4. A bowling ball that has a mass of 5 kg is lifted until its PE is equal to 73.5 J. What
height is the ball lifted to?

The day it was the coldest outside is Tuesday.Temperature is an attribute of matter that reflects the coldness or hotness of an object in degrees Fahrenheit or Celsius.The correct option is D.

 on Tuesday, the temperature outside was 75°F, whereas on other days the temperature was higher than 75°F.The temperature inside and outside the classroom was recorded every day at recess time for a week by Mary's class. The data for indoor and outdoor temperatures are listed below.

Day of the WeekTemperature InsideTemperature OutsideMonday66°F80°FTuesday67°F75°FWednesday67°F79°FThursday68°F82°FFriday70°F88°FThe coldest day outside was Tuesday. As can be seen in the table above, on Tuesday, the temperature outside was 75°F, whereas on other days the temperature was higher than 75°F.The correct option is D.

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The person will be traveling at a speed of approximately 44.3 m/s when they reach the bottom of the slope. The correct option is B.

To find the speed of the person at the bottom of the slope, we can use the principle of conservation of energy. At the top of the slope, the person only has potential energy, which is given by the formula:

PE = m * g * h

where PE is the potential energy, m is the mass of the person, g is the acceleration due to gravity, and h is the height of the slope.

At the bottom of the slope, all the potential energy is converted into kinetic energy, given by the formula:

KE = (1/2) * m * v^2

where KE is the kinetic energy and v is the speed of the person.

Since energy is conserved, we can equate the potential energy at the top to the kinetic energy at the bottom:

m * g * h = (1/2) * m * v^2

Simplifying and rearranging the equation:

v = √(2 * g * h)

Substituting the given values:

v = √(2 * 9.8 m/s² * 100.0 m) ≈ 44.3 m/s

Therefore, the person will be traveling at a speed of approximately 44.3 m/s when they reach the bottom of the slope. Option B is the correct answer.

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f(x) can be expressed as a composition of two functions g(x) = x - 2 and

h(x) = x^2 - 1.

To express a function as a composition of two functions, you can use the calculator. To do this, follow these steps:

Explanation: Find two functions f and g such that f(g(x)) = your function.

Replace f(x) with f(g(x)).

Solve for g(x).

Express the function in terms of f(x) and g(x).

For example, let's say you want to express the function

f(x) = x^2 - 4x + 3 as a composition of two functions.

First, you need to find two functions g(x) and h(x) such that f(x) = g(h(x)).

One possible way to do this is to use the formula for completing the square to rewrite f(x) as f(x) = (x - 2)^2 - 1.

Now we can let g(x) = x - 2 and

h(x) = x^2 - 1,

so that f(x) = g(h(x)).

Therefore, f(x) = (x - 2)^2 - 1

= g(h(x))

= (x^2 - 1) - 2.

The conclusion is that f(x) can be expressed as a composition of two functions g(x) = x - 2 and

h(x) = x^2 - 1.

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The scientist who determined the magnitude of the electric charge of the electron was Robert Millikan.

The Millikan's Oil Drop Experiment Measuring the Charge of the Electron. The American scientist Robert Millikan 1868–1953 carried out a series of experiments using electrically charged oil droplets, which allowed him to calculate the charge on a single electron.  J. J. Thomson discovered electron, but he could only deduce the charge to mass ration but Robert Millikan through his oil drop experiment found the value of charge on electron. The oil drop experiment was perhaps the most famous scientific work of Robert Millikan's career. While at the University of Chicago, he worked with one of his graduate students, Harvey Fletcher, to attempt to measure the charge of an electron.

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In the ground state of hydrogen, the radius of the electron's orbit is equal to the Bohr radius, a0.

lThe quantum numbers n=1, l=0, and m=0 characterise the ground state of hydrogen. The Bohr radius is calculated as follows:

a₀ = (4πε₀ħ²)/(me²)

where 0 represents the vacuum permittivity, is the reduced Planck constant, me represents the electron mass, and e represents the elementary charge.

The electron's energy in the ground state of hydrogen is given by:

E = -13.6 eV / n²

where n=1 is the fundamental quantum number.

As a result, in the ground state of hydrogen, the radius of the electron's orbit is:

r = a₀ n² / l(l+1) = a₀

Because l=0 for the ground state.

So, in the ground state of hydrogen, the radius of the electron's orbit is equal to the Bohr radius, a0.

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Hi there!

\(\large\boxed{375 sec}\)

Use the equation:

Distance / speed = time

We are given that the distance = 45,000 m and speed = 120 m/s, so plug these values into the equation to solve for time:

45,000 / 120 = 375 seconds.

