As a student studying in South Korea, what changes you think must be made in the education system to make it better?​

Answers

Answer 1

Explanation:

studying hard is the only thing that could make the educational system better

Answer 2

I think the student when he studying first time then first he want to speak Korean and study hard for that but if he try then only he can be better

Explanation:

and he or she should have interest to study if he or she have interest then only their education will be better

and if he / she didn't have interest on study then we can't do anything........


Related Questions

Answer Questions below

Answer Questions below

Answers

Answer:

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1)   V=  60 volt

Total resistance R = R₁ + R₂

                              = 20 + 10

                              = 30 Ω

2) Ohms law states that,

           \(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)

3) Voltage around 10 Ω resistor,

          V₂ = I R₂

             = 2 * 10

              = 20 volt

___________________________________________________

4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

              R₁ = 2 Ω  ; I = 1 A

              V₁ = IR₁

                   = 1 * 2

                   = 2 volt

7) Resistance 2:

        Total resistance = R

        Total voltage = V = 8 volt

        Total current = I = 1 A

                  \(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)

                  R = 8 Ω

               R₁ + R₂ = 8 Ω

                2 + R₂ = 8

                      R₂  = 8 - 2

                      R₂ = 6 Ω

8)Voltage around R₂:

                  \(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)

                  V₂ = 6 volt

9) Total R = 8 Ω

_________________________________________________

10) Total V = 12 volt

11)  Total R = 8 + 8

                 = 16 Ω

12) Total current I,

                \(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)

13) Voltage at each resistor:

           V₁ = I*R₁

               = 0.75 * 8

               = 6 volt

         V₂ = I*R₂

              = 0.75 * 8

             = 6 volt

_______________________________________________________

     14) Total R =   40 + 20

                       = 60 Ω  

15) To find V₁, first find total voltage.

           I = 2 A ;  R = 60 Ω  

           V = IR    

              = 2 * 60

               = 120 V

        V₁ + V₂  =V

        V₁ + 80 = 120

                V₁ = 120 - 80

                 V₁ = 40 volt              

When one substance is converted into another, there is always an associated conversion T/F?

Answers

True, One form of energy is constantly turned into another when one substance is transformed into another.

Define energy.

Energy is the ability to do work. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc. Additionally, there is heat and work, which is energy being transferred from one body to another.

The process of converting energy from one form to another is called energy transformation or energy conversion. Electrical energy can be produced from chemical energy. Heat energy can be produced from thermal energy. Electrical energy, potential energy, etc. can be created from mechanical energy.

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Q2. A stone leaves a slingshot horizontally with an initial speed of 15.2 m/s from a
height 1.1 m above the ground. Determine the stone's:
a) total air time
b) maximum height
c) range
d) final velocity
Horizontal
VX =
dx = ?
t = ?
Vertical
dy = -1.1m
v1y =
v2y= ?
a =
t = ?

Answers

Answer:

Assume that \(g = 9.81\; {\rm m\cdot s^{-2}}\). Also assume that that the air resistance on this stone is negligible.

The total air time of this stone is approximately \(1.5\; {\rm s}\).

The maximum height of this stone is \(1.1\; {\rm m}\), same as the height of the slingshot.

The range of this stone is approximately \(23\; {\rm m}\).

The final velocity of this stone is approximately \(21\; {\rm m \cdot s^{-1}}\).

Explanation:

If the air resistance on this stone is negligible, this stone will accelerate towards the ground with a vertical acceleration \(a_{y}\) of \(a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\).

At the same time, the horizontal velocity \(v_{x}\) of this stone will stay the same during the entire flight: \(v_{x} = 15.2\; {\rm m\cdot s^{-1}}\).

The stone was launched from a height of \(1.1\; {\rm m}\) above the ground. Therefore, the vertical displacement \(x_{y}\) of the stone will be \(x_{y} = (-1.1)\; {\rm m}\) when the stone hits the ground.

