Answer:
force, move, mass
Explanation:
force, move, mass
It's a bit hard to explain, but force is needed to move the mass of an object
PLEASE help! I am so desperate LOL
1: A 75.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 20.0 m) and spun at a constant angular velocity of 15.0 rpm (revolutions per minute). He is then slowed and brought to a stop in 2.0 minutes.
(1a) Find the magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity.
(2a) How many g’s is the astronaut experiencing when moving at constant angular velocity?
(3a) Find the torque that is needed to bring the centrifuge to a stop knowing the centrifuge has a mass of 5500.0 kg (ignore all other forces) and the force is applied at the edge of the centrifuge (20.0 m radius). Hint: torque is based on the change of linear velocity.
2: An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion, as shown in this graph.
(2a) What is the period and frequency of the pendulum’s motion?
(2b) How many seconds out of phase with the displacements shown would graphs of the velocity and acceleration be?
(2c) What is the acceleration due to gravity on the surface of the planet in m/s2? Determine the number of g-forces.
Answer: (1a) The magnitude of the centripetal acceleration is 31.4 m/s^2, and the direction is towards the center of the circular motion.
(2a) The astronaut is experiencing 31.4 m/s^2 / 9.8 m/s^2 = 3.22 g's.
(3a) The torque needed to bring the centrifuge to a stop is (5500.0 kg * 31.4 m/s^2 * 20.0 m) = 3,420,000 N * m.
2:
(2a) The period of the pendulum's motion is 0.20 m / 0.10 m/s = 2.0 seconds, and the frequency is 1 / 2.0 s = 0.50 Hz.
(2b) The graphs of velocity and acceleration would be 0.5 seconds out of phase with the displacements shown.
(2c) The acceleration due to gravity on the surface of the planet is 0.10 m/s^2 / 9.8 m/s^2 = 1.02 g's.
Explanation:
What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?
a) 4. 1 atm
b) 5. 0 atm
c) 6. 4 atm
d) 1. 1 atm
The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
Therefore, option A is correct option.
Given,
Mass m = 14g
Volume= 3.5L
Temperature T= 75+273 = 348 K
Molar mass of CO = 28g/mol
Universal gas constant R= 0.082057L
Number of moles in 14 g of CO is
n= mass/ molar mass
= 14/28
= 0.5 mol
As we know that
PV= nRT
P × 3.5 = 0.5 × 0.082057 × 348
P × 3.5 = 14.277
P = 14.277/3.5
P = 4.0794 atm
P = 4.1 atm.
Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
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Air at 20°C blows over a 50 x 75 cm hot plate made of carbon steel (AISI 1010) with 2 cm thickness. The outer surface temperature of the plate is maintained at 300°C. The convection heat transfer coefficient is 25 W/m2⋅K. 300 W is lost from the plate surface by radiation, calculate the inside plate temperature
The inside plate temperature is approximately 235.7°C.
What is the temperature inside the carbon steel plate?The net heat transfer from the plate surface to the surrounding air can be calculated using the equation:
\(Q_n_e_t\) = \(Q_r_a_d_i_a_t_i_o_n\) - \(Q_c_o_n_v_e_c_t_i_o_n\)
where \(Q_r_a_d_i_a_t_i_o_n\) = σ(ε)(A)(T⁴) is the heat lost from the plate surface by radiation, \(Q_c_o_n_v_e_c_t_i_o_n\) = h(A)(\(T_p_l_a_t_e\) - \(T_a_i_r\)) is the heat transferred from the plate surface to the air by convection, σ is the Stefan-Boltzmann constant, ε is the emissivity of the plate, A is the surface area of the plate, T is the temperature of the plate in Kelvin, \(T_a_i_r\) is the temperature of the air, \(T_p_l_a_t_e\) is the inside plate temperature, and h is the convective heat transfer coefficient.
By rearranging the equation and solving for \(T_p_l_a_t_e\), we get:
\(T_p_l_a_t_e\) = [(\(Q_r_a_d_i_a_t_i_o_n\) - h(A)(\(T_p_l_a_t_e\) - \(T_a_i_r\)))/σ(ε)(A)\(]^(^1^/^4^)\)
Substituting the given values, we get:
\(T_p_l_a_t_e\) = [(300 - 25(0.5*0.75)(\(T_p_l_a_t_e\) - 20))/ (5.67 x \(10^-^8\) x 0.4 x 0.375)\(]^(^1^/^4^)\)
Solving for \(T_p_l_a_t_e\), we get:
\(T_p_l_a_t_e\) = 508.85 K = 235.7°C
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A child's jack is three small rods joined at their centers, all at right angles. Pretend the rod's are uniform and identical. Calculate the rotational inertia of the jack if it is pivoted like a top: in the figure the vertical rod stays still and the other two rotate about it as an axis. Take the mass of one rod to be 1. 6 grams and 2 cm in length. Report your answer in millionths (10^-6) of a kgm2
The rotational inertia of the rod with a mass of the rod is 1.6 grams and the length of the rod is 2m is 0.0533×10⁻⁶ kg/m².
