Tech A says that contact breaker points are a mechanical switch that opens and closes once for every ignition spark that is created. Tech B says that contact breaker points send high voltage directly from the points to the spark plugs. Who is correct?

Answers

Answer 1

Tech A is correct. Contact breaker points are a mechanical switch that opens and closes once for every ignition spark that is created.

Which tech is correct about contact breaker points?

Tech A is correct. Contact breaker points in an ignition system are indeed a mechanical switch that opens and closes to create ignition sparks. They are a crucial component in traditional ignition systems found in older vehicles.

Contact breaker points work in conjunction with a camshaft and distributor to control the timing of the ignition spark. As the camshaft rotates, it opens and closes the contact breaker points, interrupting the primary circuit and creating a spark in the ignition coil. This spark is then sent to the spark plugs via the distributor and ignition wires.

Tech B's statement is incorrect. Contact breaker points do not directly send high voltage from the points to the spark plugs. Instead, they serve as a switch to control the flow of current and initiate the spark in the ignition coil, which then generates high voltage that is distributed to the spark plugs.

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Related Questions

is potential energy and kinetic energy real or is it theoretical and is used to explain how thing work? if it is real than where is potential energy stored? Because energy has to be stored somewhere, like in a plant the energy of the sun is stored in its leaves.

Answers

Potential energy is theoretical in a sense but kinetic energy is not as it can be observed and harnessed potential energy still exist to a certain extent tho as it

Which type of electromagnetic waves make up the colors of a rainbow seen after a storm?

A. visible light
B. infrared light
C. X-rays
D. ultraviolet light

Answers

Answer:

we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.

Hence, option A is correct.

Explanation:

Generally, after the storm, we can witness the presence of a rainbow with our naked eyes. Rainbow, visible to our eyes, consists of all the seven constituent colors of white light. Those seven colors range from violet to red, all having different wavelengths. When water particles present in our atmosphere get exposed to light, all the constituent colors of a white light tend to deviate at a variety of angles. It happens due to their refraction through water particles; thus, a spectrum is obtained.

As we cannot see X-rays, UV rays, and infrared waves through our naked eye, visible light is the kind of electromagnetic wave that makes anyone able to see the objects.  

Please note that all the constitute colors of a beautiful rainbow associate with the visible region of the electromagnetic spectrum.

Therefore, we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.

Hence, option A is correct.

Answer: A.) Visible light

Explanation: Edge 2020 good luck friend ^__^

Hai điện tích đặt cách nhau một khoảng R trong không khí thì lực tương tác
giữa chúng là 2.10−3N. Nếu khoảng cách đó mà đặt trong môi trường điện môi thì
lực tương tác giữa chúng là 10−3N. Để lực tương tác giữa hai điện tích đó khi đặt
trong môi trường điện môi bằng lực tương tác giữa hai điện tích đó khi đặt trong
không khí thì khoảng cách giữa 2 điện tích là bao nhiêu?

Answers

what language are you typing

a flat coil is wrapped with 300 turns of wire on the perimeter of a square frame (side length 20.cm). each turn has the same area as the frame. auniform magnetic field perpendicular to the plane of the coil changes in magnitude at a constant rate from 0.50 t to 0.90 t in 2.0 s. what is the magnitude of the induced emf in the coil while the field is changing?

Answers

The magnitude of the induced emf in the coil while the magnetic field is changing is 15 volts.

We are given that the magnetic field changes from 0.50 T to 0.90 T in 2.0 s. The average rate of change of the magnetic field over this time interval is:

d(B)/dt = (0.90 T - 0.50 T) / 2.0 s = 0.20 T/s

Substituting the known values into the equation for magnetic flux and multiplying by the number of turns in the coil, we get:

