The data table shows the sound levels of common noise sources.

A 2 column table with 13 rows. Column 1 is labeled sound in decibels with entries 140, 130, 120, 110, 100, 90, 80, 70, 60, 50, 40, 30, 20. Column 2 is labeled noise source with entries jet engine at 25 meters, jet aircraft at 100 meters, rock and roll concert, pneumatic chipper, woodworking machines, chainsaw, heavy truck traffic, business office, conversational speech, library, bedroom, secluded woods, whisper.
Which profession has the greatest risk of sound damage to the ear?

woodworker
librarian
teacher
truck driver

Something that is falsely advertised to help different health issues. An example could be Eyeball massagers

Differences between earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges discussed in the answer.

When plates travel in the same direction and collide, this happens. The thinner, denser, and more flexible oceanic plate dips beneath the thicker, more rigid continental plate when a continental plate meets an oceanic plate. It's known as subduction.

Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction. The continent's undercut rocks start to melt. On occasion, a chain of volcanoes forms as the molten rock rises to the surface and passes through the continent. Nearly 80% of earthquakes happen along convergent borders, when plates are being forced together.

Shallow earthquakes, often less than 30 km deep, occur in small bands adjacent to plate borders along mid-ocean ridges and transform edges. There are earthquakes in subduction zones at various depths, some of which are more than 700 km deep. Because they occur everywhere throughout the subducting slab that stretches beneath the opposing plate, earthquake bands are wider along subduction zones. Wide areas of distributed earthquakes may be associated with collision zones between continents, such as those between the Eurasian plate and the plates to the south of the African, Arabian, and Indian tectonic arcs.

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According to behaviorism, also known as behavioral psychology or conditioning, that is a theory of learning, all behaviors are learned through interaction with the environment, and conditioning.

The concept of conditioning from behavioral psychology states that training or conditioning can alter how an individual or an animal reacts to a stimulus, event, or item. Operant Conditioning was developed by Skinner using the most common example of this, classical conditioning (see below).

Social cognition theory is widely criticized as not being all-encompassing. This implies that the theory's numerous parts might not be connected. For instance, the social-cognitive approach asserts that observant learning or self-efficacy have not yet been linked by researchers.

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Answer:

800 meters

Explanation:

4 x 200 is 800 meters.

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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To create an equivalent 0.15 µF capacitor using only 0.1 µF capacitors, you would need to connect two 0.1 µF capacitors in parallel.

When capacitors are connected in parallel, their capacitances add up. Therefore, by connecting two 0.1 µF capacitors in parallel, the total capacitance becomes 0.1 µF + 0.1 µF = 0.2 µF. However, this exceeds the required capacitance of 0.15 µF.

To achieve the desired capacitance, you can place the two 0.1 µF capacitors in series with each other. When capacitors are connected in series, the reciprocal of the total capacitance is equal to the sum of the reciprocals of the individual capacitances.

In this case, the reciprocal of the total capacitance should be 1/0.15 µF. By rearranging the equation and substituting the given capacitance values, you can calculate the required capacitance for each 0.1 µF capacitor.

1/0.15 µF = 1/(C1) + 1/(C2)

1/0.15 µF = 1/0.1 µF + 1/0.1 µF

1/0.15 µF = 2/0.1 µF

0.15 µF = 0.05 µF

Therefore, each 0.1 µF capacitor should be replaced with a 0.05 µF capacitor. Connecting two 0.05 µF capacitors in series will result in an equivalent capacitance of 0.1 µF. Hence, you would need to connect two 0.1 µF capacitors in series to achieve a total capacitance of 0.15 µF.

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To create an equivalent 0.15 µF capacitor using only 0.1 µF capacitors, you would need to connect two 0.1 µF capacitors in parallel.

When capacitors are connected in parallel, their capacitances add up. Therefore, by connecting two 0.1 µF capacitors in parallel, the total capacitance becomes 0.1 µF + 0.1 µF = 0.2 µF. However, this exceeds the required capacitance of 0.15 µF.

