Construct the resonance structure for CSO, which has a formal charge of +2 on the central atom and +1 on the oxygen atom.

Answer:

1,4,6,7

Explanation:

Electrons have a negitive charge and are outside of the nucleus and have the same atomic number and have the same number os nutrons.

Answer:

Approximately \(81.84\%\).

Explanation:

Balanced equation for this reaction:

\({\rm Na_{2}CO_{3}}\, (aq) + {\rm CaCl_{2}} \, (aq) \to 2\; {\rm NaCl}\, (aq) + {\rm CaCO_{3}}\, (s)\).

Look up the relative atomic mass of elements in the limiting reactant, \(\rm CaCl_{2}\), as well as those in the product of interest, \(\rm CaCO_{3}\):

Calculate the formula mass for both the limiting reactant and the product of interest:

\(\begin{aligned}& M({\rm CaCl_{2}}) \\ &= (40.078 + 2 \times 35.45)\; {\rm g \cdot mol^{-1}} \\ &= 110.978\; \rm g \cdot mol^{-1}\end{aligned}\).

\(\begin{aligned}& M({\rm CaCO_{3}}) \\ &= (40.078 + 12.011 + 3 \times 15.999)\; {\rm g \cdot mol^{-1}} \\ &= 100.086\; \rm g \cdot mol^{-1}\end{aligned}\).

Calculate the quantity of the limiting reactant (\(\rm CaCl_{2}\)) available to this reaction:

\(\begin{aligned}n({\rm CaCl_{2}) &= \frac{m({\rm {CaCl_{2}})}}{M({\rm CaCl_{2}})} \\ &= \frac{17.87\; \rm g}{110.978\; \rm g \cdot mol^{-1}} \\ &\approx 0.161023\; \rm mol \end{aligned}\).

Refer to the balanced equation for this reaction. The coefficients of the limiting reactant (\(\rm CaCl_{2}\)) and the product (\({\rm CaCO_{3}}\)) are both \(1\). Thus:

\(\displaystyle \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} = 1\).

In other words, for every \(1\; \rm mol\) of \(\rm CaCl_{2}\) formula units that are consumed, \(1\; \rm mol\!\) of \(\rm CaCO_{3}\) formula units would (in theory) be produced. Thus, calculate the theoretical yield of \(\rm CaCO_{3}\!\) in this experiment:

\(\begin{aligned} & n(\text{${\rm CaCO_{3}}$, theoretical}) \\ =\; & n({\rm CaCl_{2}}) \cdot \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} \\ \approx \; & 0.161023\; {\rm mol} \times 1 \\ =\; & 0.161023\; \rm mol\end{aligned}\).

Calculate the theoretical yield of this experiment in terms of the mass of \(\rm CaCO_{3}\) expected to be produced:

\(\begin{aligned} & m(\text{${\rm CaCO_{3}}$, theoretical}) \\ = \; & n(\text{${\rm CaCO_{3}}$, theoretical}) \cdot M(({\rm CaCO_{3}}) \\ \approx \; & 0.161023\; {\rm mol} \times 100.086\; {\rm g \cdot mol^{-1}} \\ \approx \; & 16.1161\; \rm g \end{aligned}\).

Given that the actual yield in this question (in terms of the mass of \(\rm CaCO_{3}\)) is \(13.19\; \rm g\), calculate the percentage yield of this experiment:

\(\begin{aligned} & \text{percentage yield} \\ =\; & \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\% \\ \approx \; & \frac{13.19\; {\rm g}}{16.1161\; {\rm g}} \times 100\% \\ \approx \; & 81.84\%\end{aligned}\).

We have a hot piece of metal that is put in water, and the metal and water are allowed to come to an equilibrium. We can consider that no heat is lost. So the amount of heat that the piece of metal is losing, is gained by the water. The piece of metal is heating the water. We can write that as:

Q water = - Q metal

Then the general formula for the heat of anything is:

Q = m * C * ΔT

So:

Qwater = - Qmetal

mw * Cw ΔTw = -

The new planet is suitable for human life because it is similar to planet earth.

The new planet has similar atmosphere just like the earth's atmosphere. It has large amount of vegetation that can hold large amount of animals. It is suitable for growing for different crops that provide food to humans.

So we can conclude that the new planet is suitable for human life because it is similar to planet earth.

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A 7.99 g sample of sodium bromide contains 1.786 g of sodium.

