Liters of Oxygen : 61.6 L
Further explanationGiven
5.5 moles Na₂O
Required
Liters of Oxygen
Solution
Reaction
4Na+O₂⇒2Na₂O
mol O₂ from equation :
= 1/2 x mol Sodium oxide
= 1/2 x 5.5
= 2.75
Assume at STP(1 mol gas=22.4 L), liters O₂ :
= 2.75 x 22.4
= 61.6 L
what is the mpircial formula of a compound this is comprised of 1603 g of sulfur and 24 grans if ixygen
The empirical formula for sulfur and oxygen will be SO₃.
Steps to writing empirical formula,
Step 1: write the symbol of each element.
Step 2: write their percentage composition
Step 3: divide by atomic mass in percentage composition of each element.
step 4: divide all values obtained in the above step by the smallest value obtained in the above step.
steps 5: The ratio of the number of atoms obtained in the above step will represent the empirical formula of the compound. The empirical formula represents the simplest ratio of atoms.
Now percentage composition of \($s=\frac{\text { mass of } s}{\text { total mass }} \times 100$\)
\(\begin{aligned}&=\frac{16.03}{16.03+24} \times 100 \\&=40 \%\end{aligned}\)
percentage composition of O\($=\frac{\text { mass of } O}{\text { tofalmass }} \times 100$\)
\(\begin{aligned}&=\frac{24}{16.03+24} \times 100 \\&=60 \%\end{aligned}\)
Step 1: S O
Step 2: 40 60
Step 3: 40/32=1.25 60/16 =3.75
Step 4: 1.25/1.25 3.75/1.25
Step 5: 1 3
Thus the ratio of atoms of s & 0 is 1: 3.
So the empirical formula will be \($\mathrm{SO}_{3}$\)
What is the Empirical formula?
The Empirical Formula of a compound gives the simplest ratio of different atoms present.It is also known as the simplest formula.The Empirical formula tells about the ratio of the number of atoms in the compound.For example, the empirical formula of acetylene is CH.To learn more about empirical formulas, visit: https://brainly.com/question/14044066
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How many moles of potassium in 73.56g of potassium chlorate (V) (KClO 3 )?
Answer:
Approximately \(0.6003\; \rm mol\) formula units.
Explanation:
Formula Mass of KClO₃Look up the relative atomic mass data for \(\rm K\), \(\rm Cl\), and \(\rm O\) on a modern periodic table:
\(\rm K\): \(39.908\).\(\rm Cl\): \(35.45\).\(\rm O\): \(15.999\).The relative atomic mass of an element is numerically equal to the mass (in grams) of one mole of its atoms. For example, the relative atomic mass of \(\rm K\) is \(39.908\). Therefore, the mass of one mole of \(\rm K\!\) atoms should be \(39.908\; \rm g\).
Each \(\rm KClO_3\) "formula" unit includes one \(\rm K\) atom, one \(\rm Cl\) atom, and three \(\rm O\) atoms. Therefore, one mole of \(\rm KClO_3\!\) formula units would include:
one mole of \(\rm K\) atoms, one mole of \(\rm Cl\) atoms, and three moles of \(\rm O\) atoms.From the relative atomic mass of these three elements:
The mass of one mole of \(\rm K\) atoms would be \(39.908\; \rm g\).The mass of one mole of \(\rm Cl\) atoms would be \(35.45\; \rm g\).The mass of three moles of \(\rm O\) atoms would be \(3 \times 15.999\; \rm g = 47.997\; \rm g\).Combining these three parts should give the mass of one mole of \(\rm KClO_3\) formula units:
\(\begin{aligned}& M(\mathrm{KClO_3}) \\ &= 39.908 + 35.45 + 3 \times 15.999 \\ &= 122.545\; \rm g \cdot mol^{-1}\end{aligned}\).
