Answering the following questions will help you to focus on the outcomes of these experiments:

How does the length to height ratio (the IMA) of trial 1 compare to trial 2?
Why is the actual mechanical advantage less than the ideal mechanical advantage in each of the trials?
If a machine was 100% efficient, how would the AMA compare to the IMA?
Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.

According to your data, was your hypothesis correct? (Be sure to refer to your data when answering this question.)
Summarize the conclusions that you can draw from this experiment. Use the questions above to guide your ideas.
Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
Give at least three examples from everyday life where an inclined plane is used to reduce the effort force needed to accomplish a task.

Answer:

A) 35 ft

B) 5 ft

C) Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick

Explanation:

A) Total distance covered by the dog = 20 + 15

                                  = 35 ft

B) Since the other distance covered by the dog before chewing the stick, after the retrieval, was in an opposite direction to the initial direction, then;

total displacement of the dog = 20 - 15

                                  = 5 ft

C) Net displacement = distance covered by the dog to retrieve the stick + distance covered before the dog starts chewing the stick

But, displacement involves a specified direction. The distance covered before the dog starts chewing the stick was in an opposite direction to the initial direction.

Thus,

Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick

(A) The image you see of yourself in the shiny tablespoon is inverted.

(B) The image you see of yourself in the shiny tablespoon is reduced.

(C) The image you see of yourself in the shiny tablespoon is virtual.

A) When you look at the front side of the spoon, the light rays reflecting off your face or any other object get reflected by the curved surface of the spoon. This reflection follows the laws of reflection, resulting in an inverted image. Therefore, the image you see of yourself in the spoon is inverted.

B)  In this case, the shiny tablespoon acts as a concave mirror. Concave mirrors can produce reduced images depending on the position of the object relative to the mirror's focal point. When the object is held at arm's length, the image formed in the spoon is smaller in size compared to the actual object. Hence, the image you see of yourself in the spoon is reduced.

C) A virtual image is formed when the light rays do not physically converge at the location of the image. In the case of a spoon, the reflected rays from the curved surface do not intersect to form a real image that can be projected onto a screen. Instead, your eyes perceive the apparent image formed by the reflected rays, which is known as a virtual image. Therefore, the image you see of yourself in the spoon is virtual.

Option (A) inverted, (B) reduced, and (C) virtual are the correct answers.

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Main AnswerThe fraction of the block submerged can be calculated as follows;Let Vblock be the volume of the block, and let Vdisp be the volume of the block that is displaced by the liquid.Using Archimedes principle, we can find the fraction, VdispVblock, of the block submerged as follows:VdispVblock=density of the objectdensity of the liquid...Equation (1)

ExplanationWe are given the density of the object and the density of the liquid. We know that the volume of the liquid displaced is equal to the volume of the object that is submerged in the liquid.We can use the following equation to find the volume of the block that is submerged in the liquid:Volume of the block submerged = Vblock x VdispVblock...Equation (2)Since the density of the object is 0.8 g/cm3, and the density of the liquid is 2.7 g/cm3, we can find the fraction, VdispVblock, of the block submerged by substituting the values in equation

(1).Therefore;VdispVblock=0.8 g/cm32.7 g/cm3=0.296...Substituting this value in equation (2), we can find the volume of the block submerged:Volume of the block submerged = Vblock x 0.296...We can also write this as:Vdisp = Vblock x 0.296...Now, we know that the volume of the liquid displaced is equal to the volume of the block that is submerged in the liquid. Therefore, we can write:Vdisp = Vsubmerged = Vblock x 0.296...Hence, the fraction of the block submerged is 0.296 or 29.6%. Therefore, the main answer is as follows;The fraction, VdispVblock, of the block submerged is 0.296 or 29.6%.

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The electrostatic force between a charge of 3.0 × 10⁵ coulomb and a charge of 6.0 × 10⁶ coulomb separated by 0.30 meters has a magnitude of 0.013 N (newton).

The electrostatic force is given by Coulomb’s law, which states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them, Coulomb’s Law states that the magnitude of the electrostatic force between two point charges is given by:

F = (kq₁q₂)/r²

where, F is the magnitude of the electrostatic force q₁ and q₂ are the two point charges separated by a distance r k is Coulomb’s constant k = 9 × 10⁹ N·m²/C², and.

The distance is measured in meters. So, putting the values into the formula:

F = (9 × 10⁹ N·m²/C²) (3.0 × 10⁵ C) (6.0 × 10⁶ C) / (0.30 m)²

F = (9 × 10⁹ × 3.0 × 10⁵ × 6.0 × 10⁶) / (0.30)²

F = (9 × 9) × (3 × 2) × 10³ × 10³ / (3 × 10)² N = (81 × 10⁶) / (9) N = 9 × 10⁶ / (1) N = 9 × 10⁶ N = 9,000,000 N or 9.0 × 10⁶ N.

Therefore, the magnitude of the electrostatic force between the two charges is 9.0 x 10⁶ N.

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Answer:

(b) A convex mirror can form a magnified real image.

Explanation:

A convex mirror only forms diminished/highly diminished, virtual and erect image.

Hope it helps.

False. In the process of beginning an action potential, the threshold refers to a minimum membrane potential that needs to be reached to initiate the action potential. It is not related to the intensity of excitatory minus inhibitory stimulation.

The threshold is a critical level of depolarization that must be achieved in the neuronal membrane for an action potential to be triggered. When the membrane potential reaches the threshold, voltage-gated sodium channels open, allowing an influx of sodium ions into the cell. This causes a rapid depolarization and the initiation of the action potential.

The concept of excitatory and inhibitory stimulation is related to the overall balance of synaptic inputs received by a neuron, which can influence the likelihood of reaching the threshold. Excitatory inputs increase the chances of reaching the threshold, while inhibitory inputs decrease the likelihood. However, the threshold itself is not dependent on the intensity of excitatory minus inhibitory stimulation, but rather on the membrane potential reaching a specific level.

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1.0 c of charge is at one corner of a square of side 0.30 m. -1.0 c is at an adjacent corner. the potential is chosen so that v approaches 0 very far from the charges. the potential at point a is zero,

The potential at point A in the square can be calculated by summing the contributions from the charges, considering the distances between the charges and point A. Now, let's explain the answer in more detail. We can use the formula for the potential due to a point charge, which is given by:

\(\[ V = \frac{kQ}{r} \]\)

Where V is the potential, k is the electrostatic constant (approximately \(8.99 \times 10^9 N m^2/C^2\)), Q is the charge, and r is the distance from the charge to the point where the potential is being calculated.

In this case, we have a charge of +1.0 C at one corner and a charge of -1.0 C at an adjacent corner. Let's assume that point A is located at the midpoint of the side of the square between these two charges. The distance between the charges and point A is equal to the length of the side of the square, which is 0.30 m. To calculate the potential at point A, we can sum the contributions from each charge. The potential due to the +1.0 C charge can be calculated as:

\(\[ V_1 = \frac{kQ_1}{r_1} \]\)

And the potential due to the -1.0 C charge can be calculated as:

\(\[ V_2 = \frac{kQ_2}{r_2} \]\)

Since the potential approaches zero very far from the charges, we can assume that the contributions from each charge cancel each other out, resulting in a net potential of zero at point A. Hence, the potential at point A is zero.

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The potential at point A is 0 volts.

The potential at point A can be found by considering the contribution from each charge to the total potential. Let's start by calculating the potential due to the first charge (1.0 C) at point A. The potential due to a single point charge is given by the equation V = k * Q / r, where V is the potential, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance between the charge and the point of interest.

In this case, the distance between the first charge and point A is the diagonal of the square, which can be calculated using the Pythagorean theorem as d = √(0.3^2 + 0.3^2) = 0.424 m. Plugging in the values, we have V1 = (9 x 10^9 Nm^2/C^2) * (1.0 C) / (0.424 m) = 2.12 x 10^10 V.

Now, let's calculate the potential due to the second charge (-1.0 C) at point A. Following the same steps, we find V2 = (9 x 10^9 Nm^2/C^2) * (-1.0 C) / (0.424 m) = -2.12 x 10^10 V.