To achieve the desired capacitance, you can place the two 0.1 µF capacitors in series with each other. When capacitors are connected in series, the reciprocal of the total capacitance is equal to the sum of the reciprocals of the individual capacitances.

In this case, the reciprocal of the total capacitance should be 1/0.15 µF. By rearranging the equation and substituting the given capacitance values, you can calculate the required capacitance for each 0.1 µF capacitor.

1/0.15 µF = 1/(C1) + 1/(C2)

1/0.15 µF = 1/0.1 µF + 1/0.1 µF

1/0.15 µF = 2/0.1 µF

0.15 µF = 0.05 µF

Therefore, each 0.1 µF capacitor should be replaced with a 0.05 µF capacitor. Connecting two 0.05 µF capacitors in series will result in an equivalent capacitance of 0.1 µF. Hence, you would need to connect two 0.1 µF capacitors in series to achieve a total capacitance of 0.15 µF.

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Insulating the cable with rubber having a thermal conductivity of 0.15 W/m degree increases the heat flow from the cable to 63.80 W per meter length compared to a non-insulated cable in an atmosphere with a temperature difference of 50 degrees Celsius. The correct option is C.

To determine how the heat flow from the cable is affected by insulation, we need to calculate the heat transfer rate for both the insulated and non-insulated cases. The heat transfer rate can be determined using the formula:

Q = (T2 - T1) / (R_total)

Where:

Q is the heat transfer rate per unit length (W/m),

T2 is the surface temperature of the cable (75 degrees Celsius),

T1 is the ambient temperature (25 degrees Celsius),

R_total is the total thermal resistance.

For the non-insulated case:

R_total = R_convection

For the insulated case:

R_total = R_convection + R_insulation

Let's calculate the heat transfer rate for both cases:

Non-insulated case:

R_convection = 1 / (h * A)

A = 2 * π * r * L (surface area of the cable)

Q_non-insulated = (T₂ - T₁) / (R_convection)

Insulated case:

R_insulation = d / (k * A)

Q_insulated = (T₂ - T₁) / (R_convection + R_insulation)

Given the information:

h = 12.5 W/m² degree

k = 0.15 W/m degree

d = 10 mm = 0.01 m

T₂ = 75 degrees Celsius

T₁ = 25 degrees Celsius

By comparing the heat transfer rates for the non-insulated and insulated cases, we can determine the effect of insulation on the heat flow from the cable.

Therefore, by Calculating the values and comparing the heat transfer rates, we find that the correct option is c) 63.80 W per meter length.

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1)Baby bird cannot fly. Their mother has to feed \bf\underline{them}them

2. Vijay likes riding my bicycle. I sometimes lend \bf\underline{it}it to \bf\underline{him}him

3. Sooraj and I are brothers. \bf\underline{we\:both}weboth share the same bedroom.

4. Ravina isn't well. Dad is taking to the doctor. (No personal pronouns required)

The force exerted by the table on the block is equal to mg/3, which implies that the table is frictionless, since there is no additional force required to overcome friction.

To calculate the potential energy of the block, we need to first choose a zero level of potential energy. Let's assume that the chosen zero level is the surface of the table. Therefore, the height of the block above the zero level is simply the height of the block itself, which we can denote as h'. Therefore, the potential energy of the block is given by:

PE = mgh ÷ 3 = mg(h + h') ÷ 3

where h is the height of the table above the ground. Since the block is at rest on the table, the net force acting on it is zero. Therefore, the gravitational force acting on the block must be balanced by an equal and opposite force from the table, which we can denote as \(F_{table}\). Therefore, we have:

mg = \(F_{table}\)

The work done by the table in lifting the block from the ground to the table is equal to the change in potential energy of the block, which is given by:

W = PE = mg(h + h') ÷ 3

Therefore, we have:

\(F_{table}\) (h + h') = mg(h + h') ÷ 3

Simplifying this equation, we get:

\(F_{table}\) = mg/3

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Answer:

A- The image of the moon on the waters surface is distorted.