Since the percentage of sodium in NaBr is given, we can calculate the mass of sodium and bromide in the 14.47 g sample as follows:

Mass of sodium = 22.34% × 14.47 g = 3.23 g

Mass of bromide = 14.47 g - 3.23 g = 11.24 g

Now, we need to find the mass of sodium in a 7.99 g sample of sodium bromide. We can use the proportion:

Mass of sodium / Mass of NaBr = Mass of sodium in 7.99 g NaBr / 7.99 g

Rearranging and substituting the values, we get:

3.23 g / 14.47 g = x / 7.99 g

Solving for x, we get:

x = 3.23 g × 7.99 g / 14.47 g = 1.786 g

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Answer:

its a scientific model

Explanation:

It is a scientific model because it is showing the water cycle. In the water cycle it is scientifically showing how water circulates through the Earth. For example, the water in the ocean evaporates which is evaporation, then it condensates into a cloud that then becomes condensation and the condensation makes precipitation when it rains. When it falls to the ground, it then becomes a runoff down a hill.

Answer:

1. The partial pressure of Br₂ is 0.118951 atm 2) The value of Kp is 2.843 × 10².

Explanation:

1. The reaction at equilibrium will be:

2NOBr (g) ⇒ 2NO (g) + Br₂ (g)

The partial pressure of PNOBr is 0.363 atm, the partial pressure of NO is 0.421 atm, there is a need to find the partial pressure of Br₂, the value of Kp is 0.160. For the given reaction,

Kp = [PNO]² × [PBr₂] / [PNOBr]²

0.160 = [0.421]² × [PBr₂] / [0.363]²

0.160 = [0.177241 × [PBr₂] / 0.131769

[PBr₂] = 0.131769 × 0.160 / 0.177241

[PBr₂] = 0.118951 atm

The partial pressure of Br₂ is 0.118951 atm.

2) The reaction will be,

2NH₃ ⇔ N2 (g) + 3H₂ (g)

Kp is the equilibrium constant, and its value will be,

Kp = [PN₂] × [PH₂]³ / [PNH₃]² ------------------(i)

Considering the reactants in terms of molarity will be,

Kp = [N2] × [H₂]³ / [NH₃]²

Here, [N2] = 0.297 / 16.6 = 0.017892 M

[H₂] = 0.320/16.6 = 0.019277 M

[NH₃] = 3.53 × 10⁻⁴ / 16.6 = 2.12651 × 10⁻⁵ M

Now putting the values in equation (i) we get,

Kp = [0.017892] × [7.16399 × 10⁻⁶] / [4.52204 × 10⁻¹⁰]

Kp = 0.128167 × 10⁻⁶ / 4.52204 × 10⁻¹⁰

Kp = 2.8343 × 10²

Hence, the equilibrium constant is 2.8343 × 10²

Answer:

The correct rank of cycloalkanes in order of increasing ring strain per methylene is:

Cyclohexane < Cyclopentane < Cyclobutane < Cyclopropane.

Ring strain occurs because carbons in cycloalkanes are sp3 hybridized, so their expected ideal bond is of 109.5°. Therefore in cycloalcanes with angles smaller than 109.5° the potential energy increases.

The correct order is the given above because the shape of the molecules determines the angle between the carbon atoms and the ring strain resulting grows from cyclohexane to cyclopropane.

A  substance can dissolve in another when they have thee same type of intermolecular interaction.

The term solubility of a solute refers to the extent to which a solute dissolve in a solvent. We must know that a substance can dissolve in another when they have thee same type of intermolecular interaction.

Thus;

a) Octane (C8H18) mixes well with CCl4 because they are both non polar substances.

b) Methanol (CH3OH) is mixed with water in all ratios because the both are polar substances.

c) NaBr dissolves very poorly in acetone (CH3 ― CO ― CH3) because acetone is only slightly polar.

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Clofibrate is a lipid-lowering pharmaceutical that has been utilized to treat hyperlipidemia. Its metabolism system includes different pathways such as hydrolysis, oxidation, conjugation, and others.

Metabolites are little molecules that are produced during the process of  metabolism in living living beings.

Clofibrate hydrolysis metabolite:

Clofibrate oxidation metabolites:

Clofibrate alkylation metabolites:

Clofibrate conjugation metabolites:

Conclusively, the relative abundance and significance of each metabolite can vary among individuals.

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The ideal gas law may be used to determine the volume of oxygen created in the electrolysis that produces 548 litres of hydrogen at STP (Standard Temperature and Pressure). PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature, according to the ideal gas equation.

The pressure is 1 atm, the temperature is 273 K, and the number of moles of hydrogen is 548/22.4 = 24.5 in this example. We may compute the volume of oxygen created by rearranging the ideal gas law: V = nRT/P = 24.5*0.082*273/1 = 483.3 litres.