Number of moles of KClO₃ formula units in the sampleThe formula mass of \(\rm KClO_3\) is \(M(\mathrm{KClO_3}) = 122.545\; \rm g \cdot mol^{-1}\), meaning that the mass of one mole of \(\rm KClO_3\!\) formula units would be \(122.545\; \rm g\!\).
The mass of this \(\rm KClO_3\!\!\) sample is \(m(\mathrm{KClO_3}) = 73.56\; \rm g\). The number of moles of formula \(\rm KClO_3\!\) units in this sample would be:
\(\begin{aligned}n(\mathrm{KClO_3}) &= \frac{m(\mathrm{KClO_3})}{M(\mathrm{KClO_3})} \\ &= \frac{73.56\; \rm g}{122.545\; \rm g \cdot mol^{-1}} \approx 0.6003\; \rm mol\end{aligned}\).
To know the exact number of mole of potassium (K) in 73.56 g of potassium chlorate (v), KClO₃ do the following:
Step 1:Determination of the number of mole in 73.56 g of potassium chlorate (v), KClO₃
Mass of KClO₃ = 73.56 g
Molar mass of KClO₃ = 39 + 35.5 + (16×3)
= 39 + 35.5 + 48
= 122.5 g/mol
Mole of KClO₃ =?\(Mole =\frac{mass}{molar mass}\\\\Mol KClO_{3} = \frac{73.56}{122.5}\)
Mole of KClO₃ = 0.6 moleStep 2:Determination of the number of mole of potassium, K in 0.6 mole (i.e 73.56 g) of KClO₃
Considering the molecular formula of potassium chlorate (v), KClO₃, we can see that:
1 mole of KClO₃ contains 1 mole of K.
Therefore, 0.6 mole of KClO₃ will also contain 0.6 mole of K.
Therefore, we can conclude that 73.56 g of KClO₃ contains 0.6 mole of potassium, K.
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What method would you use to reparate rice which been mixed with flour
Answer:
You can separate flour and rice using a sieve, but you won't be able to separate all of the flour from the rice since the flour is too small to see.
Explanation:
.
Sodium likes to _____ its valence electron becoming a _____ charged ion.
gain; positive
gain; negative
lose; positive
gain; positive
Answer:
lose; positive
Explanation:
Vaporization is the reverse of condensation. Select one: True False
Answer:
True
Explanation:
How are crystals formed?
Answer:
Crystals form in nature when molecules gather to stabilize when liquid starts to cool and harden. This process is called crystallization and can happen when magma hardens or when water evaporates from a natural mixture too. Many crystals start small but as more atoms join and create a uniform and repetitive pattern, the crystal grows. This is how crystals are formed in nature.
Explanation:
彡jessbragoliwhen placed at the same temperature, compare the entropy of 10 mole of ar(g) at 10.0 atm and 10 mole of ar(g) at 0.5 atm. which system has a higher entropy? group of answer choices 10 mole of ar(g) at 10.0 atm 10 mole of ar(g) at 0.5 atm there is not enough information. they are the same in entropy.
When placed at the same temperature, the entropy of 10 mole of Ar(g) at 10.0 atm and the 10 mole of Ar(g) at 0.5 atm. The system has a higher entropy is 10 mole of Ar(g) at 0.5 atm.
The entropy is the measure the randomness of the of the system. the measure of the system's thermal energy per unit the temperature that is not available for doing the useful work.
The Entropy will increases with temperature at the constant pressure. The pressure increases leads to the higher degree of the order in the molecular arrangement. so, the entropy decreases with the increasing pressure.
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45. The following data was collected for 3 compounds:
Mass of Nitrogen that combines with 1 g of Oxygen
Compound A 1.750 g
Compound B 0.8750 g
Compound C 0.4375 g
Show whether these are the same or different compounds. What chemical law is being observed here?