Explanation:

The difference between \(C_p\) and \(C_v\) for an ideal gas is equal to the ideal gas constant, R. This means that \(C_p\) is larger than \(C_v\) by a value of 8.314 J/(mol·K), and this difference remains constant for any ideal gas.

In terms of an ideal gas, the relationship between Cp and Cv is determined by the gas's specific heat capacities. Let's explore this further:
\(C_p\) and \(C_v\)  are specific heat capacities for an ideal gas at constant pressure and constant volume, respectively. Specific heat capacity is the amount of heat needed to raise the temperature of a substance by 1 degree Celsius (or 1 Kelvin). The difference between \(C_p\) and \(C_v\) is due to the fact that, under constant pressure, some energy is used to do work by expanding the gas, whereas under constant volume, all the heat energy goes into raising the gas's internal energy.
For an ideal gas, the specific heat capacities \(C_p\)  and \(C_v\)  are related through the following equation:
\(C_p\)  - \(C_v\)  = R
Where R is the ideal gas constant. The value of R depends on the units used, but typically, it is 8.314 J/(mol·K).
Since \(C_p\) and \(C_v\) both depend on the type of gas and its atomic/molecular structure, the difference between them remains constant (equal to R) regardless of the specific values of \(C_p\) and \(C_v\) for a particular gas.

In other words, Cp will always be greater than Cv by an amount equal to R for an ideal gas.
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A new Sunway supercomputer aims to close the "quantum supremacy" gap by achieving real-time simulation of random quantum circuits.

Closing the "quantum supremacy" gap refers to the goal of achieving classical computational capabilities that can simulate the behavior of a random quantum circuit in real-time. Quantum supremacy is a term used to describe the point at which a quantum computer can perform calculations that are beyond the reach of classical computers.

To achieve real-time simulation of a random quantum circuit, a new Sunway supercomputer could potentially play a crucial role. The Sunway supercomputer is known for its high-performance computing capabilities, which can significantly enhance computational power and speed.

However, it's important to note that as an AI language model, I don't have access to the latest developments beyond my September 2021 knowledge cutoff, and I don't have specific information on any recent advancements related to a Sunway supercomputer.

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Answer:

1st: Radiation

2nd: Conduction

3rd: Convection

Explanation:

I actually learned this before in school. Yay

The mechanical energy lost by the car is 246415.84 J.

This can be defined as the energy possessed by a body due to motion or due to its position.

To calculate the mechanical energy lost, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The mechanical energy lost by the car is 246415.84 J.

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Work is characterized as the resultant action when a force moves an object in the force's direction.

It is clear what the word "force" means. The terms "push" and "pull" are perfectly acceptable at this level to describe forces. An object does not have a force inside of it or within it. Another object applies a force to the first.

When two items come into contact with one another physically and interact, these kinds of forces are involved. Frictional, tensional, normal, air resistance, applied, and spring forces are examples of the several types of contact forces.

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Answer:

Mineral Wool

Explanation:

The mineral wool is a porous material that restricts thermal energy by trapping air in.

Insulators, like Mineral Wool, are the material that restricts the flow of electricity or thermal energy.

An electrical insulator is a material that prevents electric current from flowing freely. The electrons in the insulator atoms are tightly bound and cannot move easily. Other materials, such as semiconductors and conductors, conduct electricity more easily.

Insulators are distinguished by their resistivity; insulators have higher resistivity than semiconductors or conductors. Nonmetals are the most common examples.

There is no such thing as a perfect insulator because even insulators contain a small number of mobile charges (charge carriers) that can carry current.

Furthermore, when a sufficiently high voltage is applied, the electric field tears electrons away from the atoms, all insulators become electrically conductive. This is known as an insulator's breakdown voltage.

