plsss helpppppp im begign reward brainleistttt

The integer that matches the situation I go for a hike in Colorado. The top of the mountain is feet above sea level is 14000.

A number system is defined as a system of writing to express numbers.

Given,

I go for a hike in Colorado. The top of the mountain is ___ feet above sea level.

We need to find the suitable integer in the blank.

The top of a mountain would be a high number above sea level, 144 is around ground level above sea level therefore the top of the mountain would be 14,000 feet above sea level

Hence, the integer that matches the situation I go for a hike in Colorado. The top of the mountain is feet above sea level is 14000.

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Answer: Another way to look at it is that the rectangle was reduced in a factor of 5 (1/0.2=5)

don't forget to drop a heart hope it helped

Step-by-step explanation:

Answer: 1/0.2=5

Step-by-step explanation:

I hope this helps if you guys need a reach out to me :)

Answer: the last question at the very bottom

Step-by-step explanation:

the graph is not a scatter plot, so its a line plot .

For the box and whiskers plot for the following set of data the value of Min is 3, Q1 is 6, Med is 12, Q3 is 14.5 and Max is 17.

Box and whiskers plot is the way of representation of data which gives the graphical image of the data set to understand better. In this the data is represented with the help of quartile.

The minimum and the maximum values in the box plot is plotted at the end points.

The following set of data which i s given in the problem.

3, 4, 5, 6, 6, 7, 7, 12, 13, 14, 14, 15, 15, 16, 17

Min: 3

The minimum value in the given data is 3. Thus, the min is 3.

Q1:6

First quartile appears at 6. Thus, the value of Q1 is 6.

Med:12

The middle value of the given data is 12 which appears at the center of all the values. Thus the med is 12.

Q3:14.5

Second quartile appears at 14.5. Thus, the value of  second quartile Q2 is 6.

Max: 17

The minimum value in the given data is 17 as shown in the image attached below. Thus, the min is 17.

Hence, for the box and whiskers plot for the following set of data the value of Min is 3, Q1 is 6, Med is 12, Q3 is 14.5 and Max is 17.

The complete question is : Answer the statistical measures and create a box and whiskers plot for the following set of data. You may optionally click and drag the numbers into numerical order.

3, 4, 5, 6, 6, 7, 7, 12, 13, 14, 14, 15, 15, 16, 17

3,4,5,6,6,7,7,12,13,14,14,15,15,16,17

Min:

Q1:

Med:

Q3:

Max:

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Answer:

81 + 81 + 10 aka 172

Step-by-step explanation:

Answer:

172

Step-by-step explanation:

z = 9

9 to the second power is 81

9 times 9 is 81

plus 10

= 172

hope this helps dude

Answer:

4/9 sq yard

Step-by-step explanation:

Answer:

the answer is 6/7

Step-by-step explanation:

Explanation

By definition.

so

Let

hence

I hope this helps you

Answer:

multiply the numbers

Step-by-step explanation:

I'm not really sure how to explain it

The slope of the points is 0 when the line passing through the points (-2, 1) and in its point-slope form (0, 1).

Given that,

The line passing through the points (-2, 1) and in its point-slope form (0, 1). Recognize (x₁, y₁) as (-2, 1).

We have to find to submit all of your calculations and complete responses.

We know that,

The point passing through the other point.

We can find the slope.

Slope is rise/run.

The points are (-2,1) and (0,1)

m is 1-1/0+2

m is 0/2

m is 0

Therefore, The slope of the points is 0 when the line passing through the points (-2, 1) and in its point-slope form (0, 1).

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We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

Where (from tables):

Finally, the interval at 98% confidence level is:

Given that sec(t) = -2.475 and angle t is in Quadrant III, the other five trigonometric ratios are as follows: cos(t) ≈ 0.404, sin(t) ≈ -0.916, tan(t) ≈ 2.268, csc(t) ≈ -1.092, and cot(t) ≈ 0.441.

