Balance the following chemical equation using the ion-electron method. Cr₂O7+ H₂S → Cr³+S (in acidic solution)
​

Explanation:

The lower jaw (mandible), which also shapes the lower face and chin, supports the bottom row of teeth. The bone that moves when the mouth opens and shuts is this one. The upper jaw's (maxilla) function is to support the nose, hold the upper teeth, and shape the middle of the face.

To produce 11.00 moles of MgCl2, you would need 858.00 grams of NaOH.

To determine the amount of NaOH needed to produce 11.00 moles of MgCl2, we need to use stoichiometry and the balanced chemical equation:

\(MgCl_2 + 2 NaOH\) → \(2 NaCl + Mg(OH)_2\)

From the balanced equation, we can see that the mole ratio between \(MgCl_2\)and NaOH is 1:2.

Therefore, for every 1 mole of\(MgCl_2\), we need 2 moles of NaOH.

Given: Moles of \(MgCl_2\)= 11.00 moles

Using the mole ratio, we can calculate the moles of NaOH required:

moles of NaOH = 2 * moles of MgCl2

moles of NaOH = 2 * 11.00 moles

moles of NaOH = 22.00 moles

Now, we need to convert the moles of NaOH to grams using the molar mass of NaOH:

The molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol

grams of NaOH = moles of NaOH * molar mass of NaOH

grams of NaOH = 22.00 moles * 39.00 g/mol

grams of NaOH = 858.00 grams

Therefore, to produce 11.00 moles of \(MgCl_2\), you would need 858.00 grams of NaOH.

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Answer:

Ball and stick model is 3D and has the atoms depicted as different Coloured balls Conected to each other by "sticks"

fischer projection has the atoms on the side coming out of the plane, the atoms at the ends going behind (going away from you)

bond line notation Is the most common it does not show the C or H bonds but instead carbons are represented by the bends

The three structures of glucose represent three different models, they are ball and stick model, Fischer projection and bond line notation, respectively.

Glucose is a type of simple sugar (carbohydrate) that does not further hydrolyze to give monosaccharides.

Therefore, the three glucose structures reflect three distinct models: the ball and stick model, the Fischer projection, and the bond line notation, respectively.

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Answer:

2.4* 10⁴ m

Explanation:

1km = 1000m = 10³m

(1*24)km = 10³ * 24 m

=> 24km = 2.4 * 10⁴m

6.4875 moles of nitrogen gas would be produced if 8.65 moles of copper(II) oxide were reacted with excess ammonia.

Given the following balanced equation, 2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g). We are required to determine the number of moles of nitrogen gas that would be produced if 8.65 moles of copper(II) oxide were reacted with excess ammonia. We can use stoichiometry to solve this problem. Stoichiometry is the quantitative relationship between the reactants and products in a chemical reaction. It allows us to make predictions about the amount of product produced or reactant required in a chemical reaction. Stoichiometry relies on the balanced chemical equation for the reaction. In this case, the balanced chemical equation is 2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g).

The balanced chemical equation shows that 2 moles of ammonia react with 3 moles of copper(II) oxide to produce 1 mole of nitrogen gas and 3 moles of water. This means that the mole ratio of ammonia to nitrogen gas is 2:1. We can use this mole ratio to determine the number of moles of nitrogen gas produced in the reaction. We know that 8.65 moles of copper(II) oxide is reacted with excess ammonia. Since copper(II) oxide is the limiting reagent, we can use it to calculate the number of moles of ammonia used in the reaction. The molar ratio of copper(II) oxide to ammonia is 3:2. Therefore, we can calculate the number of moles of ammonia used in the reaction as follows:Number of moles of ammonia = (3/2) × number of moles of copper(II) oxideNumber of moles of ammonia = (3/2) × 8.65Number of moles of ammonia = 12.975 molesWe know that the mole ratio of ammonia to nitrogen gas is 2:1. Therefore, the number of moles of nitrogen gas produced in the reaction is half the number of moles of ammonia used.Number of moles of nitrogen gas produced = (1/2) × number of moles of ammoniaNumber of moles of nitrogen gas produced = (1/2) × 12.975Number of moles of nitrogen gas produced = 6.4875 moles.

