 200 pounds.
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Find the values of x and y from the following equal ordered pairs. a) (x,-2) = (4,y) b) (3x, 4) = (6, 2y) c) (2x-1, y + 2) = (-1,2) d) (2x + 4, y + 5) = (3x + 3,6) e) (x + y,y + 3) = (6, 2y) f) (x + y, x - y) - (8,0)
Answer:
a)
x=4, y=-2
b)
x=2, y=2
c)
x=0, y=0
d)
x=1, y=1
e)
x=3, y=3
f)
x=4, y=4
Step-by-step explanation:
a) (x,-2) = (4,y)
x=4
y=-2
b) (3x, 4) = (6, 2y)
3x=6 => x=2
2y=4 => y=2
c) (2x-1, y + 2) = (-1,2)
2x-1 =-1 => x=0
y+2 = 2 => y=0
d) (2x + 4, y + 5) = (3x + 3,6)
2x+4 = 3x+3 => x=1
y+5 = 6 => y=1
e) (x + y,y + 3) = (6, 2y)
x+y = 6 => x+3 = 6 => x=3
y+3 = 2y => y=3
f) (x + y, x - y) - (8,0)
x+y = 8 => 2x=8 => x=4
x-y = 0 => x=y => y=4
If you deposit $5000 into an account paying 8.25% annual interest compounded semiannually, how much in the account at 20 years?
Answer:
You would have saved up to $24,407 at the end of the 20 years
janice was given a piggy bank on her seventh birthday, and she put it to use immediately. each time she puts one or more coins into the piggy bank, she keeps track of the number of coins she has collected to date and the accumulated value of her collection. janice collects only nickels, dimes, and quarters. six months after her seventh birthday, janice looked at her record and ascertained that she had collected 540 coins, which were worth $60. janice counted 100 quarters in her savings. how many nickels and dimes are in her collection?
The number of dimes and nickels in her collection are 296 and 108 respectively.
How to find the number of nickels and dimes?She had collected 540 coins. which were worth $60.
She counted 100 quarters in her saving.
The number of dimes and nickel in her collection can be solved as follows:
Therefore,
let
x = number of dimes
y = number of nickels
number of quarters = 100
Therefore,
x + y + 100 = 504
x + y = 504 - 100
x + y = 404
Hence,
0.1x + 0.05y + 100(0.25) = 60
0.1x + 0.05y = 60 - 25
0.1x + 0.05y = 35
combine the equation
x + y = 404
0.1x + 0.05y = 35
Multiply equation(i) by 0.1
0.1x + 0.1y = 40.4
0.1x + 0.05y = 35
subtract equation(ii) from equation(i)
0.05y = 5.4
divide both sides by 0.05
y = 5.4 / 0.05
y = 108
x = 404 - 108
x = 296
Therefore,
Number of dimes = 296
Number of nickels = 108
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prove that h is a subgroup of s5. how many elements are in h? is your argument valid when 5 is replaced by any ? how many elements are in h when 5 is replaced by any ?
There are (n-1)! ways to permute n-1 elements.
What is algebra?
Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.
In order to prove that a subset H of a group G is a subgroup of G, we need to show that H satisfies the three conditions of a subgroup:
Closure: for any a, b in H, the product ab is also in H.
Identity: H contains the identity element of G.
Inverses: for any a in H, the inverse of a in G is also in H.
Let H be the subset of S5 consisting of all permutations that fix the element 1. In other words, H consists of all permutations that map 1 to 1. We will show that H is a subgroup of S5.
Closure: Let a and b be two permutations in H. Then a(1) = 1 and b(1) = 1. Therefore, (ab)(1) = a(b(1)) = a(1) = 1. Hence, ab fixes 1 and is in H.
Identity: The identity permutation e always fixes 1. Therefore, e is in H.
Inverses: Let a be a permutation in H. We need to show that \(a^-1\) is also in H. Since a fixes 1, we know that \(a^{-1}\) also fixes 1. Moreover, since a is a bijection, we know that \(a^{-1}\) is also a bijection. Therefore, \(a^{-1}\) is a permutation of S5 that fixes 1, and hence, \(a^{-1}\) is in H.
Since H satisfies the three conditions of a subgroup, we can conclude that H is a subgroup of S5.
How many elements are in H? We can count the number of elements in H by counting the number of ways we can permute the remaining four elements. There are 4! = 24 ways to permute four elements. Therefore, there are 24 elements in H.
