At Dwayne's Swimwear, 75% of the 92 swimsuit styles are bikinis. How many bikini styles are there?
Answers
Answer:
69 styles
Step-by-step explanation:
75%= 3/4
92/4= 23 (1/4)
23x3= 69
Related Questions
A Galapagos tortoise can 1/5 mile in an hour. How many hours would it take the tortoise to walk 1/6?
Answers
Answer:
5/6 hours
Step-by-step explanation:
Create a proportion where x is the number of hours it will take to walk 1/6 of a mile:
\(\frac{1/5}{1}\) = \(\frac{1/6}{x}\)
Cross multiply and solve for x:
1/5x = 1/6
x = 5/6
So, it will take the tortoise 5/6 hours to walk 1/6 of a mile
what indicates a location and has no size
Answers
Answer:
a point indicates a location and has no size
simplify (3a^4b^3)^3
Answers
Answer:\quad 27a^{12}b^9
Step-by-step explanation:
\left(3a^4b^3\right)^3=3^3\left(a^4\right)^3\left(b^3\right)^3 =3^3\left(a^4\right)^3\left(b^3\right)^3 3^3=27 =27\left(a^4\right)^3\left(b^3\right)^3
HELP ME PLEASE!! Due today!!
Which expresson is equivalent to 4.35 - 5.5 ??
A. 4.35 + ( - 5.5 )
B. 5.5 - 4.35
C. 4.35 + 5.5
D. 4.25 - ( - 5.5 )
Answers
Answer:
A.
Step-by-step explanation:
The answer to 4.35-5.5 is negetive 1.15, so if you do the same for A. you will get the same answer.
evaluate each expression if m = 13 and n = 8
1.) 2m - n
2.) 3m + 2n
3.) 12 + 3 x m - n
4.)
Answers
26-8
=18
2. 3(13)+2(8)
39+16
=55
3. 12+3x13-8
12+39-8
51-8
=43
4 is blank
Hope this helps
Answer:
1.) 18
2.) 55
3.)43
Step-by-step explanation:
Charlotte ran 1.25 miles yesterday. How could we write this distance as a fraction?
Answers
Given that Charlotte ran 1.25 miles, let's represent this distance as a fraction.
To write this as a fraction, we have:
First step:
Divide the decimal by 1
\(\frac{1.25}{1}\)Second step:
Multiply the numerator and denominator by 100, because it has 2 decimal places (hundreth)
\(\frac{1.25\ast100}{1\ast100}=\frac{125}{100}\)To simplify this, we have:
\(\frac{125}{100}=\frac{5}{4}\)ANSWER:
\(\frac{125}{100}\)Pre-LAB ASSIGNMENT After teading through the introduction and skimming the procedure, complete the pre-lab assignment, which is to be handed in at the beginning of lab class session. INTRODUCTION Chemical reactions are often accompanied by formation of a precipitate, evolution of a gas, a change in color, and/or a pronounced temperature change. In this experiment, you will observe these characteristics of chemical reactions as copper is cycled through a series of reactions that produce a number of compounds. The cycle begins with cogysr metal and ends with cogner metal. Because no copper is added or removed between the beginning and end of the experiment, and because each reaction goes to completion, you should theoretically be able to quantitatively recover all the copper you stanted with as long as you are careful and skillful. This is an example of the law of conservation of matter, which states that matter is neither created nor destroyed during a chemical reaction. In the end, you will compare the mass of the copper you recovered to the mass of your starting material to determine how well you were able to carry out the experimental techniques with the equipment available. Three major types of reactions are encountered in this experiment, including precipitation reactions, redox reactions, and acid-base reactions. Precipitation reactions result in the formation of a solid when two solutions are mixed. The solid is called a precipitate (ppt). You observed several examples of this type of resction in the last experiment. Redox reactions involve the transfer of electrons from one chemical substance to another. As a result of the process, one substance loses electrons and another gains them. The substance that loses electrons becomes more positive in charge, and is said to be oxidized. The substance gaining electrons becomes more negative in charge and is said to be reduced. "Redox" is a combination of these terms. Redox reactions often involve the reduction (Cu
2+
to Cu) or the oxidation (Cu
to
Cu
2
) of a metal. Acid-base reactions in general are reactions involving a transfer of hydrogen ions, H
’.