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White vinegar typically consists of 93%–96% water and 4–7% acetic acid. It can be used to cooking, bake, cleaning, and get rid of weeds. It can also help you lose weight and lower your blood sugar and cholesterol. Consumption is safe in moderation, but excessive consumption or when combined with certain medications could be harmful.

Apple cider vinegar is widely used in cooking and as a salad dressing because it contains acetic acid and nutrients like vitamins C and B vitamins. But at the same time, it's been utilized customarily as medication. It helps in losing weight.

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Answer:

I can not see the file

Explanation:

Answer:

All of the listed factors can affect the potency of a drug.

Explanation:

All of the listed factors can affect the potency of a drug. Let's discuss each one:

The amount: The potency of a drug can be influenced by the dosage or amount administered. Generally, a higher amount of a drug can lead to a greater effect or potency. However, there may be optimal dosage ranges where the potency is maximized before plateauing or potentially causing adverse effects.

Concentration: The concentration of a drug refers to the amount of the drug present in a given volume or solution. A higher concentration of a drug can increase its potency since a greater quantity of the active substance is available to interact with the target receptors or sites.

Number of exposures: The number of times a person is exposed to a drug can also impact its potency. In some cases, repeated exposures can lead to an accumulation of the drug in the body, resulting in increased potency or stronger effects. However, this can also lead to tolerance, where the body becomes less responsive to the drug over time, requiring higher doses for the same effect.

Exposure method: The way a drug is administered or exposed to the body can affect its potency. Different routes of administration (e.g., oral, intravenous, inhalation, topical) can result in variations in the drug's absorption, distribution, and metabolism, which can influence its potency and onset of action.

It's important to note that potency is different from efficacy, which refers to the maximum therapeutic effect a drug can produce. Potency specifically relates to the amount of drug required to produce a particular effect.

We have a gas that we will assume behaves like an ideal gas. So we can apply the ideal gas law. The ideal gas law tells us:

Where,

P is the pressure of the gas

V is the volume of the gas

n is the moles of the gas

R is a constant

T is the temperature of the gas

We have two states of the gas. One initial and one final, for both states it is assumed that the moles remain constant. The conditions for each state are.

Initial state:

V1=2.3mL

P1=5.3atm

T1=45°C =318.15K

Final state:

V2=1.2L

P2=2.5atm

T2=?

For each state the ideal gas law will be:

Now, as the moles remain constant, the term nR will be constant and we can equate the two equations, we will then have that:

Now, we clear T2 and replace the known data:

The temperature of the gas will be 78.3K

Answer:

2.5 X 10^-43

Explanation:

CoS> Co + S

Co=X

S=X

X= 5.0 X 10^-22

Ksp= [X][X]

Ksp= [5.0 X 10^-22][5.0 X 10^-22]

Ksp= 2.5 X 10^-43

The Ksp for CoS is calculated as 2.5 × 10⁻⁶³ (mol/L)². This value represents the equilibrium constant for the dissociation of CoS in water and indicates the extent of its solubility in the solution.

The molar solubility of CoS is given as 5.0 × 10⁻²² mol/L. In the chemical equation for the dissolution of CoS in water, it dissociates into Co⁻²⁺ and S²⁻ ions.

The solubility product constant (Ksp) expression for CoS is written as:

Ksp = [Co²⁺] * [S²⁻]

Since CoS dissolves completely to form one Co²⁺ ion and one S²⁻ ion, we substitute the molar solubility values into the Ksp expression:

Ksp = (5.0 × 10⁻²² mol/L) * (5.0 × 10⁻²² mol/L)

Ksp = 2.5 × 10⁻⁴³ (mol/L)²

Therefore, the Ksp for CoS is calculated as 2.5 × 10⁻⁶³ (mol/L)². CoS has an extremely low solubility in water, resulting in an exceptionally small Ksp value.

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Answer:

la bombilla de flash contiene 0,00550 gramos de O2

Explanation:

Based on the given information, A is a molecule with the molecular formula C4H10O.