Φ = NBA = (300)(0.50 T)(0.20 m²) = 30 Wb

Finally, substituting the magnetic flux and time into Faraday's law, we get:

emf = -dΦ/dt = -(ΔΦ/Δt) = -(30 Wb / 2.0 s) = -15 V

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You own a geotechnical engineering firm in central California and your company has been hired to conduct a slope stability analysis. Consider a 10.0 m-thick mass of regolith (note that this is already measured perpendicular to the slope – so pay attention where you might change the cosine term) sitting on top of a bedrock surface with a slope of 14 degrees. A home is located at the top of this slope (and set back from the edge only 20 m). Upon an initial visit, you determine that the regolith is unsaturated. You also estimate the following additional parameters for this site:

regolith cohesion = 1100 N/m2

regolith angle of internal friction = 15 degrees

density of regolith = 2200 kg/m3 (density of water = 1000 kg/m3 )

a. What is the value for the Factor of Safety? Show your work. Would you consider the slope currently stable? Explain your answer. 4 pts

b. How does the factor of safety change if the water depth increases by 2 m? Does the slope become more or less stable, and by how much? How does this compare to the example above (Part a.)? 3 pts

c. How does the factor of safety change if the angle of internal friction increases by a factor of 2 (this would be the equivalent of changing the material from loose sand to semi-consolidated sediment)? Does the slope become more stable or less stable? 3 pts

d. How does the factor of safety change if the slope is steeper by a factor of 2? Does the material become more or less likely to fail? 3 pts

e. What advice would you give to the homeowners regarding the safety of their home? What remediation can you suggest if any is needed? 3 pts

Answers

The factor of safety for the slope stability analysis needs to be determined for a regolith slope in central California. The parameters provided include regolith cohesion, angle of internal friction, and regolith density. The analysis involves evaluating the stability of the slope under different conditions, such as changes in water depth, angle of internal friction, and slope steepness. Recommendations for the homeowners regarding the safety of their homes and potential remediation measures will also be provided.

To calculate the factor of safety, we need to consider the forces acting on the slope. The driving force is the weight of the regolith, which can be calculated by multiplying the density of the regolith by the volume of the slope. The resisting force is the shear strength of the regolith, which is determined by the cohesion and angle of internal friction. The factor of safety is the ratio of the resisting force to the driving force.

a. To determine the factor of safety, we can use the given parameters and calculate the driving force and resisting force. By dividing the resisting force by the driving force, we can obtain the factor of safety. If the factor of safety is greater than 1, it indicates that the slope is stable. If it is less than 1, the slope is considered potentially unstable.

b. If the water depth increases by 2 m, it adds additional weight to the slope, increasing the driving force. This decrease in the factor of safety suggests a less stable slope compared to the initial scenario.

c. If the angle of internal friction increases by a factor of 2, it enhances the shear strength of the regolith. This increase in the factor of safety indicates a more stable slope.

d. If the slope becomes steeper by a factor of 2, it increases the driving force. This decrease in the factor of safety suggests a less stable slope.

e. Based on the analysis, it is important to advise the homeowners that the slope is currently unstable, considering the factor of safety is less than 1. Remediation measures may include slope stabilization techniques such as installing retaining walls, soil reinforcement, or drainage systems to manage water infiltration and reduce driving forces. It is recommended to consult with a geotechnical engineer to develop a comprehensive slope stability plan for the safety of the home.

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How much work do you do, when you lift a 155 n child .8 m?

Answers

Answer:

1240j I think this is the answer

In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the string. Question 1 options: 5 cm 10 cm 15 cm 20 cm

Answers

Answer:

5 cm

Explanation:

why it's dangerous to jump from a moving bus?​

Answers

Answer:

A man jumping out from a moving bus holds the inertia of motion.As the man lands on the ground,feet came to rest instantly while the upper due to inertia of motion.Therefore the person may fall under bus.

A classmate is working with a source that
is labelled 18 V. The classmate refers to
the source as a cell. Why might you think
that the term cell is incorrect? How is the
source most likely related to a cell?​

Answers

The term cell is incorrect because, the average voltage of a cell is 3.40 V and as already mentioned in question, the volt of source is 18 V, so cell couldn't be the appropriate word, actually the source is battery.

Now, the source is most likely related to cell because a battery which is the source here, is made up of a "group of cell".

Plzz help me fast

(There is both physics and chemistry question )

1) Write the molecular formula of the following by crisscross method :
1. Potassium sulphate
2. Sodium chloride
3. Ammonium chloride
4. Silver oxide


2) Prove that F=ma pl

Answers

Potassium Sulphate :-

\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf K}\put(0,0){\bf 1}\put(4,3){\sf SO_4}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)

\(\boxed{\sf K_2SO_4}\)

Sodium chloride:-

\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Na}\put(0,0){\bf 1}\put(4,3){\sf Cl}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)

\(\boxed{\sf NaCl}\)

Ammonium Chloride

\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf NH_4}\put(0,0){\bf 1}\put(4,3){\sf Cl}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)

\(\boxed{\sf NH_4Cl}\)

Silver Oxide

\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Ag}\put(0,0){\bf 1}\put(4,3){\sf O}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)

\(\boxed{\sf Ag_2O}\)

are one of the deadliest types of intersections.
Roundabouts
Four way stops
Railroad crossings
Flashing yellow lights

Answers

Correct answer: railroad crossings

The weight of a boy having a mass of 50 kg is __N.
???

Answers

Answer: 490N

Explanation:

Newton is the unit for force. Force = mass x acceleration

F=N m=50kg a=9.8 (earth's acceleration of gravity)

F=50X9.8

F≈490N

Use the information and table to answer the following question! A skydiver dives from an airplane. air resistance is measured each second following the skydiver’s jump.
Time After Jump Weight Air Resistance
(seconds) Newtons (N) Newtons (N)
1 seconds 500N 200N
2 seconds 500N 300N
3 seconds 500N 400N
4 seconds 500N 500N
Which statement BEST identifies the skydiver's speed at each second?
a. The skydiver has the slowest speed at 2 seconds
b. The skydiver has the fastest speed at 4 seconds
c. The skydiver has the sloweat speed 1 second
d. The skydiver has the fastest speed at 3 seconds

Answers

The skydiver has the fastest speed at 4 seconds, and the correct statement is (b) "The skydiver has the fastest speed at 4 seconds".

To determine the skydiver's speed at each second, we need to consider the forces acting on the skydiver. In this case, the forces acting on the skydiver are the weight of the skydiver and the air resistance. The weight of the skydiver is constant at 500 N, while the air resistance increases with time.

According to Newton's second law of motion, the acceleration of an object is equal to the net force acting on it divided by its mass. In this case, the mass of the skydiver is not given, so we cannot calculate the acceleration directly.

Speed is the rate of change of displacement over time. In this case, the displacement of the skydiver is not given, so we cannot calculate the speed directly. However, we can use the information provided to determine the skydiver's speed at each second.

From the table, we can see that the air resistance increases with time, reaching a maximum of 500 N at 4 seconds. This means that the net force acting on the skydiver is greatest at 4 seconds, which would correspond to the highest acceleration and the fastest speed.

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What is the relationship between elevation and energy (think about the same can dropped from different heights)?

Answers

Elevation would be showing you what height you are at, energy would be like what force your putting into the object.

Answer: Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

Explanation:

Which of the following statements does NOT describe force?

A.Force causes objects to change direction.
B.Force causes objects to start moving.
C.Force causes objects to stop moving.
D.Force causes objects at rest to remain stationary.

Answers

Answer: D

Explanation: Force can do everything else.

Answer:

D. Force causes objects at rest to remain stationary.

Explanation:

What is the equation for torque, moment of intertia, and angular acceleration?

Answers

The equation for torque, moment of inertia, and angular acceleration is:  Torque = Moment of Inertia x Angular Acceleration.

What is equation ?

An equation is a mathematical statement that expresses the equality or equivalence of two expressions. It is a statement that asserts the equality of two expressions by providing a set of operations and/or values that, when completed, will yield a result of true. Equations are used to describe relationships between two or more variables, to solve for a particular value, or to express a specific law of nature. They are used in a wide variety of mathematical, physical, and engineering problems. Equations are typically written using symbols such as numbers, letters, and special mathematical symbols, and can include equations of lines, curves, and functions. Equations help us to understand the physical and mathematical properties of our world, and can be used to model and describe real-world phenomena.

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What are the metals and the non metals of copper carbonate

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The Copper metal carbonate is a chemical compound that is made up of copper, carbon, and oxygen. It is a salt that has a blue-green color and is commonly used as a pigment in ceramics and as a fungicide in agriculture.



In terms of its composition, copper carbonate contains both metals and non-metals. Copper, as we know, is a metal and is an important component of the compound. Meanwhile, carbon and oxygen are both non-metals. In general, metals are elements that are characterized by their ability to conduct electricity and heat, their malleability, and their shiny appearance. They tend to lose electrons when they react with other elements and form positive ions. Copper, as a metal, has all of these properties and is widely used in electrical wiring, plumbing, and coinage. Non-metals, on the other hand, are elements that lack metallic properties. They are typically poor conductors of electricity and heat, are often brittle or soft, and do not have a shiny appearance. Carbon and oxygen are two examples of non-metals and are found in a variety of different compounds. In conclusion, copper carbonate is a chemical compound that contains both metals and non-metals. Copper, as a metal, is an important part of the compound, while carbon and oxygen are both non-metals.

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Imagine diving 150 feet beneath the sea. You are looking for sponges, which is not very exciting, but it’s your job. Now imagine coming across the wreck of an ancient ship! That’s what happened to some divers off the island of Antikythera (an-tee-KITH-er-ah) in the Mediterranean Sea. The ship had been on the seafloor for almost 2000 years. Divers found coins, statues, musical instruments, and many other precious items in the shipwreck. The greatest treasure of all, however, was a collection of corroded metal gears. Nothing like them had ever been found before or has ever been found since. They seem to fit together in a complicated way. They are part of a machine that scientists call the Antikythera mechanism.
It took scientists many years to figure out what the mysterious machine was for. Eventually, scientists used x-rays to view the gears and other parts inside the machine. They were also able to read ancient Greek writing on some of the parts. Using this new information, scientists realized the Antikythera mechanism was built by ancient astronomers to predict patterns in the appearance of the sun, the planets that people were able to observe, and especially the Moon.
Ancient Greek astronomers had been observing the Moon and keeping track of its appearance for hundreds of years. Looking over all their observations, they noticed patterns. The astronomers assumed the same patterns that had been going on for hundreds of years would keep going into the future. They built the Antikythera mechanism to predict events in the future based on the patterns they had observed.
A user of the Antikythera mechanism could turn a dial on one side of the mechanism to choose a date and time, either in the past or in the future. The gears would spin into place, predicting the appearance and position of the Moon and other bodies at that time. The machine had pointers and other displays to show its predictions. For example, ancient astronomers knew there would be a full moon every 29 and a half days. There was a ball on the Antikythera mechanism that traced the phases of the moon. The ball was white on one side (representing the side of the moon illuminated by the sun) and black on the other (representing the dark side of the moon). As the user turned the date dial of the machine, the little moon ball would spin to show what phase the moon would be in on that date.
The Antikythera mechanism also traced patterns that took much longer to repeat. For instance, ancient astronomers knew that occasionally, on the night of a full moon, a lunar eclipse happens. During a lunar eclipse, the fully illuminated face of the full moon goes dark for a time. However, they noticed that this didn’t happen every full moon—in fact, over a year would sometimes pass between their observations of lunar eclipses. Through careful record-keeping, the ancient astronomers realized that eclipses, although rare, happened in patterns. They kept track of the patterns and recorded that knowledge in the workings of the Antikythera mechanism. As a user turned the date dial of the Antikythera mechanism, the mechanism counted the days and displayed exactly when people in Greece could expect to observe a lunar eclipse.
The mechanism showed WHEN an eclipse would happen, but it didn’t show WHY an eclipse would happen. The astronomers who made the Antikythera mechanism knew that the Moon seems to shine because it is illuminated by light from the sun. They also knew that an eclipse of the Moon happens when Earth blocks the sunlight and makes a shadow on the Moon. They did not know exactly why this happened at some times and not others.
Today astronomers can explain why lunar eclipses happen when they do. Lunar eclipses are caused by Earth blocking sunlight from reaching the Moon. For Earth to block the sunlight, it has to be between the sun and the Moon. Not only that, but the sun, Earth, and the Moon have to line up exactly, with Earth in the middle. When they line up in this way, Earth blocks the sunlight and the Moon goes dark. Eclipses only happen on the night of a full moon, because the full moon is the phase when the sun, Earth, and the Moon line up with Earth in the middle.

If this is true, why don’t lunar eclipses happen every time the Moon is full? Why did the ancient astronomers have to wait so long between observations of eclipses? It’s because the Moon’s orbit around Earth is slightly tilted out of alignment. During most full moons, the sun, Earth, and the Moon are lined up, but they are not lined up EXACTLY. For the three bodies to line up exactly, the Moon has to be exactly in the right spot on its tilted orbit. That happens very infrequently. The makers of the Antikythera mechanism knew how unusual this was, but they didn’t understand the reason—now you do!

1) Describe how it is possible for Lunar Eclipses to happen. Use evidence from the reading to explain how this happens.

2) Describe the main factor that leads to a lunar eclipse instead of a full moon.

Answers

Answer:

A lunar eclipse occurs when the Moon moves into the Earth's shadow. ... The only light reflected from the lunar surface has been refracted by Earth's atmosphere. This light appears reddish for the same reason that a sunset or sunrise does: the Rayleigh scattering of bluer light.

Lunar eclipses can only happen when the Moon is opposite the Sun in the sky, a monthly occurrence we know as a full Moon. But lunar eclipses do not occur every month because the Moon's orbit is tilted five degrees from Earth's orbit around the Sun. Without the tilt, lunar eclipses would occur every month.

Explanation:

what is the equation that links power, energy and time?

Answers

Answer:

Energy = Power x Time

Explanation:

for which colour of light is. the index of refraction of glass largest​

Answers

Answer:

don't know sorry for the irreverent answer..

Answer:

The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.

what must the charge (sign and magnitude) of a 1.70 g particle be for it to remain balanced against gravity when placed in a downward-directed electric field of magnitude 680 n/c ?

Answers

The charge on the particle must be 2.50 x 10^-8 C to remain balanced against gravity when placed in a downward-directed electric field of magnitude 680 N/C.

The electric force that balances the gravitational force on the 1.70 g particle can be calculated using the equation:

F_electric = q * E

where q is the charge on the particle, E is the electric field strength, and F_electric is the electric force. Setting this equal to the weight of the particle (mg), where m is the mass and g is the acceleration due to gravity, we can solve for the charge:

q = (m * g) / E

q = (1.70 g) * (9.8 m/s^2) / (680 N/C)

q = 2.50 x 10^-8 C

So, the charge on the particle must be 2.50 x 10^-8 C to remain balanced against gravity when placed in a downward-directed electric field of magnitude 680 N/C.

The sign of the charge is positive since it is repelling the downward electric field.

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consider an infinite sheet of parallel wires. the sheet lies in the xy plane. a current i runs in the -y direction through each wire. there are n/a wires per unit length in the x direction.

Answers

The magnetic field is proportional to the current and inversely proportional to the number of wires per unit length in the x direction.

The magnetic field produced by an infinite sheet of parallel wires can be determined using Ampere's Law. Since the current is running in the -y direction through each wire, the magnetic field lines will circulate around each wire in the clockwise direction when viewed from above. The magnitude of the magnetic field at a point above the sheet will depend on the distance from the sheet, as well as the number of wires per unit length in the x direction.
Using Ampere's Law, the integral of the magnetic field around a closed loop will be equal to μ₀ times the current enclosed by the loop. For a rectangular loop with sides of length L and H, the magnetic field along the sides parallel to the wires will be constant and equal to μ₀ times the current per unit length (i/n) times the width of the loop (L), while the field along the sides perpendicular to the wires will be zero. Thus, the integral of the magnetic field around the loop will be 2 times the magnetic field along one of the parallel sides, or 2μ₀(i/n)L.
Setting this equal to μ₀ times the current enclosed by the loop (iLH), we can solve for the magnetic field at a point above the sheet:
B = μ₀i/2n

