Answer:
579600J
Explanation:
Given parameters:
Height of the building = 828m
Weight of the man = 700N
Unknown:
Work done by the man = ?
Solution:
The work done by the man is the same as the potential energy expended.
Work done:
Work done = Weight x height = 700 x 828
Work done = 579600J
. A 1 m spring requires 10 J to stretch the spring to 1.1 m. How much work would it take to stretch the spring from 1 m to 1.2 m
The amount of work required to stretch the spring from 1 m to 1.2 m is 40 J.
The work required to stretch the spring from 1 m to 1.1 m is 10 J.
The work required by spring is given by Hooke's Law,
W = ∫ Fdx
Here, F = kx , where k = spring constant.
W = ∫ kxdx
W = ∫ kxdx, where lower limit = 0 and upper limit = 0.1.
W = k×(x²)/2,
On evaluating the value of k,
k = 2W/0.01
k = 2000
For stretching the string from 1 m to 1.2 m,
W = ∫ kxdx
W = k∫x²/2
On substituting values of x,
W = {2000×[(0.2)² - (0)²]}/2
W = 40 J
Hence, The work required to stretch the spring from 1m to 1.2 m is 40 J.
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As you look at the side of the wheel, you can see it spinning clockwise. What are the directions of the angular velocity, and angular momentum?
If the torque is applied to the rim, causing the wheel to slow down, what are the directions of the torque and the angular acceleration?
Answer:
The direction of angular velocity and angular momentum are perpendicular to the plane of rotation. Using the right hand rule, the direction of both angular velocity and angular momentum is defined as the direction in which the thumb of your right hand points when you curl your fingers in the direction of rotation.
Explanation:
Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
to further explore what this equation means, consider four sets of identical waves that move in the x direction. a photo is taken of each wave at time t and is displayed in the figures below. rank these sets of waves on the basis of the maximum amplitude of the wave that results from the interference of the two waves in each set. rank from largest amplitude on the left to smallest amplitude on the right. to rank items as equivalent, overlap them.
A. Y max = 2A
B. Y max = A
C. Y max = 0
D. Y max = A
So the order is, (A),(B) = (C),(D)
The maximum displacement or distance moved by means of a factor on a vibrating frame or wave measured from its equilibrium position. it's far identical to at least one-half the period of the vibration course.
For amplitude measurements, you rely the variety of vertical divisions occupied by means of the sign's vertical signal after which multiply with the aid of the vertical scale.
The better the amplitude, the better the power. To summarise, waves convey strength. The quantity of power they bring is associated with their frequency and their amplitude. The better the frequency, the greater electricity, and the better the amplitude, the more strength.
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A) \(y_{max}\) \(= 2A\)
B) \(y_{max}\) \(= A\)
C) \(y_{max}\) \(= 0\)
D) \(y_{max}\) \(= A\)
So the order is
{A), B) = D), C)}
A wave is a disturbance in a medium that transports energy without net movement of particles. This can take the form of elastic deformation, changes in pressure, electrical or magnetic strength, electrical potential, or temperature.
-It transmit energy.
-Usually it involves periodic repetitive movements.
-It does not result in net motion of the medium or particles in the medium
(mechanical waves).
Waves can be periodic, in which these quantities repeatedly oscillate around their equilibrium (rest) values at specific frequencies. If the entire waveform moves in one direction, it is called a traveling wave.
In contrast, a pair of superimposed periodic waves propagating in opposite directions form a standing wave. In a standing wave, the vibration amplitude has a zero point at some point where the wave amplitude appears smaller or even zero.
Waves are often described by the wave equation (the standing wave field of two opposing waves) or the unidirectional wave equation for propagation of a single wave in a defined direction.
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\(Question: $x_{1}=\frac{5}{2}[\sin (2 \pi t)+\cos (2 \pi t)], x_{2}=5\left[\sin \left(2 \pi t+\frac{\pi}{4}\right)\right]$\)
Find the ratio of the amplitude of the given motion?