The weight of the baseball is 1.47 N.

Weight is the gravitational pool of a body or an object.

To calculate the weight of the body, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the weight of the baseball is 1.47 N.

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Planet A exerts a force on planet B, the magnitude and direction of the gravitational force planet B exerts on planet A the gravitational force exerted by planet B on planet A is the same as the magnitude of the gravitational force exerted by planet A on planet B

Newton's third law states that if object A exerts a force on object B, then object B exerts an equal and opposite force on object A. Hence, if planet A exerts a gravitational force on planet B, then planet B exerts an equal and opposite gravitational force on planet A.The magnitude of the gravitational force exerted by planet B on planet A is the same as the magnitude of the gravitational force exerted by planet A on planet B, this is according to the law of universal gravitation,

This law states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. The direction of the gravitational force exerted by planet B on planet A is towards planet B's center, just as the direction of the gravitational force exerted by planet A on planet B is towards planet A's center. Therefore, we can say that the magnitude and direction of the gravitational force planet B exerts on planet A is equal and opposite to the gravitational force planet A exerts on planet B

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Answer:

Explanation:D

The velocity of the gold puck after the collision is equal to (2i - j) m/s. Therefore, option (A) is correct.

The rate at which a displacement of the body changes in relation to time is called its velocity. Velocity is a vector parameter with both magnitude and direction. S.I. unit of velocity can be represented as meter/second.

Given, the mass of the gold puck, m = 12 kg

The velocity of the gold puck before the collision, u =  5i – 4j m/s.

The mass of the stationary blue puck, M = 18 kg.

The velocity of it after the collision, V = 2i – 2j m/s.

We have to determine the velocity of the gold puck after the collision:

The total momentum of the system before the collision is equal to the total momentum of the system after the collision.

mu + M ×0 = mv + MV

v = u - MV/m

v  = (5i – 4j) m/s  - (2i – 2j)m/s × 18/12

v  = (5i – 4j) m/s - (3i - 3j)

v = (2i - j) m/s.

Therefore, the velocity of the gold puck is (2i - j) m/s after the collision.

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They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.

Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.

Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.

The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.

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Answer:

4km

Explanation:

Distance=speed x time

Knowing this we know the time and speed

so it is 8 x .5= D

And 8 x .5 =4

If you have any questions let me know

Given

d: diameter

d = 41 cm

We need radius information so we will calculate it:

r: radius

r = d/2

r = 41/2

r = 20.5 cm

Rotating speed

w = 242 rpm

Procedure

At a distance r from the center of the rotation, a point on the object has a linear speed equal to the angular speed multiplied by the distance r. The units of linear speed are meters per second, m/s.

But before using the formula we need to have all the units in the same system. So we need to go from rpm to rad/s and from cm to m

Now we can calculate the linear velocity of the belt.

Answer

The linear velocity of the belt would be 5.2 m/s.

Answer:

D

Explanation:

I think those are weakest

Answer:

D. ionic bonds

Explanation:

ionic bonds are the weakest as its between ions

hydrogen bonds are stronger as it is electrostatic force so its strong

metallic bonds are the sharing of many detached electrons between many positive ions they call it a glue because they are hardly breakable

Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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Answer:

2120000m^2

Explanation:

1300* 1660 and there is 3 significant figures, so the 9 would make the  round to a 2.

It is true that the accuracy of parallax measurements improves as the distance of the object from the observer increases.

As the distance between the object and the observer increases, the angle of parallax also increases. This means that there is a larger difference in the apparent position of the object when viewed from different positions on Earth's orbit. Therefore, the accuracy of parallax measurements improves as the distance of the object from the observer increases.

The accuracy of parallax measurements actually decreases as the distance of the object from the observer increases. Parallax is a technique used to measure the distance of nearby objects in space by observing their apparent shift in position as seen from different viewpoints (such as Earth at different times of the year). As the distance to the object increases, the apparent shift in position becomes smaller and more difficult to measure accurately.

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0.438 s is the period of the wave.

So, the correct answer is A.

To determine the period of the wave, we need to divide the total time taken (3.50 s) by the number of complete oscillations (8.00).

The period (T) is the time required for one complete oscillation.

T = total time / number of oscillations

T = 3.50 s / 8.00

T = 0.4375 s

Rounded to three decimal places, the period of the wave is 0.438 s, which corresponds to option A.

Your question is incomplete but most probably your full question was:

If a wave takes 3.50 s to complete 8.00 complete oscillations, what is the period of the wave?

a. 0.438 s

b. 4.50 s

c 2.29 s

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The frequency of the radiation that peaks at 500 nm is approximately 6 x 10^14 Hz. Where c is the speed of light, λ is the wavelength, and ν is the frequency .

Frequency is defined as the number of waves passing a point per unit time. The speed of light is a constant, and is approximately 3 x 10^8 m/s. We can use the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency, to calculate the frequency of the radiation that peaks at 500 nm.

In this case, the wavelength (λ) is given as 500 nm (5 x 10^-7 meters), and the speed of light (c) is approximately 3.00 x 10^8 meters per second. By substituting these values into the formula, you can find the frequency (f).
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Answer:

2 m/s

Explanation:

Just divide the distance and time. 4/2= 2 m/s

Given data

*The initial quantity of potassium-42 is 1500 mg

*The given time is t = 48 hours

*The half-life of Potassium - 42 is T = 12.4 hours

The expression for the radioactive decay is given as

Substitute the values in the above expression as

Answer:

all living things are made of cells

Explanation:

cells are kinda like matter but only for living thing like when someone says you white blood cell count is low its because they are part of you living body.

Answer:

-3 lb/wk

Explanation:

Pick any 2 points on the graph.  I pick (0,180) and (10,150)

Slope = Δy/Δx = (150 - 180) / (10 - 0) = -3 lb/wk

This is the rate of weight loss

Answer:

d) inertia is the tendency of object's to resist changes in its motion

Match the volcano type with its correct

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Volcano types can be associated with specific plate tectonic settings and magma compositions. Let's match the volcano types with their correct plate tectonic settings and magma compositions:

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

Magma Composition: Mafic

Cinder cones are typically small, steep-sided volcanoes that form from the eruption of basaltic magma. They are commonly found in volcanic regions associated with spreading ridges, where tectonic plates are moving apart, or in areas influenced by mantle plumes, such as hotspot volcanism.

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

Magma Composition: Intermediate, varies from felsic to mafic

Composite or stratovolcanoes are characterized by their steep slopes and alternating layers of lava flows and pyroclastic materials. They are commonly found in subduction zones, where an oceanic plate is being subducted beneath  continental plate. The magma composition of these volcanoes varies, ranging from felsic (high silica content) to mafic (lower silica content).

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

Magma Composition: Mafic

Shield volcanoes are large, broad, and gently sloping volcanoes that form from the eruption of basaltic magma. They are often associated with mantle plumes, such as those found in hotspot regions, as well as in volcanic areas influenced by spreading ridges.

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Magma Composition: Mafic

Large Igneous Provinces (LIPs) are extensive regions of volcanic and intrusive rock formations that are associated with massive outpourings of mafic magma. They can occur in various tectonic settings, including continental rifts, hotspot regions, and flood basalt provinces.

5. Seafloor Volcanism, Pillow Lava:

Plate Tectonic Setting: Mostly Spreading Ridges

Magma Composition: Mafic

Seafloor volcanism is primarily associated with spreading ridges, where magma wells up and creates new oceanic crust. The lava erupted underwater cools rapidly, forming pillow-shaped structures known as pillow lavas. The magma composition is typically mafic, dominated by basaltic lavas.

These associations between volcano types, plate tectonic settings, and magma compositions provide insights into the geological processes and Earth's dynamics that shape the Earth's surface.

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The total mass of the sphere is approximately 4.38 kg.

The given information describes a sphere with a radius of 0.225 m and a varying density, which decreases with distance from the center of the sphere. The density can be expressed as p=2.50 x 10² kg/m - (8.50 x 10⁰ kg/m⁴)r. This means that as the distance r from the center of the sphere increases, the density of the sphere decreases.

To find the total mass of the sphere, we need to use the formula for the volume of a sphere, which is V = (4/3)πr³. Substituting in the given radius of 0.225 m, we get V = (4/3)π(0.225³) = 0.0226 m³.

Next, we can use the formula for mass, which is m = ρV, where ρ is the density and V is the volume. Substituting in the given density, we get m = (2.50 x 10² kg/m - (8.50 x 10⁰ kg/m⁴)r)(0.0226 m³). However, since the density varies with distance from the center of the sphere, we need to integrate this expression over the entire volume of the sphere to get the total mass.

Using calculus, we can integrate the expression for density with respect to volume. This gives us m = ∫(2.50 x 10² kg/m - (8.50 x 10⁰ kg/m⁴)r)dV, where the integral is taken over the entire volume of the sphere. Simplifying this expression and substituting in the volume of the sphere, we get m = (2.50 x 10² kg/m)(0.0226 m) - (8.50 x 10⁰ kg/m⁴)(1/4)(4/3)π(0.225⁴) = 4.38 kg.

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In this type of computer keyboard, each key contains a small metal plate that acts as one of the plates of a parallel-plate capacitor. When the key is pressed, the separation between the plates decreases and the capacitance increases. The change in capacitance is detected by electronic circuitry, indicating that the key has been pressed.

In this particular keyboard, the area of each metal plate is 46.0 mm², and the separation between the plates is 0.670 mm before the key is depressed.

To calculate the capacitance of the parallel-plate capacitor, we can use the formula:

C = (ε₀ * A) / d

where C is the capacitance, ε₀ is the permittivity of free space (a constant value), A is the area of one plate, and d is the separation between the plates.

Substituting the given values:

C = (ε₀ * 46.0 mm²) / 0.670 mm

Now, since the area and separation are given in millimeters, we need to convert them to meters for consistent units. 1 mm = 0.001 m.

C = (ε₀ * 0.046 m²) / 0.00067 m

The value of ε₀ is approximately 8.85 x 10⁻¹² F/m.

C = (8.85 x 10⁻¹² F/m * 0.046 m²) / 0.00067 m

Calculating this, we find:

C ≈ 6.10 x 10⁻¹¹ F

Therefore, the capacitance of each key in this keyboard is approximately 6.10 x 10⁻¹¹ F.

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To set up a good experiment to test whether hypothesis H is true or not, try to get evidence E such that there is as big a difference between P(E | H) and P(E | ~H) as possible. This means the correct option is d.

For a good experiment to test whether hypothesis H is true or not, it is necessary to gather the right evidence. This evidence should be such that there is as big a difference between P(E | H) and P(E | ~H) as possible.

P(E | H) and P(E | ~H) are the conditional probabilities of evidence E given hypothesis H and evidence E given not-H respectively. The difference between these two probabilities measures how well evidence E supports hypothesis H versus not H.

For example, suppose we want to test the hypothesis H: All dogs bark. To get evidence that there is as big a difference between P(E | H) and P(E | ~H) as possible, we can test this hypothesis by taking two groups of dogs. One group is the dogs that bark (group A) and the other group is the dogs that don't bark (group B).

Then, we can get evidence E, which is the number of dogs in group A that bark and the number of dogs in group B that bark. Using this evidence, we can calculate the conditional probabilities of evidence E given hypothesis H (P(E | H)) and evidence E given not-H (P(E | ~H)).

Finally, we can calculate the difference between P(E | H) and P(E | ~H). If this difference is large, then the evidence supports hypothesis H more than not H.

To set up a good experiment to test whether hypothesis H is true or not, it is necessary to gather the right evidence. This evidence should be such that there is as big a difference between P(E | H) and P(E | ~H) as possible.

For example, suppose we want to test the hypothesis H: All dogs bark. To get evidence that there is as big a difference between P(E | H) and P(E | ~H) as possible, we can test this hypothesis by taking two groups of dogs. One group is the dogs that bark (group A) and the other group is the dogs that don't bark (group B).

Then, we can get evidence E, which is the number of dogs in group A that bark and the number of dogs in group B that bark. Using this evidence, we can calculate the conditional probabilities of evidence E given hypothesis H (P(E | H)) and evidence E given not-H (P(E | ~H)).

Finally, we can calculate the difference between P(E | H) and P(E | ~H). If this difference is large, then the evidence supports hypothesis H more than not H.

Hence, it is important to get evidence that has a significant difference between P(E | H) and P(E | ~H) to set up a good experiment to test whether hypothesis H is true or not.

It is necessary to gather the right evidence to set up a good experiment to test whether hypothesis H is true or not.

Evidence E should be such that there is as big a difference between P(E | H) and P(E | ~H) as possible. The difference between these two probabilities measures how well evidence E supports hypothesis H versus not H. Therefore, option d is the correct answer.

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radiation

when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation

Absence of medium is the factor which shows that heat from the sun does reach the earth's surface by convection.

The heat of the sun reaches the earth only through radiation because radiation does not require any medium for the transfer of energy but convection and conduction required a medium to transfer heat energy.

We know that there is no medium present in vacuum so convection and conduction are impossible in a vacuum that's why the sun's heat does not reach the earth by conduction or convection.

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If we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

The correct relationship between the frequency of the incident radiation (ν), its wavelength (λ), and speed (c) is:

A. ν = λ/c

This equation is known as the wave equation and describes the relationship between the frequency, wavelength, and speed of a wave. It states that the frequency of a wave is inversely proportional to its wavelength and directly proportional to its speed. The speed of light (c) is a constant in a vacuum and its value is approximately 3.0 x 10^8 m/s.

Therefore, if we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

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