the density of air is 1.3 kg/m3 and the speed of sound in air is 340 m/s. the displacement amplitude of a tone with angular frequency 1300 rad/s is 2.0×10−8 m. what is the pressure amplitude?
Answers
The pressure amplitude of a sound wave can be calculated using the equation P = ρ * v * ω * A, where P is the pressure amplitude, ρ is the density of the medium, v is the speed of sound, ω is the angular frequency, and A is the displacement amplitude. The pressure amplitude of the tone is approximately 11.43 Pascals.
To calculate the pressure amplitude, we need to use the equation:
Pressure amplitude = Density x (speed of sound)^2 x displacement amplitude
First, we need to convert the angular frequency of 1300 rad/s to regular frequency in Hz. We can do this by dividing 1300 by 2π, which gives us a frequency of approximately 207.9 Hz.
Now, we can plug in the given values into the equation:
Pressure amplitude = 1.3 kg/m3 x (340 m/s)^2 x 2.0×10−8 m
Simplifying this, we get:
Pressure amplitude = 1.3 x 340 x 340 x 2.0×10−8
Pressure amplitude = 3.1912×10−3 Pa
Therefore, the pressure amplitude of the tone with an angular frequency of 1300 rad/s is approximately 3.1912×10−3 Pa.
The pressure amplitude is 3.1912×10−3 Pa.
The pressure amplitude of a sound wave can be calculated using the equation P = ρ * v * ω * A, where P is the pressure amplitude, ρ is the density of the medium, v is the speed of sound, ω is the angular frequency, and A is the displacement amplitude.
Given the density of air (ρ) as 1.3 kg/m³, the speed of sound in air (v) as 340 m/s, the angular frequency (ω) as 1300 rad/s, and the displacement amplitude (A) as 2.0×10⁻⁸ m, we can calculate the pressure amplitude.
P = (1.3 kg/m³) * (340 m/s) * (1300 rad/s) * (2.0×10⁻⁸ m)
P ≈ 11.43 Pa
The pressure amplitude of the tone is approximately 11.43 Pascals.
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Related Questions
What value of resistor R gives the circuit in the figure a time constant of 22 μs ?
Answers
The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.
The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:
RC = τ, where R is the resistance and C is the capacitance of the circuit.
Rearranging the above formula, we get:R = τ / C
Where τ is the time constant and C is the capacitance of the circuit.
From the figure, the capacitance is given as 0.1 μF
.Substituting the values of τ and C in the above formula, we get:
R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)
R = 220 Ω
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Which two statements are true of electromagnetic waves?
DA. They do not need a medium to transfer energy.
DB. They travel by causing particles of matter to vibrate.
C. They need a medium to transfer energy.
DD. They transfer energy by disturbing electric and magnetic felds.
Answers
Answer:
AD
Explanation:
electromagnetic waves do not need a medium to travel, examples are ultraviolet radiation and infrared radiation.
Answer:
A and D
Explanation:
Just did it
What is the approximate base of the cumulus clouds if the surface air temperature at 1,000 ft MSL is 70 F and the dewpoint is 48 F?
a) 4,000 ft MSL
b) 5,000 ft MSL
c) 6,000 ft MSL
Answers
c) 6,000 ft MSL is the approximate base of the cumulus clouds if the surface air temperature at 1,000 ft MSL is 70 F and the dewpoint is 48 F.
This is the mean elevation of the ocean's surface. The accumulation of water from melting land-based glaciers and glaciers, as well as the augmentation of seawater as it warms, are the primary causes of global mean sea level rise.
The Kanchenjunga peak has been India's tallest mountain, rising over 8.5 thousand meters above sea level. It has five peaks and borders Nepal and India. This one was preceded by Nanda Devi, who stood at approximately 7.8 thousand meters.
MSL is an abbreviation for mean sea level. It is used as one of many altitude determinants by both aircraft and drone pilots. It is, however, not a standard measure that defines the space above.
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A force of 16 lb is required to hold a spring stretched 4 inches beyond its natural length. How much work is done in stretching it from its natural length to 10 inches beyond its natural length?
Answers
The work done in stretching the spring from its natural length to 10 inches beyond its natural length is 112 lb·in.