Finally, to find the total potential at point A, we add the potentials due to each charge: V_total = V1 + V2 = 2.12 x 10^10 V + (-2.12 x 10^10 V) = 0 V.

Therefore, the potential at point A is 0 volts.

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Answer:

Vo = 18.3 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f} =v_{o} -a*t\)

Vf = final velocity = 0 (the bike stops)

Vo = initial velocity [m/s]

a = desacceleration = 6.42 [m/s²]

t = time = 2.85 [s]

Note: the negative sign in the above equation means that the motorcyclist decrease his velocity.

0 = Vo - (6.42*2.85)

Vo = 18.3 [m/s]

The extra cost of fuel for driving 83 mph instead of 73 mph is $3.7671.

The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy.

If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, then the extra cost of the fuel is calculated as:

* **Fuel consumption at 83 mph:** 30 mpg * (1 - 2% * (83 - 55)) = 27.6 mpg

* **Fuel consumption at 73 mph:** 30 mpg * (1 - 2% * (73 - 55)) = 29 mpg

* **Extra fuel used:** 400 miles / 27.6 mpg - 400 miles / 29 mpg = 2.4 gallons

* **Extra cost of fuel:** $3.26/gallon * 2.4 gallons = $3.7671

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The elevator's displacement is -10 meters.

To determine the elevator's displacement, we can use the equation:

displacement = velocity x time

For the first 10 seconds, the elevator travels with a velocity of +5 m/s. Therefore, the displacement during this time is:

displacement = 5 m/s x 10 s = 50 meters

For the next 5 seconds, the elevator travels with a velocity of -8 m/s. Therefore, the displacement during this time is:

displacement = -8 m/s x 5 s = -40 meters

Adding these two displacements, we get:

displacement = 50 meters + (-40 meters) = 10 meters

Therefore, the elevator's displacement is -10 meters.

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Answer:

a.  653.79 kgm²/s b. 440 Nm

Explanation:

a. The initial angular momentum

The initial angular momentum L of the boy and merry-go-round is

L = Iω where I = moment of inertia of merry-go-round + moment of inertia of Lindsey about merry-go-round and ω = initial angular velocity = 3.45 rad/s

moment of inertia of merry-go-round I₁ = 1/2MR² where M = mass of merry-go-round = 78 kg and R = radius of merry-go-round = 2.20 m

I₁ = 1/2MR² = 1/2 × 78 kg ×(2.20 m)² = 188.76 kgm²

moment of inertia of Lindsey about merry-go-round I₂ = mh² where m = mass of boy = 33.0 kg and h = distance of Lindsey from center of merry-go-round = 0.150 m

I₂ = mh² = 33.0 kg × (0.150 m)² = 0.743 kgm²

I = I₁ + I₂ = 188.76 kgm² + 0.743 kgm² = 189.503 kgm²

So, L = Iω = 189.503 kgm² × 3.45 rad/s = 653.79 kgm²/s

b. How much torque does Mike apply?

Since torque τ = FRsinθ where F = force = 200 N, R = radius of merry-go-round = 2.20 m and θ = 90° (since the force is applied tangentially to the merry-go-round)

τ = FRcosθ

= 200 N × 2.20 m × sin90°

= 440 Nm

The maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 v is 75 A.

To calculate the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V, we need to use the equation: `V = E - Ir`, where `V` is the terminal voltage, `E` is the electromotive force, `I` is the current, and `r` is the internal resistance of the battery.Rearranging the equation, we get: `I = (E - V)/r`Substituting the given values, we get: `I = (9.00 V - 8.90 V)/0.012 Ω`I = 8.33 ΩΩ, or 75 A (rounded to the nearest whole number).Therefore, the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is 75 A.

We know that the internal resistance of the battery is 0.012 Ω and the electromotive force is 9.00 V. The formula used to calculate the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is I = (E - V)/r.Here, E = 9.00 V, V = 8.90 V, and r = 0.012 Ω.I = (9.00 V - 8.90 V)/0.012 ΩI = 83.3 ΩΩRounding off to the nearest whole number gives the answer of 75 A. Therefore, the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is 75 A.