We are given that sec(t) = -2.475, which represents the reciprocal of the cosine of angle t. Since sec(t) is negative and angle t is in Quadrant III, we can deduce that the cosine of t is negative. To find cos(t), we can use the identity sec(t) = 1/cos(t) and solve for cos(t), resulting in cos(t) ≈ 0.404.

Using the Pythagorean identity \(sin^2(t) + cos^2(t)\) = 1, we can find sin(t) as sin(t) = ±\(\sqrt(1 - cos^2(t))\). Since angle t is in Quadrant III, where sine is negative, we take the negative value. Thus, sin(t) ≈ -0.916.

By dividing sin(t) by cos(t), we obtain the tangent of t. Hence, tan(t) ≈ sin(t)/cos(t) ≈ -0.916/0.404 ≈ 2.268.

Cosecant (csc) is the reciprocal of sine, so csc(t) ≈ 1/sin(t) ≈ -1.092.

Similarly, cotangent (cot) is the reciprocal of tangent, so cot(t) ≈ 1/tan(t) ≈ 1/2.268 ≈ 0.441.

In conclusion, when sec(t) = -2.475 and angle t is in Quadrant III, the other five trigonometric ratios are approximately: cos(t) ≈ 0.404, sin(t) ≈ -0.916, tan(t) ≈ 2.268, csc(t) ≈ -1.092, and cot(t) ≈ 0.441.

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This option correctly describes that the function is defined for x-values that satisfy the inequality x - 5 < x < 3. It also states that the range of the function is {-2}, which is not accurate since the range of the function includes multiple values from 1 to 6, inclusive.

Based on the given information, it seems that the linear function is represented by the points (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1). To determine the domain and range of the function, we need to analyze the set of possible inputs (x-values) and the set of possible outputs (y-values) in the function.

The domain of a function refers to the set of all possible input values for the function. In this case, it appears that the function is defined for all values of x between 1 and 6, inclusive. Therefore, the domain can be represented as: Domain: {x | 1 ≤ x ≤ 6}.

The range of a function, on the other hand, refers to the set of all possible output values. Looking at the given points, we can observe that the y-values range from 1 to 6. Therefore, the range can be represented as: Range: {y | 1 ≤ y ≤ 6}.

From the given answer choices, the option that accurately represents the domain and range of the linear function is:

G Domain: {x | x - 5 < x < 3}

Range: {-2}

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The angles of a triangle with side lengths 5 , 12 and 13 are 90°, 22.63°, 67.38°.

In trigonometry, the law of cosines, also known as the law of cosines or cosine formula, basically relates the length of a triangle to one cosine of its angle. It states that if we know the lengths of two sides of a triangle and the angle between them, we can determine the length of the third side. c² = a²+ b² – 2ab cosγ

where a, b, c are the sides of the triangle and γ is the angle between a and b, see image above.

To find the length of a side of a triangle, take △ABC according to the cosine formula, which can be written as follows.

We have , a = 5 , b = 12 , c= 13

cos α =( 12² + 13² - 5² )/2×12×13= 288/312

=> α = cos⁻¹(0.923 ) = 22.63°

cos β = (5² + 13² - 12² )/2×13×5 = 50/130

=> β = cos⁻¹(5/13) = 67.38°

cos γ = (12² + 5² - 13² )/2×12×5= 0

=> γ = cos⁻¹(0) = 90°

Hence, the required angles are 90°, 22.63°, 67.38°.

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Answer:

3m+4g+6+k

Step-by-step explanation:

Answer:

170

Step-by-step explanation:

8x2 is 16 plus 1 is 17 times 10 is 170. PEMDAS

Answer:

No for both

Step-by-step explanation:

If 2 x values that are the same but different y values for them then its not a function

The triangle and its image are added as attachment

From the question, we have the following parameters that can be used in our computation:

A(1, 2) , B(3, 1) and C(1,- 1)

Also, we have

The translation ( x - 2 . y + 3 )

To perform a translation on a figure, we need to add -2 to the x-coordinate and 3 to the y-coordinate of each point.

i.e.