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The fraction of light from the Sun intercepted and reflected by the Earth is approximately 4.26 x 10⁻⁵.

To calculate the fraction of light from the Sun intercepted and reflected by the Earth, we need to compare the cross-section of the Earth to the area of a sphere centered on the Sun with a radius equal to the radius of Earth's orbit.

The cross-section of the Earth can be calculated as the area of a circle with radius REarth, which is option (c) R Earth.

The area of a sphere centered on the Sun with a radius r is given by 4πr², where r is the radius of the Earth's orbit. Therefore, the area of the sphere centered on the Sun with a radius equal to the radius of Earth's orbit is 4π(149.6 x 10⁶ km)²= 2.83 x 10²³ m².

The ratio of the cross-section of the Earth to the area of the sphere is A1/A2 = πREarth² / 4πr² = (REarth/r)². Using the radius of Earth's orbit in meters, r = 149.6 x 10⁹ m, and the radius of Earth, REarth = 6,371 km = 6.371 x 10⁶ m, we get A1/A2 = (6.371 x 10⁶ m / 149.6 x 10⁹ m)² = 4.26 x 10⁻⁵.

Therefore, by calculating we can say that the fraction of light is approximately 4.26 x 10⁻⁵.

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Answer:

a.  Frequency is 5.45 x 10^14 hz

b.   The period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Explanation:

The velocity of an electromagnetic wave is given by the product of the wave's frequency(f) times its wavelength(λ).  

V = λ f     where,

V is the wave speed,

f is the wave frequency,

λ is the wavelength.

To find frequency, rearrange to:

f = V/ λ

Light travels at 3.00x10^8 m/sec.

λ is 5.50 x 10^-7 m

f = (3.00x10^8 m/sec)/(5.50 x 10^-7 m)  meters cancels, secs is on the bottom]

f = (3.00/5.50)*(10^15)  [The base 10 exponent on the bottom ius subtracted from the one on top:  98-(-7)) = 15)  

f = 0.545 x 10^15 1/s or hz

f = 5.45 x 10^14 hz

b.  The period of a wave is the inverse of it's frequesncy.  It is the time it takes for 1 wave to pass.  Invert the frequency:

 Period = 1/f

  Period =  1/(0.545 x 10^15 1/s)

Period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                   \(\boxed{F=ma}\)

                                                 Δ   Being   Δ

                                             F = Force = 500 N

                                              m = Mass = 15 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

\(\boxed{a=500 \ N / 15 \ kg}\)

⇒ Resolving

\(\boxed{ a = 33.33 \ m/s^{2}}\)

Result:

The aceleration is 33,33 meters per second squared (m/s²)

Good Luck!!

The magnitude of acceleration of box is  \(33.34 \;\rm m/s^{2}\).

Given data:

The mass of box is, m = 15 kg.

The magnitude of applied force is, F = 500 N.

The given problem is based on the Newton's Second law of motion. As per the Newton's Second law, the product of mass of object and the acceleration of object is equal to the magnitude of applied force. Then,

F = ma

500 = 15 (a)

a = 500/15

\(a = 33.34 \;\rm m/s^{2}\)

Thus, we can conclude that the magnitude of acceleration of box is  \(33.34 \;\rm m/s^{2}\).

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The unit most electric companies bill in is kilowatt-hours.

The kilowatt-hour (abbreviated kWh) is an energy unit equal to one kilowatt (1 kW) of power expended for one hour (1 h). The kilowatt-hour is not an official unit of measurement, but it is widely used in electrical applications.

An energy expenditure of 1 kWh represents 3,600,000 joules (3.600x10^6J)

Kilowatt hours (kWh) are the primary units used to quantify electrical power usage; they are what appear on your electricity bill. Because kWh is a measurement of absolute power consumed over time, this unit is used to monitor your usage rather than kilowatts alone. A kilowatt-hour of energy is one kilowatt of power over one hour.