The initial vertical velocity \(u_{y}\) of this stone would be \(u_{y} = 0\; {\rm m\cdot s^{-1}}\) since the stone was launched horizontally.

Let \(v_{y}\) denote the final vertical velocity of this stone right before landing. Apply the SUVAT equation \((v_{y})^{2} - (u_{y})^{2} = 2\, a\, x\) to find \(v_{y}\!\):

\((v_{y})^{2} - (u_{y})^{2} = 2\, a\, x\).

\((v_{y})^{2} = (u_{y})^{2} + 2\, a\, x\).

\(\begin{aligned}v_{y} &= -\sqrt{(u_{y})^{2} + 2\, a\, x} \\ &= -\sqrt{0^{2} + 2\, (-9.81) \, (-1.1)}\; {\rm m\cdot s^{-1}} \\ &\approx -14.6908 \end{aligned}\).

(Final vertical velocity \(v_{y}\) is negative since the stone is travelling downwards toward the ground.)

Let \(t\) denote the duration of this flight. Apply the SUVAT equation \(t = (v_{y} - u_{y}) / (a)\) to find \(t\!\):

\(\begin{aligned} t &= \frac{v_{y} - u_{y}}{a} \\ &\approx \frac{(-14.6908) - 0}{(-9.81)}\; {\rm s} \\ &\approx 1.49753\; {\rm s} \end{aligned}\).

In other words, this stone was in the air for approximately \(1.5\; {\rm s}\).

Also because the stone was launched horizontally, the vertical velocity of this stone started at \(u_{y} = 0\; {\rm m\cdot s^{-1}}\) and became negative (toward the ground) immediately after.

Hence, this stone would not have travelled upward during the entire flight. The height of this stone would be maximized immediately after the stone was launched: \(1.1\; {\rm m}\).

Multiple the horizontal velocity \(v_{x} = 15.2\; {\rm m\cdot s^{-1}}\) of this stone by the duration of the flight \(t \approx 1.49753\; {\rm s}\) to find the range (horizontal displacement) of this stone:

\(\begin{aligned} (\text{range}) &= v_{x}\, t \\ &\approx (15.2\; {\rm m\cdot s^{-1}})\, (1.49753\; {\rm s}) \\ &\approx 23\; {\rm m} \end{aligned}\).

Right before landing, the stone would be travelling with a vertical velocity of \(v_{y} \approx (-14.6908)\; {\rm m\cdot s^{-1}}\) and a horizontal velocity of \(v_{x} = 15.2\; {\rm m\cdot s^{-1}}\). Apply the Pythagorean Theorem to find the overall velocity of this stone at that moment:

\(\begin{aligned} v &= \sqrt{{(v_{x})}^{2}\, {(v_{y})^{2}} \\ &\approx \sqrt{(15.2\; {\rm m\cdot s^{-1})^{2} + (-14.6908)^{2}}\; {\rm m\cdot s^{-1}} \\ &\approx 21\; {\rm m\cdot s^{-1}} \end{aligned}\).

A 2 kg toy cart and a 6 kg toy cart have a spring compressed between them. When the spring expands, it sends the 2 kg toy cart off with a speed of 12 m/s. How fast will the 6 kg toy cart go?


a. 2m/s

b. 3m/s

c. 4m/s

d. 6m/s

Answers

Answer:

The speed of second toy cart is 4 m/s.

(c) is correct option

Explanation:

Given that,

Mass of first toy cart = 2 kg

Mass of second toy cart = 6 kg

Speed of first toy cart = 12 m/s

We need to calculate the speed of second toy cart

Using formula of momentum

\(m_{1}v_{1}=m_{2}v_{2}\)

Where, m₁ = mass of first toy cart

m₂ = mass of second toy cart

v₁ = velocity of first toy cart

v₂ =  velocity of second toy cart

Put the value into th formula

\(2\times12=6\times v_{2}\)

\(v_{2}=\dfrac{2\times12}{6}\)

\(v_{2}=4\ m/s\)

Hence, The speed of second toy cart is 4 m/s.

