From the table of densities found in this experiment, iron has a density of 7. 85 g/cm3 and water has a density of 1. 0 g/ml. Iron is denser than water and will sink when placed in water. Explain how ships made from iron stay afloat using density principles.

An HV (High Voltage) battery for a full-electric drive vehicle can weigh more than several hundred pounds. The exact weight of an HV battery can vary depending on various factors such as the vehicle's size, range, and battery capacity.

In larger electric vehicles like SUVs or trucks, the HV battery can weigh anywhere from 800 to 1,500 pounds or more. Smaller electric vehicles such as compact cars or hatchbacks may have HV batteries weighing between 400 and 800 pounds.It's important to note that battery technology is constantly evolving, and advancements are being made to improve energy density and reduce the weight of HV batteries while maintaining their performance and range. Therefore, the weight of HV batteries can vary based on the specific vehicle and the battery technology used.

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Answer:

currently states that a person is qualified to drive a commercial motor vehicle if he/she “can read and speak the English language sufficiently to converse with the general public, to understand highway traffic signs and signals

So I think B

Complete Question

Analyze the boundary work done during the process having a rigid tank contains air at 500 kPa and 150°C. As a result of heat transfer to the surroundings, the temperature and pressure inside the tank drop to 65°C and 400 kPa, respectively.

Determine the boundary work done during this process and heat Lose

Answer:

a)  \(W=0\)

b)  \(dQ=-61.03KJ/kg\)

Explanation:

From the question we are told that:

Pressure of air \(P_1=500kpa\)

Temperature of Air \(T_2=150°C\)

Pressure drop \(P_2=400kpa\)

Temperature of drop \(T_2=65 \textdegree C\)

Generally the Constant Volume Process  is mathematically given by

 \(V_1=V_2=V\)

Therefore

a)

Generally the equation for  boundary work w is mathematically given by

 \(W=pdv\)

 \(W=P(V_2-V_1)\)

 \(W=P(V_V)\)

 \(W=0KJ\)

b)

Generally the equation for Heat Change is mathematically given by

 \(dQ=dU+dW\)

 \(dQ=dU\)

 \(dQ=C_v(T_2-T_1)\)

Where

   C_v=Specific Heat capacity of Air

  \(C_v=0.718 kJ/kg K\)

 \(dQ=0.718(338-423)\)

 \(dQ=-61.03KJ/kg\)

Answer:

Hello your question is incomplete attached below is the complete question

answer :

a) 95.80°C

b) 8.23 MW

Explanation:

Convection heat transfer coefficient = 860 W/m^2 . k

a) Calculate for the temp of sheet metal when it leaves the oil bath

first step : find the Biot number

Bi = hLc / K  ------- ( 1 )

where : h = 860 W/m^2 , Lc = 0.0025 m ,  K = 60.5 W/m°C

Input values into equation 1 above

Bi = 0.036 which is < 1  ( hence lumped parameter analysis can be applied )

next : find the time constant

t ( time constant ) = h / P*Cp *Lc  --------- ( 2 )

where : p = 7854 kg/m^3 , Lc = 0.0025 m , h = 860 W/m^2, Cp = 434 J/kg°C

Input values into equation 2 above

t ( time constant ) = 0.10092 s^-1

Determine the elapsed time

T = L / V = 9/20 = 0.45 min

∴   temp of sheet metal when it leaves the oil bath

= (T(t) - 45 ) / (820 - 45)  = e^-(0.10092 * 27 )

T∞ =  45°C

Ti = 820°C

hence : T(t) = 95.80°C

b) Calculate the required rate of heat removal form the oil

Q = mCp ( Ti - T(t) ) ------------ ( 3 )

m = ( 7854 *2 * 0.005 * 20 ) = 26.173 kg/s

Cp = 434 J/kg°C

Ti =  820°C

T(t) = 95.80°C

Input values into equation 3 above

Q = 8.23 MW

Answer:

1)ΔL = 0.616 mm

2)Δd = 0.00194 mm

Explanation:

We are given;

Force; F = 52900 N

Initial length; L_o = 207 mm = 0.207 m

Diameter; d_o = 19.2 mm = 0.0192 m

Elastic modulus; E = 61.4 GPa = 61.4 × 10^(9) N/m²

Now, from Hooke's law;

E = σ/ε

Where; σ is stress = force/area = F/A

A = πd²/4 = π × 0.0192²/4

A = 0.00009216π

σ = 52900/0.00009216π

ε = ΔL/L_o

ε = ΔL/0.207

Thus,from E = σ/ε, we have;

61.4 × 10^(9) = (52900/0.00009216π) ÷ (ΔL/0.207)

Making ΔL the subject, we have;

ΔL = (52900 × 0.207)/(61.4 × 10^(9) × 0.00009216π)

ΔL = 0.616 × 10^(-3) m

ΔL = 0.616 mm

B) Poisson's ratio is given as;

υ = ε_x/ε_z

ε_x = Δd/d_o

ε_z = ΔL/L_o

Thus;

υ = (Δd/d_o) ÷ (ΔL/L_o)

Making Δd the subject gives;

Δd = (υ × d_o × ΔL)/L_o

We are given Poisson's ratio to be 0.34.

Thus;

Δd = (0.34 × 19.2 × 0.616)/207

Δd = 0.00194 mm

Answer:

10.5

Explanation:

Convert to an equation for example P%* X=Y

P is 7.5% X is 140, so the equation Is 7.5 percent * 14= Y

convert 7.5% Into a decimal by removing the percent sign and deviding by 7.5/100= 0.075

Substitute 0.075 for 7.5% in the equation: 7.5%*140=Y becomes 0.075*140= 10.5

According to the question, the force applied to the load in the hydraulic jack will be 400 lb.

To determine the force applied to the load in the hydraulic jack, we can use the principle of Pascal's law, which states that the pressure applied to an enclosed fluid is transmitted uniformly in all directions.

According to Pascal's law, the pressure exerted on the input piston is equal to the pressure exerted on the output piston. Therefore, we can calculate the force applied to the load using the following equation:

Force on input piston / Area of input piston = Force on output piston / Area of output piston

Given:

Area of input piston = 0.5 in²

Area of output piston = 10 in²

Force on input piston = 200 lb

Using the equation mentioned above, we can solve for the force on the output piston (force applied to the load):

Force on output piston = (Force on input piston / Area of input piston) × Area of output piston

Substituting the given values into the equation, we get:

Force on output piston = (200 lb / 0.5 in²) × 10 in²

Force on output piston = 400 lb

Therefore, the force applied to the load in the hydraulic jack will be 400 lb.

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A

It would be B but I say that it isn't because children under 3 should be riding a buckle up just for safety

Two soil samples are being compacted in the lab with Modified Procter method. AASHTO classification for sample 1 is A-2-4 (0) and for sample 2 is A-6(6). One can predict that sample 1 reaches to a higher maximum Dry Density in a lower optimum moisture content compared to sample.

According to the Modified Proctor test, the dry density is determined by compacting a soil sample at a specified moisture content using a controlled amount of energy. The maximum dry density is the highest density that may be achieved using a given compaction effort and moisture content, while the optimum moisture content is the moisture content at which the maximum dry density is achieved.

A-2-4(0) soil is classified by AASHTO as well-graded sand with some gravel. A-6(6) soil is classified by AASHTO as poorly graded gravel with sand.To predict which soil sample will reach maximum dry density at an optimum moisture content, the AASHTO soil classification system may be used. The AASHTO soil classification is dependent on a soil's particle size distribution, and it is divided into 3 groups, including coarse-grained soil, fine-grained soil, and highly organic soil.

As a result, the maximum dry density of the soil is related to the size of its particles as well as the amount of fine material, which has a significant impact on the density of the soil.

Therefore, the soil sample with A-2-4 (0) classification reaches to a higher maximum dry density in a lower optimum moisture content than the A-6 (6) soil sample, because the former contains less fine-grained soil and more sand and gravel, while the latter contains less gravel and more sand and fine-grained material.

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The statement "Employees are not responsible for their own safety while at work" is false because Employees most certainly are responsible.

A multidisciplinary discipline dealing with the safety, health, and welfare of individuals at work is known as occupational safety and health, often known as occupational health and safety, occupational health, or occupational safety.

An environment that is safe and healthy for workers may minimize injury and sickness expenses, lower levels of absenteeism, boost output and quality, and improve employee morale. In other words, safety benefits the business.

Thus, the statement "Employees are not responsible for their own safety while at work" is false because Employees most certainly are responsible.

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Prioritizing calls for service instead of dispatching police immediately to all calls is an example of directed patrol. Quality-of-life offenses, contrary to the statement, are minor law violations that typically involve disturbances , rather than major offenses such as murder.

Directed patrol refers to a proactive policing strategy where law enforcement agencies prioritize calls for service based on their urgency or severity. Instead of dispatching officers immediately to every call, the agency allocates resources based on the priority of the situation. This approach allows for a more efficient allocation of police resources, focusing on high-priority calls while balancing the workload of officers. Quality-of-life offenses, on the other hand, are not major law violations like murder. Rather, they encompass a range of minor offenses that often involve disturbances, public nuisances, or violations of public order. Examples of quality-of-life offenses may include disorderly conduct, loitering, noise violations, public intoxication, or vandalism. These offenses are typically less severe in nature and may impact the overall livability and well-being of a community, but they are not considered major crimes. In summary, prioritizing calls for service is an example of directed patrol, which aims to allocate police resources efficiently. Quality-of-life offenses are minor law violations that relate to disturbances and public nuisances, differing from major offenses such as murder.

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Answer:

Email etiquette is important

Explanation:

It is important to understand how to use correct email etiquette because it helps you communicate more clearly. It also makes you seem a bit more professional too. For example depending in who you're emailing like say you're emailing your teacher for help then here's how it'd go:

Dear(teacher name, capitalize, never use first name unless they allow it)

Hello (teacher name), my name is (first and last name) from your (number class) and I was wondering if you could please help me out with (situation, be clear on what you need help with otherwise it won't get through to them)? If you could that would be greatly appreciated!

Sincerely,

(your name first and last)

Answer:

it should be A bc I took the test a while back

Answer:

In  case whereby you  work for rev and check your work email on your mobile phone and You have decided to resign your job and take a position with a different company. Regarding rdm on your mobile phone, you should B. Take your phone to IT Services, and they will wipe it clean.

What is expected to do when leaving the company?

It is expected from you to return anything that belong to the company before leaving the company, but in the case whereby there is still a rdm on your mobile phone, then you can work to the IT services so they can wipe it away.

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Missing options:

A. Turn your phone to IT Services

B. Take your phone to IT Services, and they will wipe it clean

C. Download RDM to your personal computer

D. Call IT Services for support, and they will assist

E. Nothing. IT Services will automatically remove all data

The process of die forming that uses a die and a press to form parts from the given processes is called; C: Hydroforming

There are different types of die forming in sheet metal operations. Now, Hydroforming is a specialized type of die forming that uses a high pressure hydraulic fluid to press room temperature working material into a die.

Tailor Welding is a process of making welded blanks made from individual sheets of steel of different thickness, strength and even coating that are joined together by the use of laser welding.

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At high temperatures, there is a large amount of radiative heat transfer via the fibre insulation employed in thermal protection systems (TPS) (1200 C).

At high temperatures, fibre insulation used in thermal protection systems (TPS) radiatively transfers a substantial amount of heat (1200 C). The TPS's ability to insulate can therefore be significantly affected by reducing the radiative heat transfer through the fibre insulation. Directly applying reflective coatings to the individual fibres of a fibrous insulation should reduce radiative heat transfer, resulting in a less effective thermally conductive insulation. Sol-gel processes have been used to create coatings with high infrared reflectivity. By using this method, fibre insulation can receive uniform coatings without noticeably increasing its weight or density. To assess coating performance, ellipsometry, scanning electron microscopy, and Fourier Transform infrared spectroscopy have all been used.

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First-order logic is incomplete and undecidable, so the statement is true. This means that there are some statements in first-order logic that cannot be proven true or false.

And there is no algorithm that can determine whether a given statement is true or false. This is in contrast to propositional logic, which is both complete and decidable.

First-order logic is incomplete and undecidable, meaning that it cannot express or prove all possible statements and that there is no algorithm that can determine the truth or falsity of all possible statements.

Incompleteness refers to the fact that there are true statements that cannot be proven within the system of first-order logic. This was proven by Kurt Gödel in his incompleteness theorems, which showed that any formal system that is powerful enough to express basic arithmetic is either incomplete or inconsistent. First-order logic is one such formal system, and as a result, there are statements that can be neither proved nor disproved within it.

Undecidability refers to the fact that there is no algorithmic procedure that can determine

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Answer:

Relative density = 0.7 or 70%

Explanation:

The following information was provided by this question

Pd = 1.72mg/mg³

Pd max = 1.81 mg/mg³

Pd min = 1.54 mg/mg³

We substitute into the formula. This formula is contained in the attachment.

[(1/1.54)-(1/1.72)]/[1/1.54 - 1/1.81]

= 0.649350 - 0.581395 / 0.649350 - 0.552486

= 0.067955/0.096864

= 0.7015

= 0.7

The relative density is Therefore 0.7 or 70% when converted to percentage

The numerical values for the mesh currents that we have in the question are given as:

We first have to write the KVL

2 - 1(i₁ - i₂) + 3 - 5(i₁ - i₃) = 0

We have to expand the equation that we have above

2 - i₁ + i₂ + 3 - 5i₁ + 5i₃ = 0

take like terms

-i₁ - 5i₁  i₂ + 5i₃ = 5

=  6i₁ - i₂ - 5i₃ = 5

-1(i₂ - i₁) - 6 i₂ - 9(i₃ - i2) = 0

after expanding we would have

i₁ - 16i₂ + 9i₃ = 0------- equation 2

-5 (i3 - i1) - 3 - 9(i3 - i2) - 7i3 = 0

5i1 + 9i2 - 2i3 = 3 ------ equation 3

From the equations that we have in 1, 2 and 3, we would solve the system of equations to get

1i = 0.9892 = 0.9892 ampere

i2 = 0.1501 ampere

i3 = 0.1570 ampere

These are the mesh current that are in the labeled diagram.

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Answer:

genorator- electrical to mechanical

motor- mechanical to electrical

A ProTORQ adjustable nut is unique to a preset hub. Wheel hub assemblies that are pre-adjusted and sealed at the factory are known as preset hubs. They are meant to simplify the installation process.

These bearings, which are frequently used in gearboxes, hoisting apparatus, rolling mills, and mining equipment, can support strong radial loads and axial loads in both directions, depending on the design.

The word "setting" for tapered roller bearings refers to the precise amount of end play (axial clearance) or preload (axial interference) present within a mounted bearing. The freedom to easily alter and optimise configuration at the time of assembly is an inherent advantage of tapered

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Answer:

multimeter

Explanation: in parallel

Answer:

I think it is D

Explanation:

I did a couple mins of research on this topic but there is no clear line that separates a physical and chemical reaction, so do with that as you will. i hope I somewhat helped.

Answer:

t5g5gtttttttttttttttttttttttttttttttttttttttttttt

Explanation:gt555555555555555555555555555555555555555555555555

Answer:

dawbkjbjwwjhjfbfjewfaekfhawkjndwkja

Explanation: dum*as*

Answer:

In general, exceeding the rated voltage output of a power supply or electrical system could cause damage to the components being powered by that system. In some cases, this could result in the components malfunctioning or becoming permanently damaged, potentially leading to system failure. Additionally, exceeding the rated voltage of a system could cause electrical arcing or fires, which could be dangerous or catastrophic depending on the system and the environment it is operating in. Therefore, it is generally important to ensure that electrical systems are designed to operate within their rated voltage ranges to prevent damage and ensure safety.

Answer:

The answer is below

Explanation:

\(\theta_1=cos^{-1}0.28=73.74^o\ lagging\\\\S_1=125\angle 73.74^o=35\ kW+j120\ kVAR\\\\S_2=10\ kW-j40\ kVAR\\\\S_3=15\ kW\)

Total power = P = 35 kW + 10 kW + 15 kW = 60 kW

Total kVAR = 120 kVAR - 40 kVAR = 80 kVAR

\(Total\ apparent \ power =S= S_1+S_2+S_3=(35+j120)+(10-j40)+(15)\\\\S=60\ kW+j80\ kVAR=100\angle 53.13^o\\\\Current(I)=\frac{S^*}{V^*} \frac{100000\angle -53.13^o}{1400\angle0}=71.43\angle-53.13^o\\ \\Power\ factor (PF)=cos(53.13)=0.6\ lagging\\\\The \ new\ power\ factor\ is\ to \ be\ 0.8[cos^{-1}0.8=36.87^o], hence\ since\ the\ total\ \\real\ power(P)= 60\ kW, the\ capacitor\ kVAR(Q_c)\ is:\\\\Q_c=60tan(53.13)-60tan(36.87)=80-45=35\ kVAR\\\\\)

\(C=\frac{Q_c}{wV^2} =\frac{35000\ VAR}{2\pi*60\ Hz*1400\ V}=47.38\ \mu f\)

New current (I') = \(\frac{S'^*}{V^*}=\frac{60000-j45000}{1400}=53.57\angle-36.87^o\)

Current reduce from 71.43 A to 53.57 A

The correct answer is According to the EPA (Environmental Protection Agency) regulations, if the recovery equipment was manufactured before November 15, 1993, the low pressure chiller must be evacuated to 1 mm Hg absolute pressure or lower before making a major repair.

This is to ensure that all the refrigerant has been removed from the system before any repair work is done to prevent it from escaping into the atmosphere. For recovery equipment manufactured after November 15, 1993, the required evacuation level is 10 mm Hg absolute pressure or lower.I suggest referring to the manufacturer's documentation or relevant industry standards for detailed instructions on the evacuation process and recommended vacuum levels for maintenance and repair. It is important to follow appropriate safety procedures and guidelines to ensure proper maintenance and prevent accidents.

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Incomplete question. The options read;

A. Tech A

B. Tech B

C. Both A and B

D. Neither A nor B.

Answer:

C. Both A and B

Explanation:

Technician B is correct because the technician highlighted valid reasons why draining the compressed air systems is important.

For example, since this system helps to absorb moisture or oil from storage areas they thus need to be drained periodically in other to allow for more absorption space.

Also, the reasons mentioned by Technician A are of course correct because it is generally believed that the application of lubricants such as oil helps to reduce wear and tear.

Answer:

The correct option is A

Explanation:

Thermoplastics are polymers that can be recycled. They can be melted with heat and moulded into any shape which becomes hard when cooled. The heat applied to it in the process of recycling does not affect its chemical composition.

There are two main classes of thermoplastics; semi-crystalline and amorphous.

An amorphous thermoplastic has a disorderly arranged molecular structure which makes it difficult to have a definite melting temperature (Tm). However, a semi-crystalline thermoplastic has a well arranged molecular structure which makes it melt after a certain/definite amount of heat is absolved. Hence, the correct answer is A