. from an acid substance to another substance - the base. If a reaction yoa observe in this experiment does not involve a precipitate or redox, then it is likely an acid-base H
+
transfer. Look to see if an acid or base substance is one of the reactants involved. As you carry out each step of the cycle of copper reactions think about what is happening in each reaction, and try to fit it into one of the three categories just deseribed. Along the way. you will ste how a single element and its ions can exhibit different colors depending both on the charge on the ion and the nature of its environment. SAFETY Safety information for this lab is mentioned throughoat the procetare, Be sure to pay attention to the safety concerns, Wear gloves! PRE-LAB #5: CHEMICAL REACTIONS OF COPPER: NAME: 1. What is/are the Question(s) of the Day? 2. Balance all five reactions listed in the procedure. (Write it in the procedure, not here). 3. Write the chemical equation for the reaction of copper (II) hydroxide and hydrochloric acid to give copper (II) chloride and water (note: don't forget to balance). This is an example of an acid-base reaction. Label the acid and the base reactants. 4. Write the formula and name for the solid that copper (HI) hydroxide becomes when beated. 5. Watch the video posted on Brightspace to revicw about how to properly use an analytical balance. Outline the key steps below and state how many decimal places can be measured (are signiffeant) with this type of balance? How many decimal places can be measure with a standardrop-loading balance? 6. A student was given a sample of Cu wire that weighed 0.3015 grams, After completing the experiment, she recovered only 0.2331 grams of solid copper. What was her percent recovery? See Tutorial 1, p. 140 in this lab manual.
Answers
The main questions in the pre-lab assignment are:
1. What is/are the Question(s) of the Day?
2. Balance all five reactions listed in the procedure.
3. Write the chemical equation for the reaction of copper (II) hydroxide and hydrochloric acid to give copper (II) chloride and water.
4. Write the formula and name for the solid that copper (II) hydroxide becomes when heated.
5. Outline the key steps for properly using an analytical balance and indicate the number of decimal places that can be measured.
6. Calculate the percent recovery for a student who obtained 0.2331 grams of solid copper from a sample that initially weighed 0.3015 grams.
In the given pre-lab assignment, there are several questions and tasks related to the upcoming lab session on the chemical reactions of copper. The first question asks about the "Question(s) of the Day," which is not explicitly mentioned in the provided text. It might refer to the specific focus or objectives of the lab session.
The second task requires balancing all five reactions listed in the procedure, which is expected to be completed in the designated procedure section of the assignment, not in this particular section.
The third question asks to write the chemical equation for the reaction between copper (II) hydroxide and hydrochloric acid, producing copper (II) chloride and water. This reaction is an example of an acid-base reaction. In the equation, it is important to label the acid and base reactants.
The fourth task involves writing the formula and name for the solid that copper (II) hydroxide becomes when heated. The provided information does not mention the exact outcome, so it might be necessary to refer to additional resources or experimental data to determine the formula and name of the resulting solid.
The fifth task is to outline the key steps for properly using an analytical balance. The explanation should also include the number of decimal places that can be measured with this type of balance. It is important to follow the guidelines provided in the video posted on Brightspace, which will likely cover the necessary steps for accurate measurements using an analytical balance.
The final task involves calculating the percent recovery for a student who obtained 0.2331 grams of solid copper from a sample initially weighing 0.3015 grams. The formula for percent recovery is determined by dividing the actual yield (0.2331 g) by the theoretical yield (0.3015 g) and multiplying by 100%. The resulting percentage indicates how successful the student was in recovering the copper.
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what is the answer for
-16+x=-15
Answers
Answer:
x=1
Step-by-step explanation:
-16+x=-15
-16+x+16=-15+16 Add the terms to both sides of the equation.