As a result, the volume of oxygen created in the electrolysis at STP that produces 548 litres of hydrogen is 483.3 litres.

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Answer:

Stoichiometric Calculation:

3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

2 moles of HNO₃ is produced from 3 moles of NO₂.

Therefore, By unitary method:

2.30 moles of HNO₃ produced from the moles of NO₂ = \( \dfrac{3}{2} \times 2.30 = \bf{3.45 mol}\)

The number of moles of NO₂ that would be required to produce 2.30 moles of HNO₃ in the presence of excess water in the chemical reaction is 3.45 moles

The balance equation is as follows:

3NO₂(g) + H₂O (l) → 2HNO₃(g) + NO(g)

Water molecules is in excess. Therefore, the limiting reagent is Dinitrogen oxide.

The limiting reagent will determine the amount of product produced.

Therefore,

2 moles of HNO₃ needs 3 moles of NO₂

2.30 moles of HNO₃ will need ? moles of NO₂

cross multiply

number of moles of NO₂  = 2.30 × 3 / 2

number of moles of NO₂  = 6.9 / 2

number of moles of NO₂  = 3.45 moles

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Answer

False

Explanation:

Answer:

CHO

Explanation:

Carbon = 41%,  Hydrogen = 4.58%, oxygen = 54.6%

Step 1:

Divide through by their respective relative atomic masses

41/ 12,         4.58/1,         54.6/16

3.41              4.58            3.41

Step 2:

Divide by the lowest ratio:

3.41/3.41,      4.58/3.41,     3.41/3.41

1,                    1,                  1

Hence the empirical formula is CHO

Answer:

The empirical formula of X is C3H4O3.

Explanation:

Answer:2

Explanation:

He

Given that the nitric acid solution contains 70% nitric acid, this means that for every 100g of the solution, there are 70g of nitric acid. Hence, the remaining 30g is water.Since the question requires the molarity of the solution, we need to first calculate the number of moles of nitric acid in the solution.

Number of moles of nitric acid = Mass of nitric acid / Molar mass of nitric acid Molar mass of nitric acid, HNO3 = 1(atomic mass of hydrogen) + 14(atomic mass of nitrogen) + 3(atomic mass of oxygen) = 63 g/mol For the given solution,Mass of nitric acid = 70g Number of moles of nitric acid = 70/63 = 1.1111 mol Now, we need to calculate the volume of the solution containing 1.1111 mol of nitric acid.

Assuming the density of the solution to be 1 g/mL, the volume of the solution containing 1.1111 mol of nitric acid is given by,Volume of solution = 1.1111 mol / 1 g/mL = 1.1111 L Thus, the molarity of the nitric acid solution is: Molarity, M = Number of moles / Volume of solution M(HNO3) = 1.1111 mol / 1.1111 L = 1 M Ans: M(HNO3) = 1 M

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Answer:

SF2(aq) → S²⁺(aq) + 2F-(aq)

Explanation:

The sulfur difluoride, SF2, dissolves in water because the differences in electronegativities are considerable (3.98 for Fluorine and 2.58 for S) doing the F-S bond polar. As water is a polar solvent will dissolve the SF2 as follows:

As Fluorine has a > electronegativity than S, the Fluorine will be negative and S will be positive. Also, all halogen ions has a charge of -1.

Explanation:

A) Atoms are neither created nor destroyed

number of atoms in the reactant is always equal to the number of atoms in the product and hence, option A is the right answer

Physics is a vast field that addresses a wide range of questions about the nature of the physical world. Probing questions can help to explore this field and encourage critical thinking and deep exploration of its topics.

Probing questions are open-ended questions asked to gather information, encourage critical thinking and deep exploration of a particular topic. Physics is a natural science that studies matter and its motion through space-time. It is a branch of science that deals with the fundamental nature of the universe and seeks to explain how and why objects behave as they do in the physical world.The following are some examples of probing questions within the scope of physics:What is the nature of light-The nature of light is an important topic within the scope of physics. It refers to the dual nature of light, as both a wave and a particle. Light behaves as a wave when it is traveling through space and as a particle when it is interacting with matter.How do magnets work-Magnets are a common object in the world around us, and they have a broad range of applications. They work by producing a magnetic field, which can attract or repel other magnetic objects. This topic lies within the scope of physics.What is the relationship between energy and matter-Energy and matter are two fundamental concepts in physics. The relationship between them is described by Einstein's famous equation E=mc2, which states that matter and energy are two forms of the same thing and are interchangeable. The study of the relationship between energy and matter lies within the scope of physics.What is the nature of the universe?The study of the universe's nature is one of the most significant topics within the scope of physics. This question addresses the origins and properties of the universe, its components, and the laws that govern its behavior.