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How does energy release from the sun reach Earth? How does the sun's energy interact with Earth's atmosphere and hydrosphere?

help plz soon :((

Answers

because of the water

Answer:

When the Sun's energy moves through space, it reaches Earth's atmosphere and finally the surface. This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet's systems in three ways: by radiation, conduction, and convection.

A particle’s velocity along the x-axis is described by
v(T) = AT + BT2, A being 1m/s^2 while B being -1m/s^2
what is the distance that this particle has traveled between T0: 1s and T1: 3s

Answers

The distance that this particle has traveled between T0 = 1s and T1 = 3s is 0.

To find the distance that the particle has traveled between T0 = 1s and T1 = 3s, we need to calculate the displacement during this time interval. Displacement can be found by integrating the velocity function over the given time interval.
Given the velocity function v(T) = AT + BT^2, where A = 1 m/s^2 and B = -1 m/s^2, we can integrate it to find the displacement function.
First, integrate AT with respect to T:
∫(AT) dT = (1/2)AT^2 + C1
Next, integrate BT^2 with respect to T:
∫(BT^2) dT = (1/3)BT^3 + C2
Where C1 and C2 are constants of integration.
Now, we can find the displacement between T0 and T1 by evaluating the displacement function at T1 and subtracting the displacement at T0:
Displacement(T1) - Displacement(T0) = [(1/2)AT1^2 + C1 + (1/3)BT1^3 + C2] - [(1/2)AT0^2 + C1 + (1/3)BT0^3 + C2]
Since C1 and C2 are constants, they cancel out when subtracted:
Displacement(T1) - Displacement(T0) = (1/2)AT1^2 + (1/3)BT1^3 - (1/2)AT0^2 - (1/3)BT0^3
Substituting the given values T1 = 3s and T0 = 1s, and the values of A and B:
Displacement(3) - Displacement(1) = (1/2)(1)(3)^2 + (1/3)(-1)(3)^3 - (1/2)(1)(1)^2 - (1/3)(-1)(1)^3
Simplifying the equation:
Displacement(3) - Displacement(1) = 9/2 + (-9/3) - 1/2 + (-1/3)
Displacement(3) - Displacement(1) = 9/2 - 3 - 1/2 + (-1/3)
Displacement(3) - Displacement(1) = 9/2 - 6/2 - 1/2 + (-1/3)
Displacement(3) - Displacement(1) = (9 - 6 - 1 + (-2))/2
Displacement(3) - Displacement(1) = 0/2
Displacement(3) - Displacement(1) = 0
Therefore, the distance that this particle has traveled between T0 = 1s and T1 = 3s is 0.


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Galileo's early telescopes revealed the four large moons of Jupiter, the rings of Saturn, and its large moon Titan.

a. True
b. False

Answers

The statement given "Galileo's early telescopes revealed the four large moons of Jupiter, the rings of Saturn, and its large moon Titan." is true because Galileo's early telescopes revealed the four large moons of Jupiter, the rings of Saturn, and its large moon Titan.

Galileo Galilei, an Italian astronomer, made significant observations using his early telescopes. His observations provided evidence to support the heliocentric model of the solar system proposed by Copernicus. With his telescope, Galileo discovered four large moons orbiting Jupiter, which are now known as the Galilean moons: Io, Europa, Ganymede, and Callisto. He also observed and documented the presence of rings around Saturn and identified its largest moon, Titan. These observations revolutionized our understanding of the solar system and provided critical evidence for the heliocentric model.

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How do I find average velocity and average time

Answers

Answer:

x2- x1 / t2 - t1

Explanation:

To find this speed, you have to use the operation of: X2 -X1/ t2 -t1, we know that x is the distance, we do the operation and that would be our average speed

balance of chemical equations

Answers

Answer:

an equation is balanced when the same number of each element is represented on the reactant and product sides. equations must be balanced to accurately reflect the law of conservation of matter.

explosions in one dimension: on a frictionless horizontal table, two blocks (a of mass 2.40 kg and b of mass 3.00 kg) are pressed together against an ideal massless spring that stores 150.0 j of elastic potential energy. the blocks are not attached to the spring and are free to move free of it once they are released from rest. the maximum speed achieved by each block is closest to

Answers

To solve this problem, we need to use conservation of energy. When the blocks are released, the spring will push them apart and transfer its potential energy to kinetic energy. Since there is no friction, the total mechanical energy will remain constant. Therefore, we can set the initial potential energy equal to the final kinetic energy of both blocks.

The initial potential energy is given as 150.0 J. To find the final kinetic energy of each block, we can use the formula KE = 1/2 mv^2, where m is the mass of the block and v is its speed.

Let's start with block A. Since the blocks are pressed together, they will move with the same velocity after they are released. Let's call this velocity v. Therefore, the initial velocity of block A is 0 m/s and its final velocity is v m/s.

Using conservation of energy:

150.0 J = 1/2 (2.40 kg) v^2

v = √(150.0 J / 1.20 kg) = 10.6 m/s

So block A will achieve a maximum speed of 10.6 m/s.

Now let's move on to block B. Its mass is 3.00 kg, so we can use the same formula:

150.0 J = 1/2 (3.00 kg) v^2

v = √(150.0 J / 1.50 kg) = 9.80 m/s

Therefore, block B will achieve a maximum speed of 9.80 m/s.

Note that we assumed that the blocks move in one dimension (i.e. horizontally) and that there is no external force acting on them. If there were other forces present, the speeds of the blocks would be different.

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You push on a tree with 20 N of force. If the tree doesn't move, the tree is pushing back on you with _____of force.
A. 20 N
B. 19 N
C. 21 N
D. 40 N

Answers

Answer:

A.

Explanation:

Please help!!
An archer uses an average force of 50.0 N to draw the
string of his bow through a distance of 0.412 m. Then,
he fires a 297 g arrow straight up into the air.
What is the maximum speed of the arrow at the instant it leaves the bow?
And
What is the maximum height reached by the arrow in its flight into the air?

Answers

Explaination

the maximum hight is reached by the arrow is 4.40m

HOPE IT HELPS YOU #ITZADMIRER

From Newton's second law and third equation of motion, the maximum speed of the arrow at the instant it leaves the bow is 11.8 m/s and the maximum height reached by the arrow in its flight into the air is 7.08 m

MOMENTUM

According to Newton's second law: The rate of change in momentum is directly proportional to the force applied. That is,

F = ma

Given that an archer uses an average force of 50.0 N to draw the string of his bow through a distance of 0.412 m. Then, he fires a 297 g arrow straight up into the air.

The parameters given are;

Force F = 50 NDistance S = 0.412 mMass M = 297g = 0.297

The maximum speed of the arrow at the instant it leaves the bow can be calculated by first calculating the acceleration.

F = ma

Substitute all the necessary parameters

50 = 0.297a

a = 50 / 0.297

a = 168.4 m/\(s^{2}\)

by using third equation of motion

\(V^{2}\) = \(U^{2}\) + 2as

Since it is starting from rest, U = 0

\(V^{2}\) = 2 x 168.4 x 0.412

\(V^{2}\) = 138.72

V = \(\sqrt{138.72}\)

V = 11.8 m/s

The maximum height reached by the arrow in its flight into the air will be calculated by the same formula where acceleration a = g

\(V^{2}\) = \(U^{2}\) - 2gH

At maximum height, final velocity V = 0

0 = \(11.8^{2}\) - 2 x 9.8 H

138.7 = 19.6H

H = 138.7 / 19.6

H = 7.08 m

Therefore, the maximum speed of the arrow at the instant it leaves the bow is 11.8 m/s and the maximum height reached by the arrow in its flight into the air is 7.08 m

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