g(n) = 2n^2 - 4; Find g(-2)

Answer

.03125

................................

Writing linear equations given two points can be a useful skill when graphing linear equations.

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Step-by-step explanation:

my instagram account bdq.frk follow please

Given the table:

t B

1 22.5

3 13.5

5.5 2.25

Where B represents the charge remaining in Peyton's battery.

And t represents the number of hours since Peyton left her house.

Let's determine the number of hours it would take until the phine's battery level get down to 24.75%.

First of all, let's create a linear equation that is represented on the table.

Apply the slope intercept form of a linear equation:

y = mx + b

Where m is the slope.

To find the slope apply the slope formula:

Take two points on the table:

(x1, y1) ==> (1, 22.5)

(x2, y2) ==> (3, 13.5)

Thus, we have:

To solve for b, susbtitute -4.5 for m, and input one of the points for the values of x and y:

Therefore, the equation that represents this situation is:

y = -4.5x + 27

To find the number of hours it would take until the phone's battery level got down to 24.75%, substitute 24.75 for y in the equation and solve for x.

y = -4.5x + 27

24.75 = -4.5x + 27

Subtract 27 from both sides:

24.75 - 27 = -4.5x + 27 - 27

-2.25 = -4.5x

Divide both sides by -4.5:

Therefore, it would take 0.5 hour for the phone's battery level to get down to 24.75%.

ANSWER:

0.5

Answer:

753.98224

Step-by-step explanation:

v=pie r^2 h/3=piex6^2x20/3=753.98224

Answer:

<a = 90°   (180-90 supplementary angle)

<b = 90°   (180-90 supplementary angle)

<d = 48°   (180-132 supplementary angle)

<e = 132°  (opposite angle)

<c = 42°     (interior angles of a triangle equal 180.  180-48-90=42)

Step-by-step explanation:

<a = 90°   (180-90 supplementary angle)

<b = 90°   (180-90 supplementary angle)

<d = 48°   (180-132 supplementary angle)

<e = 132°  (opposite angle)

<c = 42°     (interior angles of a triangle equal 180.  180-48-90=42)

The value of k in the point (5, k) which lies on the line represented by the equation, 2x + y = 9 is: k = -1.

A point lies on a line if the values of the coordinates makes an equation true when substituted into it.

Thus, we are given a point, (5, k), which lies on the line that has the equation, 2x + y = 9, to find the value of k, substitute x = 5 and y = k into the equation:

2(5) + k = 9

10 + k = 9

Subtract 10 from both sides:

10 + k - 10 = 9 - 10

k = -1

The value of k is: -1.

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Answer:

The distance between them is 105.07 km

Step-by-step explanation:

First we need to find the distance travelled by each ship.

To find this distance, we should use the formula:

distance = speed * time

For ship A, we have:

distance1 = 30 * 3 = 90 km

For ship B, we have:

distance2 = 37 * 3 = 111 km

Now, to find the distance between the ships, we can use the law of cosines, where a, b and c are the respectively the distance travelled by ship A, the distance travelled by ship B and the distance between them:

c^2 = a^2 + b^2 - 2*a*b*cos(62)

c^2 = 90^2 + 111^2 - 2*90*111*0.4695

c^2 = 11040.39

c = 105.07 km

The distance between them is 105.07 km

Step-by-step explanation:

5n-2

5(4) - 2

20-2=18

A= 18

5n - 2 =48

5n=48+2

5n=50

divide by 5

n= 10

B=10

The probability that at most a fifth of the buyers would prefer green is approximately 0.0198

This problem can be solved by using the binomial distribution. Let X be the number of buyers out of 15 who prefer green. Then X follows a binomial distribution with parameters n = 15 and p = 0.6.

We want to find the probability that at most a fifth of the buyers would prefer green. This means we want to find P(X ≤ 3), since a fifth of 15 is 3.

Using the binomial probability formula, we have

P(X ≤ 3) = Σ P(X = k) for k = 0 to 3

= P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= (15 choose 0) (0.6)⁰ (0.4)¹⁵ + (15 choose 1) (0.6)¹(0.4)¹⁴ + (15 choose 2) (0.6)² (0.4)¹³ + (15 choose 3) (0.6)³ (0.4)¹²

= 0.0000265 + 0.000397 + 0.00312 + 0.0163

Add the number

= 0.0198

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The triple integral ∫∫∫ex^2 y^2 dv in cylindrical coordinates evaluates to ∫ from 0 to 1, ∫ from 0 to 2π, and ∫ from 0 to (1-9r^2) e^r^2cos^2θsinr drdθdz.

In cylindrical coordinates, the given solid e is represented by the inequality 0 ≤ z ≤ 1-9r^2. Therefore, the limits of integration for z are 0 to 1-9r^2. The circular base of the solid is given by x^2 + y^2 ≤ 1/(9z), which can be rewritten as r^2 ≤ 1/(9z).

Thus, the limits of integration for r are 0 to √(1/(9z)). The angle θ ranges from 0 to 2π. Hence, the triple integral can be expressed as ∫ from 0 to 1, ∫ from 0 to 2π, and ∫ from 0 to √(1-9r^2) e^r^2cos^2θsinr drdθdz. Solving this integral yields the required answer.

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We can be 90% confident that the true population mean level of anxiety today falls within this interval.

a. To determine whether there has been a significant change in the average level of anxiety since the 1950s, we need to conduct a two-tailed hypothesis test.

Null hypothesis: The average level of anxiety is the same today as it was in the 1950s (μ = 15.1).

Alternative hypothesis: The average level of anxiety today is significantly different from what it was in the 1950s (μ ≠ 15.1).

The sample size is n = 16, and the sample mean and SS are M = 23.3 and SS = 240, respectively. We can start by calculating the sample variance:

s^2 = SS / (n - 1) = 240 / 15 = 16

Then, we can calculate the t-statistic:

t = (M - μ) / (s / sqrt(n)) = (23.3 - 15.1) / (4 / sqrt(16)) = 4.5

Using a two-tailed t-test with α = .01 and df = n - 1 = 15, the critical t-values are ±2.947. Since our calculated t-value of 4.5 falls outside of the critical region, we reject the null hypothesis and conclude that there is a significant difference in the average level of anxiety today compared to the 1950s.

b. To construct a 90% confidence interval estimate of today's population mean level of anxiety, we can use the following formula:

CI = M ± t_(α/2,df) * (s / sqrt(n))

where t_(α/2,df) is the critical t-value for a two-tailed test with α = .10 and df = 15, which can be found using a t-distribution table or a calculator. From above, we already know that s = 4 and n = 16. Therefore, the confidence interval is:

CI = 23.3 ± 1.753 * (4 / sqrt(16)) = (20.74, 25.86)

We can be 90% confident that the true population mean level of anxiety today falls within this interval.

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Therefore, the yearly fund that the orphanage will be receiving in perpetuity is Php 82,776.01 (rounded off to two decimal places).

Given that the principal amount deposited by Diego = Php 1,000,000, the interest rate = 20% compounded annually and the period for which the fund is given to the orphanage in perpetuity is one year after five years.

In order to determine the yearly fund the orphanage will be receiving, we need to calculate the amount that will be accumulated after five years on the principal amount using the formula for the future value of a single payment: FV = PV(1 + i)^n Where, FV = future valuePV = present valuei = annual interest raten = time periodSo, substituting the values in the formula we get: FV = 1,000,000(1 + 0.2)^5= 1,000,000(1.2)^5= 1,000,000(2.48832)= Php 2,488,320 So, the amount that will be accumulated after five years on the principal amount is Php 2,488,320.

Now, we need to calculate the yearly fund that the orphanage will be receiving in perpetuity using the formula for the present value of an annuity:PVA = A((1 - (1 + i)^-n)/i)

Where,PVA = present value of an annuityA = annuityi = annual interest raten = time periodSo, substituting the values in the formula we get:2,488,320 = A((1 - (1 + 0.2)^-1)/0.2)Multiplying both sides of the equation by 0.2, we get:497,664 = A(1 - (1.2)^-1)Multiplying both sides of the equation by (1 - (1.2)^-1), we get:497,664(1 - (1.2)^-1) = AA = 497,664(1 - 1/1.2)= 497,664(1 - 0.8333)= Php 82,776.01.

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Answer:

Neither

Step-by-step explanation:

-12x + 3y = 3

y = 4x + 1

y = mx + b

The second equation given is set up in the correct form already (y = 4x + 1)

We have to convert the first equation into the same format

-12x + 3y = 3

Isolate the y

3y = 3 + 12x

Divide the 3 from the y and the other side

y = 1 + 4x

y = 4x + 1

This is the same as the first equation

They can only be parallel if their slope (m or 4 in this case) is the same and their y-intercepts (b or 1 in this case) are different. Since the equations are the exact same and do not fit the y-intercept criteria for parallel, they cannot be parallel. If they were perpendicular, their lines must cross. This means they have to contain reciprocals or opposite slopes. Our slope here for both of them is 4 or 4/1. Since neither are the opposite (which would be 1/4), it is not perpendicular. Therefore, the answer is neither

The determinant of A is 1.

The plural version of the word matrix is a matrix, which refers to the arrangements of numbers, variables, symbols, or phrases in a rectangular table with varying numbers of rows and columns. These arrays have a rectangular shape, and several operations like addition, multiplication, and transposition are specified for them.

The components of the matrix are referred to as its entries or numbers. Vertical and horizontal entries in matrices are referred to as columns and rows, respectively.

A matrix with m rows and n columns will contain m n entries. The uppercase letter 'A', which here stands for "matrix," Aij.

We can compute the determinant of the 2x2 matrix A =

| 1 0 |

| 1 1 |

by expanding along the first column since it involves the least amount of computation:

| 1 0 |

| 1 1 |

det(A) = 1 * |1 1| - 0 * |1 1|

= 1

So, the determinant of A is 1.

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Complete question:

Compute the determinant by cofactor expansion. At each? step, choose a row or column that involves the least amount of computation.

The correct alternative hypothesis for the Wilcoxon rank sum test is: ha: one distribution is shifted in a location higher or lower than the other. Option C is the answer.

This means that the test is designed to determine if there is a significant difference between the medians of two independent groups, rather than testing for a difference in means.

The null hypothesis for the test is that there is no significant difference between the two groups, while the alternative hypothesis states that there is a significant difference.

The Wilcoxon rank sum test is a nonparametric test and is used when the assumptions of the t-test are not met, such as non-normality or unequal variances.

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The best estimate for the total amount of time Tim would spend answering e-mails over the course of 100 days is 100 hours with a standard deviation of 0.53 hours.

To find the total amount of time Tim would spend answering emails over the course of 100 days, we need to use the concept of the Central Limit Theorem. According to the theorem, the sum of a large number of independent and identically distributed random variables approaches a normal distribution regardless of the underlying distribution.

To calculate the standard deviation of the total amount of time Tim spends answering emails over 100 days, we can use the formula:

standard deviation = square root of (n * variance)

where n is the number of days and variance is the variance of the amount of time Tim spends in a day answering emails.

Substituting the values, we get:

standard deviation = square root of (100 * 0.0028) = 0.53 hours

Therefore, Tim would spend an average of 100 hours over the span of 100 days responding to emails, with a standard deviation of 0.53 hours, according to the best estimate.

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Answer:

68 inches

Step-by-step explanation:

16+16+18+18

To put along the outside edge of the 18 inches wide and 16 inches tall board, 68 inches of ribbon is required. The length of the ribbon required is the same as the perimeter of the classroom board.

A perimeter of a rectangle is double the sum of the breadth and length of that rectangle.

It is given that the width of the classroom board is 18 inches and its height is 16 inches.

The shape of the board is a rectangle.

Therefore, it can be assumed that a rectangle with a length of 16 inches and a width of 18 inches is given.

K wants to put the ribbon along the outside edge of the board. To find the inches of ribbon required for the task, it is sufficient to find the perimeter of the board.

The perimeter of the boards can be calculated as follows:

Perimeter = 2 × (length + width)

                 = 2 × (16 + 18)

                 = 2 × 34

                 = 68 inches

Hence, 68 inches of ribbon is required to be put along the outside edge of the board.

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The value of the exponent (2/5)^3 is \(\frac{8}{125}\)

In the above question, it is given that

(2/5)^3

The number of times a number has been multiplied by itself is referred to as an exponent. For instance, the expression 2 to the third (written as 2^3) signifies 2 x 2 x 2 = 8.

We need to solve it and then find the value of the exponent

(2/5)^3

= \(\frac{2}{5}\) x \(\frac{2}{5}\) x \(\frac{2}{5}\)

= \(\frac{2 . 2. 2}{5 . 5 . 5}\)

= \(\frac{8}{125}\)

Therefore the value of the exponent (2/5)^3 is \(\frac{8}{125}\)

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The sampling method described below appears to be flawed because it is a voluntary response sample.

Survey sampling, as used in statistics, is the process of choosing a sample of constituents from a target population to perform a survey. The word "survey" can be used to describe a wide range of observational methods or procedures. Most frequently, a questionnaire meant to assess people's traits and/or opinions is employed in survey sampling. The topic of survey data collecting is various methods of contacting sample participants after they have been chosen. Sampling is done to cut down on the expense and/or labor required to survey the complete target population.

Voluntary response sample: The researcher asks members of a population to participate; participants can choose whether or not to participate.

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Answer:

\(\displaystyle r = 7\)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Geometry

Volume of a Cone Formula: \(\displaystyle V = \frac{\pi}{3} r^2h\)

Step-by-step explanation:

Step 1: Define

Identify variables

V = 294π

h = 18

Step 2: Solve for r

Answer:

\( r = 17.5 \)

Step-by-step explanation:

Given ∆TRS,

Where,

m < R = 105°

TR = s = 15

RS = t = 6

ST = r = ?

Find r using the Law of Cosines.

\( r^2 = s^2 + t^2 - 2*s*t*cos(R) \)

Plug in the values stated above into the formula

\( r^2 = 15^2 + 6^2 - 2*15*6*cos(105) \)

\( r^2 = 225 + 36 - 180*(-0.2588)\)

\( r^2 = 261 + 46.584 \)

\( r^2 = 307.584 \)

\( r = \sqrt{307.584} \)

\( r = 17.5 \) (to the nearest tenth)

The correct statement regarding least-squares estimated residuals is:

O Some are positive and some are negative.

The residuals in a regression model represent the differences between the observed values and the predicted values. They are calculated by subtracting the predicted values from the actual values. These residuals can be positive or negative, depending on whether the observed values are greater or smaller than the predicted values.

Additionally, the other statements are incorrect:

The residuals are not set to zero as part of the regression estimation. The goal of least-squares regression is to minimize the sum of the squared residuals, but the residuals themselves are not set to zero.

Least squares is a technique that fits a line to minimize the sum of the squared residuals, not the sum of the residuals themselves. The squared residuals are minimized to ensure that both positive and negative residuals contribute to the overall fit of the model.

The size of the residuals alone does not indicate the quality or goodness of the model. While it is important to analyze and interpret the residuals, large residuals do not necessarily indicate a good model. Other diagnostic measures, such as residual plots and statistical tests, are typically used to assess the quality of a regression model.

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If 1 book cost $7, 3 books will cost: 3*$7 = $21. (Multiplying)

The answer is $21.

Answer:

3.75

hope this helps, lmk if u need an explanation on how that's the answer

Answer: 3.75

15/4, although this is a fraction, it is also division..

Answer:

I need the other expressions :l

Step-by-step explanation:

:l

To decide whether it is sensible for Stacy to utilize the ordinary show for the inspecting conveyance of the test extent, we got to check whether the conditions for utilizing the typical conveyance estimation are met. The conditions are:

The test estimate is expansive sufficient

The test information is autonomous

The populace is at slightest 10 times bigger than the test

The test estimate, in this case, is 50. To check whether it is expansive sufficient, ready to utilize the run the show of thumb that the test measure ought to be at the slightest 10% of the populace estimate.

Hence, based on these conditions, it is sensible for Stacy to utilize the ordinary demonstration for the inspecting conveyance of the test extent. She can accept that the testing dispersion is roughly typical with a cruel of p = 0.11 and a standard deviation of sqrt[(p(1-p))/n] = sqrt[(0.11(0.89))/50] = 0.05.

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The future values are:

a) $4,046.63

b) $4,838.96

c) $2,818.75

d) $4,555.30

To calculate the future value using continuous compounding, we can use the formula:

\(Future Value = Principal * e^(rate * time)\)

Where:

- Principal is the initial amount

- Rate is the annual interest rate

- Time is the number of years

- e is the mathematical constant approximately equal to 2.71828

Let's calculate the future values for each scenario:

a) 6 years at a stated annual interest rate of 8 percent:

Principal = $2,500

Rate = 0.08

Time = 6

\(Future Value = 2500 * e^(0.08 * 6)Future Value = 2500 * e^0.48Future Value ≈ 2500 * 1.61865Future Value ≈ $4,046.63\)

b) 6 years at a stated annual interest rate of 11 percent:

Principal = $2,500

Rate = 0.11

Time = 6

\(Future Value = 2500 * e^(0.11 * 6)Future Value = 2500 * e^0.66Future Value ≈ 2500 * 1.93558Future Value ≈ $4,838.96\)

c) 2 years at a stated annual interest rate of 6 percent:

Principal = $2,500

Rate = 0.06

Time = 2

\(Future Value = 2500 * e^(0.06 * 2)Future Value = 2500 * e^0.12Future Value ≈ 2500 * 1.12750Future Value ≈ $2,818.75\)

d) 6 years at a stated annual interest rate of 10 percent:

Principal = $2,500

Rate = 0.10

Time = 6

\(Future Value = 2500 * e^(0.10 * 6)Future Value = 2500 * e^0.60Future Value ≈ 2500 * 1.82212Future Value ≈ $4,555.30\)

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