If there is "waste" energy, does the Law of Conservation of Energy still apply? ​

Answer:

439.6 THz

Explanation:

The mass of the other object is 18.11 kg and their acceleration  will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².

Given parameter:

The gravitational force between two objects : F = 3.2×10⁻⁶ N.

Distance between two objects : r =  2.1x10⁻¹ m.

The mass of one object m₁ = 55 kg.

The mass of other object m₂ =?

From universal gravitational law, we know that, force acting between two objects of mass m₁ and m₂ separated by a distance r is:

F = G m₁ m₂ / r²

Where, G = universal gravitational constant = 6.67 × 10⁻¹¹ N m⁻² kg⁻².

So, we can write,

 3.2×10⁻⁶ N = (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg) m₂/( 2.1x10⁻¹ m)

⇒ m₂ = (3.2×10⁻⁶ N ×  2.1x10⁻¹ m )/ { (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg)}

= 18.11 kg.

Hence, the mass of the other object is 18.11 kg.

So, acceleration of the object of mass 55 kg is:

a₁ = F/m₁ = 3.2×10⁻⁶/55  m/s² = 5.8 × 10⁻⁸ m/s².

The acceleration of the object of mass 18.11 kg is:

a₂ = F/m₂ = 3.2×10⁻⁶/18.11 m/s² =  17.66× 10⁻⁸ m/s².

Hence, their acceleration if they are released from their position will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².

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Answer: 30 cm.

The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.

When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.

If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:

d = λ/2 + nλ

where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.

At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:

λ = 2(d_max - d_min) = 20 cm

Substituting λ and n into the formula gives:

d = λ/2 + nλ = 10 cm + 20 cm = 30 cm

Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.

Answer:

What is the first velocity of the car with three washers

at the 0.25 meter mark? 0.19

What is the second velocity of the car with three

washers at the 0.50 meter mark? 0.45

Explanation:

Look at the question carefully.

The person above me got the answer wrong.

That answer is for a very similar question, but not this one.

(1) The first velocity of the car with two washers at the 0.25 meter mark is 0.125 m/s.

(2) The second velocity of the car with two washers at the 0.5 meter mark is 0.25 m/s.

Velocity is the rate of change of displacement with time. The velocity of the  cars depends on displacement and time of motion.

First velocity of the car at the 0.25 meter mark

The first velocity is calculated as follows;

v1 = 0.25 m / t1

let t₁ = 2 s

v₁ = 0.25/2

v₁ = 0.125 m/s

Second velocity of the car at the 0.5 meter mark

v2 = 0.25 m / (t2 – t1)

let t₂ = 3 s

v₂ = 0.25(3 - 2)

v₂ = 0.25 m/s

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here, d is the distance covered.

And t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

Here, t1 is the average time for the first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

v2 = d2/t2

v2 = 0.50 /t2

Therefore, here, t2 is the average time for the second distance.

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The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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When the current in two parallel metal conductors are in the same direction, the conductors attract each other. Suppose that the current flows in upward direction in both the conductors, therefore according to right hand rule the force on the left hand side of conductor will be directed towards right direction and the force on right hand direction will be directed towards left direction which means they will attract each other.

Answer:

I think some drawbacks are that since there are no solid walls meaning it is weak and if murphy's law is in place, the water will destroy the substance. Tsunami waves also happen very quickly so even if the water can travel thru the substance quickly, it probably won't be quick enough. This design could help if the wave is smaller because less destruction would occur.

Explanation:

yeah

Answer:

35.625° C

Explanation:

See attachment

a) Final temperature is 35.625° C

b) 0°

Answer:

microscopic light or Nano technology

Answer:

The pressure at this depth is \(1.235\cdot P_{atm}\).

Explanation:

According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:

\(\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}\) (1)

Where:

\(V_{1}, V_{2}\) - Initial and final volume.

\(P_{1}, P_{2}\) - Initial and final pressure.

If we know that \(V_{2} = 0.81\cdot V_{1}\), then the pressure ratio is:

\(\frac{P_{2}}{P_{1}} = 1.235\)

If \(P_{1} = P_{atm}\), then the final pressure of the gas is:

\(P_{2} = 1.235\cdot P_{atm}\)

The pressure at this depth is \(1.235\cdot P_{atm}\).

The pressure of the fluid at this depth will be "1.16 \(P_{atm}\)".

According to the question,

Let,

The volume of surface be "100 units".

then,

The volume of depth be:

= 100 - 14

= 86 units

We know the relation,

P ∝ \(\frac{1}{V}\)

here, PV = Constant

By using Boyle's law,

→ P₁ V₁ = P₂ V₂

or,

→     P₂ = \(\frac{P_1 V_1}{V_2}\)

By substituting the values, we get

           = \(\frac{P_{atm}\times 100}{86}\)

           = 1.16 \(P_{atm}\)

Thus the above answer is appropriate.

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The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The speed of the continent is found to be 7.68 centimeters per hour when 1920000000cm is divided by 250000000years.

The distance travelled by the continent is 1920000000cm.

The time taken by the continent to complete its path is 250000000.

The speed S of the body,

S = D/T

Where,

D is the distance travelled by the body,

T is the time taken by the body to cover that distance.

The speed S of the continent is,

S = D/T

S = 1920000000cm/250000000year

S = 7.68 cm/year

Hence, the speed of the continent is 7.68 centimeters per year.

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Answer:The direction of the resultant can be determined by finding the angle that the resultant makes with either the north-south or the east-west vector. The diagram at the right shows the angle theta (Θ) marked inside the vector addition triangle. This angle theta is the angle that the resultant makes with west.

Explanation: Because i said

The electrical force between two charged objects decreases as the distance between them increases. This means that as the distance between two positively charged pith balls increases, the electrical force between them decreases. Therefore, the electrical charge on each pith ball is not affected by the distance between them. The charge on each pith ball will remain the same regardless of the distance between them. However, the electrical force between the pith balls will be weaker at greater distances, and stronger at smaller distances.

Answer:

i'm pretty sure what the other guy means is:

The greater the distance between the pith balls, the lesser the amount of electric charge that exists between them.

Explanation:

"This means that as the distance between two positively charged pith balls increases, the electrical force between them decreases"

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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The potential energy of the system have been observed as 0.7 J.

We know that the potential energy is the energy that is possessed by an object that is found at a given height. The implication of this is that the potential energy depends on the height of the object.

If we decrease the height of the object then the potential energy of the body would also change. We have been told that the mass of the balls are 30 g each hence a total mass of 120 g or 0.12 Kg.

The change in the potential energy is;

0.12 * 9.8 * (0.9 - 0.3)

= 0.7 J

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At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

A person taking the charge of the organization and leading a team under him is known as a leader.

"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."

Options:

First Blank: work ethic

First Blank: self-representation

First Blank: diversity awareness

Second Blank: leadership skills

Second Blank: nonverbal skills

Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.

By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.

Hence, self-representation and leadership skills are the correct answer.

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Answer:

Brainliest pls

Explanation:

the playing of musical tones together in chords. 2: a pleasing arrangement of parts a harmony of colors. 3: agreement sense 1, accord The committee worked in harmony.

agreement; accord; harmonious relations. a consistent, orderly, or pleasing arrangement of parts; congruity. Music. any simultaneous combination of tones. the simultaneous combination of tones, especially when blended into chords pleasing to the ear; chordal structure, as distinguished from melody and rhythm.

What is harmony? What is the meaning of it.

Law of conservation of momentum states "The total momentum of all objects interacting with one another remains constant, regardless of the nature of the forces between the objects".

Law of conservation of energy states "Within a closed system, the total amount of energy will remain constant". The equation derived using the Law of conservation of energy is

E =m g H

E = Energy

m = Mass

g = Acceleration

H = Height

The equation derived using the Law of conservation of momentum is

\(m_{1} u_{1} +m_{2} u_{2}\) = \(m_{1} v_{1} + m_{2} v_{2}\)

\(m_{1}\) = Mass of object 1

\(m_{2}\) = Mass of object 2

\(u_{1}\) = Initial velocity of object 1

\(u_{2}\) = Initial velocity of object 2

\(v_{1}\) = Final velocity of object 1

\(v_{2}\) = Final velocity of object 2

Therefore,

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Answer:

The horizontal distance between two adjacent crests or troughs is known as the wavelength.

Answer: Wavelength

Explanation:

From crest to crest, it is one full wavelength

1. Galileo.

2. Newton.

3. Kepler.

4. Brahe.

5. Refracting telescope.

6. Reflecting telescope.

7. Astrolabe

8. Camera.

9. Radio telescope.

1. Galileo, who uncovered information about the lunar surface.

2. The first reflecting telescope was created by Newton.

3. Kepler discovered elliptical orbits for planets.

4. Brahe: He meticulously mapped the sky.

5. A large glass lens is used in a refractive telescope.

6. A reflecting telescope concentrates light using a mirror.

7. Astrolabe: a device used to pinpoint a star's location.

8. Camera: a device that gathers light from an item to display greater detail.

9. The sound of stars is captured by radio telescopes.

Complete question:

The complete questions is (see in attachments).

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The period of rotation of the tires of radius 38 cm is 0.0746 s.

The angle that the tire rotate in one second is 84.21 rad.

v = 2 π r / T

v = Tangential velocity

r = Radius

T = Time period

v = 32 m / s

r = 38 cm = 0.38 m

T = 2 π r / v

T = 2 * 3.14 * 0.38 / 32

T = 0.0746 s

ω = θ / T

ω = v / r

ω = Angular velocity

θ = Angle of rotation

T = 1 s

θ = v T / r

θ = 32 * 1 / 0.38

θ = 84.21 rad

Therefore,

The period of rotation of the tires of radius 38 cm is 0.0746 s.

The angle that the tire rotate in one second is 84.21 rad.

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The stationary object achieves the speed of 5 m/s at time 0.4 second.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Mass of the object = 4 kg.

Force applied on it = 50 Newton.

Acceleration of the object = (50 ÷ 4) m/s² = 12.5 m/s²

Let at time t second, the speed of the object = 5 m/s.

Hence, the time taken to achieve the speed of 5 m/s is = (5 ÷ 12.5) second

= 0.4 second.

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Answer:

B

Explanation:

The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex

When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.

Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.

All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.

Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.

Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.

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Answer:

350 N

Explanation:

F=ma

\(f = force \\ m = mass \\ a = acceleration\)

\(m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} } \)

Force = 350 Newtons

The net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = ma

As given in the problem two people each have a mass of 55 kg. They are both in an elevator that has a mass of 240 kg. When the elevator begins to move, the people and the elevator have an upward acceleration of 1.00 m/s2, then we have to find the net force acting on the elevator,

The net force acting on the elevator,

F = ma

F =(2×55 + 240)×1

  = 350 Newtons

Thus, the net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2

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The motion of the car between the first and last stops is divided in three parts:

• The motion where the car speeds up with acceleration of 4m/s^2.

• The motion without acceleration (when the car coasts for 2 seconds).

• The motion where the car slows down with acceleration of 3 m/s^2.

To determine how far apart the stop signs are we need to calculate how much distance the car traveled in each part. Let's analyze each situation.

First part of the motion.

For this part of the motion of the car we have a constant acceleration, this means that we have an uniform accelerated motion. To determine the distance traveled in this part we can use the equation:

where x is the final position, x0 is the initial position, v0 is the initial velocity, a is the acceleration and t is the time.

In this case the initial position is zero (in here we are putting the origin of the motion at the stop sign), the initial velocity is zero (since the car starts from rest), the acceleration is 4 m/s^2 and the time is 6 seconds; plugging this values in the equation above we have that:

Hence, in this part of the motion the car travelled 72 meters.

We will need the final velocity for this part of the motion in order to calculate the distance traveled in the second part of the motion so let's calculate it. The final velocity can be obtained from the equation:

plugging the values we know and solving for the final velocity we have that:

Therefore the car is traveling at 24 m/s when it starts to coast.

Second part of the motion.

In this part of the motion the car coasts, this means that it is not accelerating, and for this reason, the car does not change its velocity. For this reason we have an uniform rectilinear motion. The change in position in a rectilinear motion is given by:

Changing our origin of the motion to where the car starts to coast we have that the initial position is zero, the velocity is 24 m/s (the velocity in which the car stopped accelerating) and the time is 2 seconds. Plugging this values in the equation we have that:

And then, we conclude, the car travelled 48 meters in this part of the motion.

Third part of the motion.

In here we know that the car is slowing down with an acceleration of 3 m/s^2 until it stops in the next stop sign. Since the acceleration is constant once again we have an uniform accelerated motion. To determine the distance the car traveled in this part we can use the equation:

In this case we know that the final velocity is zero (since the car stops), the initial velocity is 24 m/s (since the car was moving in an uniform rectiliniar motion in the previous part of the motion) and that the acceleration is -3 m/s^2 (we have to use a negative sign since the car is slowing down, this means that the acceleration is negative); plugging the values we have that:

Hence in this part in the motion the car travelled 96 meters.

Finally, now that we know how much the car travelled in each part of the motion, we can calculate how far apart the stop signs are; to do this we add the distance the car travelled in each part, then we have:

Therefore, the stops signs are 216 meters apart.

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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