(c) is correct option

Which wave form will Rayleigh waves most likely create?

A. an ocean wave
B. a skier moving down a mountain hill
C. a car traveling through the sand dunes
D. a whale gliding along the ocean's surface

Answers

a- an ocean wave
would be the correct answer

Two blocks, each with a mass of 2 kg, are sliding towards each other at a velocity of 2 m/s on a frictionless surface. The blocks collide with a coefficient of restitution of 0.5. Determine the magnitude of the velocity of the blocks after the collision.

Answers

The magnitude of the velocity of the blocks after the collision is 1 m/s. The collision is partially elastic due to the coefficient of restitution of 0.5.

To determine the magnitude of the velocity of the blocks after the collision, we can use the principles of conservation of momentum and the coefficient of restitution.

Conservation of Momentum: According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Mathematically, this can be expressed as:

(m1 * v1) + (m2 * v2) = (m1 * v1') + (m2 * v2')

where m1 and m2 are the masses of the blocks (both 2 kg in this case), v1 and v2 are the initial velocities of the blocks (2 m/s in this case), and v1' and v2' are the final velocities of the blocks after the collision.

Coefficient of Restitution: The coefficient of restitution (e) is a measure of the elasticity of the collision. It is defined as the ratio of the relative velocity of separation to the relative velocity of approach. Mathematically, we can express this as:

e = (v2' - v1') / (v1 - v2)

In this case, the coefficient of restitution is given as 0.5.

Using the given information, we can solve the two equations simultaneously. Substituting the given values, we have:

(2 * 2) + (2 * 2) = (2 * v1') + (2 * v2')

4 + 4 = 2v1' + 2v2'

8 = 2(v1' + v2')

Also, using the coefficient of restitution:

0.5 = (v2' - v1') / (2 - 2)

0.5 = (v2' - v1') / 0

0 = v2' - v1'

Simplifying these equations, we find:

v1' + v2' = 4 ...(1)

v2' - v1' = 0.5 ...(2)

Adding equation (1) and equation (2), we get:

2v2' = 4.5

v2' = 4.5 / 2

v2' = 2.25 m/s

Substituting the value of v2' into equation (2), we can solve for v1':

2.25 - v1' = 0.5

v1' = 2.25 - 0.5

v1' = 1.75 m/s

Therefore, the magnitude of the velocity of the blocks after the collision is 1 m/s.

After the collision, the blocks will have a magnitude of velocity of 1 m/s. The collision is partially elastic due to the coefficient of restitution of 0.5, indicating that some kinetic energy is lost during the collision.

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Question 24 (2 points)
What is power? (2 points)
O a
O b
O c
Od
The magnitude of a force needed to move an object
How much work can be done in a given time
The distance over time that an object moves
The energy needed to create work

Answers

A because of the keyword “magnitude”

A 61.7 kg carpenter at a construction site plans to swing in a circular arc from one roof top to an adjacent roof at the end of a 11.5 meter rope suspended from a crane boom. if her wiry arms, toughened by years of driving spikes with a no. 22 framing hammer, are capable of exerting 1229 n of force on the rope, what is the maximum speed that she can tolerate at the low point of her swing?

Answers

At the lowest point of her swing, she can withstand a maximum speed of 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body,

F = mv²/r = (61.7× v²)/11.5 = 5.37 v²

Gravitational force acting on her is

F = m × g = 61.7 × 9.81 = 605.28 N

By summing up gravitational and centripetal forces to get the total available force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Hence, the maximum speed at the low point of her swing is 10.78 m/s.

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why you get muscle cramps after heavy exercise??

Answers

Muscle cramps after heavy exercise can be caused by a number of factors, including dehydration, electrolyte imbalances, and muscle fatigue.