(x, y) = ( x - 2 . y + 3 )

So, we have

A(1 - 2, 2 + 3) , B(3 - 2, 1 + 3) and C(1 - 2,- 1 + 3)

This gives

A'(-1, 5), B'(1, 4), and  C'(-1, 2).

See attachment for the figure

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Answer:

52, if I understand the question correctly.

Step-by-step explanation:

Is this:

3ab + 2b

and we want to know the value when a = -5 and b = 4?

If so:

3ab + 2b

3(-5)(4) + 2(4)

-60 + 8 = -52

-52, if I understand the question correctly.

3ab + 2b

and we want to know the value when a = -5 and b = 4

If so:

3ab + 2b

3(-5)(4) + 2(4)

-60 + 8 = -52

Values 3ab + 2b ​​are fundamental and fundamental beliefs that guide and motivate attitudes and actions. They help us determine what is important to us. Value is the goods, services or monetary value of a thing or person. An example of value is the amount an appraiser declares after appraising a home. An example of value is the value of a consultant's contribution to a committee. noun.

Values ​​reflect our sense of right and wrong. They help us grow and develop. They help shape the future we want. The choices we make every day reflect our values.

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Observe the graph .

Y intercept=3

More:-

Slope intercept form

Where

The number of cars that pass through the intersection between 6 am and 9 am is 10,500 cars.

To find the number of cars passing through the intersection between 6 am and 9 am, we need to integrate the given traffic flow rate function r(t) from t=0 (6 am) to t=3 (9 am). Therefore, we have:

∫(r(t) dt) = ∫(400 + 900t - 150t² dt) [Limits: 0 to 3]

= [400t + 450t² - 50t³/3] from 0 to 3

= [400(3) + 450(3)² - 50(3)³/3] - [400(0) + 450(0)² - 50(0)³/3]

= 1200 + 4050 - 450

= 10,500 cars

Therefore, 10,500 cars pass through the intersection between 6 am and 9 am.

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Answer:

answer is a

Step-by-step explanation:

The accounting equation is a fundamental principle in accounting that states that assets equal liabilities plus equity. Using this equation, missing amounts can be determined in various situations.

The accounting equation is expressed as Assets = Liabilities + Equity. It serves as the foundation for double-entry bookkeeping and ensures that the financial statements are balanced. By rearranging the equation, missing amounts can be determined.

For example, if the assets and equity are given, the missing amount of liabilities can be calculated by subtracting equity from assets. Conversely, if the liabilities and equity are known, the missing amount of assets can be calculated by adding liabilities to equity.

Similarly, if the assets and liabilities are provided, the missing amount of equity can be calculated by subtracting liabilities from assets. Alternatively, if the assets and equity are known, the missing amount of liabilities can be calculated by subtracting equity from assets.

In each situation, the missing amount can be determined by applying the accounting equation and rearranging it to solve for the missing variable. This equation provides a framework for ensuring that all financial transactions are properly recorded and that the financial statements accurately reflect the financial position of a business.

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Thus, there is a 71.95% chance that a randomly selected amateur player in the tournament is not in the top 40 golfers in the world.

The first step in solving this problem is to use the given information to calculate the proportion of players who are both amateurs and ranked in the top 40 golfers in the world.

Since being a top 40 golfer and being an amateur are mutually exclusive, the proportion we're interested in is the proportion of amateur players who are not in the top 40.

We know that 15% of players are in the top 40, so 85% of players are not. We also know that 67% of players are amateurs, so 33% of players are not. To find the proportion of amateur players who are not in the top 40, we can multiply these two proportions:

0.85 x 0.33 = 0.2805

So, 28.05% of players in the tournament are amateurs who are not in the top 40.

Now, we can use this proportion to answer the question of what the probability is of selecting an amateur player who is not in the top 40, given that the player is an amateur. This is simply the proportion we just calculated:

P(amateur and not top 40) = 0.2805

Therefore, the probability of selecting an amateur player who is in the top 40 is:

P(top 40 | amateur) = 1 - P(amateur and not top 40)
= 1 - 0.2805
= 0.7195 or 71.95%

In other words, there is a 71.95% chance that a randomly selected amateur player in the tournament is not in the top 40 golfers in the world.