After that you simplify.
Add:
2:7 + 2/3
URGET HELP ASAP
Answers
Answer:
4:10
Step-by-step explanation:
No matter what even if fractions are similar to quotiants they aren't the same so if it was fractions this would be a improper fraction but in this case it isn't because they are totally different topics and ranks.
The basketball tournament began at 8:00 a.m. The championship game ended at 7:00 p.m. How long did the basketball tournament last?
Answers
-1 hour is 11 hours
It lasted 11 hours
Write an integer to represent the following situation:A loss of 20 yards
Answers
Answer:
wth is your pfp lol I'm sory
The correct integers to represent the situation ''A loss of 20 yards'' is,
⇒ - 20
What is mean by Subtraction?Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.
We have to given that;
The situation is,
⇒ A loss of 20 yards.
Since, Here A loss of 20 yards.
Hence, It represented by the integer '- 20' because of loss.
Thus, The correct integers to represent the situation is,
⇒ - 20
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(15 POINTS!)
The slope of the line passing through the points (7, 5) and (21, 15) is
5/7
7/5
5
7
Another line with a slope that is one-third that of the slope you just calculated passes through the origin and the point
3, 5
3, 7
21, 5
21, 7
Answers
Answer:
1) 5/7
2) (21, 5)
Step-by-step explanation:
1) The slope of the line passing through the points (7, 5) and (21, 15) is
\(\frac{15-5}{21-7} =\frac{10}{14}=\frac{5}{7}\)
because slope is (difference of y)/(difference of x)
the first option is correct
2) 1/3 of 5/7 is 5/21.
The line will be in the form of
y = 5/21 x + b where b is the y-intercept.
Find the complete equation by plugging in (0,0) since it passes thorugh the origin.
0 = 5/21 (0) +b
0=0+b
b=0
The equation: y=5/21 x
let's check each option by plugging in.
y= 5/21 (3)= 5/7
y is not 5 but 5/7
y= 5/21 (3)= 5/7
y is not 7 but 5/7
y= 5/21 (21) = 5
y is 5, which matches with the answer choice!!!
y= 5/21 (21) = 5
y is 5, not 7.
The third option is correct
a researcher is conducting an anova test to measure the influence of the time of day on reaction time. participants are given a reaction test at three different periods throughout the day: 7 a.m., noon, and 5 p.m. in this design, there are factor(s) and level(s). a. two; three b. one; three c. two; six d. three; one
Answers
The correct option is (a) two factors and three levels. The design has two factors (time of day) and three levels (7 a.m., noon, and 5 p.m.).
In this research design, the factor is the time of day and it has three levels: 7 a.m., noon, and 5 p.m. The researcher is conducting an ANOVA test to measure the influence of the time of day on reaction time.
The factor is the time of day, and it has three levels: 7 a.m., noon, and 5 p.m. The ANOVA test will help determine if there are any significant differences in reaction times between these three periods throughout the day.
Therefore, the design has two factors (time of day) and three levels (7 a.m., noon, and 5 p.m.). The ANOVA test will be used to analyze the influence of the time of day on reaction time.
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Look at the image for the problem, also round to the nearest hundredth if necessary.
Answers
ANSWER
\(V=3052.08ft^3\)EXPLANATION
We want to find the volume of the sphere.
The volume of a sphere is given as:
\(V=\frac{4}{3}\cdot\pi\cdot r^3\)where r = radius of the sphere.
Therefore, we have that the volume of the sphere is:
\(\begin{gathered} V=\frac{4}{3}\cdot3.14\cdot9^3 \\ V=3052.08ft^3 \end{gathered}\)That is the volume of the sphere.
If there are 35% women and 1560 men in a town find the total population of the town.
Answers
Answer:
2400Step-by-step explanation:
x - total of population
35%x - women
1560 - men
35%x + 1560 = x
0.35x + 1560 = x
1560 = x - 0.35x
0.65x = 1560
÷0.65 ÷0.65
x = 2400
hree dice are tossed, one red, one blue, and one green. what outcomes make up the event a that the sum of the three faces showing equals 5?
