(a) The frequency of the wave is approximately 6.9767 x 10⁷ Hz. (b) The angular frequency of the wave is approximately 4.387 x 10⁸ rad/s. (c) The angular wave number of the wave is approximately 1.46 rad/m. (d) The amplitude of the magnetic field component is approximately 1.13 x 10⁻⁶ Tesla.
(a) To find the frequency of the wave, we can use the formula:
frequency (f) = speed of light (c) / wavelength (λ)
Given that the wave travels in a vacuum, the speed of light is approximately 3 x 10⁸ m/s. Plugging in the values, we get:
f = (3 x 10⁸m/s) / (4.3 m) = 6.9767 x 10⁷ Hz
Therefore, the frequency of the wave is approximately 6.9767 x 10⁷ Hz.
(b) The angular frequency (ω) is related to the frequency by the equation:
angular frequency (ω) = 2π x frequency (f)
Substituting the value of the frequency, we have:
ω = 2π x (6.9767 x 10⁷ Hz) ≈ 4.387 x 10⁸ rad/s
Thus, the angular frequency of the wave is approximately 4.387 x 10⁸ rad/s.
(c) The angular wave number (k) is given by the equation:
angular wave number (k) = 2π / wavelength (λ)
Substituting the value of the wavelength, we have:
k = 2π / (4.3 m) ≈ 1.46 rad/m
Hence, the angular wave number of the wave is approximately 1.46 rad/m.
(d) The amplitude of the magnetic field component (B) is related to the amplitude of the electric field component (E) by the equation:
B = E / c
Substituting the given values, we have:
B = (340 V/m) / (3 x 10⁸ m/s) ≈ 1.13 x 10⁻⁶ T
Therefore, the amplitude of the magnetic field component is approximately 1.13 x 10⁻⁶ Tesla.
(e) The magnetic field oscillates perpendicular to both the electric field and the direction of wave propagation. In this case, the magnetic field oscillates in the positive direction of the z-axis.
(f) The time-averaged rate of energy flow associated with the wave, also known as the intensity (I), is given by the equation:
I = (1/2) ε₀ c E²
where ε₀ is the vacuum permittivity and c is the speed of light.
Substituting the given values, we have:
I = (1/2) x (8.85 x 10⁻¹² F/m) x (3 x 10⁸ m/s) x (340 V/m)² = 2.37 x 10³W/m²
Therefore, the time-averaged rate of energy flow (intensity) associated with this wave is approximately 2.37 x 10³ Watts per square meter.
(g) If the surface totally absorbs the wave, the rate at which momentum is transferred to the surface is equal to the intensity divided by the speed of light:
Rate of momentum transfer = I / c = 2.37 x 10³ W/m² / (3 x 10⁸ m/s) ≈ 7.89 x 10⁻⁶ N/m²
Therefore, the rate at which momentum is transferred to the surface is approximately 7.89 x 10⁻⁶ Newtons per square meter.
(h) The radiation pressure on the surface is given by the equation:
Pressure = I / c
Substituting the given values, we have:
Pressure = (2.37 x 10³ W/m²) / (3 x 10⁸ m/s) ≈ 7.89 x 10⁻⁶ Pa
Therefore, the radiation pressure on the surface is approximately 7.89 x 10⁻⁶ Pascals.
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the installation of glass, or the transparent material in a glazed opening
The installation of glass refers to the process of fitting transparent material into a glazed opening. This involves placing the glass securely within a frame or structure, ensuring a proper fit and seal.
Glass installation may include various types of windows, doors, skylights, or other architectural features that require transparent panels. It requires precision and expertise to ensure the glass is correctly positioned, aligned, and adequately sealed to provide insulation, weatherproofing, and security. Glass installation is essential for allowing natural light to enter a space while maintaining visibility and protecting against external elements. Glass installation involves fitting transparent material into a glazed opening, such as windows or doors. It requires precise positioning and sealing to ensure proper insulation, weatherproofing, and security. This process allows natural light to enter while maintaining visibility and protecting against external elements.
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Which scientist described an atom made of a solid positively charged substance with electrons dispersed throughout it?.
The scientist that described an atom made a solid positively charged substance with electrons dispersed throughout it was: Ernest Rutherford.
In 1911 Ernest Rutherford proposed his atomic model in which he considered the atom as a positively, densely charged center called a nucleus in which the electrons circulate around the core with a negative charge.
He was responsible for many discoveries in the radioactivity's fields and nuclear physics.
What is an atom?The atom is the smallest part of the composition of matter, it is indivisible and is composed of a nucleus that has protons and neutrons, and around the nucleus there are the electrons.
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sphere A is charged positively where sphere B is neutral.the sphere are brought near to each other
A) there is no electric force between the sphere
B) there is repulsive electrostatic force between the sphere
C)there is an attractive electrostatic force between the sphere
D)there is repulsive electrostatic force applied only on sphere B
D)there is repulsive electrostatic force applied only on sphere B
Explain the operation of a simple circuit made of logic gates
and design the following combinational circuit.
Answer:
A combinational logic circuit is a circuit whose outputs only depend on the current state of its inputs. In mathematical terms, the each output is a function of the inputs. These functions can be described using logic expressions, but is most often (at least initially) using truth tables.
An AM radio station's antenna is constructed to be λ4 tall, where λ is the wavelength of the radio waves.How tall should the antenna be for a station broadcasting at a frequency of 820 kHz ?
The antenna should be approximately 91.46 meters tall for a station broadcasting at a frequency of 820 kHz
To determine the height of an antenna that is λ/4 tall for a station broadcasting at a frequency of 820 kHz, you will first need to find the wavelength of the radio waves.
Step 1: Convert the frequency to Hz.
Frequency = 820 kHz = 820,000 Hz
Step 2: Use the formula for the speed of light (c) to find the wavelength (λ).
c = λ * frequency, where c is the speed of light (approximately 3 x 10^8 m/s).
Step 3: Rearrange the formula to solve for λ.
λ = c / frequency
Step 4: Calculate the wavelength.
λ = (3 x 10^8 m/s) / (820,000 Hz) ≈ 365.85 meters
Step 5: Find the antenna height.
Antenna height = λ/4 = 365.85 meters / 4 ≈ 91.46 meters
The antenna should be approximately 91.46 meters tall for a station broadcasting at a frequency of 820 kHz.
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which statement about electromagnetic waves is true?
A: They move slowly.
B: They carry matter from one place to another.
C: They need a medium to travel through.
D: They can travel through a vacuum
**Physical Science
Answer:
B
Good luck! Have a great day!
relationship definition
If two bodies weighing 10 kg and 20 kg respectively are standing at the
same point above the ground, which one of them has greater potential
energy?
i want step by step explanation
Answer:
potential energy = mgh , where m is mass of body , g is acceleration due to gravity and h is given height
since both of the body are at same height above the ground , so the body having greater mass will have more potential energy
that is 20 kg body will have higher P.E
Explanation:
Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.
By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.
Euler's method is defined as a numerical technique which is used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.
In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.
Step 1:
We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].
Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:
Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25
Step 2:
Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:
Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125
Thus, by using Euler's method with two steps, the approximate value of Y(2) is 2.125.
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The complete question is
Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3
When cell a sends a message to
cell b, ? occurs at cell
b.
a. osmosis
b. active transport
c. synaptic transmission
Answer:
c. Synaptic transmission
Explanation:
To transmit impulses/electronic signals around the body, nerve cells transfer messages across the synapse and the movement of the chemicals from one cell to the other is known as either diffusion or synaptic transmission.
You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when it reaches the bottom
Explanation:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 0.75 m)
v = 3.83 m/s
Can someone help me with these? Thanks!
Solve the following vector problems
8. A ship's maximum speed is 22km/hr to the South, What is its speed if there is also a current of 3km/hr to the South?
9. A ship's maximum speed is 22km/hr to the South, What is its speed if there is also a current of 3km/hr to the North?
10. What is your displacement if you travel 50m to the right, and then return 20 meters to the left?
11. What is your displacement if you drive 2 km North, then 4 km East, then 2 km South, and finally 4 km West?
The ship's speed relative to the ground is 25 km/hr to the South.
The displacement is zero, which means that the final position is the same as the initial position. The movements to the North and South cancel out, and the movements to the East and West cancel out.
What is velocity?Velocity is a vector quantity that describes the rate at which an object's position changes over time.In other words, velocity is an object's speed in a specific direction. The velocity of an object is typically represented by a vector, which has both magnitude (the speed of the object) and direction.
The ship's speed relative to the water is 22 km/hr to the South. If there is a current of 3 km/hr to the South, the ship's speed relative to the ground is the vector sum of its speed relative to the water and the velocity of the current. Since the two velocities are in the same direction, we can simply add them to get:
velocity relative to the ground = 22 km/hr to the South + 3 km/hr to the South = 25 km/hr to the South.
Therefore, the ship's speed relative to the ground is 25 km/hr to the South.
Similar to the previous problem, the ship's speed relative to the ground is the vector sum of its speed relative to the water and the velocity of the current. However, this time the current is going in the opposite direction, so we need to subtract the velocity of the current from the ship's speed relative to the water:
velocity relative to the ground = 22 km/hr to the South - 3 km/hr to the North = 22 km/hr to the South + 3 km/hr to the South = 25 km/hr to the South.
Therefore, the ship's speed relative to the ground is 25 km/hr to the South.
The displacement is characterized by the difference between the final and initial positions. In this case, the initial position and the final position are the same, so the displacement is zero. We can represent the two movements using vectors:
50 m to the right = +50 m i
20 m to the left = -20 m i
The displacement vector is the vector sum of these two vectors:
displacement = +50 m i - 20 m i = +30 m i
Since the x-component of the displacement vector is positive, the displacement is to the right.
We can represent the four movements using vectors:
2 km North = +2 km j
4 km East = +4 km i
2 km South = -2 km j
4 km West = -4 km i
The displacement vector is the vector sum of these four vectors:
displacement = +2 km j + 4 km i - 2 km j - 4 km i = 0 km i + 0 km j
Therefore, the displacement is zero, which means that the final position is the same as the initial position. The movements to the North and South cancel out, and the movements to the East and West cancel out.
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How are period and frequency related to each other?
A. Period is half the frequency
B. Period is twice the frequency
C. Period is equal to frequency
D. Period is the reciprocal of frequency
E. Period is the day root of frequency
Answer:
D
Explanation:
this is because the formula for frequency is
f = 1/T
and it is a reciprocal
you can chew through very tough objects with your incisors because they exert a large force on the small area of a pointed tooth. what pressure in pa can you create by exerting a force of 390 n with your tooth on an area of 1.14 mm2?
By exerting a force of 390 N with your tooth on an area of 1.14 mm^2, you can create a pressure of 3.42x10^8 Pa. This high pressure allows you to chew through very tough objects with your incisors.
To calculate the pressure exerted by your incisor on the tough object, we can use the formula: pressure = force/area.
Given that the force exerted by your tooth is 390 N, and the area of the pointed tooth is 1.14 mm^2, we can plug these values into the formula to get:
pressure = 390 N / 1.14 mm^2
However, we need to convert the area from mm^2 to m^2 to get the answer in Pascal (Pa), which is the SI unit of pressure.
1 mm^2 = 1x10^-6 m^2
So, the pressure exerted by your tooth on the tough object is:
pressure = 390 N / (1.14x10^-6 m^2)
pressure = 3.42x10^8 Pa
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Two 1-kg objects, C and D, increase in temperature by the same amount, but the
thermal energy transfer of object C is greater than the thermal energy transfer of
object D. If object C has a specific heat of 235 J/kg-K, which material might object
D be made of?
(A) aluminum
(B) brass
(C) iron
(D) lead
The object D is made up of material Lead. The correct option is D.
What is specific heat?The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.
Two 1-kg objects, C and D, increase in temperature by the same amount, but the thermal energy transfer of object C is greater than the thermal energy transfer of object D. The object C has a specific heat of 235 J/kg-K.
Q = m C ΔT
Qc > Qd
The energy transfer is proportional to specific heat.
Specific heat of D must be less. The possible material with specific heat less than the given value is for Lead material.
Thus, the correct option is D.
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How to integrate 1/ 1 + x2
The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.
Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.
Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:
∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du
The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.
Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.
Let us work through the steps:
Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x
Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du
Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.
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Robert hook used an early microscope to observed a cork sample. How did this help contribute to cell theory?
Answer:
Robert Hooke used an early microscope to observe a cork sample. How did this help contribute to cell theory? It helped to show that cells contain water. ... It helped to show that some cells are visible to the naked eye.
Explanation:
If your teacher checks if it was copied just put it in your on words
in the photo excitation of the cis to trans conversion in retinal, what is the energy from the photon ultimately used for?
In the photo excitation of the cis to trans conversion in retinal, the energy from the photon ultimately used for the photon is absorbed and the system gives off an electron via the phototoelectric effect.
The photoelectric effect light of a certain frequency, known as the threshold frequency, is shone onto a metal surface, electrons are ejected from the metal and can be detected as a current. This effect was first observed by Heinrich Hertz in 1887 and explained by Albert Einstein in 1905 as a consequence of the particle nature of light.
Einstein proposed that light is composed of discrete packets of energy called photons. When a photon with enough energy strikes a metal surface, it can transfer its energy to an electron, which can then escape from the metal. The energy of the electron depends on the frequency of the light, not its intensity, which was a departure from classical wave theory.
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Complete Question:-
In the photo excitation of the cis to trans conversion in retinal, what is the energy from the photon ultimately used for?
a. This process ends in stored energy via a translocation of a hydroxide ion across the cell membrane.
b. The process stores this energy in the form of charge separation between the Schiff base and amino acid of opsin.
c. Pumping Na+; ions to amplify the photo signal into an electrical signal
d.The photon is absorbed and the system gives off an electron via the photoelectric effect.
to avoid landing at the wrong airport or on the wrong runway, a
pilot should?
Pilots can prevent landing at the wrong airport or on the wrong runway by adhering to established procedures and employing various navigational aids.
Pilots can employ several measures to prevent landing at the wrong airport or on the wrong runway. Firstly, they should carefully review and follow established procedures provided by air traffic control (ATC) and the airport authority. This includes verifying the assigned runway and using the correct approach and landing charts. Secondly, pilots should make use of navigational aids such as instrument landing systems (ILS), global positioning systems (GPS), and visual aids like runway markings and signage.
These aids help pilots to accurately identify their intended destination and runway. Maintaining situational awareness throughout the flight is crucial, and pilots should cross-reference visual cues with navigational aids to ensure they are on the correct path. In cases of uncertainty or confusion, pilots should communicate with ATC to clarify any discrepancies or seek guidance. By diligently following procedures and utilizing navigational aids, pilots can significantly reduce the risk of landing at the wrong airport or on the wrong runway.
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Electric field lines can never cross. What would crossed electric field lines indicate?
a field pointing in two directions
an attractive force on a charge
a nonuniform area of the field
a place where the field strength is zero
Answer:
It indicates that a force has 2 directions at the point at which they cross
Answer:
A. A field pointing in two directions
Can anyone please tell me the properties of image formed in a spherical mirror?
I will report improper answers!!
Answer:
The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.
Explanation:
Spherical MirrorsThere are two kinds of spherical mirrors, concave and convex.The focal point (F) of a concave mirror is the point at which a parallel beam of light is "focussed" after reflection in the mirror. ...The focal length (f) and radius of curvature (R) are defined in the diagram at the right.hope it helps and thanks for following please give brainliestAnswer:
This questions answers are on the baisis of where the object is placed and see the atachments to know more
consider a pendulum swinging through a small angle. its period is independent of
When considering a pendulum swinging through a small angle, its period is independent of the amplitude of the oscillation. This is due to the principle of simple harmonic motion, where the period remains constant as long as the angle remains small and the system experiences a restoring force proportional to its displacement.
Consider a pendulum swinging through a small angle. The period of a pendulum is the time taken for one complete oscillation, which is defined as the time taken for the pendulum to swing from its highest point, through its equilibrium position, to its lowest point, and back again to its starting position.
The period of a pendulum is determined by two factors: its length and the acceleration due to gravity. According to the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity, we can see that the period of a pendulum is proportional to the square root of its length, and inversely proportional to the square root of the acceleration due to gravity.
Therefore, for a pendulum swinging through a small angle, its period is independent of its amplitude, which is the maximum angle that the pendulum swings away from its equilibrium position. This is because for small angles, the period of the pendulum is approximately constant, and is not affected by the amplitude of the oscillation.
In summary, the period of a pendulum swinging through a small angle is independent of its amplitude, and is only determined by its length and the acceleration due to gravity.
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A projectile is launched horizontally from a height of 25m and it is observed to land 50m from the base. What was the launch velocity?
The initial horizontal velocity of the projectile is 22.1 m/s.
The given parameters;
height of the projectile, h = 25 mhorizontal distance of the object, R = 50 mThe time of motion of the object is calculated as follows;
h = ut + ¹/₂gt²
where;
u is the initial vertical velocity = 0h = ¹/₂gt²
\(t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 25}{9.8} } \\\\t = 2.26 \ s\)
The initial horizontal velocity of the projectile is calculated as follows;
R = vₓt
\(v_x = \frac{R}{t} \\\\v_x = \frac{50}{2.26} \\\\v_x = 22.1 \ m/s\)
Thus, the initial horizontal velocity of the projectile is 22.1 m/s.
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on a whim, you are trying to stand in a cart attached to a strong spring. the spring is compressed and then released, and you oscillate back and forth, trying to maintain your balance. there is a sand bag in the cart.
The effect that this will have on the amplitude of your oscillation.is b.) The amplitude of oscillation will decrease.
What is the amplitude?The amplitude of an oscillating system is the magnitude of change in the oscillating variable with each oscillation. Sound waves in air, for example, are oscillations in atmospheric pressure, and their amplitudes are proportional to the pressure change during one oscillation.
When a wave travels through a medium, it loses energy as it moves. As the distance between the wave and its source grows, it spreads out over a larger and larger area. As the wave spreads through the medium, it loses energy and its amplitude decreases.
In this case, at the point of equilibrium, the cart and the skater will have maximum kinetic energy. By dropping the same bag, the energy is reduced. The amplitude of an oscillating pendulum decreases with time because of friction due to air
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On a whim, you are trying to stand in a cart attached to a strong spring. The spring is compressed and then released, and you oscillate back and forth, trying to maintain your balance. There is a sand bag in the cart.
At the instant you pass through the equilibrium (x=0) location of the spring, you drop the sandbag onto the ground, out of the cart.
Question: If you drop the sand bag out of the cart right at the equibrium location, what effect will that have on the amplitude of your oscillation? (choose correct choice):
a.) The amplitude of oscillation will increase.
b.) The amplitude of oscillation will decrease.
c.) There will be no effect on the amplitude.
Se
P Fiya
Example:
was with a mass of 1500 kg accelerates from 0 to 27.78 mis at 5.20 ms' The frictional force on the car
700 N Calculate the power of the engine (1.18 x 10"Wer 118 kW)
The instantaneous power of the engine of the car is 121 kW.
The given parameters:
Mass, m = 1500 kgInitial velocity, u = 0Final velocity, v = 27.78 m/sTime of motion, t = 5.2 sFrictional force on the car, F = 700 NThe force exerted by the car is calculated as follows;
\(F = \frac{m(v- u)}{t} \\\\F = \frac{1500(27.78-0)}{5.2 } \\\\F = 8013.46 \ N\)
The total force exerted on the engine is calculated as follows;
\(F= 8013.5 \ N + \ 700 \ N\\\\ F = 8713.46 \ N\)
The instantaneous power of the engine is calculated as follows;
\(P = F\bar v\\\\P = F \times (\frac{v-u}{2} )\\\\P = 8713.46 \times (\frac{27.78 -0}{2} )\\\\P = 1.21 \times 10^5 \ W\\\\P = 121 \ kW\)
Thus, the instantaneous power of the engine of the car is 121 kW.
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A car is approaching a stoplight. When the car is 200 m from the stoplight, the light turns yellow. The driver now has three seconds to either come to a stop, or hurry through the intersection before the light turns red. The car's initial velocity is 50 m/s, and it can accelerate at a maximum of 8 m/s^2. Determine if the car can make it through the light.
Apply third equation of kinematics
\(\\ \tt\hookrightarrow v^2-u^2=2as\)
\(\\ \tt\hookrightarrow (50)^2=2(200)(8)\)
\(\\ \tt\hookrightarrow 2500=16(200)\)
\(\\ \tt\hookrightarrow 200=2500/16\)
\(\\ \tt\hookrightarrow 200>156.25\)
Unfortunately the car cannot make it through
Answer:
No. The car could not make through the light.
Explanation:
initial velocity is 50 m/scan acceleration to 8 m/s²Needs to cover 200 metres or more.Has 3 seconds.Formula: \(s=ut+\frac{1}{2} at^{2}\)
where s is displacement, u is initial velocity, a is acceleration, t is time
Using the formula:
Distance: 50 * 3 + 1/2 * 8 * 3²
: 186 meters
The car could not make it through.
1. A pumpkin with a mass of 2 kg accelerates 2 m/s/s when an unknown force is applied to it. What is the amount of the force?
Answer:
4 Newton
Explanation:
F=ma therefore 2kg*2m/s/s=4 Newton
Please Help Quick ASAP Hurry This is Physical Science
Which statements best describe magnetic fields?
A. Magnetic fields need a conductor.
B. Magnetic fields must have only positive charges.
C. Magnetic fields have north and south magnetic poles.
D. Magnetic fields are always found in insulators.
Answer:
Think it is C
Explanation:
Not sure!!!
An organism that is only one cell big and has a nucleus is most likely a member of which kingdom?
Answer:
Protista
Explanation:
Taxonomy can be defined as the process of naming, classification and description of living organisms such as plants and animals. Thus, the biological classification of living organisms based on similarities or characteristics such as eyes, number of legs, etc., is generally referred to as taxonomy.
Basically, taxonomy helps scientist to have a good understanding and knowledge when studying various organisms.
Furthermore, the eight (8) biological classification (taxonomy) used for grouping and organizing organisms are; kingdom, domain, phylum, family, order, class, species and genus.
An organism that has only one cell, big and has a nucleus is most likely a member of Protista. Thus, a Protista such as euglena, paramecium, amoeba, etc., have a nucleus and are unicellular.
A unicellular organism refers to a living organism that possess a single-cell while a multicellular organism has many (multiple) cells.
Make a
claim about whether a mixture could be made
up of only elements and no compounds.
Summarize evidence to support the claim and
explain your reasoning.
Answer:
Yes, a mixture can be made up of just elements and no compounds. The elements never experiance a chemical interaction and stay only in physical contact with each other.
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