Answer:
The three compounds are different compounds
Explanation:
The mass of Nitrogen that combines with 1 gram of Oxygen in Compound A = 1.750 g
The mass of Nitrogen that combines with 1 gram of Oxygen in Compound B = 0.8750 g
The mass of Nitrogen that combines with 1 gram of Oxygen in Compound C = 0.4375 g
According to the law of multiple proportions, when atoms of two different elements react to form compounds, the masses of one of the elements that combines with a fixed mass of the other element are in small whole number ratios.
The ratio of the masses are;
Mass of Nitrogen in Compound B/(Mass of Nitrogen in Compound C = 0.8750/0.4375 = 2
Mass of Nitrogen in Compound A/(Mass of Nitrogen in Compound C = 1.750/0.4375= 4
Mass of Nitrogen in Compound A/(Mass of Nitrogen in Compound B = 1.750/0.8750= 2
Given that the masses of Nitrogen in the three compounds are in small whole number ratios, the three compounds, Compound A, Compound B, and Compound C are different compounds.
Who turned the ragged Continental Army into a more efficient fighting force?
what are the limiting and excess reactants if 20.0g of C3H8 reacts with 10.0g of O2
Step 1
The reaction must be completed and balanced as follows:
C3H8 + 5 O2 => 3 CO2 + 4 H2O
-------------
Step 2
Information provided:
20.0 g of C3H8
10.0 g of O2
----
Information needed:
1 mole of C3H8 = 44.1 g
1 mole of O2 = 32.0 g
(use your periodic table please)
-------------
Step 3
By stoichiometry,
C3H8 + 5 O2 => 3 CO2 + 4 H2O
44.1 g C3H8 ---------- 5 x 32.0 g O2
20.0 g C3H8 ---------- X
X = 20.0 g C3H8 x 5 x 32.0 g O2/44.1 g C3H8
X = 72.6 g O2
For 20.0 g of C3H8, 72.6 g of O2 is needed, but there is only 10.0 g of O2.
Therefore,
Answer:
The limiting reactant = O2
The excess = C3H8
Marco was looking at this picture of two boats sitting differently in the water. He decided to compare the way the two boats sit in the water to the way land is behaving in Greenland.
I don't know
Explanation:
because it does not give an question
Help I need them fast pls
Answer:
I don't have a paper right now so I am attaching images for b(i), (ii) and c(i)
Explanation:
c) Ionic bond is the result of strong electrostatic force of attraction between positively charged metal ion and negatively charged metal ion.
a. Write down any two aspects of community health
Answer:
Hope the above picture might help you :)
Answer:
Community health is a branch of public health which focuses on people and their role as determinants of their own
Without using a calculator, estimate the pH of a solution with a hydronium ion concentration of 3.4x10-2 M. Group of answer choices 6.8 2.0 1.5 3.4
The pH of a solution with a hydronium ion concentration of 3.4x10⁻² M is approximately 1.5.
pH is a logarithmic scale that measures the acidity or basicity of a solution. It is defined as the negative logarithm (base 10) of the hydronium ion concentration (H₃O⁺). The pH scale ranges from 0 to 14, where values below 7 indicate acidic solutions, values above 7 indicate basic solutions, and a pH of 7 represents a neutral solution.
To calculate the pH of a solution with a hydronium ion concentration of 3.4x10⁻² M, you can follow these steps:
Step 1: Take the negative logarithm (base 10) of the hydronium ion concentration:
pH = -log10(3.4x10⁻²)
Step 2: Simplify the logarithm expression:
pH = -log10(3.4) + log10(10⁻²)
Step 3: Evaluate the logarithm of 3.4 using a calculator:
pH ≈ -0.531 + log10(10⁻²)
Step 4: Since log10(10⁻²) equals -2, simplify further:
pH ≈ -0.531 - 2
Step 5: Add the numbers to get the final result:
pH ≈ -2.531
Therefore, the estimated pH of the solution with a hydronium ion concentration of 3.4x10⁻² M is approximately 2.53. Note that this is an estimation, and the actual pH may vary slightly depending on the precise calculation and rounding.