From the given,
the rotational inertial of rod I,
I = I₁+I₂+I₃
mass of the one rod = 1.6 gram = 1.6×10⁻³kg
length of the rod = 2 cm = 0.02m
I = I₁+I₂+I₃
= (mL²/12)+(mL²/12)+0
= mL²/6
I =mL²/6
= (1.6×10⁻³kg)×(0.02)²/6
= (1.6×10⁻⁷)/3
= 0.533 ×10⁻⁷
= 0.0533 ×10⁻⁶ kg/m²
Thus the rotational inertia of the rod is 0.0533×10⁻⁶ kg/m².
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A block on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 30 N / m . The other end of the spring is attached to a wall , and there is negligible friction between the block and the horizontal surface The block - spring system experiences simple harmonic motion , as shown in the graph ?
Help!!! If you cannot type in the box, dont answer.
Answer: lollllllllllllllllllllll
Explanation:
As a increases and c stays constant, b does what
Answer:
b decreases as a increases and c stays constant
It all depends on the definitions of a, b, and c, and the relationship among them. Your question doesn't give us any of this information.
Pravat exerts a force of 30 n to lift a bag of groceries 0.5 m. how much work did pravat do on the bag? note : work = force x distance 0 j 15 j 30 j 60 j
Answer:
he is right it’s D
Explanation:
if u could not read his hand writing
You watch two otters cross a river of width d with water flowing at vw. Otter 1 swims across the river perpendicularly to the shore (but ends up actually swimming diagonally from the reference frame of a person standing on the shore because the river flows in a direction perpendicular to the direction the otter swims). Otter 2 swims in a direction that takes her directly across the river, on a path that is actually perpendicular to the shore as seen from a person standing on the shore. Each otter swims at vo relative to the water and they take the paths described above. How much longer does the Otter 2 take to cross the river? To answer this, derive an expression for the ratio of the time taken by the Otter 2 to cross the river divided by the time taken by the Otter 1 to cross the river. Get the ratio in terms of vo and vw and select the correct answer.
The fur of a sea otter is the densest of any animal, having the most hairs per square inch of any other species. Even while floating in the water, their thick fur keeps the animal warm and dry.
Sea otters decrease heat loss when the water is too cold by floating on their backs with their feet out of the water. To increase their surface area when trying to dissipate heat, sea otters spread their feet out underwater. Sea otters typically spread out or tuck their feet up to maintain body heat. The amount of food available to sea otters would decrease if prey species in their environment declined as a result of changing temperatures.
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Which statement about the event above is NOT correct?
Answer:
i think its A
Explanation:
What does the force of gravity do for us?
Answer:
Earth's gravity is what keeps you on the ground and what makes things fall. Anything that has mass also has gravity. Objects with more mass have more gravity.
Explanation:
To make a position-time graph, you plot position relative to the starting point on the y-axis against the corresponding_______on the x-axis.
Been stuck on this question for quite awhile, a detailed
explanation will be much appreciated! Will give a like :)
We aim to test pesticides' impact on the survival time for bugs. In the experiment, the researchers consider three dose levels (low, medium, high) are applied with the same type of pesticides produced
These dose levels represent varying concentrations or amounts of the same type of pesticide that is being used. the use of three dose levels with the same type of pesticide in this experiment allows for a comprehensive evaluation of how varying pesticide concentrations affect bug survival time, providing insights into the potential impact of pesticides on insect populations and ecosystems
The purpose of using multiple dose levels is to examine the potential relationship between pesticide dosage and bug survival time. By applying different doses, the researchers can observe if there is a dose-dependent effect, where higher doses result in shorter survival times or increased mortality rates among the bugs. This allows them to understand the potential toxicity or effectiveness of the pesticide at different concentrations.Using the same type of pesticide for all three dose levels ensures that the observed effects are solely attributed to the dose variations and not due to different chemical properties or compositions of the pesticides. This helps in establishing a direct comparison between the dose levels and their impact on bug survival time.By analyzing the survival times of bugs exposed to low, medium, and high doses of the pesticide, the researchers can gather data on the dose-response relationship. This information is valuable in assessing the potential risks and determining the optimal dosage for pest control purposes while minimizing adverse effects on non-target organisms. Overall, the use of three dose levels with the same type of pesticide in this experiment allows for a comprehensive evaluation of how varying pesticide concentrations affect bug survival time, providing insights into the potential impact of pesticides on insect populations and ecosystems.
