Neutron stars, such as the one at the center of the Crab Nebula, have about the same mass as our Sun, but a much smaller diameter.
If you weigh 715 N on the Earth, what would you weigh on the surface of a neutron star that has the same mass as our Sun and a diameter of 20.0 km?
Express your answer with the appropriate units.
Answers
We would weigh 9.68x1013 N on the surface of a neutron star with the same mass as our Sun and a diameter of 20.0 km if we were to weigh 715 N on Earth.
According to the information provided, a neutron star has the same mass as the Sun, making its mass (m2) = 1.99x10^30 kg.
We must first determine our mass using the formula Fg = mg.
Given force (F) = 715N
mass (m) = 715/9.8 = 72.95kg
The distance from a planet's centre to its surface, as determined by the force of gravity equation, is equal to r.
Since the issue gives us the diameter, we can utilise it to find the radius, which is given by r = d/2.
Given distance (d) = 20km
r = 20/2 = 10km = 10000m
Now, using the formula for the force of gravity, we can determine our weight at the star: F = Gm1m2/r^2
G = gravitational constant = 6.67×10-11 N* m^2/kg^2
F = (6.67×10-11)x72.95x 1.99×10^30/10^8 = 9.68x10^13N
Hence the weight on surface of neutron star = 9.68x10^13N
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Related Questions
A radioactive isotopes has a life-life of 15 days and an initial
count-rate is 2000 counts per second. Determine the count-rate after
45 days.
Counts/s
Answers
The activity is a radioactive material is the number of counts per second it produces. 1 count per second (cps) = 1 Becquerel (Bq).
What is radioactive?As its name implies, radioactivity is the act of emitting radiation spontaneously. This is done by an atomic nucleus that, for some reason, is unstable; it "wants" to give up some energy in order to shift to a more stable configuration. During the first half of the twentieth century, much of modern physics was devoted to exploring why this happens, with the result that nuclear decay was fairly well understood by 1960. Too many neutrons in a nucleus lead it to emit a negative beta particle, which changes one of the neutrons into a proton. Too many protons in a nucleus lead it to emit a positron (positively charged electron), changing a proton into a neutron. Too much energy leads a nucleus to emit a gamma ray, which discards great energy without changing any of the particles in the nucleus. Too much mass leads a nucleus to emit an alpha particle, discarding four heavy particles (two protons and two neutrons).To learn more about neutrons refer to:
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What is the magnitude and direction of the magnetic force on the bob at the lowest point in its path, if it has a positive 0.250 μC charge and is released from a height of 30.0 cm above its lowest point? The magnetic field strength is 1.50 T.
Answers
Answer:
\(F=9.09\times 10^{-7}\ N\)
Explanation:
Given that,
Charge, q = 0.250 μC
It is released from a height of 30 cm or 0.03 m
The magnetic field strength is 1.50 T.
First we find the velocity using the conservation of energy as follows :
\(mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 0.3} \\\\v=2.424\ m/s\)
Now, the magnetic force is given by :
\(F=qvB\\\\=0.25\times 10^{-6}\times 2.424\times 1.5\\\\=9.09\times 10^{-7}\ N\)
So, the magnetic force is \(9.09\times 10^{-7}\ N\). Since, the bob is at the lowest point, the direction of the magnetic force at the lowest point is upward.
Suzanne observes two light pulses to be emitted from the same location, but separated in time by 3.00 μs. Mark sees the emission of the same two pulses separated in time by 9.00 μs. (a) How fast is Mark moving relative to Suzanne? (b) According to Mark, what is the separation in space of the two pulses?
Answers
Given that,
Separated in time t = 3.00 μs
Separated in time t' = 9.00 μs
(a). We need to calculate the speed
Using formula of time dilation
\(t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}\)
\(\dfrac{t}{t'}=\sqrt{1-\dfrac{v^2}{c^2}}\)
\(\dfrac{v^2}{c^2}=1-\dfrac{t^2}{t'^2}\)
\(v=c\sqrt{1-\dfrac{t^2}{t^2}}\)
Put the value into the formula
\(v=c\sqrt{1-\dfrac{3.00^2}{9.00^2}}\)
\(v=0.942c\)
(b). The separation that Mark sees is just the time he sees between the pulse times the speed of light,
Since the first pulse is moving at that speed
We need to calculate the separation in space of the two pulses
Using formula of separation
\(x=ct'\)
Put the value into the formula
\(x=3\times10^{8}\times9\times10^{-6}\)
\(x=2700\ m\)
Hence, (a). The speed of mark relative to Suzanne is 0.942c.