During exercise, the body loses water and electrolytes through sweating, which can lead to dehydration and an imbalance in electrolyte levels, particularly sodium, potassium, and magnesium. These imbalances can disrupt the normal function of muscle fibers, causing them to contract and spasm uncontrollably, resulting in a muscle cramp. Additionally, prolonged or intense exercise can lead to muscle fatigue, where the muscles become exhausted and are unable to contract or relax properly. This can also contribute to the development of muscle cramps. To prevent muscle cramps after exercise, it is important to stay properly hydrated by drinking water and electrolyte-containing fluids, such as sports drinks. Stretching before and after exercise can also help to prevent muscle cramps, as can gradually increasing the intensity and duration of exercise over time to avoid overexertion.

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What is the direction of the force on an electron placed at point P? (Figure 3) Enter the latter of the vector that represents the direction of F vector.

Answers

Let an electron is at blue​ sphere and positive charge Q at orange sphere. The force on electron is act towards positive charge.Therefore force is along letter C direction.

Gravity's effect on each and every construction that is built is the one thing that never changes in the entire globe. Every structural designs' main goal is to make a structure stand upright. A designer will be able to include these concerns as part of a design language that will result in a substantially clearer architectural statement if they have a solid understanding of architectonics.

The idea of a force is central to this investigation. Indeed, a force is really abstract. It can be defined, but unless it encounters opposition, it won't become physically evident. Picture a six-foot-tall block of ice moving smoothly on a surface that has been laid out within a hockey rink.

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What is the direction of the force on an electron placed at point P? (Figure 3) Enter the latter of the

A stone propelled from a catapult with a speed of 50m|s attains a height of 100m. Calculate:
a) the time taken
(b) the angle of projectile
(c) the range attained​

Answers

For the projectile motion of the stone a) The time taken T = 9.04s b) the angle of the projectile = 62.31° c) the Range attained R = 209.923m

A stone propelled from a catapult is an example of projectile motion.

Given, the initial velocity of the stone u = 50 m/s; This initial velocity with which the stone is thrown has two components 1) vertical \(u_{y}\) = u sinθ along the Y axis and 2) horizontal \(u_{x}\)=u cosθ along the X axis

where θ is the angle of projection

maximum vertical displacement or height attained by stone = H

(Use sign convention +ve for upwards and -ve for downwards)

a) equation for the maximum vertical height reached by a body during projectile motion   \(H=\frac{u^{2} sin^{2}\theta }{2g}\)      (1)

equation for the time of flight of projectile motion \(T=\frac{2usin\theta}{g}\)           (2)

Given H = displacement in the y direction = height attained = 100m

u =  initial velocity = 50m/s ; acceleration due to gravity g =9.8 m/\(s^{2}\)

using equation (1)

\(100=\frac{50^{2}sin^{2}\theta }{2*9.8}\)

⇒\(sin^{2} \theta= \frac{100*2*9.8}{50^{2} }\)

⇒sinθ\(=\sqrt{\frac{10*2*9.8}{50^{2} } }\)

⇒sinθ = 0.885437

⇒θ = \(sin^{-1} (0.885437)\)

⇒θ = 62.31°

Hence  from equation (2) time of flight

\(T=\frac{2*50*sin\theta}{9.8}\)

⇒\(T=\frac{2*50*0.885437}{9.8}\)

⇒T = 9.04 s

Time is taken T =9.04s

b) Angle of projectile θ = 62.31°

c) The range attained \(R=\frac{u^{2}sin2\theta }{g}\)

⇒\(R = \frac{50^{2}sin(2*62.31)}{9.8}\)

⇒R = \(\frac{50^{2}*0.8229}{9.8}\)

⇒R= 209.923m

horizontal range attained R= 209.923m

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a 6 amp light bulb dissipates 24j per seconds

calculat the amount of charge passing through the 6 amp light bulb per second

Answers

The  charge passing through the circuit in one second is 8 C.

What is charge?

Charge is property of matter that causes experience of force when kept in electric or magnetic field.