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Are you made of time particles? Explain.
Discribe the law of reflection
Answer:
the angle of reflection equals the angle of incidence—θr = θi. The angles are measured relative to the perpendicular to the surface at the point where the ray strikes the surface.
Explanation:
A microscope uses a mirror to reflect light to the specimen under the microscope. ... An astronomical reflecting telescope uses a large parabolic mirror to gather dim light from distant stars. A plane mirror is used to reflect the image to the eyepiece.
Name some minerals used as gems.
Answer:
Minerals to Gemstones
Mineral Name Gemstone Name
Beryl Aquamarine, Beryl, Bixbite, Emerald, Goshenite, Heliodore, Morganite
Brazilianite Brazilianite
Chalcedony Agate, Aventurine, Bloodstone, Carnelian, Chrysoprase, Heliotrope, Jasper, Onyx, Sard
Chrysoberyl Alexandrite, Chrysoberyl
6. Rock Ais thrown horizontally off a cliff with a velocity of 15 m/s. The rock lands 75m from
the base of the cliff,
75m
According to the above information and diagram, how long will Rock A be in
the air?
Answer:
5 seconds
Explanation:
Rock A is thrown horizontally off a cliff with a velocity of 15 m/s. The rock lands 75m from the base of the cliff, According to the above information the time spend by the rock will be "5 s".
To find the time given values are:
Initial horizontal velocity, u = 15 m/s
Horizontal Length, R = 75 m
What is the range of the projectile?The range of a projectile can be defined as the distance horizontally that projectile which travels with the time and then it is launched for the time and also it comes back down to the same height to the height of where it is launched. According to a projectile motion, there will be no horizontal acceleration at work.
The range of projectile will be:
R=υt
t = R /υ
By substituting the values,
t = 75 /15
t = 5 sec
Rock A is thrown horizontally off a cliff with a velocity of 15 m/s. The rock lands 75m from the base of the cliff, According to the above information the time spend by the rock will be "5 s".
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Question 4 of 10
You add 100 mL of water at 20°C to 200 mL of water at 80°C. What is the
most likely final temperature of the mixture?
A. 50°C
OB. 60°C
C. 100°C
OD. 30°C
(asons
Heat received by cold water equals heat lost by hot water. 60°C is the ultimate temperature.
What does the term temperature mean?An evaluation of an object or substance's warmth or coolness in relation to a reference value.
a measurement of how much heat is required to raise the temperature of a material by one degree Celsius for every gramme.
The unit of measurement for specific heat is Joules per gramme per degree Celsius (J/g °C).
Let c represent the water's specific heat.
based on the calorimetry concept.
Heat received by cold water equals heat lost by hot water.
200 * c * (80 - T) = 100 * c * (T - 20) (T - 20)
∴ 200c (80-T) = 100c(T-20) (T-20)
∴2 (80-T) = T - 20
∴160-2T=T-20
∴ 160+20 = T +2T
∴180 = 3T
∴T = 60 C.
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I pull my child in a sled over the snow. The rope makes an angle with the horizontal so that the pulling force has a horizontal component of 21 N and a vertical component in the upwards direction 25 N. The combined weight of the child and sled is 79 N. I'm getting tired and so the sled is slowing at a constant rate of 0.80 m/s each second.
Required:
Calculate the magnitude of the frictional force between the sled and the snow.
The magnitude of the frictional force between the sled and the snow is 46.3 N.
We are given that the pulling force has a horizontal component of 21 N and a vertical component in the upwards direction of 25 N. Using this information, we can calculate the magnitude of the pulling force as follows:
Magnitude of the pulling force = √((21 N)² + (25 N)²)
= √(441 N² + 625 N²)
= √(1066 N²)
= 32.7 N
To calculate the force of friction, we first need to calculate the net force. We can do this by finding the difference between the pulling force and the weight of the sled and child:
Net force = Magnitude of the pulling force - Weight of the sled and child
= 32.7 N - 79 N
= -46.3 N
Now, we know that this net force is equal to the force of friction:
Force of friction = Net force
= -46.3 N
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A piece of aluminum is dropped vertically downward between the poles of an electromagnet. Does the magnetic field affect the velocity of the aluminum?
