Answer:
B , D , C
Step-by-step explanation:
the central angle x is equal to the measure of the arc that subtends it, so
x = 90°
similarly
z = 22°
similarly the central angle subtended by arc y° is y°
the 3 angles on the diameter sum to 180° , that is
x + y + z = 180°
90° + y + 22° = 180°
112° + y = 180° ( subtract 112° from both sides )
y = 68°
earle bailey has 20 songs to choose from but can play only 7 in the next half-hour on sirius xm classic.how many different (ordered) playlists are possible
Applying combination, the number of playlist is: 75,435.
How to Apply Combination to Solve a Problem?A combination is a way of selecting a certain number of items from a larger set, without regard to the order of the items.
The number of possible playlists would be the number of ways to select 7 songs out of 20 without regard to order, which is commonly known as a combination.
The formula for combination is nCr, where n is the total number of items and r is the number of items being chosen at a time. So in this case, the number of possible playlists would be 20C7.
This can also be written as 20!/(7!*13!)
The answer is 75,435
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Which function has the greater slope and what does it indicate?
Answer:
The math function has the greater slope, which shows that the estimated time per question for math is greater than the estimated time per question for language arts.
OR B on edge
Step-by-step explanation:
The cauliflower function has the greater slope, which shows that the cost per pound of cauliflower is increasing at a faster rate than the cost per pound of broccoli.
What is Slope?A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the
change in y coordinate with respect to the change in x coordinate as,
m = Δy/Δx where, m is the slope
First, Slope for Broccoli
Slope = (3.6 - 3) / (3 - 2.5)
Slope = 0.6 / 0.5
Slope = 1.2
Second, Slope for Cauliflower
slope = (4.50 - 2.75) / (4.5 - 2.75)
= 1.75 / 1.75
= 1.000
Since the slope of the cauliflower function (1.0000) is greater than the slope of the broccoli function (0.8364), we can conclude that the cauliflower function has the greater slope.
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The number of years that Zach has been on the soccer team is 2 less than 5
times the number of years that Anderson has. In total, the boys have been on
the soccer team for 10 years. How long has each boy been on the soccer team?
Answer:
Brad has been on the team for 8 years. Apply that and that means that Anderson has been on the soccer team for 2 years.
Step-by-step explanation:
I dont know how to explain lol i made an equation and figured it out
Step-by-step explanation:
let x be the number of years that Zach has been on the soccer team and y the number of years Anderson has been on the soccer team.
So, reading our problem it seems that
x=5y-2
x+y=10
replacing x on the second formula we take that 5y-2+y=10
6y-2=10
6y=12
y=2
so x=5y-2=5*2-2=10-2=8
a newsletter publisher believes that 71% 71 % of their readers own a rolls royce. a testing firm believes this is inaccurate and performs a test to dispute the publisher's claim. after performing a test at the 0.02 0.02 level of significance, the testing firm fails to reject the null hypothesis. what is the conclusion regarding the publisher's claim?
We cannot claim that the newsletter publisher's statement is incorrect. Hence, the conclusion is uncertain.
The newsletter publisher's claim is uncertain after performing a test at the 0.02 level of significance as the testing firm fails to reject the null hypothesis.
In this case, we cannot claim that the publisher's statement is incorrect without additional tests and proof. Here is an explanation of the above statement.
A hypothesis test is conducted to find out whether or not there is sufficient evidence to contradict a hypothesis. In this case, the hypothesis test's null hypothesis claims that the newsletter publisher's statement is correct.
The alternate hypothesis claims that the newsletter publisher's claim is incorrect. As a result, the null hypothesis is represented by \(H_0\):
p = 0.71 (71%) and
the alternate hypothesis is represented by \(H_a\):
p ≠ 0.71 (71%).
Where 'p' denotes the percentage of newsletter readers who own a Rolls Royce.
The test statistic for a sample proportion can be calculated by
z = (p - P) / √(P(1 - P) / n)
Where 'p' denotes the sample proportion,
P denotes the population proportion, and
n denotes the sample size.
A two-tailed test is used because the alternate hypothesis is written as \(H_a\):
p ≠ 0.71 (71%).
At a 0.02 significance level, the test statistic's critical value is ±2.58 (round off) Because the test statistic does not fall in the rejection region, we fail to reject the null hypothesis.
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Let the random variables X, Y have joint density function
3(2−x)y if0
f(x,y) =
(a) Find the marginal density functions fX and fY.
(b) Calculate the probability that X + Y ≤ 1
(a) The marginal density functions fX and fY is FY(y) = 3y(2y+1)
(b)The probability that X + Y ≤ 1 is P(X + Y ≤ 1) = 5/16
(a) To discover the negligible thickness work of X, we coordinated the joint thickness work with regard to y over the extent of conceivable values of y:
fX(x) = ∫ f(x,y) dy = ∫ 3(2−x)y dy, 0<x<2
Assessing the necessary, we get:
fX(x) = (3/2)*(2-x)², 0<x<2
To discover the negligible thickness work of Y, we coordinated the joint thickness work with regard to x over the extent of conceivable values of x:
FY(y) = ∫ f(x,y) dx = ∫ 3(2−x)y dx, 0<y<1
Assessing the necessary, we get:
FY(y) = 3y(2y+1), 0<y<1
(b) To calculate the likelihood that X + Y ≤ 1, we got to coordinate the joint thickness work over the locale of the (x,y) plane where X + Y ≤ 1:
P(X + Y ≤ 1) = ∫∫ f(x,y) dA, where A is the locale X + Y ≤ 1
We will modify the condition X + Y ≤ 1 as y ≤ 1−x. So the limits of integration for y are to 1−x, and the limits of integration for x are to 1:
P(X + Y ≤ 1) = \(∫0^1 ∫0^(1−x)\) 3(2−x)y dy dx
Evaluating the inner integral, we get:
\(∫0^(1−x)\) 3(2−x)y dy = (3/2)*(2−x)*(1−x)²
Substituting this into the external indispensably, we get:
P(X + Y ≤ 1) = ∫0^(3/2)*(2−x)*(1−x)²dx
Assessing this necessarily, we get:
P(X + Y ≤ 1) = 5/16
Hence, the likelihood that X + Y ≤ 1 is 5/16.
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Math slope graph please help
Answer:
the slope is -3/4
Step-by-step explanation:
its always rise over run, thats how i remember it
Triangle A has side lengths 3, 4, and 5. Triangle B has side lengths 6, 7, and 8.
Give possible side lengths for Triangle B so that it is similar to Triangle A.
A. 6,7, and 8
B. 6,8 and 10
C. 9,12 and 15
D. None of the above
Answer:
C
Step-by-step explanation:
Simplify 9, 12, and 15 by dividing each by 3, in which it equals to 3, 4, 5. the side lengths 9, 12, 15 are the dilated version of 3, 4, 5. I hope this helps!!
can someone please help me please and thank you
Answer:2, 1, (in place of x) and y2
Step-by-step explanation: Divide your base numbers, which are 18 and 9, so you get 2. Then because you're dividing with exponents you are just subtracting them. So x 2-2 (Imagine these as exponents) so you'd get x0. Next you'd do the same with y so you'd end up with y2. Because your exponent is 0 on x it equals one.
The point (3, 2) is feasible for the constraint 2x1 + 6x2 ≤ 30.TrueFalse
The point (3, 2) is feasible for the constraint 2x1 + 6x2 ≤ 30. (False)
To determine if a point is feasible for a constraint, we need to substitute the values of the point into the constraint equation and check if the resulting inequality holds true.
In this case, the constraint is 2x1 + 6x2 ≤ 30. Substituting x1 = 3 and x2 = 2 into the equation, we get 2(3) + 6(2) = 6 + 12 = 18. Since 18 is not less than or equal to 30, the inequality is not satisfied.
Therefore, the point (3, 2) is not feasible for the given constraint. Feasible points satisfy the constraint, while infeasible points do not. In this case, any point that lies below the line represented by the constraint equation would be feasible, while points above the line would be infeasible.
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I Given:
2x-9
5
= 1
Prove: x = 7
It is proven that the value of x in the given expression 2x-9 -5 = 1 is 7.
Given: 2x-9 -5 = 1
We need to prove that x = 7
2x - 9 - 5 = 1
2x - 13 = 1
2x = 14
x = 7
Therefore, it is proven that the value of x in the given expression 2x-9 -5 = 1 is 7.
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I WILLGIVE BRAINLIEST!!!!!!! Polygons ABCD and A′B′C′D′ are shown on the following coordinate grid: What set of transformations is performed on ABCD to form A′B′C′D′? A translation 1 unit to the left followed by a 180-degree counterclockwise rotation about the origin A translation 1 unit to the right followed by a 180-degree counterclockwise rotation about the origin A 90-degree counterclockwise rotation about the origin followed by a translation 1 unit to the right A 90-degree counterclockwise rotation about the origin followed by a translation 1 unit to the left
Answer:
Step-by-step explanation:
Answer:
(A) A translation one unit to the left followed by a 180-degree rotation.
Step-by-step explanation:
I figured this out by seeing that ABCD was one unit too far from the x=0 line than A’B’C’D. To get it the same distance, we move it left one, which is the same as transforming one unit to the left.
Now, we can see that the coordinates are opposite of each other - this signifies a 180° rotation around the origin.
So, it’s a transformation one unit to the left and a 180° rotation around the origin.
Hope this helped!
Given the following Year 12 balance sheet data for a footwear company:
Balance Sheet Data
Cash on Hand 2,000
Total Current Assets 78,000
Total Assets 315,000
Overdraft Loan Payable 4,000
1- Year Bank Loan Payable 8,000
Current Portion of Long-Term Loans 13,000
Total Current Liabilities 48,000
Long - Term Bank Loans Outstanding 105,000
Shareholder Equity Year11 Balance Year 12 Change Common Stock 10,000 0 10,000
Additional Capital 100,000 0 100,000
Retained Earning 30,000 22,000 52,000
Total Shareholder Equity 140,000 +22,000 162,000
Based on the above figures and the formula for calculating the debt-assets ratio, the company's debt-assets ratio (where debt is defined to include both short-term and long-term debt) is
a) 0.375
b) 0.413.
c) 0.40.
d) 0.318.
e) 0.333.
Based on the above figures and the formula for calculating the debt-assets ratio, the company's debt-assets ratio (where debt is defined to include both short-term and long-term debt) is 0.413 or 41.3%.
The given balance sheet data,
Balance Sheet Data
Cash on Hand 2,000
Total Current Assets 78,000
Total Assets 315,000
Overdraft Loan Payable 4,000
1- Year Bank Loan Payable 8,000
Current Portion of Long-Term Loans 13,000
Total Current Liabilities 48,000
Long-Term Bank Loans Outstanding 105,000
Shareholder Equity Year11 Balance Year 12 Change Common Stock 10,000 0 10,000
Additional Capital 100,000 0 100,000
Retained Earning 30,000 22,000 52,000
Total Shareholder Equity 140,000 +22,000 162,000
The debt-assets ratio is calculated by dividing the total debt (current liabilities + long-term loans) by the total assets.
In this case, the total debt is 48,000 + 105,000 = 153,000
and the total assets are 315,000.
Thus, the debt-assets ratio is 153,000/315,000 = 0.413.
Also, the debt-assets ratio is 0.413 * 100 = 41.3%
The correct answer is b) 0.413.
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Please help, 20 points. Please include description. thanks!! :)
Answer:
a=3
Step-by-step explanation:
N.B: I don't see any k. hence solving for a
The graph is a parabola.Thus the parent function \(p(x)=x^2\). Notice p(x) has been stretched vertically by a units impling a is a positive constant. We want to find a . Let's pick a point (1,3). we already know that p(x)=x² . so substitute 3 for r(x) and 1 for x and then solve for a. [showed below]
\(r(x) = a \cdot p(x) \\ \implies 3 = a \cdot 1 \\ \boxed{a = 3}\)
Assume you are running gradient descent, what will happen when the learning rate α is too small or too large? If you run gradient descent for 30 iterations with a=0.5 and compute J(θ) after each iteration. You find that the value of J(θ) increases over time. Based on this, how do you adjust the value of α to solve the problem?
The learning rate in gradient descent determines the step size and should be not too small or too large, as it can cause the algorithm to converge slowly or overshoot the minimum; adjusting the value of the learning rate can fix the problem, but the optimal value depends on the problem and data set.
According to the given information:
When running gradient descent,
The learning rate α determines the step size taken in each iteration toward the optimal solution.
If α is too small, the algorithm will take small steps and will converge slowly, or may even get stuck in a local minimum.
If α is too large, the algorithm may overshoot the minimum and diverge, or bounce back and forth without converging.
In the scenario described, the learning rate α of 0.5 appears too large, causing J(θ) to increase over time.
This suggests that the algorithm is not converging and is overshooting the minimum.
To fix this,
The value of α can be adjusted by reducing it to a smaller value,
Such as 0.1 or 0.01.
This should allow the algorithm to take smaller steps towards the minimum and eventually converge to a lower value of J(θ).
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i need this answer asap (as soon as possible) i spelled it so the ones who dont know what asap means:/
Answer:
3 root 2, a
Step-by-step explanation:
goodluck on your test
A particle is moving along a projectile path at an initial height of 96 feet with an initial speed of 16 feet per second. This can be represented by the function H(t) = −16t2 + 16t + 96. What is the maximum height of the particle?
Answer:
The maximum height the projectile reaches is 100 feet
Step-by-step explanation:
Notice that the given equation representing the height of the projectile is a quadratic equation which negative leading coefficient (-16). Such type of equations would have a parabola that branches downwards as its graph.
therefore, what we need to find is the coordinates of the top vertex of that parabola. We can use for such the typical formula for the x-position of the vertex of a parabola with standard equation:
\(f(x)=ax^2+bx+c\)
with x-position of the vertex given by:
\(x_v=\frac{-b}{2a}\)
Then in our case (\(H(t)=-16t^2+16t+96\)) we have:
Horizontal position of the vertex given by:
\(t_{vertex}=\frac{-16}{2(-16)} =\frac{1}{2}\)
and now we can find the maximum height plugging this value into the height expression:
\(H(t)=-16(\frac{1}{2}) ^2+16\,(\frac{1}{2})+96=-4+8+96=100\,\,ft\)
PLEASE HELP! (Im horrible at math so this will really help me and my little brother 'hes in middle school) The price of a stock steadily decreased by a total of $113 over the past 17 months. Which expression shows the change in the stock's value?
Answer:
The S&P 500 index had a nominal 12-month return of 18.3% at the end of ... the rate of inflation was: Over the last 12 months, the consumer price index ... Expect a revisit to turmoil - an end to the relative calm energy markets of the past 12 months ... From June 30 through August 31, the value of the index decreased by 4.4% ...
Step-by-step explanation:
hope this help my best friend
and check your email
How to find a quadratic equation with y-intercept and vertex? Explain with examples.
To find a quadratic equation with the y-intercept and vertex, follow these steps: identify the coordinates of the y-intercept and vertex, substitute them into the general form of the quadratic equation, solve for the coefficients, and substitute the coefficients back into the equation. For example, if the y-intercept is (0, 3) and the vertex is (-2, 1), the quadratic equation would be y = x^2 + x + 3.
To find a quadratic equation with the y-intercept and vertex, we can follow these steps:
Step 1: Identify the coordinates of the y-intercept. The y-intercept has the form (0, c), where c is the y-coordinate.Step 2: Identify the coordinates of the vertex. The vertex has the form (-b/2a, f(-b/2a)), where a, b, and c are the coefficients of the quadratic equation.Step 3: Substitute the coordinates of the y-intercept and vertex into the general form of the quadratic equation, y = ax^2 + bx + c.Step 4: Solve the resulting system of equations to find the values of a, b, and c.Step 5: Substitute the values of a, b, and c back into the general form of the quadratic equation to obtain the final equation.For example, let's say the y-intercept is (0, 3) and the vertex is (-2, 1). We can substitute these coordinates into the general form of the quadratic equation:
3 = a(0)^2 + b(0) + c
1 = a(-2)^2 + b(-2) + c
Simplifying these equations, we get:
c = 3
4a - 2b + c = 1
By substituting c = 3 into the second equation, we can solve for a and b:
4a - 2b + 3 = 1
4a - 2b = -2
2a - b = -1
By solving this system of equations, we find a = 1 and b = 1. Substituting these values back into the general form of the quadratic equation, we obtain the final equation:
y = x^2 + x + 3
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To find a quadratic equation with a given y-intercept and vertex, you need the coordinates of the vertex and one additional point on the curve.
Start with the standard form of a quadratic equation: y = ax^2 + bx + c, where a, b, and c are constants.Use the vertex form of a quadratic equation: y = a(x - h)^2 + k, where (h, k) represents the coordinates of the vertex.Substitute the vertex coordinates (h, k) into the equation to obtain the equation in vertex form.Use the y-intercept to find another point on the curve. The y-intercept has the form (0, c), where c is the value of y when x is zero.Substitute the coordinates of the additional point into the equation to obtain a system of two equations. Solve the system to find the values of a, b, and c.Substitute the determined values of a, b, and c into the standard form of the quadratic equation to obtain the final equation.Example:
Suppose we want to find a quadratic equation with a y-intercept of (0, 4) and a vertex at (2, -1).
Using the vertex form, we have y = a(x - 2)^2 - 1.Substituting the y-intercept coordinates, we get 4 = a(0 - 2)^2 - 1, which simplifies to 4 = 4a - 1.Solving the equation above, we find a = 1.Substituting the values of a and the vertex coordinates into the vertex form equation, we have y = 1(x - 2)^2 - 1.Expanding the equation and simplifying, we get y = x^2 - 4x + 3.The final quadratic equation with the given y-intercept and vertex is y = x^2 - 4x + 3.To find a quadratic equation with a given y-intercept and vertex, you can use the vertex form of a quadratic equation and substitute the coordinates to obtain the equation. Then, use the y-intercept to find an additional point on the curve and solve a system of equations to determine the coefficients. Finally, substitute the coefficients into the standard form of the quadratic equation to get the final equation.
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*97 POINTS*
Use the numerals representing cardinalities in the Venn diagram, shown on the right, to give the cardinality of the set
A' ∩ B' ∩ C. '
n(A' ∩ B' ∩ C')= ___________
Answer:
19
Step-by-step explanation:
A' represents everything out A
B' represents everything out B
C' represents everything out C
So only the outside is left hope this helps
Someone please help me!! I will mark as brainliest
Answer:
if it's not on a test, just guess
Step-by-step explanation:
enter 2 Expressions that represent the retail price of the clothes you see for your variable and exclusive clothing boutiques quadruples the price of the items it purchases for resale.
Explanation
Step 1
Let
c represent the original price
if the boutiques quadruples the price of the items it purchases for resale.then
\(\begin{gathered} \text{new price=4}\cdot c \\ percentage \\ 4=4\cdot\frac{100}{100} \\ 4=\frac{400}{100} \\ 4=400\text{ per cent} \end{gathered}\)400 percent
Step 2
expressions
\(\begin{gathered} \text{new price=4}\cdot c \\ \text{new price= 400 percent of C} \end{gathered}\)4c and 400%c
I hope this helps you
Find the gradient vector field of f. f(x, y) =xe9xy
The gradient vector field of function f(x,y) is given as follows:
grad(f(x,y)) = (1 + 9xy)e^(9xy) i + 9x²e^(9xy) j.
The gradient vector field of a function
Suppose that a function defined as follows:
f(x,y).
The gradient function is defined considering the partial derivatives of function f(x,y), as follows:
grad(f(x,y)) = fx(x,y) i + fy(x,y) j.
The gradient of a function is a vector field. It is obtained by applying the vector operator V to the scalar function f(x, y). Such a vector field is called a gradient (or conservative) vector field.
In which:
fx(x,y) is the partial derivative of f relative to variable x.
fy(x,y) is the partial derivative of f relative to variable y.
The function in this problem is defined as follows:
f(x,y) = xe^(9xy).
The partial derivative relative to x as follows:
fx(x,y) = e^(9xy) + 9xye^(9xy) = (1 + 9xy)e^(9xy).
The partial derivative relative to y as follows:
fy(x,y) = 9x²e^(9xy).
Hence the gradient vector field of the function is defined as follows:
grad(f(x,y)) = (1 + 9xy)e^(9xy) i + 9x²e^(9xy) j.
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Mental processes or behavior patterns that cause emotional distress or substantial impairment in functioning are considered _____ A. conditions of worth. B. psychological disorders. C. trait theories. D. cognitive distortions.
Answer: b) psychological disorders
Step-by-step explanation:
Which of the following can tell us the variation of data within a group of samples? (Check all correct options)
a. T-value
b. Variance
c. Standard deviation
d. Mean
Variance and Standard deviation can tell us the variation of data within a group of samples.
What is a variance?
Variance is a term used in probability theory and statistics to measure how far a group of numbers are spread out from their mean value.
In the context of hypothesis testing, the variance of two groups of data is compared to see if they are statistically significant.
A smaller variance indicates that the data points are closer together, whereas a larger variance indicates that the data points are farther apart.
What is Standard deviation?
The standard deviation is the square root of the variance, and it is used to express the average distance that data points deviate from the mean in a group of samples.
It is used in statistics to measure how tightly a set of data is clustered around its mean.
What is Mean?
The average value of a group of numbers is referred to as the mean.
It is calculated by adding all of the numbers together and then dividing by the total number of numbers.
What is T-value?
The t-value is used to test the null hypothesis, which states that there is no significant difference between two groups of data.
The t-value is calculated by subtracting the mean of one group from the mean of the other group and then dividing by the standard deviation of the two groups combined.
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2d²y/dx² + yd²y/dx² = 0, dy/dx at x = 0 = 0, dy/dx at x = infinite = 1, dy/dx at x = 5 = 0.99 d²z/dx² + k/2y dz/dx = 0 z(0) = 0 and z(infinite) = 1 k is just a constant. Solve the differential equations with boundary conditions. By using Runge kutta4 method with MATLAB
Adjust the parameters as needed, such as the step size (h) and the final x-value (xn), and run the code to obtain the solution for y(x).
The resulting plot will show the solution curve.
To solve the given set of differential equations using the Runge-Kutta method in MATLAB, we need to convert the second-order differential equations into a system of first-order differential equations.
Let's define new variables:
y = y(x)
z = dz/dx
Now, we have the following system of first-order differential equations:
dy/dx = z (1)
dz/dx = -k/(2y) (2)
To apply the Runge-Kutta method, we need to discretize the domain of x. Let's assume a step size h for the discretization. We'll start at x = 0 and proceed until x = infinite.
The general formula for the fourth-order Runge-Kutta method is as follows:
k₁ = h f(xn, yn, zn)
k₂ = h f(xn + h/2, yn + k₁/2, zn + l₁/2)
k₃ = h f(xn + h/2, yn + k₂/2, zn + l₂/2)
k₄ = h f(xn + h, yn + k₃, zn + l₃)
yn+1 = yn + (k₁ + 2k₂ + 2k₃ + k₄)/6
zn+1 = zn + (l₁ + 2l₂ + 2l₃ + l₄)/6
where f(x, y, z) represents the right-hand side of equations (1) and (2).
We can now write the MATLAB code to solve the differential equations using the Runge-Kutta method:
function [x, y, z] = rungeKuttaMethod()
% Parameters
k = 1; % Constant k
h = 0.01; % Step size
x0 = 0; % Initial x
xn = 10; % Final x (adjust as needed)
n = (xn - x0) / h; % Number of steps
% Initialize arrays
x = zeros(1, n+1);
y = zeros(1, n+1);
z = zeros(1, n+1);
% Initial conditions
x(1) = x0;
y(1) = 0;
z(1) = 0;
% Runge-Kutta method
for i = 1:n
k1 = h * f(x(i), y(i), z(i));
l1 = h * g(x(i), y(i));
k2 = h * f(x(i) + h/2, y(i) + k1/2, z(i) + l1/2);
l2 = h * g(x(i) + h/2, y(i) + k1/2);
k3 = h * f(x(i) + h/2, y(i) + k2/2, z(i) + l2/2);
l3 = h * g(x(i) + h/2, y(i) + k2/2);
k4 = h * f(x(i) + h, y(i) + k3, z(i) + l3);
l4 = h * g(x(i) + h, y(i) + k3);
y(i+1) = y(i) + (k1 + 2*k2 + 2*k3 + k4) / 6;
z(i+1) = z(i) + (l1 + 2*l2 + 2*l3 + l4) / 6;
x(i+1) = x(i) + h;
end
% Plotting
plot(x, y);
xlabel('x');
ylabel('y');
title('Solution y(x)');
end
function dydx = f(x, y, z)
dydx = z;
end
function dzdx = g(x, y)
dzdx = -k / (2*y);
end
% Call the function to solve the differential equations
[x, y, z] = rungeKuttaMethod();
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-4x+5(20/11)=-4
Please explain how to get x, thank u!
\(-4x + 5 \left(\dfrac{20}{11}\right) =-4\\\\\implies \dfrac{100}{11} = -4+4x\\\\\implies 100 = -44+44x\\\\\implies 44x = 100 +44 = 144\\\\\implies x = \dfrac{144}{44} = \dfrac{36}{11}\)
What is the value of x? Enter your answer in the box. X=
3x+50
6x-10
6x-10=3x+50
6x-3x=10+50
=3x. 60
(Divide both by 3)
x = 20
Answer:
X= 20 degrees
Step-by-step explanation:
Determine whether the relations represented by these zero-one matrices are partial orders. Ti 0 1 07 1 0 1 1 0 (C) 0 0 1 1 | 1 1 0 1
the relation represented by matrix T is not a partial order, while the relation represented by matrix C is a partial order.
To determine whether the relations represented by these zero-one matrices are partial orders, we need to check for three properties: reflexivity, antisymmetry, and transitivity.
Let's analyze each matrix separately:
Matrix T:
0 1
0 1
To determine if this matrix represents a partial order, we need to check the three properties:
1. Reflexivity: For every element a, a is related to itself. In this case, both elements 0 and 1 are related to themselves, so reflexivity is satisfied.
2. Antisymmetry: If a is related to b and b is related to a, then a = b. In this case, we see that 0 is related to 1 and 1 is related to 0. Since 0 ≠ 1, the antisymmetry property is not satisfied.
3. Transitivity: If a is related to b and b is related to c, then a is related to c. In this case, we can see that 0 is related to 1, and 1 is related to 0. However, we cannot determine the relationship between 0 and 0 or between 1 and 1. Therefore, the transitivity property is not satisfied.
Since the antisymmetry and transitivity properties are not satisfied, the relation represented by matrix T is not a partial order.
Matrix C:
0 0 1 1
| 1 1 0 1
1. Reflexivity: Both 0 and 1 are related to themselves, so reflexivity is satisfied.
2. Antisymmetry: The matrix C satisfies the antisymmetry property since there are no pairs of distinct elements where both a is related to b and b is related to a simultaneously.
3. Transitivity: The matrix C also satisfies the transitivity property. For any three elements a, b, and c, if a is related to b and b is related to c, then a is related to c.
Since matrix C satisfies reflexivity, antisymmetry, and transitivity, the relation represented by matrix C is a partial order.
In summary, the relation represented by matrix T is not a partial order, while the relation represented by matrix C is a partial order.
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Factor completely
x^2 – 36.
O (x + 6)(x - 6)
O (x + 6)(x + 6)
O (x-6)(x-6)
O Prime
Answer:
I think it's a I might be wrong..
Answer:
a
Step-by-step explanation: edge 2022
Geometry: Complete the Flow Chart
Given: ∠1 is a complement of ∠2
∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
We have proven that ∠1 is a complement of ∠3 using the substitution property
Proof of anglesFrom the question, we are to prove that ∠1 is a complement of ∠3
From the given information, we have that
∠1 is a complement of ∠2
That is,
∠1 + ∠2 = 90°
NOTE: Complementary angles sum up to 90°
Also, we have that
∠2 ≅ ∠3
From the Substitution property of equality which states "If a variable x is equal to another variable y, then x can be substituted in place of y in any equation/expression and y can be substituted in place of x in any equation/expression."
Since ∠2 ≅ ∠3
We can substitute ∠3 for ∠2 in the first equation
That is,
∠1 + ∠2 = 90° becomes
∠1 + ∠3 = 90°
Since ∠1 and ∠3 sum up to 90°, then ∠1 is a complement of ∠3.
Thus,
∠1 is a complement of ∠3
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