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Answer:

Explanation:

When two non-miscible liquids are put together, the one with the higher density will be on the bottom, while the one with the lower density will be on top.

Meaning that in this problem's case toluene would be on the top layer and water in the bottom layer.

78.2g is the mass in grams of potassium chloride is produced if 21.0g of potassium metal.

A body's mass is an inherent quality. Prior to the discoveries of the atom as well as particle physics, it was widely considered to be tied to the amount of matter within a physical body. It was discovered that, despite having the same quantity of matter in theory.

Different atoms and elementary particles have varied masses. There are various conceptions of mass in contemporary physics that are theoretically different but physically equivalent.

2K + Cl\(_2\) →2KCl

moles of K = 21.0/ 20=1.05 moles

according to stoichiometric ratio

moles of KCl = 1.05 moles

mass of KCl =  1.05×74.5

                    = 78.2g

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Answer:

g. red, orange, yellow, blue

Explanation:

red is the hottest color and blue is the coolest. :)

The mass of chlorine gas product formed is 61.4 g.

What is the mass ?

First, we need to determine which reactant is limiting and which is in excess. To do this, we can use the given mass of HCl and convert it to moles:

63.2 g HCl × (1 mol HCl/36.46 g HCl) = 1.73 mol HCl

Next, we can use stoichiometry to determine how many moles of \(Cl_{2}\) will be produced from 1.73 mol of HCl:

1.73 mol HCl × (2 mol \(Cl_{2}\)/4 mol HCl) = 0.865 mol \(Cl_{2}\)

Finally, we can convert the moles of \(Cl_{2}\) to grams using its molar mass:

0.865 mol \(Cl_{2}\) × (70.91 g \(Cl_{2}\)/1 mol \(Cl_{2}\)) = 61.4 g \(Cl_{2}\)

Therefore, the mass of chlorine gas product formed is 61.4 g.

What is stoichiometry ?

Stoichiometry is a branch of chemistry that deals with the calculation of the quantities of reactants and products involved in a chemical reaction. It involves using balanced chemical equations to calculate the amounts of reactants required to produce a certain amount of product, or the amount of product that can be obtained from a given amount of reactant. Stoichiometry is an important tool for predicting the outcomes of chemical reactions and for designing chemical processes in industry.

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The statement which accurately describes a light-year is " It is the distance that light travels in a year."

A light-year would be the actual distance a light beam is able to travel in one year on Earth, that would be roughly 6 trillion miles.

The region of the electromagnetic spectrum that the human eye perceives as light, as well as visible light, has been made up of electromagnetic radiation.

The statement which accurately describes a light-year is " It is the distance that light travels in a year."

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Answer: B

Explanation:

The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.

The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.

Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.

Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.

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What would be the same  about the scientist's model probe and the eventual full-scale version of the probe is that; . They would be the same size. Option A

It is likely that the scientist's model probe would be built to replicate the size and proportions of the full-scale version because this would be vital in determining if the full-scale probe could endure the punishing conditions of Jupiter's atmosphere. The dimensions of the model probe and the real probe would therefore likely be the same.

However, it's likely that the model probe's parts weren't exactly the same as those in the actual probe.

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Answer:

false trust me gang^^^

Explanation:

There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.

The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.

According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:

1000 ml - 3.50 moles

60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml

x= 60.2 ml -0.2107 moles

So, there are 0.2107 moles of KBr.

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Answer:

Maximum pressure P = 4.9 × 10⁻⁵ Pa

Explanation:

From the information given, the mean free path can be expressed with the formula:

\(\lambda = \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times P}\)

Making Pressure P the subject of the formula because we intend to find the maximum pressure, we have:

\(P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }\)

At standard conditions

R = gas constant = 8.314 J/mol.K

T = temperature at 25°C = (273 + 25) = 298 K

π = pi = 3.14

d = (364× 10⁻¹²m)²

\(N_A\) = avogadro's number = 6.023 × 10²³

λ = mean free path = 1.0 m

\(P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }\)

\(P= \dfrac{8.314 \ J/mol.K \times 298 \ K}{\sqrt{2}\times (3.14) \times (364 \times 10^{-12} \ m) ^2 \times 6.023 \times 10^{23}/mol \times 1.0 \ m }\)

P = 0.007 kg/m.s²

P = 0.007 Pa

\(P = 0.007 Pa \times \dfrac{0.007 \ torr}{1 \ Pa}\)

P = 4.9 × 10⁻⁵ Pa

Answer:

B.Anything that takes up space and has mass