The work done in stretching a spring is given by the formula:
\(\[ W = \frac{1}{2} k (x_f^2 - x_i^2) \]\)
In this case, the spring is stretched 4 inches beyond its natural length, so the initial displacement is 4 inches. The force required to hold the spring at this displacement is 16 lb. We can use Hooke's Law to find the spring constant:
\(\[ k = \frac{F}{x_i} = \frac{16 \, \text{lb}}{4 \, \text{in}} = 4 \, \text{lb/in} \]\)
Now, we can calculate the work done in stretching the spring to 10 inches beyond its natural length:
\(\[ W = \frac{1}{2} (4 \, \text{lb/in}) \left( (10 \, \text{in})^2 - (4 \, \text{in})^2 \right) = 112 \, \text{lb·in} \]\)
Therefore, the work done in stretching the spring is 112 lb·in.
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A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Answers
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m
The force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires. If a force of 0.750 N exists between wires that are 1.75 cm apart, what is the force between them if they are separated by 2.50 cm?
Answers
the force between the two wires if they are separated by 2.50 cm is 0.525 N.
Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.
Let the initial force be F₁ and the initial distance be d₁.
Therefore, we can write the relationship between force and distance as;
F₁d₁ = F₂d₂
Where
;F₁ = 0.750 N (initial force)
d₁ = 1.75 cm (initial distance)
F₂ = ? (force at new distance)
d₂ = 2.50 cm (new distance)
Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂
Now substitute the values we know;
F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N
Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.
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Use this media to help you complete the question.
After placing the weight on the scale, use all three balance slides on the scale to determine the exact mass of the object.
589.0 g
589.30 g
589.38 g
589.3 g
Answers
Answer:
589.3 g is the answer
Explanation:
Answer:
The answer for this would be 589.3g
HELP
Match the term and the definition
Lesson 1.09
Question 5 options:
Cold Front
Stationary Front
Warm Front
Occluded Front
1.
When a cold air mass and a warm air mass meet but are at a standstill, the boundary is called
2.
If warm or more humid air presses forward and colder or drier air draws back, the boundary is called
3.
If colder or drier air presses forward and warmer or more humid air draws back, the boundary is called
4.
Sometimes a warm air mass can get caught between two cold fronts, which can force the warm air up into a wedge shape.
Answers
Answer:
Cold Front 3 // Stationary Front 1 // Warm Front 2 // Occluded Front 4
Explanation:
It's simple. Warm front means the warm air is pressing forward, which is why it's a warm front. Stationary Front, meaning they're at a standstill, also makes sense because stationary means not moving. Then since your last option is Occluded Front, since the others already have an answer, you have no choice but to match 4 with it. I took the quiz and got the answer right. :D
16. Cassandra notices that when she breathes on a cool window, the water vapor in her breath forms
liquid water. What happens to turn the water vapor in her breath into liquid water?
A. Heat is added to the water vapor from the surrounding air.
B. The temperature of the water vapor increases as it leaves her body,
C. The water molecules become more spread apart as they touch the window.
D. Heat leaves the water vapor as it touches the cool window.
Answers
Answer: A
Explanation:I studied .
An athlete spins in a circle and throws a 1.6-kg discus. The radius of the discus's path is 1.0 m, and he releases it with an angular speed of 15.0 rad/s. The athlete spins for a total of 1.2 s before releasing the discus.
– What is the tangential speed of the discus at release?
– What is the centripetal acceleration of the discus?
– What is the centripetal force on the discus?
giving Brainliest for full and proper answers! thank you for anyone who tries to help/explain :)
Answers
(a) The tangential speed of the discus at the release is 15 m/s.
(b) The centripetal acceleration of the discus is 225 m/s².
(c) The centripetal force on the discus is 360 N.
The given parameters;
mass of the discus, m = 1.6 kgradius of the path, r = 1 mangular speed, ω = 15 rad/stime of motion, t = 1.2 sThe tangential speed of the discus at the release is calculated as follows;
\(v = \omega r\\\\v = 15 \ rad/s \ \times 1 \ m\\\\v = 15 \ m/s\)
The centripetal acceleration of the discus is calculated as follows;
\(a_c = \frac{v^2}{r} \\\\a_c = \frac{15^2}{1} \\\\a _c = 225 \ m/s^2\)
The centripetal force on the discus is calculated as follows;
\(F_c = ma_c\\\\F_c = 1.6 \times 225\\\\F_c = 360 \ N\)
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20) How can electromagnetic radiation disrupt communication tools on a spacecraft?
Answers
Answer: Electromagnetic radiation, such as solar flares and other forms of radiation in space, can disrupt communication tools on a spacecraft in several ways.
First of all, it can obstruct radio signals that the spacecraft uses to connect with Earth, resulting in a signal loss or a decline in the signal's quality. When the radiation disrupts the amplifiers and receivers, which are electronics that process the signals, this can occur.
The spacecraft's computer memory may experience single-event upsets (SEUs) as a result of electromagnetic radiation. A high-energy particle striking a memory cell results in a bit flip and a SEU, which can destroy data, cause software to crash, or create other issues.
The spacecraft's solar panels and other electrical components are susceptible to harm from electromagnetic radiation, which might impair power and communication.
Spacecraft designers frequently use shielding materials and redundant communication systems to reduce the impacts of electromagnetic radiation and make sure the spacecraft can keep operating even if one system fails.
Explanation:
I don't understand how to do this?
Answers
Workers who use compressed air for cleaning should limit pressure to _____ PSI.
a. 30
b. 45
c. 60
d. 85
Answers
Option A i.e. 30PSI should be the limit of pressure for workers who use compressed air for cleaning.
Workers who use compressed air for cleaning should limit pressure to 30 PSI. This is to prevent injury and damage to equipment. Higher pressures can cause serious harm to the eyes, ears, and skin, as well as dislodge particles that can become projectiles. It's important to follow proper safety guidelines when using compressed air for cleaning. High-pressure compressed air can cause serious injuries, including skin and eye damage, hearing loss, and even death.
The pressure at which the air is discharged is a critical factor in determining the risk level. The Occupational Safety and Health Administration (OSHA) recommends that workers limit the pressure of compressed air for cleaning to no more than 30 psi (pounds per square inch). This is because compressed air at a pressure of 30 psi or more can penetrate the skin and enter the bloodstream, causing serious harm, including death.
So, the correct answer is option A i.e. 30PSI should be the limit of pressure for workers who use compressed air for cleaning.
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3.
If the specific heat of iron = 0.46 J/g Cº, how much heat is needed to warm 50 g of
iron from 20° C to 100° C?
Answers
Answer:
1.84 kJ (kilojoules)
Explanation:
A specific heat of 0.46 J/g Cº means that it takes 0.46 Joules of energy to raise the temperature of 1 gram of iron by 1 Cº.
If we want to heat 50 g of iron from 20° C to 100° C, we can make the following calculation:
Heat = (specific heat)*(mass)*(temp change)
Heat = (0.46 J/g Cº)*(50g)*(100° C - 20° C)
[Note how the units cancel to yield just Joules]
Heat = 1840 Joules, or 1.84 kJ
[Note that the number is positive: Energy is added to the system. If we used cold iron to cool 50g of 100° C water, the temperature change would be (Final - Initial) or (20° C - 100° C). The number is -1.84 kJ: the negative means heat was removed from the system (the iron).
32. Use billiard balls to model the motion of particles in a gas. Use students in a crowded
hallway to model the motion of particles in a liquid. Use an audience in a movie theater to model the
motion of particles in a solid.
55
Answers
The particles of a solid are in fixed positions, the particles of a liquid do not translate to a large extent while the particles of a gas has extreme degree of freedom.
What are particles?We have to refer to the kinetic molecular theory at this point. We would recall from the theory that the particles that compose a substance are said to be in a constant random motion. As such, the molecules of a gas do have the greatest degree of freedom thus they move about freely. On the other hand, the molecules that compose a solid have the least degree of freedom as they remain in their fixed positions and can only vibrate.
Billiard balls are free to have about and they move at high speeds since they are spaced from each other. This is the nature of the interaction between the molecules of a gas.
Students in a hall way that is crowded can be used to approximate liquid particles because they do not posses a high degree of freedom but the molecules could move a few inches away from each other.
For a solid. an apt approximation is the audience in a movie theater. This is because, they can only remain on their seats just as the particles in a solid retain a fixed position and do not translate.
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The direction of the electric field is in the direction that a
_______ test charge would be pushed or pulled if placed in the space surrounding the source charge.
Answers
Answer:
The correct answer is Positive
Explanation:
Put the word POSITIVE
Question 7 of 10
Which of the following phrases best describes the term scientific model?
A. The application of scientific knowledge to make predictions about
an object, system, or process
B. An experiment in which variables are controlled
C. A physical copy of a scientific object, system, or process
OD. A simplified representation used to explain or make predictions
about something
Answers
The following phrase that best describes the term scientific model is D. a simplified representation used to explain or make predictions about something.
A scientific model is not a physical copy of a scientific object, system, or process, nor is it an experiment in which variables are controlled. Rather, it is a simplified representation that helps scientists better understand complex phenomena. Scientific models can take many forms, including mathematical equations, computer simulations, diagrams, and physical models. These models are based on scientific observations and data, and they can be used to make predictions about how a system will behave under different conditions.
For example, climate models are used to predict how the Earth's climate will change over time based on factors like greenhouse gas emissions and solar radiation. Overall, scientific models are essential tools for scientists who seek to understand complex phenomena and make predictions about the natural world. By simplifying complex systems and processes, these models allow scientists to test hypotheses, make predictions, and develop new theories. So therefore the correct answer is D. a simplified representation used to explain or make predictions about something.
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A spring has a force of 2.0N and an extension of 0.30m. What will the extension be if the force applied is 6 N.
Will mark as brainliest
Answers
Answer:
0.9 m
Explanation:
Hooke’s Law
\(\large\boxed{F = ke}\)
where:
F is the force in newtons (N).k is the 'spring constant' in newtons per metre (N/m).e is the extension in metres (m).Given values:
F = 2.0 Ne = 0.30 mSubstitute the given values into the formula to find k:
\(\implies 2.0=0.30k\)
\(\implies k=\dfrac{2.0}{0.30}\)
\(\implies k=\dfrac{20}{3}\; \sf N/m\)
To find the extension if the force applied is 6 N, substitute the found value of k and the given value of F into the formula and solve for e:
\(\implies 6=\dfrac{20}{3}e\)
\(\implies 18=20e\)
\(\implies e=\dfrac{18}{20}\)
\(\implies e=0.9\; \sf m\)
(A): Find the currents I1, I2, I3, I4, and the voltage v, in the circuit of figure (2.1). [Hint: Use Nodal analysis method (Node-voltage method)]. [5 Marks] vo 11 12 13 14 20 A 15 22 20 Ως 25 Ω 4 A 50 Ω W Figure (2.1)
Answers
To find the currents and voltage in the circuit of figure (2.1), we can use nodal analysis or the node-voltage method.
First, we need to identify the nodes in the circuit. From the diagram, we can see that there are four nodes: node 1 (connected to the voltage source), node 2 (connected to the 20-ohm resistor and the current source), node 3 (connected to the 15-ohm resistor and the 22-ohm resistor), and node 4 (connected to the 25-ohm resistor).
Next, we can apply Kirchhoff's current law (KCL) at each node to write equations for the currents flowing into and out of each node. We can use Ohm's law to relate the voltages and resistances to the currents.
At node 1, the current flowing out is equal to the current flowing into node 2, so we have:
(11-v)/20 + 4 = (v-12)/50 + (v-13)/25
Simplifying and solving for v, we get:
3v - 340 = 4v - 196
v = 144 volts
Now we can use this value of v to find the currents at each node.
At node 1:
I1 = (11-v)/20 = -6.5 amps
At node 2:
I2 = (v-12)/50 - 4 amps
At node 3:
I3 = (v-13)/25 - (v-22)/20
Simplifying and substituting v, we get:
I3 = -2.32 amps
At node 4:
I4 = (v-22)/20 - (v-15)/22
Simplifying and substituting v, we get:
I4 = 2.64 amps
Therefore, the currents in the circuit are:
I1 = -6.5 amps
I2 = -4 amps
I3 = -2.32 amps
I4 = 2.64 amps
And the voltage in the circuit is:
v = 144 volts.
Note: The negative sign for some of the currents indicates that they are flowing in the opposite direction to the assumed direction.
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I want you to.......
Explain the Michelson-Morley experiment.
And please explain the equations.
Please ☺️❤️
Answers
Answer:
Michelson reasoned that, if the speed of light were constant with respect to the proposed ether through which Earth was moving, that motion could be detected by comparing the speed of light in the direction of Earth's motion and the speed of light at right angles to Earth's motion.
Use the following information to answer the next question.
Intensity vs. Wavelength of Electromagnetic Radiation Incident on Planet Omega
Creatures that live on Planet Omega have antennae that are sensitive to the most common type of electromagnetic radiation on the planet. From the graph above, the antennae of these creatures are most sensitive to wavelengths that range from
A) 1.0 x10^-7 m to 2.0 x10^-8 m
B) 3.0x10^-8 m to 5.5 x 10^-8 m
C) 7.0x 10^-8 m to 8.5 x 10^-8 m
D)8.5x 10^-8 m to 1.0 x 10^-7 m
Answers
Answer:
C) 7.0x10^-8 m to 8.5x10^-8 m.
Explanation:
Based on the given information, the antennae of the creatures on Planet Omega are most sensitive to wavelengths that range from 7.0x10^-8 m to 8.5x10^-8 m.
a car travels at a constant speed of 20m/s and yet it does not have a constant velocity. explain how this could be
Answers
Answer:
HOPE THIS HELPS!!
Explanation:
Velocity is speed as well as distance mentioned.
The car is traveling at a constant speed of 20m/s but it may not be traveling in any particular direction. It would be taking many turns (left and right) or it would be moving in a circular manner.
So,it is at constant speed but not constant velocity.
Thanks for helping!!!------>
a 15.3 g bullet moving with a speed of 372 m/s. Answer in units of kg · m/s.
Answers
Answer:
56.916 kg m/s
Explanation:
Convert g to kg 15.3 g = .153 kg
.153 kg * 372 m/s = 56.916 kg*m/s
Suppose you sound a tuning fork at the same time you hit a 1053-Hz note on the piano and hear 3 beats/sec. You tighten the piano string very slightly and now hear 4 beats/sec. What is the frequency of the tuning fork?
Answers
There are two possible frequencies for the tuning fork: 1050 Hz and 1056 Hz.
How to find the frequency of the tuning fork?To solve this problem, we can use the concept of beat frequencies. When two sound waves with slightly different frequencies are played together, we perceive a fluctuation in loudness known as beats. The beat frequency is equal to the absolute difference between the frequencies of the two waves.
Let's denote the frequency of the tuning fork as "f" (in Hz). According to the problem, when the tuning fork frequency and the piano note frequency (1053 Hz) are played together, we hear 3 beats per second. When the piano string is tightened slightly, the beat frequency increases to 4 beats per second.
Mathematically, we can express the beat frequency as the absolute difference between the frequencies:
|f - 1053| = 3 beats/sec (Equation 1)
|f - 1053| = 4 beats/sec (Equation 2)
To find the frequency of the tuning fork, we need to solve this system of equations. Let's examine the two possible cases:
Case 1: (f - 1053) = 3
Solving for f:
f = 1053 + 3
f = 1056 Hz
Case 2: -(f - 1053) = 3
Solving for f:
-f + 1053 = 3
f = 1050 Hz
Therefore, there are two possible frequencies for the tuning fork: 1050 Hz and 1056 Hz.
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A fault in the switch caused a householder to receive a mild electric shock before a safety device switched the circuit off.
The mean power transfer to the person was 5.75 W.
The potential difference across the person was 230 V.
Calculate the resistance of the person
Answers
The resistance of the person is 9200 Ω if a fault in the switch is caused by a householder to receive a mild electric shock with the mean power transfer to the person as 5.75 W and potential difference across the person as 230 V.
The resistance of the person can be calculated using Ohm’s law.
Ohm’s law states that the potential difference across a conductor is directly proportional to the current flowing through it, provided that its temperature and other physical conditions remain constant.
It can be expressed as: V = IR,
where V is the potential difference, I is the current, and R is the resistance of the conductor.
Rearranging the equation, we get: R = V/ I.
Given that the mean power transfer to the person was 5.75 W and the potential difference across the person was 230 V, the current flowing through the person can be calculated using the formula:
P = IV
where P is the power ,V is the potential difference and I is the current flowing through the person
Rearranging the equation, we get: I = P/V
Substituting the given values, we get:
I = 5.75/230 = 0.025 A
Therefore, the resistance of the person can be calculated as:
R = V/I = 230/0.025 = 9200 Ω
Hence, the resistance of the person is 9200 Ω.
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acceleration can occur when a car is moving at a constant speed. what must cause this acceleration?
Answers
State 3 advantages and 3 disadvantages of using the magnetic
particle method of defect detection.
Answers
The advantages and disadvantages may vary depending on the specific application, material, and the expertise of the personnel conducting the magnetic particle testing.
Advantages of using the magnetic particle method of defect detection:
Sensitivity to Surface and Near-Surface Defects: Magnetic particle testing is highly sensitive to surface and near-surface defects in ferromagnetic materials. It can detect cracks, fractures, and other discontinuities that may not be easily visible to the eye.
Rapid and Cost-Effective: Magnetic particle testing is a relatively fast and cost-effective method compared to other non-destructive testing techniques.
Real-Time Results: The method provides immediate results, allowing for real-time defect detection. This enables quick decision-making regarding the acceptability of the tested components or structures, leading to faster production cycles and reduced downtime.
Disadvantages of using the magnetic particle method of defect detection:
Limited to Ferromagnetic Materials: Magnetic particle testing is applicable only to ferromagnetic materials, such as iron, nickel, and their alloys. Non-ferromagnetic materials, such as aluminum or copper, cannot be effectively inspected using this method.
Surface Preparation Requirements: Proper surface preparation is crucial for effective magnetic particle testing. The surface must be cleaned thoroughly to remove dirt, grease, and other contaminants that can interfere with the test results. This additional step may require additional time and effort.
Limited Detection Depth: Magnetic particle testing is primarily suited for detecting surface and near-surface defects. It may not be as effective in detecting deeper or internal defects. Other non-destructive testing methods, such as ultrasonic testing or radiographic testing, may be more appropriate for inspecting components with deeper or internal flaws.
It's important to note that the advantages and disadvantages may vary depending on the specific application, material, and the expertise of the personnel conducting the magnetic particle testing.
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What is potential mechanical energy
Answers
If a car travels 23.8 meters in 4.2 seconds, what is its speed?
Put your units in the form of a correct abbreviation (example, write s for seconds, m
for meters, or m/s for meters per second).
Answers
Initial velocity * time = 0 since we assume that the car is launching from start without motion.
So, displacement = 0.5 * acceleration * time ^ 2
23.8 = 0.5 * acceleration * 4.2^2
23.8 = 0.5 * 17.64 * acceleration
23.8 = 8.82 * acceleration
23.8/8.82 = acceleration = 2.69 m/s^2
Final Velocity = initial velocity + acceleration * time
Final velocity = 0 + 2.69 * 4.2 = 11.3 m/s
Part C
Just like in the diagram, when Earth was primarily liquid, it separated into layers. What prediction can you make about the
densities of Earth's different layers?
Answers
When the Earth was primarily liquid, it separated into layers. The density of Earth's different layers may be predicted. For instance, it is assumed that the outermost layer, or crust, is less dense than the inner layers.
The Earth's crust is mostly composed of silicates (such as quartz, feldspar, and mica) and rocks, which are less dense than the mantle, core, or outer core.
The mantle is composed of solid rock, which is denser than the Earth's crust.
The core is the most dense layer, and it is composed of a liquid outer core and a solid inner core.
Most of the Earth's layers are composed of different types of rock and minerals.
The layers were formed from the molten material that cooled and solidified.
The Earth's layers are divided into four groups, or spheres, that represent different levels of density.
The lithosphere is the outermost layer, which includes the crust and upper mantle.
The asthenosphere is the soft layer beneath the lithosphere.
The mantle is a solid layer that surrounds the core.
The core is the Earth's central layer, consisting of a liquid outer core and a solid inner core.
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