Answers
The outcome that makes up the event a that the sum of the three faces showing equal 5 is; P(E) = 1/36
There are three dice, thus.
Set the Red die to R.
Set the Blue die to B.
Green Dice should be G.
Now, none of the six potential numbers can be bigger than 3 in order for the sum of the three numbers on all dice to equal 5.
So, P(R) = 3/6.
Now, if P(R) = 3/6, none of the other 2 dice can produce 3 or more because doing so would cause the sum to exceed the necessary 5.
So, P(B) = 2/6.
Now that P(R) and P(B) have been obtained, P(Y) must be 1/6.
As a result, P(E) = 3/6 2/6 1/6 is the result that constitutes the event that the sum of the three faces shown equals 5.
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Find the extremum of f(x,y) subject to the given constraint, and state whether it is a maximum or a minimum. f(x,y)=31−x^2−y^2;x+5y=26 There is a____ value of____ located at (x,y)= (Simplify your answers.)
Answers
The correct answer is "minimum value of 25 located at (x,y)= (3/2,5/2). "Given the function `f(x,y)=31−x²−y²` and the constraint `x+5y=26`. We need to find the extremum of f(x,y) and state whether it is a maximum or a minimum.We can use the method of Lagrange Multipliers to solve the given problem.
Using the method of Lagrange Multipliers, the solution to the problem is given by the following steps:
Step 1: Find the gradient of the function `f(x,y)` and the constraint `g(x,y)` at `(x,y)` respectively. Gradient of `f(x,y)` is given by:
∇f(x,y) = (-2x, -2y)
Gradient of `g(x,y)` is given by:∇g(x,y) = (1, 5)
Step 2: Using the method of Lagrange Multipliers, we equate the gradient of `f(x,y)` to the product of `λ` and the gradient of `g(x,y)`. That is, ∇f(x,y) = λ∇g(x,y) or (-2x, -2y) = λ(1, 5)
This gives us two equations as shown below: `-2x = λ` ...(i). `-2y = 5λ` ...(ii)
Step 3: We also have the constraint that `x+5y=26`.
So, we substitute `y` as `(26-x)/5` in equation `(ii)` above.
This gives us:
`-2(26-x)/5 = 5λ`
Solving the above equation for `x` gives `x= 13 - 5λ`.
Substituting this value of `x` in equation `(i)`, we have `-2(13-5λ) = λ`.
Solving for `λ`, we get `λ= -1`.
Step 4: Substituting the value of `λ` in equation `(ii)` above, we get `-2y = 5(-1)`. This gives `y= 5/2`.
Step 5: Using the value of `y`, we can find the value of `x` using the constraint that `x+5y=26`. This gives `x= 3/2`.Therefore, there is a minimum value of `25` located at `(x,y) = (3/2, 5/2)`.
Hence, the correct answer is "minimum value of 25 located at (x,y)= (3/2,5/2)."
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Is 4.259462364423... Rational or irrational? Is 3.12 (the 2 has a bar over it) rational or irrational? Is √78 (the 78 has a bar over it connected to the checkmark) rational or irrational? Is √121 (the 121 has a bar over it connected to the checkmark) rational or irrational?
Answers
Answer:
irrational
Step-by-step explanation:
I took the test and got a 100
Use the formula for continuous compounding to compute the balance in the account 1, 5, and 20 years. Also, find APY for the account. A 10,000 deposit in an account with an APR of 3.5%.
Answers
We are given the following information:
Deposit = $10,000
APR = 3.5% = 0.035
The balance in the account is given as shown below:
\(undefined\)a typical ten-pound car wheel has a moment of inertia of about 0.35kg⋅m2. the wheel rotates about the axle at a constant angular speed making 70.0 full revolutions in a time interval of 3.00 s .
