is oxygen more reactive than beryllium

The binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond.  Option b

Aminoacyl-tRNA is a complex molecule that plays a crucial role in protein synthesis. It consists of a tRNA molecule covalently linked to an amino acid. The amino acid is attached to the 3' end of the tRNA molecule through an ester bond.

An ester bond is formed between the carboxyl group (-COOH) of the amino acid and the hydroxyl group (-OH) of the ribose sugar at the 3' end of the tRNA molecule. This ester bond is also referred to as an ester linkage. The formation of the ester bond is catalyzed by the enzyme aminoacyl-tRNA synthetase.

The ester bond in aminoacyl-tRNA is essential for protein synthesis. During translation, the aminoacyl-tRNA molecule carries the specific amino acid to the ribosome, where it is incorporated into the growing polypeptide chain. The ester bond is later hydrolyzed, releasing the amino acid for further use in protein synthesis.

In summary, the binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond between the carboxyl group of the amino acid and the hydroxyl group of the ribose sugar in the tRNA molecule.

Option b

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Using the given mass of the compound (0.520 g) and the calculated moles, we can determine the molar mass of the compound.

To find the molar mass of the compound, we can use the formula:

ΔT = Kf * m

where ΔT is the freezing point depression, Kf is the cryoscopic constant (in this case, 3.90 °C/m), and m is the molality of the solution.

First, we need to calculate the molality (m) of the solution:

m = moles of solute / mass of solvent (in kg)

The mass of the solvent (lauric acid) is given as 4.62 g. Since the unknown compound is a solute, we need to convert its mass to moles:

moles = mass / molar mass

Given that the mass of the unknown compound is 0.520 g, we can now calculate the moles of the compound.

Next, we convert the mass of the solvent to kg by dividing by 1000:

mass of solvent (lauric acid) = 4.62 g / 1000 = 0.00462 kg

Now we can calculate the molality:

m = moles of solute / mass of solvent = (moles of the compound) / (mass of solvent)

Finally, we can use the freezing point depression formula to find the molar mass of the compound:

ΔT = Kf * m

Substituting the given values:

4.20 °C = 3.90 °C/m * m

Now solve for m:

m = (4.20 °C) / (3.90 °C/m)

Once we have the molality, we can calculate the moles of the compound:

moles = molality * mass of solvent (in kg)

Finally, we calculate the molar mass:

molar mass = mass of solute / moles of solute

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The molarity of the solution is 3.09M. The correct option is C.

To calculate the molarity of a solution, we need to use the formula:

Molarity (M) = (moles of solute) / (volume of solution in liters)

First, we need to convert the mass of NaCl to moles. The molar mass of NaCl is approximately 58.44 g/mol. We can calculate the number of moles using the formula:

moles = mass / molar mass

moles = 7.85 g / 58.44 g/mol ≈ 0.1346 mol

Next, we need to convert the volume of the solution from milliliters (mL) to liters (L). The volume given is 2.54 mL, which is equivalent to 2.54 × 10⁻³ L.

Now we can use the formula for molarity to find the molarity of the solution:

Molarity = 0.1346 mol / 2.54 × 10⁻³ L ≈ 52.91 M

Rounding the answer to the appropriate number of significant figures gives us a molarity of 3.09M.

Therefore, the correct answer is option C: 3.09M.

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Answer: argon

Explanation:

using the last clue “avg atomic mass of 3.33x greater than carbon-12” we can deduce the atomic mass of the element is 12x3.33=40(2sf) hence its argon. we can further confirm from third clue that it is a noble gas hence unreactive

Taking into account the reaction stoichiometry, 112.5 grams of water are formed when 12.5 g of hydrogen reacts with oxygen.

In first place, the balanced reaction is:

2 H₂ + O₂ → 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 4 grams of H₂ form 36 grams of H₂O, 12.5 grams of H₂ form how much mass of H₂O?

mass of H₂O= (12.5 grams of H₂×36 grams of H₂O)÷4 grams of H₂

mass of H₂O= 112.5 grams

Finally, 112.5 grams of H₂O are formed.

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Explanation:

IM PRETTY SURE IT IS D !! IF ITS WRONG IM SORRY THAT WHAT

I GOT

ΔH° for the reaction Fe3O4(s)+2C (graphite) → 3 Fe(s) + 2CO2(g) is - 725kj/mol⁻¹.

Hess's law states that if a process can be showed as the sum of two or more steps, the enthalpy change for the overall process is the sum of the ΔH values for each step.

Fe3O4(s)+2C (graphite) → 3 Fe(s) + 2CO2(g),    

We invert (1) and change the sign of  ΔH

Fe3O4(s)   →  3Fe(s)+3CO2(g)  ΔH = 1118

We multiply (2) by 3

2C(g)+1/2O2(g) → CO2(g)         ΔH = - -394   (2)

3CO(g)+3/2O2(g)→3CO2(g)         ΔH = 1118

We add (1) and (2)

Fe3O4(s)  →  3Fe(s)+3CO2(g)  ΔH = 824.2 kJ

3CO(g)+3/2O2(g)→3CO2(g)         ΔH = -848.1 kJ

Fe3O4(s)+2C (graphite) → 3 Fe(s) + 2CO2(g),    

Therefore, ΔH° = - 725kj/mol⁻¹

Thus,  ΔH° for the reaction Fe3O4(s)+2C (graphite) → 3 Fe(s) + 2CO2(g) is - 725kj/mol⁻¹.

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Answer:

a) Barney wants to repeat the rutheford experiment

b) the element will be in row 8 column 1 being an alkali metal

c) it should be a radioactive element, with a lot of mass

Explanation:

n this exercise they indicate that the particle Gz has atomic number 119 and atomic mass 305 amu, when reviewing the element periodicity table with this atomic number it has not yet been discovered, it should be in row 8 column 1 therefore it should be an alkali metal .

Therefore, it has only one electron in its last orbit.

a) Barney wants to repeat the rutheford experiment

b) the element will be in row 8 column 1 being an alkali metal

c) it should be a radioactive element, with a lot of mass

Answer:

3 g of H₂

Explanation:

The balanced equation for the reaction is given below:

Cr₂O₃ + 3H₂ —> 2Cr + 3H₂O

Next, we shall determine the masses of Cr₂O₃ and H₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Cr₂O₃ = (52×2) + (16×3)

= 104 + 48

= 152 g/mol

Mass of Cr₂O₃ from the balanced equation = 1 × 152 = 152 g

Molar mass of H₂ = 2 × 1 = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g

SUMMARY:

From the balanced equation above,

152 g of Cr₂O₃ reacted with 6 g of H₂

Finally, we shall determine the mass of H₂ needed to covert 76 g of Cr₂O₃. This can be obtained as follow:

From the balanced equation above,

152 g of Cr₂O₃ reacted with 6 g of H₂.

Therefore, 76 g of Cr₂O₃ will react with = (76 × 6) / 152 = 3 g of H₂

Thus, 3 g of H₂ is needed to convert 76 g of Cr₂O₃.

Answer:

(a) W

(b) X

(c) Y

Explanation:

Let's consider the following table with melting and boiling points for 4 substances.

Substance     Melting Point (°C)       Boiling Point (°C)

     W                       -7                                  60

     X                       660                              2500

     Y                        180                               1330

     Z                         115                                445

Let's consider that:

(a) Which substance is a gas at 100°C?

At 100 °C, W is above the boiling point

(b) Which substance is a liquid for the largest range of temperature?

The largest difference between the melting point and the boiling point is that of X: 2500 - 660 = 1840.

(c) Which substance is liquid at 1000 °C and a gas at 2000°C?​

Y is between the melting and the boiling point at 1000 °C and above the boiling point at 2000 °C.

Answer:

I believe it's B: Ptotal=P1+P2+P3+...

Explanation:

Answer:

1 would be a. sequence

2 would be b. compare and contrast

3 would be a. cause and effect

The five members that make up the IACUC committee are a Doctor of Veterinary Medicine (DVM) who is a member of the institution, one scientist, one non-scientist, and two members of the institution's community.

The Institutional Animal Care and Use Committee (IACUC) is a board of specialists responsible for inspecting animal treatment facilities and their compliance with animal welfare legislation and regulations, according to the federal Animal Welfare Act (AWA).

The Institutional Animal Care and Use Committee (IACUC) must include a minimum of five members, according to the AWA, who possess certain qualifications to review animal protocols from the institution or research project. Below is the required composition of a 5-member IACUC: One Doctor of Veterinary Medicine (DVM) who is a member of the institution. One scientist, who should not be affiliated with the institution, but who is qualified in the field of research and who is not a family member of the institutional employees. One person should be designated as a non-scientist and who is not affiliated with the institution in any way. Two members of the institution's community, one of whom should be an individual who is not affiliated with the institution, a layperson representative.

According to the Animal Welfare Act (AWA), the Institutional Animal Care and Use Committee (IACUC) is a group of experts that is required to include at least five members with various qualifications in order to review animal protocols from the institution or research project. It is the IACUC's responsibility to examine animal treatment facilities and their compliance with animal welfare regulations and legislation.

In general, the five members that make up the IACUC committee are a Doctor of Veterinary Medicine (DVM) who is a member of the institution, one scientist, one non-scientist, and two members of the institution's community. To qualify to be a member of the IACUC, each member must have a certain level of expertise in their field, be qualified to evaluate the science that is being conducted, and have the necessary resources to review protocols in a thorough and accurate manner. In addition, IACUC members must not have a conflict of interest and must recuse themselves from the review process if they do.

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Answer:

During the fractional distillation of crude oil: heated crude oil enters a tall fractionating column , which is hot at the bottom and gets cooler towards the top. vapours from the oil rise through the column. vapours condense when they become cool enough. liquids are led out of the column at different heights.

The correct relationship is that when a substance is reduced, it gains electrons, the charge decreases, and it is called a reducing agent. Conversely, when a substance is oxidized, it loses electrons, the charge increases, and it is called an oxidizing agent.

This can be remembered through the mnemonic "LEO the lion goes GER", which stands for "Loss of Electrons is Oxidation" and "Gain of Electrons is Reduction". It is important to note that a reducing agent facilitates the reduction of another substance by donating electrons, while an oxidizing agent facilitates the oxidation of another substance by accepting electrons. Understanding these relationships is key in many areas of chemistry, such as redox reactions and electrochemistry.

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Answer:

The correct option is;

A. Some ice cubes are floating in the tea

Explanation:

A heterogenous mixture is one that is made up of more than one clearly identifiable phase of matter (such as solid and liquid, liquid and gas, gas and solid, or solid, liquid and gas combined) and therefore having non-uniform composition, which varies from one section to another within the mixture.

Ice cubes which are solids being observable on the surface of the mixture provides clue that the student has made an heterogenous mixture.

Answer:

combustion is a high-temperature exothermic redox chemical reaction between a fuel and an oxidant, usually atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke.

Answer:

whats the question even ??/?

Explanation:

Explanation:

0.24 grams of LiOH are needed to make 100 ml of a 0.1 M solution

Answer:

4.9 x 10²²hockey pucks

Explanation:

Given parameters:

Number of moles of hockey  = 0.0814moles

Unknown:

Number of pucks there = ?

Solution:

A mole of a substance is made up of Avogadro's number of particles.

Therefore;

       1 mole of hockey pucks will contain 6.02 x 10²³ hockey pucks

       0.0814 mole of hockey pucks will contain :

                              0.0814 x 6.02 x 10²³ = 4.9 x 10²²hockey pucks

Fluorine.Accordingly the order of electronegativity of the given elements would be: Fluorine > Chlorine > Bromine > Iodine. ( Fluorine has the highest electronegativity.)

Fluorine and Chlorine (Atomic numbers 9 and 17) are situated in similar segment of the periodic table of elements. This truly intends that: fluorine and chlorine have similar number of electrons it their external shells. fluorine and chlorine have similar number of all out electrons.The elements fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At) are incandescent light. Incandescent light are profoundly reactive nonmetallic elements in bunch 17 of the periodic table. They have seven valence electrons, so they are very "energetic" to acquire one electron to have a full external energy level.

