Identify ​three pollutants released into the air when fossil fuels are burned.

Answers

Answer 1

Answer: Carbon dioxide (CO2), Carbon monoxide (CO), Methane (CH4)


Related Questions


In a DC generator, the generated emf is directly proportional to the

Answers

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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1. Two equally charged particles are held apart when they are released from rest, the initial acceleration of 1st particle is 7.22 m/s^2 and 2nd is 9.16 m/s^2. The mass of the 1st particle is 6.31×10^(-7) kg. Find the mass of 2nd particle and common charge.

Answers

The mass of 2nd particle  be 4.97×10⁻⁷ kg.

The common charge can not be determined.

What is force?

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Given that: two equally charged particles are held apart when they are released from rest. So force acting on them is same.

For 1st particle:

Mass: m₁ =  6.31×10⁻⁷ kg.

Acceleration: a₁ =  7.22 m/s².

For 2nd particle:

Acceleration: a₂ =  9.16 m/s².

Mass: m₂ = ?

As force acting on both particle is same.

m₁a₁ = m₂a₂

⇒ m₂ = m₁a₁/a₂ = ( 6.31×10⁻⁷ kg)×( 7.22 m/s²)/( 9.16 m/s²) = 4.97×10⁻⁷ kg.

So,   the mass of 2nd particle  be 4.97×10⁻⁷ kg.

As there has no mention of distance between them and which type of particle it is, common charge can not be determined.

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What happens when a moving object experiences no net force?

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Answer:

An object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Forces are "pushes" or "pulls" on the object, and forces, like velocity and acceleration are vector quantities.

Food manufacturers create fats by adding hydrogen to fats?

Answers

True, Food manufacturers create fats by adding hydrogen to fats.

What is hydrogenation?

Hydrogenation is used in the oil industry in making trans fats or margarine by increasing the melting point through reducing the carbon-to-carbon double bonds..

During hydrogenation, unsaturated fats undergo a chemical reaction in the presence of hydrogen gas and a catalyst, typically nickel.

The process involves the addition of hydrogen atoms to the carbon double bonds in the fatty acid molecules, resulting in the conversion of some of the double bonds into single bonds.

This reduces the number of unsaturated bonds in the fat, making it more saturated.

So we can conclude that the statement is true.

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As rotational speed increases, thrust____?

increases exponentially.

increases at the same rate.

decreases exponentially.

decreases at the same rate

Answers

Increases exponentially is your correct answer

What are some of the forces affecting rock climbers?​

Answers

Answer:

Gravitational force

Explanation:

Gravitational force is obviously one of the biggest obstacles in climbing. You are essentially going against this very strong force to pull your body mass up the beautiful terrain. Gravity is defined as the force of attraction between all masses in the universe, gravity is what allows the sport of climbing.

Answer:

Gravity, low oxygen, and rock slides.

Explanation:

Some rock climbers train for years but are hardly prepared for some situations.

List four states of matter. Which states of matter are most common on
Earth?

Answers

The four states of matter are:
1. Solid
2. Liquid
3. Gas
4. Plasma

The most common states of matter on Earth are solid, liquid, and gas. Plasma is the most common state of matter in the universe, but it is relatively rare on Earth.

A 58.0 kg skier is moving at 6.00 m/s on a frictionless, horizontal snow-covered plateau when she encounters a rough patch 3.65 m long. The coefficient of kinetic friction between this patch and her skis is 0.310. After crossing the rough patch and returning to friction-free snow, she skis down an icy, frictionless hill 3.50 m high.

Required:
a. How fast is the skier moving when she gets to the bottom of the hill?
b. How much internal energy was generated in crossing the rough patch?

Answers

Answer:

a) v = 3.71m/s

b) U = 616.71 J

Explanation:

a) To find the speed of the skier you take into account that, the work done by the friction surface on the skier is equal to the change in the kinetic energy:

\(-W_f=\Delta K=\frac{1}{2}m(v^2-v_o^2)\\\\-F_fd=\frac{1}{2}m(v^2-v_o^2)\)  

(the minus sign is due to the work is against the motion of the skier)

m: mass of the skier = 58.0 kg

v: final speed = ?

vo: initial speed = 6.00 m/s

d: distance traveled by the skier in the rough patch = 3.65 m

Ff: friction force = Mgμ

g: gravitational acceleration = 9.8 m/s^2

μ: friction coefficient = 0.310

You solve the equation (1) for v:

\(v=\sqrt{\frac{2F_fd}{m}+v_o^2}=\sqrt{\frac{2mg\mu d}{m}+v_o^2}\\\\v=\sqrt{-2g\mu d+v_o^2}\)

Next, you replace the values of all parameters:

\(v=\sqrt{-2(9.8m/s^2)(0.310)(3.65m)+(6.00m/s)^2}=3.71\frac{m}{s}\)

The speed after the skier has crossed the roug path is 3.71m/s

b) The work done by the rough patch is the internal energy generated:

\(U=W_fd=F_fd=mg\mu d\\\\U=(58.0kg)(9.8m/s^2)(0.310)(3.50m)=616.71\ J\)

The internal energy generated is 616.71J

What would happen if a ball of lead is dropped into a beaker filled with mercury? If the density of mercury is 13,600/m3 and the density of lead is 11,340/m2

Answers

Answer:

it will float on the surface of the mercury. The ball of lead will not sink into the mercury because it is less dense than mercury.

Explanation:

Density is a measure of how much mass is packed into a given volume of a substance. The formula for density is:

density = mass / volume

The unit for density is kg/m3 or g/cm3. The higher the density of a substance, the heavier it is for its size. When two substances are mixed together, the one with the higher density will sink to the bottom, while the one with the lower density will float on top. In this question, we are given the densities of mercury and lead as:

density of mercury = 13,600 kg/m3 density of lead = 11,340 kg/m3

We can see that mercury has a higher density than lead, which means that it is heavier for its size. Therefore, if a ball of lead is dropped into a beaker filled with mercury, it will float on the surface of the mercury. The ball of lead will not sink into the mercury because it is less dense than mercury. This is an unusual phenomenon because most metals are denser than liquids and will sink in them. However, mercury is an exception because it is a very dense liquid metal that can make other metals float on it.

What is the speed of a ball that is attached to a string and swings in a horizontal circle of radius 2.0 m with the central acceleration of 15 m/s^2?

Answers

Answer:

5.48 m/s.

Explanation:

Use the formula a=v^2/r.

What is the speed of a ball that is attached to a string and swings in a horizontal circle of radius

The mass of Jupiter is 1.9 x 10 kg and that of the sun is 2 x 10 kg. If the distance between them is 78 x 10 km, find the gravitational force between them.​

Answers

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

The gravitational force between Jupiter and the sun is determined using Newton's law of gravitation, which states that two masses attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given that the mass of Jupiter is \(1.9 * 10^{27} kg\) and that of the sun is \(2 * 10^{30} kg\), and the distance between them is \(78 * 10^6 km (which is 78 * 10^9 m)\), we can use the formula: Gravitational force = G(m1m2)/r^2where G is the universal gravitational constant, m1, and m2 are the masses of the two bodies, and r is the distance between them. Substituting the values gives Gravitational force \(= (6.67 * 10^{-11} Nm^2/kg^2) * (1.9 * 10^{27} kg) * (2 x 10^{30} kg) / (78 * 10^9 m)^2= 1.95 * 10^{22} N\)Thus, the gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)Summary: The gravitational force between Jupiter and the sun is found using Newton's law of gravitation, which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given the mass of Jupiter, the mass of the sun, and the distance between them, we can calculate the gravitational force using the formula. The gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)

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What type of tv uses a VfL for backlighting

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?

Answers

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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how is sound produced by using pipel wind instruments​

Answers

The air inside the pipes of a wind instrument vibrates. ... The result is longitudinal standing waves in the air column inside the pipe. The ends, whether open or closed, create nodes or antinodes in these standing waves.

Answer33

Explanation

33

n a double-slit experiment, the slit separation is 6.03x10-5 meters. The slits are illuminated with a laser beam of wavelength 5.37x10-7 meters. A screen is located 2.14 m from the slits. Calculate the distance on the screen from the first dark fringe on one side of the central maximum to the second dark fringe on the other side.

Answers

Answer:

D = 3.81 x 10⁻² m = 3.81 cm

Explanation:

We can use the formula of fringe spacing from Young's Double Slit experiment to answer this question:

\(\Delta x = \frac{\lambda L}{d}\\\)

where,

Δx = distance between two consecutive dark fringes

λ = wavelength of light beam = 5.37 x 10⁻⁷ m

L = Distance between screen and slits = 2.14 m

d = slit separation = 6.03 x 10⁻⁵ m

But, we need the distance between first dark fringe on 1 side to 2nd dark fringe on other side. It means we need twice the distance between two dark fringes:

\(D = 2\Delta x = 2\frac{\lambda L}{d}\\\)

where,

D = distance between first dark fringe on one side and 2nd dark fringe on other side of central maximum = ?

Therefore,

\(D = \frac{(2)(5.37\ x\ 10^{-7} m)(2.14\ m)}{6.03\ x\ 10^{-5}\ m }\)

D = 3.81 x 10⁻² m = 3.81 cm

A toy racing car moves with constant speed around the circle shown below. When it is at point A its coordinates are x = 0, y = 3 m and its velocity is (6 m/s)ˆi. When it is at point B its velocity and acceleration are

A toy racing car moves with constant speed around the circle shown below. When it is at point A its coordinates

Answers

The speed of the car is 6 m/s. The acceleration vector at point B has a direction of (-1, -1) and a magnitude of approximately 16.97 m/s².

We can start by finding the speed of the toy car. Since it is moving with constant speed around the circle, its speed is the same at points A and B. To find the speed, we can use the fact that the velocity vector has a magnitude equal to the speed:

|v| = √((6 m/s)²) = 6 m/s

So the speed of the car is 6 m/s.

Next, we can find the direction of the velocity vector at point B. We know that the car is moving around a circle centered at the origin, and that point B is on the circle. Therefore, the velocity vector at point B is tangent to the circle and perpendicular to the line connecting the origin to point B.

The line connecting the origin to point B is given by:

y = (0 - 3)/(0 - (-3)) * (x - (-3)) + 0

y = -x + 3

The velocity vector at point B is therefore perpendicular to this line, which means it has a direction given by the vector (1, -1).

Finally, we can find the acceleration vector at point B. Since the car is moving with constant speed around a circle, it is undergoing uniform circular motion, which means it is accelerating towards the center of the circle. The magnitude of the acceleration is given by:

a = v² / r

where v is the speed and r is the radius of the circle. We don't know the radius of the circle, but we can find it using the fact that point B lies on the circle. The distance from the origin to point B is:

d = √((-3 - 0)² + (0 - 3)²) = 3√(2) m

Therefore, the radius of the circle is:

r = d / 2 = (3√(2)) / 2 m

Substituting in the values for v and r, we get:

a = (6 m/s)² / ((3√(2)) / 2 m) ≈ 16.97 m/s²

To find the direction of the acceleration vector, we can use the fact that it is pointing towards the center of the circle. The center of the circle is at the origin, so the acceleration vector at point B is given by the vector (-3, 0) minus the vector (0, 3), which is:

(-3, 0) - (0, 3) = (-3, -3)

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What is the effective resistance (in Ω) of a car's starter motor when 147 A flows through it as the car battery applies 11.3 V to the motor?

Answers

Given:

The current flowing through the motor is: I = 147 A

The voltage applied to the motor is: V = 11.3 v

To find:

The effective resistance of the car's motor.

Explanation:

The relation between the voltage V, current I, and the resistance R is given by Ohm's law. The expression for Ohm's law is:

\(V=IR\)

Rearranging the above equation, we get:

\(R=\frac{V}{I}\)

Substituting the values in the above equation, we get:

\(\begin{gathered} R=\frac{11.3\text{ v}}{147\text{ A}} \\ \\ R=0.0768\text{ }\Omega \\ \\ R\approx0.077\text{ }\Omega \end{gathered}\)

Final answer:

The effective resistance of the car's motor is 0.077 Ω.

A. Organized process to test a hypothesis
B. An educated guess about the solution to a problem
C. Observations & measurements recorded
D. A summary based on the results of an experiment
E. The response that is measured in an experiment
F. The factor that is manipulated during an experiment

Answers

The scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable.

What is an observation in science?

Observation is the first step of the scientific method, which then requires to raise a question that will be answered by a testable hypothesis.

The scientific method is a series of well-established steps used to collect scientific empirical data/evidence, which allow to test a given hypothesis.

In conclusion, the scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable..

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Two boats start together and race across a 50-km-wide lake and back. Boat A goes across at 50 km/h and returns at 50 km/h. Boat B goes across at 25 km/h, and its crew, realizing how far behind it is getting, returns at 75 km/h. Turnaround times are negligible, and the boat that completes the round-trip first wins.

Required:
a. Which boat wins?
b. What is the average velocity of the winning boat?

Answers

Answer:

Boat A wins and 50km/hr

Explanation:

To solve this problem we need to calculate the time required for both boats to make the round trip.

For Boat A.

The time required for the first trip =distance/ speed = 50/50 = 1h

For the return trip the time is same since it's the same distance on the same speed.

Hence the time taken for boat A to make the round trip is 2hrs.

For boat B,

The time required for the first trip =distance/ speed = 50/25 = 2h

The time for the return trip is;

=distance/ speed = 50/75 = 2/3h= 2/3×60= 40mins

By comparing both time.

Boat A requires less time hence Boat A wins.

2.The average velocity of the winning boat is the velocity of boat A.

Which is total distance/ total time for the trip.

100km/2hrs = 50km/hr

boat A would win the race and the average velocity of the winning boat would be 50 km/h

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

As given in the problem Two boats start together and race across a 50-km-wide lake and back. Boat A goes across at 50 km/h and returns at 50 km/h. Boat B goes across at 25 km/h, and its crew, realizing how far behind it is getting, returns at 75 km/h.

Turnaround times are negligible, and the boat that completes the round-trip first wins

Average velocity of the boat A = ( 50 + 50 ) / 2

                                                              = 50 km /h

Thus, boat A would win the race and the average velocity of the winning boat would be  50 km/h

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A ball is thrown upward in the air, and its height above the ground after t seconds is H ( t ) = 63 t − 16 t 2 feet. Find the time t when the ball will be traveling upward at 15.75 feet per second.

Answers

Answer:

1.477seconds

Explanation:

The height of the stone thrown in air after t secs is expressed by the equation;

H(t) = (63t − 16t²) feet

Velocity is the change in displacement of the body with respect to time.

V(t) = d(H(t))/dt

V(t) = 63 - 32t

To get the time t when the ball will be traveling upward at 15.75 feet per second, we will substitute V(t) = 15.75 into the resulting equation as shown;

15.75 = 63 - 32t

-32t = 15.75-63

-32t = -47.25

t = 47.25/32

t = 1.477seconds

Hence the ball will be travelling upward when t is 1.477s

Which of the following did Wegener NOT explain in his theory that might have made a stronger?

A: What causes the continents to move,

B:How certain dinosaurs later evolved Into birds.

C:How the Moon causes the tides.​

Answers

The answer would probably be A

Order the following items from least inertia (bottom) to greatest inertia (top). Please Help.

Order the following items from least inertia (bottom) to greatest inertia (top). Please Help.

Answers

Answer: 3,4,1,2,5

Explanation:

After coming down a slope, a 60-kg skier is coasting northward on a level, snowy surface at a constant 15 m>s. Her 5.0-kg cat, initially running southward at 3.8 m>s, leaps into her arms, and she catches it. (a) Determine the amount of kinetic energy converted to internal energy in the Earth reference frame. (b) What is the velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat’s kinetic energy does not change?

Answers

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.

What is law of conservation of momentum?

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.

The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.

The amount of kinetic energy converted to internal energy can be calculated as follows:

m1*v1 = (m1 + m2)*vf

vf = (m1*v1)/(m1 + m2)

KE = (1/2)*m2*v2²

KE converted = KE initial - KE final

KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²

KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²

KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)

KE converted = 28.8 - 22.15

KE converted = 6.65 J

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.

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A person is drinking a glass of soda with ice.
which option describes the relative kinetic energy of molecules in and above the soda in the glass?

A. in : least energy
above : intermediate and greatest energy

B. in : greatest energy
above : least energy

C. in : least energy
above : greatest energy

D. in least and intermediate energy
above : greatest energy ​

Answers

The relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

The relative kinetic energy of gas molecules increases with increase in the mean distance between the gas molecules.

Also, relative kinetic energy of gas molecules increases with in the temperature of the gas molecules and decreases with a decrease in the temperature of the of the gas molecules;

ΔK.E ∝ T

The ice in the soda lowers the temperature of the gas molecules, thereby reducing their average speed which in turn reduces the average kinetic energy of the gas molecules in the soda.

Above the soda in the glass, the concentration of the gas molecules is less and their mean distance is greatest when compared to inside the soda. This results to an increase in the speed of the gas molecules which increases their average kinetic energy.

Thus,  the relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

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An object that floats in water weighs 20 N in air.
a. What is the weight of the object in water?
b.What is the Upthrust acting on the object in water?
c. What is the weight of the water displaced by the object?​

Answers

Answer:

a. Weight of Object in Water = 20 N

b. Up thrust = 20 N

c. Weight of Water Displaced = 20 N

Explanation:

a.

The weight of the object remains same in the water as well. Because, the same force of gravity is acting there as well. Hence,

Weight of Object in Water = 20 N

b.

Since, the object floats on the water. Therefore, according to Archimedes' principle the up thrust force acting on the object must be equal to the weight of object:

Up thrust = Weight of object

Up thrust = 20 N

c.

From Archimedes' Principle, we know that the up thrust or the Buoyant force is equal to the weight of the water displaced by the object. therefore:

Weight of Water Displaced = Up thrust

Weight of Water Displaced = 20 N

9. Which arrow or arrows indicate a process that cycles carbon from
living or nonliving organisms? Describe the process or processes
you selected. Arrow |
10. Which arrow or arrows represent reactions that demonstrate a
conservation of mass and energy? Explain your answer.

Answers

Answer:

arrow E represents cycling of carbon from living organisms to non-living organisms. this is because it is showing conversion of a carbon from the dead tree to fossil fuel.

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Darkspirit :)

To a motorist travelling due North at 50km/hr, the wind appears to come from North West at 60mk/hr. Find the true velocity of the wind.​

Answers

Answer:

The true velocity of wind will be 43.1 km/h.

Explanation:

Given that,

Velocity of motor \(\vec{v_{m}}= 50\hat{j}\ km/h\)

The resultant velocity of wind

\(\ver{v_{r}}=60\hat{i}\times\dfrac{1}{\sqrt{2}}+60\hat{j}}\times\dfrac{1}{\sqrt{2}}\)

Suppose, the true velocity of wind is \(\vec{v_{w}}\).

We need to calculate the true velocity of wind

Using formula of resultant velocity

\(\vec{v_{m}}+\vec{v_{w}}=\vec{v_{r}}\)

\(\vec{v_{w}}=\vec{v_{r}}-\vec{v_{m}}\)

Where, \(\vec{v_{m}}\) = velocity of motor

\(\vec{v_{w}}\) = velocity of wind

\(\vec{v_{r}}\) = resultant velocity

Put the value into the formula

\(\vec{v_{w}}=\dfrac{60}{\sqrt{2}}\hat{i}+(\dfrac{60}{\sqrt{2}}-50)\hat{j}\)

\(\vec{v_{w}}=42.43\hat{i}-7.57\hat{j}\)

The magnitude of true velocity is,

\(v_{m}=\sqrt{(42.43)^2+(-7.57)^2}\)

\(v_{m}=43.0.9\approx 43.1\ km/h\)

Hence,  The true velocity of wind will be 43.1 km/h.

To a motorist travelling due North at 50km/hr, the wind appears to come from North West at 60mk/hr. Find

A foot spa machine is an electronic gadget used for soaking,bathing and massaging the feet.​

Answers

Answer:

Just gonna take this at free points and yes you are right but I am confused on what you wanted us to do

A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How long until the cannonball hits the ground?
96.7 s
55.3 s
65.3 s
45.5 s

Answers

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

The chains of a swing on a playground swing set are 4.0 m
long. What is the period of this swing?
Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

2.54 seconds

Explanation:

The period of a swing on a playground swing set can be calculated using the formula:

T = 2π√(L/g)

where T is the period, L is the length of the swing's chain, and g is the acceleration due to gravity, which is approximately 9.81 m/s².

Substituting the given values, we get:

T = 2π√(4.0 m/9.81 m/s²)

T = 2π√0.407

T = 2.54 s (rounded to two significant figures)

Therefore, the period of the swing is 2.54 seconds.

Hope this helps!

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