Electric charge exists as the physical property of matter that causes charged matter to experience a force when positioned in an electromagnetic field. Electric charges can be positive or negative. Like charges repulse each other and unlike charges attract each other.

Charge, also understood as electric charge, electrical charge, or electrostatic charge and symbolized by q, exists as a characteristic of a unit of matter that represents the extent to which it has more or fewer electrons than protons.

As we know

I =Q/t

where I is current and Q is charge ,t is time

so put the value in formula

8 = Q/

Q  =  8 coulomb.

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5kg
P= 210 N
[2]
2 kg
3 kg
5 kg
P = 210 N
M = 0.2
141
1 kg​

Answers

Answer:

2

Explanation:

ate kinus to plis ffffg

A planet outside of our solar system

Answers

Answer:

exoplanets is any planet beyond our solar system.

FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions you have posted :) thank you very much!!! (22pts)

FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions

Answers

b) accelerate to the left as much more pressure is pulling it in that direction and on the right however , there is less force .

The only substance near earth's surface that is found naturally in the current atmosphere as a solid, liquid, and a gas is:_________

Answers

Water is the only substance that is naturally present near the surface of the planet in the current atmosphere as a solid, liquid, and a gas.

What is the atmosphere ?

The gaseous mixture that covers the planet is its atmosphere. The Earth's atmosphere contributes to the viability of life. In addition to giving us air to breathe, it protects us from the majority of the Sun's harmful ultraviolet (UV) radiation, increases the surface temperature of our planet by around 33° C (59° F) due to the greenhouse effect, and mainly eliminates dramatic temperature variations between day and night. There is an atmosphere on each of the other planets in our solar system, but none of them has the same proportion of gasses or layered structure as Earth's atmosphere.

The most prevalent elements are nitrogen and oxygen, which make up about 78% of dry air (N2) and about 21% of it, respectively (O2). Argon, carbon dioxide (CO2), and numerous other gases are also present in the atmosphere, although at considerably smaller concentrations; each makes up less than 1% of the total gas mixture. Water vapor is also present in the atmosphere. Water vapor is present, but its usual concentration is only about 1%. Additionally, there are a lot of tiny liquids and solids "floating" in the atmosphere. The term "aerosols" refers to a group of particles that also includes dust, pollen, spores, salt from sea spray, volcanic ash, smoke, and other substances.

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1. Convert the following to Scientific notation
A) 0.005

Answers

The scientific expression notation for 0.005 is 5.00 × 10–3.

A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. What is the momentum of the rocket?

Answers

A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. So, The momentum of the rocket is -1500 kg m/s.

According to the law of conservation of momentum, in a closed system, the total momentum before and after a process remains constant.

A fuel-filled rocket that is initially at rest expels hot gas as it burns its fuel. The gas has a momentum of 1500 kg m/s backward.

We are required to determine the momentum of the rocket.

Consider the fuel-filled rocket as a system.

We have: Momentum before the burn = 0 kg m/s (since the rocket was at rest initially)Momentum after the burn = momentum of the expelled gas

We can therefore say that the initial momentum of the system was zero (0), and after the burn, the total momentum of the system remains the same as the momentum of the expelled gas.

Therefore: Momentum of rocket = - momentum of expelled gas

The negative sign signifies that the rocket's momentum is in the opposite direction of the expelled gas.

Hence, the momentum of the rocket is -1500 kg m/s.

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Calculating Force ^F=? air Fballoon=-3 N The action force is the balloon pushing the air out. What is the magnitude of the reaction force of the air pushing on the balloon? IN.​

Answers

According to Newton's third law of motion, the reaction force exerted by the air on the balloon is equal in magnitude but opposite in direction to the action force exerted by the balloon on the air.

Given that the magnitude of the action force (F_balloon) is -3 N, the magnitude of the reaction force (F_air) will also be 3 N. The negative sign indicates that the forces are in opposite directions, but when considering magnitudes, we ignore the negative sign.