(b). The separation in space of the two pulses is 2700 m.
Einstein developed much of his understanding of relativity through the use of gedanken, or thought, experiments. In a gedanken experiment, Einstein would imagine an experiment that could not be performed because of technological limitations, and so he would perform the experiment in his head. By analyzing the results of these experiments, he was led to a deeper understanding of his theory. In each the following gedanken experiments, Albert is in the exact center of a glass-sided freight car speeding to the right at a very high speed vvv relative to you. Albert has a flashlight in each hand and directs them at the front and rear ends of the freight car. Albert switches the flashlights on at the same time.
In Albert's frame of reference, which beam of light travels at a greater speed, the one directed toward the front or the one toward the rear of the train, or do they travel at the same speed? Which beam travels faster in your frame of reference? Enter the answers for Albert's frame of reference and your frame of reference separated by a comma using the terms front, rear, and same. For example, if in Albert's frame of reference the beam of light directed toward the front of the train travels at a greater speed and in your frame of reference the two beams travel at the same speed, then enter front,same.
Answers
Answer:
For eintein's frame of reference, both beam travel at the same speed.
For my own frame of reference, both beams travel at the same speed.
Explanation:
According to special relativity, the speed of light is the same in all direction on all reference frame. If not for this law we will assume the from beam will have a relative speed that will be the speed of light plus the speed of the fright car. This is not so and it violates the speed limit of light which according to the first law is the highest speed possible and nothing can go beyond that.
Jenny experiences an average downward force of 441 N anywhere she goes on Earth. Calculate her mass
Answers
Answer:
Given,
Force = 441 N
mass = ?
Keep in mind that acceleration due to gravity is constant 10m/s.
Force = mass × acceleration due to gravity
mass = Force / acceleration due to gravity
m = 411 N /10m/s
m = 41.1 kg
Therefore her Jenny mass is 41.1 kg.
Tuning a guitar string, you play a pure 330 Hz note using a tuning device, and pluck the string. The combined notes produce a beat frequency of 5 Hz. You then play a pure 350 Hz note and pluck the string, finding a beat frequency of 25 Hz. What is the frequency of the string note?
Answers
Answer:
The frequency is \(F = 325 Hz\)
Explanation:
From the question we are told that
The frequency for the first note is \(F_1 = 330 Hz\)
The beat frequency of the first note is \(f_b = 5 \ Hz\)
The frequency for the second note is \(F_2 = 350 \ H_z\)
The beat frequency of the first note is \(f_a = 25 \ Hz\)
Generally beat frequency is mathematically represented as
\(F_{beat} = | F_a - F_b |\)
Where \(F_a \ and \ F_b\) are frequencies of two sound source
Now in the case of this question
For the first note
\(f_b = F_1 - F \ \ \ \ \ ...(1)\)
Where F is the frequency of the string note
For the second note
\(f_a = F_2 - F \ \ \ \ \ ...(2)\)
Adding equation 1 from 2
\(f_b + f_a = F_1 + F_2 + ( - F) + (-F) )\)
\(f_b + f_a = F_1 + F_2 -2F\)
substituting values
\(5 +25 = 330 + 350 -2F\)
=> \(F = 325 Hz\)
Which of the following are considered to be price discrimination? (Select all that apply.)
Giving seniors a breakfast discount at the local diner.
Providing a bulk discount for school supplies to local school districts.
Charging schoolchildren half-fare for subway or bus transport.
Charging less for phone services in one location to drive out a competitor.
Answers
Charging less for phone services in one location to drive out a competitor is considered to be price discrimination.
What is price discrimination?A selling tactic known as price discrimination involves charging clients various rates for the same good or service depending on what the vendor believes they can persuade the customer to accept.
When a merchant uses pure price discrimination, they charge each consumer the highest price they will agree to.
In more prevalent types of price discrimination, the supplier divides clients into groups based on particular characteristics and assesses a different price to each group.
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State the three rules of refraction for converging lenses
Answers
The three rules of refraction for converging lenses, also known as convex lenses, are as follows:
1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.
2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.
3. The incident ray passing through the center of the lens continues undeviated.
The three rules of refraction for converging lenses, also known as convex lenses, are as follows:
1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.
When a ray of light traveling parallel to the principal axis (the horizontal line passing through the center of the lens) enters a converging lens, it refracts and bends toward the principal axis. After refraction, the ray passes through the focal point on the opposite side of the lens. This rule is essential in understanding the behavior of light rays in converging lenses.