The unit most electric companies bill in is kilowatt-hours.

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The charge q should be divided equally between the two spheres in proportion to their radii, so that the potential energy of the resulting charge distribution is minimized.

To find the charge distribution that minimizes the potential energy of the system, we need to use the principle of superposition. The potential energy of the system is given by:

\($$U = \frac{1}{4\pi \epsilon_0} \int\int \frac{\rho(\mathbf{r}) \rho(\mathbf{r'})}{|\mathbf{r} - \mathbf{r'}|} dV dV'$$\)

where \($\rho(\mathbf{r})$\) and\($\rho(\mathbf{r'})$\) are the charge densities at points \($\mathbf{r}$\) and \($\mathbf{r'}$,\)respectively, and \($\epsilon_0$\) is the permittivity of free space.

Let's assume that the charge \($q$\) is distributed between the two spheres in such a way that the charges on the two spheres are\($q_1$ and $q_2$\), respectively. Then the charge densities on the spheres are given by:

\($$\rho_1 = \frac{q_1}{4\pi r_1^2}$$\)

\($$\rho_2 = \frac{q_2}{4\pi r_2^2}$$\)

Since the spheres are far apart, we can assume that the potential energy of the system is the sum of the potential energies of the charges on the two spheres:

\($$U = U_1 + U_2$$\)

where

\($$U_1 = \frac{1}{4\pi \epsilon_0} \int\int \frac{\rho_1(\mathbf{r}) \rho_1(\mathbf{r'})}{|\mathbf{r} - \mathbf{r'}|} dV dV'$$\)

\($$U_2 = \frac{1}{4\pi \epsilon_0} \int\int \frac{\rho_2(\mathbf{r}) \rho_2(\mathbf{r'})}{|\mathbf{r} - \mathbf{r'}|} dV dV'$$\)

Using the expressions for the charge densities, we can write the potential energies as:

\($$U_1 = \frac{1}{4\pi \epsilon_0} \left(\frac{q_1^2}{2\pi \epsilon_0 r_1}\right)$$\)

\($$U_2 = \frac{1}{4\pi \epsilon_0} \left(\frac{q_2^2}{2\pi \epsilon_0 r_2}\right)$$\)

To minimize the total potential energy of the system, we need to minimize \($U_1 + U_2$\) subject to the constraint that \($q_1 + q_2 = q$\). We can use Lagrange multipliers to solve this constrained optimization problem:

\($$L = U_1 + U_2 - \lambda(q_1 + q_2 - q)$$\)

Taking the partial derivatives with respect to\($q_1$, $q_2$\), and \($\lambda$\) and setting them to zero, we get:

\($$\frac{\partial L}{\partial q_1} = \frac{1}{4\pi \epsilon_0} \left(\frac{q_1}{\epsilon_0 r_1}\right) - \lambda = 0$$\)

\($$\frac{\partial L}{\partial q_1} = \frac{1}{4\pi \epsilon_0} \left(\frac{q_1}{\epsilon_0 r_1}\right) - \lambda = 0$$\)

Therefore, the charge q should be divided between the two spheres in proportion to their radii, so that the potential energy of the resulting charge distribution is minimized.

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The equation to obtain the vertical distance cobered by the object is,

The acceleration due to gravity on saturn is 0.066 m/s2.

Plug in the known values,

Thus, the time taken by object to fall is 17.4 s.

True. In Workspace Mode, it is possible to change the priority of an OCR (Optical Character Recognition) job.

OCR is a process that converts scanned images or printed text into machine-readable text that can be edited and searched. Depending on the size and complexity of the document, OCR jobs can take longer to process than other tasks in Workspace Mode. By changing the priority of the OCR job, users can ensure that it is given higher processing power and completed faster. To change the priority of an OCR job, users can navigate to the "Processing" tab in Workspace Mode and select the OCR job they want to modify. From there, they can adjust the priority level and save the changes. It is important to note that changing the priority of an OCR job may impact the processing of other tasks in Workspace Mode, so users should consider their overall workload before making any adjustments.

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The combined mass of the cessna plane and the passangers, with a potential energy of 800 J is 0.041 kg.

Mass can be defined as the quantity of matter a body contains.

To calculate the combined mass of the cessna plane and passangers, we use the formula below

Formula:

Where:

Make M the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the combined mass of the cessna plane and the passangers is 0.041 kg.

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It is true that a vector's component can vary depending on the chosen coordinate system, that a vector can be multiplied by a scalar, and that a vector can have a component equal to 0 even if its magnitude is not 0.

The idea that a vector cannot have a different direction in different coordinate systems is untrue. A physical quantity that exists without us is represented by a vector. As a result, the vector itself is independent of the coordinate system we use. However, the vector's coordinates are affected by the coordinate system. Only when two vectors have the same magnitude and direction are they regarded as being equal. The coordinate system has no influence on a vector.

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Answer:

94600kgm/s

Explanation:

Linear momentum of a body can be calculated using the formula;

P = mv

Where;

P = linear momentum (Kgm/s)

m = mass of body (kg)

v = speed of the moving body (m/s)

According to the provided information in the question, m = 110kg, v = 860m/s

P = 110 × 860

P = 94600kgm/s

Answer:

i think its b

Explanation:

its been awhile since I've worked on Newton's first law

The image height on the detector will change by a factor of 2 if you change from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocus.

The magnification of a lens is given by the ratio of the image height to the object height. Since the object height remains the same, the change in magnification is solely determined by the change in focal length.

The magnification of a lens is given by the formula:

Magnification = - (image distance / object distance).

Since we are only interested in the ratio of image heights, we can ignore the negative sign.

For the 50-mm lens, the magnification is:

Magnification1 = 50 mm / object distance.

For the 100-mm lens, the magnification is:

Magnification2 = 100 mm / object distance.

Taking the ratio of the two magnifications:

Magnification2 / Magnification1 = (100 mm / object distance) / (50 mm / object distance) = 100 mm / 50 mm = 2.

Therefore, the image height on the detector changes by a factor of 2 when switching from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocusing.

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The number of revolutions the tire makes during this motion, assuming that no slipping occurs is 54 and the final angular speed of a tire in revolutions per second is 12.2 revolutions per second.

Given Data

Initial speed (u) = 0, Final speed (v) = 22.5 m/s, Time (t) = 8.95 s, Diameter of tire (d) = 58.6 cm = 0.586 m, Radius of tire (r) = d/2 = 0.293 m(a)

Number of revolutions the tire makes during this motion: The circumference of the tire is given as:

Circumference = πd = 3.14 x 0.586 = 1.84 m

Since there is no slipping, the distance covered by the car in 8.95 s is given by: d = ut + 1/2 at²,

Where acceleration (a) = (v - u)/t = 22.5/8.95 = 2.51 m/s²

Therefore, d = 0 x 8.95 + 1/2 x 2.51 x (8.95)² = 100 m

The number of revolutions of the tire during the motion can be given by the ratio of the distance covered by the circumference of the tire.

Revolutions = Distance covered/Circumference = 100/1.84 = 54.35 or 54 revolutions (approx.)

(b) The final angular speed of a tire in revolutions per second:

We can use the following formula to find the angular speed of the tire:

v = ωr

Where, v = final velocity, ω = angular velocity, and r = radius of the tire

So, ω = v/r = 22.5/0.293 = 76.8 rad/s

Number of revolutions per second = 76.8/2π = 12.23 or 12.2 revolutions per second (approx.)

Thus, the number of revolutions the tire makes during this motion, assuming that no slipping occurs is 54 and the final angular speed of a tire in revolutions per second is 12.2 revolutions per second.

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