Options:
\((a) $\sqrt{2}: 1$\\(b) $2: 1$\\(c) $1: \sqrt{2}$\\(d) $1: 2$\)
Condense x₁ to get
sin(2πt) + cos(2πt) = √2 • (sin(2πt) + cos(2πt))/√2
… = √2 (cos(2πt) cos(π/4) + sin(2πt) sin(π/4))
… = √2 cos(2πt - π/4)
So the amplitude of x₁ is (5/2) • √2 = 5/√2, while the amplitude of x₂ is 5. The ratio between them is then 5/√2 : 5, or equivalently 1/√2 : 1 or 1 : √2.
which system works with the respiratory system for the exchange of gases to take place?
Answer:
Circulatory System
Explanation:
The respiratory system works with the circulatory system to provide tis oxygen and to remove the waste products of metabolism. It also helps to regulate PH of the blood. Respiration is the sequence of events that result in the exchange of oxygen and carbon dioxide between the atmosphere and the body cells.
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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4. A 40.0 kg child swings in a swing supported by two chains, each 3.00 m long. If the tension in each at the lowest point is 350N, find (i) The child’s speed at the lowest point ,
The child's speed at the lowest point is 5.42 m/s.
At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.
Using the conservation of mechanical energy, we can write:
Potential energy at highest point = Kinetic energy at lowest point
mgh = (1/2)mv²
where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.
First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:
h = (1/2)3.00 m = 1.50 m
Next, we can solve for the child's speed at the lowest point:
mgh = (1/2)mv²
40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²
588 J = 20.0 kg * v²
v² = 29.4 m²/s²
v = 5.42 m/s
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4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward
with the horizontal.
What is the magnitude of the velocity when it hits the ground?
Answer:
Explanation:
Angle:
β = - 23°
( From the symmetry condition)
If you catch the ruler 4.9 cm from the lower end, what is your reaction time?
Answer:
0.10s
Explanation:
the fall time is
4.9/100=.5*9.81*t^2
solve for t
A teacher is examining laboratory supplies with a diverging lens. The lens has a focal length of magnitude 19.4 cm. The lens is always held between the teacher's eye and the object under study. However, the distance between the lens and the object is different for each object that the teacher observes.
Determine the image location and magnification for each of the following three objects. In addition, determine whether the image is real or virtual, whether it is upright or inverted, and whether it makes the object appear larger or smaller than actual size.
A) The object lies 38.8 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (a).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
B) A) The object lies 19.4 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (b).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
C) A) The object lies 9.70 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (c).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
The answers are (a) |q| = 58.2 cm, M = -1.50, virtual, upright, shrunk; (b) |q| =, M = -, actual, substantially magnified; and (c) |q| = 6.5 cm, M = -1.68, virtual, upright, enlarged.
We can use the magnification formula and the thin lens equation to solve:
Where f is the lens's focal length, d_i is the image distance, and d_o is the object distance, the equation is: 1/f = 1/d_i + 1/d_o.
The formula for magnification is M = -d_i/d_o, where M stands for magnification.
For part (a), the object distance is d_o = -38.8 cm and the focal length is f = -19.4 cm.
1/-19.4 = 1/d_i + 1/-38.8
|d_i| = 58.2 cm
The image is virtual and smaller than the object (since the magnification is less than 1)
For part (b), the object distance is d_o = -19.4 cm, and the focal length is f = -19.4 cm.
1/-19.4 = 1/d_i + 1/-19.4
|d_i| = ∞
The image is at infinity, which means it is a real image and highly magnified (since the object distance is close to the focal length).
For part (c), the object distance is d_o = -9.70 cm, and the focal length is f = -19.4 cm.
1/-19.4 = 1/d_i + 1/-9.70
|d_i| = 6.5 cm
The image is virtual and larger than the object (since the magnification is greater than 1).
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a stone dropps 7,11m how long will it take it to fall
The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Heightu = Initial velocityt = Timeg = Acceleration due to gravityFrom the question,
Given:
u = 0 m/sH = 7.11 mg = 9.8 m/s²Substitute these values into equation 1 and solve for t.
7.11 = (0×t)+9.8×t²/27.11 = 4.9t²t² = 7.11/4.9t² = 1.451t = √1.451t = 1.2 secondsHence, the time it takes the stone to fall is 1.2 seconds.
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True or False:
Some stars appear dimmer than others. Dim stars are always further
away from us than bright stars.
Answer:
A star's brightness also depends on its proximity to us. The more distant an object is, the dimmer it appears.
there are three basic rules of electric charge
The three basic rules for the electric charge are like charges repel each other, unlike charges attract each other and the charges in the system are constant. The unit of charge is coulomb (C).