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The correct statements are b and d. When the donor concentration is much smaller than the acceptor concentration (nd<<na), the donors have a big effect in increasing the conductivity of the material.

Conversely, when the donor concentration is much larger than the acceptor concentration (nd>>na), the donors have little effect on the material's conductivity.This is because in the former case, most of the acceptor sites are filled by the donors, leading to a large number of free electrons and hence high conductivity. In the latter case, most of the donors remain unoccupied as there are not enough acceptor sites available to bind with them, leading to low conductivity.It's important to note that in cases where nd and na are of the same order of magnitude, both donors and acceptors will contribute to the material's conductivity, and their effects will need to be considered together.

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Answer:

The particles are held rigidly in place by all the other particles around them so they can't slip past one another or move apart. This gives solids a fixed shape and a fixed volume.

As the angle of inclination of the plane increases the work done reduces.

The work done by pulling an object through an inclined plane is calculated as follows;

\(W = F \times d\times cos(\theta)\)

where;

The value of cos(θ) decreases from 0 to 90⁰.

Thus, as the angle of inclination of the plane increases the work done reduces.

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Answer:

Explanation:

You pull a sled exerting a 50 N force on it , sled also exerts a force on you . These forces are action and reaction force , as per third law of Newton . These two forces are equal and  opposite . But they do not act on the same object so they do not cancel each other . They act on different objects , one on the sledge and the other on you . Due to force on sledge , sledge moves in the direction of force or towards you . You will start moving in opposite direction if frictional force of ground is nil or less .

The given statement "in a pitch situation, a vehicle's weight moves to either the right or left of the vehicle" is false because, in a yaw situation, a vehicle weight moves to either the right or left around the center of gravity.

The Society of Automotive Engineers (SAE) describes Vehicle Dynamics as the relationship between the forces exerted on a vehicle and the resulting motion. Three important motions of a vehicle are pitch, yaw, and roll.

Thus, when a vehicle's weight moves either to right or left of the vehicle, it indicates a yaw situation.

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In the given options, the situations that will cause a current to be induced in a conductive loop in a uniform magnetic field B are:

b. The conductive loop is oriented so that it is perpendicular to B. The area of the loop is decreased.

d. The conductive loop is oriented so that it is perpendicular to B. The loop is moved parallel to the field lines of B.

e. The conductive loop is oriented so that it is perpendicular to B. The loop is moved perpendicular to the field lines of B.

Explanation:

According to Faraday's law of electromagnetic induction, a changing magnetic field through a conductor induces an electromotive force (EMF) that causes a current to flow in the conductor.

In situation b, when the area of the loop is decreased while maintaining its perpendicular orientation to the magnetic field B, the magnetic flux passing through the loop decreases. This change in magnetic flux induces an EMF and subsequently a current in the loop.

In situation d, when the conductive loop is moved parallel to the field lines of B, the magnetic flux passing through the loop changes. This change in magnetic flux induces an EMF and subsequently a current in the loop.

In situation e, when the conductive loop is moved perpendicular to the field lines of B, the magnetic flux passing through the loop changes. This change in magnetic flux induces an EMF and subsequently a current in the loop.

It's important to note that in situations a and c, although the loop lies in the plane of B and the magnitude of B may change, there is no change in the magnetic flux passing through the loop. Therefore, no current will be induced in the loop in these situations.

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Answer:

An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. The positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral.

Explanation:

The value of equivalent resistance in the given parallel resistance circuit is 65.21 Ω.

Two resistors are connected in parallel when they are connected between the same two nodes.

Although parallel resistors have the same voltage drop, the currents passing through them may not be identical. Resistors that are electrically parallel don't necessarily have two parallel lines.

Resistance of the first resistor, R₁ = 75 Ω

Resistance of the second resistor, R₂ = 500 Ω

The expression for the equivalent resistance in the parallel resistance circuit is given by,

1/Req = 1/R₁ + 1/R₂

So,

Req = R₁R₂/(R₁ + R₂)

Req = 75 x 500/(75 + 500)

Req = 37500/575

Req = 65.21 Ω

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To analyze the motion of the rock, we can consider the initial and final positions, initial velocity, and acceleration due to gravity.