Chemical structure refers to the arrangement of atoms, bonds, and other chemical groups in a molecule. It describes the spatial orientation of the atoms in a molecule and how they are connected to each other. The chemical structure of a molecule can be represented using a variety of different notations, including molecular formulas, Lewis structures, condensed structures, and three-dimensional models.

Based on the given information, A is a molecule with the molecular formula C4H10O. There are different isomers of C4H10O that could potentially be A, but one possibility is n-butanol (also known as 1-butanol). The structure of n-butanol is:

H   H

\ /

 C

/ \

C   O

/ /

H H

Therefore, the structure of A (assuming it is n-butanol) is:

H   H

\ /

 C

/ \

C   O

/ /

H H

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:

Hydrogen-2 has one neutron, hydrogen-1 has none.

Explanation:

Answer:as below

Explanation:Zn(NO3)2 (aq) + 2 NaOH (aq) —> Zn(OH)2 (ppt) + 2NaNO3

Zn++ + 2NO3- + 2Na++ + 2OH- —> 2NO3- + 2Na+ + Zn(OH)2

Zn++ + 2OH- —> Zn(OH)2

spectator ions are Na, NO3

Like charges repel each other, while opposite charges attract each other. This principle is one of the fundamental aspects of electrostatics. According to Coulomb's law, the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

As the distance between two charged particles decreases, the force between them increases. This is because the closer the particles are, the stronger the electric field they create, leading to a stronger force of interaction.

On the other hand, as the magnitude of the charges decreases, the force between the particles also decreases. This is because the force is directly proportional to the product of the charges. If one or both of the charges are smaller, the force they exert on each other will be weaker.

In summary, according to Coulomb's law, decreasing the distance between charged particles increases the force between them, while decreasing the magnitude of the charges decreases the force. This understanding of the relationship between charge, distance, and force is crucial in explaining the behavior of charged particles and the interactions between them.

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Answer:

Seismologists

Explanation:

Big brain

The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A

In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).

When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.

Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.

In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.

The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A

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Answer:

Explanation:

Chemical reactions involve combining different substances. The chemical reaction produces a new substance with new and different physical and chemical properties. Matter is never destroyed or created in chemical reactions. The particles of one substance are rearranged to form a new substance.

Answer:

The chemical reaction produces a new substance with new and different physical and chemical properties. Matter is never destroyed or created in chemical reactions. The particles of one substance are rearranged to form a new substance. The same number of particles that exist before the reaction exist after the reaction.

Explanation: hope this helps

Answer:

B) In order to accurately identify the source of any blood. In order to thoroughly and accurately recreate the crime scene.

Answer:

Generally the ice should be more than 4 inches thick to skate on it safely. However, the ice thickness is not always even and there can be thin spots, especially near springs or near river inlets or outlets. Most lakes and ponds don't completely freeze because the ice (and eventually snow) on the surface acts to insulate the water below. Our winters aren't long or cold enough to completely freeze most local water bodies. This process of lakes turning over is critically important to the life in the lake.

Explanation:

Answer:

0.0730

Explanation:

decimal 0s don't count except for ones at the end

We are given:

Molar mass of air = 28.97 grams/mole

Amount of Air in question = 3.33 moles

Mass of 3.33 moles:

We know that:

mass = molar mass * number of moles

replacing the variables

mass = 28.97 \(\frac{grams}{mol}\) * 3.33 moles

[the 'mole' in the numerator and the denominator will cancel out]

mass = 28.97 * 33.3 grams

mass = 96.47 grams

Answer:

The reaction CO₂ + H₂O → C₆H₁₂O₆ + O₂ is exothermic because it releases energy. The energy is released because the bonds in the products (C₆H₁₂O₆ and O₂) are stronger than the bonds in the reactants (CO₂ and H₂O). Specifically, the reaction releases energy because the bonds between carbon and oxygen in CO₂ and the bonds between hydrogen and oxygen in H₂O are weaker than the bonds between carbon, hydrogen, and oxygen in C₆H₁₂O₆ and the bonds between oxygen atoms in O₂

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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The addition of \(O_2(g)\) will shift the equilibrium towards the right side of the reaction and will consume \(Cl_2(g)\).

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