2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.
When a ray of light passes through the focal point before entering the lens, it refracts and emerges parallel to the principal axis. This rule implies that light rays that enter the lens at different angles converge and meet at the focal point on the opposite side.
3. The incident ray passing through the center of the lens continues undeviated.
When a ray of light passes through the center of a lens, it continues in a straight line without deviating from its path. This rule is derived from the fact that the refractive index of the lens material is the same throughout, resulting in no change in the direction of light passing through the center of the lens.
These rules of refraction for converging lenses help in understanding how light rays interact with the lens and how the lens focuses incoming light. By applying these rules, one can predict the behavior of light rays and determine the location and characteristics of images formed by converging lenses.
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Why does Earth have a liquid water supply and Mars does not?
A. Mars is too cold.
B. Mars has no magnetic field.
C. Earth was never bombarded with comets.
D. Mars is much larger than Earth.
Answers
Answer:
Earth have a liquid water supply and Mars does not because of the difference in their magnetic fields. Therefore the option B is correct.
Explanation:
The atmosphere of Earth is shielded from solar winds and radiation by a potent magnetic field, which keeps the atmosphere from being torn away. This enables water to remain liquid on the surface of the planet.
Mars, in contrast, has a weaker magnetic field, which results in a thinner atmosphere that is unable to support liquid water. Mars is hence more colder and drier than Earth.
One of the main reasons that Mars has no life as we know it is because it lacks a magnetic field, whereas the magnetic field of Earth is crucial in fostering the conditions necessary for life to flourish.
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A physics book slides off a horizontal tabletop with a speed
of 1.10 m/s. It strikes the floor in 0.480 s. Ignore air resistance.
What is the height of the tabletop above the floor in meters.
Answers
A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.480 s. The height of the tabletop above the floor is 0.264 m.
Given data:
Speed = 1.10 m/s
Time taken to strike the floor = 0.480 s
We are supposed to find the height of the tabletop above the floor in meters.
We can use the formula of distance to calculate the height of the tabletop above the floor.
We also need to make use of kinematic equations to find out the distance fallen by the book.
Let us first calculate the distance fallen by the book.
Let the height of the table be ‘h’.
From the kinematic equations of motion, we know thats = ut + 1/2 at²Here, u = 1.10 m/s, a = acceleration due to gravity = 9.8 m/s², t = 0.480 s
Putting these values in the above equation, we get:s = 1.10 × 0.480 + 1/2 × 9.8 × (0.480)² = 0.264 m
Now, we can find the height of the tabletop using the formula of distance.d = h + sHere, d = distance fallen by the book = h, s = 0.264 m
Putting these values in the above equation, we get: h = d = s = 0.264 m
Therefore, the height of the tabletop above the floor is 0.264 m.
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No no no no. no no no no
Answers
Loosing weight without diet require moving to the top of a mountain explain using weight and gravitational force
Answers
Answer:
You would weigh very slightly more at sea level than at the top of a mountain, not enough for you to notice, but a measurable amount. Weight, which really means gravitational force, is proportional to the product of the masses of two objects acting on each other, in this case the giant earth and the minuscule you.
Explanation:
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
Answers
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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A heat engine receives heat of 400kW from a heat source of 1100 K, and rejects the waste heat into a heat sink at 320K. It generates 120 kW of power output. Determine the 2nd law thermal efficiency of the heat engine.
Answers
Answer:
Explanation:
efficiency of carnot engine operating between 1100 K and 320 K
= 1100 - 320 / 1100
= .709
efficiency of heat engine = 120 / 400 = .30
2 nd law thermal efficiency of heat engine = .30 x 100 / .709
= 42.31 % .
If an object is placed 15cm in of front of a concave mirror of radius Curvature 20cm. Determine the position of the image formed
Answers
The image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.
Given that,
Object distance, u = -15 cm
The radius of curvature of the concave mirror, R = 20 cm
Focal length, f = R/2 = -10 cm (negative for concave mirror)
Let v is the distance between mirror and the formed image. Using mirror's formula to find it as :
\($\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$\)
\($\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$\)
\($\frac{1}{v}=\frac{1}{(-10)}-\frac{1}{(-15)}$\)
\($v=-30 \mathrm{~cm}$\)
So, the image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.
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It occurs if the amount of loads is greater than the current carrying capacity of the electric wave
A: simple circuit
B: Short circuit
C: overload circuit
D: Switch
Answers
Answer:
C. Overload circuit
Explanation:
Sana ka tulong mark me brainliest plsss thnks
Help, I really need to solve this right away!!
Answers
Answer:
can you like zoom in i cant see that much.
Explanation:
what is a water resavore.......................................
Answers
Answer: A Water resavoir is a place where they hold water until needed. Like let's say there was a drought in Arizona, the state would rely on the resavoir's until the drought is gone. I hope I explained it well.
A p.d. of 6 V is applied across a 2 resistor. What current flows?
Answers
Answer: current is 3 A.
Explanation:
V = 6V
R = 2Ω
I = ?
∴ V = IR
I = V/R
I = 6V/2Ω
I = 6/2
I = 3 A ...answer...
hope that helps...
Answer:
3 amps
Explanation:
V = IR
V/R = I
6/2 = 3 amps
4. Two people each have a mass of 55 kg. They are both in an
elevator that has a mass of 240 kg. When the elevator
begins to move, the people and the elevator have an upward
acceleration of 1.00 m/s2. What is the net force that acts on
the elevator as it accelerates upward at 1.00 m/s2?
Answers
Answer:
350 N
Explanation:
F=ma
\(f = force \\ m = mass \\ a = acceleration\)
\(m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} } \)
Force = 350 Newtons
The net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2.
What is Newton's second law?
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = ma
As given in the problem two people each have a mass of 55 kg. They are both in an elevator that has a mass of 240 kg. When the elevator begins to move, the people and the elevator have an upward acceleration of 1.00 m/s2, then we have to find the net force acting on the elevator,
The net force acting on the elevator,
F = ma
F =(2×55 + 240)×1
= 350 Newtons
Thus, the net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2
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Whether or not electrons will be ejected from metal when light shines on the metal depends on
Answers
Answer:
Mark me as barinlest
Explanation:
If you shine light of high enough energy on to a metal, electrons will be emitted from the metal. Light below a certain threshold frequency, no matter how intense, will not cause any electrons to be emitted. Light above the threshold frequency, even if it's not very intense, will always cause electrons to be emitted.
Consider me the worst. When a metal is exposed to high-energy light, electrons are released. Electrons cannot be released below a certain frequency, no matter how bright the light is. Even in the absence of significant intensity, light above the threshold frequency will always result in electron emission.
What takes place when light hits metal?The photoelectric effect occurs when light shines on a metal and causes electrons to be ejected from the metal's surface. This process is also known as photoemission, and the electrons ejected from the metal are known as photoelectrons. In general, metals with high free electron mobility, such as Au, Ag, Cu, and Bi, enable LSPR absorption of light ranging from near infrared (IR) to ultraviolet (UV). Metal nanoparticles can also absorb light via inter-band electron transitions from the d-band to the sp-band. The photoelectric effect is a phenomenon that occurs when light shines on the surface of a metal and causes electrons to be released.To learn more about light hits metal, refer to:
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Which lists three organic biological molecules?
O carbohydrates, salts, metals
O salts, proteins, minerals,
O proteins, lipids, carbohydrates
O lipids, metals, minerals
Answers
Answer:
B
Explanation:
I'm learning it in science.
Answer:
its not b i just took the test and b was wrong
Explanation:
A particular cookie provides 54.0 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without acceleration) a 103-kilogram weight 2.45-decimeters above the ground with an energy efficiency of 25%. How many repetitions of this exercise can the athlete do with the energy supplied from one of these cookies?
Answers
The maximum quantity of repetitions that the athlete could complete with their current level of energy was 229 for such a workout.
Energy efficiency is the ratio of input power to energy output. As just a result, a cookie contains 54.0 kcal in calories. An athlete utilizes the 54.0 kcal in just this cookie for input energy.
The following formula could be employed to measure efficiency:
Energy intake minus power generated is efficiency.
Efficiency = output energy / input energy
After rearrangement above equation.
output energy = efficiency × input energy
Put the given data in above equation.
Output energy = 0.25 × 54 kcal = 13.5 kcal.
Again for power capacity, the lifting exercise was already carried out n times. The source of total output energy is mgh within the form of electromagnetic potential.
So, Energy per repetition = mgh
Where, m will represent mass g will represent gravity h is height.
By entering the data provided above.
Energy per repetition = 103 kg × 9.8 m/\(s^{2}\) × (2.45 × 0.1m)
Energy per repetition= 247.303 J
Energy per repetition = 0.059 kcal.