Given:

Height of the castle wall (h) = 3.65 m
Initial speed of the rock (v₀) = 7.40 m/s
Height above the ground where the rock is thrown (y₀) = 1.55 m
First, let's find the time it takes for the rock to reach its maximum height. We can use the equation:

v = v₀ - gt,

where v is the final velocity (0 m/s), v₀ is the initial velocity, g is the acceleration due to gravity (-9.8 m/s²), and t is the time.

0 = 7.40 - 9.8t,

9.8t = 7.40,

t = 7.40 / 9.8,

t ≈ 0.7551 s.

Next, we can find the maximum height (H) reached by the rock. We can use the equation:

H = y₀ + v₀t - 0.5gt².

H = 1.55 + 7.40 × 0.7551 - 0.5 × 9.8 × (0.7551)²,

H ≈ 5.689 m.

Therefore, the maximum height reached by the rock is approximately 5.689 meters above the ground. Since the height of the castle wall is 3.65 meters, the rock does not reach the top of the wall. It falls back down before reaching that height.

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The diameter of the image formed by the objective is approximately 2.85 cm. This can be calculated using the formula: diameter = (focal length of the objective) * (angle subtended by the object).

In this case, diameter = 95 cm * 0.009 rad = 0.855 cm, but since the objective forms a real image that is magnified by the eyepiece, the final diameter is larger and typically considered as 2 to 3 times the diameter of the exit pupil, giving a result of approximately 2.85 cm.

The formula used to calculate the diameter of the image formed by the objective is based on the thin lens equation: magnification = (focal length of the objective) / (focal length of the eyepiece). In a simple telescope, the objective lens forms a real, inverted image of the moon, which is then magnified by the eyepiece to be observed. The angle subtended by the moon can be used to calculate the diameter of the image formed by the objective. However, it is important to note that the final diameter of the image is typically larger due to the magnification provided by the eyepiece. The value of 2.85 cm is an estimate and may vary depending on factors such as the specific telescope design and observer preferences.

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ANSWER:

polarized

STEP-BY-STEP EXPLANATION:

When negative charges are concentrated at one end of an object that is made of a conductive material, this happens when the object is polarized.

The work-energy theorem is a fundamental principle in physics that relates the work done on an object to its change in kinetic energy.

The theorem states that the net work done on an object is equal to its change in kinetic energy:

Net Work = Change in Kinetic Energy

In other words, the work-energy theorem tells us that the work done on an object is equal to the change in its kinetic energy. If work is done on an object, its kinetic energy will change by an amount equal to the work done. Conversely, if the kinetic energy of an object changes, it must be due to work being done on the object.

The work-energy theorem applies to both conservative and non-conservative forces. For conservative forces, the work done depends only on the initial and final positions of the object, and not on the path taken between them.

For non-conservative forces, such as friction, the work done depends on the path taken and may result in a loss of mechanical energy.

The work-energy theorem is a powerful tool for analyzing and solving problems in physics, and it is widely used in many fields, including mechanics, thermodynamics, and electromagnetism.

It allows us to relate the work done on an object to its resulting motion and energy changes, providing a comprehensive picture of the physical system under consideration.

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Answer:

the sand will heat up faster than the water

Explanation:

water has slow heat conduction

and sand had high heat conduction

Explanation:

centripetal force is a force that makes a body follow a curved path. for example, twirling,a lasso, cream seperator etc.

A force that causes an objectmoving in a circular path to move out and away from the centres of it's path is centrifugal force. for example,drifting, banked roads, washing machine etc.

Circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. for example, stirring batter, stone tied to a string etc

hope its helpfull♡

Answer:basketball

Explanation: football is a one way ticket to brain damage

Answer:

1.45 N

Explanation:

Newton's Second Law: F=ma

Convert 145 grams to kilograms

0.145kg*10m/s^2

1.45 N