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what can you infer about a wave with a short wave leagth
Answer:
It has a high frequency
Explanation:
ABS plastic is a polymer consisting of three monomer units: acrylonitrile (C3H3N), butadiene (C4H6), and styrene (C3H8). A sample of ABS plastic contains 11.9% N by mass. It took 1.56 g of Br2 to react completely with a 2.00 g sample of ABS plastic. Bromine reacts 1:1 (by moles) with the butadiene units in the polymer and nothing else, so bromination is a method for determining the quantity of butadiene in the polymer. What is the percent by mass of styrene in the polymer?
The percent by mass of styrene in ABS plastic is 73.55%.
What percentage by mass of styrene in the polymer?The percent by mass of styrene in the polymer is calculated as follows:.
moles of Br2 used:
Moles of Br₂ = mass of Br₂ used / molar mass of Br₂
Moles of Br₂ = 1.56 g / 159.80 g/mol
Moles of Br₂ = 0.00977 mol
moles of butadiene:
Moles of butadiene = Moles of Br₂
Moles of butadiene = 0.00977 mol
The mass of butadiene:
Mass of butadiene = Moles of butadiene × molar mass of butadiene
Mass of butadiene = 0.00977 mol × 54.10 g/mol
Mass of butadiene = 0.529 g
The mass of styrene:
Mass of styrene = Total mass of ABS plastic - Mass of butadiene
Mass of ABS plastic = 2.00 g
Mass of styrene = 2.00 g - 0.529 g
Mass of styrene = 1.471 g
The percent by mass of styrene:
The percent by mass of styrene = (Mass of styrene / Total mass of ABS plastic) × 100
Percent by mass of styrene = (1.471 g / 2.00 g) × 100
Percent by mass of styrene = 73.55%
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Separate the Pennie’s you have into two groups: one group with Pennie’s dated before 1982 and the other with pennies dated after 1982. Compare the two groups. Record any similarities or differences in size or appearance that you notice between the two groups
Using hypothetical scenario, the Separation of the Pennie’s are given below
What are the Pennies about?Pennies dated after 1982 are lighter and thinner because zinc is less dense than copper. However, they have a similar diameter of 19.05mm to pennies dated before 1982. The difference in composition between the two groups is important because copper is a valuable metal, and the cost of producing a penny exceeded its value. By reducing the amount of copper in pennies, the U.S. Mint was able to save money on production costs.
Pennies dated before 1982 are made of 95% copper and 5% zinc and weigh 3.11 grams. They have a diameter of 19.05mm and a thickness of 1.55mm. Pennies dated after 1982 are made of 97.5% zinc and 2.5% copper and weigh 2.5 grams. They have a diameter of 19.05mm and a thickness of 1.52mm.
Therefore, the main difference between the two groups is their composition, weight, and thickness. The pennies dated before 1982 are larger, heavier, and thicker than those dated after 1982.
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Complete reaction carbon-13 + alpha = oxygen-16 + x0123456789abcdefghij edited question
This is a perfect answer
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\(\text{y = ax + b}\)The first-order decomposition of cyclopropane has a rate constant of 6. 7 x 10-4 s-1. if the initial concentration of cyclopropane is 4. 33 m, what is the concentration of cyclopropane after 234 s?
The concentration of cyclopropane after 234 s is 3.70M, using formula of half life.
As indicated by units of k, this is a first order reaction.
We can use the integrated rate law \([A] = [A]_{0} e^{-kt}\)or we can use half life.
First order half life = 0.693/k = 0.693/6.7x10-4 s-1
1034s = \(t\frac{1}{2}\)
number of half lives elapsed =234sec x 1 half life/1034 sec = 0.226 half lives elapsed
Fraction remaining = \(0.5^{n}\)
where n is half lives elapsed
Fraction remaining = \(0.5^{0.226}\)
Fraction remaining = 0.855
Concentration remaining = 4.33 M x 0.855 = 3.70 M
Therefore, concentration of cyclopropane after 234 s is 3.70M, using formula of half life.
