please help!!!!!! 26 points

Answer:

The time for the rock to reach the bottom is 4.02 seconds.

Explanation:

Given;

mass of the rock, m = 5 kg

height of the rock fall, h = 79 meters

The time to drop to the given height is given by;

\(t = \sqrt{\frac{2h}{g} }\)

where;

t is the time to fall to the bottom

g is acceleration due to gravity = 9.8 m/s²

\(t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2*79}{9.8} }\\\\t = 4.02 \ s\)

Therefore, the time for the rock to reach the bottom is 4.02 seconds.

Speed of the rock at the bottom of the cliff is 44.3 m/s.

Kinetic energy of the rock at the bottom of the cliff is 4915 J.

Work done by air resistance is -2250 J

Average force exerted by the air on the rock is 11.25 N.

a) The speed of the rock at the bottom of the cliff can be calculated using the equation:

v = √(2gh)

where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).

Plugging in the values:

v = √(2 x 9.81 x 200) = 44.3 m/s

Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.

b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:

KE = (1/2)mv²

where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).

Plugging in the values:

KE = (1/2) x 5 x (44.3)² = 4915 J

Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.

c) The work done by air resistance can be calculated using the work-energy principle:

Work done by air resistance = KE_initial - KE_final

where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).

Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:

KE_final = (1/2)mv_terminal²

where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).

Plugging in the values:

KE_final = (1/2) x 5 x (30)² = 2250 J

Therefore, the work done by air resistance is:

Work done by air resistance = 0 - 2250 = -2250 J

The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.

d) The average force exerted by the air on the rock can be calculated using the equation:

Work done by air resistance = Force x Distance

where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.

Rearrange the equation to solve for Force:

Force = Work done by air resistance / Distance

Plugging in the values:

Force = -2250 / 200 = -11.25 N

Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.

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Answer:

The acceleration of the block is -0.884 m/s²

Explanation:

Given;

mass of the block, m = 43 kg

frictional force, Fk = 61 N

applied force on object, F = 23 N

The net horizontal force on the body is given by;

∑Fx = F - Fk

∑Fx = 23 N - 61 N

∑Fx = -38 N

Apply Newton's second law of motion;

F = ma

a = F/m

a = -38 / 43

a = -0.884 m/s²

this is the deceleration of the block, because the applied the applied force is than the frictional force; which is preventing forward motion of the block.

Therefore, the acceleration of the block is -0.884 m/s²

We are given that a force of 24N is exerted on an object to lift it a distance of 2.24m. To determine the work done we will use the following formula:

Where:

Substituting the values we get:

Solving the operations:

Therefore, the work done is 53.76 Joules.

Answer:

5.5N/m

Explanation:

Calculation for What is the spring constant

First step is to calculate the time period

T = 12 second/10

T = 1.2 second

Now let calculate the spring constant using this formula

k=4π²m/T²

Where,

m=0.2kg

T=1.2second

k represent spring constant=?

Let plug in the formula

k=4π²×0.2kg/(1.2)²

k=39.48×0.2kg/1.44

k=7.90/1.44

k=5.48N/m

k=5.5N/m ( Approximately)

Therefore the spring constant will be 5.5N/m

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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A group of organs working together comprises an organ system, B.

Answer:Since pressure = force/area, the same force on a smaller area means more pressure. When you are walking on sand, the force being applied by your body is spread out over the entire surface of your foot. ... So, more pressure applied on a given area of your foot causes more pain.

Explanation:

Good Question

Answer: low = 1.73 m and high = 0.129 m

Explanation: All you have to do is use the formula (Wavelength = Velocity/Frequency. Which would be 340m/s divided by 196 Hz and then 340m/s divided by 2637Hz.

The wavelength of a wave is its speed divided by frequency. The wavelength corresponds to the lower frequency of 196 Hz is 1.73 m and that for 2637 Hz is 0.12 m. Hence the wavelength range is 1.73 m to 0.12 m.

Frequency of a wave is the number of wave cycles per unit time. It is the inverse of the time period. Thus, its unit is s⁻¹ which is equal to Hz. Frequency of a wave is inversely proportional to the wavelength.

The relation between speed and frequency with wavelength of the wave is given by,

c = νλ

Given frequency  ν1 = 196 Hz.

speed of sound wave c = 340 m/s

then, wavelength at this frequency λ1 = 340 m/s / 196 Hz = 1.73 m.

For a frequency ν2 = 2637 Hz.

λ2 = 340 m/s/ 2637 Hz = 0.12 m.

Therefore, the range of wavelength of the notes from the violin will be in between 1.73 m to 0.12 m.

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a) Magnitude of force is 5.37N

b) Angle of force is - 37.88°

In physics, we define a force is an influence that can change the motion of object. A force can cause an object with mass to change to accelerate.

Given force from above is 5.9N

∑Fₓ = F₁ₓ + F₂ₓ+F₃ₓ = 0

F₂ cos 44° + Fₓ = 0

Fₓ = - 5.9 cos44°

= - 4.24  N

Given force that acts downward as 7.4N

∑Fy= Fy1+ Fy2 +Fy3 =0

Fy+ 5.9 sin 44° - 7.4= 0

F =  3.30 N

F =√Fₓ² +Fy²

=  5.37 N

b)  angle of force= tan⁻¹ (3.30/-4.24)

= - 37.88°

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Answer:

1. Milky Way Galaxy

2. The Moon

3. False

4. A black hole

6. Moving away from us

Stretched as galaxies move away from us

8. Expanding

9. Cosmic Microwave Background

Explanation:

Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

Answer:

0.5429 m/s^2

Explanation:

velocity of waterjet = 18 m/s

diameter of water jet ( d ) = 4 cm = 0.04 m

mass of vertical plate(m) = 750 kg

Determine the acceleration of plate when the jet first strikes ( i.e. t = 0 )

first we will determine the impact force

F = β*A*V^2 ----- ( 1 )

where ; β = 1000 kg/m^3  ,  A = π/4 * d^2 , V = 18 m/s

input values into equation 1

F = 407.15 N

finally determine the acceleration at t = 0

F = m*a

a = F / m =  407.15 / 750 = 0.5429 m/s^2

Answer:

30 m

Explanation:

Answer:

-11459.478 N

Explanation:

mass of the ball = 152 g = 152 / 1000 = 0.152 kg

initial speed of the ball = 40.6 m/s

final speed of the ball = - 46.1 m/s

time of impact = 1.15 ms = 1.15 / 1000 = 0.00115 s

impulse, Ft = change in momentum = mv - mu = m (v-u)

F = m (v - u) / t = 0.152 kg ( -46.1 -40.6) / 0.00115 s = -11459.478 N

a) The cost of using the microwave oven for one hour is 6 cents.

b) The cost of using the microwave oven for 20 minutes in a day is 2 cents.

c) The cost of using the microwave oven for 20 minutes a day for a month of 30 days is 59 cents.

a) The microwave oven draws 0.8 kWh of electricity for one hour. The cost of electricity per kWh is 7.5 cents. Therefore, the cost of using the microwave oven for one hour can be calculated as follows:

Cost = 0.8 kWh x $0.075/kWh = $0.06

b) If the microwave oven is used for 20 minutes in a day, the energy consumed can be calculated as follows:

Energy consumed = Power x Time

Power = Energy consumed / Time

We know that the microwave oven draws 0.8 kWh of electricity for one hour. Therefore, the power can be calculated as:

Power = 0.8 kWh / 1 hour = 0.8 kW

The time for which the microwave is used is 20 minutes, or 0.33 hours. Therefore, the energy consumed can be calculated as:

Energy consumed = Power x Time = 0.8 kW x 0.33 hours = 0.264 kWh

The cost of using 0.264 kWh of electricity can be calculated as:

Cost = 0.264 kWh x $0.075/kWh = $0.02

c) If the microwave oven is used for 20 minutes a day for a month of 30 days, the energy consumed can be calculated as:

Energy consumed = Power x Time x Number of days

Power = Energy consumed / Time

Using the same values of power and time as in part b, the energy consumed for 30 days can be calculated as:

Energy consumed = 0.8 kW x 0.33 hours x 30 days = 7.92 kWh

The cost of using 7.92 kWh of electricity can be calculated as:

Cost = 7.92 kWh x $0.075/kWh = $0.59

In summary, the cost of using a microwave oven for electrical energy consumption depends on the power rating of the oven and the cost of electricity per kWh. By calculating the energy consumed and multiplying it by the cost per kWh, one can determine the cost of using the microwave for a particular period of time.

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Answer:

If Earth hadn't been hit by Orpheus, it would be covered by ocean, with perhaps a few mountaintops emerging through the water. There would be no humans, but there could be other forms of life. Earth would rotate rapidly, as the moon would not be present to produce the tidal friction that slows Earth's rotation today

Answer:

\(Velocity=\frac{dx}{dt}\)

Explanation:

Remember that instantaneous velocity is just a measure to know the velocity that any object has at any point given in time, so we just need to know the distance it has travel, which would be the change in position, and the time it took that change in position to occurr, this means distance by time, so we just divide dx by dt and we have the solution for instantaneous velocity.

If a change in position as denoted by \(dx\) and \(dt\) change in time, the instantaneous velocity will be given by,

\(v = \dfrac {dx}{dt}\)

\(v = \dfrac {dx}{dt}\)

Where,

\(v\) - instantaneous velocity

\(dt\)   - change in distance (position)

\(dt\)- change in time

Therefore, if a change in position as denoted by \(dx\) and \(dt\)change in time, the instantaneous velocity will be given by,

\(v = \dfrac {dx}{dt}\)

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Distance between two lines of grating is 4.85*10^-4 cm.

The act of bending light around corners where it spreads out and illuminates regions is known as the diffraction of light.

A optical element known as a diffraction grating splits light into numerous beams that move in various directions. The directions, as well as diffraction angles of these beams, depending on the wavelength of the incident light, the angle at which the wave strikes, and the distance or spacing between consecutive diffracting elements.

The distance between the two grating lines is calculated by taking the reciprocal of the grating value which is provided.

Distance between two lines of grating is, 1/2060 = 4.85*10^-4 cm.

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Answer:

any substance which does not allow the passage of electricity through it is known as insulator

Answer:

1.60 s

Explanation:

t² = (2h)/g

t = √(2h)/g

t = \(\sqrt{2(12.6m)/9.80 m/s2}\)

t = 1.60 s

Answer:

\(\alpha =1\ rad/s^2\)

Explanation:

It is given that,

The radius of a wheel, r = 2 m

Tangential acceleration of the wheel, \(a=2\ m/s^2\)

We need to find the angular acceleration of the wheel. We know that the relation between angular and tangential acceleration is given by :

\(a=\alpha r\\\\\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{2}{2}\\\\\alpha =1\ rad/s^2\)

So, the angular acceleration of the wheel is \(1\ rad/s^2\).

Answer:

There is always space (vacuum) between particles. The particles are small objects that exist in (sometimes vast) empty space. In gas particles there's a lot more space between the particles; the particles fly around in vacuum, bumping into each other.

Answer:

A) F = 1.8375 N, B) V = 1.25 10⁻⁴ m³, C) V= 1.25 10⁻⁴ m³

Explanation:

This exercise should select some values ​​such as the weight of the block m=0.250 kg and the density of the liquid ρ = 500 kg / m³ (water); with these values ​​answer the question, for this we use the static equilibrium relations.

          Σ F = 0

          F + B - W = 0

the expression for thrust is

          B = ρ g V_liquid

A) the weight of the block is

          W = m g

          W = 0.250 9.8

          W = 2.45 N

Let's look for the maximum push

           V_body = V_liquid

            B = 500 9.8 0.05³

           B = 0.6125 N

we substitute

          F = W - B

          F = 2.45 - 0.6125

          F = 1.8375 N

B) As the body is totally submerged, the volume of the liquid and the body are equal

           V = l³

           V = 0.05³

           V = 1.25 10⁻⁴ m³

C) the volume of water displaced is equal to the volume of the body

           V_liquid = 1.25 10⁻⁴ m³

The diameter of the Moon is around one-fourth (27.2%) of the diameter of the Earth.

what is diameter ?

A diameter of a circle would be any straight line segment that goes through the Centre of the circle and has ends that are on the circle. It can alternatively be described as the circle's longest chord. Both definitions are true for the diameter of a sphere.

In current parlance, the length d of a diameter is also referred to as the diameter. In this context, the diameter is used rather than the diameter (which corresponds to the line segment itself), since all diameters of a circle or sphere share the same length, which is twice the radius.

3476 km is the diameter of the moon (equator) 3472 kilometres 

The diameter of the Earth is 12756 km at the equator and 12742 km at the poles.

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Answer:

The average angular acceleration is 0.05 radians per square second.

Explanation:

Let suppose that Ferris wheel accelerates at constant rate, the angular acceleration as a function of change in angular position and the squared final and initial angular velocities can be clear from the following expression:

\(\omega^{2} = \omega_{o}^{2} + 2 \cdot \alpha\cdot (\theta-\theta_{o})\)

Where:

\(\omega_{o}\), \(\omega\) - Initial and final angular velocities, measured in radians per second.

\(\alpha\) - Angular acceleration, measured in radians per square second.

\(\theta_{o}\), \(\theta\) - Initial and final angular position, measured in radians.

Then,

\(\alpha = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot (\theta-\theta_{o})}\)

Given that \(\omega_{o} = 0\,\frac{rad}{s}\), \(\omega = 0.70\,\frac{rad}{s}\) and \(\theta-\theta_{o} = 4.9\,rad\), the angular acceleration is:

\(\alpha = \frac{\left(0.70\,\frac{rad}{s} \right)^{2}-\left(0\,\frac{rad}{s} \right)^{2}}{2\cdot \left(4.9\,rad\right)}\)

\(\alpha = 0.05\,\frac{rad}{s^{2}}\)

Now, the time needed to accelerate the Ferris wheel uniformly is described by this kinematic equation:

\(\omega = \omega_{o} + \alpha \cdot t\)

Where \(t\) is the time measured in seconds.

The time is cleared and obtain after replacing every value:

\(t = \frac{\omega-\omega_{o}}{\alpha}\)

If \(\omega_{o} = 0\,\frac{rad}{s}\),  \(\omega = 0.70\,\frac{rad}{s}\) and \(\alpha = 0.05\,\frac{rad}{s^{2}}\), the required time is:

\(t = \frac{0.70\,\frac{rad}{s} - 0\,\frac{rad}{s} }{0.05\,\frac{rad}{s^{2}} }\)

\(t = 14\,s\)

Average angular acceleration is obtained by dividing the difference between final and initial angular velocities by the time found in the previous step. That is:

\(\bar \alpha = \frac{\omega-\omega_{o}}{t}\)

If \(\omega_{o} = 0\,\frac{rad}{s}\),  \(\omega = 0.70\,\frac{rad}{s}\) and \(t = 14\,s\), the average angular acceleration is:

\(\bar \alpha = \frac{0.70\,\frac{rad}{s} - 0\,\frac{rad}{s} }{14\,s}\)

\(\bar \alpha = 0.05\,\frac{rad}{s^{2}}\)

The average angular acceleration is 0.05 radians per square second.

The change in Mary’s potential energy is 3412.5 Joule.

Potential energy is a form of stored energy that is dependent on the relationship between different system components. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.

Given that: Mary weighs 525 N and she walks down a flight of stairs to a level 6.5 m below her starting point.

Hence, change in potential energy is = weight × change in height

= 525 N × 6.5 m

= 3412.5 Joule.

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Answer:

See below

Explanation:

Specific heat of water = 4.182 J / g-C°

4.182  J / g-C  * 60 g  *  °C = - 313   J       where C is the change in degrees

°C = -1.247°   <==== this is the temp change from 23.52 °C

(23.52 - 1.247 =22.57 ° C is the final temp)

A battery of 9 volts is connected to a resistor of 1000 ohms, then the value of current flowing through it will be 0.009 A.

Any flow of electrical charge carriers, such as ions, holes, or subatomic charged particles, is referred to as electrical current.

When electrons serve as the charge transfer in a wire, the amount of charge moving through any point of wire in a given amount of time is measured as electric current. Electric charges' motion is intermittently reversed in the alternating current, but not in direct current.

In many situations, the direction of movement in electric circuits is assumed to be the direction of positive charge flow, which is the way opposite of the real particle drift. When properly specified, the current is known as conventional current.

From the question,

V = ir

i = v/r

i = 9/1000

i = 0.009 A

Therefore, the value of the current flowing through it is  0.009 A.

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