PLEASE HELP ME ANSWER DIRECTIONS ARE IN THE PIC PLEASE HELP ASAP!

The distance bewteen the points (-3,5) and (3,1) in a simple radical form is 2√13.

The distance formula used in finding the distance between two points is expressed as;

d = √( ( x₂ - x₁ )² + ( y₂ - y₁ )² )

From the graph;

Point A: (-3,5)

x₁ = -3

y₁ = 5

Point B: (3,1)

x₂ = 3

y₂ = 1

Plug the given values into the distance formula and simplify.

\(d = \sqrt{( x_2 - x_1)^2 + (y_2 -y_1 )^2} \\\\d = \sqrt{( 3-(-3))^2 + (1 -5)^2} \\\\d = \sqrt{( 3+ 3)^2 + (1 -5)^2} \\\\d = \sqrt{( 6)^2 + (-4)^2} \\\\d = \sqrt{36 + 16} \\\\d = \sqrt{52}\\\\d = 2\sqrt{13}\)

Therefore, the distance between the points is 2√13.

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Answer:

1

Step-by-step explanation:

3 divided by 1/3 is 9, and 9-9=0

0+1=1

1

Step-by-step explanation:

The amount that is included in the calculation of an employee's regular rate of pay is Reimbursed expenses therefore option B. Reimbursed expenses is correct.

Compensation is defined as the amount of total reward that an employee is given in return for their work.  

It is divided into two categories: direct and indirect compensation.

Direct compensation: Direct compensation refers to the money given to employees in exchange for their work.

The following are some examples of direct compensation: Salary Wages Commission

Indirect  compensation: Indirect compensation refers to non-monetary rewards given to employees as a result of their employment.

Some examples of indirect compensation are: Employer-provided benefits Paid leave Insurance Retirement plans Reimbursement for work-related expenses.

An employee's regular rate of pay refers to the hourly rate that an employee earns based on their work hours. An employer must pay their employees one and a half times their regular rate of pay for all hours worked beyond 40 hours in a workweek.However, not all payments made to an employee are included in the regular rate of pay. Only payments made to employees based on their work hours are included. Reimbursed expenses are an example of a payment that is included in the calculation of an employee's regular rate of pay.

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Hello!

it's 21.9 for me

Answer:

B

Step-by-step explanation:

The equation is

y<=-x+1.

We test all and figure that B is correct.

-2<=-3+1

-2<=-2.

Correct!

So the answer is B

Hope this helps ;D

Answer:

Step-by-step explanation:

the answer is bee

The 99% confidence interval for the proportion of all American youngsters who are seriously overweight is approximately 0.169 to 0.191.

A confidence interval for the proportion of all American youngsters who are seriously overweight, we can use the following formula:

Confidence Interval = Sample Proportion ± Margin of Error

Sample Size (n) = 4707

Sample Proportion (p (cap)) = 18% = 0.18

Confidence Level = 99%

First, we need to calculate the margin of error (ME). The formula for the margin of error is:

Margin of Error (ME) = Critical Value × Standard Error

The critical value depends on the desired confidence level. For a 99% confidence level, the critical value can be obtained from a standard normal distribution table or a statistical software. In this case, the critical value is approximately 2.576.

The standard error (SE) is calculated as

Standard Error (SE) = √((p (cap) × (1 - p (cap))) / n)

Now, let's calculate the margin of error and the confidence interval

Standard Error (SE) = √((0.18 × (1 - 0.18)) / 4707)

Margin of Error (ME) = 2.576 × SE

Confidence Interval = Sample Proportion ± Margin of Error

Calculating the values

SE ≈ 0.00429

ME ≈ 2.576 × 0.00429 ≈ 0.01103

Lower bound = Sample Proportion - ME Lower bound

= 0.18 - 0.01103

= 0.169

Upper bound = Sample Proportion + ME Upper bound

= 0.18 + 0.01103

= 0.191

Rounding the results to three decimal places

Lower bound ≈ 0.169 Upper bound ≈ 0.191

Therefore, the 99% confidence interval for the proportion of all American youngsters who are seriously overweight is approximately 0.169 to 0.191.

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Answer:

-1 1/4

Step-by-step explanation:

1/4 - (1 1/2)

Get a common denominator

1/4 - 1 2/4

Take the larger number and subtract the smaller number and take the sign of the larger

1 2/4 - 1/4 = 1 1/4

The sign of the larger was negative

-1 1/4

The Root Cause Analysis technique used to identify the underlying causes of a problem is the Ishikawa diagram. It is a graphical tool also known as the Fishbone diagram or Cause and Effect diagram. The other techniques mentioned, such as the Rule of 72, Marginal Analysis, and Bayesian Thinking, are not specifically associated with Root Cause Analysis.

Root Cause Analysis is a systematic approach used to identify the fundamental reasons or factors that contribute to a problem or an undesirable outcome. It aims to go beyond addressing symptoms and focuses on understanding and resolving the root causes. The Ishikawa diagram is a commonly used technique in Root Cause Analysis. It visually displays the potential causes of a problem by organizing them into different categories, such as people, process, equipment, materials, and environment. This diagram helps to identify possible causes and facilitates the investigation of relationships between different factors. On the other hand, the Rule of 72 is a mathematical formula used to estimate the doubling time or the time it takes for an investment or value to double based on compound interest. Marginal Analysis is an economic concept that involves examining the additional costs and benefits associated with producing or consuming one more unit of a good or service. Bayesian Thinking is a statistical approach that combines prior knowledge or beliefs with observed data to update and refine probability estimates. In the context of Root Cause Analysis, the Ishikawa diagram is the technique commonly used to visually analyze and identify the root causes of a problem.

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Answer:

y=30x+300

14 weeks

Step-by-step explanation:

Part A:

To begin, we are asked to write an equation.  We are given the amount you start with, which is $300, and you put $30 in every week.

We can write an equation that looks like:

y=30x+300

with x being the number of weeks you put in money.

Part B:

Part B asks us to find x, the number of weeks that you had to put in money to save a total of $720.

We have the equation:

y=30x+300

with x being the number of weeks, and y being the total amount, $720.  This means we can substitute:

720=30x+300

subtract 300 from both sides

420=30x

divide both sides by 30

14=x

So, you had to have been saving for 14 weeks.

Hope this helps! :)

The Fourier transform of the function \(\(f(x) = e^{-\alpha |x|} \cos(\beta x)\)\), where \(\(\alpha > 0\)\) and \(\(\beta\)\) is a real number, is given by: \(\[F[f] = \hat{f}(\xi) = \frac{2\pi}{\alpha^2 + \xi^2} \left(\frac{\alpha}{\alpha^2 + (\beta - \xi)^2} + \frac{\alpha}{\alpha^2 + (\beta + \xi)^2}\right)\]\)

In the Fourier transform, \(\(\hat{f}(\xi)\)\) represents the transformed function with respect to the variable \(\(\xi\)\). The Fourier transform of a function decomposes it into a sum of complex exponentials with different frequencies. The transformation involves an integral over the entire real line.

To derive the Fourier transform of \(\(f(x)\)\), we substitute the function into the integral formula for the Fourier transform and perform the necessary calculations. The resulting expression involves trigonometric and exponential functions. The transform has a resonance-like behavior, with peaks at frequencies \(\(\beta \pm \alpha\)\). The strength of the peaks is determined by the value of \(\(\alpha\)\) and the distance from \(\(\beta\)\). The Fourier transform provides a representation of the function f(x) in the frequency domain, revealing the distribution of frequencies present in the original function.

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The correct answer is B) Her sample is 38, 68, 35, 02, 22. This is because the scientist is selecting a random sample of 5 forest sites from a population of 45 without replacement. She is using consecutive pairs of digits from the table of random digits to select her sample.

Starting at the beginning of the line of random digits, the first pair is 38, which corresponds to forest site 38. The second pair is 68, which corresponds to forest site 68. The third pair is 35, which corresponds to forest site 35. The fourth pair is 02, which corresponds to forest site 02. And the fifth pair is 22, which corresponds to forest site 22.
Now, let's select a random sample of 5 forest sites without replacement:
1) 38
2) 35
3) 02
4) 22
5) 24
Thus, the correct answer is not listed in the given options. However, based on the consecutive pairs of digits and following the process mentioned, the sample should be 38, 35, 02, 22, and 24.

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Answer:

Begin by finding the area of the square, 24x22. This would equal 528. Then, we need to find the area of each circle using the area formula, \(\pi\)\(r^{2}\). We can plug in the numbers to get \(\pi\)\(3^{2}\). Multiply 3x3 to get 9\(\pi\). Because there are 4 circular burners, we need to multiply 9\(\pi\) by 4 to get 36\(\pi\) or 113.04. Now, we can subtract 528 with 113.04 to result with 414.96 or 415, when rounded. So, the answer would be 415 \(in.^{2}\)

Jacques should have spent 1 hour working on problems and 3.75 hours reading to get the best possible exam score.

Let's denote the increase in exam score by x, and assume that working on 15 problems raises the exam score by x and reading the textbook for 1 hour also raises the exam score by x. We can then set up the following equation:

4 = a(15) + b

where a is the number of hours spent on problem sets, b is the number of hours spent reading the textbook, and 4 represents the total number of study hours available.

To solve for a and b, we can use the information given in the problem: "working on 15 problems raises a student’s exam score by about the same amount as reading the textbook for 1 hour." This means that:

15a = b

Substituting this into our first equation, we get:

4 = a(15) + 15a

Simplifying this equation, we get:

4 = 16a

a = 0.25

So Jacques should spend 0.25 * 4 = 1 hour working on problem sets, and 15 * 0.25 = 3.75 hours reading the textbook.

Therefore, Jacques should have spent 1 hour working on problems and 3.75 hours reading to get the best possible exam score.

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okay i will answer it for you yes

Answer:

1590 minutes

Step-by-step explanation:

November 17 ends on 12:00, which is 8 hours after 4:00 pm. The time from the beginning of November 18 to noon is 12 hours, and the distance from noon to 6:30 is 6 hours and 30 minutes, so the total time in hours is 8+12+6 +1/2=26 1/2.

Because we know that one hour is 60 minutes, 26 hours is going to be 60*26, which is equal to 60*20+60*6=1560.

1/2 * 60 = 30. 1560+30=1590, so the value of minutes is 1590 minutes.

Step-by-step explanation:

5x+13+3x=8x-5

13=-5

no solution

Answer:

f(0) = - 81

Step-by-step explanation:

f(0) means what is the value of f(x) when x = 0

substitute x = 0 into f(x)

f(0) = 12(0)² - 81 = 12(0) - 81 = 0 - 81 = - 81

The number of stray cats in the town in t=0 years will be 243.

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

The given function is:-

\(f(t) = 243(\dfrac{1}{3})^t\)

f(t) is representing the number of the stray cats in t years so in t=0 years the number of the cats will be:-

\(f(t) = 243(\dfrac{1}{3})^0= 243\)

f(t) = 243 cats

It states that initially at t=0 years there were 243 cats in the town.

Therefore the number of stray cats in the town in t=0 years will be 243.

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Answer:

15.75 gallons

Step-by-step explanation:

We can first look for a common characteristic between gallons and quarts, which will be: 1 gallon = 4 quarts

Then, we can make this equation to cancel out quarts and find gallons:

63 quarts * \(\frac{1 gallon}{4 quarts}\) = 15.75 gallons

(a) The solution is x = 32, y = 2.

(b) The system has no solution.

(c) The system has no unique solution.

To use Cramer's Rule, we need to compute the determinants of the coefficient matrix and each augmented matrix.

(a) The coefficient matrix is

1 1

2 -1

and its determinant is (1)(-1) - (2)(1) = -3.

The augmented matrix is

1 1 34

2 -1 30

and its determinant is (1)(-1) - (2)(1) = -3.

Using Cramer's Rule, we have

x = (-3(34) - 1(30))/-3 = 32

y = (1(34) - (-2)(30))/-3 = 2

(b) The coefficient matrix is

2 -3

-4 6

and its determinant is (2)(6) - (-3)(-4) = 0.

The augmented matrix is

2 -3 5

-4 6 10

and its determinant is (2)(6) - (-3)(-4) = 0.

Since the determinant of the coefficient matrix is zero, the system has no solution.

(c) The coefficient matrix is

3 1

2 -2

and its determinant is (3)(-2) - (2)(1) = -8.

The augmented matrix is

3 1 7

2 -2 7

and its determinant is (3)(-2) - (2)(1) = -8.

Since the determinant of the coefficient matrix is nonzero but the determinant of the augmented matrix is zero, the system has no unique solution.

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Answer:

SA = 384 in²

Step-by-step explanation:

Assuming we're finding surface area:

SA of top of large cube: 8(8) - 4(4) = 48 in²

SA of sides of large cube: 4(8)(8) = 256 in²

SA of exposed faces of small cube: 5(4)(4) = 80 in²

Total = 48 + 256 + 80 = 384 = ∑SA

Answer:

2p + 9 = 3

2p = 3 - 9

2p = -6

p = -6/2

p = -3

The value of Sin2t is 1/4 and cos2t is (15/16)^1/2  and tan2t is 1/(15)^1/2.

According to the statement

we have given that the sint=1/8 then we have to find the exact value of

sin(2t) , cos(2t) , and tan(2t).

Here the value of Sint = 18

then sin2t becomes

sin2t = 2*1/8 then

sin2t = 1/4.

And

(Cos2t)^2 = 1 - (Sin2t)^2

(Cos2t)^2 = 1 - 1/16

(Cos2t)^2 = (16 - 1)/16

(Cos2t)^2 = 15/16

(Cos2t) = (15/16)^1/2

then

tan2t = sin2t/cos2t

tan2t = (1/4)/(15)^1/2 / 4

tan2t = 1/(15)^1/2

these are the values of given terms.

So, The value of Sin2t is 1/4 and cos2t is (15/16)^1/2  and tan2t is 1/(15)^1/2.

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444 ft traveled in 6 seconds.

If the car travels 74 ft in 1 second, all you have to do is multiply 74 by 6 to find the answer, which is 444 ft.

Without a visual aid, it is not possible to provide a specific answer as to which box-and-whisker plot correlates with the given data set. However, we can describe the characteristics of a typical box-and-whisker plot and how it is constructed.

A box-and-whisker plot is a graphical representation of a data set that shows the distribution of the data and its central tendency. The box in the plot represents the interquartile range (IQR), which is the range of values that fall within the middle 50% of the data. The line inside the box represents the median, which is the middle value of the data set when arranged in order. The whiskers extending from the box represent the range of the data, excluding outliers. Outliers are any data points that fall more than 1.5 times the IQR above the upper quartile or below the lower quartile.

To construct a box-and-whisker plot, we first arrange the data set in order from smallest to largest. Then, we find the median and the quartiles (the values that divide the data into quarters). The first quartile (Q1) is the median of the lower half of the data, and the third quartile (Q3) is the median of the upper half of the data. The IQR is then calculated as Q3 - Q1. The whiskers extend from the box to the smallest and largest data points that are not outliers. Any data points that fall outside the whiskers are plotted as individual points or asterisks to indicate outliers.

Therefore, to determine which box-and-whisker plot correlates with the given data set, we would need to see the plots and identify which one has a box representing the IQR, a line inside the box representing the median, and whiskers representing the range of the data, excluding outliers. Additionally, we would need to identify any outliers in the data set and see if they are represented in the plot.

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Answer

c

Step-by-step explanation:

It is not d because of the way that it is formed

The F-test is used in regression analysis to test the hypothesis that all model parameters are zero. It is also used in statistical analysis when comparing statistical models.

Statistical models that have been fitted using the same underlying factors and data set to determine the model with the best fit. That is:

H₀ : B₁ = B₂ = .............  = Bₓ =0

H₁: Bₙ ≠ 0 for at least one j.

The F-test was developed by Ronald A. Fisher (hence F-test) and is a measure of the ratio of variances. The F-statistic is defined as:

F = \(\frac{explained variables}{unexplained variables}\)

A general rule of thumb that is often used in regression analysis is that if  

F > 2.5then we can reject the null hypothesis. We would conclude that there is a least one parameter value that is nonzero.

The F-distribution is generally a skewed distribution and also related to a chi-squared distribution. The f distribution is the ratio of X1 random chi-square variable with degrees of freedom ϑ1 and X2 random chi-square variable with degrees of freedom ϑ2. (In other words each of the chi-square random variable has been divided by its degrees of freedom)

The F-distribution is generally a skewed distribution and also related to a chi-squared distribution. The f distribution is the ratio of X1 random chi-square variable with degrees of freedom ϑ1 and X2 random chi-square variable with degrees of freedom ϑ2. (In other words each of the chi-square random variable has been divided by its degrees of freedom)

                        F =\(\frac{x_{1}/v_{1} }{x_{2}/v_{2} }\)

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Two algebraic expressions that have the same value for all values of their variable(s) are called Equivalent expression.

Algebraic expression is an expression which is made up of variables and constants along with algebraic operation (addition, subtraction etc. )

Variables are values that can change over time.

Constant are the quantities that have fixed numerical value.

Two algebraic expression are equivalent expression if they have the same value for all values of their variable(s).

Equivalent algebraic expression are those expression which on simplification give the same resulting expression.

or

Two expression are said to be equivalent if their values obtained by substituting the values of the variable are same

For example:

Let,

\(f(x)=3(x+2)\\g(x)=3x+6\)

Substituting the \(x=4\) in the both equation..

\(f(x)=3(x+2)=3(4+2)=3(6)=3*6=18\)

\(g(x)=3x+6=3*4+6=12+6=18\)

\(3(x+2)\) and \(3x+6\) are the equivalent expression because the value of both equation remain same for any value of \(x\)

Two algebraic expressions that have the same value for all values of their variable(s) are called Equivalent expression.

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