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2(t. A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6"C. Determine thetemperature at which the volume of the gas is 3.45 L.a) 309 K b) 281 K e) 20,6 K d) 294 K e) 326 K
They tell us that the pressure of the gas is constant and the temperature and volume vary. If we assume that the gas behaves like an ideal gas, we can apply Charles's law, which tells us:
\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)where,
V1 is the initial volume, 3.62L
T1 is the initial temperature, 21.6°C=294.75K
V2 is the final volume, 3.45L
T2 is the final temperature, in Kelvin
Now, we clear T2 and replace the known data:
\(T_2=V_2\times\frac{T_1}{V_1}\)\(T_2=3.45L\times\frac{294.75K}{3.62L}=281K\)The temperature at which the volume of the gas is 3.45 L will be 281K
Answer. b) 281K
the _________ in the equation means a reaction is happening
HELP ANYONE ASAP!!!
Answer:
i think its A but im not sure. Hope this helps
which of the following energy sources is considered nonrenewable? which of the following energy sources is considered nonrenewable? solar energy wind energy fossil fuel energy tidal energy geothermal energy
The nonrenewable energy source among the options provided is fossil fuel energy, option C is correct.
Fossil fuels, such as coal, oil, and natural gas, are derived from ancient organic matter that has been buried and transformed over millions of years. These resources are finite and cannot be replenished within a human lifespan. Additionally, their combustion releases carbon dioxide and other greenhouse gases, contributing to climate change and air pollution.
Solar energy, wind energy, tidal energy, and geothermal energy are renewable sources of energy. They rely on naturally replenishing resources like sunlight, wind, tides, and heat from the Earth's core, making them sustainable and environmentally friendly alternatives to fossil fuels, option C is correct.
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The complete question is:
Which of the following energy sources is considered nonrenewable?
A. solar energy
B. wind energy
C. fossil fuel energy
D. tidal energy
E. geothermal energy
what is the net ionic equation for the following reaction? 2koh (aq) h2so4 (aq) ⇒ k2so4 2h2o nr 2h (aq) 2oh- (aq) --> 2h2o (l) oh- (aq) hso4- (aq) --> 2k (aq) h2o (l) none of the above
The given chemical equation is, 2KOH(aq) + H2SO4(aq) → K2SO4 + 2H2O(aq) + nrIt is necessary to write the given chemical equation in the molecular form to get the main answer. The complete balanced molecular chemical equation for the given reaction is;2KOH(aq) + H2SO4(aq) → K2SO4 + 2H2O(aq)In order to obtain the net ionic equation, first, we need to find the state of each element given in the chemical equation.
The given chemical equation is,2KOH(aq) + H2SO4(aq) → K2SO4 + 2H2O(aq)KOH(aq) and H2SO4(aq) are both strong electrolytes, which means that they are completely ionized in the aqueous solution. Now, let's write the dissociation reaction for KOH(aq) and H2SO4(aq).KOH (aq) → K+(aq) + OH-(aq)H2SO4 (aq) → 2H+(aq) + SO4-2(aq)The reaction shows that KOH dissociates into potassium ions, K+(aq), and hydroxide ions, OH-(aq), while H2SO4 dissociates into hydrogen ions, H+(aq), and sulfate ions,
SO4-2(aq).Now, we need to balance the ionic equation by following the rules given below:(i) Cancel out the spectator ions which are present on both sides of the equation.(ii) Write the remaining ions separately as a product.In the given reaction, K+(aq) and SO4-2(aq) are the spectator ions as they are present on both sides of the equation. Therefore, they are canceled out. The balanced net ionic equation is:H+ (aq) + OH- (aq) → H2O(l)OH-(aq) and HSO4-(aq) are the reactants in the net ionic equation.The net ionic equation is 2H+ (aq) + SO4-2(aq) + 2OH- (aq) → 2H2O(l)The answer is "2H+ (aq) + SO4-2(aq) + 2OH- (aq) → 2H2O(l)".