Is this argument valid when 5 is replaced by any n? Yes, the argument is valid for any n. We can define H as the set of permutations in Sn that fix the element 1. The same three conditions hold, and we can conclude that H is a subgroup of Sn.
How many elements are in H when 5 is replaced by any n?
There are (n-1)! elements in H. We can count the number of elements in H by counting the number of ways we can permute the remaining n-1 elements. There are (n-1)! ways to permute n-1 elements. Therefore, there are (n-1)! elements in H.
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if you can explain it best, and answer them you'll get a brainliest
Answer:
11. -3 - (-8) = 5
12. -10 + (-25) = -35
13. -11 - (-10) = -1
14. 12 + (-5) = 7
15. -9 (9 + (-9) = 0)
Step-by-step explanation:
I don't really know how to explain it. For 11 I just found found the difference kind of. It's easier if you draw out a number line. 12 is self - explanatory, you just add the two negative numbers and it will be a negative. I look at 14 as just another minus equation.
Answer:
11. 5
12. -35
13. -1
14. 7
15. -9
Step-by-step explanation:
11. -3-(-8)
= -3 + 8 (double negative is positive)
= 8-3
= 5
12. -10 + (-25)
= -10 -25 (positive negative is negative)
= -35
13. -11 - (-10)
= -11 + 10
= -1
14. 12 + (-5)
= 12 - 5
= 7
15. 9 + x = 0
x = 0 - 9
x = -9
PLS GIVE BRAINLIEST
Help Please :)
f(x) = 5x +7
and
g(x) = -2x - 4
f(g(x)) = -2x + ????
Answer:
f(g(x)) = - 10x - 13Step-by-step explanation:
Given functions:
f(x) = 5x +7and
g(x) = -2x - 4Work out the composite f(g(x)):
f(g(x)) = f( -2x - 4) = 5( - 2x - 4) + 7 = -10x - 20 + 7 = - 10x - 13Answer:
f(g(x)) = -10x - 13
???? = - 8x - 13
Step-by-step explanation:
f(x) = 5x +7
and
g(x) = -2x - 4
f(g(x)) = f(-2x - 4) = 5(-2x - 4) + 7
f(g(x)) = -10x - 20 + 7
f(g(x)) = -10x - 13
f(g(x)) = -2x - 8x - 13
T/F compensatory approach lower weight on one selection method can be offset by higher weight on another
True. In a compensatory approach, lower weight on one selection method can be offset by a higher weight on another.
In selection processes, organizations often use multiple selection methods or criteria to assess candidates for a position. These selection methods can include interviews, tests, assessments, and other evaluation tools. In a compensatory approach, different selection methods are assigned weights or scores, and these weights are used to calculate an overall score or rank for each candidate.
In a compensatory approach, the lower weight assigned to one selection method can be compensated or offset by assigning a higher weight to another method. This means that a candidate who may score lower on one method can still have a chance to compensate for it by scoring higher on another method. The compensatory approach acknowledges that different selection methods capture different aspects of a candidate's qualifications or skills, and by assigning appropriate weights, a comprehensive evaluation can be achieved.
By allowing for compensatory adjustments, the compensatory approach recognizes that individuals may excel in certain areas while performing less strongly in others. This approach provides flexibility in the decision-making process and allows for a more holistic assessment of candidates' overall qualifications.
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three tins of oil with heights 6 cm, 10 cm and 15 cm are similar. if the medium tin hold 2 litres, calculate the capacities of the other two tins
The capacities of the other two tins of oil are 1.2L and 3L with the capacity of the medium tin being 2L.
The three tin of oils have height of 6, 10 and 15 cm and because they are similar, we can say that they will have similar radius.
So, let us say that the radius is R. Now, the capacity of the medium one is given to be 2 liters.
The capacity of each tin can be calculated by finding the volume,
The volume cylinder = πR²H
H is the height of the cylinder.
We also know, 2 liters = 2000 cm³
Volume of Larger tin = πR²(15)
Volume of medium tin = πR²(10)
Volume of small tin = πR²(6)
Now,
Volume of medium tin = πR²(10)
2000 = πR²(10)
R² = 200/π. Putting this value in the other volumes,
Volume of Larger tin = π(15)(200/π)
Volume of small tin = π(200/π)(6)
Volume of Larger tin = (3000)
Volume of small tin = (1200)
Now, the capacities in liters are 1.2, 2 and 3 liters in small, medium and large tin of oil.
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