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The cost of each pizza is $12.50 while the cost of each drink is $1.99.

An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the cost of each pizza and y the cost of each drink. Hence:

3x + 5y = 47.45  (1)

Also:

4x + 8y = 65.92  (2)

From both equations:

x = 12.5, y = 1.99

The cost of each pizza is $12.50 while the cost of each drink is $1.99.

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The statement that is true about Sheila's savings plan is that; C.

Sheila must save $60 per month to achieve her goal.

The price of bathroom remodeling is $ 810.

After 13 months , she has saved $ 510

This means that she has a $300 shortage to cover in 5 months.

This means that she need to save :

$300/5  = $60 / month in order to achieve her goal

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Answer: C

Step-by-step explanation: edge

Using ratios and assuming the given values, the rate of the total cost for items in the United Kingdom to that of the total cost of items in Australia is 2/3.

Assume that the costs are:

The ratio would be:

So, we have:

Simplify:

Express as rate

Therefore, using ratios and assuming the given values, the rate of the total cost for items in the United Kingdom to that of the total cost of items in Australia is 2/3.

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Answer:

\(5 {x}^{2} - 11x + 6 \\ 5 {x}^{2} - (5 + 6)x + 6 \\ 5 {x}^{2} - 5x + 6x + 6 \\ 5x(x - 1) - 6(x - 1) \\ (5x - 6)(x - 1)\)

a. The sample space S is given by S = {(1, 1), (1, 2), (1, 3), ..., (6, 6)}. f(3), f(4), ..., f(12). The CDF of X can be represented as F(x) = P(X ≤ x). b. c = 1/21.  the probability that an even number appears is 4/7.

(a)

(i) The sample space S for the experiment consists of all possible outcomes when tossing two dice and observing the total of the upturned faces. Each die has six faces numbered 1 to 6. Since there are two dice, we can represent the outcomes as ordered pairs (a, b), where a and b are the numbers on the first and second dice, respectively. The sample space S is given by:

S = {(1, 1), (1, 2), (1, 3), ..., (6, 6)}

(ii) Let X be the discrete random variable representing the total of the upturned faces. To find the discrete density function of X, denoted by f(x), we need to determine the probability of each possible value of X. The total on the upturned faces ranges from 2 to 12. We can calculate the probability of each value by considering all the outcomes in the sample space S. For example, to find f(2), we count the number of outcomes in S where the total is 2 and divide it by the total number of outcomes. Similarly, we can calculate f(3), f(4), ..., f(12).

(iii) The cumulative distribution function (CDF) of X gives the probability that X is less than or equal to a given value. It can be obtained by summing the probabilities of all values less than or equal to the given value. The CDF of X can be represented as F(x) = P(X ≤ x). To find F(x), we calculate the probabilities for each value of X and sum them up for all values less than or equal to x.

(b)

(i) If the die is biased or loaded so that the probability of each face landing upper-most is proportional to the number on the face, then the probabilities of each face can be expressed as P(k) = ck, where k = 1, 2, ..., 6. To find the constant c, we can use the fact that the sum of the probabilities for all possible outcomes must be equal to 1. Therefore, we have:

P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1

c(1) + c(2) + c(3) + c(4) + c(5) + c(6) = 1

c(1 + 2 + 3 + 4 + 5 + 6) = 1

21c = 1

c = 1/21

(ii) The probability that an even number appears can be found by summing the probabilities of the even numbers 2, 4, and 6. Since we know the probabilities for each face P(k) = ck, we can calculate:

P(even) = P(2) + P(4) + P(6)

= c(2) + c(4) + c(6)

= (1/21)(2 + 4 + 6)

= 12/21

= 4/7

Therefore, the probability that an even number appears is 4/7.

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