The magnetic field does not directly affect the velocity of the aluminum. When a piece of aluminum is dropped vertically downward between the poles of an electromagnet, the force of gravity is primarily responsible for its motion.
The magnetic field generated by the electromagnet exerts a force on the aluminum, but this force acts perpendicular to the direction of motion.
As a result, the magnetic force does not change the speed of the aluminum. However, it does cause the aluminum to experience a sideways deflection due to the interaction between the magnetic field and the induced currents in the aluminum. This phenomenon is known as magnetic induction or the Eddy current effect.
The deflection caused by the magnetic field depends on factors such as the strength of the magnetic field, the mass and shape of the aluminum, and the speed at which it is falling. The higher the strength of the magnetic field, the greater the deflection. Similarly, the larger the mass or shape of the aluminum, the smaller the deflection.
In summary, the magnetic field generated by the electromagnet does not directly affect the velocity of the aluminum, but it does cause a sideways deflection known as the Eddy current effect.
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What type of energy change results when friction slows down an object.
An orbiting satellite experiences no force due to the Earth's
gravity.
Answer:
false
Explanation:
The statement "An orbiting satellite experiences no force due to the Earth's gravity." is a False statement. This is further explained below.
What is Gravity?Generally, Gravity is simply defined as the force that pulls items toward the center of a planet or other entity.
In conclusion, an orbiting satellite experiences force due to the Earth's gravity.
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Based on the data, which prediction should he expect to occur? A2 repels B1. C2 attracts B2. B1 repels C1. A1 attracts C2.
Answer:
its not B1 or A1. must be A2 or C2
Explanation:
Please give me concept to solve this.
Answer:
The difference in tension, between adjacent sections of the pull cable at the given conditions is 17.701 kN
Explanation:
We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation
\(F_{car}\) = Upward tension force, \(Tension_{(upwards)}\) - Downward tension force, \(Tension_{(downwards)}\) - Component of the weight of the car along the taut cable
The parameters given are;
Mass of car, m = 2750 kg
Angle of inclination of taut cables, θ = 35°
The upward acceleration of the car, a = 0.81 m/s²
Given that the weight is acting vertically downwards, we have;
Component of the weight of the car along the taut cable = m × g × sin(θ)
∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N
We therefore have;
\(F_{car}\) = \(Tension_{(upwards)}\) - \(Tension_{(downwards)}\) - 15473.66 N
\(F_{car}\) = m × a = 2750 × 0.81 = \(T_{upwards}\) - \(T_{downwards}\) - 15473.66
∴ \(Tension_{(upwards)}\) - \(Tension_{(downwards)}\) = 2750 × 0.81 + 15473.66 = 17701.16 N
Hence the difference in tension, \(Tension_{(upwards)}\) - \(Tension_{(downwards)}\) between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.
what type of wiring should be used for a high-speed connection between two buildings?
For a high-speed connection between two buildings, the type of wiring that should be used is fiber optic cable. Fiber optic cable is the most reliable and efficient way to transmit data over long distances at high speeds.
It uses light to transmit data instead of electrical signals, which means it is not affected by electromagnetic interference that can cause interruptions in transmission.
Fiber optic cable also has a much higher bandwidth than traditional copper wiring, which means it can handle more data at once. This is especially important for businesses that need to transfer large files or stream video across their network.
When installing fiber optic cable between two buildings, it is important to consider factors such as distance, the amount of data that will be transmitted, and the required level of security. A professional installer should be consulted to ensure that the cable is installed correctly and meets the specific needs of the business.
Overall, fiber optic cable is the best choice for a high-speed connection between two buildings due to its reliability, efficiency, and high bandwidth.
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rewrite your result for g(r) in terms of gp , the gravitational acceleration at the surface of the planet, times a function of r. express your answer in terms of gp , r , and rp
The gravitational acceleration at the surface of the planet, times a function of r is g = mG/r².
Gravitational acceleration is described as an object receiving acceleration due to the gravitational force acting on it.
It is represented by 'g' and its unit is m/s². Gravitational acceleration is a vector quantity, that is, it has both magnitude and direction.From Newton's second law of motion we can write
F=ma
Here, F is the force acting on the object.
m is its mass and
"a" is the acceleration.
Also according to Newton's law of gravity we can write,
Fg = GmM / (r+h)²
Also a = Fg/M
a = g = {GmM / (r+h)²} / M
g = Gm/r²
The gravitational acceleration at the surface of the planet, times a function of r is g = mG/r².
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A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following case:
How far will the load move if it starts from rest and accelerates for 20 seconds?
Answer:
The answer is below
Explanation:
A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the
cable for the following cases:
a. The load moves downward at a constant velocity
b. The load accelerates downward at a rate 0.4 m/s??
C. The load accelerates upward at a rate 0.4 m/s??
Solution:
Acceleration due to gravity (g) = 10 m/s²
a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:
mg - T = ma
Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:
mg - T = m(0)
mg - T = 0
T = mg
T = 140(10) = 1400 N
T = 1400 N
b) If the load moves downward, the tension (T) is given by:
mg - T = ma
T = mg - ma = m(g - a)
T = 140(10 - 0.4) = 140(9.96) = 134.4
T = 134.4 N
c) If the load moves upward, the tension (T) is given by:
T - mg = ma
T = ma + mg = m(a + g)
T = 140(0.4 + 10) = 140(10.4)
T = 145.6 N
2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:
s = ut + (1/2)gt²
s = 0(20) + (1/2)(10)(20)²
s = 2000 m
14. A load of bricks is being lifted by a crane at the steady velocity of 16ft/sec, but 20ft above the ground one brick falls off. Describe the motion of the free brick by sketching x(t). (a) What is the greatest height the brick reaches above the ground? (b) How long does it take to reach the ground? (c) What is its speed just before it hits the ground?
The maximum height reached by the brick above the ground is 20 ft. The time taken by the brick to reach the ground is 0 seconds. Free-fall motion (uniformly accelerated motion) after falling from a height of 20 feet. Further, the acceleration experienced by the free brick is equal to the acceleration due to gravity which is approximately 32ft/sec², downward.
Hence, we can write its acceleration as, a = g = 32ft/sec².
Here, u = 0 as the brick was not moving initially while it was at rest on the top of the load of bricks.
Now, the value of v(t) can be obtained by integrating the above expression w.r.t. time as shown below:v(t) = u + a.t = 0 + 32t = 32t ...(1)
The value of x(t) can be obtained by integrating the expression for v(t) w.r.t. time, i.e. t as shown below :x(t) = (1/2).a.t² + u.t + x₀ = (1/2).32t² + 0 + 20ft = 16t² + 20ft ...(2)
Here, x₀ = 20ft is the initial displacement of the brick above the ground.
Now, we can answer the questions as follows:
(a) Using the following relation: v = u + a.t = 0 when the brick is at its highest point.
Hence, the time taken to reach this point can be obtained as follows:0 = u + a.t ⇒ t = (-u/a) = (0/32) sec = 0 secThis means that the brick reaches its maximum height at t = 0 sec, which is the initial moment.
Thus, the maximum height reached by the brick above the ground is, x(0) = 16.0² + 20 = 20 ft
(b) The time taken by the brick to reach the ground can be obtained by using the following relation: x(t) = 0.
Here, we are interested in finding the value of t.
Hence, we can substitute x(t) from equation (2) above and equate it to 0 to obtain the value of t as shown below:16t² + 20 = 0 ⇒ t² = -(20/16) sec².
This means that the brick doesn't take any finite time to reach the ground from its maximum height.
This is because it falls vertically downwards from a height of 20 ft under the action of gravity.
Thus, it reaches the ground at t = 0 sec only.
(c) The speed of the brick just before it hits the ground can be obtained by using the expression for v(t) from equation (1) above and substituting t = 0 sec (just before it hits the ground) as shown below:
v(0) = 32(0) = 0 ft/sec.
Hence, the speed of the brick just before it hits the ground is 0 ft/sec.
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Convert 149 °F into a °C, (b) Kelvin
Answer:
a.149 °F into °C
149 - 32 = 117
117 x 5 = 585
585 / 9 = 65
149 °F = 65 °C
b.149 °F into Kelvin
(149°F − 32) × 5/9 + 273.15 = 338.15K
for laminar flow of air over flat plates with uniform surface temperature, the curve that most closely describes how the average heat transfer coefficient changes with the length of the plate is
For a laminar airflow over flat plates with a constant surface temperature, the curve that best represents how the average heat transfer coefficient declines with plate length increases.
In fluid dynamics, laminar flow is characterized by fluid particles passing each other in layers along straight paths with little to no mixing in between. When the fluid is traveling at moderate speeds, it tends to Laminar flow without lateral mixing, which causes adjacent layers to slip past one another like playing cards. The heat transfer coefficient measures the convective heat transfer between a fluid medium (a fluid) and the surface (a wall) it flows over. The Newton-Richmann relation shows the heat transfer coefficient as a proportionality factor.
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