Therefore, the magnitude of the reaction force of the air pushing on the balloon is 3 N.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

how many types Of Ornital does the atomic orbital have ?​

Answers

Answer:

There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals

The temperature of one substance is 90 degrees F and another
substance is 50 degrees F. If they are placed close together, what will
happen

Answers

Answer:

Substance that is 90 degrees will lose energy and the substance that is 50 degrees will gain energy

Explanation:

because that is how energy work duhhhhh

Which statements correctly identify chart of Earth and Jupiter?

Which statements correctly identify chart of Earth and Jupiter?

Answers

Answer:

b

Explanation:

Answer:

The first box, second box, and fourth box are correct. I think the fifth might be correct...not completley sure about the fifth box.

Explanation:

A source charge of 5. 0 µC generates an electric field of 3. 93 × 105 at the location of a test charge. How far is the test charge from the source charge? 0. 11 m 0. 34 m 1. 1 m 3. 4 m.

Answers

The distance of the test charge from the source charge is 1.1 m. Option A is correct.

What does Gauss Law state?

It states that the electric flux across any closed surface is directly proportional to the net electric charge enclosed by the surface.\(R= \sqrt \dfrac {Qk^}E\)

Where,

\(E\) = electric force = 3. 93 × 10⁵  N/C

\(k\) = Coulomb constant = \(8.99 \times 10^9 \rm\ N m ^2 /C ^2\)

\(Q\\ \)     = charges =  5.0 µC

\(r\) = distance of separation =?

Put the values in the formula,

\(R= \sqrt \dfrac {5\times 10^{-6}8.99 \times 10^9}{3. 93 \times 10^5}}\\\\ R = 1.1 \rm \ m\)

Therefore, the distance of the test charge from the source charge is 1.1 m.

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Calculate the rotational kinetic energy in the motorcycle wheel as shown in the figure, if its angular velocity is 120 rad/s. Assume M=12.0 kg, R1=0.280 m, and R2 = 0.330 m
.

Answers

The rotational kinetic energy in the motorcycle wheel is 1317.6 Joules when its angular velocity is 120 rad/s.

To calculate the rotational kinetic energy of the motorcycle wheel, we need to first find its moment of inertia (I). The wheel can be considered as a combination of two cylinders, one with a radius of R1 and another with a radius of R2.

For a solid cylinder, the moment of inertia can be calculated as I = (1/2) * M * R^2. Let's calculate the moments of inertia for both cylinders:

I1 = (1/2) * M * R1^2 = 0.5 * 12 * (0.280)^2 = 0.4704 kg m^2

I2 = (1/2) * M * R2^2 = 0.5 * 12 * (0.330)^2 = 0.6534 kg m^2

Since the wheel consists of both cylinders, we should subtract the moment of inertia of the inner cylinder (I1) from the outer cylinder (I2) to find the net moment of inertia:

I_net = I2 - I1 = 0.6534 - 0.4704 = 0.183 kg m^2

Now that we have the moment of inertia, we can calculate the rotational kinetic energy (KE) using the formula KE = (1/2) * I * ω^2, where ω is the angular velocity (120 rad/s):

KE = 0.5 * 0.183 * (120)^2 = 0.0915 * 14400 = 1317.6 J

Therefore, the rotational kinetic energy of the motorcycle wheel is approximately 1317.6 Joules.

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19. Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s. How far did he travel during this time?

Answers

Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s.

So he travel ---m during this time.

Jorge was driving at 20m/s, so speed = 20 units

He accelerated at a rate of 2m/s² so acceleration = 2 units

Time taken by Jorge is 10 units.

We know by Newton's 2nd equation of motion that

S= ut + (1/2)*a*t*t

where S is distance, a is acceleration, u is initial velocity and t is time.

So S=?

Time t = 10

Acceleration a =2

Initial Velocity u = 20

Hence distance travelled by Jorge is S=300 m

Thus Jorge travelled 300m during this time  at speed 20m/s accelerated at a rate of 2m/s² for 10s.

