He looks directly at the pen and can now see that it is
red. Which light-sensitive cells are being used to make
the image now?

Answer:

Light Winds

Explanation:

Hi there!

Using the equation for current:

\(I = \frac{\Delta Q}{\Delta t}\)

I = Current (A)
Q = Charge (C)
t = time (s)

Therefore, the current is equivalent to the amount of charge passing through a wire over a given time interval.

We can plug in the given values and solve.

\(I = \frac{1200}{200} = \boxed{6 A}\)

Answer:

You have to compare the densities,

Explanation:

To find density:

1. Measure the object's weight

2. Divide the mass by the volume

Answer:

Vận tốc pháp tuyến tỉ lệ với vận tốc góc nhân với bán kính r. T T T là chu kỳ, ω là vận tốc góc và f là tần số. Chu kì tỉ lệ nghịch với vận tốc góc nhân với hệ số 2 π 2 \ pi 2π và tỉ lệ nghịch với tần số.

If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.

I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.

Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.

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Answer:

105 kg*m/s

Explanation:

p=mv

momentum=mass*velocity

momentum=15kg*7m/s

momentum=105kg*m/s

Answer:

According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since Sharon's puck stops after the collision, all of its momentum is transferred to Kaylyn's puck. Therefore, the resulting momentum of Kaylyn's puck is equal to the initial momentum of Sharon's puck:

m1v1 = m2v2

where m1 and v1 are the mass and velocity of Sharon's puck before the collision, and m2 and v2 are the mass and velocity of Kaylyn's puck after the collision.

Substituting the given values:

0.3 kg × 6 m/s = 0.3 kg × v2

Simplifying:

1.8 kg m/s = 0.3 kg × v2

Dividing both sides by 0.3 kg:

v2 = 6 m/s

Therefore, the resulting velocity of Kaylyn's puck should be equal to the velocity of Sharon's puck before they collided, which is 6 m/s.

Answer: A. Equal to the velocity of Sharon's puck before they collided.

The electrostatic force of attraction between the proton and electron is 4.2 x 10⁻⁸N.

The gravitational force between the proton and electron is 1.9 x 10⁻⁴⁷N.

a) Charge on proton = charge on electron = q = 1.6 x 10⁻¹⁹C

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The electrostatic force of attraction between the proton and electron is given by,

F = 1/4πε₀(q²/r²)

F = 9 x 10⁹ x (1.6 x 10⁻¹⁹)²/(7.4 x 10⁻¹¹)²

F = 9 x 10⁹ x 2.56 x 10⁻³⁸/54.76 x 10⁻²²

F = 4.2 x 10⁻⁸N

b) Mass of the electron, m₁ = 9.1 x 10⁻³¹kg

Mass of the proton, m₂ = 1.67 x 10⁻²⁷kg

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The gravitational force between the proton and electron is given by,

F = Gm₁m₂/r²

F = 6.67 x 10⁻¹¹x 9.1 x 10⁻³¹x 1.67 x 10⁻²⁷/(7.4 x 10⁻¹¹)²

F = 1.9 x 10⁻⁴⁷N

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Answer:

Gravity only becomes noticeable when there is a really massive object like a moon, planet or star. We are pulled down towards the ground because of gravity. The gravitational force pulls in the direction towards the centre of any object.

Answer:

Explanation:

Given that:

To Calculate:

We know that:

We have:

Finding its density:

⟶ Density = 270/360

⟶ Density = 0.75

Hence,

Answer: Is it possible to produce metals that comprise the martensitic matrix when graphite is embedded in any nodule or flake form and the treatment required to produce each of these two sub-structures is as follows is:

Spheroidal graphite cast iron usually has a pear lite matrix.

However, the removal of the anneal causes the carbon in the pear lite to roll over to the existing graphite or to form other small graphite particles, leaving a ferric matrix.

This gives the metal even greater ductility.

As the name implies flake graphite has a clear or platy morphology.

All graphite has a morphology dispersed to some degree, but in most cases flake-graphite has this structure regardless of particle size.

The platy morphology of flake graphite is reflected in electron scanning and bright micro graphs.

Micro structures are the result of a variety of heat treatments depending on the degree of cooling from the Austen range; are predicted using a TTT diagram with cooling curves at the top of the selected object.  

Explanation:

Answer:

11 km

Explanation:

Given that,

A car travel 4 km east and 7 km west. We need to find the distance traveled by the car from the initial point. We know that the overall path covered is called distance. So,

distance = total path covered

D = 4 km + 7 km

D = 11 km

So, the distance of the car from the initial point is 11 km.

Answer:

5941m/s

Explanation:

velocity equals frequency x lamdha

Answer:

the focal length of the eyepiece is 17.23 cm

Explanation:

The computation of the focal length of the eyepiece is shown below:

= Focal length of objective lens ÷ angular magnification magnitude

= 86.3 ÷ -5.01

= 17.23 cm

Hence, the focal length of the eyepiece is 17.23 cm

We simply divided the angular magnification magnitude from the focal length of objective lens so that the focal length of the eyepiece could come

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

The number of turns determines the strength; whether the core is made of soft or hard magnetic material. Soft iron is more easily magnetized than steel. As a result, using a soft core increases the electromagnet's strength.

The magnetic field is mathematically described as a vector field. This vector field can be directly plotted as a grid of many vectors. Each vector points in the same direction as a compass and has a length proportional to the strength of the magnetic force. This technique is demonstrated by arranging many small compasses in a grid pattern and placing the grid in a magnetic field. The only difference is that a compass does not indicate field strength. Field lines are another way to represent the information contained within a vector field. We remove the grid pattern and connect the vectors with smooth lines. We are free to draw as many lines as we want.

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The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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Answer:

Net force: 20 N to the right

mass of the bag: 20.489 kg

acceleration:  0.976  m/s^2

Explanation:

Since the normal force and the weight are equal in magnitude but opposite in direction, they add up to zero in the vertical direction. In the horizontal direction, the 195 N tension to the right minus the 175 force of friction to the left render a net force towards the right of magnitude:

195 N - 175 N = 20 N

So net force on the bag is 20 N to the right.

The mass of the bag can be found using the value of the weight force: 201 N:

mass = Weight/g = 201 / 9.81 = 20.489 kg

and the acceleration of the bag can be found as the net force divided by the mass we just found:

acceleration = 20 N / 20.489 kg = 0.976  m/s^2

Answer:

a. 0.342 kg-m² b. 2.0728 kg-m²

Explanation:

a. Since the skater is assumed to be a cylinder, the moment of inertia of a cylinder is I = 1/2MR² where M = mass of cylinder and r = radius of cylinder. Now, here, M = 56.5 kg and r = 0.11 m

I = 1/2MR²

= 1/2 × 56.5 kg × (0.11 m)²

= 0.342 kgm²

So the moment of inertia of the skater is

b. Let the moment of inertia of each arm be I'. So the moment of inertia of each arm relative to the axis through the center of mass is (since they are long rods)

I' = 1/12ml² + mh² where m = mass of arm = 0.05M, l = length of arm = 0.875 m and h = distance of center of mass of the arm from the center of mass of the cylindrical body = R/2 + l/2 = (R + l)/2 = (0.11 m + 0.875 m)/2 = 0.985 m/2 = 0.4925 m

I' = 1/12 × 0.05 × 56.5 kg × (0.875 m)² + 0.05 × 56.5 kg × (0.4925 m)²

= 0.1802 kg-m² + 0.6852 kg-m²

= 0.8654 kg-m²

The total moment of inertia from both arms is thus I'' = 2I' = 1.7308 kg-m².

So, the moment of inertia of the skater with the arms extended is thus I₀ = I + I'' = 0.342 kg-m² + 1.7308 kg-m² = 2.0728 kg-m²

a) The moment of inertia as the skater pulled his/her arm inward by assuming he/she is a cylinder is 0.3418kg-m².

b) If the body of the skater is assumed to be a cylinder of the same size, and the arms are rods extending straight out from his/her body being rotated at the ends, the moment of inertia is 1.7495kg-m².

Given the data in the question;

Mass of skater; \(M = 56.5kg\)

a)

When the skater has his arms pulled inward by assuming they are cylinder of radius; \(R = 0.11 m\)

Moment of inertia; \(I = \ ?\)

From Parallel axis theorem; Moment of Inertia for a cylindrical body is expressed:

\(I = \frac{1}{2}MR^2\)

Where M is the mass and R is the radius

We substitute our given values into the equation

\(I = \frac{1}{2}\ *\ 56.5kg\ *\ (0.11m)^2\\\\I = \frac{1}{2}\ *\ 56.5kg\ *\ 0.0121m^2\\\\I = 0.3418kg.m^2\)

Therefore, the moment of inertia as the skater pulled his/her arm inward by assuming he/she is a cylinder is 0.3418kg-m²

b)

With the skater's arms extended by assuming that each arm is 5% of the mass of their body

Mass of each arm; \(M_a = \frac{5}{100} * M = \frac{5}{100} * 56.5kg = 2.825kg\)

Remaining mass; \(M_b = M - 2M_a = 56.5kg - 2(2.825kg) = 50.85kg\)

Assume the body is a cylinder of the same size and the arms are 0.875 m long rods extending straight out from their body being rotated at the ends.

Length of arm; \(L = 0.875 m\)

From Parallel axis theorem; Moment of Inertia about vertical axis is expressed as:

\(I = \frac{1}{2}M_bR^2 + \frac{2}{3}M_aL^2\)

We substitute in our values

\(I = \frac{1}{2}*50.85kg*(0.11m)^2 + \frac{2}{3}*2.825kg*(0.875m)^2\\\\I = [\frac{1}{2}*50.85kg * 0.0121m^2] + [\frac{2}{3}*2.825kg*0.765625m^2]\\\\I = 0.3076kg.m^2 + 1.4419kg.m^2\\\\I = 1.7495kg.m^2\)

Therefore, if the body of the skater is assumed to be a cylinder of the same size, and the arms are rods extending straight out from his/her body being rotated at the ends, the moment of inertia is 1.7495kg-m².

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Answer:

Explanation:

Males measuring;

161 - 165 = 2

166 - 170 = 1

171 - 175 = 7

176 - 180 = 1

181 - 185 = 6

186 - 190 = 3

Males taller than 175 cm = 1 + 6 + 3 = 10

Total number of Males = 2 + 1 + 7 + 1 + 6 + 3  = 20

Percentage of total over 175 cm

= 10 / 20

= 50%

The rotational kinetic energy = 7909.73 Joules

The mass of the motorcycle, m = 9kg

The angular velocity, w = 137 rad/s

Inner radius, r = 0.280 m

Outer radius, R = 0.330 m

The rotational kinetic energy is calculated as:

Substitute m = 9, r = 0.280, R = 0.330, and w = 137 rad/s into the formula above

Answer:

0.065 seconds

Explanation:

i) Change in momentum is equal to impulse so, m(v-u) = ft  (Where f is force and t is time)

ii) Since we know the mass of the ball, we change grams to the SI unit of kilograms, kg so 0.057kg

iii) We are also told that the ball CHANGES direction, so we know that the new velocity is the negative value of the initial one,

iv) Putting this all together we get 0.057(25--15) which is the same as 0.057(25 + 15)

v) We get an impulse of 2.28 Ns

vi) We take this value and divide it by 35 as we want the Force alone and not the time,

vii) To which we get 0.065 seconds,

Hope this was helpful!!

Answer:

A syncline is visible.

Explanation:

A syncline is visible.

Answer:

These mountains show no evidence of folding.

Answer:

lunch box, cotton, toilet paper, and the foam peanuts

Explanation:

bc I did this experiment in 3rd grade =w="

Hope this helped! Have a nice day!

Please give brainliest when possible!

:3

Answer:

a camera employs camera lens to firm some images.

Explanation:

hope this helps.

The statement that what matters in an experiment is asking the right questions and not necessarily finding the right answer potryas the importance of the scientific process and inquiry-based approach.

The aim of scientific study is to learn about and comprehend the natural world. This is accomplished through developing hypotheses, posing questions, carrying out experiments, and evaluating the outcomes. While getting the right response is critical, it's just as important to ask the right questions in the first place.

Asking the right questions helps to define the scope and objectives of the experiment and also  guides the researcher to focus on specific variables, design appropriate experiments, and gather relevant data.

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