Electric charge is of two types and they are positive and negative charges. The negative charge is free electrons and the positive charges are the holes in the conductors. The basic rules are, two positive charges repel each other and two negative charges repel each other and they are called like charges.
One positive and one negative charge attract each other and hence they are unlike charges. The attractional force and repulsion force increase with a decrease in the distance of separation. The charges remain constant in the system and it is called as law of conservation of charges in the system.
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The mass of an empty cylindrical tin is
proportional to its surface area.
Two empty cylindrical tins, G and H, are
shown below.
The mass of tin G is 72 g, and the surface
area of tin H is 792π cm².
2
a) Work out the total surface area of tin G in
terms of π.
b) Work out the mass of tin H.
Tin G
12 cm
5 cm
Tin H
Not drawn accurately
a) The total surface area of tin G in terms of π is 170π cm².
b) The mass of tin H is 336 g.
To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.
a) Total surface area of tin G in terms of π:
The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:
Lateral surface area = 2πrh
where r is the radius of the base and h is the height of the cylinder.
In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:
Lateral surface area = 2π(5 cm)(12 cm)
Lateral surface area = 120π cm²
Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:
Area of a circle = πr²
The radius of the circular base of tin G is 5 cm, so the area of each circular base is:
Area of each circular base = π(5 cm)²
Area of each circular base = 25π cm²
To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:
Total surface area of tin G = Lateral surface area + 2 × Area of each circular base
Total surface area of tin G = 120π cm² + 2 × 25π cm²
Total surface area of tin G = 120π cm² + 50π cm²
Total surface area of tin G = 170π cm²
Therefore, the total surface area of tin G in terms of π is 170π cm².
b) Mass of tin H:
We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:
(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)
Using the given values, we have:
(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)
Cross-multiplying and solving for the mass of tin H, we get:
(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)
mass of tin H = (72 g) × (792π cm²) / (170π cm²)
mass of tin H = 336 g
Therefore, the mass of tin H is 336 g.
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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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Calculate the net force on the particle q1.
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
Which group is an international organization which United States is
involved
Answer:
D. The World Bank.
Explanation:
UNDP is an acronym for United Nations Development Programme and it is a global (world) development initiative of the United Nations (UN). The main purpose of the United Nations Development Programme (UNDP) is to provide resources such as loans, grants and training to developing nations in order to improve their technical plans and infrastructural investments. One of the programmes sponsored by the United Nations Development Programme (UNDP) in developing countries around the world is the Sustainable Development Goals (SDGs).
Similarly, The World Bank is an international financial institution that is saddled with the responsibility of providing loans and grants to developing countries just like the United Nations Development Programme (UNDP).
Furthermore, several countries across the world such as Nigeria, Austria, Japan, Germany, United Kingdom, Ghana, Netherlands, Guinea, Brazil, Canada, China, Qatar, Egypt, United States of America, etc.
Hence, the World Bank is an international organization which the United States of America is involved.
How do I solve this problem
Answer:
it is light
Explanation:
the arrow that says light is on the glass it must be near from tungsten
unit 3 test waves sps4 physics need all answers
Answer:
What is the question on the testtt
PLEASE HELP I NEED THE CORRECT ANSWER TODAY
Answer:
The most common oxidation numbers for a given element
In an experiment, a 0.028-kilogram rubber stopper is attached to one end of a string. A student whirls the stopper overhead in a horizontal circle with a radius of 1.0 meter. The stopper completes 10 revolutions in 10 seconds.
22. Determine the speed of the whirling stopper.
23. Calculate the magnitude of the centripetal force on the whirling stopper. [Show all work, including the equation and substitution with units.]
Hi there!
22.
We can calculate the speed by first calculating the period of the stopper.
1 period = time taken for one revolution
10 rev/10 sec = 1 rev/sec
Since it takes 1 second for the stopper to make a complete circle, its velocity can be found using the equation for circumference:
\(v = \frac{2\pi r}{t} = \frac{2\pi (1)}{1} = \boxed{2\pi \approx 6.28 m/s}\)
23.
The centripetal force can be solved for using the following:
\(F_c = \frac{mv^2}{r}\)
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Fc = Centripetal force (N)
Plug in the givens:
\(F_c = \frac{0.028(2\pi)^2}{1} = \boxed{1.105 N}\)
Max (15 kg) and Maya (12 kg) are ice-skating on a frozen pond. While standing at the center of the pond, Maya throws a 1.5-kg snowball at Max and, as a result, recoils away from Max at 2.5 m/s. With what speed did Maya throw the snowball at Max
Answer: The speed at which Maya threw the snowball at Max is 20m/s
Explanation:
Given that
Mass of snowball= 1.5-kg.
Mass of Maya= 12kg
Initial speed of Maya=2.5m/s
We use the law of conservation of momentum to calculate the speed of the snowball which depends on its own mass, the mass of Maya who threw the snowball and the initial velocity at which the snowball was thrown by Maya
Ms x Us = Mm x Um
Mass of snowball x Initial speed of Snow ball =Mass of Maya x Initial speed of Maya
1.5kg x Initial speed of Snow ball =12 kg x 2.5m/s
Initial speed of Snow ball=( 12 kg x 2.5m/s) /1.5kg
Initial speed of Snow ball =20m/s
A toy car is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 2.0 m/s.
What is the final velocity after 8.0
the speed at which a launcher fires tennis balls is constant but the angle between the launcher and the horizontal can be varied. As an angle is decreased from 45° to 30° the range of the tennis balls?
a. increases
b. decreases
c. remains the same
d. can’t be determined
The range of the tennis ball will decreases if the angle is decreased from 45° to 30° .
What is projectile motion?Anything hurled into space with only gravity acting on it is considered a projectile. Gravity is the main factor that influences a projectile. The fact that other forces have a negligible impact in comparison to gravity does not necessarily imply that they do not affect the object. A projectile's trajectory is the path it takes when it travels. One type of projectile is a baseball that has been batted or thrown.
Horizontal range of projectile motion is = \(}\frac{u^{2} sin{2\theta}}{g}\)
Where u is initial velocity, θ is angle of projection and g is acceleration due to gravity.
Now, when the tennis ball fired at \(45^{0}\), the horizontal range is\(}\frac{u^{2} sin{2*45^0}}{g}\) = \(}\frac{u^{2} }{g}\).
And, when the tennis ball fired at \(45^{0}\), the horizontal range is \(}\frac{u^{2} sin{2*30^0}}{2g}\) = \(}\frac{u^{2} }{2g}\).
Hence, by decreasing angle of projection from 45° to 30°, the range of the tennis balls also decreases.
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Q.1 Lorna built the circuit diagram below. All the bulbs are identical. (a) Complete the table below by writing on or off for each bulb.
Answer:
on and off
Explanation:
if there are switches, it can change if the electricity can get to the bulb or not. if it appears that there is no pathway for the electricity to get to the light bulb, it is of, if there is a pathway, its on
explain the statement that what is matters in an experiment is asking the right questions and not finishing the right answer
The statement that what matters in an experiment is asking the right questions and not necessarily finding the right answer potryas the importance of the scientific process and inquiry-based approach.
How do we explain ?The aim of scientific study is to learn about and comprehend the natural world. This is accomplished through developing hypotheses, posing questions, carrying out experiments, and evaluating the outcomes. While getting the right response is critical, it's just as important to ask the right questions in the first place.
Asking the right questions helps to define the scope and objectives of the experiment and also guides the researcher to focus on specific variables, design appropriate experiments, and gather relevant data.
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Calculate the Reynold's number using a viscosity of air as 1.81E-05 kilograms/(meters-seconds), the density of air (see above), the diameter as 0.15 m, and, from the data, 0.89 m/s.
Answer:
8924.6
Explanation:
We are given that
Viscosity of air,\(\eta=1.81\times 10^{-5}kg/m-s\)
Density of air,\(\rho=1.21kg/m^3\)
Diameter,d=0.15 m
v=0.89m/s
We have to find the Reynold's number.
Reynold's number,R=\(\frac{\rho vd}{\eta}\)
Substitute the values then we get
\(R=\frac{1.21\times 0.89\times 0.15}{1.81\times 10^{-5}}\)
R=\(8924.6\)
Hence, the value of Reynold's number=8924.6
Halfway through Mila's run, when the music stopped playing, was there energy in Mila's phone? What is your
evidence?
Answer:
No energy
Explanation: