Desde lo alto de un acantilado de 140 m, se lanza verticalmente un objeto hacia abajo con velocidad de 3m/s. Entonces la magnitud del desplazamiento que ejecuta en t = 3s es: (use g = 10 m/s2)
Answers
Answer:
54
Explanation:
d = vo*t + ½*g*t²
d = 3*3 + ½*10*3²
d = 9 + 45
d = 54 m
entonces el objeto tiene 54 m de desplazamiento
Related Questions
A copy machine uses a lens to make an image of a page in the physics textbook to print a copy. When the print is regular size, both the book and its image are 16.0 cm from the lens.
What is the focal length of this lens?
If the lens is moved so that it is 24 cm from the book, what is the distance to the new image?
This new image will be magnified, reduced, or the same size compared to the original book?
How do you know?
Answers
1/f = 1/di + 1/do
where f is the focal length, di is the distance from the lens to the image, and do is the distance from the lens to the object. Since both the object and image are 16.0 cm from the lens, we can substitute do = di = 16.0 cm and solve for f:
1/f = 1/16.0 + 1/16.0
1/f = 1/8.0
f = 8.0 cm
So the focal length of the lens is 8.0 cm.
If the lens is moved so that it is 24 cm from the book, we can use the same formula to find the new distance to the image:
1/f = 1/di + 1/do
1/8.0 = 1/di + 1/24.0
1/di = 1/8.0 - 1/24.0
1/di = 1/12.0
di = 12.0 cm
So the distance from the lens to the new image is 12.0 cm.
To determine whether the new image will be magnified, reduced, or the same size compared to the original book, we can use the magnification formula:
m = -di/do
where m is the magnification. Since the image is inverted, we include a negative sign. We already know that do = 24.0 cm and di = 12.0 cm, so we can substitute these values and solve for m:
m = -di/do
m = -12.0/24.0
m = -0.5
Since the magnification is negative, the image is inverted. And since the magnification is less than 1 in absolute value, the image is reduced compared to the original book.
What ocean features occur along areas of volcanic activity in the ocean floor and release high pressure, extremely hot water and chemicals?
Trenches
Mid-ocean ridges
Hydrothermal vents
Continental shelfs
Answers
Answer:
Hydrothermal vents
Explanation:
A hydrothermal vent is found along with areas of volcanic activity in the ocean floor which discharges geothermally heated water. Tectonic plates in such areas move apart at spreading centers and hotspots to form hydrothermal vent.
A hydrothermal vent ejects hot and often toxic, fluids and gases into the surrounding seawater when seawater meets magma.
Hence, the correct answer is "Hydrothermal vents".
if the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field. express your answer in newtons per coulomb.
Answers
The unit of electric field, E, is newtons per coulomb (N/C).
To find the magnitude of the electric field, we can use the equation F = qE, where F is the electric force, q is the charge of the electron, and E is the electric field. Since the electron just misses the upper plate, the electric force is zero. Thus, we can write:
0 = qE
Solving for E, we have:
E = 0 / q
However, we can express the answer in newtons per coulomb, which is the unit for electric field. The unit of electric field, E, is newtons per coulomb (N/C).
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How should the table be changed to correctly distinguish between mechanical and electromagnetic waves? Earthquake waves and radiation waves need to change places. Light waves and X-ray waves need to change places. Ocean waves and X-ray waves need to change places. Sound waves and light waves need to change places. ...the answer is D
Answers
Answer:
Electromagnetic waves are visible; mechanical waves are invisible. Electromagnetic waves always reflect; mechanical waves always refract.
Explanation:
Answer:
well you already answered yourself i don't see why you would waist points to do that but yes you are correct .
Explanation:
stay safe and where a mask 2021
A physicist observes that a cannonball shot horizontally from a cannon travels 1.000 m before falling to the ground. Which of the following statements correctly explains this observation using Newton's laws?
O Objects tend to remain in the state of motion they are in unless acted upon by an unbalanced force. Friction and gravity acted on the cannonball, slowing it down and slamming it into the ground
O Objects at rest tend to remain in their cument state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion
The force on the cannonball produced by the cannon was less than the force of friction on the cannonball, causing the cannonball to slow down and fall to the ground.
O The force on the cannonball produced by the cannon exactly equaled the force of friction on the cannonball, balancing the forces and causing it to fall to the ground.
Answers
The correct statement that explains the observation using Newton's laws is objects at rest tend to remain in their current state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion. Here option A is correct.
According to Newton's first law of motion, an object will continue moving at a constant velocity in a straight line unless acted upon by an external force. In this case, when the cannonball is shot horizontally from the cannon, it initially possesses a forward velocity due to the force applied by the cannon. However, once the cannonball is in motion, the only forces acting on it are gravity and friction.
Gravity acts vertically downward, causing the cannonball to accelerate downward. Friction acts horizontally in the opposite direction to the motion of the cannonball. As the cannonball moves forward, friction opposes its motion and gradually slows it down.
Since there is no force continuously propelling the cannonball forward, and the forces of friction and gravity act on it, the cannonball eventually comes to a stop and falls to the ground. Hence option A is correct.
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5. What happens when air absorbs more water vapor?
the air becomes lighter
the air becomes heavier
the air becomes cooler
the air becomes warmer
Answers
Answer
the air becomes heavier
Explanation:
Answer:
When air holds as much water vapor as it can for a given temperature (100% relative humidity), it is said to be saturated. If saturated air is warmed, it can hold more water (relative humidity drops), which is why warm air is used to dry objects--it absorbs moisture. ... Such air compresses and warms.
so it is the air becomes warmer.
An 82.0-kg person rides on a carnival ride in a 45.0-kg basket supported by a single chain. When the ride reaches its top speed, the basket moves at a constant speed in a horizontal circle with a radius of 7.10 m. At this point, the chain supporting the basket is at a 45.0 angle to the vertical. A)At top speed, how large are the vertical and horizontal components of the tension in the chain? (Hint: The vertical component of the tension equals the weight it supports.) B) What is the magnitude of the centripetal acceleration of the basket and its passenger? C) What is the speed of the basket and its passenger? D) How long does it take the basket to make one complete circle?
Answers
The vertical component of the tension is 1,177.05 N while the horizontal component of the tension is 127.47 × 3.90² = 1,949.04 N.
The magnitude of the centripetal acceleration is 2.14 m/s².
What is the value of the vertical and horizontal components of the tension in the chain?A) The vertical component of the tension equals the weight it supports, which is the weight of the person plus the weight of the basket:
Weight = (82.0 kg + 45.0 kg) × 9.81 m/s²
Weight = 1,177.05 N
Therefore, the vertical component of the tension is 1,177.05 N.
To find the horizontal component of the tension, we can use the fact that the net force in the horizontal direction is zero when the basket is moving at a constant speed.
The only horizontal force is the component of the tension perpendicular to the radius, so:
The horizontal component of tension = centripetal force
Horizontal component of tension = (mass × centripetal acceleration)
Horizontal component of tension = (82.0 kg + 45.0 kg) × (v²/7.10 m)
Horizontal component of tension = 127.47 v² N
Setting these two components equal to each other gives:
1,177.05 N = 127.47 v² N
Solving for v gives:
v = 3.90 m/s
Therefore, the horizontal component of the tension is 127.47 × 3.90² = 1,949.04 N.
B) The centripetal acceleration is given by:
a = v²/r
a = (3.90 m/s)²/7.10 m
a = 2.14 m/s²
Therefore, the magnitude of the centripetal acceleration is 2.14 m/s².
C) The speed of the basket and its passenger is 3.90 m/s.
D) The time it takes the basket to make one complete circle is given by:
T = 2πr/v
T = 2π(7.10 m)/3.90 m/s
T = 12.9 s
Therefore, it takes the basket 12.9 s to make one complete circle.
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if the average speed of a car is 45 km/hr , how far can it travel in 30 mins ?
Answers
what is the average speed of a person who swims 105m in 70s ?
Answers
Answer:
v = 1.5 [m/s]
Explanation:
This problem can be solved using the definition of velocity which is the relationship between space and time.
v = x/t
where:
v = speed [m/s]
x = distance = 105 [m]
t = time = 70 [s]
v = 105/70
v = 1.5 [m/s]
Answer:time.
v = x/t
where:
v = speed [m/s]
x = distance = 105 [m]
t = time = 70 [s]
v = 105/70
v = 1.5 [m/s]
Explanation:time.
v = x/t
where:
v = speed [m/s]
x = distance = 105 [m]
t = time = 70 [s]
v = 105/70
v = 1.5 [m/s]
Which of the following describes how energy is transferred in a wave? (select all that apply)
Answers
Energy transfer will be greater if the amplitude of the wave is greater.
The particles of the medium vibrate until they transfer the energy and after transferring energy, they return back to their equilibrium position.
Thus, options 3 and 4 are correct.
EARS: Two ears (E) is dominant to one ear (e). Both parents are heterozygous.
Answers
Answer:
what's the question
Explanation:
I don't understand the question
No machine have 100% efficiency. Why?
Answers
\(\huge\fcolorbox{black}{pink}{Answer}\)
Because said machines have to operate in the physical world with constraints caused by the laws of physics. It’s not possible to do useful work without encountering some of these issues. The mains ones are:
Heat lost from the systemFriction (including air resistance)Electrical resistance\(\sf\blue{hope\:it\:helps}\)
you are standing 0.50 m in front of a lens that projects an image of you onto a wall 2.7 m on the other side of the lens. part a what is the focal length of the lens?
Answers
If you are standing 0.50 m in front of a lens that projects an image of you onto a wall 2.7 m on the other side of the lens the focal length of the lens is approximately 0.42 meters.
To find the focal length of the lens, we can use the lens formula:
1/f = 1/u + 1/v
Where:
f = focal length of the lens
u = object distance (distance between the object and the lens)
v = image distance (distance between the image and the lens)
Given:
u = 0.50 m (you are standing 0.50 m in front of the lens)
v = 2.7 m (the image is projected onto a wall 2.7 m on the other side of the lens)
Now, we can plug the values into the lens formula:
1/f = 1/0.50 + 1/2.7
To solve for f, first find the sum of the two fractions:
1/f = (2.7 + 0.50) / (0.50 * 2.7)
1/f = 3.2 / 1.35
Now, take the reciprocal of both sides to get the focal length:
f = 1.35 / 3.2
f ≈ 0.42 m
So, the focal length of the lens is approximately 0.42 meters.
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I have a 3 cc piece of aluminum with a density of steel with a mass of 24.0 g. I cut it into 2 equal pieces. How has the density of the steel pieces changed
Answers
Answer:
What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
Explanation:
What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
A cat pushes a 0.25-kg toy with a net force of 8n. According to Newton's second law of motion, what is the acceleration of the ball?
Answers
Answer:
a = 32 m/s sq
Explanation:
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air? Part 1 of 2 The speed of the plane in still air is Part 2
Answers
The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.
Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.
The distance traveled with the wind in 3 hours is 408 miles.
Therefore, we can write the equation as:
3(x + y) = 408
Divide both sides by 3:
x + y = 136 .... (1)
The distance traveled against the wind in 4 hours is also 408 miles.
Therefore, the equation can be written as:
4(x - y) = 408
Divide both sides by 4:
x - y = 102 .... (2)
Now we can solve these two equations using the elimination method.
Add equations (1) and (2):
x + y + x - y = 136 + 1022x = 238x = 119 mph
Therefore, the speed of the plane in still air is 119 mph.
Now, substitute this value of x in equation (1):
119 + y = 136y = 17 mph
Therefore, the speed of the wind is 17 mph.
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The correct question is:
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?
In a sugar factory bagasse (the remains of the cane after the juice is extracted) is burned to provide electricity. The types of energy involved are W thermal energy X chemical energy Y electrical energy Z kinetic energy. In what order are these forms of energy converted in this process?A) WXZYB) XWZYC) WZXYD ZXWY
Answers
Given:
Thermal energy is denoted by W
Chemical energy is denoted by X
Electrical energy is denoted by Y
Kinetic energy is denoted by Z
To find the order of energy while converting bagasse to electricity.
Explanation:
The bagasse has chemical energy stored in it.
The bagasse is burned, so chemical energy gets converted into thermal energy.
The thermal energy gets converted into kinetic energy.
The kinetic results in the motion of electrons.
Thus, producing electrical energy.
Hence, the conversion order is XWZY
energy is the ability to___or___ matter
Answers
Energy is defined in science as the ability to move matter or change matter in some other way.
A positive test charge of 5.0x10 -6 C is in an electric field that exerts a force of 2.0x10 -4 N on it. What is the magnitude of the electric field at the location of the test charge
Answers
answer:
click on the picture, hope it helps
The magnitude of the electric field at that location is is 40 N.C⁻¹.
What is electric field?The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
Electric charge or magnetic fields with variable amplitudes can produce an electric field.
Given parameters:
Charge of the positive test charge, q = 5.0x10⁻⁶ C.
Electric force exerted by the electric field, F = 2.0x10⁻⁴ N.
Then, electric field at the position, E = F/q
= 2.0x10⁻⁴ / 5.0x10⁻⁶ N.C⁻¹.
= 40 N.C⁻¹.
Hence, the magnitude of the electric field at the location of the test charge is 40 N.C⁻¹.
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what gauge pressure in the water mains is necessary if a firehose is to spray water to a height of 45 mm ?
Answers
The necessary gauge pressure in the water mains is approximately 70 kPa (10 psi).
The pressure necessary in the water mains to spray water to a height of 45 mm depends on factors such as the diameter of the hose, the length of the hose, the type of nozzle used, and the specific gravity of water.
Assuming the hose is of a standard size (e.g. 1.5 inch diameter) and the nozzle is designed for a nozzle pressure of 70 psi, then the pressure necessary in the water mains would be 70 psi + the pressure required to push the water 45 mm (1.8 inches) up the hose.
To calculate the pressure required, we use Bernoulli's equation:
P1 + (1/2)*ρ*V1^2 = P2 + (1/2)*ρ*V2^2
Where P is the pressure, ρ is the density of water, and V is the velocity of the water.
Assuming the velocity of the water at the nozzle is 10 m/s, and the density of water is 1000 kg/m^3, then the pressure necessary in the water mains to spray water to a height of 45 mm is 90 psi.
P1 + (1/2)*1000*10^2
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How much longer would it take to travel a
distance of 600 km at a speed of 50 kmhr-1
than it would at a speed of 60 kmhr-1?
Answers
“To get time just divide the distance traveled by its speed.
t1= distance/speed1 and t2 = distance / speed2
t1= 600km / 50 km/h and t2 = 600 km / 60 km/h
t1= 12 hours and t2 takes 10 hours
The body traveling at 50 km/h would take 2 hours more than the body traveling at 60 km/h.”
Explanation:
Time=distance/speed
=600/50
=12
=600/60=10
==12-10=2 hours
What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?
Answers
Answer:
weight = 225 N
Explanation:
We are asked to calculate the weight of an object of mass 60 kg on Mars given that the acceleration due to gravity (g) on Mars is 3.75 m/s². We can do so using the following formula:
\(\boxed{W = mg}\),
where:
• W = weight of object in Newtons (N)
• m = mass of object in kg
• g = acceleration due to gravity in m/s².
Substituting the given data into the formula above, we can calculate the weight of the object:
W = 60 × 3.75
= 225 N
Therefore the weight of the 60 kg object on Mars is 225 N.
A cube measures 3cm on each side has a mass of 25 grams. what it its density and relative density.
Answers
Answer:
Density= 2.78 g/cm³
Relative density=2.8
Explanation:
To calculate the density of the cube we have to use the formula ρ=mass/volume
ρ stands for density.
So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³
3³= 9 cm³
Now plug in the values. ρ= 25 g/9 cm³
ρ= 2.78 g/cm³
To find the relative density, we have to use the formula ρsample/ρH20
The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.
Now we have to make the units same so you change the unit of the density of cube to kg/m³
So, 25/1000= 0.025 kg
9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)
=0.000009 m³
The new density= 0.025 kg/ 0.000009 m³
= 2777.78 kg/m³
Now plug the values into the formula:
relative density= 2.777.78 kg/m³ / 997 kg/m³
=2.8
There is no unit since kg/m³ and kg/m³ cancels
1. What is the velocity final if an object starts with 2 m/s and
accelerates at 4 m/s² in 3 s?
Answers
Answer:
Use v = u + at but since u is equal to zero then it becomes v = at. The final velocity of the body is equal to 12 m/s. The acceleration of an object decreases ...
Explanation:
a sailboat started its trip at an average speed of 50 mph. the sailboat travels at this speed for 3.5 hours until it reaches it destination. how many miles did the sailboat travel?
Answers
The sailboat, which travelled at an average speed of 50mph for 3.5hours has travelled for a distance of 175miles
HOW TO CALCULATE DISTANCE:
The distance traveled by a substance can be calculated by multiplying the speed of that substance by the time traveled. That is;Distance (miles) = average speed (miles/hr) × time (hr)Distance = 50mph × 3.5hrs
Distance = 175miles
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Answer:
175 miles
Explanation:
I know because i just did the question on CK12 and got it right
PlEaSe HeLp MeE
What is the gpe of a rock weighing 100N that is sitting on top pf a hill 300 m high?
Answers
Answer:
Gpe = 30000J
Explanation:
Given the following data;
Weight = 100N
Height = 300m
To find the gravitational potential energy (gpe);
Gravitational potential energy can be defined as an energy possessed by an object or body due to its position above the earth surface.
Mathematically, potential energy is given by the formula;
\( G.P.E = mgh\)
Where,
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Gpe = mgh
But weight = mg = 100N
Substituting into the equation, we have:
Gpe = 100*300
Gpe = 30000J
Compare the normal force exerted on the book by the inclined plane and the weight force exerted on the book by the earth.
Are they equal in magnitude?
1. Yes
2. No
3. Their magnitudes cannot be determined
since the forces are not in the same direction
Answers
No, the normal force exerted on the book by the inclined plane and the weight force exerted on the book by the earth are not equal in magnitude.
The normal force acts perpendicularly to the inclined plane, while the weight force is a downward force. Since they are not in the same direction, their magnitudes cannot be determined.
The magnitude of the normal force is determined by the angle of the inclined plane. Since the normal force acts perpendicularly to the inclined plane, it can be calculated by finding the cosine of the angle of the inclined plane multiplied by the weight of the object.
For example, if the inclined plane has an angle of 30°, the normal force would be cos(30°) times the weight of the object. On the other hand, the weight force is determined by the gravitational force, which is a constant and always acts in the downward direction. Thus, the magnitude of the weight force is always equal to the weight of the object.
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3. A shuffleboard player applies a horizontal force of 10.0 N to the shuffleboard puck (400 g). If the puck accelerates at 24.5 m/s/s as the player continues to push it, what is the frictional force on the puck?
Answers
Answer:
Friction = 2 N
Explanation:
F = ma
= .4 * 24.5 = 9.8 N net force 10 N by stick means Ffriction = 2 N
The frictional force acting on the shuffleboard puck is 6.08 N.
What is meant by frictional force ?Frictional force is defined as the resistive force that prevents the relative motion between two surfaces that are in contact with each other.
Here,
Horizontal force applied on the shuffleboard puck, F = 10 N
Mass of the shuffleboard puck, m = 400 g = 0.4 kg
Acceleration of the shuffleboard puck, a = 24.5 m/s²
According to Newton's third law,
F - f = ma
where f is the frictional force acting on the shuffleboard puck.
So, the frictional force,
f = F - ma
f = 10 - (0.4 x 9.8)
f = 10 - 3.92
f = 6.08 N
Hence,
The frictional force acting on the shuffleboard puck is 6.08 N.
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1. If a car travels 40m in 30 seconds how fast is it
going?
Answers
Answer: 80 mph
Explanation:
Why does the speed of the ball have to be measured after it has left the ramp?