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_____of gas molecules with an object is the cause of
pressure by a gas.
Answer:
Gas Pressure
Explanation:
Gas pressure is caused by the force exerted by gas molecules colliding with the surfaces of objects (Figure 5.2. 1). Although the force of each collision is very small, any surface of appreciable area experiences a large number of collisions in a short time, which can result in a high pressure.
Answer:
Collisions
Explanation:
It says that it was the answer.
An organic compound containing 40% carbon, 6.67% hydrogen and rest of oxygen, has the molecular mass 180g.mol-1. Find out the EF as well as MF of the compound.
Answer:
The EF of the compound is CH2O and the MF is C6H12O6.
Explanation:
To find the empirical formula (EF) of the compound, we need to determine the simplest whole number ratio of the atoms in the compound. We can assume we have 100 g of the compound, which means we have:
40 g of carbon
6.67 g of hydrogen
53.33 g of oxygen (since the rest of the compound is oxygen)
Next, we can convert the masses to moles:
Moles of carbon = 40 g / 12.01 g/mol = 3.33 mol
Moles of hydrogen = 6.67 g / 1.01 g/mol = 6.61 mol
Moles of oxygen = 53.33 g / 16.00 g/mol = 3.33 mol
We then divide each of the mole values by the smallest number of moles, which is 3.33, to get the simplest whole number ratio:
Carbon: 3.33 / 3.33 = 1
Hydrogen: 6.61 / 3.33 = 1.98 (rounded to 2)
Oxygen: 3.33 / 3.33 = 1
So the EF of the compound is CH2O.
To find the molecular formula (MF), we need to know the molecular mass of the EF. The empirical formula mass (EFM) of CH2O is:
EFM = (1 x 12.01 g/mol) + (2 x 1.01 g/mol) + (1 x 16.00 g/mol) = 30.03 g/mol
We can then calculate the molecular formula mass (MFM) by dividing the given molecular mass (180 g/mol) by the EFM:
MFM = 180 g/mol / 30.03 g/mol = 6
This means the MF is 6 times the EF, or C6H12O6. Therefore
please help me !!! im failing :(
Answer: H
H- C- H
H
Explanation:
Lewis structures are the structures which represent the valence electrons of the element around the chemical symbol of the element.
Carbon is an element which belong to group 14. Atomic number of carbon is 6 that means it contains 6 electrons, Thus the electronic configuration is represented as: \(1s^22s^22p^2\) . Thus the valence electrons are 4.
Hydrogen is an element which belong to group 1. Atomic number of hydrogen is 1 that means it contains 1 electron, Thus the electronic configuration is represented as: \(1s^1\) . Thus the valence electron are 1.
The four valence electrons of carbon are shared with one valence electron of hydrogen each.
Which best describes an element?
a pure substance
a type of a mixture
a pure compound
an impure substance
Answer:
An impure substance
Explanation:
Substance means: hard surface example: salt,corals,coal.
Which element contains the same number of valence electrons as carbon (C)?
Answer:
silicon
Explanation:
Carbon and silicon BOTH come from Group 14 of the Periodic Table , i.e. both formally have the same number of valence electrons, 4 such electrons
Answer:
silicon
Explanation:
Carbon and silicon both come from Group 14 of the Periodic Table
How many Joules of heat are needed to raise the temperature of 500. grams of water from 15.0ºC to 20.0ºC?
Answer: 2,090J
The equation to find the specific heat is determined by the equation q = mcΔT, where q = total heat, m=mass, c = specific heat, and ∆T change in temperature.
Recall that the specific heat capacity for water is 4.18J/gºC
So, plug this along with your specific values into the equation.
q = 100g * (4.18J/gºC) * (20.0ºC-15.0ºC)
q = 2090J