Answers
To solve this problem, we can use the equation relating angular speed, angular displacement, and time:
Angular speed (ω) = Angular displacement (θ) / Time (t)
In this case, the wheel makes 70.0 full revolutions, which is equivalent to an angular displacement of 70.0 * 2π radians. The time interval is given as 3.00 seconds.
We can rearrange the equation to solve for angular speed:
Angular speed (ω) = (Angular displacement (θ)) / (Time (t))
ω = (70.0 * 2π) / 3.00
To calculate the angular speed, we substitute the given values into the equation: ω = (70.0 )(2π) / 3.00 ≈ 369.8 radians/second
Therefore, the angular speed of the wheel is approximately 369.8 radians/second.
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Find the volume of the cylinder . Round to the nearest tenth. r = 5 cm 5 cm V=[?]cm^ 3
![Find the volume of the cylinder . Round to the nearest tenth. r = 5 cm 5 cm V=[?]cm^ 3](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/j3fEthi55WUR7FOmChv3mBt46ClmkcP4.png)
Answers
Answer:
V = 392.70 cm³
Step-by-step explanation:
Volume of a cylinder = πr²h
V = 22/7 * 5² * 5
V = 392.70 cm³
Answer: Acellus uses 3.14 for pi, so 5^2*5*3.14 is 392.5
Step-by-step explanation: 392.5
HELPPPPPPP 1.The expression p−0.15p can be used to calculate the final cost of an item that has a price of p and is discounted 15%.
What is the final cost of an item that has an original price of $23?
2.6t+3
3.2t−3
4.t2
Answers
Answer:
Answer is in the attachment
brainliest?! plzzzzzzzzzzz
Answers
Answer:
F
Step-by-step explanation:
she spins it 2 times and there's 4 different spinners on the board
there's 1 * on the board so
* = 1/4
there's 1 & on the board so
& = 1/4
its 1/4 for both
so 1/4 + 1/4 = 2/8 or .25
2/8 = 1/4
Answer:
f
Step-by-step explanation:
The area of a square of side X is 8. What's the area of a square of side 3x
Answers
Answer:
Step-by-step explanation:
We know, for square
\((side)^2=(Area)\\=>X^2=8\\\)
∴\(X=2\sqrt{2}\) unit
\(Now, Side=3X\)
\(Then,Area=(3X)^2=(3*2\sqrt{2} )^2=(6\sqrt{2} )^2=72 sq. unit\)
hope you have understood this...
pls mark my answer as the brainliest
The area of square of side 3X is 72 square unit.
What is square?The square is a 4 sided figure, each side of the square is equal and make a right angle.
The area of square having sided a unit can be given by a² square unit.
Given that,
Area of square having side X is 8.
Since, formula for area of square having side X is X².
Implies that,
X² = 8
X = 2√2
The area of square having side 3X
side =3 × 2√2
side = 6√2
The area of square = (6√2)²
= 36 x 2
= 72
The area of square is 72 square unit.
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Michael picks three different digits from the set { } 12345 ,,,, and forms a mixed number by placing the digits in the spaces of . The fractional part of the mixed number must be less than 1. (For example, 4 2 3 ). What is the difference between the largest and smallest possible mixed number that can be formed?
Answers
Answer:
The largest number =5 3/4
The smallest number =1 2/5
Required difference = 5 3/4 − 1 2/5 = 4 7/2
I could be very off. hope it helps somehow
what is the equation of the line that contains the point (2,3) and has a slope of - 3/2
Answers
equation of line
y=mx+b
If m=-3/2
we have
\(\begin{gathered} y=mx+b \\ y=-\frac{3}{2}\cdot x+b \end{gathered}\)From points (2,3), we find b
\(\begin{gathered} y=-\frac{3}{2}\cdot x+b \\ 3=-\frac{3}{2}\cdot2+b \\ 3=-3+b \\ b=6 \end{gathered}\)Therefore
\(y=-\frac{3}{2}\cdot x+6\)Given independent events AA and BB such that P(A)=0.3P(A)=0.3 and P(B)=0.5P(B)=0.5, which of the following is a correct statement?