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Answer:

When the standard electrode potential for a redox reaction, E^o(redox reaction), is positive, the response is spontaneous. The reaction will proceed in the forward direction (spontaneous) if E^o(redox reaction) is positive.

Explanation:

Please give the brainliest, really appreciated. Thank you

Answer:

Unlike protons and neutrons, which are located inside the nucleus at the center of the atom, electrons are found outside the nucleus. Because opposite electric charges attract each other, negative electrons are attracted to the positive nucleus.

The empirical formula of the compound would be A3B4.The empirical formula of a compound gives the simplest whole-number ratio of the atoms in the compound.

To determine the empirical formula of a hypothetical compound that contains 60% by mass of element A, we need to know the atomic mass of element A.Assuming we know the atomic mass of element A, we can start by assuming a 100 g sample of the compound. Since the compound contains 60% by mass of element A, this means the sample contains 60 g of element A.

Next, we need to convert the mass of element A to moles using its atomic mass. Once we know the number of moles of element A, we can calculate the number of moles of the other element(s) present in the compound by subtracting the number of moles of element A from the total number of moles in the sample.

Finally, we can divide the number of moles of each element by the smallest number of moles to get the simplest whole-number ratio of the atoms. This will give us the empirical formula of the compound.

For example, let's assume that element A has an atomic mass of 20 g/mol. Then, in a 100 g sample of the compound, there would be 60 g of element A, which corresponds to 3 moles of element A (60 g / 20 g/mol = 3 mol). If we assume that the other element in the compound has an atomic mass of 10 g/mol, then the remaining 40 g of the sample would correspond to 4 moles of the other element (40 g / 10 g/mol = 4 mol).

Dividing the number of moles of each element by the smallest number of moles (which is 3), we get the ratio of 3:4 for element A to the other element. Therefore, the empirical formula of the compound would be A3B4.

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Answer:

  72.8 liters (see comment below)

Explanation:

You want the volume of CO₂ at STP resulting from the decomposition of 3.25 moles of CaCO₃.

The balanced reaction is ...

  CaCO₃(s) + heat ⇒ CaO(s) + CO₂(g)

This tells you that 3.25 moles of CaCO₃ will evolve 3.25 moles of CO₂ gas.

At STP, each mole of gas has a volume of 22.4 liters. The volume of CO₂ produced is ...

  (3.25 mol) × (22.4 L/mol) ≈ 72.8 L

At STP, the volume of gas produced is 72.8 liters.

__

Additional comment

After 1982, the IUPAC defined STP as 0 °C, 100 kPa, so one mole of gas occupies 22.711 liters. If this is the value of STP you're to use, then the appropriate answer is ...

  (3.25 mol) × (22.711 L/mol) ≈ 73.8 L

Prior to 1982, IUPAC standard pressure was 1 atm, or 101.325 kPa. At that pressure the volume of one mole is 22.414 liters. Many authors continue to use this definition of STP, so that is the value we have used in the answer above.

We have rounded the volume to 3 significant figures, in accordance with the precision of the given amount of material.

Answer:

C

Explanation:

As the size of a star increases, luminosity increases. If you think about it, a larger star has more surface area. That increased surface area allows more light and energy to be given off.

GIVEN

• 800g of H2O > 800/1000= ,0.8 Litres of water

• Concentration = 6.25 M

• Molar mass acetic acid = 60.05g/mol

The combination of the given components yields -16.5.

To find the combination AV​/2 - 2By​ + 5CV​,

We need to substitute the given components of vectors A, B, and C into the expression.

Given:

Ax​ = 1.0

Ay​ = 2.0

Bx​ = 3.5

By​ = -4.0

Cx​ = -5.0

Cy​ = 6.

Substituting these values into the expression:

AV​/2 - 2By​ + 5CV​ = (Ax/2) - 2(By) + 5(Cx)= (1.0/2) - 2(-4.0) + 5(-5.0)

= 0.5 + 8.0 - 25.0

= -16.5

Therefore, the combination of the given components yields -16.5.

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