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NEED ASAP !!!
Create 10 questions regarding how physical health affect social media .

They should be directed to
GEN Z
MILLENNIALS
& GEN X


for example : what impact do you think social media has had on you physically?

Answers

Physical health can have a critical effect on social media utilization and behaviour. Individuals with way better physical well-being may have more vitality and inspiration to lock in with social media.

Generally, physical well-being can impact the recurrence and nature of social media utilization, as well as the passionate and mental impacts it has on people. Here are few questions regarding how physical health affect social media-

GEN Z:

Do you think social media utilize has influenced your physical wellbeing adversely?Have you ever experienced physical side effects, such as migraines or eye strain, from investing much time as well on social media?Do you think social media has contributed to your need of physical movement?How do you adjust the utilize of social media and physical work out in your day-by-day schedule? 

MILLENIALS:

How has social media utilize influenced your physical wellbeing over time?Have you ever experienced rest unsettling influences as a result of social media utilize some time recently bed?How do you oversee your screen time to guarantee it doesn't affect your physical wellbeing adversely?Do you are feeling like social media has influenced your eating propensities or body picture in any way? 

GEN X:

How do you guarantee that your utilize of social media does not adversely affect your physical wellbeing?Have you ever experienced torment or distress from destitute pose whereas utilizing social media?Have you ever utilized social media as a instrument to move forward your physical wellbeing, such as following wellness or sustenance?How do you adjust the utilize of social media and other physical exercises or pastimes? 

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a girl throws a rock horizontally, with a velocity of 8.0 m/s, from a bridge. it falls 20 m to the water below. how far does the rock travel horizontally before striking the water, assuming negligible air resistance?

Answers

The rock thrown horizontally at 8.0 m/s from a bridge before it hits the water = 16.15 m.

Free fall motion

Free fall motion is a motion that falls from a height without having an initial velocity. As long as the object is falling, air resistance is negligible, its acceleration is constant and the magnitude is equal to the acceleration due to gravity. In addition, the time it takes for an object to fall does not depend on its mass, but depends on its height.

We have,

The velocity of the rock = 8.0 m/s ⇒ v

Fall height of the rock = 20 m ⇒ h

And, to determine  how far does the rock travel horizontally before striking the water, we use the equation:

d = v x t

We have the velocity (v), but don't have the time (t).

So, determine the time first

Use the equation to determine the height:

h = ½ gt²

20 =  ½ (9.8)t²

t² = 4.08

t = \(\sqrt{4.08}\)

= 2.01 s

So, the distance the stone traveled before striking to the water:

d = (8.0) (2.01)

= 16.15 m

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what's electron affinity? and what is the formula of electric current?​

Answers

Answer:

Electron affinity is the energy change that results from adding an electron to a gaseous atom. For example, when a fluorine atom in the gaseous state gains an electron to form F⁻(g), the associated energy change is -328 kJ/mol.

Give brainliest please.

Answer:

Electron affinity is the energy change that results from adding an electron to a gaseous atom.

Sorry I don't know about the second one.

Which is a unit of volume?

A) centimeter
B) meter
C) milligram
D) milliliter

Answers

Answer:

I think milligram is the correct answer.

Answer:

D. milliliter

Explanation:

Took it on usatestprep

HELPPPPPP (This is for Astronomy i put physics cuz that’s the closest thing)
Which of the following BEST describes the gravitational binding of galaxies?
A) They are arranged from smallest to largest.
B) There is no certain arrangement.
C) They are found in clumps called clusters or superclusters.
D) They often violently collide because of their absence of gravity.

Answers

Answer:

C

Explanation:

Because when they clump together they bind. Get it?

Answer:

I'm thinking C) They are found in clumps called clusters and superclusters.

Explanation:

Galaxies with stronger gravity cause others to get close to them which means they created clusters

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