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The speed that the mobile develops is 160 kilometers per hour or 44.4 meters per second.

Explanation:

Data:

Formula:

Developing:

Conversion:

V = 44.4m/s

¿Doubts? On the comments. Greetings :D

Answer:

Thanks For the points

The result or 44.4 m/s

Convex mirror always produces virtual images is the correct option.

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Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

The stone moves at a linear speed of 9.42 m/s.

Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).

The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.

C = 2πr

where r is the rope's length. If we substitute r = 30 cm, we obtain:

C = 2π(30 cm) ≈ 188.5 cm

As a result, one revolution of the stone moves it approximately 188.5 cm.

The stone moves a total of five times, covering the following distance:

d = 5(188.5 cm) = 942.5 cm

v = d/t

Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:

v = d/t = 942.5 cm/t

To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:

v = 9.425 m/t

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Given:

m = 32.6 g

Vi = 2.8 ml

vf = 5.7 ml

Apply:

ρ= mass / volume

Replacing:

ρ = 32.6g / (5.7 - 2.8 ) mL = 11.24 g/mL

Answer: 11.24 g/mL

If you need to shade the part of a circle indicative of parent material, these are the guidelines:

It should be noted that to complete the shading process, employ techniques such as utilizing solid colors with pencils, markers, cross-hatching, or diagonal lines.

Ensure that you correctly portray the shaded fraction of the circle and provide clear contrasts between the unshaded segment.

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Answer:

iv

Explanation:

to be honest the others make since but the last 1 and all of the others are actually used.

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Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is  the objects have opposite charges.

An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.

In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.

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Answer: 1.646 m/s²

Explanation:

The distance that is traveled by the astronaut given that the motion is free-fall can be calculated through the equation,

   d = Vot + 0.5at²

where d is the distance, Vo is the initial velocity, t is the time, and a is the acceleration. Substituting the known,

  6 = (0 m/s)(2.7 s) + 0.5(a)(2.7 s)²

Determining the value of a,

   a = 1.646 m/s²

Answer:

C- The more food and garnishes on the plate, the better.

The rate at which an object changes its velocity is known as acceleration, a vector quantity.

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Answer:

a. \(\mathbf{F_{f_2} = 2 F_{f1}}\), \(\mathbf { since \ the \ force \ o f \ friction \ is \ represented \ as \ the \ slope \ for \ each \ of \ the \ two \ curves.}\)

Explanation:

From the information given;

Using the work-energy theorem

ΔKE = W = \(\mathbf{ F_f \times r}\)

K = \(\mathbf{ F_f \times r}\)

∴

\(\dfrac{K_1}{K_2} = \dfrac{F_{f1}}{F_{f2}} (\dfrac{r_1}{r_2})\)

Since \(K_1 = K_2\) and r_1 = 4, and r_2 = 2 (from the missing diagram which is attached below)

Then;

\(1 = \dfrac{F_{f1}}{F_{f2}} (\dfrac{4 \ m}{2 \ m})\)

\(\mathbf{F_{f_2} = 2 F_{f1}}\)

Answer:

skalarna wielkość fizyczna charakteryzująca stan układu fizycznego (materii)

jako jego zdolność do wykonania pracy

Answer:

8a = 20.   8b=4

Explanation:

Distance is total amount the object moved. It went from 10, to -2 which is 12 meters away, then to 6 which is 8, adding 8 and 12 is 20 so that is the distance. Displacement is how far it is relative to the starting position, so 10 and 6 are 4 meters away, therefore displacement is 4.

Hope I helped : )

Answer:

i think the 2nd one

the first=0 b/c it's initial velocity and final ones are equal the third one is constant

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

\(f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz\)

The angular frequency of the oscillation is calculated as follows;

\(\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s\)

The force constant of the spring is calculated as follows;

\(\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m\)

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Answer:

the magnitude of the ball's acceleration as it comes to rest on the foam is 817.5 m/s²

Explanation:

Given the data in the question;

initial velocity; u = 0 m/s

height; h = 2.5 m

we find the velocity of the ball just before it touches the foam.

using the equation of motion;

v² = u² + 2gh

we know that acceleration due gravity g = 9.81 m/s²

so we substitute

v² = ( 0 )² + ( 2 × 9.81 × 2.5 )

v² = 49.05

v = √49.05

v = 7.00357 m/s

Now as the ball touches the foam

final velocity v₀ = 0 m/s

compresses S = 3 cm = 0.03 m

so

v₀² = v² + 2as

we substitute

( 0 )² = 49.05 + 0.06a

0.06a = -49.05

a = -49.05 / 0.06

a = -817.5 m/s²

Therefore, the magnitude of the ball's acceleration as it comes to rest on the foam is 817.5 m/s²

Answer:

The experimental procedures that will allow the students to determine both of these relationships is option E:

The formula  F = IL x B calculates the magnetic force acting through a magnetic field on a current-carrying wire. The magnetic field acts on a wire when a current is conducted through it in a direction that is perpendicular to both the magnetic force.

By increasing the amount of current flowing through the wire, the magnetic field's strength can be enhanced. As you get further from the wire, the strength gets weaker. If the amount of current flowing through it stays constant, its length and thickness have no bearing.

Therefore, the length of the wire in the magnetic field has an impact on the magnetic force's strength as well. The force acting on a wire increases with wire length in a magnetic field.

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When the wildebeest pick up their race again, they will be 83.82 meters from the end zone (a). The speed of the gazelle is 15.0 m/s (b) The wildebeest remained motionless for 450 seconds.

Velocity is the pace and velocity of an object's mobility, whereas speed is the forecasting at which an element is travelling along a path.

Distance, S = 1.90 Km

= 1900 m

S1 = 1.520 km

= 1520 m

Speed V1 = 15 m/s

V2 = 3.30 m/s

Time, t1 = S1/t1

= 1520/15

= 101 s

t2 = 380/15

= 25.4 s

T = S/ V2

= 1900/3.3

= 576 s

(a) distance = 3.3 * 25.4

= 83.82 m

(b) Time = T -(t1 + t2)

= 576 -126.4

= 449.6

= 450 s

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Magnetic particle separation is a powerful tool for separating particles based on their velocities in a magnetic field, and it has significant practical applications in various scientific and technological fields.

To separate particles of different velocities moving in a magnetic field, one can utilize a technique called magnetic field separation or magnetic particle separation.

This method takes advantage of the fact that charged particles moving in a magnetic field experience a force called the Lorentz force, which acts perpendicular to both the velocity vector and the magnetic field.

The basic principle behind magnetic particle separation is to apply a magnetic field perpendicular to the motion of the particles. The Lorentz force will then cause the particles to curve in different directions based on their velocities and charges.

By carefully controlling the strength and direction of the magnetic field, particles with different velocities can be steered onto different paths and separated.

One common approach to achieve magnetic particle separation is to use a device called a magnetic separator. This device typically consists of a strong magnet or a series of magnets arranged to create a uniform magnetic field.

The particles to be separated are injected into a chamber or a flow system where the magnetic field is applied. As the particles move through the magnetic field, they experience the Lorentz force and deviate from their original trajectory. The degree of deviation depends on their velocity and charge.

By carefully adjusting the magnetic field strength, particle size, and other parameters, it is possible to optimize the separation process and achieve effective separation of particles with different velocities. This technique has various applications in fields such as biomedical research, environmental monitoring, and materials science.

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The exploded star is called a black hole.

The time horizon of the black hole is an area of spacetime where gravitational pull is so intense that nothing, not even light or other electromagnetic waves, have the energy to pass through it.

It is believed that the first black holes appeared shortly after the big bang, in the beginning of the cosmos. When the core of an extremely massive star is collapsed on itself, stellar black holes are created.

A supernova, also known as an exploding star, is also brought on by this collapse and sends a portion of the star into space.

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Answer:

Therefore it is save to carry a 62kg adult

Explanation:

From the question we are told that:

Mass \(m=380kg\)

Height of supporting Rock \(X=85cm\)

Length of Board\(L_r=4.5m\)

Mass of board \(M_b=22kg\)

Mass of adult \(M_a=62\)  

Generally the moment of balance about wedge part about  is mathematically given by

\(N -Q + R = Mg + mg\)

\(0.85*N - Mg*2.25 - mg*(2.25 + x) = 0\)

\(0.85*N = + Mg*2.25 + mg*(2.25 + x)\)

where

\(N+R=4547\)

therefore

\(N = 570.70588 + 1608.3529 + 714.823 x\)

if N=0 at fallen person

\(x=3.04m\)

Therefore it is save to carry a 62kg adult

The potential and kinetic energy of the system at the following time instances is zero and maximum.

From the given,

The displacement of the system is, x = A cos(3πt/T)

1) At t =0, the displacement of the system is given by, x = cos(3π×0/T)= cos(0) = 1. The displacement is maximum at t=0. Hence, the potential energy is maximum and kinetic energy is zero.

2) At t=T, the displacement, x = cos(3πT/T)= cos(3π) = -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

3) At t = T/6, the displacement x = cos(3πT/6T)=cos(π/2)=0, the displacement is zero, and hence, both the potential and kinetic energy is zero.

4) At t=T/3, the displacement, x= cos(3πt/T)=cos(3πT/3)= -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

5) At t=T/2, the displacemetn x = cos(3πt/T) = cos(3πT/2T) = cos (3π/2)=0. Hence, both the potential and kinetic energy is zero.

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Answer:

Below

Explanation:

   Acceleration = change in velocity / change in time = 35/5 = 7 m/s^2

F = m * a

  = 6000 kg  *   7  m/s^2 = 42 000 N

The average net force exerted on the boxcar and its riders by the magnets is 42,000 N.

The average net force exerted on the boxcar and riders by the magnets is calculated as;

F(net) = ma

where;

The acceleration is calculated as;

a = Δv / Δt

a = 35 m/s / 5 s

a = 7 m/s²

The acceleration of the boxcar and its riders is 7 m/s².

The average net force exerted on the boxcar and riders by the magnets is;

F = 6,000 kg x 7 m/s²

F = 42,000 N

Thus, the average net force exerted on them is determined as 42,000 N.

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The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)

The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)

The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)

force = mass * acceleration

mass1 = 62 kg

force1 = 480 N

acceleration1 = force / mass

                     = 480 / 62 = 7.74 \(m/s^{2}\)

mass2 = 62 kg

force2  = 240 N

acceleration 2  = 240 / 62 = 3.87  \(m/s^{2}\)

mass 3 = 62 kg

force 3  = 600 N

acceleration 3  = 600 / 62  = 9.68  \(m/s^{2}\)

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Explanation:

Momentum is conserved in the collision. Momentum is conserved for any interaction between two objects occurring in an isolated system.