Answers
The correct statement is: P(A and B) <= 0.3 * 0.5 = 0.15.
The probability of A and B both occurring is denoted by P(A and B). If A and B are independent events, then the probability of both events occurring is given by the product of their individual probabilities, that is P(A and B) = P(A) * P(B). Therefore, P(A and B) = 0.3 * 0.5 = 0.15.
To understand why this statement is correct, we need to understand the concept of independence and multiplication rule of probability. When two events are independent, the occurrence of one event does not affect the occurrence of the other. In other words, the probability of one event occurring is not affected by the occurrence of the other event.
The multiplication rule of probability states that if two events A and B are independent, then the probability of both events occurring together is given by the product of their individual probabilities, that is P(A and B) = P(A) * P(B).
In this case, we are given that events A and B are independent, and their individual probabilities are P(A) = 0.3 and P(B) = 0.5. Therefore, we can calculate the probability of both events occurring together as follows:
P(A and B) = P(A) * P(B)
= 0.3 * 0.5
= 0.15
This means that the probability of both events occurring together is less than or equal to 0.15. This statement is correct because the multiplication of probabilities can never result in a probability greater than the smaller of the two individual probabilities.
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Flying against the , a jet travels 2850 miles in 3 hoursFlying with the Jetstream, the same travels 8190 miles in 7 hours. What is the rate of the in still and what is the rate of the Jetstream ?
Answers
Answer:
ASK
ALGEBRA
Joey C. asked • 07/15/15
Flying against the wind, a jet travels 1860 mi in 3 hours.
Flying against the wind, a jet travels 1860 mi in 3 hours. Flying with the wind, the same jet travels 9180 mi in 9 hours. What is the rate of the jet in still air and what is the rate of the wind?
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Andrew M. answered • 07/15/15
TUTOR New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
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Let J = rate of jet in still air
Let W = rate of wind
Distance formula: d = rt so r = d/t
Flying against the wind the Jet flies at a rate of J - W = 1860mi/3hrs = 620 mph
Flying with the wind the Jet flies at a rate of J+W = 9180mi/9hrs = 1020 mph
The average of these two rate is the speed of the Jet in still air
J = (620+1020)/2 = 820 mph
J - W = 620 so
820 - W = 620
W = 820 - 620 = 200 mph
The Jet in still air flies at a rate of 820 mph
The wind speed is 200 mph
A wall of a building is 30 inches wide.Sixteen inches is concrete,10 inches is brick, and 4 inches is limestone . What fraction of the wall is limestone
Answers
Answer:
\(Fraction = \frac{2}{15}\)
Step-by-step explanation:
Given
Wall = 30 inches
Concrete = 16 inches
Brick = 10 inches
Limestone = 4 inches
Required
Fraction of the wall that is limestone
The fraction of limestone is calculated as follows;
\(Fraction = \frac{Size\ of\ limestone}{Size\ of\ wall}\)
Substitute 4 for size of limestone and 30 for size of size of wall
The formula becomes
\(Fraction = \frac{4}{30}\)
Divide numerator and denominator by 2
\(Fraction = \frac{4/2}{30/2}\)
\(Fraction = \frac{2}{15}\)
The fraction can not be further simplified; hence, the fraction of limestone is \(\frac{2}{15}\)
Answer:
2/15
Step-by-step explanation:
Fractions can be found by dividing the part by the whole.
part/whole
In this problem, the part is the limestone portion of the wall and the whole is the total width of the wall.
limestone/total
16 inches are concrete, 10 inches are brick and 4 inches are limestone. The total width is 30 inches.
limestone = 4
total = 30
4/30
This fraction can be simplified. Both the numerator and denominator can be evenly divided by 2.
(4/2) / (30/2)
2/ (30/2)
2/15
This fraction cannot be simplified further, therefore it is our answer.
2/15 of the wall is limestone.
which equation generates the value in the table
Answers
Answer:
A
Step-by-step explanation: