PLS HELP ME I REALLY NEED HELP I DO NOT FEEL GOOD AND I HAVE TO MCUH WORK...pls? (7th grade work)

Water flows from reservoir 2 (110 ft) to reservoir 1 (15 ft) and reservoir 3 (55 ft) due to the pressure difference created by the varying water levels, with the flow rate determined by the magnitude of the pressure difference.

The three water reservoirs are connected to each other with galvanized iron pipes. Reservoir 1 has a free surface height of 15 ft, reservoir 2 has a height of 110 ft, and reservoir 3 has a height of 55 ft. Each reservoir is connected to the others via a pipe, and the three pipes meet at one node.

To understand how the water flows between the reservoirs, we can use the concept of water pressure. Water always flows from areas of higher pressure to areas of lower pressure.

In this case, reservoir 2 has the highest water level at 110 ft, so it has the highest pressure. Water will flow from reservoir 2 to reservoir 1 and reservoir 3 because their water levels are lower.

The water flow between the reservoirs is determined by the difference in their water levels. For example, the water level in reservoir 2 is 110 ft, and the water level in reservoir 1 is 15 ft. This means there is a pressure difference of 110 ft - 15 ft = 95 ft between the two reservoirs.

Water will flow from reservoir 2 to reservoir 1 until the pressure is equalized. Similarly, water will flow from reservoir 2 to reservoir 3, but the pressure difference will be different because the water level in reservoir 3 is 55 ft.

The pipe connecting reservoir 2 to reservoir 1 will have a higher flow rate compared to the pipe connecting reservoir 2 to reservoir 3 because the pressure difference is greater between reservoir 2 and reservoir 1.

In summary, the water will flow from reservoir 2 to reservoir 1 and reservoir 3 due to the difference in their water levels. The flow rate will depend on the pressure difference between the reservoirs.

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Answer:

The same-side interior angle theorem states that when two lines that are parallel are intersected by a transversal line, the same-side interior angles that are formed are supplementary, or add up to 180 degrees

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

I hope this helps you out!

we can replace y on the second equation to find x

to find X we need to use this formula to factor

where a=3, b=2 and c=-6

so, replace

we have 2 solutions for x

Answer:

x = 1

Step-by-step explanation:

3(2) = \(\sqrt{4^{2} + 20 x }\)

6=\(\sqrt{16+20 x}\)

square both side

36 = 16 +20x

20 = 20x

x= 1

The maximum value of F is 24, which occurs at point B(0, 8), and the minimum value of F is -22, which occurs at point D(6, 2).

To find the maximum and minimum values of the function F = -5x + 3y, subject to the given constraints, we need to analyze the feasible region defined by the constraints.

The constraints are:

5x + 3y ≤ 24

3x + 5y ≤ 20

We can graph these constraints on a coordinate plane and find the feasible region, which is the overlapping region satisfying both constraints.

By solving the system of inequalities, we find the feasible region bounded by the lines:

x = 0

y = 0

5x + 3y = 24

3x + 5y = 20

To find the maximum and minimum values of F = -5x + 3y within the feasible region, we evaluate the function at the corners or vertices of the feasible region. The corners can be found by solving the equations of the intersecting lines.

By solving the system of equations, we find the vertices of the feasible region:

A(0, 0)

B(0, 8)

C(4, 0)

D(6, 2)

Evaluating F at each vertex, we get:

F(A) = -5(0) + 3(0) = 0

F(B) = -5(0) + 3(8) = 24

F(C) = -5(4) + 3(0) = -20

F(D) = -5(6) + 3(2) = -22

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Answer:

option B

Step-by-step explanation:

the slope is -2, so the equation must have -2x in it.

This narrows it down to option C and B

the intercept is at -5, not +5 so the correct answer is y = -2x - 5

Answer: Debit Supplies Expense $877 and credit Supplies $877

Step-by-step explanation:

From the question, we are informed that a physical count of supplies on hand at the end of may for Masters, inc. showed $1,253 of supplies on hand while the general leger balance before any adjusting is $2,130.

The adjusting entry for office supplies that should be recorded on may 31 will be the difference in the physical count and general ledger balance which is ($2130 - $1253) = $877. We then have to debit Supplies expense $877 and then credit supplies $877

Given wave function for a particle is:ψ(x)=(2/A)​sinAπx​(a) The probability of finding the particle between x = 0 and x = A is to be computed. Probability density function is given as:

P(x) = |ψ(x)|²ψ(x) = (2/A)​sinAπx​P(x) = |(2/A)​sinAπx​|²P(x) = (4/A²)sin²AπxA

= ∫₀ᴬ P(x) dx= ∫₀ᴬ |(2/A)​sinAπx​|² dx= ∫₀ᴬ (4/A²)sin²Aπx dx.

Applying the formula of sin²θ = 1/2 - cos2θ / 2= ∫₀ᴬ (2/A²) [1 - cos(2Aπx)] dx= (2/A²) [x - sin(2Aπx)/2Aπ]₀ᴬ= 1.

Hence, the probability of finding the particle between x = 0 and x = A is 1.

As per the above computation, it is evident that the probability of finding the particle between x = 0 and x = A is 1. Therefore, it can be concluded that the particle can be found at any point in the given interval with equal probability. This also shows that the particle is bound between the limits of x = 0 and x = A.

(b) The probability of finding the particle between x = 0 and x = A/2 is to be computed.

Probability density function is given as:

P(x) = |ψ(x)|²ψ(x) = (2/A)​sinAπx​P(x) = |(2/A)​sinAπx​|²P(x)

= (4/A²)sin²AπxA/2 = ∫₀ᴬ/₂ P(x) dx

= ∫₀ᴬ/₂ |(2/A)​sinAπx​|² dx= ∫₀ᴬ/₂ (4/A²)sin²Aπx dx.

Applying the formula of sin²θ = 1/2 - cos2θ / 2= ∫₀ᴬ/₂ (2/A²) [1 - cos(2Aπx)] dx= (2/A²) [x - sin(2Aπx)/2Aπ]₀ᴬ/₂= 1/2.

Hence, the probability of finding the particle between x = 0 and x = A/2 is 1/2.

As per the above computation, it is evident that the probability of finding the particle between x = 0 and x = A/2 is 1/2. Therefore, it can be concluded that the particle is likely to be found between the limits of x = 0 and x = A/2. It is to be noted that the probability of finding the particle is not equal at all points in the given interval.

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Answer:

x = -8

Step-by-step explanation:

4

+

4

(

2

+

5

)

=

6

−

2

8

4x+{\color{#c92786}{4(2x+5)}}=6x-28

4x+4(2x+5)=6x−28

4

+

8

+

2

0

=

6

−

2

8

4

+

8

+

2

0

=

6

−

2

8

{\color{#c92786}{4x}}+{\color{#c92786}{8x}}+20=6x-28

4x+8x+20=6x−28

1

2

+

2

0

=

6

−

2

8

1

2

+

2

0

=

6

−

2

8

12x+20=6x-28

12x+20=6x−28

1

2

+

2

0

−

2

0

=

6

−

2

8

−

2

0

Subtract the numbers

Subtract the numbers

1

2

=

6

−

4

8

1

2

=

6

−

4

8

12x=6x-48

12x=6x−48

1

2

−

6

=

6

−

4

8

−

6

Combine like terms

Combine like terms

6

=

−

4

8

6

=

−

4

8

6x=-48

6x=−48

6

6

=

−

4

8

6

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

−

8

Hope this helps!!! :))

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Answer:

Step-by-step explanation:

4x+8x+20=6x-28

12x+20=6x-28

12x-6x= -28-20

6x= -48

x= -48/6

x= -8

The equivalent expression of -6(b + 2) + 8 is -6b - 4

The expression is given as

-6(b + 2) + 8

Expand

-6b - 12 + 8

Evaluate the like terms

-6b - 4

Hence, the equivalent expression of -6(b + 2) + 8 is -6b - 4

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Answer:

13

Step-by-step explanation:

If an n × n matrix A can be diagonalized, then for any invertible n × n matrix B, the new matrix B^(-1)AB is still possible to diagonalize, and both matrix A and matrix B^(-1)AB have the same eigenvalues.

Assume that matrix A is diagonalizable, which means there exists an invertible matrix P and a diagonal matrix D such that \(A = PDP^(-1).\)

Let matrix B be any invertible n × n matrix.

Consider the matrix \(B^(-1)AB\). We want to show that \(B^(-1)AB\) is also diagonalizable and has the same eigenvalues as matrix A.

We start by substituting the expression for matrix A: \(B^(-1)AB = B^(-1)(PDP^(-1))B.\)

Rearranging the expression, we have: \(B^(-1)AB = (B^(-1)P)(P^(-1)BP)D(P^(-1)BP^(-1)).\)

Notice that both \((B^(-1)P)\) and \((P^(-1)BP)\) are invertible matrices since B and P are invertible.

Let matrix Q = B^(-1)P and matrix C = P^(-1)BP. Then, the expression simplifies to: \(B^(-1)AB = QCDQ^(-1).\)

Now, we have expressed B^(-1)AB in a form similar to the diagonalization of matrix A. Matrix C is similar to D, and matrix Q is similar to P.

Since matrix C is similar to a diagonal matrix, it is also diagonalizable.

Therefore,\(B^(-1)AB\) is similar to a diagonal matrix \(QCDQ^(-1)\), which means it is also diagonalizable.

Furthermore, since matrix C is similar to D, they have the same eigenvalues.

Similarly, since matrix Q is similar to P, they also have the same eigenvalues.

Therefore, matrix A and matrix \(B^(-1)AB\) have the same eigenvalues.

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Yes all your used tiles are correct.

Let's solve the equation too

The value of variable x in the equation 2x+4=3x+(-1) is 5.

Equation is a relationship between two or more variables that are expressed in equal to form. Equation of twwo variable looks like ax+y=c. It cab be linear equation, quadratic equation and cubic equation. linear equation has a straight line curve.

We have been given equation 2x4=3x+(-1) and we have to solve the equation. Our equation has only one variable, so we have to solve for that variable only.

2x+4=3x+(-1)

2x+4=3x-1

5=x

Hence the value of x in the equation 2x+4=x+(-1) is 5.

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The correct answer is, P(X > 18) is the same as P(X < 18). Option b is correct. The probability P(X > 18) is related to P(X < 18) in such a way that: P(X > 18) is the same as 1 − P(X < 18).

Explanation:

The mean length of a certain product X is μ = 18 inches.

As we know that the length of a certain product X is normally distributed.

So, we can conclude that: Z = (X - μ) / σ, where Z is the standard normal random variable.

Let's find the probability of X > 18 using the standard normal distribution table:

P(X > 18) = P(Z > (18 - μ) / σ)P(Z > (18 - 18) / σ) = P(Z > 0) = 0.5

Therefore, P(X > 18) = 0.5

Using the complement rule, the probability of X < 18 can be obtained:

P(X < 18) = 1 - P(X > 18)P(X < 18) = 1 - 0.5P(X < 18) = 0.5

Therefore, the probability P(X > 18) is the same as P(X < 18).

Hence, the correct answer is, P(X > 18) is the same as P(X < 18). Option b is correct.

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The angular area of the HST's field of view is 25 square degrees.

The field of view is the extent of the sky that the Hubble Space Telescope (HST) can observe at a given time. It is usually measured in degrees.

To calculate the angular area, we can use the formula for the area of a circle:

Area = π * (angular size/2)^2

Where π is a mathematical constant approximately equal to 3.14, and the angular size is in degrees.

Let's say the angular size of the HST's field of view is 10 degrees.

First, we divide the angular size by 2:

10 degrees / 2 = 5 degrees

Next, we square the result:

5 degrees * 5 degrees = 25 square degrees

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The C program for RK 4th order .

C program,

#include<stdio.h>

//differential equation "dy/dx = (y-2*x*y)"

float f(float x, float y)

{

return(y-2*x*y);

}

int main()

{

// Finds value of y for a given x using step size h

int i,n;

float x0,y0,x,h,k1,k2,k3,k4;

printf("Enter the value of x:");

scanf("%f",&x);

//initial value y0 at x0.

printf("Enter the initial value of x & y:");

scanf("%f%f",&x0,&y0);

//step size

printf("Enter the value of h:");

scanf("%f",&h);

//prints the initial value of y at x and step size.

printf("x0=%f\t yo=%f\t h=%f\n",x0,y0,h);

//Count number of iterations using step size or

//step height h

n=(x-x0)/h;

// Iterate for number of iterations

for(i=1;i<=n;i++)

{

//Apply Runge Kutta Formulas to find

//next value of y

k1 = h*f(x0,y0);

k2 = h*f(x0+h/2,y0+k1/2);

k3 = h*f(x0+h/2,y0+k2/2);

k4 = h*f(x0+h,y0+k3);

//Update next value of y

y0 = y0+(k1+2*k2+2*k3+k4)/6;

//Update next value of x

x0=x0+h;

}

//print the value of y at entered value of x.

printf("at x=%f\t,y=%f\n",x,y0);

return 0;

}

Solution of DE,

y' = y - 2xy, y(0) = 1

The task is to find value of unknown function y at a given point x.

Below is the formula used to compute next value yn+1 from previous value yn. The value of n are 0, 1, 2, 3, ….(x – x0)/h.

Here h is step height and xn+1 = x0 + h

\(K_{1} = h f(x_{n} ,y_{n} )\)

\(K_{2} = hf( x_{n} + h/2 , y_{n} + K_{1}/2 )\)

Thus,

\(y_{n+1} = y_{n} + K_{1} / 6 + K_{2} / 3 + K_{3} / 3 + K_{4} / 6 +O(h^{5} )\)

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The code 1814151418 decodes to RADE using a simple substitution cipher, where each letter is replaced with a different letter or number. To decipher the message, one must know the key, which is the code that maps each letter to a number

The code provided indicates that each number corresponds to a letter in the alphabet. Since 1 is A, 2 is B, and so on, the code 1814151418 would decode as RADE. This is an example of a simple substitution cipher, a type of encryption where each letter is replaced with a different letter or number. To decipher the message, one must know the key, which in this case is the code that maps each letter to a number. Knowing this, it is a simple task to decode any message that has been encrypted with this code.

The code 1814151418 decodes to RADE using a simple substitution cipher, where each letter is replaced with a different letter or number. To decipher the message, one must know the key, which is the code that maps each letter to a number

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Answer:

IM SORRY THIS ISNT HELPING BUT I LOVE THE NOAH NECK PFP LUEJEHE

The given task involves estimating a polynomial regression model using period, per squared, and dummy variables for the months of February to December.

The equation should include all variables without removing them based on their p-values, and no additional variables should be added. The desired format for coefficient values is two decimal places, and negative numbers should be displayed as "-5" instead of "(5)".

To estimate a polynomial regression model, we need to specify the equation that relates the dependent variable to the independent variables. In this case, the independent variables are period, per squared, and dummy variables for the months from February to December.

The equation for the polynomial regression model would look like this:

f = Intercept + Variable * period + Variable * per squared + Variable * Feb + Variable * Mar + Variable * Apr + ...

Each variable is multiplied by its corresponding independent variable. The intercept term represents the constant value in the equation. The coefficients for each variable determine the impact or contribution of that variable to the dependent variable.

To estimate the polynomial regression model, you need to provide the coefficient values for each variable. The desired format for the coefficients is two decimal places. For negative numbers, use the format "-5" instead of "(5)".

Please provide the coefficient values for the intercept, period, per squared, Feb, Mar, Apr, and any additional variables you have included in the model.

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Answer:

oh dang i hated doing these when i was in sixth grade lol umm  55?????

Step-by-step explanation:

Answer:

x < - 3

Step-by-step explanation:

Given the interval (- ∞, - 3 )

The parenthesis on both ends indicates that x cannot equal the end values.

Thus

x < - 3 represents the interval

The width of a confidence interval is primarily determined by the chosen confidence level, sample size, and variability of the data.

1. Confidence level: The confidence level represents the level of certainty desired in the estimation. A higher confidence level, such as 95% or 99%, requires a wider interval to capture a larger range of possible values within that level of confidence. Conversely, a lower confidence level, such as 90%, allows for a narrower interval.

2. Sample size: Increasing the sample size generally leads to a narrower confidence interval. With a larger sample, there is more data available to estimate the population parameter, resulting in a more precise estimate and reducing the margin of error.

3. Variability of the data: Higher variability in the data, indicated by a larger standard deviation or greater spread, requires a wider confidence interval. This is because a larger range of possible values is needed to account for the uncertainty associated with more variable data.

By adjusting these factors, researchers can control the width of the confidence interval, striking a balance between the desired level of confidence and the precision of the estimate.

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Answer:

32 Fahrenheit

Step-by-step explanation:

Since it is -8, subtract -8.

Now, you have 0 Fahrenheit.

Then, you add 24, since the high was -24 Fahrenheit.

The total number you added and subtracted is 32 Fahrenheit.

Hope this helps!

Answer:

46, 57 , 67

Step-by-step explanation:

Acute scalene triangle : A triangle in which all three angles are less then 90 degrees and all three angles are different measurements .

have a good day

Answer:

See below

Step-by-step explanation:

If you consider an open circle, it would exclude the value with which we have circled when writing the inequality. Hence the only possible signs with in such an example can be a greater than sign ( > ) or less than sign ( < );

Let us take a look at an example to help. We are given a graph with an open circle on the number say 3. An arrow extends to the right of this number 3;

\(Inequality Sign - <,\\Inequality - x > 3,\\\)

Hope this helps!

For f(x) =4x+1 and g(x) = x²-5, the answer of (f/g) (x) is D) 4x+1/x²-5, x≠±√5

From the question, we have:

f(x) =4x+1

g(x) = x²-5

If what you are looking for is( f/g) (x), then only place the value of f(x) as the quantifier and g(x) as the denominator. Then the function that satisfies is D.

But here there is a condition that (f/g) (x) applies if the value of x is not √5 or -√5. Because if it becomes an x value then the result will be 0.

We can prove this:

With this equation (f/g) (x)=4x+1/x²-5

let's try to use value of x is √5, it will be

(f/g) (x)=4x+1/x²-5

(f/g) (√5) = 4.√5+1/(√5)²-5

=(4√5+1)/5-5

=(4√5+1) /0

=0

Then, try to use value of x is -√5, it will be

(f/g) (x)=4x+1/x²-5

(f/g) (√5) = 4.(-√5)+1/(-√5)²-5

=(-4√5+1)/5-5

=(-4√5+1) /0

=0

From the results above it proves that option D cannot be used if x= ±√5.

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Answer:

To solve for e, divide 10 from each side.. 1 divided by 10 e=0.1

Answer:

Matrix calculator

Step-by-step explanation:

There are matrix calculators online with analytics steps

Answer:

D) 7

Step-by-step explanation:

The answer is D because A, B, and C are not considered numbers that are natural, whole, integers, or fractional. Irrational numbers are numbers that cannot be quantified any other way, do not have repeating decimals, and never end. A good example of this is π or 3.14159265.... you get the picture.

Hope this helps!