So, quantity of repetitions = overall output energy / energy per repetition
quantity of repetitions = 13.5 kcal / 0.059 kcal
quantity of repetitions will be equal to 229 repetitions.
Therefore, the quantity of repetition would be be 229.
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Graph a heating curve for water. Label (with the most specific names & numbers) the following parts of the graph, adding units where appropriate:
1) x axis
2) y axis
3) title
4) all 3 phases of matter
5) show where KE is increasing
6) show where PE is increasing
7) identify the phases changes
Answers
Answer:
Explanation:
1. x-axis: Temperature (in degrees Celsius)
2. y-axis: Heat (in Joules)
3. Title: Heating Curve for Water
4. All 3 phases of matter: solid (ice), liquid (water), gas (steam)
5. Show where KE is increasing: The line segment from A to B represents the increase in kinetic energy as the water is heated from solid to liquid state, and the line segment from C to D represents the increase in kinetic energy as the water is heated from liquid to gas state.
6. Show where PE is increasing: The line segment from A to B represents the increase in potential energy as the ice is melting into water, and the line segment from C to D represents the increase in potential energy as the liquid water is vaporizing into steam.
7. Identify the phase changes: The segment from A to B represents the melting of ice (solid to liquid), and the segment from C to D represents the vaporization of water (liquid to gas). The flat portions between B and C represent the heating of water in liquid state and the absorption of heat without any change in temperature (latent heat of fusion and latent heat of vaporization).
A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
Answers
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
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What would you do if natural calamity or disaster strikes you now ?
Answers
Answer:
How can you help the victims of any natural calamity or disaster?If you have not been ordered to evacuate, stay in a safe area or shelter during a natural disaster. In your home, a safe area may be a ground floor interior room, closet or bathroom. Be sure you have access to your survival kit in case you are in an emergency event that lasts several days.
Explanation:
hope that helps. Make sure to be safe and sheltered
A person following a liberal ideology would likely approve of
Answers
not sure sorry :5
If a violin A4 string has a length of 35 cm and is tightened to a tension of 60 N, what mass density should the string have?
Answers
The mass density of the violin A4 string should be approximately 1800 kg/m^3.
The mass density of a string can be calculated using the following formula:
ρ = T / ((π/4) * d^2 * L)
where:
ρ is the mass density of the string in kg/m^3
T is the tension in Newtons (N)
d is the diameter of the string in meters (m)
L is the length of the string in meters (m)
π is the mathematical constant pi, approximately equal to 3.14159
We are given the length of the violin A4 string (L = 0.35 m) and the tension on the string (T = 60 N). We are asked to find the mass density of the string (ρ).
The diameter of the string (d) is not given, so we cannot solve for it directly. However, we can make an assumption about the diameter based on typical values for violin strings.
A common diameter for a violin A4 string is 0.6 mm, or 0.0006 m. We will use this value for d.
Now we can solve for ρ:
ρ = T / ((π/4) * d^2 * L)
ρ = 60 N / ((π/4) * (0.0006 m)^2 * 0.35 m)
ρ ≈ 1800 kg/m^3
Therefore, the mass density of the violin A4 string should be approximately 1800 kg/m^3.
What is mass density?
Mass density, also known as density, is a measure of how much mass is contained within a given volume of a substance. It is usually denoted by the Greek letter rho (ρ) and is expressed in units of kilograms per cubic meter (kg/m^3) or grams per cubic centimeter (g/cm^3).
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1. Calculate the electric field due to a single +1nC point charge at a distance of lm, 2m, and 3m
Answers
Answer:
Approximately \(9.0\; \rm N \cdot C^{-1}\) at \(1\; \rm m\) from this charge, pointing away from the point charge.Approximately \(2.2\; \rm N \cdot C^{-1}\) at \(\rm 2\; \rm m\) from this charge, pointing away from the point charge.Approximately \(1.0\; \rm N \cdot C^{-1}\) at \(3\; \rm m\) from this charge, pointing away from the point charge.Assumption: there is no object between this point charge and the observer.
Explanation:
The electric field of a point charge is inversely proportional to the square of the distance from that point charge.
Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:
\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).
Convert the magnitude of the point charge in this question to standard units:
\(q = 1\; \rm nC = 10^{-9}\; \rm C\).
Apply that equation to find the magnitude of the electric field due to this point charge:
\(r = 1\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 2\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 3\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).
The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.
Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
Answers
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
Learn more about acceleration here: https://brainly.com/question/14344386
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